I need to implement 256 bit AES encryption for cash flow i have c# answer but the answer is not the same,for a newbie, I am not sure if my direction is correct.
this is my code
public static void main(String[] args) {
String key = "12345678901234567890123456789012";
String hashIv = "1234567890123456";
String value = "MerchantID=3430112RespondType=JSONTimeStamp=1485232229Version=1.4MerchantOrderNo=S_1485232229Amt=40ItemDesc=UnitTest";
String result = encrypt(key, hashIv, value);
System.out.println(result);
System.out.println();
String sha256 = encrySha256("HashKey=" + key + "&" + result + "&HashIV=" + hashIv);
System.out.println(sha256.trim());
}
public static String encrypt(String hashKey, String hashIv, String text) {
try {
SecretKeySpec skeySpec = new SecretKeySpec(hashKey.getBytes("UTF-8"), "AES");
IvParameterSpec ivParameterSpec = new IvParameterSpec(hashIv.getBytes("UTF-8"));
Cipher cipher = Cipher.getInstance("AES/CBC/PKCS5PADDING");
cipher.init(Cipher.ENCRYPT_MODE, skeySpec, ivParameterSpec);
byte[] encrypted = cipher.doFinal((text.getBytes("UTF-8")));
String test = bytesToHex(encrypted);
return test.toLowerCase();
} catch (Exception e) {
System.out.println(e.getMessage());
}
return null;
}
public static String bytesToHex(byte[] bytes) {
StringBuffer sb = new StringBuffer();
for (int i = 0; i < bytes.length; i++) {
String hex = Integer.toHexString(bytes[i] & 0xFF);
if (hex.length() == 1) {
hex = '0' + hex;
}
sb.append(hex.toUpperCase());
}
return sb.toString();
}
public static String encrySha256(String value) {
try {
MessageDigest messageDigest = MessageDigest.getInstance("SHA-256");
messageDigest.update(value.getBytes());
byte byteBuffer[] = messageDigest.digest();
StringBuffer strHexString = new StringBuffer();
for (int i = 0; i < byteBuffer.length; i++) {
String hex = Integer.toHexString(0xff & byteBuffer[i]);
if (hex.length() == 1) {
strHexString.append('0');
}
strHexString.append(hex);
}
return strHexString.toString().toUpperCase();
} catch (Exception e) {
}
return null;
}
sample encrypt answer :
ff91c8aa01379e4de621a44e5f11f72e4d25bdb1a18242db6cef9ef07d80b0165e476fd1d
9acaa53170272c82d122961e1a0700a7427cfa1cf90db7f6d6593bbc93102a4d4b9b66d9
974c13c31a7ab4bba1d4e0790f0cbbbd7ad64c6d3c8012a601ceaa808bff70f94a8efa5a4f
984b9d41304ffd879612177c622f75f4214fa
encryptSha256 answer : EA0A6CC37F40C1EA5692E7CBB8AE097653DF3E91365E6A9CD7E91312413C7BB8
this is c# code and this is sample data
[MerchantID] => 3430112 [RespondType] => JSON [TimeStamp] => 1485232229
[Version] => 1.4 [MerchantOrderNo] => S_1485232229 [Amt] => 40 [ItemDesc] =>
UnitTest
public string EncryptAES256(string source)//加密
{
string sSecretKey = "12345678901234567890123456789012";
string iv = "1234567890123456";
byte[] sourceBytes =
AddPKCS7Padding(Encoding.UTF8.GetBytes(source), 32);
var aes = new RijndaelManaged();
aes.Key = Encoding.UTF8.GetBytes(sSecretKey);
aes.IV = Encoding.UTF8.GetBytes(iv);
aes.Mode = CipherMode.CBC;
aes.Padding = PaddingMode.None;
ICryptoTransform transform = aes.CreateEncryptor();
return ByteArrayToHex(transform.TransformFinalBlock(sourceBytes, 0,
sourceBytes.Length)).ToLower();
}
private static byte[] AddPKCS7Padding(byte[] data, int iBlockSize)
{
int iLength = data.Length;
byte cPadding = (byte)(iBlockSize - (iLength % iBlockSize));
var output = new byte[iLength + cPadding];
Buffer.BlockCopy(data, 0, output, 0, iLength);
for (var i = iLength; i < output.Length; i++)
output[i] = (byte)cPadding;
return output;
}
private static string ByteArrayToHex(byte[] barray)
{
char[] c = new char[barray.Length * 2];
byte b;
for (int i = 0; i < barray.Length; ++i)
{
b = ((byte)(barray[i] >> 4));
c[i * 2] = (char)(b > 9 ? b + 0x37 : b + 0x30);
b = ((byte)(barray[i] & 0xF));
c[i * 2 + 1] = (char)(b > 9 ? b + 0x37 : b + 0x30);
}
return new string(c);
}
The reason for the different encrypted data is that you compare different plain texts. In your Java code you encrypt the plain text
MerchantID=3430112RespondType=JSONTimeStamp=1485232229Version=1.4MerchantOrderNo=S_1485232229Amt=40ItemDesc=UnitTest
and you compare the encrypted data with your reference data
ff91c8aa01379e4de621a44e5f11f72e4d25bdb1a18242db6cef9ef07d80b0165e476fd1d9acaa53170272c82d122961e1a0700a7427cfa1cf90db7f6d6593bbc93102a4d4b9b66d9974c13c31a7ab4bba1d4e0790f0cbbbd7ad64c6d3c8012a601ceaa808bff70f94a8efa5a4f984b9d41304ffd879612177c622f75f4214fa
However, these reference data correspond to a different plain text. The latter you can easily derive by decrypting the reference data with the C# DecryptAES256-method which provides
MerchantID=3430112&RespondType=JSON&TimeStamp=1485232229&Version=1.4&MerchantOrderNo=S_1485232229&Amt=40&ItemDesc=UnitTest
Here, in contrast to the plain text in your Java code, a &-delimiter is used.
If you use the same plain text the Java encrypt- and the C# EncryptAES256-method provide the same encrypted data (same key, IV and padding supposed; for the latter see EDIT-section).
In the following testcase the plain text from your Java code is used:
encrypt("12345678901234567890123456789012", "1234567890123456", "MerchantID=3430112RespondType=JSONTimeStamp=1485232229Version=1.4MerchantOrderNo=S_1485232229Amt=40ItemDesc=UnitTest")
and
EncryptAES256("MerchantID=3430112RespondType=JSONTimeStamp=1485232229Version=1.4MerchantOrderNo=S_1485232229Amt=40ItemDesc=UnitTest")
both provide the encrypted data:
ff91c8aa01379e4de621a44e5f11f72ef45b7b9f9663d386da51af13f7f3b8f2b1ed4a3b7ac6b7783402193ea1d766e3046b6acf612d62568ccdbc475e5a14d114273735b069464dcc8281f4e5bf8486eb97d31602c3fe79cfe7140d2848413edad9d96fabf54d103f3d7a9b401c83fa5e4f17b10a280df10b3d61f23e69bbb8
which (as expected) differs from your reference data (with the exception of the first block).
EDIT
There is a second issue concerning the padding: Your C# EncryptAES256-method uses a custom padding provided by the C# AddPKCS7Padding-method which pads to a multiple of 32 bytes.
In contrast, your Java encrypt-method uses PKCS5Padding which pads to a multiple of 16 bytes.
Thus, the encrypted data of the Java encrypt- and the C# EncryptAES256-method differ if the length of the plain text is between 16 * n byte and 16 * (n + 1) - 1 byte with even n (0,2,4,...).
For odd n (1,3,5,...) the encrypted data are identical. In the example above the byte array of the plain text has 116 bytes that is n = 7 (112 <= 116 <= 127) and therefore the encrypted data are the same.
If the Java encrypt-method should use the same padding as the C# EncryptAES256-method you additionally have to implement an analogous Java-method e.g.:
private static byte[] addPKCS7Padding(byte[] data, int iBlockSize)
{
int iLength = data.length;
byte cPadding = (byte)(iBlockSize - (iLength % iBlockSize));
byte[] output = new byte[iLength + cPadding];
System.arraycopy(data, 0, output, 0, iLength);
for (int i = iLength; i < output.length; i++)
output[i] = (byte)cPadding;
return output;
}
and in the Java encrypt-method you have to replace:
Cipher cipher = Cipher.getInstance("AES/CBC/PKCS5Padding");
with
Cipher cipher = Cipher.getInstance("AES/CBC/NoPadding");
and also
byte[] encrypted = cipher.doFinal(text.getBytes("UTF-8"));
with
byte[] encrypted = cipher.doFinal(addPKCS7Padding(text.getBytes("UTF-8"), 32));
before:
MerchantID=3430112RespondType=JSONTimeStamp=1485232229Version=1.4MerchantOrderNo=S_1485232229Amt=40ItemDesc=UnitTest
After:
MerchantID=3430112&RespondType=JSON&TimeStamp=1485232229&Version=1.4&MerchantOrderNo=S_1485232229&Amt=40&ItemDesc=UnitTest
I only add "&" with each parameter, it's work!!!!
try it!!!
(我只加了&就成功拉，你的代碼沒問題，只是參數要加&而已)
This is C# code. I want to implement it in JAVA exactly.
The result of encryption is as same as C#. If you know about it. Please keep me posted!!
public static byte[] HexStringToByteArray(string hex)
{
int hexLen = hex.Length;
byte[] ret = new byte[hexLen / 2];
for (int i = 0; i < hexLen; i += 2)
{
ret[i / 2] = Convert.ToByte(hex.Substring(i, 2), 16);
}
return ret;
}
public string doEncryption(string password)
{
// If needed, working sample values for mod and exp can be provided
string mod = "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";
string exp = "010001";
RNGCryptoServiceProvider secureRandom = new RNGCryptoServiceProvider(); // Import System.Security.Cryptography
byte[] encryptedPasswordBytes;
using (var rsaEncryptor = new RSACryptoServiceProvider())
{
var passwordBytes = Encoding.ASCII.GetBytes(password);
var rsaParameters = rsaEncryptor.ExportParameters(false);
rsaParameters.Exponent = HexStringToByteArray(exp);
rsaParameters.Modulus = HexStringToByteArray(mod);
rsaEncryptor.ImportParameters(rsaParameters);
encryptedPasswordBytes = rsaEncryptor.Encrypt(passwordBytes, false);
}
// Encrypted password should be identical in the C# and Java versions
string encryptedPassword = Convert.ToBase64String(encryptedPasswordBytes);
return encryptedPassword;
}
as the title says, how do I do it? Its easy to convert from string -> byte -> string binary, But how do I convert back? Below is a example.
The output is :
'f' to binary: 01100110
294984
I read somewhere that I could use the Integer.parseInt but clearly that is not the case :( Or am I doing something wrong?
Thanks,
:)
public class main{
public static void main(String[] args) {
String s = "f";
byte[] bytes = s.getBytes();
StringBuilder binary = new StringBuilder();
for (byte b : bytes)
{
int val = b;
for (int i = 0; i < 8; i++)
{
binary.append((val & 128) == 0 ? 0 : 1);
val <<= 1;
}
binary.append(' ');
}
System.out.println("'" + s + "' to binary: " + binary);
System.out.println(Integer.parseInt("01100110", 2));
}
}
You can use Byte.parseByte() with a radix of 2:
byte b = Byte.parseByte(str, 2);
Using your example:
System.out.println(Byte.parseByte("01100110", 2));
102
You can parse it to an integer in base 2, and convert to a byte array.
In your example you've got 16 bits you can also use short.
short a = Short.parseShort(b, 2);
ByteBuffer bytes = ByteBuffer.allocate(2).putShort(a);
byte[] array = bytes.array();
Just in case if you need it for a Very Big String.
String b = "0110100001101001";
byte[] bval = new BigInteger(b, 2).toByteArray();
I made like this, converted a string s -> byte[] and then used Integer.toBinaryString to get binaryStringRep. I converted bianryStringRep by using Byte.parseByte to get the bianryStringRep into byte and the String(newByte[]) to get the byte[] into a String! Hope it helps others then me aswell! ^^
public class main{
public static void main(String[] args) throws UnsupportedEncodingException {
String s = "foo";
byte[] bytes = s.getBytes();
byte[] newBytes = new byte[s.getBytes().length];
for(int i = 0; i < bytes.length; i++){
String binaryStringRep = String.format("%8s", Integer.toBinaryString(bytes[i] & 0xFF)).replace(' ', '0');
byte newByte = Byte.parseByte(binaryStringRep, 2);
newBytes[i] = newByte;
}
String str = new String(newBytes, "UTF-8");
System.out.println(str);
}
}
Can someone figure out why the output of these (php and java) snippets of code don't return the same SHA512 for the same input?
$password = 'whateverpassword';
$salt = 'ieerskzcjy20ec8wkgsk4cc8kuwgs8g';
$salted = $password.'{'.$salt.'}';
$digest = hash('sha512', $salted, true);
echo "digest: ".base64_encode($digest);
for ($i = 1; $i < 5000; $i++) {
$digest = hash('sha512', $digest.$salted, true);
}
$encoded_pass = base64_encode($digest);
echo $encoded_pass;
This is the code on the android application:
public String processSHA512(String pw, String salt, int rounds)
{
try {
md = MessageDigest.getInstance("SHA-512");
} catch (NoSuchAlgorithmException e) {
e.printStackTrace();
throw new RuntimeException("No Such Algorithm");
}
String result = hashPw(pw, salt, rounds);
System.out.println(result);
return result;
}
private static String hashPw(String pw, String salt, int rounds) {
byte[] bSalt;
byte[] bPw;
String appendedSalt = new StringBuilder().append('{').append(salt).append('}').toString();
try {
bSalt = appendedSalt.getBytes("ISO-8859-1");
bPw = pw.getBytes("ISO-8859-1");
} catch (UnsupportedEncodingException e) {
throw new RuntimeException("Unsupported Encoding", e);
}
byte[] digest = run(bPw, bSalt);
Log.d(LCAT, "first hash: " + Base64.encodeBytes(digest));
for (int i = 1; i < rounds; i++) {
digest = run(digest, bSalt);
}
return Base64.encodeBytes(digest);
}
private static byte[] run(byte[] input, byte[] salt) {
md.update(input);
return md.digest(salt);
}
The library for base64 encoding is this: base64lib
This java code is actually some modified code I found around another question in StackOverflow.
Although the Android code is running fine it doesn't match with the output from the php script. It doesn't even match the first hash!
Note 1: On php hash('sha512',$input, $raw_output) returns raw binary output
Note 2: On java I tried to change the charset (UTF-8, ASCII) but it also didn't work.
Note 3: The code from the server can not be changed, so I would appreciate any answer regarding how to change my android code.
The first hash should be the same on the server and in Java. But then in the loop what gets appended to the digest is password{salt} in the PHP code, but only {salt} in the Java code.
For the lazy ones, one example better than a thousand words ;). I finally understood what was happening. The method update appends bytes to the digest, so when you append $password.{$salt} is the same as doing mda.update(password bytes) and the mda.digest("{$salt}" bytes. I do that answer because I was going crazy finding why it was not working and it was all in this answer.
Thanks guys.
This is the example that works in a Java Server:
public static String hashPassword(String password, String salt) throws Exception {
String result = password;
String appendedSalt = new StringBuilder().append('{').append(salt).append('}').toString();
String appendedSalt2 = new StringBuilder().append(password).append('{').append(salt).append('}').toString();
if(password != null) {
//Security.addProvider(new BouncyCastleProvider());
MessageDigest mda = MessageDigest.getInstance("SHA-512");
byte[] pwdBytes = password.getBytes("UTF-8");
byte[] saltBytes = appendedSalt.getBytes("UTF-8");
byte[] saltBytes2 = appendedSalt2.getBytes("UTF-8");
byte[] digesta = encode(mda, pwdBytes, saltBytes);
//result = new String(digesta);
System.out.println("first hash: " + new String(Base64.encode(digesta),"UTF-8"));
for (int i = 1; i < ROUNDS; i++) {
digesta = encode(mda, digesta, saltBytes2);
}
System.out.println("last hash: " + new String(Base64.encode(digesta),"UTF-8"));
result = new String(Base64.encode(digesta));
}
return result;
}
private static byte[] encode(MessageDigest mda, byte[] pwdBytes,
byte[] saltBytes) {
mda.update(pwdBytes);
byte [] digesta = mda.digest(saltBytes);
return digesta;
}
I am trying to convert a string like "testing123" into hexadecimal form in java. I am currently using BlueJ.
And to convert it back, is it the same thing except backward?
Here's a short way to convert it to hex:
public String toHex(String arg) {
return String.format("%040x", new BigInteger(1, arg.getBytes(/*YOUR_CHARSET?*/)));
}
To ensure that the hex is always 40 characters long, the BigInteger has to be positive:
public String toHex(String arg) {
return String.format("%x", new BigInteger(1, arg.getBytes(/*YOUR_CHARSET?*/)));
}
import org.apache.commons.codec.binary.Hex;
...
String hexString = Hex.encodeHexString(myString.getBytes(/* charset */));
http://commons.apache.org/codec/apidocs/org/apache/commons/codec/binary/Hex.html
Use DatatypeConverter.printHexBinary():
public static String toHexadecimal(String text) throws UnsupportedEncodingException
{
byte[] myBytes = text.getBytes("UTF-8");
return DatatypeConverter.printHexBinary(myBytes);
}
Example usage:
System.out.println(toHexadecimal("Hello StackOverflow"));
Prints:
48656C6C6F20537461636B4F766572666C6F77
Note: This causes a little extra trouble with Java 9 and newer since the API is not included by default. For reference e.g. see this GitHub issue.
The numbers that you encode into hexadecimal must represent some encoding of the characters, such as UTF-8. So first convert the String to a byte[] representing the string in that encoding, then convert each byte to hexadecimal.
public static String hexadecimal(String input, String charsetName) throws UnsupportedEncodingException {
if (input == null) throw new NullPointerException();
return asHex(input.getBytes(charsetName));
}
private static final char[] HEX_CHARS = "0123456789abcdef".toCharArray();
public static String asHex(byte[] buf)
{
char[] chars = new char[2 * buf.length];
for (int i = 0; i < buf.length; ++i)
{
chars[2 * i] = HEX_CHARS[(buf[i] & 0xF0) >>> 4];
chars[2 * i + 1] = HEX_CHARS[buf[i] & 0x0F];
}
return new String(chars);
}
Here an other solution
public static String toHexString(byte[] ba) {
StringBuilder str = new StringBuilder();
for(int i = 0; i < ba.length; i++)
str.append(String.format("%x", ba[i]));
return str.toString();
}
public static String fromHexString(String hex) {
StringBuilder str = new StringBuilder();
for (int i = 0; i < hex.length(); i+=2) {
str.append((char) Integer.parseInt(hex.substring(i, i + 2), 16));
}
return str.toString();
}
All answers based on String.getBytes() involve encoding your string according to a Charset. You don't necessarily get the hex value of the 2-byte characters that make up your string. If what you actually want is the equivalent of a hex viewer, then you need to access the chars directly. Here's the function that I use in my code for debugging Unicode issues:
static String stringToHex(String string) {
StringBuilder buf = new StringBuilder(200);
for (char ch: string.toCharArray()) {
if (buf.length() > 0)
buf.append(' ');
buf.append(String.format("%04x", (int) ch));
}
return buf.toString();
}
Then, stringToHex("testing123") will give you:
0074 0065 0073 0074 0069 006e 0067 0031 0032 0033
byte[] bytes = string.getBytes(CHARSET); // you didn't say what charset you wanted
BigInteger bigInt = new BigInteger(bytes);
String hexString = bigInt.toString(16); // 16 is the radix
You could return hexString at this point, with the caveat that leading null-chars will be stripped, and the result will have an odd length if the first byte is less than 16. If you need to handle those cases, you can add some extra code to pad with 0s:
StringBuilder sb = new StringBuilder();
while ((sb.length() + hexString.length()) < (2 * bytes.length)) {
sb.append("0");
}
sb.append(hexString);
return sb.toString();
To get the Integer value of hex
//hex like: 0xfff7931e to int
int hexInt = Long.decode(hexString).intValue();
I would suggest something like this, where str is your input string:
StringBuffer hex = new StringBuffer();
char[] raw = tokens[0].toCharArray();
for (int i=0;i<raw.length;i++) {
if (raw[i]<=0x000F) { hex.append("000"); }
else if(raw[i]<=0x00FF) { hex.append("00" ); }
else if(raw[i]<=0x0FFF) { hex.append("0" ); }
hex.append(Integer.toHexString(raw[i]).toUpperCase());
}
Java 17 introduces a utility class for hexadecimal formatting: java.util.HexFormat
Convert to hex:
public String toHex(String value) {
return HexFormat.of().formatHex(value.getBytes());
}
Convert from hex:
public String fromHex(String value) {
return new String(HexFormat.of().parseHex(value));
}
More about HexFormat here
Documentation: here
Convert a letter in hex code and hex code in letter.
String letter = "a";
String code;
int decimal;
code = Integer.toHexString(letter.charAt(0));
decimal = Integer.parseInt(code, 16);
System.out.println("Hex code to " + letter + " = " + code);
System.out.println("Char to " + code + " = " + (char) decimal);
To go the other way (hex to string), you can use
public String hexToString(String hex) {
return new String(new BigInteger(hex, 16).toByteArray());
}
One line HEX encoding/decoding without external libs (Java 8 and above):
Encoding :
String hexString = inputString.chars().mapToObj(c ->
Integer.toHexString(c)).collect(Collectors.joining());
Decoding :
String decodedString = Stream.iterate(0, i -> i+2)
.limit(hexString.length()/2 + Math.min(hexString.length()%2,1))
.map(i -> "" + (char)Integer.parseInt("" + hexString.charAt(i) + hexString.charAt(i+1),16))
.collect(Collectors.joining());
First convert it into bytes using getBytes() function and then convert it into hex usign this :
private static String hex(byte[] bytes) {
StringBuilder sb = new StringBuilder();
for (int i=0; i<bytes.length; i++) {
sb.append(String.format("%02X ",bytes[i]));
}
return sb.toString();
}
Using Multiple Peoples help from multiple Threads..
I know this has been answered, but i would like to give a full encode & decode method for any others in my same situation..
Here's my Encoding & Decoding methods..
// Global Charset Encoding
public static Charset encodingType = StandardCharsets.UTF_8;
// Text To Hex
public static String textToHex(String text)
{
byte[] buf = null;
buf = text.getBytes(encodingType);
char[] HEX_CHARS = "0123456789abcdef".toCharArray();
char[] chars = new char[2 * buf.length];
for (int i = 0; i < buf.length; ++i)
{
chars[2 * i] = HEX_CHARS[(buf[i] & 0xF0) >>> 4];
chars[2 * i + 1] = HEX_CHARS[buf[i] & 0x0F];
}
return new String(chars);
}
// Hex To Text
public static String hexToText(String hex)
{
int l = hex.length();
byte[] data = new byte[l / 2];
for (int i = 0; i < l; i += 2)
{
data[i / 2] = (byte) ((Character.digit(hex.charAt(i), 16) << 4)
+ Character.digit(hex.charAt(i + 1), 16));
}
String st = new String(data, encodingType);
return st;
}
Much better:
public static String fromHexString(String hex, String sourceEncoding ) throws IOException{
ByteArrayOutputStream bout = new ByteArrayOutputStream();
byte[] buffer = new byte[512];
int _start=0;
for (int i = 0; i < hex.length(); i+=2) {
buffer[_start++] = (byte)Integer.parseInt(hex.substring(i, i + 2), 16);
if (_start >=buffer.length || i+2>=hex.length()) {
bout.write(buffer);
Arrays.fill(buffer, 0, buffer.length, (byte)0);
_start = 0;
}
}
return new String(bout.toByteArray(), sourceEncoding);
}
import java.io.*;
import java.util.*;
public class Exer5{
public String ConvertToHexadecimal(int num){
int r;
String bin="\0";
do{
r=num%16;
num=num/16;
if(r==10)
bin="A"+bin;
else if(r==11)
bin="B"+bin;
else if(r==12)
bin="C"+bin;
else if(r==13)
bin="D"+bin;
else if(r==14)
bin="E"+bin;
else if(r==15)
bin="F"+bin;
else
bin=r+bin;
}while(num!=0);
return bin;
}
public int ConvertFromHexadecimalToDecimal(String num){
int a;
int ctr=0;
double prod=0;
for(int i=num.length(); i>0; i--){
if(num.charAt(i-1)=='a'||num.charAt(i-1)=='A')
a=10;
else if(num.charAt(i-1)=='b'||num.charAt(i-1)=='B')
a=11;
else if(num.charAt(i-1)=='c'||num.charAt(i-1)=='C')
a=12;
else if(num.charAt(i-1)=='d'||num.charAt(i-1)=='D')
a=13;
else if(num.charAt(i-1)=='e'||num.charAt(i-1)=='E')
a=14;
else if(num.charAt(i-1)=='f'||num.charAt(i-1)=='F')
a=15;
else
a=Character.getNumericValue(num.charAt(i-1));
prod=prod+(a*Math.pow(16, ctr));
ctr++;
}
return (int)prod;
}
public static void main(String[] args){
Exer5 dh=new Exer5();
Scanner s=new Scanner(System.in);
int num;
String numS;
int choice;
System.out.println("Enter your desired choice:");
System.out.println("1 - DECIMAL TO HEXADECIMAL ");
System.out.println("2 - HEXADECIMAL TO DECIMAL ");
System.out.println("0 - EXIT ");
do{
System.out.print("\nEnter Choice: ");
choice=s.nextInt();
if(choice==1){
System.out.println("Enter decimal number: ");
num=s.nextInt();
System.out.println(dh.ConvertToHexadecimal(num));
}
else if(choice==2){
System.out.println("Enter hexadecimal number: ");
numS=s.next();
System.out.println(dh.ConvertFromHexadecimalToDecimal(numS));
}
}while(choice!=0);
}
}
new BigInteger(1, myString.getBytes(/*YOUR_CHARSET?*/)).toString(16)
Here are some benchmarks comparing different approaches and libraries. Guava beats Apache Commons Codec at decoding. Commons Codec beats Guava at encoding. And JHex beats them both for decoding and encoding.
JHex example
String hexString = "596f752772652077656c636f6d652e";
byte[] decoded = JHex.decodeChecked(hexString);
System.out.println(new String(decoded));
String reEncoded = JHex.encode(decoded);
Everything is in a single class file for JHex. Feel free to copy paste if you don't want yet another library in your dependency tree. Also note, it is only available as Java 9 jar until I can figure out how to publish multiple release targets with Gradle and the Bintray plugin.
Convert String to Hexadecimal:
public String hexToString(String hex) {
return Integer.toHexString(Integer.parseInt(hex));
}
definitely this is the easy way.
check this solution for String to hex and hex to String vise-versa
public class TestHexConversion {
public static void main(String[] args) {
try{
String clearText = "testString For;0181;with.love";
System.out.println("Clear Text = " + clearText);
char[] chars = clearText.toCharArray();
StringBuffer hex = new StringBuffer();
for (int i = 0; i < chars.length; i++) {
hex.append(Integer.toHexString((int) chars[i]));
}
String hexText = hex.toString();
System.out.println("Hex Text = " + hexText);
String decodedText = HexToString(hexText);
System.out.println("Decoded Text = "+decodedText);
} catch (Exception e){
e.printStackTrace();
}
}
public static String HexToString(String hex){
StringBuilder finalString = new StringBuilder();
StringBuilder tempString = new StringBuilder();
for( int i=0; i<hex.length()-1; i+=2 ){
String output = hex.substring(i, (i + 2));
int decimal = Integer.parseInt(output, 16);
finalString.append((char)decimal);
tempString.append(decimal);
}
return finalString.toString();
}
Output as follows :
Clear Text = testString For;0181;with.love
Hex Text = 74657374537472696e6720466f723b303138313b776974682e6c6f7665
Decoded Text = testString For;0181;with.love
A short and convenient way to convert a String to its Hexadecimal notation is:
public static void main(String... args){
String str = "Hello! This is test string.";
char ch[] = str.toCharArray();
StringBuilder sb = new StringBuilder();
for (int i = 0; i < ch.length; i++) {
sb.append(Integer.toHexString((int) ch[i]));
}
System.out.println(sb.toString());
}