Why is my catch block looping forever? - java

I am doing a program that calculates factorials, and I wrote a loop that catches NumberFormatException and InputMismatchException. The NumberFormatException runs fine and loops back to the try block, but the InputMismatchException displays its message over and over again without looping back to the try block. I'm not sure what I'm doing wrong. Here's my code:
import java.util.*;
public class Factorial
{
public static void main(String[] args)
{
Scanner s = new Scanner(System.in);
System.out.println("Factorial Test Program\n");
boolean success = false;
while (!success)
{
try
{
System.out.print("Enter an integer number: ");
int number = s.nextInt();
if (number < 0) throw new NumberFormatException();
long f = number;
for (int i = number-1; i>0; i--)
f *= i;
if (number==0) f=1;
System.out.printf("The factorial of %s is %s.\n", number, f);
success=true;
System.out.println("Done!");
}
catch (NumberFormatException e)
{
System.out.println("Factorial of this value cannot be represented as an integer");
}
catch (InputMismatchException e)
{
System.out.println("You must enter an integer - please re-enter:");
}
}
}
}

Once an invalid integer is entered s.nextInt() continously passes the newline character through the while loop and the process repeats itself ad infinitum. On the other hand, when the NumberFormatException occurs, a valid integer has already been read, so there's no newline character being passed through to the while loop.
Adding s.nextLine() within the InputMismatchException exception block will correct this issue.

add break; in the catch block.
or make the while loop inside the try block
try {
while() {
}
} catch () {
}

Related

Java - How to handle Exception Handling in a Looping Switch Statement [duplicate]

So, I'm getting stuck with this piece of code:
import java.util.InputMismatchException;
import java.util.Scanner;
public class ConsoleReader {
Scanner reader;
public ConsoleReader() {
reader = new Scanner(System.in);
//reader.useDelimiter(System.getProperty("line.separator"));
}
public int readInt(String msg) {
int num = 0;
boolean loop = true;
while (loop) {
try {
System.out.println(msg);
num = reader.nextInt();
loop = false;
} catch (InputMismatchException e) {
System.out.println("Invalid value!");
}
}
return num;
}
}
and here is my output:
Insert a integer number:
Invalid value!
Insert a integer number:
Invalid value!
...
As per the javadoc for Scanner:
When a scanner throws an
InputMismatchException, the scanner
will not pass the token that caused
the exception, so that it may be
retrieved or skipped via some other
method.
That means that if the next token is not an int, it throws the InputMismatchException, but the token stays there. So on the next iteration of the loop, reader.nextInt() reads the same token again and throws the exception again. What you need is to use it up. Add a reader.next() inside your catch to consume the token, which is invalid and needs to be discarded.
...
} catch (InputMismatchException e) {
System.out.println("Invalid value!");
reader.next(); // this consumes the invalid token
}
What I would do is read in the whole line using Scanner.nextLine(). Then create another scanner that reads the returned string.
String line = reader.nextLine();
Scanner sc = new Scanner(line);
This would make your sample function something like this:
public int readInt(String msg) {
int num = 0;
boolean loop = true;
while (loop) {
try {
System.out.println(msg);
String line = reader.nextLine();
Scanner sc = new Scanner(line);
num = sc.nextInt();
loop = false;
} catch (InputMismatchException e) {
System.out.println("Invalid value!");
}
}
return num;
}
This way you have one scanner that gets the input and one that validates it so you don't have to worry about reader caring if they input the correct form of input.
The guard of your while-do is 'loop' variable.
The exception itself thrown before your code reaches assignment loop = false;
To be precise, the exception is thrown in previous statement which is num = reader.nextInt();
When exception thrown, value of 'loop' variable is 'true' but your code jumps to catch block and then repeats the while-do. This while-do will never stop because next iteration will throw an exception again, jumps to catch block again and so on.
To terminate this while-do, you need to guard your while-do with another logical thing such as :
Exit when reader gets non-int character
Exit when EOF
This can be done in catch block or some other lines. But precise solution depends on your specifications.
You may also try this:
public int readInt(String msg) {
int num = 0;
try {
System.out.println(msg);
num = (new Scanner(System.in)).nextInt();
} catch (InputMismatchException e) {
System.out.println("Invalid value!");
num = readInt(msg);
}
return num;
}
package nzt.nazakthul.app;
import java.util.*;
public class NztMainApp {
public static void main(String[] args) {
ReadNumber readObj = new ReadNumber();
readObj.readNumber();
}
}
class ReadNumber {
int no;
int readNumber() {
Scanner number = new Scanner(System.in);
int no=0;
boolean b=true;
do {
try {
System.out.print("Enter a number:\t");
no = number.nextInt();
} catch (InputMismatchException e) {
System.out.println("No Number");
//e.printStackTrace();
b=false;
}
}
while (b);
return no;
}
}
Personally i use BufferedReader and InputStreamReader to read String and check if is a number or not, but with scanner is less code. The code is checked and run ok.

Java Infinite Loop with Scanner Input [duplicate]

So, I'm getting stuck with this piece of code:
import java.util.InputMismatchException;
import java.util.Scanner;
public class ConsoleReader {
Scanner reader;
public ConsoleReader() {
reader = new Scanner(System.in);
//reader.useDelimiter(System.getProperty("line.separator"));
}
public int readInt(String msg) {
int num = 0;
boolean loop = true;
while (loop) {
try {
System.out.println(msg);
num = reader.nextInt();
loop = false;
} catch (InputMismatchException e) {
System.out.println("Invalid value!");
}
}
return num;
}
}
and here is my output:
Insert a integer number:
Invalid value!
Insert a integer number:
Invalid value!
...
As per the javadoc for Scanner:
When a scanner throws an
InputMismatchException, the scanner
will not pass the token that caused
the exception, so that it may be
retrieved or skipped via some other
method.
That means that if the next token is not an int, it throws the InputMismatchException, but the token stays there. So on the next iteration of the loop, reader.nextInt() reads the same token again and throws the exception again. What you need is to use it up. Add a reader.next() inside your catch to consume the token, which is invalid and needs to be discarded.
...
} catch (InputMismatchException e) {
System.out.println("Invalid value!");
reader.next(); // this consumes the invalid token
}
What I would do is read in the whole line using Scanner.nextLine(). Then create another scanner that reads the returned string.
String line = reader.nextLine();
Scanner sc = new Scanner(line);
This would make your sample function something like this:
public int readInt(String msg) {
int num = 0;
boolean loop = true;
while (loop) {
try {
System.out.println(msg);
String line = reader.nextLine();
Scanner sc = new Scanner(line);
num = sc.nextInt();
loop = false;
} catch (InputMismatchException e) {
System.out.println("Invalid value!");
}
}
return num;
}
This way you have one scanner that gets the input and one that validates it so you don't have to worry about reader caring if they input the correct form of input.
The guard of your while-do is 'loop' variable.
The exception itself thrown before your code reaches assignment loop = false;
To be precise, the exception is thrown in previous statement which is num = reader.nextInt();
When exception thrown, value of 'loop' variable is 'true' but your code jumps to catch block and then repeats the while-do. This while-do will never stop because next iteration will throw an exception again, jumps to catch block again and so on.
To terminate this while-do, you need to guard your while-do with another logical thing such as :
Exit when reader gets non-int character
Exit when EOF
This can be done in catch block or some other lines. But precise solution depends on your specifications.
You may also try this:
public int readInt(String msg) {
int num = 0;
try {
System.out.println(msg);
num = (new Scanner(System.in)).nextInt();
} catch (InputMismatchException e) {
System.out.println("Invalid value!");
num = readInt(msg);
}
return num;
}
package nzt.nazakthul.app;
import java.util.*;
public class NztMainApp {
public static void main(String[] args) {
ReadNumber readObj = new ReadNumber();
readObj.readNumber();
}
}
class ReadNumber {
int no;
int readNumber() {
Scanner number = new Scanner(System.in);
int no=0;
boolean b=true;
do {
try {
System.out.print("Enter a number:\t");
no = number.nextInt();
} catch (InputMismatchException e) {
System.out.println("No Number");
//e.printStackTrace();
b=false;
}
}
while (b);
return no;
}
}
Personally i use BufferedReader and InputStreamReader to read String and check if is a number or not, but with scanner is less code. The code is checked and run ok.

My loop with try catch is stuck in endless loop and it should prompt the user each time for an input

I'm trying to ask the user for a number and if they enter anything wrong (not an int between 1 and 99) then catch (to prevent crash if string) and loop until enter a right number. My loop is stuck in an endless loop somehow. Note: I do have the Scanner imported and the exception imported too.
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String result;
int number;
boolean done = false;
while (true) {
try {
System.out.println("Please select a number from 1 to 99.");
number = input.nextInt();
input.nextLine();
if (number >= 1 || number <= 99) {
result = checkNumber(number);
System.out.println(result);
break;
}
} catch (InputMismatchException exception) {
}
}
}
input.nextInt() won't consume anything not an int. It will throw an exception. You ignore the exception and try to consume an int. It's still not an int. Same exception. Infinite loop. Add another input.nextLine() in your catch block.

java try-catch inputMismatchException [duplicate]

So, I'm getting stuck with this piece of code:
import java.util.InputMismatchException;
import java.util.Scanner;
public class ConsoleReader {
Scanner reader;
public ConsoleReader() {
reader = new Scanner(System.in);
//reader.useDelimiter(System.getProperty("line.separator"));
}
public int readInt(String msg) {
int num = 0;
boolean loop = true;
while (loop) {
try {
System.out.println(msg);
num = reader.nextInt();
loop = false;
} catch (InputMismatchException e) {
System.out.println("Invalid value!");
}
}
return num;
}
}
and here is my output:
Insert a integer number:
Invalid value!
Insert a integer number:
Invalid value!
...
As per the javadoc for Scanner:
When a scanner throws an
InputMismatchException, the scanner
will not pass the token that caused
the exception, so that it may be
retrieved or skipped via some other
method.
That means that if the next token is not an int, it throws the InputMismatchException, but the token stays there. So on the next iteration of the loop, reader.nextInt() reads the same token again and throws the exception again. What you need is to use it up. Add a reader.next() inside your catch to consume the token, which is invalid and needs to be discarded.
...
} catch (InputMismatchException e) {
System.out.println("Invalid value!");
reader.next(); // this consumes the invalid token
}
What I would do is read in the whole line using Scanner.nextLine(). Then create another scanner that reads the returned string.
String line = reader.nextLine();
Scanner sc = new Scanner(line);
This would make your sample function something like this:
public int readInt(String msg) {
int num = 0;
boolean loop = true;
while (loop) {
try {
System.out.println(msg);
String line = reader.nextLine();
Scanner sc = new Scanner(line);
num = sc.nextInt();
loop = false;
} catch (InputMismatchException e) {
System.out.println("Invalid value!");
}
}
return num;
}
This way you have one scanner that gets the input and one that validates it so you don't have to worry about reader caring if they input the correct form of input.
The guard of your while-do is 'loop' variable.
The exception itself thrown before your code reaches assignment loop = false;
To be precise, the exception is thrown in previous statement which is num = reader.nextInt();
When exception thrown, value of 'loop' variable is 'true' but your code jumps to catch block and then repeats the while-do. This while-do will never stop because next iteration will throw an exception again, jumps to catch block again and so on.
To terminate this while-do, you need to guard your while-do with another logical thing such as :
Exit when reader gets non-int character
Exit when EOF
This can be done in catch block or some other lines. But precise solution depends on your specifications.
You may also try this:
public int readInt(String msg) {
int num = 0;
try {
System.out.println(msg);
num = (new Scanner(System.in)).nextInt();
} catch (InputMismatchException e) {
System.out.println("Invalid value!");
num = readInt(msg);
}
return num;
}
package nzt.nazakthul.app;
import java.util.*;
public class NztMainApp {
public static void main(String[] args) {
ReadNumber readObj = new ReadNumber();
readObj.readNumber();
}
}
class ReadNumber {
int no;
int readNumber() {
Scanner number = new Scanner(System.in);
int no=0;
boolean b=true;
do {
try {
System.out.print("Enter a number:\t");
no = number.nextInt();
} catch (InputMismatchException e) {
System.out.println("No Number");
//e.printStackTrace();
b=false;
}
}
while (b);
return no;
}
}
Personally i use BufferedReader and InputStreamReader to read String and check if is a number or not, but with scanner is less code. The code is checked and run ok.

Try Catch Statement Infinite Loop [duplicate]

So, I'm getting stuck with this piece of code:
import java.util.InputMismatchException;
import java.util.Scanner;
public class ConsoleReader {
Scanner reader;
public ConsoleReader() {
reader = new Scanner(System.in);
//reader.useDelimiter(System.getProperty("line.separator"));
}
public int readInt(String msg) {
int num = 0;
boolean loop = true;
while (loop) {
try {
System.out.println(msg);
num = reader.nextInt();
loop = false;
} catch (InputMismatchException e) {
System.out.println("Invalid value!");
}
}
return num;
}
}
and here is my output:
Insert a integer number:
Invalid value!
Insert a integer number:
Invalid value!
...
As per the javadoc for Scanner:
When a scanner throws an
InputMismatchException, the scanner
will not pass the token that caused
the exception, so that it may be
retrieved or skipped via some other
method.
That means that if the next token is not an int, it throws the InputMismatchException, but the token stays there. So on the next iteration of the loop, reader.nextInt() reads the same token again and throws the exception again. What you need is to use it up. Add a reader.next() inside your catch to consume the token, which is invalid and needs to be discarded.
...
} catch (InputMismatchException e) {
System.out.println("Invalid value!");
reader.next(); // this consumes the invalid token
}
What I would do is read in the whole line using Scanner.nextLine(). Then create another scanner that reads the returned string.
String line = reader.nextLine();
Scanner sc = new Scanner(line);
This would make your sample function something like this:
public int readInt(String msg) {
int num = 0;
boolean loop = true;
while (loop) {
try {
System.out.println(msg);
String line = reader.nextLine();
Scanner sc = new Scanner(line);
num = sc.nextInt();
loop = false;
} catch (InputMismatchException e) {
System.out.println("Invalid value!");
}
}
return num;
}
This way you have one scanner that gets the input and one that validates it so you don't have to worry about reader caring if they input the correct form of input.
The guard of your while-do is 'loop' variable.
The exception itself thrown before your code reaches assignment loop = false;
To be precise, the exception is thrown in previous statement which is num = reader.nextInt();
When exception thrown, value of 'loop' variable is 'true' but your code jumps to catch block and then repeats the while-do. This while-do will never stop because next iteration will throw an exception again, jumps to catch block again and so on.
To terminate this while-do, you need to guard your while-do with another logical thing such as :
Exit when reader gets non-int character
Exit when EOF
This can be done in catch block or some other lines. But precise solution depends on your specifications.
You may also try this:
public int readInt(String msg) {
int num = 0;
try {
System.out.println(msg);
num = (new Scanner(System.in)).nextInt();
} catch (InputMismatchException e) {
System.out.println("Invalid value!");
num = readInt(msg);
}
return num;
}
package nzt.nazakthul.app;
import java.util.*;
public class NztMainApp {
public static void main(String[] args) {
ReadNumber readObj = new ReadNumber();
readObj.readNumber();
}
}
class ReadNumber {
int no;
int readNumber() {
Scanner number = new Scanner(System.in);
int no=0;
boolean b=true;
do {
try {
System.out.print("Enter a number:\t");
no = number.nextInt();
} catch (InputMismatchException e) {
System.out.println("No Number");
//e.printStackTrace();
b=false;
}
}
while (b);
return no;
}
}
Personally i use BufferedReader and InputStreamReader to read String and check if is a number or not, but with scanner is less code. The code is checked and run ok.

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