I am working on eclipse plugin. In this i have a file name present in a project hierarchy. i need the full path of file abc.java present in project Test.
The file presented in path F:/Test/src/main/java/com/sung/Pre/abc.java
IWorkspaceRoot rootWorkspace = ResourcesPlugin.getWorkspace().getRoot();
IProject project = rootWorkspace.getProject("/Test");
file1 = project.getFile("/abc.java");
FileEditorInput fileEditorInput = new FileEditorInput(file1);
IWorkbench workbench = PlatformUI.getWorkbench();
IEditorDescriptor desc = workbench.getEditorRegistry().getDefaultEditor(file1.getName());
IWorkbenchPage page11 = workbench.getActiveWorkbenchWindow().getActivePage();
try {
page11.openEditor(fileEditorInput, desc.getId(),true);
} catch (PartInitException e1) {
e1.printStackTrace();
}
This is searching file in /Test folder. If the file presented in the root Test folder it's able to open this file but if it's inside some folder like F:/Test/src/main/java/com/sung/Pre/abc.java than it's can not find the file.
I also tried below code but facing the same issue
try {
//IDE.openEditor(page11, uri, "org.eclipse.ui.ide.IDE", true);
IDE.openEditor(page11, file1, true);
} catch (PartInitException e2) {
// TODO Auto-generated catch block
e2.printStackTrace();
}
so my question is if we have a file name presented in project hierarchy so how can we get the absolute or full path of that.
Please remember that i am doing this task in eclipse plugin project
You can specify a path on project.getFile:
project.getFile(new Path("src/main/java/com/sung/Pre/abc.java"));
or get the IFolder for the folder containing the file and use
folder.getFile(new Path("abc.java"));
Related
I'm trying to get file (readme.txt) from my project folder. Don't know how to get location of project. When I say project, I mean location where my application code is written and not runtime application. I've tried getting absolute path, relative path... and it always gives me folder of runtime application. Also tried something like this.getClass() and tried to extract path or System.getProperty("user.dir"). These two also gives me path of my eclipse.../.../...runtime app. I'm making eclipse plugin, and this file is suppose to be part of my plugin, so that when user click's on button, this file opens (it's some help txt file). This is my code for opening file, problem is path.
/**
* Help button listener. If button is pressed, help file is opened.
*/
private void listenButtonHelp() {
buttonHelp.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent evt) {
if (Desktop.isDesktopSupported()) {
File helpFile = new File("\\readme.txt");
helpFile.setReadOnly();
Desktop desktop = Desktop.getDesktop();
try {
desktop.open(helpFile);
} catch (IOException e) {
e.printStackTrace();
}
}
}
});
}
It depends on where exactly the file is in your project. A clean point to put it might be ${project.root}/resources, so create a folder and put the file there. Mark it as a "source folder" in Eclipse (project properties -> build path -> source folders). Your current setup isn't a good idea because the file will not be included in your distribution by Eclipse's compile.
Now, when you compile the code, this gets copied into the target directors (bin per default); you can check by opening it in your file browser.
So to check the file is there, you can do
Path filePath = Paths.get("resources", "readme.txt");
System.out.println(Files.exists(filePath));
If you need it as a File, you can do
File readmeFile = filePath.toFile();
This reads the file from the source project folder, so it won't be much use after you run the program somewhere else.
For that, you can use the ClassLoader:
URL readmeUrl = ClassLoader.getSystemClassLoader().getResource("resources/readme.txt"));
File readmeFile = new File(readmeUrl.getFile());
I found answer, this works for me:
/**
* Help button listener. If button is pressed, help file is opened.
*/
private void listenButtonHelp() {
buttonHelp.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent evt) {
if (Desktop.isDesktopSupported()) {
File file = null;
Bundle bundle = Platform.getBundle("TestProject");
IPath path = new Path("resources/readme.txt");
URL url = FileLocator.find(bundle, path, null);
/*
* After FileLocator, I get also this, like I commented before:
* D:\\eclipse-rcp-oxygen\\eclipse\\..\\..\\..\\eclipse_oxygen_workspace\\
* TestProject\\resources\\readme.txt and before it didn't work but if
* you add these lines:
* url = FileLocator.toFileURL(url);
* file = URIUtil.toFile(URIUtil.toURI(url));
* Like in my try bracket, it works. I guess it needs to be
* converted using URIUtil.
* Now it finds file, and it can be opened, also works for .html files.
*/
Desktop desktop = Desktop.getDesktop();
try {
url = FileLocator.toFileURL(url);
file = URIUtil.toFile(URIUtil.toURI(url));
// file.setReadOnly();
desktop.open(file);
} catch (Exception e1) {
e1.printStackTrace();
}
}
}
});
}
I'm having a weird problem in java. I want to create a runnable jar:
This is my only class:
public class Launcher {
public Launcher() {
// TODO Auto-generated constructor stub
}
public static void main(String[] args) {
String path = Launcher.class.getResource("/1.png").getFile();
File f = new File(path);
JOptionPane.showMessageDialog(null,Boolean.toString(f.exists()));
}
}
As you can see it just outputs if it can find the file or not. It works fine under eclipse (returns true). i've created a source folder resources with the image 1.png. (resource folder is added to source in build path)
As soon as I export the project to a runnable jar and launch it, it returns false.
I don't know why. Somebody has an idea?
Thanks in advance
edit: I followed example 2 to create the resources folder: Eclipse exported Runnable JAR not showing images
If you would like to load resources from your .jar file use getClass().getResource(). That returns a URL with correct path.
Image icon = ImageIO.read(getClass().getResource("imageĀ“s path"));
To access images in a jar, use Class.getResource().
I typically do something like this:
InputStream stream = MyClass.class.getResourceAsStream("Icon.png");
if(stream == null) {
throw new RuntimeException("Icon.png not found.");
}
try {
return ImageIO.read(stream);
} catch (IOException e) {
throw new RuntimeException(e);
} finally {
try {
stream.close();
} catch(IOException e) { }
}
Still you're understand, Kindly go through this link.
Eclipse exported Runnable JAR not showing images
Because the image is not separate file but packed inside the .jar.
Use the code to create the image from stream
InputStream is=Launcher.class.getResourceAsStream("/1.png");
Image img=ImageIO.read(is);
try to use this to get image
InputStream input = getClass().getResourceAsStream("/your image path in jar");
Two Simple steps:
1 - Add the folder ( where the image is ) to Build Path;
2 - Use this:
InputStream url = this.getClass().getResourceAsStream("/load04.gif");
myImageView.setImage(new Image(url));
I am trying to read properties which is located external to the jar file of my code.using ResourceBundle but its unable to read the property file locations.properties. The property file is located under resource folder and both jar and resource folder are under same directory.
myDir
--> myJar.jar
--> resource
-->locations.properties
I don't know whats wrong with my code below:
public static ResourceBundle getResourceBundle(String fileName) throws MalformedURLException{
if (resourceBundle == null) {
File file = new File("resource/"+fileName);
URL[] urls = { file.toURI().toURL() };
ClassLoader loader = new URLClassLoader(urls);
resourceBundle = ResourceBundle.getBundle(fileName, Locale.getDefault(), loader);
}
return resourceBundle;
}
And this is how am invoking ResourceBundle object:
ResourceBundle locationBundle = null;
try {
locationBundle = ReadPropertyUtil.getResourceBundle(propFileName);
} catch (MalformedURLException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
Please guide whats wrong with this code and whats the correct way of reading an external properties file.
Get Jar file path.
Get Parent folder of that file.
Use that path in InputStreamPath with your properties file name.
Properties prop = new Properties();
try {
File jarPath=new File(YourClassNameInJar.class.getProtectionDomain().getCodeSource().getLocation().getPath());
String propertiesPath=jarPath.getParentFile().getAbsolutePath();
System.out.println(" propertiesPath-"+propertiesPath);
prop.load(new FileInputStream(propertiesPath+"/resource/locations.properties"));
} catch (IOException e1) {
e1.printStackTrace();
}
Well, I figured out the error myself. I was appending the fileName to the directory location File file = new File("resource/"+fileName); which was wrong.
All I had to do was to first get the present working directory name using
System.getProperties("user.dir") //this gives me the path of my current directory
and passing only the directory name to file object.
File file = new File("resource/");
And then load the bundle using the specified file name.
resourceBundle = ResourceBundle.getBundle(fileName, Locale.getDefault(), loader);
ResourceBundle automatically looks into the directory and loads the file specified by the fileName
I have a properties file which is located under conf folder. conf folder is under the project root directory. I am using the following code.
public class PropertiesTest {
public static void main(String[] args) {
InputStream inputStream = PropertiesTest.class
.getResourceAsStream("/conf/sampleprop.conf");
Properties prop = new Properties();
try {
prop.load(inputStream);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
System.out.println(prop.getProperty("TEST"));
}
}
But I get nullpointer exception.
I have tried using
InputStream inputStream = PropertiesTest.class
.getResourceAsStream("./conf/sampleprop.conf");
and
InputStream inputStream = PropertiesTest.class
.getResourceAsStream("conf/sampleprop.conf");
But all result in nullpointer exception.
Can anyone please help.
Thanks in advance
Try to recover your working directory first:
String workingDir = System.getProperty("user.dir");
System.out.println("Current working dir: " + workingDir);
and then is simple:
Properties propertiesFile = new Properties();
propertiesFile.load(new FileInputStream(workingDir+ "/yourFilePath"));
String first= propertiesFile.getProperty("myprop.first");
Regards, fabio
The getResourceAsStream() method tries to locate and load the resource using the ClassLoader of the class it is called on. Ideally it can locate the files only the class folders .. Rather you could use FileInputStream with relative path.
EDIT
if the conf folder is under src, then you still be able to access with getResourceAsStream()
InputStream inputStream = Test.class
.getResourceAsStream("../conf/sampleprop.conf");
the path would be relative to the class from you invoke getRes.. method.
If not
try {
FileInputStream fis = new FileInputStream("conf/sampleprop.conf");
Properties prop = new Properties();
prop.load(fis);
System.out.println(prop.getProperty("TEST"));
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
NOTE: this will only work if it is Stand alone application/in eclipse. This will not work if its web based (as the root will be Tomcat/bin, for eg)
I would suggest to copy the configuration file at designated place, then you can acess at ease. At certain extent 'System.getProperty("user.dir")' can be used if you are always copying the file 'tomcat` root or application root. But if the files to be used by external party, ideal to copy in a configurable folder (C:\appconf)
Your code works like a charm! But you might have to add the project root dir to your classpath.
If you work with Maven, place your configuration in src/main/resources/conf/sampleprop.conf
When invoking java directly add the project root dir with the java -classpath parameter. Something like:
java -classpath /my/classes/dir:/my/project/root/dir my.Main
protected void executeInternal(JobExecutionContext context) throws JobExecutionException
{
System.out.println("Sending Birthday Wishes... ");
try
{
for(int i=0;i<maillist.length;i++)
{
Email email = new Email();
email.setFrom("spv_it#yahoo.com");
email.setSubject("Happy IndependenceDay");
email.setTo(maillist[i]);
email.setText("<font color=blue><h4>Dear Users,<br><br><br>Wish you a Happy Independence Day!<br><br><br>Regards,<br>Penna Cement Industries Limited</h4></font>");
byte[] data = null;
ClassPathResource img = new ClassPathResource("newLogo.gif");
InputStream inputStream = img.getInputStream();
data = new byte[inputStream.available()];
while((inputStream.read(data)!=-1));
Attachment attachment = new Attachment(data, "HappyBirthDay","image/gif", true);
email.addAttachment(attachment);
emailService.sendEmail(email);
}
}
catch (MessagingException e)
{
e.printStackTrace();
}
catch (Exception e)
{
e.printStackTrace();
}
}
This is the error I'm getting:
java.io.FileNotFoundException: class path resource [newLogo.gif] cannot be opened because it does not exist
at org.springframework.core.io.ClassPathResource.getInputStream(ClassPathResource.java:135)
at com.mail.schedular.BirthdayWisherJob.executeInternal(BirthdayWisherJob.java:55)
at org.springframework.scheduling.quartz.QuartzJobBean.execute(QuartzJobBean.java:66)
at org.quartz.core.JobRunShell.run(JobRunShell.java:223)
at org.quartz.simpl.SimpleThreadPool$WorkerThread.run(SimpleThreadPool.java:549)
The best practise is to read/write or to provide reference of any file is by mentioning the ABSOLUTE PATH of that file.
To your question, It shows the FileNotFoundException because, JVM failed to locate the file in your current directory which is by default your source path. So provide the absolute path in ClassPathResource or copy that image file to your current directory. It will solve your problem.
I think you need to put your file inside inside the src folder , if it's there then check whether it's under some directory which is inside the src directory.
Then give the correct location like given details below
src[dir]----->newLogo.gif
ClassPathResource img = new ClassPathResource("newLogo.gif");
or,
src[dir]----->images[dir]---->newLogo.gif
ClassPathResource img = new ClassPathResource("/images/newLogo.gif");
You got this error since the job is running in a separate quartz thread, I suggest that you locate your file newLogo.gif outside the jar and use the following to load it.
Thread.currentThread().getContextClassLoader().getResource("classpath:image/newLogo.gif");