I have a button to open a URL in browser:
URI uri = new URI("http://google.com/");
Desktop dt = Desktop.getDesktop();
dt.browse(uri.toURL()); // has error
but i get following error in last statement:
The method browse(URI) in the type Desktop is not applicable for the arguments (URL)
thanks for any suggestion.
Found solution:
1. Remove .toURL()
2. use try catch block
try
{
URI uri = new URI("http://google.com/");
Desktop dt = Desktop.getDesktop();
dt.browse(uri);
}
catch(Exception ex){}
What it tells you is that you are sending an URL object while it expects an URI.
just change
dt.browse(uri.toURL()); // has error
to
dt.browse(uri); // has error
before being able to use Desktop, you have to consider if it is supported
if (Desktop.isDesktopSupported()) {
desktop = Desktop.getDesktop();
// now enable buttons for actions that are supported.
enableSupportedActions();
}
and the enableSupportedActions
private void enableSupportedActions() {
if (desktop.isSupported(Desktop.Action.BROWSE)) {
txtBrowserURI.setEnabled(true);
btnLaunchBrowser.setEnabled(true);
}
}
that shows that you have to check also, if BROWSE action is also supported.
use some thing like this
try {Desktop.getDesktop().browse(new URI("http://www.google.com"));
} catch (Exception e)
{JOptionPane.showMessageDialog(null,e);}
}
Related
I have browse button to browse for the file. After browsing there is a import button which will actually import the file.
I'm able to browse the path using the following code:
public static void uploadFiles(String object, String data) {
try {
String filemode="";
Capabilities cap = ((RemoteWebDriver) driver).getCapabilities();
String browsername = cap.getBrowserName();
//System.out.println(browsername);
if (browsername.contains("chrome")){
filemode= "Open";
}
else if (browsername.contains("firefox")){
filemode= "File Upload";
}
else if (browsername.contains("explorer")){
filemode = "Choose File to Upload";
}
String EXE_FILE=DriverScript.EXE_FILENAME;
String[] command={EXE_FILE,filemode,data};
Runtime.getRuntime().exec(command);
Thread.sleep(5000);
} catch (Exception e) {
}
}
But when I click on the import button after that "JavaScript error (WARNING: The server did not provide any stacktrace information)" exception is thrown. EXE_FILE is the path to Fileload.exe which is used for browsing
Uploading a file using Selenium:
WebElement upload = driver.findElement(By.id("identifier of input tag"));
upload.sendKeys("path to file");
Remove capability INTRODUCE_FLAKINESS_BY_IGNORING_SECURITY_DOMAINS if you're using it in your test code and manually set your IE protected mode settings to be the same for all zones.
It should fix the problem.
I'm getting a MalformedURLException some code in my Android Studio project. My aim is to get and display an image from a web page, and the URL seems to be fine, but it's giving me this error.
I have already put the code in a try,catch, but that is still giving me the error.
Here is the code to grab the image and display it:
try
{
url = new URL(items.get(position).getLink());
bmp = BitmapFactory.decodeStream(url.openConnection().getInputStream());
}
catch (IOException e)
{
throw new RuntimeException("Url Exception" + e);
}
holder.itemTitle.setText(items.get(position).getTitle());;
holder.itemHolder.setBackgroundDrawable(new BitmapDrawable(bmp));
items.get(position).getLink() is meant to get the link that is being displayed in a ListView, but even something like URL url = new URL("https://www.google.com") doesn't work.
Thanks.
your url is formatted without the protocol at the beginning try
url = new URL("http://"+items.get(position).getLink());
sometimes the url string may have special characters, in which case you need to encode it properly please see this.
And also, the url you posted in the comment is not an image.
it is exception beacuse of url class
add antoher catch like
catch (MalformedURLException e) {
e.printStackTrace();
}
Just click alt+enter and then import try catch section... this helped me...
I try to create a PDF with iText within my JSP-Application and want to insert an image.
The file is located in my webapp-directory under:
http://localhost:8087/Buran/Symbols/Logos/dobi1.jpg
It's no problem to use it in html or jsp-files but within the bean it just does not work. To get the correct path by trial and error I created a test-file to see from which directory I had to start. Unfortunately that's not really what I expected it to be:
./apache-tomcat-7.0.41/bin/testfile.test
I got a recommendation to use:
private final String dobiurl = "/Buran/Symbols/Logos/dobi1.jpg";
URLConnection connection;
/**/
try {
connection = new URL(dobiurl).openConnection();
} catch (IOException ex) {
Logger.getLogger(Etikette.class.getName()).log(Level.SEVERE, null, ex);
}
But just cause errors...
I'm creating a Java application using Netbeans. From the 'Help' Menu item, I'm required to open a PDF file. When I run the application via Netbeans, the document opens, but on opening via the jar file, it isn't opening. Is there anything that can be done?
m_aboutItem.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
Runtime rt = Runtime.getRuntime();
URL link2=getClass().getResource("/newpkg/Documentation.pdf");
String link=link2.toString();
link=link.substring(6);
System.out.println(link);
System.out.println(link2);
String link3="E:/new/build/classes/newpkg/Documentation.pdf";
try {
Process proc = rt.exec("rundll32.exe url.dll,FileProtocolHandler " + link3);
} catch (IOException ex) {
Logger.getLogger(Menubar1.class.getName()).log(Level.SEVERE, null, ex);
}
}
});
The two outputs are as follows:
E:/new/build/classes/newpkg/Documentation.pdf
file:/E:/new/build/classes/newpkg/Documentation.pdf
Consider the above code snippet. On printing 'link',we can see that it is exactly same as the hard coded 'link3'. On using the hard coded 'link3' , the PDF file gets opened from jar application. But when we use link, though it is exactly same as 'link3', the PDF doesn't open.
This is most likely related to the incorrect PDF resource loading. In the IDE you have the PDF file either as part of the project structure or with a directly specified relative path. When a packaged application is running it does not see the resource.
EDIT:
Your code reveals the problem as I have described. The following method could be used to properly identify resource path.
public static URL getURL(final String pathAndFileName) {
return Thread.currentThread().getContextClassLoader().getResource(pathAndFileName);
}
Pls refer to this question, which might provide additional information.
Try out this:
m_aboutItem.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
if (Desktop.isDesktopSupported()) {
Desktop desktop = Desktop.getDesktop();
URL link2=Menubar1.class.getResource("/newpkg/Documentation.pdf");
String link=link2.toString();
link=link.substring(6);
System.out.println(link);
File file=new File(link);
System.out.println(file);
try {
desktop.open(file);
} catch (IOException ex) {
Logger.getLogger(Menubar1.class.getName()).log(Level.SEVERE, null, ex);
}
}
}
});
I want to be able to launch native and J2ME applications through my application using the content handler API (JSR 211) on a Nokia 6212.
At the moment, I am unable to do so, as it always states that there is "No Content Handler Found" and throws a javax.microedition.content.ContentHandlerException.
At the moment, I am trying to get the phone to launch its browser and go to a certain website, just to test that I can use the framework. I have tried many different Invocation objects:
//throw exceptions
new Invocation("http://www.somesite.com/index.html",
"application/internet-shortcut");
new Invocation("http://www.google.co.uk","text/html");
// a long shot, I know
new Invocation("http://www.somesite.com/text.txt","text/plain");
// massive long shot
new Invocation("http://www.google.co.uk","application/browser");
//appears to download the link and content (and definitely does in the Nokia
// emulator) and then throws an exception
new Invocation("http://www.google.co.uk");
new Invocation("http://www.somesite.com/index.html");
Below is the code that I have been using, please bear in mind the parameters often changed to generate the different Invocation objects.
/*
* Invokes an application using the Content Handler API
*/
public void doInvoke(String url, String mime, String payload){
Registry register = Registry.getRegistry(this.getClass().getName());
Invocation invoke = new Invocation(url, mime, null, false,
ContentHandler.ACTION_OPEN);
boolean mustQuit = false;
try {
mustQuit = register.invoke(invoke);
} catch (IllegalArgumentException e) {
e.printStackTrace();
} catch (ContentHandlerException e) {
e.printStackTrace();
} catch (SecurityException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
if(mustQuit){
this.quit();
}
}
Try this:
Registry register = Registry.getRegistry(this.getClass().getName());
You must call Registry.getRegistry for the MIDlet inheritor. Just use your MIDlet for getting the class name.