How to access ResourceBundle in drl file? - java

I am trying to use ResourceBundle inside .drl file. But its throwing an exception like
`java.util.MissingResourceException: Can't find bundle for base name messages, locale en_US.`
My code is as follows
public class KnowledgeHelper {
#BeforeClass
public static KnowledgeBase getKnowledgeBase() throws Exception {
KnowledgeBuilder builder = KnowledgeBuilderFactory.newKnowledgeBuilder();
String droolsRuleFilePath = System.getenv("JBOSS_HOME") + "/pp-Conf/rules/Validator.drl";
builder.add(ResourceFactory.newFileResource(droolsRuleFilePath), ResourceType.DRL);
if (builder.hasErrors()) {
throw new RuntimeException(builder.getErrors().toString());
}
KnowledgeBaseConfiguration configuration = KnowledgeBaseFactory.newKnowledgeBaseConfiguration();
KnowledgeBase knowledgeBase = KnowledgeBaseFactory.newKnowledgeBase(configuration);
knowledgeBase.addKnowledgePackages(builder.getKnowledgePackages());
return knowledgeBase;
}
I am accessing this helper class to generate KnowledgeBase
I am creating the Knowledge session in my controller class as follows
knowledgeBase=knowledgeHelper.getKnowledgeBase();
knowledgeSession = knowledgeBase.newStatefulKnowledgeSession();
knowledgeSession.insert(olmvo);
knowledgeSession.insert(validationResponse1);
knowledgeSession.fireAllRules();
and my drl file is as follows
rule "OLM_PRODUCTION_VALIDATOR"
when
$olm : OLMVO(workflow.code == "OLM_PRODUCTION" ,workflow_type : workflow.processKey)
$validationResponse : ValidationResponse()
then
System.out.println("MESSAGE FILE-----"+EdgeAppConstant.EDGE_APP_MESSAGES_FILE);
ResourceBundle edgeappErrorBundle = ResourceBundle.getBundle(EdgeAppConstant.EDGE_APP_MESSAGES_FILE);
System.out.println("Workflow Type-----"+workflow_type);
end
I have imported all the classes that i'm using in this drl.
So i want to know how to access properties file directly inside .drl file.
Please Help!!

Related

How can I print the error message into a txt or json file in my directory?

I have a function that save all the error in a errormessage list
public class Util {
private List<String> errorMessages = new ArrayList<>();
public void outputResult(String content) {
logger.error(content);
errorMessages.add(content);
}
}
and my compare function add all the error message to the list,
public void compare(Config source, Config target) {
if (source.getId() != target.getId()) {
util.outputResult("id not equal");
}
// ...
}
And in my main function, I call this compare function and want to save all the error message in a txt or some other file in my current directory
public class MyClass {
public void main() {
compare();
// writeToFile
}
}
This is what I'm doing right now, I convert ByteArrayOutputStream to a string and print it, there a txt file generated but is empty, and I don't want to a string, I want each error message in the list be printed, how can I do that?
ByteArrayOutputStream errorMessages = new ByteArrayOutputStream();
try (FileWriter w = new FileWriter(pathToReport)) {
w.write(errorMessages.toString());
}
File errorMessagesFile = new File(pathToReport);
errorMessagesFile.writeText(errorMessages.toString());
What logger library that you are using? If you use sl4j, you can couple it with log4j by configuring properly to just log the error messages into the file that you have specified in the configuration. I've done some lookup and I find this stackoverflow: where-does-the-slf4j-log-file-get-saved answer provided a template for you to follow on with this setup.

Using M2Doc programmatically : Error in the generated .docx document

I'm trying to use M2Doc programmatically, I managed to generate my .docx file without getting errors in the validation part but I'm getting the following Error in the generated document:
{m:self.Name} Couldn't find the 'aqlFeatureAccess(org.eclipse.emf.common.util.URI.Hierarchical,java.lang.String)' service
The "self.Name" part is what I wrote in my template.
I think I'm lacking some kind of reference to a service but I don't know how to fix it.
The self variable is a reference to a model based on a meta-model I created. But I'm not sure I imported it correctly in my code.
I based my code on the code I found on the M2Doc website + some code I found on their GitHub, especially concerning how to add a service in the queryEnvironment.
I searched in the source code of acceleo and M2Doc to see which services they add but it seems that they already import all the services I'm using.
As I said, the validation part is going well and doesn't generate a validation file.
public static void parseDocument(String templateName) throws Exception{
final URI templateURI = URI.createFileURI("Template/"+templateName+"."+M2DocUtils.DOCX_EXTENSION_FILE);
final IQueryEnvironment queryEnvironment =
org.eclipse.acceleo.query.runtime.Query.newEnvironmentWithDefaultServices(null);
final Map<String, String> options = new HashMap<>(); // can be empty
M2DocUtils.prepareEnvironmentServices(queryEnvironment, templateURI, options); // delegate to IServicesConfigurator
prepareEnvironmentServicesCustom(queryEnvironment, options);
final IClassProvider classProvider = new ClassProvider(ClassLoader.getSystemClassLoader()); // use M2DocPlugin.getClassProvider() when running inside Eclipse
try (DocumentTemplate template = M2DocUtils.parse(templateURI, queryEnvironment, classProvider)) {
ValidationMessageLevel validationLevel = validateDocument(template, queryEnvironment, templateName);
if(validationLevel == ValidationMessageLevel.OK){
generateDocument(template, queryEnvironment, templateName, "Model/ComplexKaosModel.kaos");
}
}
}
public static void prepareEnvironmentServicesCustom(IQueryEnvironment queryEnvironment, Map<String, String> options){
Set<IService> services = ServiceUtils.getServices(queryEnvironment, FilterService.class);
ServiceUtils.registerServices(queryEnvironment, services);
M2DocUtils.getConfigurators().forEach((configurator) -> {
ServiceUtils.registerServices(queryEnvironment, configurator.getServices(queryEnvironment, options));
});
}
public static void generateDocument(DocumentTemplate template, IQueryEnvironment queryEnvironment,
String templateName, String modelPath)throws Exception{
final Map<String, Object> variable = new HashMap<>();
variable.put("self", URI.createFileURI(modelPath));
final Monitor monitor = new BasicMonitor.Printing(System.out);
final URI outputURI = URI.createFileURI("Generated/"+templateName+".generated."+M2DocUtils.DOCX_EXTENSION_FILE);
M2DocUtils.generate(template, queryEnvironment, variable, outputURI, monitor);
}
The variable "self" contains an URI:
variable.put("self", URI.createFileURI(modelPath));
You have to load your model and set the value of self to an element from your model using something like:
final ResourceSet rs = new ResourceSetImpl();
final Resource r = rs.getResource(uri, true);
final EObject value = r.getContents()...;
variable.put("self", value);
You can get more details on resource loading in the EMF documentation.

Test File Selection with JUnit/JMockit

I am attempting to test a method that returns a File object using JUnit and JMockit. I am a beginner with both of these.
The problem I am having is that I can't figure out how to properly/successfully mock the implementation method returning a file, since in reality, the user has to actually select a file for the method to return. The error I keep running into is:
java.lang.IllegalStateException: Missing invocation to mocked type at this point; please make sure such invocations appear only after the declaration of a suitable mock field or parameter
Any suggestions?
Here is a recreation of my implementation:
public final class MyClass {
public static File OpenFile(Stage stage, String title, String fileTypeText, ArrayList<String> fileType) throws Exception {
File file = null;
try {
FileChooser fileChooser = new FileChooser();
fileChooser.setTitle(title);
FileChooser.ExtensionFilter extFilter = new FileChooser.ExtensionsFilter(fileTypeText + fileType, fileType);
fileChooser.getExtensionsFilters().add(extFilter);
file = fileChooser.showOpenDialog(stage);
return file;
}
catc (Exception e) {
if(fileType==null) {
...
}
return file;
}
}
}
Here is a recreation of my attempted JUnit test:
#Test
public void TestOpenFile(#Mocked Stage stage) throws Exception {
final ArrayList<String> extensions = new ArrayList<String>();
extensions.add(".txt");
final File file = null;
new Expectations() {{
MyClass.OpenFile(stage, anyString, anyString, extensions); returns(file);
}};
assertEquals(file, MyClass.OpenFile(stage, "some title", "some type", extensions));
}
Your solution is correct, but I would use expectations instead:
public void TestOpenFile(#Mocked FileChooser chooser) throws Exception{
new Expectations() {
{
chooser.showOpenDialog(stage); result = expectedFile;
}};
final File actualFile = MyClass.OpenFile(...);
assertEquals(expectedFile, actualFile);}
I find this easier to understand and write (my personal preference)
I realized that I was approaching the problem incorrectly at first. What I did to resolve this was:
Mock the FileChooser.showOpenDialog method to return a file instead of trying to mock my own method to return a file, which would have defeated the purpose of testing.
final File expectedFile = new File("abc");
new MockUp<FileChooser>() {
#Mock
File showOpenDialog(final Window overWindow) {
return expectedFile;
}
};
final File actualFile = MyClass.OpenFile(...);
assertEquals(expectedFile, actualFile);

How to list the files inside a JAR file?

I have this code which reads all the files from a directory.
File textFolder = new File("text_directory");
File [] texFiles = textFolder.listFiles( new FileFilter() {
public boolean accept( File file ) {
return file.getName().endsWith(".txt");
}
});
It works great. It fills the array with all the files that end with ".txt" from directory "text_directory".
How can I read the contents of a directory in a similar fashion within a JAR file?
So what I really want to do is, to list all the images inside my JAR file, so I can load them with:
ImageIO.read(this.getClass().getResource("CompanyLogo.png"));
(That one works because the "CompanyLogo" is "hardcoded" but the number of images inside the JAR file could be from 10 to 200 variable length.)
EDIT
So I guess my main problem would be: How to know the name of the JAR file where my main class lives?
Granted I could read it using java.util.Zip.
My Structure is like this:
They are like:
my.jar!/Main.class
my.jar!/Aux.class
my.jar!/Other.class
my.jar!/images/image01.png
my.jar!/images/image02a.png
my.jar!/images/imwge034.png
my.jar!/images/imagAe01q.png
my.jar!/META-INF/manifest
Right now I'm able to load for instance "images/image01.png" using:
ImageIO.read(this.getClass().getResource("images/image01.png));
But only because I know the file name, for the rest I have to load them dynamically.
CodeSource src = MyClass.class.getProtectionDomain().getCodeSource();
if (src != null) {
URL jar = src.getLocation();
ZipInputStream zip = new ZipInputStream(jar.openStream());
while(true) {
ZipEntry e = zip.getNextEntry();
if (e == null)
break;
String name = e.getName();
if (name.startsWith("path/to/your/dir/")) {
/* Do something with this entry. */
...
}
}
}
else {
/* Fail... */
}
Note that in Java 7, you can create a FileSystem from the JAR (zip) file, and then use NIO's directory walking and filtering mechanisms to search through it. This would make it easier to write code that handles JARs and "exploded" directories.
Code that works for both IDE's and .jar files:
import java.io.*;
import java.net.*;
import java.nio.file.*;
import java.util.*;
import java.util.stream.*;
public class ResourceWalker {
public static void main(String[] args) throws URISyntaxException, IOException {
URI uri = ResourceWalker.class.getResource("/resources").toURI();
Path myPath;
if (uri.getScheme().equals("jar")) {
FileSystem fileSystem = FileSystems.newFileSystem(uri, Collections.<String, Object>emptyMap());
myPath = fileSystem.getPath("/resources");
} else {
myPath = Paths.get(uri);
}
Stream<Path> walk = Files.walk(myPath, 1);
for (Iterator<Path> it = walk.iterator(); it.hasNext();){
System.out.println(it.next());
}
}
}
erickson's answer worked perfectly:
Here's the working code.
CodeSource src = MyClass.class.getProtectionDomain().getCodeSource();
List<String> list = new ArrayList<String>();
if( src != null ) {
URL jar = src.getLocation();
ZipInputStream zip = new ZipInputStream( jar.openStream());
ZipEntry ze = null;
while( ( ze = zip.getNextEntry() ) != null ) {
String entryName = ze.getName();
if( entryName.startsWith("images") && entryName.endsWith(".png") ) {
list.add( entryName );
}
}
}
webimages = list.toArray( new String[ list.size() ] );
And I have just modify my load method from this:
File[] webimages = ...
BufferedImage image = ImageIO.read(this.getClass().getResource(webimages[nextIndex].getName() ));
To this:
String [] webimages = ...
BufferedImage image = ImageIO.read(this.getClass().getResource(webimages[nextIndex]));
I would like to expand on acheron55's answer, since it is a very non-safe solution, for several reasons:
It doesn't close the FileSystem object.
It doesn't check if the FileSystem object already exists.
It isn't thread-safe.
This is somewhat a safer solution:
private static ConcurrentMap<String, Object> locks = new ConcurrentHashMap<>();
public void walk(String path) throws Exception {
URI uri = getClass().getResource(path).toURI();
if ("jar".equals(uri.getScheme()) {
safeWalkJar(path, uri);
} else {
Files.walk(Paths.get(path));
}
}
private void safeWalkJar(String path, URI uri) throws Exception {
synchronized (getLock(uri)) {
// this'll close the FileSystem object at the end
try (FileSystem fs = getFileSystem(uri)) {
Files.walk(fs.getPath(path));
}
}
}
private Object getLock(URI uri) {
String fileName = parseFileName(uri);
locks.computeIfAbsent(fileName, s -> new Object());
return locks.get(fileName);
}
private String parseFileName(URI uri) {
String schemeSpecificPart = uri.getSchemeSpecificPart();
return schemeSpecificPart.substring(0, schemeSpecificPart.indexOf("!"));
}
private FileSystem getFileSystem(URI uri) throws IOException {
try {
return FileSystems.getFileSystem(uri);
} catch (FileSystemNotFoundException e) {
return FileSystems.newFileSystem(uri, Collections.<String, String>emptyMap());
}
}
There's no real need to synchronize over the file name; one could simply synchronize on the same object every time (or make the method synchronized), it's purely an optimization.
I would say that this is still a problematic solution, since there might be other parts in the code that use the FileSystem interface over the same files, and it could interfere with them (even in a single threaded application).
Also, it doesn't check for nulls (for instance, on getClass().getResource().
This particular Java NIO interface is kind of horrible, since it introduces a global/singleton non thread-safe resource, and its documentation is extremely vague (a lot of unknowns due to provider specific implementations). Results may vary for other FileSystem providers (not JAR). Maybe there's a good reason for it being that way; I don't know, I haven't researched the implementations.
So I guess my main problem would be, how to know the name of the jar where my main class lives.
Assuming that your project is packed in a Jar (not necessarily true!), you can use ClassLoader.getResource() or findResource() with the class name (followed by .class) to get the jar that contains a given class. You'll have to parse the jar name from the URL that gets returned (not that tough), which I will leave as an exercise for the reader :-)
Be sure to test for the case where the class is not part of a jar.
I've ported acheron55's answer to Java 7 and closed the FileSystem object. This code works in IDE's, in jar files and in a jar inside a war on Tomcat 7; but note that it does not work in a jar inside a war on JBoss 7 (it gives FileSystemNotFoundException: Provider "vfs" not installed, see also this post). Furthermore, like the original code, it is not thread safe, as suggested by errr. For these reasons I have abandoned this solution; however, if you can accept these issues, here is my ready-made code:
import java.io.IOException;
import java.net.*;
import java.nio.file.*;
import java.nio.file.attribute.BasicFileAttributes;
import java.util.Collections;
public class ResourceWalker {
public static void main(String[] args) throws URISyntaxException, IOException {
URI uri = ResourceWalker.class.getResource("/resources").toURI();
System.out.println("Starting from: " + uri);
try (FileSystem fileSystem = (uri.getScheme().equals("jar") ? FileSystems.newFileSystem(uri, Collections.<String, Object>emptyMap()) : null)) {
Path myPath = Paths.get(uri);
Files.walkFileTree(myPath, new SimpleFileVisitor<Path>() {
#Override
public FileVisitResult visitFile(Path file, BasicFileAttributes attrs) throws IOException {
System.out.println(file);
return FileVisitResult.CONTINUE;
}
});
}
}
}
Here is an example of using Reflections library to recursively scan classpath by regex name pattern augmented with a couple of Guava perks to to fetch resources contents:
Reflections reflections = new Reflections("com.example.package", new ResourcesScanner());
Set<String> paths = reflections.getResources(Pattern.compile(".*\\.template$"));
Map<String, String> templates = new LinkedHashMap<>();
for (String path : paths) {
log.info("Found " + path);
String templateName = Files.getNameWithoutExtension(path);
URL resource = getClass().getClassLoader().getResource(path);
String text = Resources.toString(resource, StandardCharsets.UTF_8);
templates.put(templateName, text);
}
This works with both jars and exploded classes.
Here's a method I wrote for a "run all JUnits under a package". You should be able to adapt it to your needs.
private static void findClassesInJar(List<String> classFiles, String path) throws IOException {
final String[] parts = path.split("\\Q.jar\\\\E");
if (parts.length == 2) {
String jarFilename = parts[0] + ".jar";
String relativePath = parts[1].replace(File.separatorChar, '/');
JarFile jarFile = new JarFile(jarFilename);
final Enumeration<JarEntry> entries = jarFile.entries();
while (entries.hasMoreElements()) {
final JarEntry entry = entries.nextElement();
final String entryName = entry.getName();
if (entryName.startsWith(relativePath)) {
classFiles.add(entryName.replace('/', File.separatorChar));
}
}
}
}
Edit:
Ah, in that case, you might want this snippet as well (same use case :) )
private static File findClassesDir(Class<?> clazz) {
try {
String path = clazz.getProtectionDomain().getCodeSource().getLocation().getFile();
final String codeSourcePath = URLDecoder.decode(path, "UTF-8");
final String thisClassPath = new File(codeSourcePath, clazz.getPackage().getName().repalce('.', File.separatorChar));
} catch (UnsupportedEncodingException e) {
throw new AssertionError("impossible", e);
}
}
Just to mention that if you are already using Spring, you can take advantage of the PathMatchingResourcePatternResolver.
For instance to get all the PNG files from a images folder in resources
ClassLoader cl = this.getClass().getClassLoader();
ResourcePatternResolver resolver = new PathMatchingResourcePatternResolver(cl);
Resource[] resources = resolver.getResources("images/*.png");
for (Resource r: resources){
logger.info(r.getFilename());
// From your example
// ImageIO.read(cl.getResource("images/" + r.getFilename()));
}
A jar file is just a zip file with a structured manifest. You can open the jar file with the usual java zip tools and scan the file contents that way, inflate streams, etc. Then use that in a getResourceAsStream call, and it should be all hunky dory.
EDIT / after clarification
It took me a minute to remember all the bits and pieces and I'm sure there are cleaner ways to do it, but I wanted to see that I wasn't crazy. In my project image.jpg is a file in some part of the main jar file. I get the class loader of the main class (SomeClass is the entry point) and use it to discover the image.jpg resource. Then some stream magic to get it into this ImageInputStream thing and everything is fine.
InputStream inputStream = SomeClass.class.getClassLoader().getResourceAsStream("image.jpg");
JPEGImageReaderSpi imageReaderSpi = new JPEGImageReaderSpi();
ImageReader ir = imageReaderSpi.createReaderInstance();
ImageInputStream iis = new MemoryCacheImageInputStream(inputStream);
ir.setInput(iis);
....
ir.read(0); //will hand us a buffered image
Given an actual JAR file, you can list the contents using JarFile.entries(). You will need to know the location of the JAR file though - you can't just ask the classloader to list everything it could get at.
You should be able to work out the location of the JAR file based on the URL returned from ThisClassName.class.getResource("ThisClassName.class"), but it may be a tiny bit fiddly.
Some time ago I made a function that gets classess from inside JAR:
public static Class[] getClasses(String packageName)
throws ClassNotFoundException{
ArrayList<Class> classes = new ArrayList<Class> ();
packageName = packageName.replaceAll("\\." , "/");
File f = new File(jarName);
if(f.exists()){
try{
JarInputStream jarFile = new JarInputStream(
new FileInputStream (jarName));
JarEntry jarEntry;
while(true) {
jarEntry=jarFile.getNextJarEntry ();
if(jarEntry == null){
break;
}
if((jarEntry.getName ().startsWith (packageName)) &&
(jarEntry.getName ().endsWith (".class")) ) {
classes.add(Class.forName(jarEntry.getName().
replaceAll("/", "\\.").
substring(0, jarEntry.getName().length() - 6)));
}
}
}
catch( Exception e){
e.printStackTrace ();
}
Class[] classesA = new Class[classes.size()];
classes.toArray(classesA);
return classesA;
}else
return null;
}
public static ArrayList<String> listItems(String path) throws Exception{
InputStream in = ClassLoader.getSystemClassLoader().getResourceAsStream(path);
byte[] b = new byte[in.available()];
in.read(b);
String data = new String(b);
String[] s = data.split("\n");
List<String> a = Arrays.asList(s);
ArrayList<String> m = new ArrayList<>(a);
return m;
}
There are two very useful utilities both called JarScan:
www.inetfeedback.com/jarscan
jarscan.dev.java.net
See also this question: JarScan, scan all JAR files in all subfolders for specific class
The most robust mechanism for listing all resources in the classpath is currently to use this pattern with ClassGraph, because it handles the widest possible array of classpath specification mechanisms, including the new JPMS module system. (I am the author of ClassGraph.)
How to know the name of the JAR file where my main class lives?
URI mainClasspathElementURI;
try (ScanResult scanResult = new ClassGraph().whitelistPackages("x.y.z")
.enableClassInfo().scan()) {
mainClasspathElementURI =
scanResult.getClassInfo("x.y.z.MainClass").getClasspathElementURI();
}
How can I read the contents of a directory in a similar fashion within a JAR file?
List<String> classpathElementResourcePaths;
try (ScanResult scanResult = new ClassGraph().overrideClasspath(mainClasspathElementURI)
.scan()) {
classpathElementResourcePaths = scanResult.getAllResources().getPaths();
}
There are lots of other ways to deal with resources too.
One more for the road that's a bit more flexible for matching specific filenames because it uses wildcard globbing. In a functional style this could resemble:
import java.io.IOException;
import java.net.URISyntaxException;
import java.nio.file.FileSystem;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
import java.util.function.Consumer;
import static java.nio.file.FileSystems.getDefault;
import static java.nio.file.FileSystems.newFileSystem;
import static java.util.Collections.emptyMap;
/**
* Responsible for finding file resources.
*/
public class ResourceWalker {
/**
* Globbing pattern to match font names.
*/
public static final String GLOB_FONTS = "**.{ttf,otf}";
/**
* #param directory The root directory to scan for files matching the glob.
* #param c The consumer function to call for each matching path
* found.
* #throws URISyntaxException Could not convert the resource to a URI.
* #throws IOException Could not walk the tree.
*/
public static void walk(
final String directory, final String glob, final Consumer<Path> c )
throws URISyntaxException, IOException {
final var resource = ResourceWalker.class.getResource( directory );
final var matcher = getDefault().getPathMatcher( "glob:" + glob );
if( resource != null ) {
final var uri = resource.toURI();
final Path path;
FileSystem fs = null;
if( "jar".equals( uri.getScheme() ) ) {
fs = newFileSystem( uri, emptyMap() );
path = fs.getPath( directory );
}
else {
path = Paths.get( uri );
}
try( final var walk = Files.walk( path, 10 ) ) {
for( final var it = walk.iterator(); it.hasNext(); ) {
final Path p = it.next();
if( matcher.matches( p ) ) {
c.accept( p );
}
}
} finally {
if( fs != null ) { fs.close(); }
}
}
}
}
Consider parameterizing the file extensions, left an exercise for the reader.
Be careful with Files.walk. According to the documentation:
This method must be used within a try-with-resources statement or similar control structure to ensure that the stream's open directories are closed promptly after the stream's operations have completed.
Likewise, newFileSystem must be closed, but not before the walker has had a chance to visit the file system paths.
Just a different way of listing/reading files from a jar URL and it does it recursively for nested jars
https://gist.github.com/trung/2cd90faab7f75b3bcbaa
URL urlResource = Thead.currentThread().getContextClassLoader().getResource("foo");
JarReader.read(urlResource, new InputStreamCallback() {
#Override
public void onFile(String name, InputStream is) throws IOException {
// got file name and content stream
}
});

Spring - validate that all message resources are well configured

We need to add some code to be executed on application load in order to validate that all the messages.properties elements are well defined for all languages.
Is this possible?
Steps: dynamically read on application load all the spring message codes from JSP or java classes then pass through all message resources properties files and validate that nothing is missing from them.
We ended up doing this manually but without using any library.
Steps:
have all the keys used in Java classes or JSP defined in a constant file
Read them using Java .class properties:
Field[] fields = Constants.class.getFields();
String filed[i].get(Constants.class);
Read all messageResources.properties file names from the project using:
String pathToThisClass = MessageResourcesValidator.class.getProtectionDomain().getCodeSource().getLocatin().getPath();
File filePath = new File(pathToThisClass);
String[] list = filePath.list(new DirFilter("(messages).*\\.(properties)"));
DirFilter is a normal class implementing Java's FileNameFilter
Create a class that read the properties from a file using its file name:
public class PropertiesFile{
private Properties prop;
public PropertiesFile(String fileName) throws Exception
{
init(fileName);
}
private void init(String fileName) throws Exception
{
prop = new Properties();
try (InputStream input = getClass().getClassLoader().getResourceAsStream(fileName);)
{
if(input == null)
{
throw new Exception("Enable to load properties file " + fileName);
}
prop.load(input);
}
catch(IOException e)
{
throw new Exception("Error loading properties file " + fileName);
}
}
public List<String> getPropertiesKeysList()
{
List<String> result = new ArrayList<>();
Enumeration<?> e = prop.propertyNames();
while(e.hasMoreElements())
{
result.add((String) e.nextElement());
// String value = prop.getProperty(key);
}
return result;
}
}
The part that does the comparison should be something as the following code that calls the above methods:
List<String> msgResourcesFiles = getMessageResourcesFileNames();
List<String> codeKeys = getListOfCodeMessageResources();
PropertiesFile file = null;
List<String> propKeys = null;
for(String fileName : msgResourcesFiles)
{
file = new PropertiesFile(fileName);
propKeys = file.getPropertiesKeysList();
for(String key : codeKeys)
{
if(!propKeys.contains(key))
{
throw new Exception("Missing key " + key);
}
}
}
Note: or another workaround would be to compare all message resources files to a default one and this way we minimize the code needed from the above explanation.

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