We Keep Coding

Xpages - Passing <ahref> in Arraylist

I'm trying to add a href to Arraylist and this adds nicely to the Arraylist, but the link is broken. Everything after the question mark (?) in the URL is not included in the link.
Is there anything that I'm missing, code below:
private String processUpdate(Database dbCurrent) throws NotesException {
int intCountSuccessful = 0;
View vwLookup = dbCurrent.getView("DocsDistribution");
ArrayList<String> listArray = new ArrayList<String>();
Document doc = vwLookup.getFirstDocument();
while (doc != null) {
String paperDistro = doc.getItemValueString("DistroRecords");
if (paperDistro.equals("")) {
String ref = doc.getItemValueString("ref");
String unid = doc.getUniversalID();
// the link generated when adding to Arraylist is broken
listArray.add("" + ref + "");
}
Document tmppmDoc = vwLookup.getNextDocument(doc);
doc.recycle();
doc = tmppmDoc;
}
Collections.sort(listArray);
String listString = "";
for (String s : listArray) {
listString += s + ", \t";
}
return listString;
}

You have a problem with " escaping around unid value due to which you URL becomes gandhi.w3schools.com/testbox.nsf/distro.xsp?documentId="+ unid + "&action=openDocument.
It would be easier to read if you use String.format() and single quotes to generate the a tag:
listArray.add(String.format(
"<a href='gandhi.w3schools.com/testbox.nsf/distro.xsp?documentId=%s&action=openDocument'>%s</a>",
unid, ref));

Java + MongoDB: how get a nested field value using complete path?

I have this path for a MongoDB field main.inner.leaf and every field couldn't be present.
In Java I should write, avoiding null:
String leaf = "";
if (document.get("main") != null &&
document.get("main", Document.class).get("inner") != null) {
leaf = document.get("main", Document.class)
.get("inner", Document.class).getString("leaf");
}
In this simple example I set only 3 levels: main, inner and leaf but my documents are deeper.
So is there a way avoiding me writing all these null checks?
Like this:
String leaf = document.getString("main.inner.leaf", "");
// "" is the deafult value if one of the levels doesn't exist
Or using a third party library:
String leaf = DocumentUtils.getNullCheck("main.inner.leaf", "", document);
Many thanks.

Since the intermediate attributes are optional you really have to access the leaf value in a null safe manner.
You could do this yourself using an approach like ...
if (document.containsKey("main")) {
Document _main = document.get("main", Document.class);
if (_main.containsKey("inner")) {
Document _inner = _main.get("inner", Document.class);
if (_inner.containsKey("leaf")) {
leafValue = _inner.getString("leaf");
}
}
}
Note: this could be wrapped up in a utility to make it more user friendly.
Or use a thirdparty library such as Commons BeanUtils.
But, you cannot avoid null safe checks since the document structure is such that the intermediate levels might be null. All you can do is to ease the burden of handling the null safety.
Here's an example test case showing both approaches:
#Test
public void readNestedDocumentsWithNullSafety() throws IllegalAccessException, NoSuchMethodException, InvocationTargetException {
Document inner = new Document("leaf", "leafValue");
Document main = new Document("inner", inner);
Document fullyPopulatedDoc = new Document("main", main);
assertThat(extractLeafValueManually(fullyPopulatedDoc), is("leafValue"));
assertThat(extractLeafValueUsingThirdPartyLibrary(fullyPopulatedDoc, "main.inner.leaf", ""), is("leafValue"));
Document emptyPopulatedDoc = new Document();
assertThat(extractLeafValueManually(emptyPopulatedDoc), is(""));
assertThat(extractLeafValueUsingThirdPartyLibrary(emptyPopulatedDoc, "main.inner.leaf", ""), is(""));
Document emptyInner = new Document();
Document partiallyPopulatedMain = new Document("inner", emptyInner);
Document partiallyPopulatedDoc = new Document("main", partiallyPopulatedMain);
assertThat(extractLeafValueManually(partiallyPopulatedDoc), is(""));
assertThat(extractLeafValueUsingThirdPartyLibrary(partiallyPopulatedDoc, "main.inner.leaf", ""), is(""));
}
private String extractLeafValueUsingThirdPartyLibrary(Document document, String path, String defaultValue) {
try {
Object value = PropertyUtils.getNestedProperty(document, path);
return value == null ? defaultValue : value.toString();
} catch (Exception ex) {
return defaultValue;
}
}
private String extractLeafValueManually(Document document) {
Document inner = getOrDefault(getOrDefault(document, "main"), "inner");
return inner.get("leaf", "");
}
private Document getOrDefault(Document document, String key) {
if (document.containsKey(key)) {
return document.get(key, Document.class);
} else {
return new Document();
}
}

How to update a record after extracting

private List<String> getSCFData(int trdCustomerKy, Date lastRunDate, Date currentDate) throws TradeException {
List<String> reportData = null;
String paymentDate = EMPTY_STRING;
String partyId = EMPTY_STRING;
YOWDAO hdDAO = new YOWDAO(mConnection);
List<YOWSCFExtractData> reportItems = hdDAO.getSCFData(trdCustomerKy, lastRunDate, currentDate);
if (null != reportItems && reportItems.size() > 0) {
reportData = new ArrayList<String>();
mTracer.log("Total records retrieved: " + reportItems.size());
for (YOWSCFExtractData data : reportItems) {
String Source = (null != data.getSource()) ? data.getSource() : BLANK_STRING;
String paymentCurrencyCd = (null != data.getPaymentCurrencyCd()) ? data.getPaymentCurrencyCd()
: BLANK_STRING;
String sellerName = (null != data.getSellerName()) ? data.getSellerName() : BLANK_STRING;
String paymentAmount = (null != data.getPaymentAmount()) ? data.getPaymentAmount() : BLANK_STRING;
if (null != data.getPaymentDate()) {
paymentDate = DateUtil.formatDate(data.getPaymentDate());
}
if (null != data.getapplCifId()) {
partyId = hdDAO.getPartyId(mConfiguration.getCustomerKy(), data.getapplCifId());
}
String dataRow = StringUtils.join(new String[] { Source, data.getBankRef(), partyId, sellerName,
data.getPartyId(), paymentAmount, paymentDate, paymentCurrencyCd}, COMMA);
reportData.add(dataRow);
}
}
return reportData;
}
I am extracting the data from oracle database. I want to update the record of a column once it is fetched to a string. for example when I had extracted data.getBanref() then I want to set it some string back in database. how would I do that? I am using hibernate........

What you can do is set the object data whatever values you want and then save it in the hibernate. If you want to update then use session.saveOrUpdate() or if you want to save a new record then use session.save(). Hope that helps!

You can write a hibernate query
Update table_Name column_Name and set it to whatever you want and call this query in your program. It will be easier i think so

Hibernate query restrictions using URL key/value style parameters

I'm using Tapestry5 and Hibernate. I'm trying to build a criteria query that uses dynamic restrictions generated from the URL. My URL context is designed like a key/value pair.
Example
www.mywebsite.com/make/ford/model/focus/year/2009
I decode the parameters as followed
private Map<String, String> queryParameters;
private List<Vehicle> vehicles;
void onActivate(EventContext context) {
//Count is 6 - make/ford/model/focus/year/2009
int count = context.getCount();
if (count > 0) {
int i;
for (i = 0; (i + 1) < count; i += 2) {
String name = context.get(String.class, i);
String value = context.get(String.class, i + 1);
example "make"
System.out.println("name " + name);
example "ford"
System.out.println("value " + value);
this.queryParameters.put(name, value);
}
}
this.vehicles = this.session.createCriteria(Vehicle.class)
...add dynamic restrictions.
}
I was hoping someone could help me to figure out how to dynamically add the list of restrictions to my query. I'm sure this has been done, so if anybody knows of a post, that would be helpful too. Thanks

Exactly as the other answer said, but here more spelt out. I think the crux of your question is really 'show me how to add a restriction'. That is my interpretation anyhow.
You need to decode each restriction into its own field.
You need to know the Java entity property name for each field.
Then build a Map of these 2 things, the key is the known static Java entity property name and the value is the URL decoded data (possibly with type conversion).
private Map<String, Object> queryParameters;
private List<Vehicle> vehicles;
void onActivate(EventContext context) {
//Count is 6 - make/ford/model/focus/year/2009
int count = context.getCount();
queryParameters = new HashMap<String,Object>();
if (count > 0) {
int i;
for (i = 0; (i + 1) < count; i += 2) {
String name = context.get(String.class, i);
String value = context.get(String.class, i + 1);
Object sqlValue = value;
if("foobar".equals(name)) {
// sometime you don't want a String type for SQL compasition
// so convert it
sqlValue = UtilityClass.doTypeConversionForFoobar(value);
} else if("search".equals(name) ||
"model".equals(name) ||
"year".equals(name)) {
// no-op this is valid 'name'
} else if("make".equals(name)) {
// this is a suggestion depends on your project conf
name = "vehicleMake.name";
} else {
continue; // ignore values we did not expect
}
// FIXME: You should validate all 'name' values
// to be valid and/or convert to Java property names here
System.out.println("name " + name);
System.out.println("value " + value);
this.queryParameters.put(name, sqlValue);
}
}
Criteria crit = this.session.createCriteria(Vehicle.class)
for(Map.Entry<String,Object> e : this.queryParameters.entrySet()) {
String n = e.getKey();
Object v = e.getValue();
// Sometimes you don't want a direct compare 'Restructions.eq()'
if("search".equals(n))
crit.add(Restrictions.like(n, "%" + v + "%"));
else // Most of the time you do
crit.add(Restrictions.eq(n, v));
}
this.vehicles = crit.list(); // run query
}
See also https://docs.jboss.org/hibernate/orm/3.5/reference/en/html/querycriteria.html
With the above there should be no risk of SQL injection, since the "name" and "n" part should be 100% validated against a known good list. The "value" and "v" is correctly escaped, just like using SQL position placeholder '?'.
E&OE

I would assume you would just loop over the parameters Map and add a Restriction for each pair.
Be aware that this will open you up to sql injection attacks if you are not careful. the easiest way to protect against this would be to check the keys against the known Vehicle properties before adding to the Criteria.

Another option would be to create an example query by building an object from the name/value pairs:
Vehicle vehicle = new Vehicle();
int count = context.getCount();
int i;
for (i = 0; (i + 1) < count; i += 2) {
String name = context.get(String.class, i);
String value = context.get(String.class, i + 1);
// This will call the setter for the name, passing the value
// So if name is 'make' and value is 'ford', it will call vehicle.setMake('ford')
BeantUtils.setProperty(vehicle, name, value);
}
// This is using a Hibernate example query:
vehicles = session.createCriteria(Vehicle.class).add(Example.create(vehicle)).list();
See BeanUtils.setProperty and Example Queries for more info.
That assumes you are allowing only one value per property and that the query parameters map to the property names correctly. There may also be conversion issues to think about but I think setProperty handles the common ones.

If they are query paramaters you should treat them as query parameters instead of path parameters. Your URL should look something like:
www.mywebsite.com/vehicles?make=ford&model=focus&year=2009
and your code should look something like this:
public class Vehicles {
#ActivationRequestParameter
private String make;
#ActivationRequestParameter
private String model;
#ActivationRequestParameter
private String year;
#Inject
private Session session;
#OnEvent(EventConstants.ACTIVATE)
void activate() {
Criteria criteria = session.createCriteria(Vehicle.class);
if (make != null) criteria.add(Restrictions.eq("make", make));
if (model != null) criteria.add(Restrictions.eq("model", model));
if (year != null) criteria.add(Restrictions.eq("year", year));
vehicles = criteria.list();
}
}
Assuming you are using the Grid component to display the vehicles I'd highly recommend using the HibernateGridDataSource instead of making the query in the "activate" event handler.
public class Vehicles {
#ActivationRequestParameter
private String make;
#ActivationRequestParameter
private String model;
#ActivationRequestParameter
private String year;
#Inject
private Session session;
#OnEvent(EventConstants.ACTIVATE)
void activate() {
}
public GridDataSource getVehicles() {
return new HibernateGridDataSource(session, Vehicles.class) {
#Override
protected void applyAdditionalConstraints(Criteria criteria) {
if (make != null) criteria.add(Restrictions.eq("make", make));
if (model != null) criteria.add(Restrictions.eq("model", model));
if (year != null) criteria.add(Restrictions.eq("year", year));
}
};
}
}

Simplest way to strip an int out of a URL in Java?

I have a String containing a URL. I want to get just one piece of data out of it: an int that should be showing up in the query string.
So if the url is:
http://domain.tld/page.html?iVar=123
I want to get "123" into an int.
What's the most elegant way you know to do this?

You could try matching just that parameter in the URL string:
public static Integer getIVarParamValue(String urlStr) {
Pattern p = Pattern.compile("iVar=(\\d+)");
Matcher m = p.matcher(urlStr);
if (m.find()) {
return Integer.parseInt(m.group(1));
}
return null;
}

It seems you want to obtain get parameters and parse them. I have this method here (got it from somewhere on SO, I guess):
public static Map<String, List<String>> getQueryParams(String url) {
try {
Map<String, List<String>> params = new HashMap<String, List<String>>();
String[] urlParts = url.split("\\?");
if (urlParts.length > 1) {
String query = urlParts[1];
for (String param : query.split("&")) {
String[] pair = param.split("=");
String key = URLDecoder.decode(pair[0], "UTF-8");
String value = "";
if (pair.length > 1) {
value = URLDecoder.decode(pair[1], "UTF-8");
}
List<String> values = params.get(key);
if (values == null) {
values = new ArrayList<String>();
params.put(key, values);
}
values.add(value);
}
}
return params;
} catch (UnsupportedEncodingException ex) {
throw new AssertionError(ex);
}
}
So:
String var = WebUtils.getQueryParams(url).get("iVar");
int intVar = Integer.parseInt(var);

You can use the URL class.
i.e.:
URL myUrl = new URL("http://domain.tld/page.html?iVar=123");
String query = myUrl.getQuery(); //this will return iVar=123
//at this point you can either parse it manually (i.e. use some of the regexp in the other suggestions, or use something like:
String[] parts = query.split();
String variable = parts[0];
String value = parts[1];
This will work only for this case though and won't work if you have additional params or no params.
There are a number of solution that will split it into a param map online, you can see some here.

If it's really as simple as you describe: There is only 1 int in your URL and all you want is that int, I'd go for a regular expression. If it is actually more complicated see the other answers.
Pattern p = Pattern.compile("[0-9]+");
Matcher m = p.matcher("http://domain.tld/page.html?iVar=123");
if (m.find())
System.out.println(m.group());

This also could do the work :
public static int getIntParam(HttpServletRequest request, String name, int defaultValue) {
String value = request.getParameter(name);
try {
if (value != null) {
return Integer.valueOf(value);
}
} catch (NumberFormatException e) {
}
return defaultValue;
}
Hope it helps!

If the query string part of the URL is always the same (so if it was always iVar) you could use urlAsString.indexOf("iVar=") to find iVar= and then knowing the number is after that, extract the number. That is admittedly not the least brittle approach.
But if you're looking for all the query strings then Bozho's answer is much better.