In my Java application, I create a temporary batch file which does some work for me and the self deletes using this line del /f /q %0. The bat file is launched using ProcessBuilder and then System.exit(0) is called.
This workflow works perfectly, however once the batch file reaches the end I am left with a command prompt window saying "The batch file cannot be found" and waiting for another command. Is there any way I can stop this from happening?
del /f /q %0 &exit
should help
Related
I have a Java jar file located in:
C:\Users\myusername\bin\MyDir\MyApp.jar
I also have some required properties files (needed as input arguments to the .jar file) located in the same directory as the .jar file.
I created a runme.bat file here:
C:\Users\myusername\Desktop\runme.bat
In the runme.bat file, this is what I have:
setlocal
set JAVA_HOME="C:\Program Files\Java\jdk1.8.0_161\bin\"
set PATH=C:\Users\myusername\bin\MyDir\
start %JAVA_HOME%javaw -jar %PATH%MyApp.jar %PATH%propertiesfile.properties
However, whenever I try to run the .bat file, I get the error:
Windows cannot find '-jar' Make sure you typed the name correctly, and then try again.
On the command line I see Windows trying to do this:
> "C:\Program Files\Java\jdk1.8.0_161\bin\"javaw -jar C:\Users\myusername\bin\MyDir\MyApp.jar ...
I get this error when running from the command line. If I simply double-click the .bat file, a cmd window comes up and quickly disappears.
So, what am I doing wrong?
Thanks!
Use Double quotes around the set command, not inside the variables.
Also, I see no reason to use the START command unless you want to do more in your batch file in the original command prompt after starting your Java in a second command prompt. Possible but seems unlikely.
Generally, you will just type in the executable or use CALL so that the executable runs and control returns to the batch after reaching conclusion.
Additionally, you changed your system path variable to be just the path of your java files which will make the session pretty screwy. Thankfully this should only persist in your open command windows and those spawned by the original window, so close them all and then use a different variable name for your path.
So I will put this both ways, using Call, and using start.
Here is your code using call:
#(
setlocal
ECHO ON
)
set "_Title=Runnning My Java"
set "JAVA_HOME=C:\Program Files\Java\jdk1.8.0_161\bin"
set "_MyJarPath=C:\Users\%UserName%\bin\MyDir"
TITLE "%_Title%"
CD /D "%JAVA_HOME%"
CALL "%JAVA_HOME%\javaw.exe" -jar "%_MyJarPath%\MyApp.jar" "%_MyJarPath%\propertiesfile.properties"
(
ENDLOCAL
EXIT /B 0
)
Here is your code using the start command:
#(
SETLOCAL
ECHO ON
)
set "_Title=Runnning My Java"
set "JAVA_HOME=C:\Program Files\Java\jdk1.8.0_161\bin"
set "_MyJarPath=C:\Users\%UserName%\bin\MyDir"
start "%_Title%" /D "%JAVA_HOME%" "%JAVA_HOME%\javaw.exe" -jar "%_MyJarPath%\MyApp.jar" "%_MyJarPath%propertiesfile.properties"
(
ENDLOCAL
EXIT /B 0
)
I'm trying to do a script in batch to launch many java applications.
I did a loop with a .txt file, I'm trying to start a programm which doesn't open many windows, but just one and print all the outpout of the others. So I did that :
start java gateway/gateway %%a
Of course th programm is running in background , but how can I redirect the outpout to the actual terminal ?
Thanks
Try this to redirect programs output back to the Cmd window:
Start "" /B java gateway/gateway %%a
I am running a batch (ScanProject.bat) file using java by following code
Process p= Runtime.getRuntime().exec("cmd /c start /wait ScanProject.bat "+ BaseProjDir+"\\"+jo.getString("Name")+" "+st.nextToken());
System.out.println("Exit value : "+p.waitFor());
And following is the batch file code :-
%2:
cd %1
ant -f ..\antbuild.xml analyse
exit
Batch file run successfully but problem is command prompt window do not closes automatically and hence Process do not terminated automatically and my program wait for infinite time to complete this process.Please suggest me any technique so that cmd exit after running ant -f ..\antbuild.xml analyse command.
Thanks.
cd /D "Full path of directory" or pushd "Full path of directory" with popd before exit is better to switch the current directory to any directory on any drive (cd and pushd/popd) or even to a network share (just pushd/popd). Run in a command prompt window cd /? and pushd /? for details.
cmd /C starts a new Windows command process with closing the process automatically after last command was executed. Run in a command prompt window cmd /? for details on options of Windows command interpreter.
start is a command to start a new Windows command process or a GUI/hybrid application in a separate process.
So what you do here is starting a new Windows command process which starts a new Windows command process.
Running in a command prompt window start /? outputs the help for this command. start interprets often the first double quoted string as title string for the new command process. This causes often troubles on command lines with at least 1 double quoted string. Therefore usage of start requires often an explicit definition of a title string in double quotes as first argument for start which can be even an empty string, i.e. simply "" as first argument after start.
As it can be read after running exit /? in a command prompt window, this command without /B always exits the current Windows command process immediately. So when ant.exe finished, the command process in which the batch file was processed is definitely terminated.
I'm having no experience on Java development, but in my point of view it should be enough to use the following execution command which does not need a batch file at all.
The Java code line
Process p= Runtime.getRuntime().exec("cmd.exe /C cd /D \"" + jo.getString("Name") + "\" && ant.exe -f ..\\antbuild.xml analyse");
should be enough to
start a new Windows command process,
set the current directory within this command process to the drive and directory specified by jo.getString("Name") which of course must return a directory path with drive letter and using backslashes as directory separators, and on success
execute ant in this directory with the specified parameters
with terminating the Windows command process automatically after console application ant.exe finished if ant.exe is a console application.
I'm not sure if cmd.exe /C is needed at all.
I suggest to test this command first manually from within a command prompt window. Then use it in the Java application if really working and producing the expected result. And finally I would further test if cmd.exe /C is needed at all in Java code.
See Single line with multiple commands using Windows batch file for details about the operator && to run a command after previous command was successful. And see also Why do not all started applications save the wanted information in the text files as expected? for an explanation of console / GUI / hybrid application.
NOTE: There is also Java Runtime method exec(String[] cmdarray, String[] envp, File dir) to execute a command like ant.exe with its parameters -f and ..\antbuild.xml and analyse in the directory defined with third parameter which might be better for this task.
Swap out exit for taskkill, assuming you do not have any other cmd processes running. Not very graceful but it will get the job done.
%2:
cd %1
ant -f ..\antbuild.xml analyse
taskkill /im cmd.exe
I was able to use an amalgamation of SO questions to get a line of code that would:
Run a batch file from within a Java application
Include an argument located in the same directory as the batch file
The argument & batch file are in a directory unrelated to the JAR/java app
So I used this:
Runtime.getRuntime().exec("cmd /c start batchfile.bat argument.js", null, new File( path ));
This works well except that it leaves the cmd prompt open after it has finished executing the batch file. I've looked around and it seems like having the /c flag should make it close after running, but for me it has been staying open. I tried removing 'start' but this meant that the cmd prompt never opened up at all.
Is it because I'm combining having an argument and using a different path that it's not causing the cmd prompt to open and then close after completion like most examples on SO?
Calling both cmd.exe and start in that order is creating a separate window but it doesn't seem like the command shell is terminating based on what you described. I was able to replicate this behavior in a simple batch script. If you want to leave your Java call as it is, check to make sure your batch script includes an exit statement. Preferably exit based on a success or failure condition within your batch script (i.e.: exit 0 or exit 1, etc...)
:: batchfile.bat
...
exit 0
Assuming you are not firing up any new shells within your batch script or prompting for input, adding an explicit exit to your existing batch script should cause the window to close. You can also try to leave your batch script as is, and as others have suggested in comments, change the order of your command text slightly.
Use this instead
start cmd.exe /c ...
Where you call start first and then call cmd.exe /c after followed by your parameters as needed. I tried both options here and either worked fine to cause the batch window to close as expected.
Pass the below command to Runtime to execute.
taskkill /F /IM (processName)
Runtime.getRuntime().exec("taskkill /F /IM "+pProcessName);
I am invoking a java swing program from command program and after executing the java program the console remains open. My bat file contains :
set Gantt_Generator_v5.0="C:\Program Files\GANTT_GENERATOR_V5.0"
java -jar %Gantt_Generator_v5.0%\GANTT_GENERATOR_V5.0.jar "C:\Program Files\GANTT_GENERATOR_V5.0\test\Parameter_File.csv" FALSE
exit
When I close the command prompt the java application quits.
Tried options : changed the extension from .bat to .cmd but didn't work for me.
Any other solutions?
used "START JAVAW..." so the final Script is :
set Gantt_Generator_v5.0="C:\Program Files (x86)\GANTT_GENERATOR_V5.0"
start javaw -jar %Gantt_Generator_v5.0%\GANTT_GENERATOR_V5.0.jar "C:\Program Files (x86)\GANTT_GENERATOR_V5.0\test\Parameter_File.csv" FALSE