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How to convert String value to Integer value and want to provide by 'SendKeys' in webdriver [closed]

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I have one read method from excel file and return me String value.
ReqQty = 2 in my excel value but it is in string and from UI side application is not allowing to enter string value in "ReqQty" it is allowing only Integer value . so here i am not able to provide value in 'ReqQty' field by 'SendKeys' method .
The code is:
String Str = ExcelUtils.getcell(1,2) ;
Integer x = Integer.Valueof(x);
driver.findelement(By.xpath("xpath").sendkeys(Integer.valueo‌​f(x)); –

Here is something to get you going:
#Test
public void testParsing() {
String input = "ReqQty = 2";
Pattern pattern = Pattern.compile("ReqQty.*=.*([\\d]+)");
Matcher matcher = pattern.matcher(input);
if (!matcher.find()) {
throw new IllegalArgumentException("failed to parse digits from: " + input);
}
System.out.println(Integer.parseInt(matcher.group(1)));
}
The key elements:
a regular expression pattern used to "match" for a number of digits within a string
Integer.parseInt() to turn that substring of digits into a number
Beyond that: it looks like you are overburdening yourself. The error message you got is quite clear "ReqQty = 2" is not a string that only contains a number. Thus you have to extract that number part from this string. This is really basic stuff. If that is already beyond your skills, then fetching data from excel to pass that into selenium is probably beyond your current skills!
Thus: the real answer is - step back and study the java basics!

you can convert a string into an integer using Integer.parseInt(String x)
String x = "17";
int xAsInt = Integer.parseInt(x);
System.out.println(xAsInt);

To convert a string value into an integer you can try this
'int x = Integer.parseInt("1234");'
or if you are using StringBuilder or StringBuffer you can try this
'Integer.parseInt(myBuilderOrBuffer.toString());'

String to int parseInt [closed]

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I am trying to convert a string to an int but i take an error. Here is my code:
int foo = Integer.parseInt(ABoard[first]);
if (computerBoard[foo] != -1) {
second = computerBoard[foo];
} else {
second = board.getRandomPosition();
while (first==second) {
second = board.getRandomPosition();
}
}
I want to take a number (int) from a string array and then to take the value of this number from an int array if the value of this number isn't -1.

You need to trim off all of the whitespaces before you parse,
int foo = Integer.parseInt(ABoard[first].trim());
Or replace all non numeric digits
int foo = Integer.parseInt(ABoard[first].replaceAll("[^0-9\\-]", ""); //including 0-9 and -

In order to parse String to int you need to remove all non-numeric characters from it (assuming we are not interested in negative integers).
Here is the code to do that:
int foo = Integer.parseInt(ABoard[first].replaceAll("[^0-9]", ""));

Finding all 3 character length substrings in a string [closed]

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I am trying to find all three letter substrings from a string in Java.
For example from the string "example string" I should get "exa", "xam", "amp", "mpl", "ple", "str", "tri", "rin", "ing".
I tried using the Java Regular expression "([a-zA-Z]){3}" but I only got "exa", "mpl", "str", "ing".
Can someone tell me a regex or method to correct this.

Implementing Juvanis' idea somewhat, iterate to get your substrings, then use a regular expression to make sure the substring is all letters:
String s = "example string";
for (int i = 0; i <= s.length() - 3; i++) {
String substr = s.substring(i, i + 3);
if (substr.matches("[a-zA-Z]+")) { System.out.println(substr); }
}

When a character is consumed in one regex, it cannot be used in other regexes. In your example, a is consumed in exa so amp will not be listed as output. You should try traditional iterative approach. It is easier to implement.

try this
Matcher m = Pattern.compile("([a-zA-Z]){3}").matcher("example string");
for (int i = 0; m.find(i); i = m.start() + 1) {
System.out.print(m.group() + " ");
}
output
exa xam amp mpl ple str tri rin ing

This can be done using regex as follows:
Find the position of all matches for the string using the regex \w(?=\w\w). This will give you the start index of the first character of each required sub-string.
In this case, you would get: 0, 1, 2, 3, 4, 8, 9, 10 and 11.
Get what you need by taking the sub-strings starting from each position going upto that plus 2.
In this case, that would mean, my_string.substring(0,3), my_string.substring(1,4) and so on, as the begin index parameter is inclusive while the end index parameter is exclusive.

how to get last three words of a string? [closed]

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I have a string containing this:
D:\ptc\Windchill_10.0\Windchill\wtCustom\wt\lifecycle\StateRB.rbInfo.
I want to get just this part:
wt\lifecycle\StateRB
How can I do that?

You can simply spilt whole path to parts and then get the parts you want.
String path = "D:\ptc\Windchill_10.0\Windchill\wtCustom\wt\lifecycle\StateRB.rbInfo";
String[] parts = path.split("\\");
parts = Arrays.copyOfRange(parts, parts.length-3, parts.length);
Or you can get throught string using loop (this seems to be better)
int index = 0, i = 0;
Stack<String> al = new Stack<String>();
while((index = path.lastIndexOf()))!=-1 && i < 3) {
al.push((path = path.substring(index)));
i++;
}
String[] parts = (String[])al.toArray(); //if you don't have array elements
// in correct order, you can use
// Collections.reverse with Arrays.asList
// applied on array

You can use string tokeniezer with \ delimiter and fetch only last three string tokens. i hope that above path going to be constant always.

http://www.tutorialspoint.com/java/java_string_substring.htm
Check the above link
example :
String Str = new String("Welcome to Tutorialspoint.com");
System.out.print("Return Value :" );
System.out.println(Str.substring(10) );
System.out.print("Return Value :" );
System.out.println(Str.substring(10, 15) );

How to get only integer part from String variable? [closed]

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I have some string type data in my database table like as D-101 and D-102.
I want to get automatically next data in front end (a JSF web application) to send to database which is D-103.
For this I want to get only int data from string.
How can I do this?

final Pattern lastIntPattern = Pattern.compile("[^0-9]+([0-9]+)$");
String input = D101;
Matcher matcher = lastIntPattern.matcher(input);
if (matcher.find()) {
String someNumberStr = matcher.group(1);
int lastNumberInt = Integer.parseInt(someNumberStr);
System.out.println("Test int output - " + lastNumberInt);
inputList.add(lastNumberInt);
}
then compare max value
int currentBranchCode = 0;
for (Integer CCS : companyArrayList) {
if (currentBranchCode <= CCS) {
currentBranchCode = CCS;
}
}
and then
currentBranchCode =currentBranchCode +1;
String codegenerate="D"+currentBranchCode;
you must try it.

In your managed bean you can use split() function.
String s = "D-101";
String[] arr = s.split("[^\\d]+");
System.out.println(arr[1]); //prints 101
OR
In the xhtml page you can write an EL like this. Note that myBean is the name of your bean and getColumnValue() method returns a value of a column(i.e. "D-101").
#{myBean.columnValue.split('[^\\d]+')[1]}

This can be done in just a couple of lines:
int i = Intger.parseInt(input.replaceAll(".*(?<!\\d)(\\d+)", "$1");
String next = input.replaceAll("(.*)(?<!\\d)\\d+", "$1"+ ++i);