Java RandomAccessFile setLength but for the start of binary file - java

I've been reading on RandomAccessFile and understand that its possible to truncate the end of a file by setLength to a length shorter than the file. Im trying to copy just the "end" of the file to a new file and truncate the beginning.
So for example: I want to delete the first 1300 bytes of a file and copy the rest of the file into a new file.
Is there any way of doing this?
Cheers

Have you considered using the RandomAccessFile seek method to seek to 1300 bytes, and then read the remainder of the file starting at the offset and use another RandomAccessFile (or different stream output) to create a new file with the values you read in from the original file beginning at the 1300 byte offset you specified?

Related

File split in java [duplicate]

This question already has answers here:
Java - Read file and split into multiple files
(11 answers)
Closed 4 years ago.
How can I split a file in two ( file1 and file2 ) such that the file1 contains first 10kb of the file and file2 contains rest of the remaining data of the file.
I am using AIDE on android.
There is no "system call" to split a file. You need to open a file, read it and copy the contents to the corresponding output files (which you need to create).
Synopsis:
Open the input file as a FileInputStream
Make a byte[] buffer somewhere around 4k
Open the two output files as two FileOutputStreams
Read from input into buffer and write buffer to first OutputStream
Do this until exactly 10kb bytes have been read and written
Read from input into buffer and write buffer to second OutputStream
Do this until there are no more bytes from the input stream
Close all three streams
Of course, you will need to be careful to make sure that you copy exactly the correct number of bytes. See InputStream.read(buf, offset, length) for details. Test also for special case when input file is less than 10k long.

Zip files size anomaly

I am seeing something unusual in my zip files.
I have two .txt files and both are then zipped through java.util.zip(ZipOutputStream, ZipEntry ...) in my application and then returned in response as downloadable zip files through the browser.
One file has data which is a database blob and other is a StringBuffer. My blob txt file is of size 10 mb and my StringBuffer txt file is 15 mb but when these are zipped the blob txt zip file has size larger that the StringBuffer txt file although it contains a smaller txt file.
Any reason why this might be happening?
the StringBuffer and (as of Java 5) StringBuilder classes store just
the buffer for the character data plus current length (without the
additional offset and hash code fields of a String), but that buffer
could be larger than the actual number of characters placed in it;
a Java char takes up two bytes, even if you're using them to store
boring old ASCII values that would fit into a single byte;
Your BLOB -- binary large object -- probably contains data that isn't text, and as compressible as text. For example, it could contain an image.
If you don't already know what the blob contains, you can use a hexdump program to look at it.

How to speed up reading of a large OBJ (text) file?

I am using an OBJ Loader library that I found on the 'net and I want to look into speeding it up.
It works by reading an .OBJ file line by line (its basically a text file with lines of numbers)
I have a 12mb OBJ file that equates to approx 400,000 lines. suffice to say, it takes forever to try and read line by line.
Is there a way to speed it up? It uses a BufferedReader to read the file (which is stored in my assets folder)
Here is the link to the library: click me
Just an idea: you could first get the size of the file using the File class, after getting the file:
File file = new File(sdcard,"sample.txt");
long size = file.length();
The size returned is in bytes, thus, divide the file size into a sizable number of chunks e.g. 5, 10, 20 e.t.c. with a byte range specified and saved for each chunk. Create byte arrays of the same size as each chunk created above, then "assign" each chunk to a separate worker thread, which should read its chunk into its corresponding character array using the read(buffer, offset, length) method i.e. read "length" characters of each chunk into the array "buffer" beginning at array index "offset". You have to convert the bytes into characters. Then concatenate all arrays together to get the final complete file contents. Insert checks for the chunk sizes so each thread does not overlap the others boundaries. Again, this is just an idea, hopefully it will work when actually implemented.

How to read a file in java based on file number? [duplicate]

This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
Read a specific line from a text file
Is there any way to read a line in a file in java.I mean if i want to read 100th line only then can i read it directly? Or I have to read the whole file until it comes to line 100.
You can use java.io.RandomAccessFile.
Moving to 100th line use the following lines:
RandomAccessFile file = new RandomAccessFile("D:\\test.txt", "rw");
int totalLines = (int)file.length();
file.seek(100);
long pointer = file.getFilePointer();
for(int pt = 100; ct < totalLines; ct++){
byte b = file.readByte(); //read byte from the file
System.out.print((char)b); //convert byte into char
}
file.close();
For more details please see the below link which will helps you:
http://tutorials.jenkov.com/java-io/randomaccessfile.html
No, no matter the abstractions, there really isn't an efficient way of "directly" reading the 100th line from a file-system. You can of course use offsets in case you have lines with fixed lengths per line (assuming CR or LF etc.) but that's it. You can't jump around in a file based on the "line" abstraction.
Under most circumstances you will need to read line-by-line starting from the start of the file.
There are exceptions to this:
If you create and maintain an index for the file that indicates the positions of each line start, you can lookup a line in the index and then seek the file to the position to read it.
If your file consists of fixed length lines, you can calculate the position of the start of a line as line_no * line_length, and then seek to that position.

Read and a write a file in a reverse order - Java

I have a very big file (might be even 1G) that I want to create a new file from in a reversed order (in Java).
For example:
Original file:
This is the first line
This is the 2nd line
This is the 3rd line
The reversed file:
This is the 3rd line
This is the 2nd line
This is the first line
Since the file is very big, loading the entire file to memory at once and reversing the order there might be problematic (there is a limit to the memory I can use).
How can I achieve this in Java?
Thanks
Nothing very direct, I'm afraid. But you can easily create some (say) ReverseBufferedRead class wrapping a RandomAccessFile.
See also here.
Read the file by chunks of few hundreds lines, reverse the order of lines in the chunks and write them to temporary files. Then join the temporary files in the reverse order and clean up.
In other words, use disk instead of memory.
I would propose making a RandomAccessFile for the output and using setLength() to make it appropriately sized.
Then start scanning the original file and write it out in chunks starting at the end of the RandomAccessFile in reverse.
Java-ish Pseudo:
out.seek(size_of_out_file); //seek to end
RandomAccessFile out = new RandomAccessFile("out_fname", "rw");
out.setLength(size_of_file_to_be_reversed)
File in = new File ("in_fname");
while (hasMoreData(in)){
String chunk = in.readsize();
out.seekBackwardsBy(chunk.length());
out.write(chunk.reverse);
out.seekBackwardsBy(chunk.length());
}
Reading a file line-by-line in reverse order is fundamentally tricky.
It's not too bad if you've got a fixed width encoding. It's feasible if you've got a variable width encoding which you can detect the first byte of etc (e.g. UTF-8). It's virtually impossible to do efficiently if the encoding is variable width with no sensible way of determining boundaries (or if it uses "shifting" for example).
I have an implementation in C# in another question, but it would take a fair amount of effort to port that to Java.
If you use the RandomAccessFile like leonbloy suggested you can use a FileChannel
to skip to the end of the file, you can then read the line and write it to another file.
There is a simple example here in the Java tutorials: example
I would assume you know how to read a file. One way i would advise you do it is with an ArrayList of generic type string. So you read each line of the file and store it in that list. After reading you print the list out or do whatever you want to.
Just wrote something that might be of help here : http://pastebin.com/iWTVrAvm
Read using RandomAccessFile - position the file using randomAccesFile.length()and write using BufferedWriter
A better solution is use a ReversedLinesFileReader provided in Apache Commons IO package. Look at the API here https://commons.apache.org/proper/commons-io/apidocs/org/apache/commons/io/input/ReversedLinesFileReader.html

Categories