I'm developing a simple standalone Java application using Spring and Hibernate to try to learn them.
I'm having some problems in the configuration of Spring and Hibernate, in order to really create some "useful" result from the code...
I've tried to follow the examples as reported in the book "Beginning Hibernate 2nd edition" and "Pro Spring 3", but i'm having , regarding Hibernate, this problem (i'm using log4j for the logging) :
1824 [main] INFO org.springframework.beans.factory.support.DefaultListableBeanFactory - Destroying singletons in org.springframework.beans.factory.support.DefaultListableBeanFactory#38638273: defining beans [dataSource,sessionFactory,transactionManager,org.springframework.aop.config.internalAutoProxyCreator,org.springframework.transaction.annotation.AnnotationTransactionAttributeSource#0,org.springframework.transaction.interceptor.TransactionInterceptor#0,org.springframework.transaction.config.internalTransactionAdvisor,org.springframework.context.annotation.internalConfigurationAnnotationProcessor,org.springframework.context.annotation.internalAutowiredAnnotationProcessor,org.springframework.context.annotation.internalRequiredAnnotationProcessor,org.springframework.context.annotation.internalCommonAnnotationProcessor,org.springframework.context.annotation.internalPersistenceAnnotationProcessor,personaDao,org.springframework.context.annotation.ConfigurationClassPostProcessor.importAwareProcessor]; root of factory hierarchy
Exception in thread "main" org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'dataSource' defined in class path resource [app-context.xml]: Error setting property values; nested exception is org.springframework.beans.PropertyBatchUpdateException; nested PropertyAccessExceptions (1) are:
PropertyAccessException 1: org.springframework.beans.MethodInvocationException: Property 'driverClassName' threw exception; nested exception is java.lang.IllegalStateException: Could not load JDBC driver class [${jdbc.driverClassName}]
It seems that the placeholder is ignored in the parsing of the configuration files
Here i've have copied an extract of them :
app-context.xml:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:jdbc="http://www.springframework.org/schema/jdbc"
xsi:schemaLocation="
http://www.springframework.org/schema/jdbc
http://www.springframework.org/schema/jdbc/spring-jdbc-3.2.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.2.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-3.2.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.2.xsd">
<bean id="dataSource"
class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="${jdbc.driverClassName}" />
<property name="url" value="${jdbc.url}" />
<property name="username" value="${jdbc.username}" />
<property name="password" value="${jdbc.password}" />
</bean>
<bean id="sessionFactory"
class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="configLocation" >
<value>classpath:hibernate.cfg.xml</value>
</property>
<property name="configurationClass">
<value>org.hibernate.cfg.AnnotationConfiguration</value>
</property>
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">${jdbc.dialect}</prop>
<prop key="hibernate.show_sql">true</prop>
</props>
</property>
</bean>
<bean id="transactionManager" class="org.springframework.orm.hibernate3.HibernateTransactionManager">
<property name="sessionFactory" ref="sessionFactory"/>
</bean>
<tx:annotation-driven/>
<bean id="personaDao" class="org.bladela.dataaccess.persona.PersonaDaoImpl">
<property name="sessionFactory" ref="sessionFactory"/>
</bean>
</beans>
hibernate.cfg.xml
<?xml version='1.0' encoding='utf-8'?>
<!DOCTYPE hibernate-configuration PUBLIC
"-//Hibernate/Hibernate Configuration DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
<session-factory>
<property name="show_sql">true</property>
<mapping class="org.bladela.dataaccess.persona.Persona"/>
</session-factory>
</hibernate-configuration>
jdbc.properties :
jdbc.driverClassName=org.postgresql.Driver
jdbc.dialect=org.hibernate.dialect.PostgreSQLDialect
jdbc.databaseurl=jdbc:postgresql://localhost:5432/employeemanagementdb
jdbc.username=bladela
jdbc.password=password
if i substitute all the placeholders with their values, the program goes on and it connects to the db (if i substitute only one...the error "goes" to the next one)
then it return an incorrect result (an empty list when it should return a list with one element) but maybe i'll ask about it later, if i can't solve it.
Any suggestion?
I don't see any PropertyPlaceholderConfigurer declared in your context. How are property placeholders supposed to be resolved?
One solution is to add
<context:property-placeholder location="classpath:jdbc.properties"/>
to your context.
Related
Beating my head against the wall for hours and can't resolve this issue, seems to be either a mistake in my config setup or maybe a dependency conflict or missing dependency. Any thoughts?
Relevant dependencies:
Spring Data Commons Core 1.2.0
Spring Data JPA 1.8.0
Hibernate Core 5.0
Hibernate JPA 2.1
Error message in Eclipse:
Configuration problem: Failed to import bean definitions from relative location [SpringDbContext.xml] Offending resource: class path resource [SpringAppContext.xml]; nested exception is
org.springframework.beans.factory.xml.XmlBeanDefinitionStoreException: Line 43 in XML document from class path resource [SpringDbContext.xml] is invalid; nested exception is org.xml.sax.SAXParseException; systemId:
http://www.springframework.org/schema/data/jpa/spring-jpa-1.8.xsd; lineNumber: 43; columnNumber: 63; src-resolve: Cannot resolve the name 'repository:auditing-attributes' to a(n) 'attribute group' component.at
org.springframework.beans.factory.parsing.FailFastProblemReporter.error(FailFastProblemReporter.java:70)
SpringAppContext.xml:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.2.xsd">
<import resource="SpringWebContext.xml"/>
<import resource="SpringDbContext.xml"/>
<import resource="SpringSecurityContext.xml"/>
<import resource="SpringSocialContext.xml"/>
<context:component-scan base-package="com.metagravy.ark.security"/>
<bean id="messageSource" class="org.springframework.context.support.ResourceBundleMessageSource">
<property name="basename" value="i18n/messages"/>
<property name="useCodeAsDefaultMessage" value="true"/>
</bean>
</beans>
Hibernate configs:
hibernate.dialect=org.hibernate.dialect.PostgreSQLDialect
hibernate.format_sql=true
hibernate.hbm2ddl.auto=create-drop
hibernate.ejb.naming_strategy=org.hibernate.cfg.ImprovedNamingStrategy
hibernate.show_sql=false
SpringDbContext.xml:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:jpa="http://www.springframework.org/schema/data/jpa"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-4.1.xsd
http://www.springframework.org/schema/data/jpa
http://www.springframework.org/schema/data/jpa/spring-jpa-1.8.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-4.1.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-4.1.xsd">
<context:property-placeholder location="classpath:application.properties"/>
<bean id="dataSource" class="com.jolbox.bonecp.BoneCPDataSource">
<property name="driverClass" value="${db.driver}"/>
<property name="jdbcUrl" value="${db.url}"/>
<property name="username" value="${db.username}"/>
<property name="password" value="${db.password}"/>
</bean>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory"/>
</bean>
<tx:annotation-driven/>
<bean id="hibernateJpaVendorAdapter" class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"/>
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource"/>
<property name="jpaVendorAdapter" ref="hibernateJpaVendorAdapter"/>
<property name="packagesToScan" value="com.metagravy.ark"/>
<property name="jpaProperties">
<props>
<prop key="hibernate.dialect">${hibernate.dialect}</prop>
<prop key="hibernate.ejb.naming_strategy">${hibernate.ejb.naming_strategy}</prop>
<prop key="hibernate.format_sql">${hibernate.format_sql}</prop>
<prop key="hibernate.hbm2ddl.auto">${hibernate.hbm2ddl.auto}</prop>
<prop key="hibernate.show_sql">${hibernate.show_sql}</prop>
</props>
</property>
</bean>
<jpa:repositories base-package="com.metagravy.ark.security"/>
</beans>
Thanks for the help, I upgraded spring-data-commons from 1.2 to 1.10 and it resolved the error.
I have a small application using Spring3, Hibernate4 and JSF2.
So far in my application I do not have hibernate.cfg.xml file, I have used Spring applicationContext.xml for scanning classes and annotations for Entity class.
applicationContext.xml
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<context:component-scan base-package="net.test" />
<!-- Data Source Declaration -->
<bean id="DataSource" class="com.mchange.v2.c3p0.ComboPooledDataSource"
destroy-method="close">
<property name="driverClass" value="oracle.jdbc" />
<property name="jdbcUrl"
value="jdbc:oracle:thin:#server:1521:TEST" />
<property name="user" value="scott" />
<property name="password" value="tiger" />
<property name="maxPoolSize" value="10" />
<property name="maxStatements" value="0" />
<property name="minPoolSize" value="5" />
</bean>
<!-- Session Factory Declaration -->
<bean id="SessionFactory"
class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
<property name="dataSource" ref="DataSource" />
<property name="annotatedClasses">
<list>
<value>net.test.model.Employees</value>
</list>
</property>
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.Oracle10gDialect</prop>
<prop key="hibernate.show_sql">true</prop>
</props>
</property>
</bean>
<!-- Enable the configuration of transactional behavior based on annotations -->
<tx:annotation-driven transaction-manager="txManager" />
<!-- Transaction Manager is defined -->
<bean id="txManager"
class="org.springframework.orm.hibernate4.HibernateTransactionManager">
<property name="sessionFactory" ref="SessionFactory" />
</bean>
</beans>
What I would like to do is add hibernate.cfg.xml into my application, I know it is not mandatory if I have applicaionContext.xml exists.
The reason why I would want to include is because I would like to specify the following in hibernate.cfg.xml in order to resolve the issue of
org.hibernate.QueryException: ClassNotFoundException:
org.hibernate.hql.internal.ast.HqlToken
See this for details of exceptions I am getting
<property name="hibernate.query.factory_class" value="org.hibernate.hql.classic.ClassicQueryTranslatorFactory">
</property>
As I already have the following in applicationContext.xml, how best I could use hibernate.cfg.xml? Any help is highly appreciable.
<property name="annotatedClasses">
<list>
<value>net.test.model.Request</value>
</list>
</property>
Update 1
Error creating bean with name 'requestDAOImpl': Injection of autowired dependencies
failed; nested exception is org.springframework.beans.factory.BeanCreationException:
Could not autowire field: private org.hibernate.SessionFactory
net.test.request.dao.RequestDAOImpl.sessionFactory; nested exception is
org.springframework.beans.factory.BeanCreationException: Error creating
bean with name 'SessionFactory' defined in ServletContext resource
[/WEB-INF/applicationContext.xml]: Invocation of init method failed;
nested exception is org.hibernate.HibernateException: could not
instantiate QueryTranslatorFactory:
org.hibernate.hql.classic.ClassicQueryTranslatorFactory
.
Have you tried to set *hibernate.query.factory_class* property using Spring's application.xml like this?:
<bean id="SessionFactory"
class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
...
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.Oracle10gDialect</prop>
<prop key="hibernate.show_sql">true</prop>
<prop key="hibernate.query.factory_class">org.hibernate.hql.internal.classic.ClassicQueryTranslatorFactory</prop>
</props>
</property>
</bean>
It seems to me that this should work without explicitly using hibernate.cfg.xml.
I'm trying to use Hibernate in my Spring application but i've got an error on the project's deployment
Exception while loading the app : java.lang.IllegalStateException: ContainerBase.addChild: start: org.apache.catalina.LifecycleException: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'sessionFactory' defined in ServletContext resource [/WEB-INF/dispatcher-servlet.xml]: Initialization of bean failed; nested exception is org.springframework.beans.TypeMismatchException: Failed to convert property value of type 'java.lang.String' to required type 'java.lang.Class' for property 'configurationClass'; nested exception is java.lang.IllegalArgumentException: Cannot find class [org.hibernate.cfg.AnnotationConfiguration].
Here my dispatcher-servlet with the bean session factory :
<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p" xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-2.5.xsd"
default-autowire="byName">
<context:component-scan base-package="hibernateTest" />
<context:annotation-config/>
<bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter"/>
<bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"
p:prefix="/WEB-INF/jsp/"
p:suffix=".jsp" />
<bean id="propertyConfigurer"
class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="locations">
<list>
<value>classpath:jdbc.properties</value>
</list>
</property>
</bean>
<bean id="sessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="configLocation">
<value>classpath:hibernate.cfg.xml</value>
</property>
<property name="configurationClass">
<value>org.hibernate.cfg.AnnotationConfiguration</value>
</property>
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect</prop>
<prop key="hibernate.show_sql">true</prop>
</props>
</property>
</bean>
<bean id="transactionManager"
class="org.springframework.orm.hibernate3.HibernateTransactionManager">
<property name="sessionFactory" ref="sessionFactory" />
</bean>
And my hibernate-cfg.xml :
<?xml version='1.0' encoding='utf-8'?>
<!DOCTYPE hibernate-configuration PUBLIC
"-//Hibernate/Hibernate Configuration DTD//EN"
"http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
<session-factory>
<mapping class="hibernateTest.web.InventoryController" />
</session-factory>
</hibernate-configuration>
I've many jars in my classpath and i thoutgh it doesn't miss anyone. Could you help me finding an issue ?
Thanks
You need to put the hibernate-annotations.jar on the classpath.
Cannot find class [org.hibernate.cfg.AnnotationConfiguration]
This is the reason, Can you check for this class in classpath.
org.hibernate.cfg.AnnotationConfiguration is deprecated,
and all its functionality has been moved to org.hibernate.cfg.Configuration.
change your code
<property name="configurationClass">
<value>org.hibernate.cfg.Configuration</value>
</property>
I am attempting to split out the Hibernate DAO and Model Object layer from an existing application so they can be used across multiple applications. Unfortunately, I'm not having much success: a NoSuchBeanDefinitionException is thrown when trying to get the SessionFactory from the Application Context.
All of DAO classes extend a class called GenericDaoHibernate2. Each DAO extends this, and passes a Class in the constructor. Pretty standard Generic DAO stuff.
I figured this would be the logical place to set the session factory as well (there are ALOT of DAO classes). So, in the constructor class, I did this:
public GenericDaoHibernate2(final Class<T> persistentClass) {
ctx = new ClassPathXmlApplicationContext("META-INF/applicationContext-dao.xml");
this.sessionFactory = (SessionFactory) ctx.getBean(SessionFactory.class);
log.debug("Value of app context: " + ctx.toString());
log.debug("Value of sessionFactory: " + sessionFactory);
this.persistentClass = persistentClass;
}
Unfortunately, this blew up with the previously mentioned exception:
Caused By: org.springframework.beans.factory.NoSuchBeanDefinitionException: No matching bean of type [org.hibernate.SessionFactory] found for dependency: expected at least 1 bean which qualifies as autowire candidate for this dependency. Dependency annotations: {}
at org.springframework.beans.factory.support.DefaultListableBeanFactory.raiseNoSuchBeanDefinitionException(DefaultListableBeanFactory.java:924)
at org.springframework.beans.factory.support.DefaultListableBeanFactory.doResolveDependency(DefaultListableBeanFactory.java:793)
at org.springframework.beans.factory.support.DefaultListableBeanFactory.resolveDependency(DefaultListableBeanFactory.java:707)
at org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor$AutowiredMethodElement.inject(AutowiredAnnotationBeanPostProcessor.java:551)
at org.springframework.beans.factory.annotation.InjectionMetadata.inject(InjectionMetadata.java:87)
Truncated. see log file for complete stacktrace
I've also attempted this with the app context file just in the classpath, setting the value when declaring the variable, etc, etc.
I'm guessing what is happing is that as part of the Maven build, the jar isn't referencing the libraries on the classpath, but I really don't know...
UPDATE: Stupid, stupid me... forgot to show the application context file.
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:jee="http://www.springframework.org/schema/jee" xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.1.xsd
http://www.springframework.org/schema/jee
http://www.springframework.org/schema/jee/spring-jee-3.1.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.1.xsd"
default-lazy-init="true">
<tx:annotation-driven transaction-manager="transactionManager" />
<context:component-scan base-package="org.jason.dao.hibernate" />
<bean id="dataSource"
class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="oracle.jdbc.driver.OracleDriver" />
<property name="url" value="jdbc:oracle:thin:#//192.168.1.1/db01" />
<property name="username" value="USER" />
<property name="password" value="PASSWORD" />
</bean>
<!-- Hibernate SessionFactory -->
<bean id="sessionFactory"
class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.Oracle10gDialect</prop>
<prop key="hibername.format_sql">true</prop>
<prop key="hibernate.show_sql">true</prop>
<prop key="hibernate.jdbc.use_get_generated_keys">true</prop>
<prop key="hibernate.cglib.use_reflection_optimizer">true</prop>
<prop key="hibernate.default_catalog">CATALOG</prop>
<prop key="hibernate.cache.use_second_level_cache">true</prop>
<prop key="hibernate.cache.region.factory_class">org.hibernate.cache.ehcache.SingletonEhCacheRegionFactory
</prop>
</props>
</property>
<property name="packagesToScan">
<list>
<value>org.jason.model</value>
</list>
</property>
</bean>
</beans>
Another update: Was asked for a sample DAO. The interface is a "standard" generic interface, accepting the generic paramters T and PK, just like the Impl. The following one doesn't have any specific methods other than what it inherits from GenericDaoHibernate2.
#Repository("AreaOfPreferenceDAO")
public class HibernateAreaOfPreferenceDAO extends GenericDaoHibernate2<AreaOfPreference, AreaOfPreferenceCompositeId> implements AreaOfPreferenceDAO {
public HibernateAreaOfPreferenceDAO()
{
super(AreaOfPreference.class);
}
}
In order to wire in the SessionFactory into your custom generic DAO, you can go ahead and simply use #Autowire, as long as the overall Spring context is defining the SessionFactory bean.
To define the bean:
<bean id="sessionFactory" class=
"org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="packagesToScan" value="org.rest" />
<property name="hibernateProperties">
...
</property>
</bean>
<bean id="dataSource" class=
"org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="${driverClassName}" />
<property name="url" value="${url}" />
<property name="username" value="restUser" />
<property name="password" value="restmy5ql" />
</bean>
And to wire, simply:
#Autowired
SessionFactory sessionFactory;
The right place to bootstrap the context is not in the constructor of your DAO; if you're working with a web application, you can go with the traditional approach:
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/dispatcher-config.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
Since this is not a web application, then the context cannot be bootstrapped in web.xml; however, the bootstrapping still needs to be external - a main class would simply need to create the XmlWebApplicationContext and configure it.
Hope this helps.
The fact that you are creating a new application context in each DAO object may be getting you into trouble.
ctx = new ClassPathXmlApplicationContext("META-INF/applicationContext-dao.xml");
This is kind of circular if you think about it. You call the context, which does a component scan for DAO's, then the DAO instantiates a new context, which does a component scan for DAO's ...
I would just autowire the sessionfactory directly as someone else had mentioned.
#Repository("AreaOfPreferenceDAO")
public class HibernateAreaOfPreferenceDAO extends GenericDaoHibernate2<AreaOfPreference, AreaOfPreferenceCompositeId> implements AreaOfPreferenceDAO {
#Autowired
public HibernateAreaOfPreferenceDAO(SessionFactory sessionFactory)
{
super(sessionFactory, AreaOfPreference.class);
}
}
No component should need to construct a new application context.
Had the same problem, unable to make injection work.
My problem was "sequence". Hibernate xml must be invoked first.
dispatcher-servlet.xml:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.1.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-3.1.xsd">
<!-- init hibernate first -->
<import resource="classpath:HibernateContext.xml"/>
<bean id="viewResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/pages/" />
<property name="suffix" value=".jsp" />
</bean>
<mvc:annotation-driven />
<context:component-scan base-package="com.xxx.yyy" />
content of hibernateContext.xml:
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.2.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-3.2.xsd">
<bean id="propertyConfigurer"
class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="locations">
<list>
<value>classpath:database.properties</value>
</list>
</property>
</bean>
<bean id="dataSource"
class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="${jdbc.driver}" />
<property name="url" value="${jdbc.url}" />
<property name="username" value="${jdbc.user}" />
<property name="password" value="${jdbc.password}" />
</bean>
<bean id="sessionFactory"
class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="packagesToScan" value="com.xxx.yyy.model" />
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.Oracle10gDialect</prop>
<prop key="hibernate.show_sql">true</prop>
</props>
</property>
</bean>
<tx:annotation-driven transaction-manager="transactionManager"/>
<bean id="transactionManager" class="org.springframework.orm.hibernate4.HibernateTransactionManager">
<property name="sessionFactory" ref="sessionFactory"/>
</bean>
<!-- bean id="transactionManager" class=" org.springframework.transaction.jta.JtaTransactionManager">
<property name="sessionFactory" ref="sessionFactory"/>
</bean-->
I have a simple Java application and I'm trying to integrate Hibernate in Spring but it seems that the Spring configuration file can't find the *.hbm.xml (the mapping resource):
I have a file named persistence-context.xml that I use it as a Spring config file and I have the following bean declared:
org.hibernate.dialect.MySQLDialect
But is being thrown the exception:
java.io.FileNotFoundException: class path resource [pool.hbm.xml] cannot be opened because it does not exist
I've even tried giving the mapping resources property an absolute path value. It doesn't work.
Thank you!
UPDATE:
My Spring conf file:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource">
<property name="driverClassName" value="com.mysql.jdbc.Driver" />
<property name="url" value='jdbc:mysql://localhost/bestofs_seinfeld' />
<property name="username" value="root" />
<property name="password" value="futifuti825300" />
<property name="initialSize" value="5" />
<property name="maxActive" value="10" />
</bean>
<bean id="mySessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">
<property name="dataSource" ref="dataSource"/>
<property name="mappingResources" value="pool.hbm.xml" />
<property name="hibernateProperties">
<props>
<prop key="dialect">org.hibernate.dialect.MySQLDialect</prop>
</props>
</property>
</bean>
<bean id="hibernateTemplate" class="org.springframework.orm.hibernate3.HibernateTemplate">
<property name="sessionFactory">
<ref bean="mySessionFactory"/>
</property>
</bean>
<bean id="voteDao" class="bestofs.persistence.HibernatePoolDao">
<property name="hibernateTemplate">
<ref bean="hibernateTemplate"/>
</property>
</bean>
</beans>
And my pool.hbm.xml is:
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping>
<class name="bestofs.persistence.PoolBean" table="sein_pool">
<id name="idVote" column="ID_Vote">
<generator class="assigned"/>
</id>
<property name="IdActor">
<column name="ID_Actor"/>
</property>
<property name="IdUser">
<column name="ID_User"/>
</property>
<property name="IdSession">
<column name="ID_Session"/>
</property>
</class>
</hibernate-mapping>
And both configuration files are on the same folder.
If you are giving absolute path to the file location on disk (e.g. c:/mapings/pool.hbm.xml), it will not work, because it searches for mapping on a class path. Mapping file should be inside your jar or in IDE class path.
If you are using Tomcat + web project, you should create resource folder inside your src folder and put your mapping files there it will be equal to:
<property name="mappingResources">
<list>
<value>object.hbm.xml</value>
</list>
</property>
Hope it helps.
Use
<property name="mappingResources" value="pool.hbm.xml" />
and put pool.hbm.xml in the root of your classpath. I.e. your bestofs.persistence.PoolBean will be in a directory structure like <somewhere>/bestofs/persistence/PoolBean.class. The mapping file should be inside <somewhere>, right alongside bestofs.
That's all you need to do unless you have some strange ClassLoader magic happening.