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Using parameters from shell script in my Java code

I have to write two scripts, one to compile my code and another one to run it. I manage to compile the code with this script:
#!/bin/bash
javac SimilaridadeP.java
And I was able to run it using this script:
#!/bin/bash
java SimilaridadeP
The problem is that I need to execute my second shell script following this command:
./execute.sh input output
Where input and output are the names of the files that I am going to use in my Java code. The problem that I am facing right now is that I don't know how I can use these both names in my Java code.
So far I managed to get both names using this code:
#!/bin/bash
in=$1
out=$2
java SimilaridadeP
But since "SimilaridadeP" is the name of my java file and it can't be called like a method with parameters I am kind of lost.

If your java code is already reading the command-line parameters, it's just a matter of changing the bash this way:
#!/bin/bash
java SimilaridadeP "$1" "$2"

This works with arbitrary number of arguments:
#!/bin/bash
java SimilaridadeP "$#"

Need help providing parameter while batch file execution in perl script

I have to execute a abc.bat file in a perl script.
If I run the batch file manually it asks for first param at first step. When I provide this at second step it will ask for second param..
I need to call this abc.bat file in a perl script
Something like..
system(‘abc.bat’); or exec()
But how to provide param run time..
The abc.bat batch file is a calling a java myclass which takes two params at runtime.
Below is the batch file
#echo off
setlocal
set classpath=.\my.jar;%classpath%
"%JAVA_HOME%"\bin\java com.myclass
#echo on
Please help .. Thank you.

Can you just use the %ENV variable to do everything directly in perl? Maybe:
$ENV{classpath} = ".\\my.jar;$ENV{classpath}";
system("$ENV{JAVA_HOME}\\bin\\java com.myclass");

Executing a java class in the linux terminal without the java command

I have a java class, cs.class, that I would like to execute from the command line, just as you use any other command. I would like to be able to type 'cs file1' etc. Without having to use 'java cs file1'. How can I do this?
edit: I would also like this to work if I put my class anywhere in my path.

It looks like this will work for you on linux.

For Windows
Create a file named custom.cmd and add the following to it
#echo off
DOSKEY cs=java cs $*
Now
right click your command prompt shortcut->properties->shortcut tab->and append the following to your target field
/K C:\custom.cmd
my custom.cmd resides in C:, change the path to yours
Now you can use "cs" as a command within that cmd shell. You can mention you filename as an argument as well as $* specifies command line arguments.

Java Filepath Question

I am trying to finish a java program that uploads a file from a client machine to a webserver. The java program is executed with a bat script. I need to pass in a file name to the java program somehow since the filename is different every time. Or can i somehow use %1 instead of the filepath? I dont know.

Why not simply forward the parameters passed to the shell script to the Java application. I usually do something like this:
#!/bin/zsh
java -jar someapp.jar $#
This will pass all the arguments with which the script was executed to the java app and you can act upon them - as far as I understand you need only only - the file path. I'm not familiar with bat scripts, but I assume they have some similar way of passing args around.

What does the batch file look like that runs the Java program? You can indeed use parameters like this:
java -jar program.jar %1
If you put that line in a file runprogram.bat, then you could run it with:
runprogram somefilename.xyz
and somefilename.xyz will be passed to the Java program as a command line argument.

No they got it, if i could just pass the filepath as a parameter to the executed jar that would be awesome. Just need to figure out how to pass that parameter into a variable in the program....

How to pass Properties to jar from Powershell?

I've been using Powershell-1.0 for command line needs for a while, instead of cmd.exe. Unfortunately, there are still some caveats when using Java. I need to pass a property to a jar, like that:
java -jar -Duser.language=en any.jar
This line works fine in cmd.exe, but not in Powershell as it searches for another jar:
Unable to access jarfile user.language=en
Using quotes doesn't help.
Is it doable in Powershell-1.0, or do I miss something in Java?

Take a look at my answer to this question. Note how you can use echoargs.exe to diagnose these sort of problems. Most likely the fix would be to quote the parameter e.g.:
java -jar "-Duser.language=en" any.jar
You can test that using echoargs (from PowerShell Community Extensions):
echoargs -jar "-Duser.language=en" any.jar
Arg 0 is <-jar>
Arg 1 is <-Duser.language=en>
Arg 2 is <any.jar>

Using quotes works fine for me in PowerShell on Windows 7.
java "-Dmy.property=value" -jar myjar.jar
Be careful: the jar name must be placed right after -jar, and arguments placed after -jar myjar.jar will be passed to the program inside the jarFile.

Try launching instead using the following pattern:
java -Duser.language=en -jar any.jar
That assumes that user.language is meant as a system property. If you meant it as a command line argument, change that to:
java -jar any.jar -Duser.language=en
I am actually surprised that the command line you mentioned works at all outside of powershell (though I have confirmed that it works fine for me too, even on Linux) and it is also a little strange that things would work differently inside and outside of powershell.
From java -help:
Usage: java [-options] class [args...]
(to execute a class)
or java [-options] -jar jarfile [args...]
(to execute a jar file)
where options include:
...
-D<name>=<value>
set a system property
...
So basically you should always put the JAR filename directly after the -jar command line option, and any JVM options (such as setting system properties with -D) before.