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maven: Some input files use unchecked or unsafe operations [duplicate]

In NetBeans 7.2, I'm having trouble finding how to compile using -Xlint:unchecked in a Maven project. Under an Ant project, you can change compiler flags by going to Project Properties -> Compiling, but Maven projects don't seem to have any such option.
Is there any way to configure the IDE to compile with such flags using Maven?

I guess you can set compiler arguments in your pom.xml. Please refer this http://maven.apache.org/plugins/maven-compiler-plugin/examples/pass-compiler-arguments.html
<compilerArgument>-Xlint:unchecked</compilerArgument>

I want to elaborate on #Nishant's answer. The compilerArgument tag needs to go inside plugin/configuration tag. Here is a full example:
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-compiler-plugin</artifactId>
<version>3.3</version>
<configuration>
<source>1.8</source>
<target>1.8</target>
<testSource>1.8</testSource>
<testTarget>1.8</testTarget>
<compilerArgument>-Xlint:unchecked</compilerArgument>
</configuration>
</plugin>
</plugins>

This works for me...
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-compiler-plugin</artifactId>
<version>3.8.1</version>
<configuration>
<source>11</source>
<target>11</target>
<compilerArguments>
<endorseddirs>${endorsed.dir}</endorseddirs>
</compilerArguments>
<compilerArgs>
<arg>-Xlint:unchecked</arg> <-------this right here ---->
</compilerArgs>
</configuration>
</plugin>
</plugins>

The pom file information is spot on. I had the additional challenge of building someone else's Maven project in Jenkins and not having access to the pom file repository.
I created a pre-build step to insert the compiler parameter into the pom file after downloading it from git, for example
sed -i 's|/target> *$|/target>\n<compilerArgument>\n-Xlint:deprecation\n</compilerArgument>|' $WORKSPACE/pom.xml

Exclude webapp folder from Maven Build

I was trying to achieve a custom directory structure for my war with maven build.
Below is my build command used in pom.xml.
<build>
<finalName>abc</finalName>
<plugins>
<plugin>
<artifactId>maven-antrun-plugin</artifactId>
<executions>
<execution>
<configuration>
<tasks>
<mkdir dir="bin" />
</tasks>
</configuration>
</execution>
</executions>
</plugin>
<plugin>
<artifactId>maven-resources-plugin</artifactId>
<version>3.0.2</version>
<executions>
<execution>
<id>copy-resources</id>
<!-- here the phase you need -->
<phase>validate</phase>
<goals>
<goal>copy-resources</goal>
</goals>
<configuration>
<outputDirectory>bin</outputDirectory>
<resources>
<resource>
<directory>src/main/webapp/</directory>
</resource>
</resources>
</configuration>
</execution>
</executions>
</plugin>
<plugin>
<artifactId>maven-compiler-plugin</artifactId>
<version>3.1</version>
<configuration>
<source>1.7</source>
<target>1.7</target>
</configuration>
</plugin>
<plugin>
<artifactId>maven-war-plugin</artifactId>
<version>2.4</version>
<configuration>
<warSourceDirectory>bin</warSourceDirectory>
<failOnMissingWebXml>false</failOnMissingWebXml>
</configuration>
</plugin>
</plugins>
</build>
Please find below the current directory structure of war file after unzip the war. Maven is including complete webapp directory under WEB-INF/Classes , But i want only java class files(ndaws directory). I have tried a lot of excluding techniques, But nothing works.

Got the solution, My changes in pom is not reflecting, war is being created from build folder under target.
Thanks

remove resource directory from maven-resources-plugin
and add warSourceDirectory to maven-war-plugin
<plugin>
<artifactId>maven-war-plugin</artifactId>
<version>3.0.0</version>
<configuration>
<warSourceDirectory>src/main/webapp</warSourceDirectory>
</configuration>
</plugin>
or if using intelij and webapp folder marked 'resoures', select the folder.
open context menu.
Mark Directory as > Unmark as Resources Root

I tryed alot of solutions. In the end I found one that solve my problem... It's a similiar case, but I need to exclude a folder inside the webapp.
I opened my war file using 7zip... The folder that I want to exclude were in the main page.
I used this:
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-war-plugin</artifactId>
<version>3.2.3</version>
<configuration>
<packagingExcludes>myfolder/**</packagingExcludes>
</configuration>
</plugin>
Just change "myfolder" with the folder that you want to exclude.
If that is more than one folder, multiply this line.

How to give an output directory in maven bundle plugin

I started creating an OSGI bundle. So It works fine. But when I put output directory in configuration section in maven bundle plugin, it won't add any of compiled classes. simply say, the classpath is empty.I am also using maven compiler plugin. Are they conflicting each other? Is there anything which I configured in a wrong way. This is the build section of my pox.xml file.
<build>
<plugins>
<plugin>
<artifactId>maven-compiler-plugin</artifactId>
<version>3.1</version>
<configuration>
<source>1.7</source>
<target>1.7</target>
</configuration>
</plugin>
<plugin>
<groupId>org.apache.felix</groupId>
<artifactId>maven-bundle-plugin</artifactId>
<version>1.4.0</version>
<extensions>true</extensions>
<configuration>
<instructions>
<Bundle-SymbolicName>${project.artifactId}</Bundle-SymbolicName>
<Bundle-Name>${project.artifactId}</Bundle-Name>
<Export-Package>
demo.wso2.orderprocess.*
</Export-Package>
</instructions>
<outputDirectory>/home/wso2/product/wso2esb-4.9.0/repository/components/dropins</outputDirectory>
</configuration>
</plugin>
</plugins>

You should use <buildDirectory>/home/wso2/product/wso2esb-4.9.0/repository/components/dropins</buildDirectory> instead of <outputDirectory>/home/wso2/product/wso2esb-4.9.0/repository/components/dropins</outputDirectory>. It did the trick for me, so now I can increase the speed of the OSGI bundles development!
Reference:
Maven Bundle Plugin documentation

Here is what I did to get around the issue and it worked!!!
Keep your project packaging type as "jar" and add OSGI metadata to it. This can be achieved by adding an execution goal to the maven-bundle-plugin and referencing it from maven-jar-plugin. Now, just add the outputDirectory path into the maven-jar-plugin where you want to place the jar.
<plugin>
<artifactId>maven-jar-plugin</artifactId>
<configuration>
<archive>
<manifestFile>${project.build.outputDirectory}/META-INF/MANIFEST.MF</manifestFile>
</archive>
</configuration>
<outputDirectory>/path/to/output/directory</outputDirectory>
</plugin>
<plugin>
<groupId>org.apache.felix</groupId>
<artifactId>maven-bundle-plugin</artifactId>
<executions>
<execution>
<id>bundle-manifest</id>
<phase>process-classes</phase>
<goals>
<goal>manifest</goal>
</goals>
</execution>
</executions>
</plugin>
Now, to build the project, run the following command. This will generate the manifest file and package it into jar.
mvn org.apache.felix:maven-bundle-plugin:manifest install
Reference:
Apache Felix Documentation

How to put maven zip dependency on classpath for Java tests

I have a Java project entirely consisting of junit/integration tests which is managed by maven. One of the dependencies is a zip archive, the contents of which I would like to be available on the classpath when the tests are run. Since maven does not put the content of a zip dependency on the classpath I have had to come up with what I consider to be a hacky workaround. I unpack the zip archive to a temp directory then copy one of the resulting directories into the /test-classes folder. I also had to make the clean step delete the temp directory. Here are the relevant parts of the pom:
<groupId>com.my.package</groupId>
<artifactId>test-project</artifactId>
<version>0.0.1-SNAPSHOT</version>
<name>My Test Project</name>
<properties>
<config.artifactId>environment-dev</config.artifactId>
<config.version>2.0.8-SNAPSHOT</config.version>
<tempDir>${project.basedir}/temp</tempDir>
</properties>
<build>
<plugins>
...
<!-- clean out our custom temp directory as well as the default dir during clean phase-->
<plugin>
<artifactId>maven-clean-plugin</artifactId>
<version>2.3</version>
<configuration>
<filesets>
<fileset>
<directory>${tempDir}</directory>
</fileset>
</filesets>
</configuration>
</plugin>
<!-- since the config dependency is a zip it does not get added to the classpath. So we extract
it to a temp dir, then copy the content we need into a directory on the classpath -->
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-dependency-plugin</artifactId>
<version>2.8</version>
<executions>
<execution>
<id>unpack-config</id>
<phase>compile</phase>
<goals><goal>unpack-dependencies</goal></goals>
<configuration>
<includeGroupIds>com.my.package.config</includeGroupIds>
<includeArtifactIds>${config.artifactId}</includeArtifactIds>
<includeClassifiers>config</includeClassifiers>
<outputDirectory>${tempDir}</outputDirectory>
</configuration>
</execution>
</executions>
</plugin>
<!-- copy the content of the zip file that we extracted into a directory on the classpath -->
<plugin>
<artifactId>maven-resources-plugin</artifactId>
<version>2.6</version>
<executions>
<execution>
<phase>compile</phase>
<goals><goal>copy-resources</goal></goals>
<configuration>
<outputDirectory>${project.build.directory}/test-classes/TargetDir</outputDirectory>
<resources>
<resource>
<directory>${tempDir}/${config.artifactId}-${config.version}/TargetDir</directory>
<filtering>true</filtering>
</resource>
</resources>
</configuration>
</execution>
</executions>
</plugin>
</plugins>
</build>
<dependencies>
...
<dependency>
<groupId>com.my.package.config</groupId>
<artifactId>${config.artifactId}</artifactId>
<version>${config.version}</version>
<classifier>config</classifier>
<type>zip</type>
</dependency>
</dependencies>
There must be a better way of doing this.
Can I force maven to treat the zip file as if it were a jar? The link I provided has a tantalising hint that this might once have been possible, but I can't find anything relevant in the documentation. This seems like such a simple thing to be able to do, I really hope I've just missed a config parameter somewhere. Can anyone suggest a better way of getting the content of a zip dependency onto the classpath?

I would unzip the dependency into a subdirectory of the target directory and add that directory to the additionalClasspathElements configuration of the surefire plugin.
<properties>
<config.artifactId>environment-dev</config.artifactId>
<config.version>2.0.8-SNAPSHOT</config.version>
<unzipDir>${project.build.directory}/addTestClasspath</unzipDir>
</properties>
<build>
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-dependency-plugin</artifactId>
<version>2.8</version>
<executions>
<execution>
<id>unpack-config</id>
<phase>compile</phase>
<goals><goal>unpack-dependencies</goal></goals>
<configuration>
<includeGroupIds>com.my.package.config</includeGroupIds>
<includeArtifactIds>${config.artifactId}</includeArtifactIds>
<includeClassifiers>config</includeClassifiers>
<outputDirectory>${unzipDir}</outputDirectory>
</configuration>
</execution>
</executions>
</plugin>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-surefire-plugin</artifactId>
<version>2.17</version>
<configuration>
<additionalClasspathElements>
<additionalClasspathElement>${unzipDir}</additionalClasspathElement>
</additionalClasspathElements>
</configuration>
</plugin>
</plugins>
</build>
In this case you can omit the clean plugin config because everything is under the target folder which will be deleted by the clean plugin by default.
Sadly this configuration does only work on the command line and not within eclipse, because the m2e plugin does not honor the additionalClasspathElement. See the jira issue MNGECLIPSE-1213

Maven: Where to put generated resources for tomcat-maven-plugin?

I have CSS and JavaScript files in src/main/webapp directory of my project.
I want to join add joined and minified version of these resources to my WAR file and to the place where tomcat-maven-plugin picks it up.
I used yuicompressor-maven-plugin to create the files and put it to ${project.build.directory}/${project.build.finalName}. It works great for maven package and those resources make their way to WAR file, but somehow tomcat-maven-plugin does not see those at all. Should I use a different directory for it?
My pom:
<plugins>
<plugin>
<groupId>org.codehaus.mojo</groupId>
<artifactId>tomcat-maven-plugin</artifactId>
<version>1.1</version>
<configuration>
<path>/MyApp</path>
<warDirectory>${project.build.directory}/${project.build.finalName}</warDirectory>
</configuration>
</plugin>
<plugin>
<version>2.5.1</version>
<inherited>true</inherited>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-compiler-plugin</artifactId>
<configuration>
<source>1.6</source>
<target>1.6</target>
<optimize>true</optimize>
<debug>true</debug>
</configuration>
</plugin>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-resources-plugin</artifactId>
<version>2.5</version>
<configuration>
<encoding>UTF-8</encoding>
</configuration>
</plugin>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-war-plugin</artifactId>
<version>2.2</version>
<configuration>
<webResources>
<resource>
<directory>${basedir}/src/main/resources/META-INF</directory>
<filtering>true</filtering>
<targetPath>META-INF</targetPath>
<includes>
<include>context.xml</include>
</includes>
</resource>
</webResources>
<archive>
<addMavenDescriptor>false</addMavenDescriptor>
<manifest>
<addDefaultImplementationEntries>true</addDefaultImplementationEntries>
<addClasspath>true</addClasspath>
</manifest>
</archive>
</configuration>
</plugin>
<plugin>
<groupId>net.alchim31.maven</groupId>
<artifactId>yuicompressor-maven-plugin</artifactId>
<version>1.3.0</version>
<executions>
<execution>
<phase>process-resources</phase>
<configuration>
<excludes>
<exclude>**/*</exclude>
</excludes>
<aggregations>
<aggregation>
<output>${project.build.directory}/${project.build.finalName}/js/commons-pack.js</output>
<includes>
<include>${project.build.sourceDirectory}/../webapp/js1.js</include>
<include>${project.build.sourceDirectory}/../webapp/js2.js</include>
...
What should I do to make mvn tomcat:run to also pick up my generated files?

Use warSourceDirectory:
<warSourceDirectory>${project.build.directory}/${project.build.finalName}</warSourceDirectory>
Instead of this configuration property (warDirectory) for the tomcat-maven-plugin:
<warDirectory>${project.build.directory}/${project.build.finalName}</warDirectory>
According to the tomcat-maven-plugin documentation, warSourceDirectory is where the web resources get picked up, and its default value is ${basedir}/src/main/webapp. This means that if you don’t set that property, you need to generate your unified/minified JavaScript file under ${basedir}/src/main/webapp.
If you set warSourceDirectory to the output folder, this means you need to generate this file before starting Tomcat.

Alternatively, you can also use the run-war goal instead of run, e.g. mvn tomcat6:run-war. This wil use the exploded war in your build directory (and thus filtered resources). See this site. There is also run-war-only which skips the packaging phase.

Note the plugin is now maintained at Apache (so upgrade a bit :-) ) see http://tomcat.apache.org/maven-plugin-2.0/.
Even it works using install I'm not sure it's the optimum solution (regarding io and build time).
The tomcat run must be able to use resources from more than one directory (I'm not sure it's possible with the current tomcat embeded api).
Can you add a feature request here https://issues.apache.org/jira/browse/MTOMCAT
Thanks