In my app, I have a requirement to format 12 hours time to 24 hours time. What is the method I have to use?
For example, time like 10:30 AM. How can I convert to 24 hours time in java?
Try this:
import java.text.SimpleDateFormat;
import java.util.Date;
public class Main {
public static void main(String [] args) throws Exception {
SimpleDateFormat displayFormat = new SimpleDateFormat("HH:mm");
SimpleDateFormat parseFormat = new SimpleDateFormat("hh:mm a");
Date date = parseFormat.parse("10:30 PM");
System.out.println(parseFormat.format(date) + " = " + displayFormat.format(date));
}
}
which produces:
10:30 PM = 22:30
See: http://download.oracle.com/javase/1.5.0/docs/api/java/text/SimpleDateFormat.html
java.time
In Java 8 and later it could be done in one line using class java.time.LocalTime.
In the formatting pattern, lowercase hh means 12-hour clock while uppercase HH means 24-hour clock.
Code example:
String result = // Text representing the value of our date-time object.
LocalTime.parse( // Class representing a time-of-day value without a date and without a time zone.
"03:30 PM" , // Your `String` input text.
DateTimeFormatter.ofPattern( // Define a formatting pattern to match your input text.
"hh:mm a" ,
Locale.US // `Locale` determines the human language and cultural norms used in localization. Needed here to translate the `AM` & `PM` value.
) // Returns a `DateTimeFormatter` object.
) // Return a `LocalTime` object.
.format( DateTimeFormatter.ofPattern("HH:mm") ) // Generate text in a specific format. Returns a `String` object.
;
See this code run live at IdeOne.com.
15:30
See Oracle Tutorial.
Assuming that you use SimpleDateFormat implicitly or explicitly, you need to use H instead of h in the format string.
E.g
HH:mm:ss
instead of
hh:mm:ss
12 to 24 hour time conversion and can be reversed if change time formate in output and input SimpleDateFormat class parameter
Test Data Input:
String input = "07:05:45PM";
timeCoversion12to24(input);
output
19:05:45
public static String timeCoversion12to24(String twelveHoursTime) throws ParseException {
//Date/time pattern of input date (12 Hours format - hh used for 12 hours)
DateFormat df = new SimpleDateFormat("hh:mm:ssaa");
//Date/time pattern of desired output date (24 Hours format HH - Used for 24 hours)
DateFormat outputformat = new SimpleDateFormat("HH:mm:ss");
Date date = null;
String output = null;
//Returns Date object
date = df.parse(twelveHoursTime);
//old date format to new date format
output = outputformat.format(date);
System.out.println(output);
return output;
}
SimpleDateFormat parseFormat = new SimpleDateFormat("hh:mm a");
provided by Bart Kiers answer should be replaced with somethig like
SimpleDateFormat parseFormat = new SimpleDateFormat("hh:mm a",Locale.UK);
Try This
public static String convertTo24Hour(String Time) {
DateFormat f1 = new SimpleDateFormat("hh:mm a"); //11:00 pm
Date d = null;
try {
d = f1.parse(Time);
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
DateFormat f2 = new SimpleDateFormat("HH:mm");
String x = f2.format(d); // "23:00"
return x;
}
static String timeConversion(String s)
{
String s1[]=s.split(":");
char c[]=s1[2].toCharArray();
if(s1[2].contains("PM"))
{
int n=Integer.parseInt(s1[0]);
n=n+12;
return n+":"+s1[1]+":"+c[0]+c[1];
}
else``
return s1[0]+":"+s1[1]+":"+c[0]+c[1];
}
It can be done using Java8 LocalTime. Here is the code.
import java.time.LocalTime;
import java.time.format.DateTimeFormatter;
public class TimeConversion {
public String timeConversion(String s) {
LocalTime.parse(s, DateTimeFormatter.ofPattern("hh:mm a"));
}
}
And Here is the test case for the same:
import org.junit.jupiter.api.Assertions;
import org.junit.jupiter.api.Test;
class TimeConversionTest {
#Test
void shouldReturnTimeIn24HrFormat() {
TimeConversion timeConversion = new TimeConversion();
Assertions.assertEquals("22:30", timeConversion.timeConversion("10:30 PM"));
}
}
Using LocalTime in Java 8, LocalTime has many useful methods like getHour() or the getMinute() method,
For example,
LocalTime intime = LocalTime.parse(inputString, DateTimeFormatter.ofPattern("h:m a"));
String outtime = intime.format(DateTimeFormatter.ISO_LOCAL_TIME);
In some cases, First line alone can do the required parsing
This is the extract of code that I have done.
String s="08:10:45";
String[] s1=s.split(":");
int milipmHrs=0;
char[] arr=s1[2].toCharArray();
boolean isFound=s1[2].contains("PM");
if(isFound){
int pmHrs=Integer.parseInt(s1[0]);
milipmHrs=pmHrs+12;
return(milipmHrs+":"+s1[1]+":"+arr[0]+arr[1]);
}
else{
return(s1[0]+":"+s1[1]+":"+arr[0]+arr[1]);
}
import java.text.SimpleDateFormat;
import java.text.DateFormat;
import java.util.Date;
public class Main {
public static void main(String [] args){
try {
DateFormat parseFormat = new SimpleDateFormat("dd-MM-yyyy hh:mm:ss a");
String sDate = "22-01-2019 9:0:0 PM";
Date date = parseFormat.parse(sDate);
SimpleDateFormat displayFormat = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");
sDate = displayFormat.format(date);
LOGGER.info("The required format : " + sDate);
} catch (Exception e) {}
}
}
Try this to calculate time difference between two times.
first it will convert 12 hours time into 24 hours then it will take diff between two times
String a = "09/06/18 01:55:33 AM";
String b = "07/06/18 05:45:33 PM";
String [] b2 = b.split(" ");
String [] a2 = a.split(" ");
SimpleDateFormat displayFormat = new SimpleDateFormat("HH:mm:ss");
SimpleDateFormat parseFormat = new SimpleDateFormat("hh:mm:ss a");
String time1 = null ;
String time2 = null ;
if ( a.contains("PM") && b.contains("AM")) {
Date date = parseFormat.parse(a2[1]+" PM");
time1 = displayFormat.format(date);
time2 = b2[1];
}else if (b.contains("PM") && a.contains("AM")) {
Date date = parseFormat.parse(a2[1]+" PM");
time1 = a2[1];
time2 = displayFormat.format(date);
}else if (a.contains("PM") && b.contains("PM")){
Date datea = parseFormat.parse(a2[1]+" PM");
Date dateb = parseFormat.parse(b2[1]+" PM");
time1 = displayFormat.format(datea);
time2 = displayFormat.format(dateb);
}
System.out.println(time1);
System.out.println(time2);
SimpleDateFormat format = new SimpleDateFormat("HH:mm:ss");
Date date1 = format.parse(time1);
Date date2 = format.parse(time2);
long difference = date2.getTime() - date1.getTime();
System.out.println(difference);
System.out.println("Duration: "+DurationFormatUtils.formatDuration(difference, "HH:mm"));
For More Details Click Here
I have written a simple utility function.
public static String convert24HourTimeTo12Hour(String timeStr) {
try {
DateFormat inFormat = new SimpleDateFormat( "HH:mm:ss");
DateFormat outFormat = new SimpleDateFormat( "hh:mm a");
Date date = inFormat.parse(timeStr);
return outFormat.format(date);
}catch (Exception e){}
return "";
}
Try this below code,
public static String timeConversion(String s) {
String militaryTime = "";
String hourString = s.substring(0,2);
String timeFormat = s.substring(8,10);
String timeBody = s.substring(2,8);
if (timeFormat.equals("AM")){
if (hourString.equals("12")){
militaryTime = "00" + timeBody;
}else{
militaryTime = hourString + timeBody;
}
}else if (timeFormat.equals("PM")){
if (hourString.equals("12")){
militaryTime = hourString + timeBody;
}else{
int value = Integer.parseInt(hourString) + 12;
militaryTime = String.valueOf(value) + timeBody;
}
}
return militaryTime;
}
Without using library methods
public static String timeConversion(String s) {
String[] timeElements = s.split(":");
if (s.contains("PM")) {
timeElements[0] = getPMHours(timeElements[0]);
} else {
timeElements[0] = getAMHours(timeElements[0]);
}
timeElements[2] = timeElements[2].substring(0,2);
return timeElements[0]+":"+timeElements[1]+":"+timeElements[2];
}
private static String getAMHours(String hour) {
if(Integer.parseInt(hour) == 12) return "00";
return hour;
}
private static String getPMHours(String hour) {
int i = Integer.parseInt(hour);
if(i != 12) return 12+i+"";
return i+"";
}
I was looking for same thing but in number, means from integer xx hour, xx minutes and AM/PM to 24 hour format xx hour and xx minutes, so here what i have done:
private static final int AM = 0;
private static final int PM = 1;
/**
* Based on concept: day start from 00:00AM and ends at 11:59PM,
* afternoon 12 is 12PM, 12:xxAM is basically 00:xxAM
* #param hour12Format
* #param amPm
* #return
*/
private int get24FormatHour(int hour12Format,int amPm){
if(hour12Format==12 && amPm==AM){
hour12Format=0;
}
if(amPm == PM && hour12Format!=12){
hour12Format+=12;
}
return hour12Format;
}`
private int minutesTillMidnight(int hour12Format,int minutes, int amPm){
int hour24Format=get24FormatHour(hour12Format,amPm);
System.out.println("24 Format :"+hour24Format+":"+minutes);
return (hour24Format*60)+minutes;
}
We can solve this by using String Buffer
String s;
static String timeConversion(String s) {
StringBuffer st=new StringBuffer(s);
for(int i=0;i<=st.length();i++){
if(st.charAt(0)=='0' && st.charAt(1)=='1' &&st.charAt(8)=='P' ){
// if(st.charAt(2)=='1'){
// st.replace(1,2,"13");
st.setCharAt(0, '1');
st.setCharAt(1, '3');
}else if(st.charAt(0)=='0' && st.charAt(1)=='2' &&st.charAt(8)=='P' ){
// if(st.charAt(2)=='1'){
// st.replace(1,2,"13");
st.setCharAt(0, '1');
st.setCharAt(1, '4');
}else if(st.charAt(0)=='0' && st.charAt(1)=='3' &&st.charAt(8)=='P' ){
// if(st.charAt(2)=='1'){
// st.replace(1,2,"13");
st.setCharAt(0, '1');
st.setCharAt(1, '5');
}else if(st.charAt(0)=='0' && st.charAt(1)=='4' &&st.charAt(8)=='P' ){
// if(st.charAt(2)=='1'){
// st.replace(1,2,"13");
st.setCharAt(0, '1');
st.setCharAt(1, '6');
}else if(st.charAt(0)=='0' && st.charAt(1)=='5' &&st.charAt(8)=='P' ){
// if(st.charAt(2)=='1'){
// st.replace(1,2,"13");
st.setCharAt(0, '1');
st.setCharAt(1, '7');
}else if(st.charAt(0)=='0' && st.charAt(1)=='6' &&st.charAt(8)=='P' ){
// if(st.charAt(2)=='1'){
// st.replace(1,2,"13");
st.setCharAt(0, '1');
st.setCharAt(1, '8');
}else if(st.charAt(0)=='0' && st.charAt(1)=='7' &&st.charAt(8)=='P' ){
// if(st.charAt(2)=='1'){
// st.replace(1,2,"13");
st.setCharAt(0, '1');
st.setCharAt(1, '9');
}else if(st.charAt(0)=='0' && st.charAt(1)=='8' &&st.charAt(8)=='P' ){
// if(st.charAt(2)=='1'){
// st.replace(1,2,"13");
st.setCharAt(0, '2');
st.setCharAt(1, '0');
}else if(st.charAt(0)=='0' && st.charAt(1)=='9' &&st.charAt(8)=='P' ){
// if(st.charAt(2)=='1'){
// st.replace(1,2,"13");
st.setCharAt(0, '2');
st.setCharAt(1, '1');
}else if(st.charAt(0)=='1' && st.charAt(1)=='0' &&st.charAt(8)=='P' ){
// if(st.charAt(2)=='1'){
// st.replace(1,2,"13");
st.setCharAt(0, '2');
st.setCharAt(1, '2');
}else if(st.charAt(0)=='1' && st.charAt(1)=='1' &&st.charAt(8)=='P' ){
// if(st.charAt(2)=='1'){
// st.replace(1,2,"13");
st.setCharAt(0, '2');
st.setCharAt(1, '3');
}else if(st.charAt(0)=='1' && st.charAt(1)=='2' &&st.charAt(8)=='A' ){
// if(st.charAt(2)=='1'){
// st.replace(1,2,"13");
st.setCharAt(0, '0');
st.setCharAt(1, '0');
}else if(st.charAt(0)=='1' && st.charAt(1)=='2' &&st.charAt(8)=='P' ){
st.setCharAt(0, '1');
st.setCharAt(1, '2');
}
if(st.charAt(8)=='P'){
st.setCharAt(8,' ');
}else if(st.charAt(8)== 'A'){
st.setCharAt(8,' ');
}
if(st.charAt(9)=='M'){
st.setCharAt(9,' ');
}
}
String result=st.toString();
return result;
}
I am trying to count the occurrence of the each string. If the month matches with current, then I'm displaying count of the that string.
Suppose this month is 07 and modifiedtime months are like 07, 06, 09, 06, 07 in that what are the month 07 are there for that month what is count of the each item
Example: Month = 07 , count of opportunity should be 1,
output:
What I'm getting :
Count_opportunity:02
Count_proposal:02
Count_negotiation:01
Count_won:32
Count_lost:17
Desired output:
Count_opportunity:01
Count_proposal:0
Count_negotiation:0
Count_won:0
Count_lost:0
The following code gives me a wrong count. Can some-one detect the error?
private void workingOnResponseMonthwiseOpportunity(SyncModule syncModule){
String success = syncModule.getSuccess();
if (success.equals("true")) {
SyncResults results = syncModule.getResult();
Sync sync = results.getSync();
ArrayList<SyncUpdated> syncUpdateds = sync.getUpdated();
for (SyncUpdated syncUpdated : syncUpdateds) {
ArrayList<SyncBlocks> syncBlocks = syncUpdated.getBlocks();
String scheduleDates = "";
String scheduleDate = "";
String supportrequired="";
String winprob="";
String salesstage="";
String modality="";
String modifydatetime="";
String modifiedtime="";
String date1 = new SimpleDateFormat("dd-MM-yyyy", Locale.getDefault()).format(new Date());
for (SyncBlocks syncBlocks1 : syncBlocks) {
String label = syncBlocks1.getLabel();
if (label.equals("Basic Information")) {
ArrayList<SynFields> synFields = syncBlocks1.getFields();
for (SynFields synFields1 : synFields) {
name = synFields1.getName();
values = synFields1.getValue();
//sales stage
if (name.equals("sales_stage")) {
salesstage = String.valueOf(values);
salesstage_list.add(salesstage);
//support required
}
}
}
else if (label.equals("Opportunity Details")) {
ArrayList<SynFields> synFields = syncBlocks1.getFields();
for (SynFields synFields1 : synFields) {
String name = synFields1.getName();
values = synFields1.getValue();
if (("modifiedtime".equals(name))) {
modifydatetime = String.valueOf(values);
Log.d("modifydatetime",modifydatetime);
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
modifiedmonth= LocalDateTime.from(LocalDateTime.parse(modifydatetime, DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss")));
Log.d("modifiedmonth", String.valueOf(modifiedmonth));
break;
}
}
}
PreferenceManagerMyOpportunity.getInstance(requireContext()).setMultipleDataOpportunity(scheduleDate, salesstage, supportrequired, winprob, modality,modifiedtime);
}
MyOpportunityModel opportunityModel = new MyOpportunityModel(scheduleDate, salesstage, supportrequired, winprob, modality, modifydatetime);
java.time.LocalDate today = java.time.LocalDate.now();
int month=today.getMonthValue();
Log.d("month",String.valueOf(month));
boolean isModifiedThisMonth =modifiedmonth==month;
Log.d("isModifiedThisMonth",String.valueOf(isModifiedThisMonth));
if (isModifiedThisMonth) {
//Sales stage starts
Count_opportunity = Collections.frequency(salesstage_list, "Opportunity");
System.out.println("Count_opportunity: "+ Count_opportunity);
Count_proposal = Collections.frequency(salesstage_list, "Proposal or Price Quote");
//System.out.println("Count of In Complete is: "+ Count_Incomplete);
Count_negotiation = Collections.frequency(salesstage_list, "Negotiation or Review");
Count_won = Collections.frequency(salesstage_list, "Closed Won");
Count_lost = Collections.frequency(salesstage_list, "Closed Lost");
// System.out.println("Count of Completed is: "+ Complted_Count);
}
}
}
}
}
I have a text file which contains a list of athletes with their date of birth.
I'm trying to figure out how I can read from the text file only the athletes who are on the "elite" team and who are older than 18.
I have figured out how to get only the "elite" athletes, but I can't think of how to solve the age problem.
The birthdates are created separated integers day, month and year
This is the code I've been working on
public void readUngdomElite() throws FileNotFoundException, IOException {
BufferedReader br = null;
try {
String sCurrentLine;
//file to read
br = new BufferedReader(new FileReader("medlemlist.txt"));
while ((sCurrentLine = br.readLine()) != null) {
if (sCurrentLine.contains("elite")) {
System.out.println(sCurrentLine);
}}
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
if (br != null)br.close();
} catch (IOException ex) {
ex.printStackTrace();
}
}
}
This code gets me all the athletes who are elite, but I want the elite athletes who are older than 18.
Firstly you should provide a .txt file content. But to check if team is older than 18 years you can use this method. Date there is String type and YYYY-MM-dd format.
public boolean isAdult(String birthday) {
String[] parts = birthday.split("-");
if (parts.length==3) {
int year = Integer.parseInt(parts[0]);
int month = Integer.parseInt(parts[1]);
int day = Integer.parseInt(parts[2]);
String currentDate = getCurrentDate();
if (!currentDate.isEmpty() && currentDate.contains("-")) {
String[] parts2 = currentDate.split("-");
if (parts2.length==3) {
int cYear = Integer.parseInt(parts2[0]);
int cMonth = Integer.parseInt(parts2[1]);
int cDay = Integer.parseInt(parts2[2]);
int rYear = cYear - year;
int rMonth = cMonth - month;
int rDay = cDay - day;
if (rMonth<0)
rYear = rYear - 1;
else if (rMonth == 0 && rDay<0)
rYear = rYear - 1;
if (rYear > 17)
return true;
}
}
}
return false;
}
private String getCurrentDate() {
Date todayDate = Calendar.getInstance().getTime();
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd");
String todayString = formatter.format(todayDate);
return (todayString!=null)? todayString : "";
}
Feel free to edit the code as you need
The new Date and Time library provides you with convenient methods such as:
LocalDate.of(2015, 02, 20);
LocalDate.parse("2015-02-20");
Period.between(firstDate, secondDate)
With that it shouldn't be too hard to find an age based on how your string looks.
String str = "12 01 1996";
String[] arr = str.split(" ");
LocalDate birth = LocalDate.of(Integer.valueOf(arr[2]), Integer.valueOf(arr[1]), Integer.valueOf(arr[0]));
LocalDate now = LocalDate.now();
if (Period.between(birth, now).getYears() > 18) {
System.out.println("major");
} else {
System.out.println("minor");
}
I want to write a java method that takes a string in input and outputs another string following this rule:
input output
"123456" "12:34:56"
"23456" "02:34:56"
"3456" "00:34:56"
"456" "00:04:56"
"6" "00:00:06"
Any help would be appreciated. Thanks.
I would advice to use DateFormat as below. This will take care of all the burdens of conversion.
DateFormat formatFrom = new SimpleDateFormat("HHmmss");
DateFormat formatTo = new SimpleDateFormat("HH:mm:ss");
String origTimeString = "456";
String newDateString = null;
try {
String formattedString =
String.format("%06d", Integer.parseInt(origTimeString));
Date date = formatFrom.parse(formattedString);
newDateString = formatTo.format(date);
} catch (ParseException e) {
e.printStackTrace();
}
System.out.println("Updated string : " + newDateString);
Copy this method and use it.
1) If string length is more than 6, it's going to return "ERROR".
2) First fixes the String with '0'
3) Second fixes the String with ':'
4) StringBuilder is used for concat. Avoid using '+' operator for concat.
5) Method 'getDate' is static because of 'main' method is static, too.
public static String getDate(String variable){
StringBuilder aux= new StringBuilder();
StringBuilder string= new StringBuilder();
int length = variable.length();
if(length>6 || length<=0){
return "ERROR";
}else{
//first to fill blanks with 0
for(int i=0;i<6-length;i++){
aux.append("0");
}
variable = aux.append(variable).toString();
//second to put :
for(int i=0;i<6;i++){
if(i%2==0 && i!=0){
string.append(":");
}
string.append(variable.charAt(i));
}
return string.toString();
}
}
public static void main(String[] args) {
System.out.print(getDate("464"));
}
my application takes in a string like this "2002-10-15 10:55:01.000000". I need to validate that the string is a valid for a db2 timestamp.
How can I do this?
EDIT: This mostly works
public static boolean isTimeStampValid(String inputString) {
SimpleDateFormat format = new java.text.SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSSSSS");
try {
format.parse(inputString);
return true;
} catch (ParseException e) {
return false;
}
}
The problem is that if I pass it a bad format for milliseconds like "2011-05-02 10:10:01.0av" this will pass validation. I am assuming that since the first millisecond character is valid then it just truncates the rest of the string.
I'm not exactly sure about the format but you you can play around it and can try something like this
public static bool isTimeStampValid(String inputString)
{
SimpleDateFormat format = new java.text.SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSSSSS");
try{
format.parse(inputString);
return true;
}
catch(ParseException e)
{
return false;
}
}
EDIT: if you want to validate for numbers after successful parsing, you could do
format.parse(inputString);
Pattern p = Pattern.compile("^\\d{4}[-]?\\d{1,2}[-]?\\d{1,2} \\d{1,2}:\\d{1,2}:\\d{1,2}[.]?\\d{1,6}$");
return p.matcher(inputString).matches();
instead of
format.parse(inputString);
return true;
http://download.oracle.com/javase/6/docs/api/java/text/SimpleDateFormat.html
I believe the format would be "yyyy-MM-dd HH:mm:ss.SSSSSS"
Call parse(String) and catch ParseException indicating it is invalid.
/**
* This method validates the given time stamp in String format
* #param timestamp
* #return
*/
public static boolean isTimeStampValid(String timestamp) {
//(Considering that formal will be yyyy-MM-dd HH:mm:ss.SSSSSS )
//Tokenize string and separate date and time
boolean time = false;
try {
//Tokenize string and separate date and time
StringTokenizer st = new StringTokenizer(timestamp, " ");
if (st.countTokens() != 2) {
return false;
}
String[] dateAndTime = new String[2];
int i = 0;
while (st.hasMoreTokens()) {
dateAndTime[i] = st.nextToken();
i++;
}
String timeToken = dateAndTime[1];
StringTokenizer timeTokens = new StringTokenizer(timeToken, ":");
if (timeTokens.countTokens() != 3) {
return false;
}
String[] timeAt = new String[4];
int j = 0;
while (timeTokens.hasMoreTokens()) {
timeAt[j] = timeTokens.nextToken();
j++;
}
try {
int HH = Integer.valueOf(timeAt[0].toString());
int mm = Integer.valueOf(timeAt[1].toString());
float ss = Float.valueOf(timeAt[2].toString());
if (HH < 60 && HH >= 0 && mm < 60 && mm >= 0 && ss < 60 && ss >= 0) {
time = true;
} else {
}
} catch (Exception e) {
e.printStackTrace();
}
//Got Date
String dateToken = dateAndTime[0];//st.nextToken();
//Tokenize separated date and separate year-month-day
StringTokenizer dateTokens = new StringTokenizer(dateToken, "-");
if (dateTokens.countTokens() != 3) {
return false;
}
String[] tokenAt = new String[3];
//This will give token string array with year month and day value.
int k = 0;
while (dateTokens.hasMoreTokens()) {
tokenAt[k] = dateTokens.nextToken();
k++;
}
//Now try to create new date with got value of date
int dayInt = Integer.parseInt(tokenAt[2]);
int monthInt = Integer.parseInt(tokenAt[1]);
int yearInt = Integer.parseInt(tokenAt[0]);
Calendar cal = new GregorianCalendar();
cal.setLenient(false);
cal.set(yearInt, monthInt - 1, dayInt);
cal.getTime();//If not able to create date it will throw error
} catch (Exception e) {
e.printStackTrace();
return false;
}
//Here we ll check for correct format is provided else it ll return false
try {
Pattern p = Pattern.compile("^\\d{4}[-]?\\d{1,2}[-]?\\d{1,2} \\d{1,2}:\\d{1,2}:\\d{1,2}[.]?\\d{1,6}$");
if (p.matcher(timestamp).matches()) {
} else {
return false;
}
} catch (Exception e) {
e.printStackTrace();
return false;
}
//Cross checking with simple date format to get correct time stamp only
SimpleDateFormat format = new java.text.SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSSSSS");
try {
format.parse(timestamp);
//return true;
if (time) {
return true;
} else {
return false;
}
} catch (ParseException e) {
e.printStackTrace();
return false;
} catch (Exception e) {
e.printStackTrace();
return false;
}
}
If you're already connected to the database, you can execute a query that attempts to cast the input string as a timestamp, and check for a failure message (in this case, SQLSTATE 22007).
VALUES CAST( ? AS TIMESTAMP )
The above query will fully validate the input string while consuming hardly any resources on the database server. If the string is invalid for any reason, your database client will encounter an exception.