I'm developing a simple utility to record the screen of device using the new function of kitkat 4.4. So, I've create a button with various edit text for the parameters such as bit rate, seconds and file name. I've this code.
StringBuilder builder;
builder = new StringBuilder("system/bin/screenrecorder");
When i retrieve the parameters do something like
builder.append(" --bit-rate ").append(editText.getText());
Finally I've the complete command to record, like
"system/bin/screenrecorder --size 720x1184 --bit-rate 5 --time-limit 5 /storage/emulated/0/MyVideos/example.mp4"
My question now is this:
How can i execute this command? In other words, what should I do now to start recording using the variable builder?
Related
I got this simple problem whenever I say "search music click" its searching for 'search music click' too it's supposed to search my music file name click. I tried to put different variables but only boolean is the one that not causing an error.
if(voice_result.indexOf("search music") != -1){
voice_result.contains(voice_result)
String a = voice_result;
Intent intent = new Intent(MediaStore.INTENT_ACTION_MEDIA_PLAY_FROM_SEARCH);
intent.putExtra(MediaStore.EXTRA_MEDIA_FOCUS, MediaStore.Audio.Media.ENTRY_CONTENT_TYPE);
intent.putExtra(SearchManager.QUERY, a);
startActivity(intent);}
the voice_result here is the process result of my voice and if ever I try to search a music from voice command it always search "search music risky" instead of "risky".
You should write a parser/filter for whatever returned from the voice recognition api first. For example, you say "search music risk":
Remove unnecessary or confusing strings like "search" "music" from the raw data. I suggest you use regex matcher and map the with a set of commands with values.
After filtering the raw data (now only has "risk"), use the result for next job
I'm working on Java APP that will process the stream from the IP Camera (Milesight MS-C2682-P) located on Local network. It will detect objects and trigger actions depending on what's in the image (let´s say it will start an alarm, when a person is detected) - for that I need it to be with minimal delay.
I have an RTSP link "rtsp://username:password#ip_addr:rtsp_port/main", to access stream from my IP Camera, but in my JAVA app there is a 12 seconds delay (and it's increasing). This happens, when images are not handled fast enough, so they are buffered. There are "hacks" and "workarounds" (OpenCV VideoCapture lag due to the capture buffer), but I believe there has to be a prettier solution.
The other link I was able to get is an HTTP one, that uses also H.264 codec (can be used with MJPEG and MPEG4, if there is a possible way to use them effectively). "http://username:password#ip_addr:http_port/ipcam/mjpeg.cgi" - works like a charm.. in Python and browser. However, it doesn´t work in Java, an error is thrown:
OpenCV(4.2.0) C:\build\master_winpack-bindings-win64-vc14-static\opencv\modules\videoio\src\cap_images.cpp:253: error: (-5:Bad argument) CAP_IMAGES: can't find starting number (in the name of file): HTTP_URL in function 'cv::icvExtractPattern'
Both links work smoothly in VLC.
So, the network is not a problem ('cause VLC handles stream with minimal delay) and Python using OpenCV is also doing a good job. It all comes down to Java implementation of OpenCV.. I guess.
Here is a Java code:
VideoPlayer videoPlayer = new VideoPlayer(); // My Class, just creates and updates JFrame, works like a charm with laptop's webcam, so certainly no issues here
Mat image = new Mat();
VideoCapture ipCamera = new VideoCapture(RTSP_URL);
// or the HTTP link
// VideoCapture ipCamera = new VideoCapture(HTTP_URL);
// verify if u got access to camera
if (!ipCamera.isOpened()) {
System.out.println("ERROR: Camera isn't working !!! ");
return;
}
System.out.println("OK: Connected to camera.");
while (true) {
ipCamera.read(image);
videoPlayer.updateVideo_MatImage(image);
}
And this is the Python code I'm using:
import cv2
cap = cv2.VideoCapture(RTSP_URL)
# or the HTTP link
# cap = cv2.VideoCapture(HTTP_URL)
while True:
ret, image = cap.read()
cv2.imshow("Test", image)
if cv2.waitKey(1) & 0xFF == ord('q'):
break
cv2.destroyAllWindows()
I just need to get the latest image, when a request is made. So I need to avoid any kind of buffering. It has to be implemented in Java since it's a requirement for this project.
So is there a way to get only latest image from camera?
What could cause the error mentioned above?
Thank you guys for any advice.
I am trying to get VLCJ to do a visualizer for the mp3 files its playing from a HTTP stream. Video shows up when I stream one. But when audio plays, nothing happens.
This is my code on the cliente side
EmbeddedMediaPlayerComponent empc = new EmbeddedMediaPlayerComponent();
String[] op = {"audio-visual=visual", "effect-list=spectrum", "effect-width=800", "effect-height=80"};
empc.mediaPlayer().media().play("http://127.0.0.1:" + port, op);
There's a lot more code, but nothing directly related to VLCJ.
I can post the server code if you think it's necessary, but I think it's not needed since the media reaches the client perfectly.
So, audio and video work fine, but the visualizer simply doesn't show up.
Any help would be appreciated.
First, check if you have the visualisation plugins installed on your OS distribution.
I am using Linux Mint and those plugins are NOT installed by default when you install VLC.
Do this:
sudo apt install vlc-plugin-visualization
Second, it seems you have to set the visualisation options on the MediaPlayerFactory rather than passing them when you invoke play() on the media player.
For example:
String[] options = new String[] {"--audio-visual=visual", "--effect-list=scope,vuMeter,spectrometer,spectrum"};
factory = new MediaPlayerFactory(options);
mediaPlayer = factory.mediaPlayers().newEmbeddedMediaPlayer();
This example configures the factory before creating a media player from it, you can use any of the media player factory creation methods.
The visualisations scale with the size of the window, I could not get the width and height parameters to do anything.
This is fine for audio.
If you play video, then the video will go the video surface embedded in your application and VLC will open up a new separate window to show the visualisations (probably you don't want that).
I need to play Alert.startAudio() through the loudspeaker of a Blackberry device instead of the headset.
I know that I can change the Audio path through the AudioPathControl interface, but I don't know how to get an instance of AudioPathControl.
I found a LINK on how to do it on the Blackberry Knowledge base, but it only tells me how to do it using the Player class, which I don't want to do. Is there any way to get an instance of AudioPathControl of the current Application?
I would prefer to play a tone programmatically instead of including my own sound file. I found the following code snippet for that.
Player p = javax.microedition.media.Manager.createPlayer(javax.microedition.media.Manager.TONE_DEVICE_LOCATOR);
p.realize();
ToneControl tc = (ToneControl) p.getControl("ToneControl");
AudioPathControl apc = (AudioPathControl) p
.getControl("AudioPathControl");
apc.setAudioPath(AudioPathControl.AUDIO_PATH_HANDSFREE);
tc.setSequence(mySequence);
p.start();
But the problem is that apc is null and throws an Exception. Any solution?
Check the section Where Does the Sound Go? (preview from Google Books), from Advanced BlackBerry 6 Development By Chris King.
I'm currently building a Twitter client in Java using the Twitter4J API. To create a Twitter "timeline", I am currently pulling data from Twitter such as profile images, tweets and usernames, then displaying them in a JTextPane, formatted using HTML. Code example below:
StringBuilder out = new StringBuilder();
try {
List<Status> statuses = HandleEvents.instance().twitter.getHomeTimeline();
out.append("<html>");
for (Status status : statuses)
{
out.append("<img src=\"").append(status.getUser().getProfileImageURL())
.append("\" width=30 height=30><b>").append(status.getUser().getName())
.append(":</b> ").append(status.getText())
.append("<br><br>");
}
out.append("</html>");
tweetsTextPane.setText(out.toString());
This displays a timeline of 20 tweets, separated by two line breaks. Under each tweet, I would like to place a simple hyperlink, called "Retweet", which calls one of my Java methods - HandleEvents.instance().twitter.retweetStatus(status.getId())
How would I got about doing this? Can the call be made directly between the tags, or do I have to make the call using JavaScript?
Any help would be appreciated. Many thanks.
You don't really need to have a hyperlink do you? Since it's a Swing app you could just add a JLabel that only looks like a hyperlink (but if you put in a little effort, it could behave like one as well). Add a listener for mouse clicks on that JLabel and you've can hook your current handler there.
On the other hand, if you do want actual HTML links, what you can do is implement your own HyperlinkListener.
Here are a couple of examples:
http://www.java2s.com/Tutorial/Java/0240__Swing/HyperlinkListenerExample.htm
http://www.java2s.com/Code/Java/Event/DemonstratingtheHyperlinkListener.htm
http://www.devx.com/tips/Tip/12997