What is the Simple Date Format for "2014-01-02T23:03:30-05:00"?
I have googled and got the format only, yyyy-MM-dd'T'HH:mm:ssz. But this format is only working when my date format is without colon in the end "2014-01-02T23:03:30-0500".
Can anyone please advise on this?
If you use Java 7, you can replace the z by a X to allow for colon separator: yyyy-MM-dd'T'HH:mm:ssX.
See also the javadoc.
Before Java 7, you need to either parse it manually by first removing the colon or you can use an external library such as Jodatime or threeten.
There is the letter X for ISO 8601 timezone.
import java.text.*;
import java.util.*;
public class TimeZoneTest {
public static void main(final String[] args) throws ParseException {
final DateFormat format = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssXXX");
final String string = "2014-01-02T23:03:30-05:00";
final Date date = format.parse(string);
System.out.println(date);
}
}
Use an X instead of the Z
docs.oracle.com/javase/7/docs/api/java/text/SimpleDateFormat.html
FYI, you can pass that string directly to a constructor in Joda-Time 2.3. No need for a formatter. Joda-Time uses that standard ISO 8601 format as its default, even tolerating the lack of a colon in the offset.
Instead of passing DateTimeZone.UTC as I did in my example code below, you would pass the specific time zone of your interest.
// © 2013 Basil Bourque. This source code may be used freely forever by anyone taking full responsibility for doing so.
// import org.joda.time.*;
// import org.joda.time.format.*;
String string = "2014-01-02T23:03:30-0500";
DateTime dateTime = new DateTime( string, DateTimeZone.UTC );
System.out.println( "dateTime: " + dateTime );
When run:
dateTime: 2014-01-03T04:03:30.000Z
Related
public static String convertInDateTimeSecondTOJodaTime(String dateTime) {
try {
DateTimeFormatter formatter = DateTimeFormat.forPattern("yyyy-MM-dd'T'HH:mm:ss'Z'");
DateTime date = formatter.parseDateTime(dateTime).withZoneRetainFields(DateTimeZone.UTC);
return date.toString("h:mm aa");
} catch (Exception e) {
return null;
}
}
main(){
print(convertInDateTimeSecondTOJodaTime("2020-04-09T07:31:16Z"))
}
I am trying to convert given date-time in UTC format using joda date time it's giving wrong time it's given one hour before please help me what I am doing wrong.
The desired result is in London time, so 8:31 AM in this case.
import java.util.Date;
import java.util.TimeZone;
import java.text.SimpleDateFormat;
public class CurrentUtcDate {
public static void main(String[] args) {
Date date = new Date();
SimpleDateFormat dateFormat = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");
dateFormat.setTimeZone(TimeZone.getTimeZone("UTC"));
System.out.println("UTC Time is: " + dateFormat.format(date));
}
}
Output
UTC Time is: 22-01-2018 13:14:35
You can check here https://www.quora.com/How-do-I-get-the-current-UTC-date-using-Java
As you need to you use Joda DateTime, you need to use formatter of Joda.
You are returning date with pattern "h:mm aa" so I assume you need to extract time from the date.
Below code should work:
import java.util.Locale;
import org.joda.time.DateTime;
import org.joda.time.format.DateTimeFormat;
import org.joda.time.format.DateTimeFormatter;
public class MyDateCoonverter {
public static void main(String a[]) {
System.out.println(convertInDateTimeSecondTOJodaTime("2020-04-09T07:31:16Z"));
}
public static String convertInDateTimeSecondTOJodaTime(String dateTime) {
DateTimeFormatter formatter = DateTimeFormat.forPattern("yyyy-MM-dd'T'HH:mm:ss'Z'");
DateTime dt = formatter.parseDateTime(dateTime);
return dt.toString("h:mm aa", Locale.ENGLISH);
}
}
It gives output as:
7:31 AM
If you don't want to use any third party library & still want to extract only time from date, you can use Java's LocalTime.
If you are using Java 8 or newer, you should not use java.util.Date (deprecated) or Joda Time (replaced by the new DATE API of Java 8 with java.time package) :
public static void main(String[] args) {
String date = "2020-04-09T07:31:16Z";
String formatedDate = ZonedDateTime.parse(date).format(DateTimeFormatter.ofLocalizedTime(FormatStyle.SHORT));
System.out.println(formatedDate); //print "7:31 AM"
}
}
First, don’t handle date and time as strings in your program. Handle them as proper date-time objects. So but for all but the simplest throw-away programs you should not want a method that converts from a string in UTC to a string in London time in a different format.
So when you accept string input, parse into a DateTime object:
String stringInput = "2020-04-09T07:31:16Z";
DateTime dt = DateTime.parse(stringInput);
System.out.println("Date-time is: " + dt);
Output so far is:
Date-time is: 2020-04-09T07:31:16.000Z
I am exploiting the fact that your string is in ISO 8601 format, the default for Joda-Time, so we need no explicit formatter for parsing it.
Not until you need to give string output, convert your date and time to the desired zone and format into the desired string:
DateTimeZone zone = DateTimeZone.forID("Europe/London");
DateTime outputDateTime = dt.withZone(zone);
String output = outputDateTime.toString("h:mm aa");
System.out.println("Output is: " + output);
Output is: 8:31 AM
What went wrong in your code
Z in single quotes in your format pattern string is wrong. Z in your input string is an offset of 0 from UTC and needs to be parsed as an offset, or you are getting an incorrect result. Never put those quotes around Z.
withZoneRetainFields() is the wrong method to use for converting between time zones. The method name means that the date and hour of day are kept the same and only the time zone changed, which typically leads to a different point in time.
What happened was that your string was parsed into 2020-04-09T07:31:16.000+01:00, which is the same point in time as 06:31:16 UTC, so wrong. You next substituted the time zone to UTC keeping the time of day of 07:31:16. This time was then formatted and printed.
Do consider java.time
As Fabien said, Joda-Time has later been replaced with java.time, the modern Java date and time API. The Joda-Time home page says:
Note that Joda-Time is considered to be a largely “finished” project.
No major enhancements are planned. If using Java SE 8, please migrate
to java.time (JSR-310).
Links
Wikipedia article: ISO 8601
Joda-Time home
How can I convert current time to this format:
"2017-04-25T17:12:42+01:00"
The closest I could get is this:
"2017-05-16T19:58:21+0100"
by using this format:
SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZZZ").format(new Date())
Thanks
You should use the modern Java 8 java.time package, more specifically DateTimeFormatter, the ISO_OFFSET_DATE_TIME.
From the docs:
public static final DateTimeFormatter ISO_OFFSET_DATE_TIME
The ISO date-time formatter that formats or parses a date-time with an
offset, such as '2011-12-03T10:15:30+01:00'.
Working code:
import java.time.ZonedDateTime;
import java.time.format.DateTimeFormatter;
public class Main
{
public static void main(String[] args)
{
ZonedDateTime date = ZonedDateTime.now();
String text = date.format(DateTimeFormatter.ISO_OFFSET_DATE_TIME);
System.out.println(text);
}
}
Result:
> run Main
2017-05-19T13:03:16.167+02:00
You can use "yyyy-MM-dd'T'HH:mm:ssXXX" as pattern instead of yyyy-MM-dd'T'HH:mm:ssZZZ, see the examples here
ZZZ is RFC 822 time zone like this: -0800;
XXX is ISO 8601 time zone like this: -08:00;
Use XXX if want to second foramt and don't want use ISO_OFFSET_DATE_TIME, for example, want to display “01/15/2000T14:44:59-08:00”:
DateTimeFormatter.ofPattern("MM/dd/yyyy'T'HH:mm:ssXXX").format(...);
For this specific format you can simply use java.time.OffsetDateTime, available since Java-8 :
OffsetDateTime.now().toString();
SimpleDateFormat will do a thing for you
SimpleDateFormat formatter= new SimpleDateFormat("yyyy-MM-dd");
formatter.format(date);
I'm a beginner in java programmeing.
I want to parse a complex date format : YYYY-MM-DDthh:mm:ssTZD, for example 2014-09-24T21:32:39-04:00
I tried this :
String str_date="2014-09-24T21:32:39-04:00";
DateFormat formatter = new SimpleDateFormat("YYYY-MM-DDthh:mm:ss");
Date date = (Date)formatter.parse(str_date);
But for the timezone part (-04:00), i have no idea what to put (after the :ss)
Any help ?
If you are using Java < 7 then you'd need to remove ':' from your input and parse it:
Here is an example:
public static void main(String[] args) throws ParseException {
String str_date="2014-09-24T21:32:39-04:00";
str_date = str_date.replaceAll(":(\\d\\d)$", "$1");
System.out.println("Input modified according to Java 6: "+str_date);
DateFormat formatter = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZ");
Date date = (Date)formatter.parse(str_date);
System.out.println(date);
}
prints:
Input modified according to Java 6: 2014-09-24T21:32:39-0400
Wed Sep 24 21:32:39 EDT 2014
Java7
SimpleDateFormat documentation lists the timezone as z, Z, and X and for you it looks like you want XXX.
Java6
Java7 added X specifier, but 6 still has the Z and z. However, you will have to modify the string first so that it either has no colon in the timezone or has GMT before the -:
String str_date="2014-09-24T21:32:39-04:00";
int index = str_date.lastIndexOf( '-' );
str_date = str_date.substring( 0, index ) + "GMT" + str_date.substring( index+1 );
Then you can use the format specifier z
ISO 8601
Your string complies with the ISO 8601 standard. That standard is used as the default in parsing and generating strings by two excellent date-time libraries:
Joda-Time
java.time package (bundled with Java 8, inspired by Joda-Time, defined by JSR 310)
Merely pass your string to the constructor or factory method. A built-in formatter is automatically used to parse your string.
Unlike java.util.Date, in these two libraries a date-time object knows its own assigned time zone. The offset from UTC specified at the end of your string is used to calculate a number of milliseconds (or nanoseconds in java.time) since the Unix epoch of the beginning of 1970 in UTC time zone. After that calculation, the resulting date-time is assigned a time zone of your choice. In this example I arbitrarily assign a India time zone. For clarity this example creates a second date-time object in UTC.
Joda-Time
DateTimeZone timeZoneIndia = DateTimeZone.forID( "Asia/Kolkata" );
DateTime dateTimeIndia = new DateTime( "2014-09-24T21:32:39-04:00" , timeZoneIndia );
DateTime dateTimeUtc = dateTimeIndia.withZone( DateTimeZone.UTC );
I'm getting these times from Facebook events. E.g: start_time and it's a string like this:
2013-12-21T18:30:00+0100
Now I just want the time, like:
18.30
I tried to do it with this:
SimpleDateFormat formatter = new SimpleDateFormat(" EEEE, dd MMMM yyyy", java.util.Locale.getDefault());
Date formatted = null;
try {
formatted = formatter.parse(p.getStart_time());
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
String formattedString = formatted.toString();
txtStart_time.setText(""+formattedString);
p.getStart_time() is a String that gives me the date like I said before.
If I do this method, I get an error:
Unparseable date.
Does anybody know a work around?
You need two formats: one to parse the date and one to format it
String startTime = "2013-12-21T18:30:00+0100";
SimpleDateFormat incomingFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZ");
Date date = incomingFormat.parse(startTime);
SimpleDateFormat outgoingFormat = new SimpleDateFormat(" EEEE, dd MMMM yyyy", java.util.Locale.getDefault());
System.out.println(outgoingFormat.format(date));
prints
Saturday, 21 December 2013
I'm getting these times from Facebook events. E.g: start_time and it's
a string like this:
2013-12-21T18:30:00+0100
Now I just want the time, like:
18.30
Solution using java.time, the modern date-time API:
OffsetDateTime.parse(
"2013-12-21T18:30:00+0100",
DateTimeFormatter.ofPattern("uuuu-MM-dd'T'HH:mm:ssZ")
).toLocalTime()
Description: Your date-time string has a timezone offset of +01:00 hours. java.time API provides you with OffsetDateTime to contain the information of date-time units along with the timezone offset. Using the applicable DateTimeFormatter, parse the string into an OffsetDateTime and then get the LocalTime part of this date-time using OffsetDateTime#toLocalTime.
Demo using java.time API:
import java.time.OffsetDateTime;
import java.time.format.DateTimeFormatter;
class Main {
public static void main(String[] args) {
System.out.println(OffsetDateTime.parse(
"2013-12-21T18:30:00+0100",
DateTimeFormatter.ofPattern("uuuu-MM-dd'T'HH:mm:ssZ")
).toLocalTime());
}
}
Output:
18:30
ONLINE DEMO
Note: You can use y instead of u here but I prefer u to y.
Learn more about the modern Date-Time API from Trail: Date Time.
A note about the legacy API:
The question and the accepted answer use java.util.Date and SimpleDateFormat which was the correct thing to do in 2013. In Mar 2014, the java.util date-time API and their formatting API, SimpleDateFormat were supplanted by the modern date-time API. Since then, it is highly recommended to stop using the legacy date-time API.
Use something like yyyy-MM-dd'T'HH:mm:ssZ as parsing format instead of EEEE, dd MMMM yyyy.
Substring
If all you want is literally the time component lifted from that string, call the substring method on the String class…
// © 2013 Basil Bourque. This source code may be used freely forever by anyone taking full responsibility for doing so.
// import org.joda.time.*;
// import org.joda.time.format.*;
String dateTimeStringFromFacebook = "2013-12-21T18:30:00+0100";
// Extract a substring.
String timeSubstring = dateTimeStringFromFacebook.substring( 11, 19 );
DateTime Object
If you want the time converted to a particular time zone, convert the string to a date-time object. Use a formatter to express just the time component.
Here is some example code using the Joda-Time 2.3 library. Avoid the notoriously bad java.util.Date/Calendar classes. Use either Joda-Time or the new java.time.* JSR 310 classes bundled with Java 8.
// From String to DateTime object.
DateTime dateTime = new DateTime( dateTimeStringFromFacebook, DateTimeZone.UTC );
// From DateTime object to String
// Extract just the hours, minutes, seconds.
DateTimeFormatter formatter = DateTimeFormat.forPattern("HH:mm:ss");
String timeFragment_Paris = formatter.withZone( DateTimeZone.forID( "Europe/Paris" ) ).print( dateTime );
String timeFragment_Kolkata = formatter.withZone( DateTimeZone.forID( "Asia/Kolkata" ) ).print( dateTime ); // Formerly known as Calcutta, India.
Dump to console…
System.out.println( "dateTimeStringFromFacebook: " + dateTimeStringFromFacebook );
System.out.println( "timeSubstring: " + timeSubstring );
System.out.println( "dateTime: " + dateTime );
System.out.println( "timeFragment_Paris: " + timeFragment_Paris );
System.out.println( "timeFragment_Kolkata: " + timeFragment_Kolkata + " (Note the 00:30 difference due to +05:30 offset)");
When run…
dateTimeStringFromFacebook: 2013-12-21T18:30:00+0100
timeSubstring: 18:30:00
dateTime: 2013-12-21T17:30:00.000Z
timeFragment_Paris: 18:30:00
timeFragment_Kolkata: 23:00:00 (Note the 00:30 difference due to +05:30 offset)
Think Time Zone
Your question fails to address the question of time zone. Make a habit of always thinking about time zone whenever working with date-time values. If you mean the same time zone, say so explicitly. If you mean the default time zone of the Java environment, say so. If you mean UTC… well, you get the idea.
I have a line of C# code that I am trying to replicate in Java. The code looks as follows.
n.InnerText = DateTime.Parse(n.InnerText).ToUniversalTime().ToString("yyyy-MM-ddTHH:mm:ssZ");
The intent is to replace the DateTime already in the xml context with one representing universal time.
I have attempted to use
node.setTextContent = Date.parse(node.getTextContent())
but I am unable to continue due to the Date.parse() being deprecated. I read through the note in Eclipse and tried DateFormat as suggested but DateFormat does not have a parse method.
Can someone suggest a solution to my problem that does not use any third party libraries?
You can use:
DateFormat format = new SimpleDateFormat("yyyy-MM-ddTHH:mm:ssZ");
Date date = format.parse(myString);
Be sure to check the locale if it's appropriate, and to check that the fields are the same (as I don't know what you intended to parse, I just copied them).
(For example "T" does not exist.)
Date d = new Date();
(java.text) SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'Z'");
sdf.setTimeZone(TimeZone.getTimeZone("Etc/UTC"));
String formatted = sdf.format(d);
The other answers are outdated, using old legacy classes.
java.time
The java.time framework built into Java 8 and later supplants the troublesome old date-time classes.
ISO 8601
Your input string happens to be in standard ISO 8601 format.
The java.time classes use ISO 8601 formats by default when parsing/generating String representations of date-time values. So no need to specify a formatting pattern.
An Instant represents a moment on the timeline in UTC with a resolution of nanoseconds.
Instant instant = Instant.parse( "2016-04-29T22:04:07Z" );
You mean like this one:
import java.util.Date;
import java.text.SimpleDateFormat;
public class DateFormat{
public static void main(String[] args){
Date date=new Date();
SimpleDateFormat sdf=new SimpleDateFormat("yyyy-MM-dd");
String yourDate=sdf.format(date);
System.out.println(yourDate);
}
}
package com.pnac;
import org.joda.time.DateTime;
public class TestDateTime {
public static void main(String[] args) {
DateTime dateTime = new DateTime();
System.out.println("########## " + dateTime.minusHours(10).toString("yyyy-MM-dd HH:mm:ss"));
}
}