Related
How do you read and display data from .txt files?
BufferedReader in = new BufferedReader(new FileReader("<Filename>"));
Then, you can use in.readLine(); to read a single line at a time. To read until the end, write a while loop as such:
String line;
while((line = in.readLine()) != null)
{
System.out.println(line);
}
in.close();
If your file is strictly text, I prefer to use the java.util.Scanner class.
You can create a Scanner out of a file by:
Scanner fileIn = new Scanner(new File(thePathToYourFile));
Then, you can read text from the file using the methods:
fileIn.nextLine(); // Reads one line from the file
fileIn.next(); // Reads one word from the file
And, you can check if there is any more text left with:
fileIn.hasNext(); // Returns true if there is another word in the file
fileIn.hasNextLine(); // Returns true if there is another line to read from the file
Once you have read the text, and saved it into a String, you can print the string to the command line with:
System.out.print(aString);
System.out.println(aString);
The posted link contains the full specification for the Scanner class. It will be helpful to assist you with what ever else you may want to do.
In general:
Create a FileInputStream for the file.
Create an InputStreamReader wrapping the input stream, specifying the correct encoding
Optionally create a BufferedReader around the InputStreamReader, which makes it simpler to read a line at a time.
Read until there's no more data (e.g. readLine returns null)
Display data as you go or buffer it up for later.
If you need more help than that, please be more specific in your question.
I love this piece of code, use it to load a file into one String:
File file = new File("/my/location");
String contents = new Scanner(file).useDelimiter("\\Z").next();
Below is the code that you may try to read a file and display in java using scanner class. Code will read the file name from user and print the data(Notepad VIM files).
import java.io.*;
import java.util.Scanner;
import java.io.*;
public class TestRead
{
public static void main(String[] input)
{
String fname;
Scanner scan = new Scanner(System.in);
/* enter filename with extension to open and read its content */
System.out.print("Enter File Name to Open (with extension like file.txt) : ");
fname = scan.nextLine();
/* this will reference only one line at a time */
String line = null;
try
{
/* FileReader reads text files in the default encoding */
FileReader fileReader = new FileReader(fname);
/* always wrap the FileReader in BufferedReader */
BufferedReader bufferedReader = new BufferedReader(fileReader);
while((line = bufferedReader.readLine()) != null)
{
System.out.println(line);
}
/* always close the file after use */
bufferedReader.close();
}
catch(IOException ex)
{
System.out.println("Error reading file named '" + fname + "'");
}
}
}
If you want to take some shortcuts you can use Apache Commons IO:
import org.apache.commons.io.FileUtils;
String data = FileUtils.readFileToString(new File("..."), "UTF-8");
System.out.println(data);
:-)
public class PassdataintoFile {
public static void main(String[] args) throws IOException {
try {
PrintWriter pw = new PrintWriter("C:/new/hello.txt", "UTF-8");
PrintWriter pw1 = new PrintWriter("C:/new/hello.txt");
pw1.println("Hi chinni");
pw1.print("your succesfully entered text into file");
pw1.close();
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (UnsupportedEncodingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
BufferedReader br = new BufferedReader(new FileReader("C:/new/hello.txt"));
String line;
while((line = br.readLine())!= null)
{
System.out.println(line);
}
br.close();
}
}
In Java 8, you can read a whole file, simply with:
public String read(String file) throws IOException {
return new String(Files.readAllBytes(Paths.get(file)));
}
or if its a Resource:
public String read(String file) throws IOException {
URL url = Resources.getResource(file);
return Resources.toString(url, Charsets.UTF_8);
}
You most likely will want to use the FileInputStream class:
int character;
StringBuffer buffer = new StringBuffer("");
FileInputStream inputStream = new FileInputStream(new File("/home/jessy/file.txt"));
while( (character = inputStream.read()) != -1)
buffer.append((char) character);
inputStream.close();
System.out.println(buffer);
You will also want to catch some of the exceptions thrown by the read() method and FileInputStream constructor, but those are implementation details specific to your project.
Using a Buffer reader I parse throughout a file. If Oranges: pattern is found, I want to replace it with ApplesAndOranges.
try (BufferedReader br = new BufferedReader(new FileReader(resourcesFilePath))) {
String line;
while ((line = br.readLine()) != null) {
if (line.startsWith("Oranges:")){
int startIndex = line.indexOf(":");
line = line.substring(startIndex + 2);
String updatedLine = "ApplesAndOranges";
updateLine(line, updatedLine);
I call a method updateLine and I pass my original line as well as the updated line value.
private static void updateLine(String toUpdate, String updated) throws IOException {
BufferedReader file = new BufferedReader(new FileReader(resourcesFilePath));
PrintWriter writer = new PrintWriter(new File(resourcesFilePath+".out"), "UTF-8");
String line;
while ((line = file.readLine()) != null)
{
line = line.replace(toUpdate, updated);
writer.println(line);
}
file.close();
if (writer.checkError())
throw new IOException("Can't Write To File"+ resourcesFilePath);
writer.close();
}
To get the file to update I have to save it with a different name (resourcesFilePath+".out"). If I use the original file name the saved version become blank.
So here is my question, how can I replace a line with any value in the original file without losing any data.
For this you need to use the regular expressions (RegExp) like this:
str = str.replaceAll("^Orange:(.*)", "OrangeAndApples:$1");
It's an example and maybe it's not excactly what you want, but here, in the first parameter, the expression in parentesis is called a capturing group. The expression found will be replaced by the second parameter and the $1 will be replaced by the value of the capturing group. In our example Orange:Hello at the beggining of a line will be replaced by OrangeAndApples:Hello.
In your code, it seams you create one file per line ... maybe inlining the sub-method would be better.
try (
BufferedReader br = new BufferedReader(new FileReader(resourcesFilePath));
BufferedWriter writer = Files.newBufferedWriter(outputFilePath, charset);
) {
String line;
while ((line = br.readLine()) != null) {
String repl = line.replaceAll("Orange:(.*)","OrangeAndApples:$1");
writer.writeln(repl);
}
}
The easiest way to write over everything in your original final would be to read in everything - changing whatever you want to change and closing the stream. Afterwards open up the file again, then overwrite the file and all its lines with the data you want.
You can use RandomAccessFile to write to the file, and nio.Files to read the bytes from it. In this case, I put it as a string.
You can also read the file with RandomAccessFile, but it is easier to do it this way, in my opinion.
import java.io.RandomAccessFile;
import java.io.File;
import java.io.IOException;
import java.nio.file.*;
public void replace(File file){
try {
RandomAccessFile raf = new RandomAccessFile(file, "rw");
Path p = Paths.get(file.toURI());
String line = new String(Files.readAllBytes(p));
if(line.startsWith("Oranges:")){
line.replaceAll("Oranges:", "ApplesandOranges:");
raf.writeUTF(line);
}
raf.close();
} catch (IOException e) {
e.printStackTrace();
}
}
It seems there are different ways to read and write data of files in Java.
I want to read ASCII data from a file. What are the possible ways and their differences?
My favorite way to read a small file is to use a BufferedReader and a StringBuilder. It is very simple and to the point (though not particularly effective, but good enough for most cases):
BufferedReader br = new BufferedReader(new FileReader("file.txt"));
try {
StringBuilder sb = new StringBuilder();
String line = br.readLine();
while (line != null) {
sb.append(line);
sb.append(System.lineSeparator());
line = br.readLine();
}
String everything = sb.toString();
} finally {
br.close();
}
Some has pointed out that after Java 7 you should use try-with-resources (i.e. auto close) features:
try(BufferedReader br = new BufferedReader(new FileReader("file.txt"))) {
StringBuilder sb = new StringBuilder();
String line = br.readLine();
while (line != null) {
sb.append(line);
sb.append(System.lineSeparator());
line = br.readLine();
}
String everything = sb.toString();
}
When I read strings like this, I usually want to do some string handling per line anyways, so then I go for this implementation.
Though if I want to actually just read a file into a String, I always use Apache Commons IO with the class IOUtils.toString() method. You can have a look at the source here:
http://www.docjar.com/html/api/org/apache/commons/io/IOUtils.java.html
FileInputStream inputStream = new FileInputStream("foo.txt");
try {
String everything = IOUtils.toString(inputStream);
} finally {
inputStream.close();
}
And even simpler with Java 7:
try(FileInputStream inputStream = new FileInputStream("foo.txt")) {
String everything = IOUtils.toString(inputStream);
// do something with everything string
}
ASCII is a TEXT file so you would use Readers for reading. Java also supports reading from a binary file using InputStreams. If the files being read are huge then you would want to use a BufferedReader on top of a FileReader to improve read performance.
Go through this article on how to use a Reader
I'd also recommend you download and read this wonderful (yet free) book called Thinking In Java
In Java 7:
new String(Files.readAllBytes(...))
(docs)
or
Files.readAllLines(...)
(docs)
In Java 8:
Files.lines(..).forEach(...)
(docs)
The easiest way is to use the Scanner class in Java and the FileReader object. Simple example:
Scanner in = new Scanner(new FileReader("filename.txt"));
Scanner has several methods for reading in strings, numbers, etc... You can look for more information on this on the Java documentation page.
For example reading the whole content into a String:
StringBuilder sb = new StringBuilder();
while(in.hasNext()) {
sb.append(in.next());
}
in.close();
outString = sb.toString();
Also if you need a specific encoding you can use this instead of FileReader:
new InputStreamReader(new FileInputStream(fileUtf8), StandardCharsets.UTF_8)
Here is a simple solution:
String content = new String(Files.readAllBytes(Paths.get("sample.txt")));
Or to read as list:
List<String> content = Files.readAllLines(Paths.get("sample.txt"))
Here's another way to do it without using external libraries:
import java.io.File;
import java.io.FileReader;
import java.io.IOException;
public String readFile(String filename)
{
String content = null;
File file = new File(filename); // For example, foo.txt
FileReader reader = null;
try {
reader = new FileReader(file);
char[] chars = new char[(int) file.length()];
reader.read(chars);
content = new String(chars);
reader.close();
} catch (IOException e) {
e.printStackTrace();
} finally {
if(reader != null){
reader.close();
}
}
return content;
}
I had to benchmark the different ways. I shall comment on my findings but, in short, the fastest way is to use a plain old BufferedInputStream over a FileInputStream. If many files must be read then three threads will reduce the total execution time to roughly half, but adding more threads will progressively degrade performance until making it take three times longer to complete with twenty threads than with just one thread.
The assumption is that you must read a file and do something meaningful with its contents. In the examples here is reading lines from a log and count the ones which contain values that exceed a certain threshold. So I am assuming that the one-liner Java 8 Files.lines(Paths.get("/path/to/file.txt")).map(line -> line.split(";")) is not an option.
I tested on Java 1.8, Windows 7 and both SSD and HDD drives.
I wrote six different implementations:
rawParse: Use BufferedInputStream over a FileInputStream and then cut lines reading byte by byte. This outperformed any other single-thread approach, but it may be very inconvenient for non-ASCII files.
lineReaderParse: Use a BufferedReader over a FileReader, read line by line, split lines by calling String.split(). This is approximatedly 20% slower that rawParse.
lineReaderParseParallel: This is the same as lineReaderParse, but it uses several threads. This is the fastest option overall in all cases.
nioFilesParse: Use java.nio.files.Files.lines()
nioAsyncParse: Use an AsynchronousFileChannel with a completion handler and a thread pool.
nioMemoryMappedParse: Use a memory-mapped file. This is really a bad idea yielding execution times at least three times longer than any other implementation.
These are the average times for reading 204 files of 4 MB each on an quad-core i7 and SSD drive. The files are generated on the fly to avoid disk caching.
rawParse 11.10 sec
lineReaderParse 13.86 sec
lineReaderParseParallel 6.00 sec
nioFilesParse 13.52 sec
nioAsyncParse 16.06 sec
nioMemoryMappedParse 37.68 sec
I found a difference smaller than I expected between running on an SSD or an HDD drive being the SSD approximately 15% faster. This may be because the files are generated on an unfragmented HDD and they are read sequentially, therefore the spinning drive can perform nearly as an SSD.
I was surprised by the low performance of the nioAsyncParse implementation. Either I have implemented something in the wrong way or the multi-thread implementation using NIO and a completion handler performs the same (or even worse) than a single-thread implementation with the java.io API. Moreover the asynchronous parse with a CompletionHandler is much longer in lines of code and tricky to implement correctly than a straight implementation on old streams.
Now the six implementations followed by a class containing them all plus a parametrizable main() method that allows to play with the number of files, file size and concurrency degree. Note that the size of the files varies plus minus 20%. This is to avoid any effect due to all the files being of exactly the same size.
rawParse
public void rawParse(final String targetDir, final int numberOfFiles) throws IOException, ParseException {
overrunCount = 0;
final int dl = (int) ';';
StringBuffer lineBuffer = new StringBuffer(1024);
for (int f=0; f<numberOfFiles; f++) {
File fl = new File(targetDir+filenamePreffix+String.valueOf(f)+".txt");
FileInputStream fin = new FileInputStream(fl);
BufferedInputStream bin = new BufferedInputStream(fin);
int character;
while((character=bin.read())!=-1) {
if (character==dl) {
// Here is where something is done with each line
doSomethingWithRawLine(lineBuffer.toString());
lineBuffer.setLength(0);
}
else {
lineBuffer.append((char) character);
}
}
bin.close();
fin.close();
}
}
public final void doSomethingWithRawLine(String line) throws ParseException {
// What to do for each line
int fieldNumber = 0;
final int len = line.length();
StringBuffer fieldBuffer = new StringBuffer(256);
for (int charPos=0; charPos<len; charPos++) {
char c = line.charAt(charPos);
if (c==DL0) {
String fieldValue = fieldBuffer.toString();
if (fieldValue.length()>0) {
switch (fieldNumber) {
case 0:
Date dt = fmt.parse(fieldValue);
fieldNumber++;
break;
case 1:
double d = Double.parseDouble(fieldValue);
fieldNumber++;
break;
case 2:
int t = Integer.parseInt(fieldValue);
fieldNumber++;
break;
case 3:
if (fieldValue.equals("overrun"))
overrunCount++;
break;
}
}
fieldBuffer.setLength(0);
}
else {
fieldBuffer.append(c);
}
}
}
lineReaderParse
public void lineReaderParse(final String targetDir, final int numberOfFiles) throws IOException, ParseException {
String line;
for (int f=0; f<numberOfFiles; f++) {
File fl = new File(targetDir+filenamePreffix+String.valueOf(f)+".txt");
FileReader frd = new FileReader(fl);
BufferedReader brd = new BufferedReader(frd);
while ((line=brd.readLine())!=null)
doSomethingWithLine(line);
brd.close();
frd.close();
}
}
public final void doSomethingWithLine(String line) throws ParseException {
// Example of what to do for each line
String[] fields = line.split(";");
Date dt = fmt.parse(fields[0]);
double d = Double.parseDouble(fields[1]);
int t = Integer.parseInt(fields[2]);
if (fields[3].equals("overrun"))
overrunCount++;
}
lineReaderParseParallel
public void lineReaderParseParallel(final String targetDir, final int numberOfFiles, final int degreeOfParalelism) throws IOException, ParseException, InterruptedException {
Thread[] pool = new Thread[degreeOfParalelism];
int batchSize = numberOfFiles / degreeOfParalelism;
for (int b=0; b<degreeOfParalelism; b++) {
pool[b] = new LineReaderParseThread(targetDir, b*batchSize, b*batchSize+b*batchSize);
pool[b].start();
}
for (int b=0; b<degreeOfParalelism; b++)
pool[b].join();
}
class LineReaderParseThread extends Thread {
private String targetDir;
private int fileFrom;
private int fileTo;
private DateFormat fmt = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
private int overrunCounter = 0;
public LineReaderParseThread(String targetDir, int fileFrom, int fileTo) {
this.targetDir = targetDir;
this.fileFrom = fileFrom;
this.fileTo = fileTo;
}
private void doSomethingWithTheLine(String line) throws ParseException {
String[] fields = line.split(DL);
Date dt = fmt.parse(fields[0]);
double d = Double.parseDouble(fields[1]);
int t = Integer.parseInt(fields[2]);
if (fields[3].equals("overrun"))
overrunCounter++;
}
#Override
public void run() {
String line;
for (int f=fileFrom; f<fileTo; f++) {
File fl = new File(targetDir+filenamePreffix+String.valueOf(f)+".txt");
try {
FileReader frd = new FileReader(fl);
BufferedReader brd = new BufferedReader(frd);
while ((line=brd.readLine())!=null) {
doSomethingWithTheLine(line);
}
brd.close();
frd.close();
} catch (IOException | ParseException ioe) { }
}
}
}
nioFilesParse
public void nioFilesParse(final String targetDir, final int numberOfFiles) throws IOException, ParseException {
for (int f=0; f<numberOfFiles; f++) {
Path ph = Paths.get(targetDir+filenamePreffix+String.valueOf(f)+".txt");
Consumer<String> action = new LineConsumer();
Stream<String> lines = Files.lines(ph);
lines.forEach(action);
lines.close();
}
}
class LineConsumer implements Consumer<String> {
#Override
public void accept(String line) {
// What to do for each line
String[] fields = line.split(DL);
if (fields.length>1) {
try {
Date dt = fmt.parse(fields[0]);
}
catch (ParseException e) {
}
double d = Double.parseDouble(fields[1]);
int t = Integer.parseInt(fields[2]);
if (fields[3].equals("overrun"))
overrunCount++;
}
}
}
nioAsyncParse
public void nioAsyncParse(final String targetDir, final int numberOfFiles, final int numberOfThreads, final int bufferSize) throws IOException, ParseException, InterruptedException {
ScheduledThreadPoolExecutor pool = new ScheduledThreadPoolExecutor(numberOfThreads);
ConcurrentLinkedQueue<ByteBuffer> byteBuffers = new ConcurrentLinkedQueue<ByteBuffer>();
for (int b=0; b<numberOfThreads; b++)
byteBuffers.add(ByteBuffer.allocate(bufferSize));
for (int f=0; f<numberOfFiles; f++) {
consumerThreads.acquire();
String fileName = targetDir+filenamePreffix+String.valueOf(f)+".txt";
AsynchronousFileChannel channel = AsynchronousFileChannel.open(Paths.get(fileName), EnumSet.of(StandardOpenOption.READ), pool);
BufferConsumer consumer = new BufferConsumer(byteBuffers, fileName, bufferSize);
channel.read(consumer.buffer(), 0l, channel, consumer);
}
consumerThreads.acquire(numberOfThreads);
}
class BufferConsumer implements CompletionHandler<Integer, AsynchronousFileChannel> {
private ConcurrentLinkedQueue<ByteBuffer> buffers;
private ByteBuffer bytes;
private String file;
private StringBuffer chars;
private int limit;
private long position;
private DateFormat frmt = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
public BufferConsumer(ConcurrentLinkedQueue<ByteBuffer> byteBuffers, String fileName, int bufferSize) {
buffers = byteBuffers;
bytes = buffers.poll();
if (bytes==null)
bytes = ByteBuffer.allocate(bufferSize);
file = fileName;
chars = new StringBuffer(bufferSize);
frmt = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
limit = bufferSize;
position = 0l;
}
public ByteBuffer buffer() {
return bytes;
}
#Override
public synchronized void completed(Integer result, AsynchronousFileChannel channel) {
if (result!=-1) {
bytes.flip();
final int len = bytes.limit();
int i = 0;
try {
for (i = 0; i < len; i++) {
byte by = bytes.get();
if (by=='\n') {
// ***
// The code used to process the line goes here
chars.setLength(0);
}
else {
chars.append((char) by);
}
}
}
catch (Exception x) {
System.out.println(
"Caught exception " + x.getClass().getName() + " " + x.getMessage() +
" i=" + String.valueOf(i) + ", limit=" + String.valueOf(len) +
", position="+String.valueOf(position));
}
if (len==limit) {
bytes.clear();
position += len;
channel.read(bytes, position, channel, this);
}
else {
try {
channel.close();
}
catch (IOException e) {
}
consumerThreads.release();
bytes.clear();
buffers.add(bytes);
}
}
else {
try {
channel.close();
}
catch (IOException e) {
}
consumerThreads.release();
bytes.clear();
buffers.add(bytes);
}
}
#Override
public void failed(Throwable e, AsynchronousFileChannel channel) {
}
};
FULL RUNNABLE IMPLEMENTATION OF ALL CASES
https://github.com/sergiomt/javaiobenchmark/blob/master/FileReadBenchmark.java
Here are the three working and tested methods:
Using BufferedReader
package io;
import java.io.*;
public class ReadFromFile2 {
public static void main(String[] args)throws Exception {
File file = new File("C:\\Users\\pankaj\\Desktop\\test.java");
BufferedReader br = new BufferedReader(new FileReader(file));
String st;
while((st=br.readLine()) != null){
System.out.println(st);
}
}
}
Using Scanner
package io;
import java.io.File;
import java.util.Scanner;
public class ReadFromFileUsingScanner {
public static void main(String[] args) throws Exception {
File file = new File("C:\\Users\\pankaj\\Desktop\\test.java");
Scanner sc = new Scanner(file);
while(sc.hasNextLine()){
System.out.println(sc.nextLine());
}
}
}
Using FileReader
package io;
import java.io.*;
public class ReadingFromFile {
public static void main(String[] args) throws Exception {
FileReader fr = new FileReader("C:\\Users\\pankaj\\Desktop\\test.java");
int i;
while ((i=fr.read()) != -1){
System.out.print((char) i);
}
}
}
Read the entire file without a loop using the Scanner class
package io;
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class ReadingEntireFileWithoutLoop {
public static void main(String[] args) throws FileNotFoundException {
File file = new File("C:\\Users\\pankaj\\Desktop\\test.java");
Scanner sc = new Scanner(file);
sc.useDelimiter("\\Z");
System.out.println(sc.next());
}
}
The methods within org.apache.commons.io.FileUtils may also be very handy, e.g.:
/**
* Reads the contents of a file line by line to a List
* of Strings using the default encoding for the VM.
*/
static List readLines(File file)
I documented 15 ways to read a file in Java and then tested them for speed with various file sizes - from 1 KB to 1 GB and here are the top three ways to do this:
java.nio.file.Files.readAllBytes()
Tested to work in Java 7, 8, and 9.
import java.io.File;
import java.io.IOException;
import java.nio.file.Files;
public class ReadFile_Files_ReadAllBytes {
public static void main(String [] pArgs) throws IOException {
String fileName = "c:\\temp\\sample-10KB.txt";
File file = new File(fileName);
byte [] fileBytes = Files.readAllBytes(file.toPath());
char singleChar;
for(byte b : fileBytes) {
singleChar = (char) b;
System.out.print(singleChar);
}
}
}
java.io.BufferedReader.readLine()
Tested to work in Java 7, 8, 9.
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
public class ReadFile_BufferedReader_ReadLine {
public static void main(String [] args) throws IOException {
String fileName = "c:\\temp\\sample-10KB.txt";
FileReader fileReader = new FileReader(fileName);
try (BufferedReader bufferedReader = new BufferedReader(fileReader)) {
String line;
while((line = bufferedReader.readLine()) != null) {
System.out.println(line);
}
}
}
}
java.nio.file.Files.lines()
This was tested to work in Java 8 and 9 but won't work in Java 7 because of the lambda expression requirement.
import java.io.File;
import java.io.IOException;
import java.nio.file.Files;
import java.util.stream.Stream;
public class ReadFile_Files_Lines {
public static void main(String[] pArgs) throws IOException {
String fileName = "c:\\temp\\sample-10KB.txt";
File file = new File(fileName);
try (Stream linesStream = Files.lines(file.toPath())) {
linesStream.forEach(line -> {
System.out.println(line);
});
}
}
}
What do you want to do with the text? Is the file small enough to fit into memory? I would try to find the simplest way to handle the file for your needs. The FileUtils library is very handle for this.
for(String line: FileUtils.readLines("my-text-file"))
System.out.println(line);
Below is a one-liner of doing it in the Java 8 way. Assuming text.txt file is in the root of the project directory of the Eclipse.
Files.lines(Paths.get("text.txt")).collect(Collectors.toList());
The most intuitive method is introduced in Java 11 Files.readString
import java.io.*;
import java.nio.file.Files;
import java.nio.file.Paths;
public class App {
public static void main(String args[]) throws IOException {
String content = Files.readString(Paths.get("D:\\sandbox\\mvn\\my-app\\my-app.iml"));
System.out.print(content);
}
}
PHP has this luxury for decades! ☺
The buffered stream classes are much more performant in practice, so much so that the NIO.2 API includes methods that specifically return these stream classes, in part to encourage you always to use buffered streams in your application.
Here is an example:
Path path = Paths.get("/myfolder/myfile.ext");
try (BufferedReader reader = Files.newBufferedReader(path)) {
// Read from the stream
String currentLine = null;
while ((currentLine = reader.readLine()) != null)
//do your code here
} catch (IOException e) {
// Handle file I/O exception...
}
You can replace this code
BufferedReader reader = Files.newBufferedReader(path);
with
BufferedReader br = new BufferedReader(new FileReader("/myfolder/myfile.ext"));
I recommend this article to learn the main uses of Java NIO and IO.
Using BufferedReader:
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
BufferedReader br;
try {
br = new BufferedReader(new FileReader("/fileToRead.txt"));
try {
String x;
while ( (x = br.readLine()) != null ) {
// Printing out each line in the file
System.out.println(x);
}
}
catch (IOException e) {
e.printStackTrace();
}
}
catch (FileNotFoundException e) {
System.out.println(e);
e.printStackTrace();
}
This is basically the exact same as Jesus Ramos' answer, except with File instead of FileReader plus iteration to step through the contents of the file.
Scanner in = new Scanner(new File("filename.txt"));
while (in.hasNext()) { // Iterates each line in the file
String line = in.nextLine();
// Do something with line
}
in.close(); // Don't forget to close resource leaks
... throws FileNotFoundException
Probably not as fast as with buffered I/O, but quite terse:
String content;
try (Scanner scanner = new Scanner(textFile).useDelimiter("\\Z")) {
content = scanner.next();
}
The \Z pattern tells the Scanner that the delimiter is EOF.
The most simple way to read data from a file in Java is making use of the File class to read the file and the Scanner class to read the content of the file.
public static void main(String args[])throws Exception
{
File f = new File("input.txt");
takeInputIn2DArray(f);
}
public static void takeInputIn2DArray(File f) throws Exception
{
Scanner s = new Scanner(f);
int a[][] = new int[20][20];
for(int i=0; i<20; i++)
{
for(int j=0; j<20; j++)
{
a[i][j] = s.nextInt();
}
}
}
PS: Don't forget to import java.util.*; for Scanner to work.
You can use readAllLines and the join method to get whole file content in one line:
String str = String.join("\n",Files.readAllLines(Paths.get("e:\\text.txt")));
It uses UTF-8 encoding by default, which reads ASCII data correctly.
Also you can use readAllBytes:
String str = new String(Files.readAllBytes(Paths.get("e:\\text.txt")), StandardCharsets.UTF_8);
I think readAllBytes is faster and more precise, because it does not replace new line with \n and also new line may be \r\n. It is depending on your needs which one is suitable.
I don't see it mentioned yet in the other answers so far. But if "Best" means speed, then the new Java I/O (NIO) might provide the fastest preformance, but not always the easiest to figure out for someone learning.
http://download.oracle.com/javase/tutorial/essential/io/file.html
Guava provides a one-liner for this:
import com.google.common.base.Charsets;
import com.google.common.io.Files;
String contents = Files.toString(filePath, Charsets.UTF_8);
Cactoos give you a declarative one-liner:
new TextOf(new File("a.txt")).asString();
This might not be the exact answer to the question. It's just another way of reading a file where you do not explicitly specify the path to your file in your Java code and instead, you read it as a command-line argument.
With the following code,
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.IOException;
public class InputReader{
public static void main(String[] args)throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String s="";
while((s=br.readLine())!=null){
System.out.println(s);
}
}
}
just go ahead and run it with:
java InputReader < input.txt
This would read the contents of the input.txt and print it to the your console.
You can also make your System.out.println() to write to a specific file through the command line as follows:
java InputReader < input.txt > output.txt
This would read from input.txt and write to output.txt.
For JSF-based Maven web applications, just use ClassLoader and the Resources folder to read in any file you want:
Put any file you want to read in the Resources folder.
Put the Apache Commons IO dependency into your POM:
<dependency>
<groupId>org.apache.commons</groupId>
<artifactId>commons-io</artifactId>
<version>1.3.2</version>
</dependency>
Use the code below to read it (e.g. below is reading in a .json file):
String metadata = null;
FileInputStream inputStream;
try {
ClassLoader loader = Thread.currentThread().getContextClassLoader();
inputStream = (FileInputStream) loader
.getResourceAsStream("/metadata.json");
metadata = IOUtils.toString(inputStream);
inputStream.close();
}
catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return metadata;
You can do the same for text files, .properties files, XSD schemas, etc.
try {
File f = new File("filename.txt");
Scanner r = new Scanner(f);
while (r.hasNextLine()) {
String data = r.nextLine();
JOptionPane.showMessageDialog(data);
}
r.close();
} catch (FileNotFoundException ex) {
JOptionPane.showMessageDialog("Error occurred");
ex.printStackTrace();
}
Use Java kiss if this is about simplicity of structure:
import static kiss.API.*;
class App {
void run() {
String line;
try (Close in = inOpen("file.dat")) {
while ((line = readLine()) != null) {
println(line);
}
}
}
}
import java.util.stream.Stream;
import java.nio.file.*;
import java.io.*;
class ReadFile {
public static void main(String[] args) {
String filename = "Test.txt";
try(Stream<String> stream = Files.lines(Paths.get(filename))) {
stream.forEach(System.out:: println);
} catch (IOException e) {
e.printStackTrace();
}
}
}
Just use java 8 Stream.
In case you have a large file you can use Apache Commons IO to process the file iteratively without exhausting the available memory.
try (LineIterator it = FileUtils.lineIterator(theFile, "UTF-8")) {
while (it.hasNext()) {
String line = it.nextLine();
// do something with line
}
}
try (Stream<String> stream = Files.lines(Paths.get(String.valueOf(new File("yourFile.txt"))))) {
stream.forEach(System.out::println);
} catch (IOException e) {
e.printStackTrace();
}
new File(<path_name>)
Creates a new File instance by converting the given pathname string into an abstract pathname. If the given string is the empty string, then the result is the empty abstract pathname.
Params:
pathname – A pathname string
Throws:
NullPointerException – If the pathname argument is null
Files.lines returns a stream of String
Stream<String> stream = Files.lines(Paths.get(String.valueOf(new File("yourFile.txt"))))
can throw nullPointerExcetion , FileNotFoundException so, keepint it inside try will take care of Exception in runtime
stream.forEach(System.out::println);
This is used to iterate over the stream and print in console
If you have different use case you can provide your custome function to manipulate the stream of lines
My new favorite approach to simply read a whole text file from a BufferedReader input goes:
String text = input.lines().collect(Collectors.joining(System.lineSeparator())));
This will read the whole file by adding new line (lineSeparator) behind each line. Without the separator it would join all lines together as one.
This appears to have existed since Java 8.
For Android developers ending up here (who use Kotlin):
val myFileUrl = object{}.javaClass.getResource("/vegetables.txt")
val text = myFileUrl.readText() // Not recommended for huge files
println(text)
Other solution:
val myFileUrl = object{}.javaClass.getResource("/vegetables.txt")
val file = File(myFileUrl.toURI())
val lines = file.readLines() // Not recommended for huge files
lines.forEach(::println)
Another good solution which can be used for huge files as well:
val myFileUrl = object{}.javaClass.getResource("/vegetables.txt")
val file = File(myFileUrl.toURI())
file
.bufferedReader()
.lineSequence()
.forEach(::println)
Or:
val myFileUrl = object{}.javaClass.getResource("/vegetables.txt")
val file = File(myFileUrl.toURI())
file.useLines { lines ->
lines.forEach(::println)
}
Notes:
The vegetables.txt file should be in your classpath (for example, in src/main/resources directory)
The above solutions all treat the file encodings as UTF-8 by default. You can specify your desired encoding as the argument for the functions.
The above solutions do not need any further action like closing the files or readers. They are automatically taken care of by the Kotlin standard library.
Closed. This question needs debugging details. It is not currently accepting answers.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Closed 8 years ago.
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I've got this question and I'm not very sure how to answer it - I am able to read the file but unsure on how to display only the words with more than 10 characters
Although other answers are correct , I recommend using scanner class to read files, as it safely allows to detect end of file conditions and has simpler/more useful utility methods:-
Scanner input = new Scanner(new File("file.txt"));
while(input.hasNextLine())
{
String word = input.nextLine();
if(word.length()>10){
System.out.println(word)
}
}
This should work:
private static void readFile(File fin) throws IOException {
FileInputStream fis = new FileInputStream(fin);
BufferedReader br = new BufferedReader(new InputStreamReader(fis));
String line = null;
while ((line = br.readLine()) != null) {
if(line.length()>10) System.out.println(line);
}
br.close();
}
Suposing you have the word in a String variable called word:
if (word.length() > 10)
System.out.println(word);
PS: google before asking!!
Here's some pseudo code to help you get started
create empty list //where we'll add all the >10char words
read file(split per newline) //see the apache commons api
for each line
split on space
for each word in splitted sentence
if wordLength > 10 add to empty list
print each entry in your filled list
Here is your logic.
import java.io.BufferedReader;
import java.io.File;
import java.io.FileInputStream;
import java.io.InputStreamReader;
public class Test {
public static void main(String[] args) throws Exception{
FileInputStream fis = new FileInputStream(new File("your.txt")); // path for the text file
BufferedReader br = new BufferedReader(new InputStreamReader(fis));
String line = null;
while ((line = br.readLine()) != null) {
String st[] = line.split(" ");
for(int i=0; i<st.length; i++){
if(st[i].length()>10) System.out.println(st[i]);
}
}
}
}
It seems there are different ways to read and write data of files in Java.
I want to read ASCII data from a file. What are the possible ways and their differences?
My favorite way to read a small file is to use a BufferedReader and a StringBuilder. It is very simple and to the point (though not particularly effective, but good enough for most cases):
BufferedReader br = new BufferedReader(new FileReader("file.txt"));
try {
StringBuilder sb = new StringBuilder();
String line = br.readLine();
while (line != null) {
sb.append(line);
sb.append(System.lineSeparator());
line = br.readLine();
}
String everything = sb.toString();
} finally {
br.close();
}
Some has pointed out that after Java 7 you should use try-with-resources (i.e. auto close) features:
try(BufferedReader br = new BufferedReader(new FileReader("file.txt"))) {
StringBuilder sb = new StringBuilder();
String line = br.readLine();
while (line != null) {
sb.append(line);
sb.append(System.lineSeparator());
line = br.readLine();
}
String everything = sb.toString();
}
When I read strings like this, I usually want to do some string handling per line anyways, so then I go for this implementation.
Though if I want to actually just read a file into a String, I always use Apache Commons IO with the class IOUtils.toString() method. You can have a look at the source here:
http://www.docjar.com/html/api/org/apache/commons/io/IOUtils.java.html
FileInputStream inputStream = new FileInputStream("foo.txt");
try {
String everything = IOUtils.toString(inputStream);
} finally {
inputStream.close();
}
And even simpler with Java 7:
try(FileInputStream inputStream = new FileInputStream("foo.txt")) {
String everything = IOUtils.toString(inputStream);
// do something with everything string
}
ASCII is a TEXT file so you would use Readers for reading. Java also supports reading from a binary file using InputStreams. If the files being read are huge then you would want to use a BufferedReader on top of a FileReader to improve read performance.
Go through this article on how to use a Reader
I'd also recommend you download and read this wonderful (yet free) book called Thinking In Java
In Java 7:
new String(Files.readAllBytes(...))
(docs)
or
Files.readAllLines(...)
(docs)
In Java 8:
Files.lines(..).forEach(...)
(docs)
The easiest way is to use the Scanner class in Java and the FileReader object. Simple example:
Scanner in = new Scanner(new FileReader("filename.txt"));
Scanner has several methods for reading in strings, numbers, etc... You can look for more information on this on the Java documentation page.
For example reading the whole content into a String:
StringBuilder sb = new StringBuilder();
while(in.hasNext()) {
sb.append(in.next());
}
in.close();
outString = sb.toString();
Also if you need a specific encoding you can use this instead of FileReader:
new InputStreamReader(new FileInputStream(fileUtf8), StandardCharsets.UTF_8)
Here is a simple solution:
String content = new String(Files.readAllBytes(Paths.get("sample.txt")));
Or to read as list:
List<String> content = Files.readAllLines(Paths.get("sample.txt"))
Here's another way to do it without using external libraries:
import java.io.File;
import java.io.FileReader;
import java.io.IOException;
public String readFile(String filename)
{
String content = null;
File file = new File(filename); // For example, foo.txt
FileReader reader = null;
try {
reader = new FileReader(file);
char[] chars = new char[(int) file.length()];
reader.read(chars);
content = new String(chars);
reader.close();
} catch (IOException e) {
e.printStackTrace();
} finally {
if(reader != null){
reader.close();
}
}
return content;
}
I had to benchmark the different ways. I shall comment on my findings but, in short, the fastest way is to use a plain old BufferedInputStream over a FileInputStream. If many files must be read then three threads will reduce the total execution time to roughly half, but adding more threads will progressively degrade performance until making it take three times longer to complete with twenty threads than with just one thread.
The assumption is that you must read a file and do something meaningful with its contents. In the examples here is reading lines from a log and count the ones which contain values that exceed a certain threshold. So I am assuming that the one-liner Java 8 Files.lines(Paths.get("/path/to/file.txt")).map(line -> line.split(";")) is not an option.
I tested on Java 1.8, Windows 7 and both SSD and HDD drives.
I wrote six different implementations:
rawParse: Use BufferedInputStream over a FileInputStream and then cut lines reading byte by byte. This outperformed any other single-thread approach, but it may be very inconvenient for non-ASCII files.
lineReaderParse: Use a BufferedReader over a FileReader, read line by line, split lines by calling String.split(). This is approximatedly 20% slower that rawParse.
lineReaderParseParallel: This is the same as lineReaderParse, but it uses several threads. This is the fastest option overall in all cases.
nioFilesParse: Use java.nio.files.Files.lines()
nioAsyncParse: Use an AsynchronousFileChannel with a completion handler and a thread pool.
nioMemoryMappedParse: Use a memory-mapped file. This is really a bad idea yielding execution times at least three times longer than any other implementation.
These are the average times for reading 204 files of 4 MB each on an quad-core i7 and SSD drive. The files are generated on the fly to avoid disk caching.
rawParse 11.10 sec
lineReaderParse 13.86 sec
lineReaderParseParallel 6.00 sec
nioFilesParse 13.52 sec
nioAsyncParse 16.06 sec
nioMemoryMappedParse 37.68 sec
I found a difference smaller than I expected between running on an SSD or an HDD drive being the SSD approximately 15% faster. This may be because the files are generated on an unfragmented HDD and they are read sequentially, therefore the spinning drive can perform nearly as an SSD.
I was surprised by the low performance of the nioAsyncParse implementation. Either I have implemented something in the wrong way or the multi-thread implementation using NIO and a completion handler performs the same (or even worse) than a single-thread implementation with the java.io API. Moreover the asynchronous parse with a CompletionHandler is much longer in lines of code and tricky to implement correctly than a straight implementation on old streams.
Now the six implementations followed by a class containing them all plus a parametrizable main() method that allows to play with the number of files, file size and concurrency degree. Note that the size of the files varies plus minus 20%. This is to avoid any effect due to all the files being of exactly the same size.
rawParse
public void rawParse(final String targetDir, final int numberOfFiles) throws IOException, ParseException {
overrunCount = 0;
final int dl = (int) ';';
StringBuffer lineBuffer = new StringBuffer(1024);
for (int f=0; f<numberOfFiles; f++) {
File fl = new File(targetDir+filenamePreffix+String.valueOf(f)+".txt");
FileInputStream fin = new FileInputStream(fl);
BufferedInputStream bin = new BufferedInputStream(fin);
int character;
while((character=bin.read())!=-1) {
if (character==dl) {
// Here is where something is done with each line
doSomethingWithRawLine(lineBuffer.toString());
lineBuffer.setLength(0);
}
else {
lineBuffer.append((char) character);
}
}
bin.close();
fin.close();
}
}
public final void doSomethingWithRawLine(String line) throws ParseException {
// What to do for each line
int fieldNumber = 0;
final int len = line.length();
StringBuffer fieldBuffer = new StringBuffer(256);
for (int charPos=0; charPos<len; charPos++) {
char c = line.charAt(charPos);
if (c==DL0) {
String fieldValue = fieldBuffer.toString();
if (fieldValue.length()>0) {
switch (fieldNumber) {
case 0:
Date dt = fmt.parse(fieldValue);
fieldNumber++;
break;
case 1:
double d = Double.parseDouble(fieldValue);
fieldNumber++;
break;
case 2:
int t = Integer.parseInt(fieldValue);
fieldNumber++;
break;
case 3:
if (fieldValue.equals("overrun"))
overrunCount++;
break;
}
}
fieldBuffer.setLength(0);
}
else {
fieldBuffer.append(c);
}
}
}
lineReaderParse
public void lineReaderParse(final String targetDir, final int numberOfFiles) throws IOException, ParseException {
String line;
for (int f=0; f<numberOfFiles; f++) {
File fl = new File(targetDir+filenamePreffix+String.valueOf(f)+".txt");
FileReader frd = new FileReader(fl);
BufferedReader brd = new BufferedReader(frd);
while ((line=brd.readLine())!=null)
doSomethingWithLine(line);
brd.close();
frd.close();
}
}
public final void doSomethingWithLine(String line) throws ParseException {
// Example of what to do for each line
String[] fields = line.split(";");
Date dt = fmt.parse(fields[0]);
double d = Double.parseDouble(fields[1]);
int t = Integer.parseInt(fields[2]);
if (fields[3].equals("overrun"))
overrunCount++;
}
lineReaderParseParallel
public void lineReaderParseParallel(final String targetDir, final int numberOfFiles, final int degreeOfParalelism) throws IOException, ParseException, InterruptedException {
Thread[] pool = new Thread[degreeOfParalelism];
int batchSize = numberOfFiles / degreeOfParalelism;
for (int b=0; b<degreeOfParalelism; b++) {
pool[b] = new LineReaderParseThread(targetDir, b*batchSize, b*batchSize+b*batchSize);
pool[b].start();
}
for (int b=0; b<degreeOfParalelism; b++)
pool[b].join();
}
class LineReaderParseThread extends Thread {
private String targetDir;
private int fileFrom;
private int fileTo;
private DateFormat fmt = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
private int overrunCounter = 0;
public LineReaderParseThread(String targetDir, int fileFrom, int fileTo) {
this.targetDir = targetDir;
this.fileFrom = fileFrom;
this.fileTo = fileTo;
}
private void doSomethingWithTheLine(String line) throws ParseException {
String[] fields = line.split(DL);
Date dt = fmt.parse(fields[0]);
double d = Double.parseDouble(fields[1]);
int t = Integer.parseInt(fields[2]);
if (fields[3].equals("overrun"))
overrunCounter++;
}
#Override
public void run() {
String line;
for (int f=fileFrom; f<fileTo; f++) {
File fl = new File(targetDir+filenamePreffix+String.valueOf(f)+".txt");
try {
FileReader frd = new FileReader(fl);
BufferedReader brd = new BufferedReader(frd);
while ((line=brd.readLine())!=null) {
doSomethingWithTheLine(line);
}
brd.close();
frd.close();
} catch (IOException | ParseException ioe) { }
}
}
}
nioFilesParse
public void nioFilesParse(final String targetDir, final int numberOfFiles) throws IOException, ParseException {
for (int f=0; f<numberOfFiles; f++) {
Path ph = Paths.get(targetDir+filenamePreffix+String.valueOf(f)+".txt");
Consumer<String> action = new LineConsumer();
Stream<String> lines = Files.lines(ph);
lines.forEach(action);
lines.close();
}
}
class LineConsumer implements Consumer<String> {
#Override
public void accept(String line) {
// What to do for each line
String[] fields = line.split(DL);
if (fields.length>1) {
try {
Date dt = fmt.parse(fields[0]);
}
catch (ParseException e) {
}
double d = Double.parseDouble(fields[1]);
int t = Integer.parseInt(fields[2]);
if (fields[3].equals("overrun"))
overrunCount++;
}
}
}
nioAsyncParse
public void nioAsyncParse(final String targetDir, final int numberOfFiles, final int numberOfThreads, final int bufferSize) throws IOException, ParseException, InterruptedException {
ScheduledThreadPoolExecutor pool = new ScheduledThreadPoolExecutor(numberOfThreads);
ConcurrentLinkedQueue<ByteBuffer> byteBuffers = new ConcurrentLinkedQueue<ByteBuffer>();
for (int b=0; b<numberOfThreads; b++)
byteBuffers.add(ByteBuffer.allocate(bufferSize));
for (int f=0; f<numberOfFiles; f++) {
consumerThreads.acquire();
String fileName = targetDir+filenamePreffix+String.valueOf(f)+".txt";
AsynchronousFileChannel channel = AsynchronousFileChannel.open(Paths.get(fileName), EnumSet.of(StandardOpenOption.READ), pool);
BufferConsumer consumer = new BufferConsumer(byteBuffers, fileName, bufferSize);
channel.read(consumer.buffer(), 0l, channel, consumer);
}
consumerThreads.acquire(numberOfThreads);
}
class BufferConsumer implements CompletionHandler<Integer, AsynchronousFileChannel> {
private ConcurrentLinkedQueue<ByteBuffer> buffers;
private ByteBuffer bytes;
private String file;
private StringBuffer chars;
private int limit;
private long position;
private DateFormat frmt = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
public BufferConsumer(ConcurrentLinkedQueue<ByteBuffer> byteBuffers, String fileName, int bufferSize) {
buffers = byteBuffers;
bytes = buffers.poll();
if (bytes==null)
bytes = ByteBuffer.allocate(bufferSize);
file = fileName;
chars = new StringBuffer(bufferSize);
frmt = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
limit = bufferSize;
position = 0l;
}
public ByteBuffer buffer() {
return bytes;
}
#Override
public synchronized void completed(Integer result, AsynchronousFileChannel channel) {
if (result!=-1) {
bytes.flip();
final int len = bytes.limit();
int i = 0;
try {
for (i = 0; i < len; i++) {
byte by = bytes.get();
if (by=='\n') {
// ***
// The code used to process the line goes here
chars.setLength(0);
}
else {
chars.append((char) by);
}
}
}
catch (Exception x) {
System.out.println(
"Caught exception " + x.getClass().getName() + " " + x.getMessage() +
" i=" + String.valueOf(i) + ", limit=" + String.valueOf(len) +
", position="+String.valueOf(position));
}
if (len==limit) {
bytes.clear();
position += len;
channel.read(bytes, position, channel, this);
}
else {
try {
channel.close();
}
catch (IOException e) {
}
consumerThreads.release();
bytes.clear();
buffers.add(bytes);
}
}
else {
try {
channel.close();
}
catch (IOException e) {
}
consumerThreads.release();
bytes.clear();
buffers.add(bytes);
}
}
#Override
public void failed(Throwable e, AsynchronousFileChannel channel) {
}
};
FULL RUNNABLE IMPLEMENTATION OF ALL CASES
https://github.com/sergiomt/javaiobenchmark/blob/master/FileReadBenchmark.java
Here are the three working and tested methods:
Using BufferedReader
package io;
import java.io.*;
public class ReadFromFile2 {
public static void main(String[] args)throws Exception {
File file = new File("C:\\Users\\pankaj\\Desktop\\test.java");
BufferedReader br = new BufferedReader(new FileReader(file));
String st;
while((st=br.readLine()) != null){
System.out.println(st);
}
}
}
Using Scanner
package io;
import java.io.File;
import java.util.Scanner;
public class ReadFromFileUsingScanner {
public static void main(String[] args) throws Exception {
File file = new File("C:\\Users\\pankaj\\Desktop\\test.java");
Scanner sc = new Scanner(file);
while(sc.hasNextLine()){
System.out.println(sc.nextLine());
}
}
}
Using FileReader
package io;
import java.io.*;
public class ReadingFromFile {
public static void main(String[] args) throws Exception {
FileReader fr = new FileReader("C:\\Users\\pankaj\\Desktop\\test.java");
int i;
while ((i=fr.read()) != -1){
System.out.print((char) i);
}
}
}
Read the entire file without a loop using the Scanner class
package io;
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class ReadingEntireFileWithoutLoop {
public static void main(String[] args) throws FileNotFoundException {
File file = new File("C:\\Users\\pankaj\\Desktop\\test.java");
Scanner sc = new Scanner(file);
sc.useDelimiter("\\Z");
System.out.println(sc.next());
}
}
The methods within org.apache.commons.io.FileUtils may also be very handy, e.g.:
/**
* Reads the contents of a file line by line to a List
* of Strings using the default encoding for the VM.
*/
static List readLines(File file)
I documented 15 ways to read a file in Java and then tested them for speed with various file sizes - from 1 KB to 1 GB and here are the top three ways to do this:
java.nio.file.Files.readAllBytes()
Tested to work in Java 7, 8, and 9.
import java.io.File;
import java.io.IOException;
import java.nio.file.Files;
public class ReadFile_Files_ReadAllBytes {
public static void main(String [] pArgs) throws IOException {
String fileName = "c:\\temp\\sample-10KB.txt";
File file = new File(fileName);
byte [] fileBytes = Files.readAllBytes(file.toPath());
char singleChar;
for(byte b : fileBytes) {
singleChar = (char) b;
System.out.print(singleChar);
}
}
}
java.io.BufferedReader.readLine()
Tested to work in Java 7, 8, 9.
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
public class ReadFile_BufferedReader_ReadLine {
public static void main(String [] args) throws IOException {
String fileName = "c:\\temp\\sample-10KB.txt";
FileReader fileReader = new FileReader(fileName);
try (BufferedReader bufferedReader = new BufferedReader(fileReader)) {
String line;
while((line = bufferedReader.readLine()) != null) {
System.out.println(line);
}
}
}
}
java.nio.file.Files.lines()
This was tested to work in Java 8 and 9 but won't work in Java 7 because of the lambda expression requirement.
import java.io.File;
import java.io.IOException;
import java.nio.file.Files;
import java.util.stream.Stream;
public class ReadFile_Files_Lines {
public static void main(String[] pArgs) throws IOException {
String fileName = "c:\\temp\\sample-10KB.txt";
File file = new File(fileName);
try (Stream linesStream = Files.lines(file.toPath())) {
linesStream.forEach(line -> {
System.out.println(line);
});
}
}
}
What do you want to do with the text? Is the file small enough to fit into memory? I would try to find the simplest way to handle the file for your needs. The FileUtils library is very handle for this.
for(String line: FileUtils.readLines("my-text-file"))
System.out.println(line);
Below is a one-liner of doing it in the Java 8 way. Assuming text.txt file is in the root of the project directory of the Eclipse.
Files.lines(Paths.get("text.txt")).collect(Collectors.toList());
The most intuitive method is introduced in Java 11 Files.readString
import java.io.*;
import java.nio.file.Files;
import java.nio.file.Paths;
public class App {
public static void main(String args[]) throws IOException {
String content = Files.readString(Paths.get("D:\\sandbox\\mvn\\my-app\\my-app.iml"));
System.out.print(content);
}
}
PHP has this luxury for decades! ☺
The buffered stream classes are much more performant in practice, so much so that the NIO.2 API includes methods that specifically return these stream classes, in part to encourage you always to use buffered streams in your application.
Here is an example:
Path path = Paths.get("/myfolder/myfile.ext");
try (BufferedReader reader = Files.newBufferedReader(path)) {
// Read from the stream
String currentLine = null;
while ((currentLine = reader.readLine()) != null)
//do your code here
} catch (IOException e) {
// Handle file I/O exception...
}
You can replace this code
BufferedReader reader = Files.newBufferedReader(path);
with
BufferedReader br = new BufferedReader(new FileReader("/myfolder/myfile.ext"));
I recommend this article to learn the main uses of Java NIO and IO.
Using BufferedReader:
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
BufferedReader br;
try {
br = new BufferedReader(new FileReader("/fileToRead.txt"));
try {
String x;
while ( (x = br.readLine()) != null ) {
// Printing out each line in the file
System.out.println(x);
}
}
catch (IOException e) {
e.printStackTrace();
}
}
catch (FileNotFoundException e) {
System.out.println(e);
e.printStackTrace();
}
This is basically the exact same as Jesus Ramos' answer, except with File instead of FileReader plus iteration to step through the contents of the file.
Scanner in = new Scanner(new File("filename.txt"));
while (in.hasNext()) { // Iterates each line in the file
String line = in.nextLine();
// Do something with line
}
in.close(); // Don't forget to close resource leaks
... throws FileNotFoundException
Probably not as fast as with buffered I/O, but quite terse:
String content;
try (Scanner scanner = new Scanner(textFile).useDelimiter("\\Z")) {
content = scanner.next();
}
The \Z pattern tells the Scanner that the delimiter is EOF.
The most simple way to read data from a file in Java is making use of the File class to read the file and the Scanner class to read the content of the file.
public static void main(String args[])throws Exception
{
File f = new File("input.txt");
takeInputIn2DArray(f);
}
public static void takeInputIn2DArray(File f) throws Exception
{
Scanner s = new Scanner(f);
int a[][] = new int[20][20];
for(int i=0; i<20; i++)
{
for(int j=0; j<20; j++)
{
a[i][j] = s.nextInt();
}
}
}
PS: Don't forget to import java.util.*; for Scanner to work.
You can use readAllLines and the join method to get whole file content in one line:
String str = String.join("\n",Files.readAllLines(Paths.get("e:\\text.txt")));
It uses UTF-8 encoding by default, which reads ASCII data correctly.
Also you can use readAllBytes:
String str = new String(Files.readAllBytes(Paths.get("e:\\text.txt")), StandardCharsets.UTF_8);
I think readAllBytes is faster and more precise, because it does not replace new line with \n and also new line may be \r\n. It is depending on your needs which one is suitable.
I don't see it mentioned yet in the other answers so far. But if "Best" means speed, then the new Java I/O (NIO) might provide the fastest preformance, but not always the easiest to figure out for someone learning.
http://download.oracle.com/javase/tutorial/essential/io/file.html
Guava provides a one-liner for this:
import com.google.common.base.Charsets;
import com.google.common.io.Files;
String contents = Files.toString(filePath, Charsets.UTF_8);
Cactoos give you a declarative one-liner:
new TextOf(new File("a.txt")).asString();
This might not be the exact answer to the question. It's just another way of reading a file where you do not explicitly specify the path to your file in your Java code and instead, you read it as a command-line argument.
With the following code,
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.IOException;
public class InputReader{
public static void main(String[] args)throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String s="";
while((s=br.readLine())!=null){
System.out.println(s);
}
}
}
just go ahead and run it with:
java InputReader < input.txt
This would read the contents of the input.txt and print it to the your console.
You can also make your System.out.println() to write to a specific file through the command line as follows:
java InputReader < input.txt > output.txt
This would read from input.txt and write to output.txt.
For JSF-based Maven web applications, just use ClassLoader and the Resources folder to read in any file you want:
Put any file you want to read in the Resources folder.
Put the Apache Commons IO dependency into your POM:
<dependency>
<groupId>org.apache.commons</groupId>
<artifactId>commons-io</artifactId>
<version>1.3.2</version>
</dependency>
Use the code below to read it (e.g. below is reading in a .json file):
String metadata = null;
FileInputStream inputStream;
try {
ClassLoader loader = Thread.currentThread().getContextClassLoader();
inputStream = (FileInputStream) loader
.getResourceAsStream("/metadata.json");
metadata = IOUtils.toString(inputStream);
inputStream.close();
}
catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return metadata;
You can do the same for text files, .properties files, XSD schemas, etc.
try {
File f = new File("filename.txt");
Scanner r = new Scanner(f);
while (r.hasNextLine()) {
String data = r.nextLine();
JOptionPane.showMessageDialog(data);
}
r.close();
} catch (FileNotFoundException ex) {
JOptionPane.showMessageDialog("Error occurred");
ex.printStackTrace();
}
Use Java kiss if this is about simplicity of structure:
import static kiss.API.*;
class App {
void run() {
String line;
try (Close in = inOpen("file.dat")) {
while ((line = readLine()) != null) {
println(line);
}
}
}
}
import java.util.stream.Stream;
import java.nio.file.*;
import java.io.*;
class ReadFile {
public static void main(String[] args) {
String filename = "Test.txt";
try(Stream<String> stream = Files.lines(Paths.get(filename))) {
stream.forEach(System.out:: println);
} catch (IOException e) {
e.printStackTrace();
}
}
}
Just use java 8 Stream.
In case you have a large file you can use Apache Commons IO to process the file iteratively without exhausting the available memory.
try (LineIterator it = FileUtils.lineIterator(theFile, "UTF-8")) {
while (it.hasNext()) {
String line = it.nextLine();
// do something with line
}
}
try (Stream<String> stream = Files.lines(Paths.get(String.valueOf(new File("yourFile.txt"))))) {
stream.forEach(System.out::println);
} catch (IOException e) {
e.printStackTrace();
}
new File(<path_name>)
Creates a new File instance by converting the given pathname string into an abstract pathname. If the given string is the empty string, then the result is the empty abstract pathname.
Params:
pathname – A pathname string
Throws:
NullPointerException – If the pathname argument is null
Files.lines returns a stream of String
Stream<String> stream = Files.lines(Paths.get(String.valueOf(new File("yourFile.txt"))))
can throw nullPointerExcetion , FileNotFoundException so, keepint it inside try will take care of Exception in runtime
stream.forEach(System.out::println);
This is used to iterate over the stream and print in console
If you have different use case you can provide your custome function to manipulate the stream of lines
My new favorite approach to simply read a whole text file from a BufferedReader input goes:
String text = input.lines().collect(Collectors.joining(System.lineSeparator())));
This will read the whole file by adding new line (lineSeparator) behind each line. Without the separator it would join all lines together as one.
This appears to have existed since Java 8.
For Android developers ending up here (who use Kotlin):
val myFileUrl = object{}.javaClass.getResource("/vegetables.txt")
val text = myFileUrl.readText() // Not recommended for huge files
println(text)
Other solution:
val myFileUrl = object{}.javaClass.getResource("/vegetables.txt")
val file = File(myFileUrl.toURI())
val lines = file.readLines() // Not recommended for huge files
lines.forEach(::println)
Another good solution which can be used for huge files as well:
val myFileUrl = object{}.javaClass.getResource("/vegetables.txt")
val file = File(myFileUrl.toURI())
file
.bufferedReader()
.lineSequence()
.forEach(::println)
Or:
val myFileUrl = object{}.javaClass.getResource("/vegetables.txt")
val file = File(myFileUrl.toURI())
file.useLines { lines ->
lines.forEach(::println)
}
Notes:
The vegetables.txt file should be in your classpath (for example, in src/main/resources directory)
The above solutions all treat the file encodings as UTF-8 by default. You can specify your desired encoding as the argument for the functions.
The above solutions do not need any further action like closing the files or readers. They are automatically taken care of by the Kotlin standard library.