I have a document with many string like this:
<rdf:type rdf:resource="http://example.com"/>
where http://example.com is not a constant value, it change every time.
The string must become:
<process:valueType rdf:datatype="http://www.w3.org/2001/XMLSchema#anyURI">http://example.com</process:valueType>
How can i do in java?
I solved in this way:
result = result.replaceAll("(<rdf:type rdf:resource=\"([^<]*)\"/>)", "<process:valueType rdf:datatype=\"http://www.w3.org/2001/XMLSchema#anyURI\">$2</process:valueType>");
I would use lookbehind to find rdf:datatype and select everything other than " which is actually the end of the value, something like this:
(?<=datatype=\")[^\"]*
you can do that with lookahead to:
(?<=datatype=\").*(?=\")
Related
My String is like this.
{\\\"692950841314120\\\":[{\\\"type\\\":\\\"ads_management\\\",\\\"call_count\\\":3,\\\"total_cputime\\\":1,\\\"total_time\\\":5,\\\"estimated_time_to_regain_access\\\":0}]}
Since the key here is a variable value I am trying to replace this 692950841314120(or the values which I get from sever) with a constant like ID. My main goal is to parse this as POJO. I have tried using..
string.replaceAll("^[0-9]{15}$","ID")
but due to Slashes I think i am not able to get the desired value. Is there any better way to do this. I know I can do below Code but I don't want any ID123 if I added extra value and distort any other info in JSON.
string.replaceAll("[0-9]{15}","ID")
Strictly speaking, if you have a valid JSON string, you should parse it using something like GSON, rather than using regex. That being said, if you must use regex, you could try removing the starting and ending anchors:
string.replaceAll("[0-9]{15}", "ID")
Or maybe use double quotes instead:
string.replaceAll("\"[0-9]{15}\"", "ID")
It is safer to assume the value is inisde \" and \":.
You can then use
.replaceAll("(\\\\\")[0-9]{15}(\\\\\":)", "$1ID$2")
The regex is (\\")[0-9]{15}(\\":) and it means:
(\\") - match and capture \" substring into Group 1
[0-9]{15} - fifteen digits
(\\":) - Group 2: a \": substring.
The $1 and $2 are placeholders holding the Group 1 and 2 values.
You should use "A word boundary" \b.
Try this.
public static void main(String[] args) {
String input = "{\\\"692950841314120\\\":"
+ "[{\\\"type\\\":\\\"12345678901234567890\\\","
+ "\\\"call_count\\\":3,"
+ "\\\"total_cputime\\\":1,"
+ "\\\"total_time\\\":5,"
+ "\\\"estimated_time_to_regain_access\\\":0}]}";
System.out.println(input.replaceAll("\\b[0-9]{15}\\b", "ID"));
}
output:
{\"ID\":[{\"type\":\"12345678901234567890\",\"call_count\":3,\"total_cputime\":1,\"total_time\":5,\"estimated_time_to_regain_access\":0}]}
I have a tag like following, I want to replace the USERNAME in this, here user name is dynamic value:
<ns3:AgentName xmlns:ns3="http://example.com">USERNAME</ns3:AgentName>
I want to replace this tag with
<ns3:AgentName>XXXXXXX</ns3:AgentName>
I tried the regex like following:
<ns3:AgentName.*</ns3:AgentName>
<ns3:AgentName xmlns:ns3="http://example.com">.*</ns3:AgentName>
Nothing worked for me
This worked for me when I tested it at RegexPlanet.
My regular expression was:
(\<ns3:AgentName) xmlns:ns3="http://example.com"(\>).*(\</ns3:AgentName\>)
If you want to replace USERNAME with x's, my replacement was:
$1$2xxxxxx$3
If you want to put USERNAME in the replacement, I'd make my regular expression this:
(\<ns3:AgentName) xmlns:ns3="http://example.com"(\>.*)(\</ns3:AgentName\>)
and my replacement this:
$1$2$3
I have following hql query,
from Channe where ip='1.11.6.0';
But in the db the IP is saving as 1.11.6.0:8080 .
So I need to modify the query in a way that, split the ip with a delimiter ':' and take the firstcome value. I do not wish to modify the search with value 1.11.6.0:8080.
See this page in the Hibernate docs. On the page below there is a section called 14.10. Expressions
http://docs.jboss.org/hibernate/orm/3.3/reference/en/html/queryhql.html
It says, among other things:
string concatenation ...||... or concat(...,...) current_date(),
...
Any function or operator defined by EJB-QL 3.0: substring(), trim(), lower(), upper(),
length(), locate(), abs(), sqrt(), bit_length(), mod()
But you are actually better off doing as #Hansraj suggests in the comments and appending a wildcard to your search term
String query = "from Channe where ip like :term";
entityManager.createQuery(query).setParameter("term",ipString + "%");
This assumes that your data type is string, of course.
Try the following:
Say variable ip had the address
ip = "10.131.56.40:8080";
var ipSplit = ip.Split(':');
var ipStart = ipSplit[0];
ipStart will store only 10.131.56.40
This could solve your problem
Try this:
SPLIT(".", FIELDNAME)
I have a String with single quote. I want to replace the single quote with 2 single quotes.
I tried using
String s="Kathleen D'Souza";
s.replaceAll("'","''");
s.replaceAll("\'","\'\'");
s.replace("'","''");
s.replace("\'","\'\'");
But the single quote is not getting replaced with 2 single quotes.
reassign the replaced string to s
String s="Kathleen D'Souza";
s = s.replaceAll("'","''");
Please try
s= "test ' test";
`s.replaceAll("'","\"");` => test " test
`s.replaceAll("'","''");` => test '' test
Strings are immutable. Assign the result of replaceAll to your String:
s = s.replaceAll("'","''");
String s="Kathleen D'Souza";
s= s.replace("'", "''");
Try String#replace(). It will replace all occurrence of single ' with double ''.
Note, with the given solutions successive single quotes will be doubled, so Kathleen D''Souza turns into Kathleen D''''Souza. (I've seen users outsmart themselves like this.) If that is something you are concerned about, you can match successive single quotes with:
s = s.replaceAll("''*","''");
I have the following string:
I would "surely" like to "go to school".
Now, I would like to split this string at the ellipses, that is i would like to get the following output:
I would
surely
like to
go to school
.
I case you meant quotation mark (") instead of ellipsis, the easiest solution is to use String.split:
String text = "I would \"surely\" like to \"go to school\".";
String[] result = text.split("\"");