I am having problem with java Calendar dates.
Bassically I have a list of holidays and want to check if a date belong
to the list. Still confused about how the Calendar class
is creating and formating its dates.
Please see the folowing code sample:
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Calendar;
import java.util.Date;
public class CompareCalendarDates {
public static void main(String args[]) {
Date date1 = null;
try {
date1= new SimpleDateFormat("yyyy-MM-dd").parse("2019-12-25");
} catch (ParseException e) {
date1 = null;
}
Calendar calendar1 = Calendar.getInstance();
calendar1.clear();
calendar1.setTime(date1);
Calendar calendar2 = Calendar.getInstance();
calendar2.clear();
calendar2.setLenient(false); // Don't automatically convert invalid date.
calendar2.set(2019, 11, 25, 0, 0, 0);
calendar2.getTimeInMillis();
boolean isEqual = calendar1.equals(calendar2);
System.out.println ("Are to dates equal: " + isEqual);
}
}
I'm creating in 2 dates using different methods from Calendar class.
In my opinion the dates should be equal but there are not.
What am I missing? What is the difference between the methods
setTime () and set ?
You should use
boolean isEqual = calendar1.getTime().equals(calendar2.getTime());
Instead of
boolean isEqual = calendar1.equals(calendar2);
because the equals() method in Calendar class looks like these:
public boolean equals(Object obj) {
return obj instanceof Date && getTime() == ((Date) obj).getTime();
}
So it checks if the dates in these two calendars are the same objects, and in your case they are not the same objects, they jut have the same value.
tl;dr
LocalDate
.parse( "2019-12-25" )
.isEqual(
LocalDate.of( 2019 , Month.DECEMBER , 25 )
)
true
Details
Never use Date/Calendar. Use only java.time classes.
LocalDate::isEqual
For a date-only value without time-of-day and without time zone, use LocalDate.
LocalDate ld = LocalDate.parse( "2019-12-25" ) ;
LocalDate other = LocalDate.of( 2019, 11, 25 ) ;
Compare using isEqual, isBefore, isAfter.
boolean sameDates = ld.isEqual( other ) ;
This has been addressed many many times already on Stack Overflow. So I am keeping this Answer brief. Search to learn more.
December versus November
Unlike those legacy classes, the java.time classes use sane numbering. Months are counted 1-12 for January-December.
So notice that your pair of inputs differ, one for December, and one for November.
For clarity, you can use Month enum rather than an integer. Another benefit of enums is to ensure valid values.
LocalDate other = LocalDate.of( 2019 , Month.NOVEMBER , 25 ) ;
java.time
If you have got a Calendar object from a legacy API that you cannot afford to upgrade to java.time, the modern Java date and time API, just now, and you want to know whether it denotes the same date as some string, convert both to LocalDate and compare using the isEqual method:
String date1Str = "2019-12-25";
Calendar calendar2 = new GregorianCalendar(2019, Calendar.DECEMBER, 25);
LocalDate date1 = LocalDate.parse(date1Str);
LocalDate date2 = ((GregorianCalendar) calendar2).toZonedDateTime().toLocalDate();
boolean isEqual = date1.isEqual(date2);
System.out.println ("Are to dates equal: " + isEqual);
Output:
Are to dates equal: true
A LocalDate is a date without time of day, time zone, and all the other things that an old-fashioned Calendar object carries with it. So comparing two LocalDate will give you the result that you had expected.
What went wrong in your code?
While your two Calendar objects do denote the same point in time and also the same calendar date (which is not the same thing to ask), there are some differences, for example:
calendar1 has got all its fields set while calendar2 has got some uncomputed fields including for example era, week of year, AM/PM, millisecond of second and zone offset.
calendar1 is lenient, calendar2 is not.
I believe that this is more than enough that the objects are not considered equal. I haven’t checked the documentation for the exact criteria. You may do that out of curiosity, but I suggest that you don’t need to because you are not going to need to compare two Calendar objects for equality.
To answer your question, it seems that setTime() sets all fields while set obviuosly only sets some. I was surprised to see that getTimeInMillis() didn’t calculate the rest, but it doesn’t.
Link
Oracle tutorial: Date Time explaining how to use java.time.
In my app I create an object that represents a high school class. This object holds 2 Calendar objects that represents the class's start and stop time each day. When a user creates an assignment I want to check if the current time is between the two times of any of the classes. If it is I know that the assignment was created during that class. Here is my current code that does not work because .getTime() returns a date that includes month, and day, while I would just like to compare hours, and minutes. SO how can I trim the returned dates to just include the time in day? Would this be easier with joda-time, and if so what classes should be used?
public void checkTimeFrame() {
time = Calendar.getInstance().getTime();
ArrayList<SchoolClass> mList = mClassList;
// Changes index if assignment falls under time frame of class
for (int a = 0; a < mList.size(); a++) {
if (mList.get(a).getStartTime() != null && mList.get(a).getEndTime() != null &&
time.after(mList.get(a).getStartTime().getTime()) && time.before(mList.get(a)
.getEndTime().getTime())) {
index = a;
updateClassEditText();
}
}
}
JDK 8 Date-Time APIs are a good approach to solving these kinds of issues. Instead of Calendar , use LocalTime to store the start and end time of the class.
LocalTime now = LocalTime.now(ZoneId.systemDefault());
LocalTime start = mList.get(a).getStartTime();
LocalTime end = mList.get(a).getEndTime();
if(now.isAfter(start) && now.isBefore(end)){
//do something
}
For Android, you can use The ThreeTenABP project which adapts the java.time APIs for Android.
You can use Calendar.get(), as mentioned in another answer. To compare minutes, though, you should use Calendar.MINUTE, too:
int minutes_in_day = time.get(Calendar.HOUR_OF_DAY)*60 + time.get(Calendar.MINUTE);
Then, you can just compare the minutes within the day of the current time with that of the start and end times. This will, of course, only work when the times are in the same day.
The Calendar class has a get method where you can get different fields
e.g.
int hr = time.get(Calendar.HOUR_OF_DAY)
I will here only provide the Joda-Time-related answer you asked for. Joda-Time has the advantage to offer a dedicated type for the clock time, namely LocalTime. The old java.util.Calendar-stuff does not offer this advantage hence your difficulties.
First you convert an instance of java.util.Date like follows:
Date time = ...;
DateTime dt = new DateTime(time, DateTimeZone.getDefault());
LocalTime lt = dt.toLocalTime();
Note that the conversion is always timezone dependent. Then you can compare two LocalTime instances using the inherited methods isAfter(...) or isBefore(...).
try {
Date date1 = sdf.parse(given time);
Date date2 = sdf.parse("08:00 AM");
Date date3 = sdf.parse("06:00 PM");
if((date1.after(date2))&&(date1.before(date3))||date1.equals(date2) ||date1.equals(date3) ) {
}
} catch (ParseException e){
e.printStackTrace();
}
I want to compare two dates, however I'm running into trouble. 1 date is created from a java.util.date object and the other is manually crafted. The following code is an example:
Date ds = new Date();
DateTime d = new DateTime(ds);
DateTime e = new DateTime(2012,12,07, 0, 0);
System.out.println(d.isEqual(e));
However the test turns out false. I am guessing that it is because of the time. How can I check if these two dates are equal to each other (I mean the Year, month, date are identical)?
System.out.println(d.toDateMidnight().isEqual(e.toDateMidnight()));
or
System.out.println(d.withTimeAtStartOfDay().isEqual(e.withTimeAtStartOfDay()));
You should use toLocalDate():
date1.toLocalDate().isEqual(date2.toLocalDate())
This will get rid of the Time part of the DateTime.
There is another approach, but it does not account for the case where the two dates have a different timezone, so it's less reliable:
date1.withTimeAtStartOfDay().isEqual(date2.withTimeAtStartOfDay())
return DateTimeComparator.getDateOnlyInstance().compare(first, second);
Via How to compare two Dates without the time portion?
If you want to ignore time components (i.e. you want to compare only dates) you can use DateMidnight class instead of Date Time. So your example will look something like this:
Date ds = new Date();
DateMidnight d = new DateMidnight(ds);
DateMidnight e = new DateMidnight(2012, 12, 7);
System.out.println(d.isEqual(e));
But beware, it will print "true" only today :)
Also note that by default JDK Date and all Joda-Time instant classes (DateTime and DateMidnight included) are constructed using default timezone. So if you create one date to compare in code, but retrieve another one from the DB which probably stores dates in UTC you may encounter inconsistencies assuming you are not in UTC time zone.
As they're DateTime objects, their time parts are also taken into consideration when you're comparing them. Try setting the time parts of the first date to 0, like:
d = d.withTime(0, 0, 0, 0);
I stumbled into this question while looking for a comparison with today. Here's how you can compare a date to today :
date1.toLocalDate().isBeforeNow() // works also with isAfterNow
This is a static method which works for me.
public static boolean isSameDay(DateTime date1, DateTime date2){
return date1.withTimeAtStartOfDay().isEqual(date2.withTimeAtStartOfDay());
}
DateTimeComparator.getDateOnlyInstance().compare(obj1, obj2);
obj1 and obj2 can be a String, Long, Date(java.util)... For the details see
http://www.joda.org/joda-time/apidocs/index.html?org/joda/time/DateTimeComparator.html
Write your own method
public boolean checkEqual(DateTime first,DateTime second){
if(first.<getterforyear> == second.<getterforyear> && first.<getterformonth> == second.<getterformonth> && first.<getterforday> == second.<getterforday>){
return true;
}
return false;
}
I would like to have a compareTo method that ignores the time portion of a java.util.Date. I guess there are a number of ways to solve this. What's the simplest way?
Update: while Joda Time was a fine recommendation at the time, use the java.time library from Java 8+ instead where possible.
My preference is to use Joda Time which makes this incredibly easy:
DateTime first = ...;
DateTime second = ...;
LocalDate firstDate = first.toLocalDate();
LocalDate secondDate = second.toLocalDate();
return firstDate.compareTo(secondDate);
EDIT: As noted in comments, if you use DateTimeComparator.getDateOnlyInstance() it's even simpler :)
// TODO: consider extracting the comparator to a field.
return DateTimeComparator.getDateOnlyInstance().compare(first, second);
("Use Joda Time" is the basis of almost all SO questions which ask about java.util.Date or java.util.Calendar. It's a thoroughly superior API. If you're doing anything significant with dates/times, you should really use it if you possibly can.)
If you're absolutely forced to use the built in API, you should create an instance of Calendar with the appropriate date and using the appropriate time zone. You could then set each field in each calendar out of hour, minute, second and millisecond to 0, and compare the resulting times. Definitely icky compared with the Joda solution though :)
The time zone part is important: java.util.Date is always based on UTC. In most cases where I've been interested in a date, that's been a date in a specific time zone. That on its own will force you to use Calendar or Joda Time (unless you want to account for the time zone yourself, which I don't recommend.)
Quick reference for android developers
//Add joda library dependency to your build.gradle file
dependencies {
...
implementation 'joda-time:joda-time:2.9.9'
}
Sample code (example)
DateTimeComparator dateTimeComparator = DateTimeComparator.getDateOnlyInstance();
Date myDateOne = ...;
Date myDateTwo = ...;
int retVal = dateTimeComparator.compare(myDateOne, myDateTwo);
if(retVal == 0)
//both dates are equal
else if(retVal < 0)
//myDateOne is before myDateTwo
else if(retVal > 0)
//myDateOne is after myDateTwo
Apache commons-lang is almost ubiquitous. So what about this?
if (DateUtils.isSameDay(date1, date2)) {
// it's same
} else if (date1.before(date2)) {
// it's before
} else {
// it's after
}
If you really want to use the java.util.Date, you would do something like this:
public class TimeIgnoringComparator implements Comparator<Date> {
public int compare(Date d1, Date d2) {
if (d1.getYear() != d2.getYear())
return d1.getYear() - d2.getYear();
if (d1.getMonth() != d2.getMonth())
return d1.getMonth() - d2.getMonth();
return d1.getDate() - d2.getDate();
}
}
or, using a Calendar instead (preferred, since getYear() and such are deprecated)
public class TimeIgnoringComparator implements Comparator<Calendar> {
public int compare(Calendar c1, Calendar c2) {
if (c1.get(Calendar.YEAR) != c2.get(Calendar.YEAR))
return c1.get(Calendar.YEAR) - c2.get(Calendar.YEAR);
if (c1.get(Calendar.MONTH) != c2.get(Calendar.MONTH))
return c1.get(Calendar.MONTH) - c2.get(Calendar.MONTH);
return c1.get(Calendar.DAY_OF_MONTH) - c2.get(Calendar.DAY_OF_MONTH);
}
}
My preference would be to use the Joda library insetad of java.util.Date directly, as Joda makes a distinction between date and time (see YearMonthDay and DateTime classes).
However, if you do wish to use java.util.Date I would suggest writing a utility method; e.g.
public static Date setTimeToMidnight(Date date) {
Calendar calendar = Calendar.getInstance();
calendar.setTime( date );
calendar.set(Calendar.HOUR_OF_DAY, 0);
calendar.set(Calendar.MINUTE, 0);
calendar.set(Calendar.SECOND, 0);
calendar.set(Calendar.MILLISECOND, 0);
return calendar.getTime();
}
Any opinions on this alternative?
SimpleDateFormat sdf = new SimpleDateFormat("yyyyMMdd");
sdf.format(date1).equals(sdf.format(date2));
If you want to compare only the month, day and year of two dates, following code works for me:
SimpleDateFormat sdf = new SimpleDateFormat("yyyyMMdd");
sdf.format(date1).equals(sdf.format(date2));
Thanks Rob.
tl;dr
myJavaUtilDate1.toInstant()
.atZone( ZoneId.of( "America/Montreal" ) )
.toLocalDate()
.isEqual (
myJavaUtilDate2.toInstant()
.atZone( ZoneId.of( "America/Montreal" ) )
.toLocalDate()
)
Avoid legacy date-time classes
Avoid the troublesome old legacy date-time classes such as Date & Calendar, now supplanted by the java.time classes.
Using java.time
A java.util.Date represents a moment on the timeline in UTC. The equivalent in java.time is Instant. You may convert using new methods added to the legacy class.
Instant instant1 = myJavaUtilDate1.toInstant();
Instant instant2 = myJavaUtilDate2.toInstant();
You want to compare by date. A time zone is crucial in determining a date. For any given moment, the date varies around the globe by zone. For example, a few minutes after midnight in Paris France is a new day while still “yesterday” in Montréal Québec.
Specify a proper time zone name in the format of continent/region, such as America/Montreal, Africa/Casablanca, or Pacific/Auckland. Never use the 3-4 letter abbreviation such as EST or IST as they are not true time zones, not standardized, and not even unique(!).
ZoneId z = ZoneId.of( "America/Montreal" );
Apply the ZoneId to the Instant to get a ZonedDateTime.
ZonedDateTime zdt1 = instant1.atZone( z );
ZonedDateTime zdt2 = instant2.atZone( z );
The LocalDate class represents a date-only value without time-of-day and without time zone. We can extract a LocalDate from a ZonedDateTime, effectively eliminating the time-of-day portion.
LocalDate localDate1 = zdt1.toLocalDate();
LocalDate localDate2 = zdt2.toLocalDate();
Now compare, using methods such as isEqual, isBefore, and isAfter.
Boolean sameDate = localDate1.isEqual( localDate2 );
See this code run live at IdeOne.com.
instant1: 2017-03-25T04:13:10.971Z | instant2: 2017-03-24T22:13:10.972Z
zdt1: 2017-03-25T00:13:10.971-04:00[America/Montreal] | zdt2: 2017-03-24T18:13:10.972-04:00[America/Montreal]
localDate1: 2017-03-25 | localDate2: 2017-03-24
sameDate: false
About java.time
The java.time framework is built into Java 8 and later. These classes supplant the troublesome old legacy date-time classes such as java.util.Date, Calendar, & SimpleDateFormat.
The Joda-Time project, now in maintenance mode, advises migration to the java.time classes.
To learn more, see the Oracle Tutorial. And search Stack Overflow for many examples and explanations. Specification is JSR 310.
Where to obtain the java.time classes?
Java SE 8 and SE 9 and later
Built-in.
Part of the standard Java API with a bundled implementation.
Java 9 adds some minor features and fixes.
Java SE 6 and SE 7
Much of the java.time functionality is back-ported to Java 6 & 7 in ThreeTen-Backport.
Android
The ThreeTenABP project adapts ThreeTen-Backport (mentioned above) for Android specifically.
See How to use ThreeTenABP….
The ThreeTen-Extra project extends java.time with additional classes. This project is a proving ground for possible future additions to java.time. You may find some useful classes here such as Interval, YearWeek, YearQuarter, and more.
I too prefer Joda Time, but here's an alternative:
long oneDay = 24 * 60 * 60 * 1000
long d1 = first.getTime() / oneDay
long d2 = second.getTime() / oneDay
d1 == d2
EDIT
I put the UTC thingy below in case you need to compare dates for a specific timezone other than UTC. If you do have such a need, though, then I really advise going for Joda.
long oneDay = 24 * 60 * 60 * 1000
long hoursFromUTC = -4 * 60 * 60 * 1000 // EST with Daylight Time Savings
long d1 = (first.getTime() + hoursFromUTC) / oneDay
long d2 = (second.getTime() + hoursFromUTC) / oneDay
d1 == d2
Already mentioned apache commons-utils:
org.apache.commons.lang.time.DateUtils.truncate(date, Calendar.DAY_OF_MONTH)
gives you Date object containing only date, without time, and you can compare it with Date.compareTo
If you're using Java 8, you should use the java.time.* classes to compare dates - it's preferred to the various java.util.* classes
eg; https://docs.oracle.com/javase/8/docs/api/java/time/LocalDate.html
LocalDate date1 = LocalDate.of(2016, 2, 14);
LocalDate date2 = LocalDate.of(2015, 5, 23);
date1.isAfter(date2);
I am afraid there is no method of comparing two dates that could be called "easy" or "simple".
When comparing two time instances with any sort of reduced precision (e.g. just comparing dates), you must always take into account how time zone affects the comparison.
If date1 is specifying an event that occurred in +2 timezone and date2 is specifying an event that occurred in EST, for example, you must take care to properly understand the implications of the comparison.
Is your purpose to figure out if the two events occurred in the same calendar date in their own respective time zones? Or do You need to know if the two dates fall into the same calendar date in a specific time zone (UTC or your local TZ, for example).
Once you figure out what it is actually that You are trying to compare, it is just a matter of getting the year-month-date triple in an appropriate time zone and do the comparison.
Joda time might make the actual comparison operation look much cleaner, but the semantics of the comparison are still something You need to figure out yourself.
Simply Check DAY_OF_YEAR in combination with YEAR property
boolean isSameDay =
firstCal.get(Calendar.YEAR) == secondCal.get(Calendar.YEAR) &&
firstCal.get(Calendar.DAY_OF_YEAR) == secondCal.get(Calendar.DAY_OF_YEAR)
EDIT:
Now we can use the power of Kotlin extension functions
fun Calendar.isSameDay(second: Calendar): Boolean {
return this[Calendar.YEAR] == second[Calendar.YEAR] && this[Calendar.DAY_OF_YEAR] == second[Calendar.DAY_OF_YEAR]
}
fun Calendar.compareDatesOnly(other: Calendar): Int {
return when {
isSameDay(other) -> 0
before(other) -> -1
else -> 1
}
}
If you just want to compare only two dates without time, then following code might help you:
final SimpleDateFormat dateFormat = new SimpleDateFormat("yyyyMMdd");
Date dLastUpdateDate = dateFormat.parse(20111116);
Date dCurrentDate = dateFormat.parse(dateFormat.format(new Date()));
if (dCurrentDate.after(dLastUpdateDate))
{
add your logic
}
I don't know it is new think or else, but i show you as i done
SimpleDateFormat dtf = new SimpleDateFormat("dd/MM/yyyy");
Date td_date = new Date();
String first_date = dtf.format(td_date); //First seted in String
String second_date = "30/11/2020"; //Second date you can set hear in String
String result = (first_date.equals(second_date)) ? "Yes, Its Equals":"No, It is not Equals";
System.out.println(result);
Here is a solution from this blog: http://brigitzblog.blogspot.com/2011/10/java-compare-dates.html
long milliseconds1 = calendar1.getTimeInMillis();
long milliseconds2 = calendar2.getTimeInMillis();
long diff = milliseconds2 - milliseconds1;
long diffDays = diff / (24 * 60 * 60 * 1000);
System.out.println("Time in days: " + diffDays + " days.");
i.e. you can see if the time difference in milliseconds is less than the length of one day.
`
SimpleDateFormat sdf= new SimpleDateFormat("MM/dd/yyyy")
Date date1=sdf.parse("03/25/2015");
Date currentDate= sdf.parse(sdf.format(new Date()));
return date1.compareTo(currentDate);
`
Using http://mvnrepository.com/artifact/commons-lang/commons-lang
Date date1 = new Date();
Date date2 = new Date();
if (DateUtils.truncatedCompareTo(date1, date2, Calendar.DAY_OF_MONTH) == 0)
// TRUE
else
// FALSE
In Java 8 you can use LocalDate which is very similar to the one from Joda Time.
public Date saveDateWithoutTime(Date date) {
Calendar calendar = Calendar.getInstance();
calendar.setTime( date );
calendar.set(Calendar.HOUR_OF_DAY, 0);
calendar.set(Calendar.HOUR, 0);
calendar.set(Calendar.MINUTE, 0);
calendar.set(Calendar.SECOND, 0);
calendar.set(Calendar.MILLISECOND, 0);
return calendar.getTime();
}
This will help you to compare dates without considering the time.
Using the getDateInstance of SimpleDateFormat, we can compare only two date object without time. Execute the below code.
public static void main(String[] args) {
Date date1 = new Date();
Date date2 = new Date();
DateFormat dfg = SimpleDateFormat.getDateInstance(DateFormat.DATE_FIELD);
String dateDtr1 = dfg.format(date1);
String dateDtr2 = dfg.format(date2);
System.out.println(dateDtr1+" : "+dateDtr2);
System.out.println(dateDtr1.equals(dateDtr2));
}
Another Simple compare method based on the answers here and my mentor guidance
public static int compare(Date d1, Date d2) {
Calendar c1 = Calendar.getInstance();
Calendar c2 = Calendar.getInstance();
c1.setTime(d1);
c1.set(Calendar.MILLISECOND, 0);
c1.set(Calendar.SECOND, 0);
c1.set(Calendar.MINUTE, 0);
c1.set(Calendar.HOUR_OF_DAY, 0);
c2.setTime(d2);
c2.set(Calendar.MILLISECOND, 0);
c2.set(Calendar.SECOND, 0);
c2.set(Calendar.MINUTE, 0);
c2.set(Calendar.HOUR_OF_DAY, 0);
return c1.getTime().compareTo(c2.getTime());
}
EDIT:
According to #Jonathan Drapeau, the code above fail some cases (I would like to see those cases, please) and he suggested the following as I understand:
public static int compare2(Date d1, Date d2) {
Calendar c1 = Calendar.getInstance();
Calendar c2 = Calendar.getInstance();
c1.clear();
c2.clear();
c1.set(Calendar.YEAR, d1.getYear());
c1.set(Calendar.MONTH, d1.getMonth());
c1.set(Calendar.DAY_OF_MONTH, d1.getDay());
c2.set(Calendar.YEAR, d2.getYear());
c2.set(Calendar.MONTH, d2.getMonth());
c2.set(Calendar.DAY_OF_MONTH, d2.getDay());
return c1.getTime().compareTo(c2.getTime());
}
Please notice that, the Date class is deprecated cause it was not amenable to internationalization. The Calendar class is used instead!
First, be aware that this operation depends on the time zone. So choose whether you want to do it in UTC, in the computer’s time zone, in your own favourite time zone or where. If you are not yet convinced it matters, see my example at the bottom of this answer.
Since your question isn’t quite clear about this, I am assuming that you have a class with an instance field representing a point in time and implementing Comparable, and you want the natural ordering of your objects to be by the date, but not the time, of that field. For example:
public class ArnesClass implements Comparable<ArnesClass> {
private static final ZoneId arnesTimeZone = ZoneId.systemDefault();
private Instant when;
#Override
public int compareTo(ArnesClass o) {
// question is what to put here
}
}
Java 8 java.time classes
I have taken the freedom of changing the type of your instance field from Date to Instant, the corresponding class in Java 8. I promise to return to the treatment of Date below. I have also added a time zone constant. You may set it to ZoneOffset.UTC or ZoneId.of("Europe/Stockholm") or what you find appropriate (setting it to a ZoneOffset works because ZoneOffset is a subclass of ZoneId).
I have chosen to show the solution using the Java 8 classes. You asked for the simplest way, right? :-) Here’s the compareTo method you asked for:
public int compareTo(ArnesClass o) {
LocalDate dateWithoutTime = when.atZone(arnesTimeZone).toLocalDate();
LocalDate otherDateWithoutTime = o.when.atZone(arnesTimeZone).toLocalDate();
return dateWithoutTime.compareTo(otherDateWithoutTime);
}
If you never need the time part of when, it is of course easier to declare when a LocalDate and skip all conversions. Then we don’t have to worry about the time zone anymore either.
Now suppose that for some reason you cannot declare your when field an Instant or you want to keep it an old-fashioned Date. If you can still use Java 8, just convert it to Instant, then do as before:
LocalDate dateWithoutTime = when.toInstant().atZone(arnesTimeZone).toLocalDate();
Similarly for o.when.
No Java 8?
If you cannot use java 8, there are two options:
Solve it using one of the old classes, either Calendar or SimpleDateFormat.
Use the backport of the Java 8 date and time classes to Java 6 and 7, then just do as above. I include a link at the bottom. Do not use JodaTime. JodaTime was probably a good suggestion when the answers recommending it were written; but JodaTime is now in maintenance mode, so the ThreeTen backport is a better and more futureproof option.
The old-fashioned ways
Adamski’s answer shows you how to strip the time part off a Date using the Calendar class. I suggest you use getInstance(TimeZone) to obtain the Calendar instance for the time zone you want. As an alternative you may use the idea from the second half of Jorn’s answer.
Using SimpleDateFormat is really an indirect way of using Calendar since a SimpleDateFormat contains a Calendar object. However, you may find it less troublesome than using Calendar directly:
private static final TimeZone arnesTimeZone = TimeZone.getTimeZone("Europe/Stockholm");
private static final DateFormat formatter = new SimpleDateFormat("yyyyMMdd");
static {
formatter.setTimeZone(arnesTimeZone);
}
private Date when;
#Override
public int compareTo(ArnesClass o) {
return formatter.format(when).compareTo(formatter.format(o.when));
}
This was inspired by Rob’s answer.
Time zone dependency
Why do we have to pick a specific time zone? Say that we want to compare two times that in UTC are March 24 0:00 (midnight) and 12:00 (noon). If you do that in CET (say, Europe/Paris), they are 1 am and 1 pm on March 24, that is, the same date. In New York (Eastern Daylight Time), they are 20:00 on March 23 and 8:00 on March 24, that is, not the same date. So it makes a difference which time zone you pick. If you just rely on the computer’s default, you may be in for surprises when someone tries to run your code on a computer in another place in this globalized world.
Link
Link to ThreeTen Backport, the backport of the Java 8 date and time classes to Java 6 and 7: http://www.threeten.org/threetenbp/.
My proposition:
Calendar cal = Calendar.getInstance();
cal.set(1999,10,01); // nov 1st, 1999
cal.set(Calendar.AM_PM,Calendar.AM);
cal.set(Calendar.HOUR,0);
cal.set(Calendar.MINUTE,0);
cal.set(Calendar.SECOND,0);
cal.set(Calendar.MILLISECOND,0);
// date column in the Thought table is of type sql date
Thought thought = thoughtDao.getThought(date, language);
Assert.assertEquals(cal.getTime(), thought.getDate());
Using Apache commons you can do:
import org.apache.commons.lang3.time.DateUtils
DateUtils.truncatedEquals(first, second, Calendar.DAY_OF_MONTH)
public static Date getZeroTimeDate(Date fecha) {
Date res = fecha;
Calendar calendar = Calendar.getInstance();
calendar.setTime( fecha );
calendar.set(Calendar.HOUR_OF_DAY, 0);
calendar.set(Calendar.MINUTE, 0);
calendar.set(Calendar.SECOND, 0);
calendar.set(Calendar.MILLISECOND, 0);
res = calendar.getTime();
return res;
}
Date currentDate = getZeroTimeDate(new Date());// get current date
this is the simplest way to solve this problem.
I solved this by comparing by timestamp:
Calendar last = Calendar.getInstance();
last.setTimeInMillis(firstTimeInMillis);
Calendar current = Calendar.getInstance();
if (last.get(Calendar.DAY_OF_MONTH) != current.get(Calendar.DAY_OF_MONTH)) {
//not the same day
}
I avoid to use Joda Time because on Android uses a huge space. Size matters. ;)
Another solution using Java 8 and Instant, is using the truncatedTo method
Returns a copy of this Instant truncated to the specified unit.
Example:
#Test
public void dateTruncate() throws InterruptedException {
Instant now = Instant.now();
Thread.sleep(1000*5);
Instant later = Instant.now();
assertThat(now, not(equalTo(later)));
assertThat(now.truncatedTo(ChronoUnit.DAYS), equalTo(later.truncatedTo(ChronoUnit.DAYS)));
}
// Create one day 00:00:00 calendar
int oneDayTimeStamp = 1523017440;
Calendar oneDayCal = Calendar.getInstance();
oneDayCal.setTimeInMillis(oneDayTimeStamp * 1000L);
oneDayCal.set(Calendar.HOUR_OF_DAY, 0);
oneDayCal.set(Calendar.MINUTE, 0);
oneDayCal.set(Calendar.SECOND, 0);
oneDayCal.set(Calendar.MILLISECOND, 0);
// Create current day 00:00:00 calendar
Calendar currentCal = Calendar.getInstance();
currentCal.set(Calendar.HOUR_OF_DAY, 0);
currentCal.set(Calendar.MINUTE, 0);
currentCal.set(Calendar.SECOND, 0);
currentCal.set(Calendar.MILLISECOND, 0);
if (oneDayCal.compareTo(currentCal) == 0) {
// Same day (excluding time)
}
If you strictly want to use Date ( java.util.Date ), or without any use of external Library. Use this :
public Boolean compareDateWithoutTime(Date d1, Date d2) {
SimpleDateFormat sdf = new SimpleDateFormat("yyyyMMdd");
return sdf.format(d1).equals(sdf.format(d2));
}
Date today = new Date();
Date endDate = new Date();//this
endDate.setTime(endDate.getTime() - ((endDate.getHours()*60*60*1000) + (endDate.getMinutes()*60*1000) + (endDate.getSeconds()*1000)));
today.setTime(today.getTime() - ((today.getHours()*60*60*1000) + (today.getMinutes()*60*1000) + (today.getSeconds()*1000)));
System.out.println(endDate.compareTo(today) <= 0);
I am simply setting hours/minutes/second to 0 so no issue with the time as time will be same now for both dates. now you simply use compareTo. This method helped to find "if dueDate is today" where true means Yes.