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Spring-Data Jpa Inheritance: Keeping Entity Id's in Children Entity

I'm dealing with a couple of Entities with Tree like structures that were getting more complicated so I decided to create an abstract class for it so code was a bit more mainainable:
#Entity
#Inheritance(strategy = InheritanceType.TABLE_PER_CLASS)
public abstract class TreeStructure<T extends TreeStructure>
{
#ManyToOne
protected T parent;
#OneToMany(mappedBy = "parent", fetch = FetchType.LAZY)
protected Set<T> children = new HashSet<>();
//...
Then I have two Entities which extend it:
#Entity(name = "TreeStructureOne")
public class TreeStructureOne extends TreeStructure<TreeStructureOne>
{
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#JsonProperty("TreeStructureOne_id")
private long id;
And I basically want the database to be completely unaware of this TreeStructure abstraction and save all of the fields in each Entities tableand expected InheritanceType.TABLE_PER_CLASS to deal with that. But it seems I need to define the Id in the TreeStructure Entity at least or I get:
Invocation of init method failed; nested exception is org.hibernate.AnnotationException: No identifier specified for entity: TreeStructure
And I don't want to add an ID into the abstract class since this makes three tables in the database called: HT_TREE_STRUCTURE, HT_TREE_STRUCTURE_ONE and HT_TREE_STRUCTURE_TWO with one field ID each one.
Is there any solution to that?

Since TreeStructure is not an #Entity use only #MappedSuperclass
#MappedSuperclass
public abstract class TreeStructure<T extends TreeStructure> {
instead of #Entity and #Inheritance for the parent class.
You can find #MappedSuperclass in the Oracle JEE API documentation.

JPA OneToMany Association from superClass

I’m trying to map the inheritance from the superclass LendingLine and the subclasses Line and BlockLine. LendingLine has an ManyToOne association with Lending.
When I try to get the LendingLines from the database without the inheritance it works fine. The association works also. But when i add the inheritance, lendingLines in Lending is empty. I also can't get any LendingLines from the DB with the inheritance.
Can anybody help me?
(Sorry for the bad explanation)
Thanks in advance!
LendingLine:
#Entity
#Inheritance(strategy=InheritanceType.SINGLE_TABLE)
#DiscriminatorColumn(name="TYPE")
#DiscriminatorValue(value="Line")
#Table(name = "LendingLine")
public class LendingLine {
...
public LendingLine(){}
#ManyToOne(cascade = CascadeType.ALL,fetch = FetchType.EAGER, targetEntity=Lending.class)
#JoinColumn(name = "LendingId")
private Lending lending;
...
Lending:
#Entity
#Table(name = "Lending")
public class Lending {
...
public Lending(){}
#OneToMany(cascade = CascadeType.ALL,fetch = FetchType.EAGER, mappedBy = "lending")
private List<LendingLine> lendingLines;
...
BlockDate:
#Entity
#DiscriminatorValue(value = "BlockLine")
public class BlockLine extends LendingLine {
public BlockLine(){
}
}
LendingLineRepository:
This class only reads from the db because the db was created by another application ( C#) where the objects are added to the db.
public class LendingLineRepository extends JpaUtil implement LendingLineRepositoryInterface {
#Override
protected Class getEntity() {
return LendingLine.class;
}
#Override
public Collection<LendingLine> findAll() {
Query query = getEm().createQuery("SELECT l FROM LendingLine l");
System.out.println(query.getResultList().size());
return (Collection<LendingLine>) query.getResultList();
}
Table LendingLine:

Choose your type of superclass according to your needs:
Concrete Class
public class SomeClass {}
Define your superclass as a concrete class, when you want to query it and when you use a new operator for further logic. You will always be able to persist it directly. In the discriminator column this entity has it's own name. When querying it, it returns just instances of itself and no subclasses.
Abstract Class
public abstract class SomeClass {}
Define your superclass as an abstract class when you want to query it, but don't actually use a new operator, because all logic handled is done by it's subclasses. Those classes are usually persisted by its subclasses but can still be persisted directly. U can predefine abstract methods which any subclass will have to implement (almost like an interface). In the discriminator column this entity won't have a name. When querying it, it returns itself with all subclasses, but without the additional defined information of those.
MappedSuperclass
#MappedSuperclass
public abstract class SomeClass {}
A superclass with the interface #MappedSuperclass cannot be queried. It provides predefined logic to all it's subclasses. This acts just like an interface. You won't be able to persist a mapped superclass.
For further information: JavaEE 7 - Entity Inheritance Tutorial
Original message
Your SuperClass LendingLine needs to define a #DiscriminatorValue as well, since it can be instantiated and u use an existing db-sheme, where this should be defined.

Map Collection of Interface using annotation in Hibernate

I have an interface called Rule with 2 implementing classes who all share one Abstract base class.
#MappedSuperclass
public interface Rule { .. }
#Entity
#Inheritance(strategy = InheritanceType.TABLE_PER_CLASS)
public abstract class BaseRule implements Rule {
#Entity
public class ImlementingRule1 extends BaseRule {
#Entity
public class ImlementingRule1 extends BaseRule {
I'm using this Rule interface in a containgRules class as such:
#OneToMany
#JoinColumn(name = "RULES_ID")
private List<Rule> rules;
Whatever setup I try I always end up with:
Caused by: org.hibernate.MappingException: Cannot use identity column key generation with <union-subclass> mapping for: mynamespace.BaseRule

I personally have found no other solution than to use the abstract base class, instead of interface.
#OneToMany
#JoinColumn(name = "RULES_ID")
private List<BaseRule> rules;
It states right here:
Annotating interfaces is currently not supported.

Mapping Multiple Classes to a Table in Hibernate, Without a DTYPE Column

I have two hibernate classes: a base class, and an extended class that has additional fields. (These fields are mapped by other tables.)
For example, I have:
#Entity
#Table(name="Book")
public class A {
private String ID;
private String Name;
// ...
}
#Entity
#Table(name="Book")
public class B extends A {
public String node_ID;
// ...
}
public class Node {
public String ID; // maps to B.node_ID
// ...
}
How do I map this in Hibernate? The hibernate documentation states three types of inheritence configurations: one table per class, one table with a type column, and a join table -- none of which apply here.
The reason I need to do this is because class A is from generic framework that's reused over multiple projects, and class B (and Node) are extensions specific to one project -- they won't be used again. In the future, I may have perhaps a class C with a house_ID or some other field.
Edit: If I try the above pseudo-code configuration (two entities mapped to the same table) I get an error that the DTYPE column doesn't exist. The HQL has a "where DTYPE="A" appended.

This is possible by mapping the #DiscriminatorColumn and #DiscriminatorValue to the same values for both classes; this can be from any column you use that has the same data regardless of which type (not sure if it works with null values).
The classes should look like so:
#Entity
#Table(name="Book")
#Inheritance(strategy=InheritanceType.SINGLE_TABLE)
#DiscriminatorColumn(name="published")
#DiscriminatorValue(value="true")
public class A {
private String ID;
private String Name;
// ...
}
#Entity
#Table(name="Book")
#DiscriminatorValue(value="true")
public class B extends A {
public String node_ID;
// ...
}

For anyone who got here like me and does not want to have the dtype column but instead want to use the same table for more than one entity as is I would recommend using this
Basically you can create a Base like this
#MappedSuperclass
public abstract class BaseBook<T extends BaseBook> {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "id", nullable = false)
private Long id;
... any other variables, getters + setters
}
#Entity
#Table(name= "book")
public class BookA extends BaseBook<BookA>{
//Default class no need to specify any variables or getters/setters
}
#Entity
#Table(name= "book")
public class BookB extends BaseBook<BookB>{
#Column(name = "other_field")
private String otherFieldInTableButNotMapedInBase
... Any other fields, getter/setter
}
From the above we have created base super class which does not have any entity or table mapping. We then create BookA to be default with the Entity + Table mapping. From there we can create other Entities all extending from BaseBook but pointing to one table

Hibernate Mapped Superclass relationships and overriding

I have an abstract MappedSuperClass, Participant, which is extended by three kinds of 'Participant'. Each one then uses its own kind of 'Project', also an abstract MappedSuperClass. However, I want the base class to know about Projects so I can write generic code to interact with Participants. How do I specify this using Hibernate annotations? and how will I override it in the ExtendedParticipant and ExtendedProject classes?
Each Participant type, and each Project type, have their own database tables with existing data and ids (not unique across tables) that I cannot change.
The following code gives me the IDE error "Many to one attribute should not be 'Mapped Superclass'".
#MappedSuperclass
public abstract class Participant implements Persistable {
...
#ManyToOne
#JoinColumn(name = "project_id")
public Project getProject() {
return project;
}
public void setProject(Project project) {
this.project = project;
}
...
}
and the Project class is much the same with the same problem:
#MappedSuperclass
public abstract class Project implements Persistable {
...
#OneToMany
public List<Participant> getParticipants() {
return participants;
}
public void setProject(List<Participant> participants) {
this.participants = participants;
}
...
}

A mapped superclass is not an Entity, it can't be part of an association. So map your classes as entities and either introduce a mapped superclass "above" them or use a TABLE_PER_CLASS strategy.
See also
EclipseLink: Query to MappedSuperclass fails
Hibernate - Persisting polymorphic joins

Seems possible to have relations defined through the mappedsuperclass
according to the following
jboss_docs
another_stackoverflow_thread
object_db_doc

Docs said it's possible, but superclass isn't abstract in example
https://docs.oracle.com/javaee/5/api/javax/persistence/MappedSuperclass.html