I apparently doing something wrong in the configuration of a jdbcRealm. But I don't know what exactly.
This is my configuration:
What else is needed to help me?
#Entity
#Table(name = "gebruiker")
public class User implements Serializable {
#Id #Column(name="User_NAME")
private String name;
#ManyToOne
#JoinTable(name = "groep_gebruiker")
private Role rol;
#Entity
#Table(name = "groep")
public class Role implements Serializable {
#Id
private String rol;
#OneToMany(mappedBy = "rol")
private Collection<User> gebruikers = new ArrayList();
Obviously this is because you did not create a JDBC realm user /Hans/
Related
I'm using a JPARepository called PublicationRepository and want to find all Publications from a certain Person. This Classes are connected over the Class Author.
Person Class:
#Entity
public class Person {
#Id
private String email;
private String telefon;
private String password;
#OneToMany(mappedBy = "person")
Set<Author> Author;
}
Author Class:
#Entity
#Data
#NoArgsConstructor
#AllArgsConstructor
public class Author {
#Id
private int id;
#ManyToOne
#JoinColumn(name="Person_ID")
Person person;
#ManyToOne
#JoinColumn(name="Publication_ID")
Publication publication;
private String Date;
private String Writerstatus;
}
Publication Class
#Entity
#AllArgsConstructor
#NoArgsConstructor
#Data
public class Publication {
#Id
private int id;
private String publicationname;
#OneToMany(mappedBy = "publication")
Set<Author> author;
}
And the PublicationRepository
public interface ProjektRepository extends JpaRepository<Projekt,Integer> {
}
public interface PublicationRepository extends JpaRepository<Publication,Integer> {
#Query(value = "SELECT pub.* FROM author as auth INNER JOIN publications as pub ON auth.publication_id = pub.id WHERE auth.person_id = ?1", native = true)
List<Publication> findAllPublicationsOfThisPerson(int personId);
}
Try this.
I would also recommend to annotate the entities with their table names:
#Table(name = "publication")
You use a manually build table for a Many-to-Many relationship Author
You could also delegate that to Spring Data Jpa by using #ManyToMany Annotation.
A good tutorial:
https://attacomsian.com/blog/spring-data-jpa-many-to-many-mapping
I've a User and Contact entities in my app and I need to every user can add some private comment about every contact and that comment must be available only for that user. So I create new entity - PrivateInfo. Here's the code.
User class:
#Entity
#Table(name = "users")
#XmlAccessorType(XmlAccessType.FIELD)
public class User implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private long id;
private String login;
// other fields
}
Contact class:
#Entity
#Table(name = "contacts")
#XmlAccessorType(XmlAccessType.FIELD)
public class Contact implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private long id;
#Column(name = "first_name")
private String firstName;
#Column(name = "last_name")
private String lastName;
#OneToMany(fetch = LAZY, cascade = ALL, mappedBy = "contact")
private Set<PrivateInfo> privateInfo;
// etc.
}
PrivateInfo class:
#Entity
#Table(name = "private_info")
#XmlAccessorType(XmlAccessType.FIELD)
public class PrivateInfo implements Serializable {
#EmbeddedId
private PrivateInfoKey pk;
#Column(name = "additional_info")
private String additionalInfo;
#ManyToOne(fetch = FetchType.EAGER)
#MapsId("contactId")
private Contact contact;
}
#Embeddable
public class PrivateInfoKey implements Serializable {
#Column(name = "contact_id")
private Long contactId;
#Column(name = "user_id")
private Long userId;
}
I'm using Spring Data repositories with JpaSpecificationExecutor for querying so here's my attempt to write specification for getting all contacts with private info for specific user.
public static Specification<Contact> withPrivateInfo(final long userId) {
return new Specification<Contact>() {
#Override
public Predicate toPredicate(Root<Contact> root, CriteriaQuery<?> query, CriteriaBuilder cb) {
Join<Contact, PrivateInfo> joinPrivateInfo = root.join(Contact_.privateInfo, JoinType.LEFT);
joinPrivateInfo.on(cb.equal(
joinPrivateInfo.get(PrivateInfo_.pk).get(PrivateInfoKey_.userId), userId
));
return cb.conjunction(); // translates in sql like '... where 1 = 1'
}
};
}
However, when I call
contactRepository.findAll(withPrivateInfo(1));
I'm receiving contacts and each of them contains in privateInfo field all users information about this contact (not only for user with id = 1, as expected). Seems like join on condition ignored.
Any suggestions how to achieve my goal? Maybe with another entities structure. Is this possible with JPA/Criteria?
I have an issue with the JPA relationship within a MVC SpringBoot application.
I'm trying to create an application where I have a number of users and every user can have a number of cars. A user can have multiple cars. I've done a #OneToOne relationship between the user and the car object, here's what I've done:
here is the User class:
#Entity
#Table(name = "user")
public class User implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
#Column(name = "username", nullable = false)
private String username;
#Column(name = "password", length = 500, nullable = false)
private String password;
#OneToMany(mappedBy = "user", cascade = CascadeType.ALL)
private List<Car> cars;
}
then here is the Car class:
#Entity
#Table(name = "car")
public class Car implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#Column(length = 11)
#GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
#Column(name = "make", nullable = false)
private String make;
#Column(name = "model", nullable = false)
private String model;
#ManyToOne(fetch = FetchType.LAZY, cascade = CascadeType.ALL)
#JoinColumn(name = "id")
private User user;
}
Then, here is the actual service implementation
#Component
#Transactional(readOnly = true)
public class CarServiceImpl implements CarService {
#Inject
private CarRepository carRepository;
#Inject
private UserRepository userRepository;
#Override
#Transactional(readOnly = false)
public Car addCar(Long userId, Car car) {
User user = userRepository.findOne(userId);
user.getGpsLocationModels().add(car);
car.setUser(user);
carRepository.save(car);
return car;
}
then I have the endpoint but that works fully. The add method looks like does work as supposed to, at least I get the expected output, however the find method I have no idea how to write it, well can't figure it out how to retrieve cars based on user, I know how to get them by their ID but not for every user separately.
Here is my try:
#Override
public Car findCar(Long userId, Long carId) {
//get the current user (that comes as JSON Request Param)
User user = userRepository.findOne(userId);
//get the car based on its ID, here's the problem, I want the car based on its ID AND its user, I can't display cars which aren't for that particular user
Car car = carRepository.findOne(carId);
return car;
}
Here is the method for get all cars for a particular user:
#Override
public List<Car> displayAllCars(Long userId) {
return userRepository.findOne(userId).getCars();
}
I'd really appreciate any help that you could advise.
Thank you so much
Your mappings are incorrect. Car > User is #ManyToOne. If you also make this bi-directional you can also then retrieve the cars via the user:
#Entity
#Table(name = "user")
public class User implements Serializable {
#OneToMany(mappedBy ="user",cascade = CascadeType.ALL)
private Set<Car> cars;
public Set<Car> getCars(){
return cars;
}
public void addCar(Car car){
cars.add(car);
car.setUser(this);
}
}
#Entity
#Table(name = "car")
public class Car implements Serializable {
#ManyToOne(fetch=FetchType.LAZY, cascade = CascadeType.ALL)
#JoinColumn(name="user_id")
private User user;
}
#Override
public Set<Car> findCars(Long userId) {
return userRepository.findOne(userId).getCars();
}
You could have a method that accepts the user ID and returns the list in the car repository like:
List<Car> findCarByUser(Long userID);
And then you will have
#Override
public List<Car> displayAllCars(Long userId) {
return carRepository.findCarByUser(userId);
}
Class has property that can be one of two class-types, that's why I try to create interface that class-types implement
#Entity
#Table(name = "users")
public class User{
#Id
#Column(name="id")
#GeneratedValue(strategy=GenerationType.AUTO)
private Long userID;
#Column(name="email")
private String email;
#OneToOne(mappedBy = "user")
private Login login;
... getters/setters
#MappedSuperclass
public interface Login {
User user = new User();
}
#Entity
#Table(name = "user_logins_social")
#IdClass(UserLoginSocialID.class)
public class UserLoginSocial implements Login{
#OneToOne
#JoinColumn(name="uid")
private User user;
...
#Entity
#Table(name = "user_logins_native")
public class UserLoginNative implements Login{
#OneToOne
#JoinColumn(name="uid")
private User user;
...
So I can't use target entity because both classes can be used. Here is error stack: org.hibernate.AnnotationException: Unknown mappedBy in: model.User.login, referenced property unknown: model.Login.user. Help me please
Cannot map or query on an inferface.
#MappedSuperclass should be able to use abstract class and class.
Please check: wikihttp://en.wikibooks.org/wiki/Java_Persistence/Advanced_Topics#Interfaces
#MappedSuperclass
public abstract class User{
#Id
#Column(name="id")
#GeneratedValue(strategy=GenerationType.AUTO)
private Long userID;
#Column(name="email")
private String email;
#OneToOne(mappedBy = "user")
private Login login;
// ... getters/setters
#Entity
#Table(name = "login")
public class Login{
#OneToOne
private User user;
}
#Entity
#Table(name = "user_logins_social")
#IdClass(UserLoginSocialID.class)
public class UserLoginSocial extends User{
//...
}
#Entity
#Table(name = "user_logins_native")
public class UserLoginNative extends User{
//...
}
I have 3 tables, each mapped to an entity. The entities are something like this:
#Entity
#Table(name = "person")
public class Person implements Serializable {
private int id;
//other fields
}
#Entity
#Table(name = "phone")
public class Phone implements Serializable {
private int id;
private Long price;
#ManyToOne
#JoinColumn(name = "personId")
private Person person;
#ManyToOne
#JoinColumn(name = "manufacturerId")
private Manufacturer manufacturer;
//other fields
}
#Entity
#Table(name = "manufacturer")
public class Manufacturer implements Serializable {
private int id;
private String name;
//other fields
}
What I want to do is to create a method that will return a list of Persons that have phones from a specified manufacturer with the price in a specified range.
EDIT: My dao class implements EntityJpaDao . I would need a solution that would work with this implementation.
Following query will return the Samsung mobile users with phone price range.
Criteria criteria = session.createCriteria(Phone.class, "phone");
criteria.createAlias("phone.person", "person")
criteria.add(Restrictions.between("phone.price", minPrice, maxPrice));
criteria.createAlias("phone.manufacturer","manufacturer");
criteria.add(Restrictions.eq("manufacturer.name", Samsung));
criteria.setProjection(Projections.property("person"));
List<Person> persons = criteria.list();