I'm having a problem in parsing a date. I'm new on android and try to search for the solution but it seems no luck. I'd already tried to follow this one http://developer.android.com/reference/java/text/SimpleDateFormat.html but still got an error.
please help me..
I try to parse this date 2014-03-18T02:07:35.742-0400 and try to format to this 03/18/2014 02:07
I got this error:
java.lang.IllegalArgumentException
at java.text.DateFormat.format(DateFormat.java:361)
at java.text.Format.format(Format.java:93)
Try something like this:
Date date = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSZ").parse("2014-03-18T02:07:35.742-0400");
System.out.println(new SimpleDateFormat("MM/dd/yyyy HH:mm").format(date));
For my time zone prints:
03/18/2014 10:07
private final DateFormat parsedFormat = new SimpleDateFormat("MM/dd/yyyy HH:mm", Locale.getDefault());
private final DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSZ", Locale.getDefault());
Date date = dateFormat.parse(dateFormat.format(your_date));
Date parsedDate = parsedFormat.parse(parsedFormat.format(date));
Reference
use following code
try{
String srcDate = new String("2014-03-18T02:07:35.742-0400");
SimpleDateFormat srcDf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSZ");
SimpleDateFormat destDf = new SimpleDateFormat("yyyy/MM/dd");
Date date = srcDf.parse(srcDate);
// format the date into another format
dateStr = destDf.format(date);
}catch (ParseException e) {
// TODO: handle exception
}
Related
I have this string: 2018-09-22 10:17:24.772000
I want to convert it to Date:
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSSSSS");
String sdate = "2018-09-22 10:17:24.772000";
Date dateFrom = simpleDateFormat.parse(sdate);
but it shows: Sat Sep 22 10:17:24 GMT+03:30 2018
Here is what you should do instead, you are printing date object itself, you should print its format.
I will provide the code with old date api and new local date api :
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSSSSS");
String sdate = "2018-09-22 10:17:24.772000";
Date dateFrom = simpleDateFormat.parse(sdate);
System.out.println(dateFrom); // this is what you do
System.out.println(simpleDateFormat.format(dateFrom)); // this is what you should do
// below is from new java.time package
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss.SSSSSS");
System.out.println(LocalDateTime.parse(sdate, formatter).format(formatter));
output is :
Sat Sep 22 10:30:16 EET 2018
2018-09-22 10:30:16.000000
2018-09-22 10:17:24.772000
Hope This will help you
public class Utils {
public static void main(String[] args) {
String mytime="2018-09-22 10:17:24.772000";
SimpleDateFormat dateFormat = new SimpleDateFormat(
"yyyy-MM-dd HH:mm:ss.SSSSSS");
Date myDate = null;
try {
myDate = dateFormat.parse(mytime);
} catch (ParseException e) {
e.printStackTrace();
}
SimpleDateFormat timeFormat = new SimpleDateFormat("yyyy-MM-dd");
String finalDate = timeFormat.format(myDate);
System.out.println(finalDate);
}
}
Looks to me like you have converted it to a Date. What is your desired result? I suspect what you are wanting to do is to create another Simple date format that shows your expected format and then use simpledateformat2.format(dateFrom)
I should also point out based on past experience that you should add a Locale to your simple date formats otherwise a device with a different language setting may not be able to execute this code
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSSSSS", Locale.US);
I'm trying to create a Date from a String I receive from the server. The String is:
2018-05-23T06:39:37+0000
So the correct format should be:
yyyy-MM-dd'T'HH:mm:ss.SSSZ
Here is my code:
String createdDate = comment.getCreatedDateTime();
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSZ", Locale.US);
try {
Date parsedDate = simpleDateFormat.parse(createdDate);
createdDate = parsedDate.toString();
} catch (ParseException ex) {
ex.printStackTrace();
}
mCommentDate.setText(createdDate);
I don't know if there is any way to do this, because after that I would like to parse again to the next format:
dd/MM/yyyy hh:mm
I've tried to parse the original String using this last format directly but I'm getting the same exception.
Any suggestion?
I see you've solved your own problem with a little help from the comments, however I would suggest you seriously consider LocalDate, as the older Date classes are quite troublesome at times.
In fact, as your incoming value has a TimeZone, you'll need to use ZonedDateTime to parse your input.
String createdDate = "2018-05-23T06:39:37+0000";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ssZ");
ZonedDateTime localDate = ZonedDateTime.parse(createdDate, formatter);
System.out.println(localDate.format(DateTimeFormatter.ofPattern("dd/MM/yyyy HH:mm")));
Output:
23/05/2018 06:39
The given input date String format
2018-05-23T06:39:37+0000
is incorrect so that you are getting ParseException since millisecond(SSS) part is missing from your date format yyyy-MM-dd'T'HH:mm:ss.SSSZ
So please try with
2018-05-23T06:39:37.235-0530
so below code should work
String createdDate = comment.getCreatedDateTime();
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSZ", Locale.US);
try {
Date parsedDate = simpleDateFormat.parse(createdDate);
createdDate = parsedDate.toString();
System.out.println(parsedDate.toString());
} catch (ParseException ex) {
ex.printStackTrace();
}
mCommentDate.setText(createdDate);
Ok, the first mistake (as you've pointed) is I didn't have milliseconds on the original String.
After removing "SSS" from the simpleDateFormat it works like a charm. So this is the final code:
String createdDate = comment.getCreatedDateTime();
SimpleDateFormat defaultDateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZ", Locale.getDefault());
try {
Date parsedDate = defaultDateFormat.parse(createdDate);
SimpleDateFormat finalDateFormat = new SimpleDateFormat("dd/MM/yyyy HH:mm", Locale.getDefault());
createdDate = finalDateFormat.format(parsedDate);
} catch (ParseException ex) {
ex.printStackTrace();
}
mCommentDate.setText(createdDate);
I have this:
DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'Z'");
Date result = dateFormat.parse(this.getCreatedTime());
Basically I want to convert a string like "2016-09-27T09:19:57Z" into something like "September 27, 2016 at 9:19 AM".
If I use the code above I end up with a Date object, but all the methods are deprecated. So how do I achieve this?
You can use DateFormat again as #Thomas wrote:
DateFormat inputFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'Z'");
Date inputDate = inputFormat.parse(this.getCreatedTime());
DateFormat outputFormat = new SimpleDateFormat("outputFormat");
String output = outputFormat.format(inputDate);
You should do research before posting any question here.
Use this to get Date from your required pattern
SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'", Locale.getDefault());
Date date = null;
try {
date = format.parse(unformattedDate);
} catch (ParseException e) {
e.printStackTrace();
}
Make new instance of your desired patter.
format = new SimpleDateFormat("MMMM dd, yyyy 'at' HH:mm a", Locale.getDefault());
String formattedDate = format.format(date);
I've received this start_time from my facebook query:
2013-05-30T19:30:00+0300
how can i parse it to Date in Android ?
I've tried this:
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss' '");
Use yyyy-MM-dd'T'HH:mm:ssZ format as below...
String dateString = "2013-05-30T19:30:00+0300";
SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZ");
Date date = dateFormat.parse(dateString);
dateFormat = new SimpleDateFormat("yyyy-MM-dd hh:mm");
String formatedDate = dateFormat.format(date);
Log.d("Date", formatedDate);
Output:
03-10 18:29:47.074: D/Date(27257): 2013-05-30 10:30
Try out this link:
https://stackoverflow.com/a/13607418/3110609
You need to use SimpleDateFormat but need to manage correctly
In PHP to convert a string to DateTime() its very very easy:
$dateTime = new DateTime("2013-12-11 10:109:08");
echo $dateTime->format("d/m/Y"); // output 11/12/2013
What is the equivalent in Java? I've seen a lot of questions in stackoverflow. I cant find a way to solve this problem.
My last try is:
SimpleDateFormat dateFormat = new SimpleDateFormat("HH:mm", Locale.ITALIAN);
return dateFormat.format(new Date(datetime)).toString();
This crash application. Android Studio tells me that Date(java.lang.String) is deprecated.
Can someone help me?
// First convert the String to a Date
String dateTime = "2013-11-12 13:14:15";
SimpleDateFormat dateParser = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss",Locale.ITALIAN);
Date date = dateParser.parse(dateTime);
// Then convert the Date to a String, formatted as you dd/MM/yyyy
SimpleDateFormat dateFormatter = new SimpleDateFormat("dd/MM/yyyy");
System.out.println(dateFormatter.format(date));
You can let the parser / formatter take the timezone into account by using SimpleDateFromat.setTimeZone() if you have to deal with TimeZones that are not in your default locale.
try this
String time1="";
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss,SSS",Locale.US);
GregorianCalendar calendar = new GregorianCalendar(TimeZone.getTimeZone("US/Central"));
calendar.setTimeInMillis(yourmilliseconds);
time1=sdf.format(calendar.getTime());
Yes As of JDK version 1.1, Date(java.lang.String) is deprecated and replaced by DateFormat.parse(String s).
Parse it like that:
SimpleDateFormat formatter =
new SimpleDateFormat("dd.MM.yyyy", Locale.GERMANY);
Calendar date = Calendar.getInstance();
try {
date.setTime(formatter.parse("12.12.2010"));
} catch (ParseException e) {
e.printStackTrace();
}
Have a look at my Android date picker example here.