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Hibernate + JPA does not find the column for an #ElementCollection table

I am trying to add an #ElementCollection but the column is not found after the setup, so I constantly receive an error. I use Spring + flyway for the set up. Everything happens in the public schema
So here is my big object:
#Entity
#Table(name = "my_big_table")
MyBigObject{
#Id
#Column(name=COL_ID)
#GeneratedValue(generator="gen_name")
#GenericGenerator(
name = "gen_name",
strategy = "seq_name"
)
#AttributeAccessor(CommonConstants.HIBERNATE_ACCESS_PROPERTY)
private long id;
...
...
#ElementCollection(fetch = FetchType.EAGER)
#CollectionTable(
name = "my_small_table",
joinColumns = #JoinColumn(name = "big_object_id")
)
private List<MySmallObject> mySmallObjects;
}
Here is my embedded object:
#Embeddable
public class MySmallObject {
#Column(name = "small_object_type")
private String smallObjectType;
}
Then besides the existing my_big_table table I add my_small_table using flyway
create table if not exists my_small_table
(
big_object_id bigint not null,
small_object_type varchar(64) not null
);
alter table my_small_table
add constraint FK_my_small_table
foreign key (big_object_id)
references my_big_table (id);
After this the my_small_table is successfully created but any instance of MyBigObject cannot be found because it looks for a column in the my_small_table that does not exist. As you can see it does not understand that the column name should use an underscore.
Big error trace ands with the following message:
Caused by: org.postgresql.util.PSQLException: ERROR: column mysmalltab0_.smallobjecttype does
not exist
09:17:24.994 INFO - STDOUT: Hint: Perhaps you meant to reference the column "mysmalltab0_.smallobjecttype".
Do you know what I could forget? Could lombock annotations that I also use for both classes spoil the picture?

As it's stated in the documentation:
By default, the placement of the #Id annotation gives the default access strategy. When placed on a field, Hibernate will assume field-based access. When placed on the identifier getter, Hibernate will use property-based access.
But the usage of the #AttributeAccessor leads to the changing access strategy for the field that hold #Id and as result your #Column(name = "small_object_type") annotation just was ignored. You can try to put it on the appropriate getter and it should work. But it's considered a good practiсe not to mix up access strategies for the entity fields.

Spring Boot joining two entities with invalid FK entries

I am mapping some Java classes using hibernate on a database that I have no write access for. One of the fields used as a FK between ClientEpisodes and Physician's has 6 rows that contain a -1 for the FK. THis is obviously an invalid FK, but I need to still join and simply ignore these Physicians and have a null physician.
I am joining the class using
#JoinColumn(name = "epi_phid1", referencedColumnName = "ph_id", foreignKey = #ForeignKey(ConstraintMode.NO_CONSTRAINT))
private Physician physician;
I tried specifying NO_CONSTRAINT to see if it would ignore it then, but even still I get the following error:
javax.persistence.EntityNotFoundException: Unable to find private.package.info.Physician with id -1
Is there any way to tell Hibernate to ignore values that aren't valid such as the -1?

The #ForeignKey annotation with NO_CONSTRAINT value tells hibernate to not generate foreign keys, if schema generation is used. It doesn't have any effect on the internal entity validation in the JPA framework.
There is a hibernate specific #NotFound annotation which you could use:
#JoinColumn(name = "epi_phid1", referencedColumnName = "ph_id")
#NotFound(action = NotFoundAction.IGNORE)
private Physician physician;
However be advised that if you use this in a #OneToMany or #ManyToMany annotation which maps a Collection, hibernate will fill the invalid/missing entities with null (so the list will contain null value(s)).

JPA secondary table as read only view - hibernate still tries to insert rows

I've got the following entity:
#Entity
#Table(name = "ONE")
#SecondaryTable(name = "VIEW_TWO", pkJoinColumns = #PrimaryKeyJoinColumn(name="ONE_ID"))
public class CpBracket {
#Id
private Long id;
#Column(name="progress", table="VIEW_TWO", updatable = false, insertable = false)
private int progress = 0;
(...)
}
As you see, this entity uses table ONE and (read only) view VIEW_TWO. When I'm persisting the entity, hibernate is performing insert into view:
insert into VIEW_TWO (ONE_ID) values (?)
It is ignoring the non-updatable and non-insertable column progress (that's good) and it is still trying to insert value of ONE_ID column. As far as I know, the annotation #PrimaryKeyJoinColumn marks selected column as insertable=false and updatable=false.
How can I prevent hibernate from inserting rows into secondary table (view)?

As far as I know, the annotation #PrimaryKeyJoinColumn marks selected
column as insertable=false and updatable=false.
I do not believe this can be the case: how then do we get records inserted into the #SecondaryTable when it is an actual table rather than a view?
As neither #SecondaryTable or #PrimarykeyJoinColumn have a means to prevent insert then it would appear that your original solution is not going to work and an alternative is required.
One option is to map VIEW_TWO as an #Entity and link to your class CPBracket as a #OneToOne relationship with cascade options set to none.
#Entity
#Table(name ="VIEW_TWO")
private CpBracketSummaryData(){
}
#Entity
#Table(name = "ONE")
public class CpBracket {
#OneToOne
#PrimaryKeyJoinColumn
private CPBracketSummaryData summaryData;
public int getSomeValue(){
return summaryData.getSomeValue();
}
}
The second option would be to use the non JPA compliant, Hibernate specific #Formula annotation.
#Entity
#Table(name = "ONE")
public class CpBracket {
#Formula("native sql query")
private int someValue;
}
Update October 2016
I have revisited this in both Hibernate 4.3.10.Final and 5.1.0.Final and it is possible to have the view as a #SecondaryTable without the insert: if you have the correct mappings.
Scenario 1
Load an entity for edit and do not touch any fields mapped to the secondary table. No update is issued to the secondary table
Scenario 2
Create and save a new entity and do not set any fields mapped to the secondary table. No insert is issued for the secondary table
Scenario 3
Create or update an entity including a field mapped to a secondary table and where this field is marked as insertable = false and updateable = false. An insert is made to the secondary table only for the ID field -the behaviour reported in the original question.
The issue with the mapping in the original question is the fact that the secondary table field is a primitive type and therefore when saving a new entity Hibernate does think a record has to be written to the secondary table with a value of zero.
#Column(name="progress", table="VIEW_TWO", updatable = false, insertable = false)
private int progress = 0;
The solution then is to replace primitives with the corresponding wrapper types and leave them as null. Then when saving a new record there is nothing to write to the secondary table and no insert will be made:
#Column(name="progress", table="VIEW_TWO")
private Integer progress;

I solved a similar problem with #SecondaryTable, which was a database view. So maybe it will help someone else.
The problem was on cascade delete to #SecondaryTable, when record from primary table was deleted.
As a solution, I implemented RULE on view for delete
CREATE RULE on_delete AS ON DELETE TO my_view DO INSTEAD(
select 1;
)
Similar solution can be used for INSERT and UPDATE operation on view.

org.hibernate.AnnotationException: Unable to create unique key constraint

I am using hibernate 4.3.5.Final version.
To handle reserve words at Database,I used a property in hibernate
hibernate.globally_quoted_identifiers = true.
And My pojo class having a unique column and it looks like
#Entity
#Table(name="theme1"
,catalog="theme2"
, uniqueConstraints = #UniqueConstraint(columnNames={"name1"})
public class Theme1 implements java.io.Serializable {
#Id #GeneratedValue(strategy=IDENTITY)
private Integer id;
#Column(name="name1", unique=true, nullable=false, length=32)
private String name1;
.....
Then when my SessionFactoryBean is loading it is failing with below error
Caused by: org.hibernate.AnnotationException: Unable to create unique key constraint (name1) on table theme1: database column 'name1' not found. Make sure that you use the correct column name which depends on the naming strategy in use (it may not be the same as the property name in the entity, especially for relational types)
at org.hibernate.cfg.Configuration.buildUniqueKeyFromColumnNames(Configuration.java:1682)
at org.hibernate.cfg.Configuration.buildUniqueKeyFromColumnNames(Configuration.java:1614)
at org.hibernate.cfg.Configuration.secondPassCompile(Configuration.java:1450)
In the debugging process,I find issue is because of the property I add (hibernate.globally_quoted_identifiers).
When this property is added,Hibernate will append single quotes to handle reserved words.But while mapping from PhysicalToLogical,it is failed to map 'name1' with name1.Hence I got above error.
Can any one suggest how to handle above two cases(reserve words + UniqueConstraint) at a time.

When hibernate.globally_quoted_identifiers is set, Hibernate expects exact column name.
Check JPA with Hibernate 3.6.8.Final, PostgresSQL 9.1, SQLGrammarException - configuration issue? Weird SQL statement for more information.
So according to this, your column name and Table names in the pojo class need to be quoted.

Hibernate zeroToOne

I am trying to establish a relationship between 2 entities which would be zero-to-one. That is, the Parent can be saved without the associated Child entity and also along with the assoicated Child.
Following are the 2 Entity classes...
Employee (Parent)
public class Employee {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
#Column(name="EMP_NAME")
private String name;
#PrimaryKeyJoinColumn
#OneToOne(cascade = {CascadeType.ALL})
private EmployeeInfo info;
#Column(name="EMP_ENUM")
private Integer enumId;
EmployeeInfo (Child)
public class EmployeeInfo {
#Id
#GeneratedValue(strategy=GenerationType.AUTO)
private Long id;
#Column(name="EMPLOYEE_EMAIL")
private String email;
With such kind of a relation and id column of the only Parent (Employee) table set to AUTO INCREMENT in MySql DB, the problem is that while saving a Parent->Child object graph, I get the following exception
org.springframework.orm.hibernate3.HibernateJdbcException: JDBC exception on Hibernate data access: SQLException for SQL [insert into EMP_INFO
Caused by: java.sql.SQLException: Field 'id' doesn't have a default value
I tried setting the Child Table's Id property to AUTO INCREMENT in the DB , and the persistence of such a Parent->Child object graph is successful.
However, the problem described here surfaces, because I have a scenario in which I would like to save the parent (Employee) object without the associated EmpInfo object, and hence do NOT want to have AUTO INCREMENT on the Child's id column.
One solution could be not use the PrimaryKeyJoinColumn, but use a particular JoinColumn, but that adds an unnecessary column to my existing Table.
Has anyone come across such a problem? If yes, any pointers would be much helpful.

Finally, I got it working thanks to Pascal and some googling from my side. Apparently, I cannot use the Native key generator for such relationships where the parent can exist without the child (optional = true).
The thing that worked finally was the following, leaving me the downside of having to deal with Hibernate specific annotation (#GenericGenerator) and also having to make-do with bi-directional relationships instead of the unidirectional that I wanted.
Employee (Parent) class remains unchanged as above. It has AUTO INCREMENT on the Id column.
As for the child class (EmployeeInfo) it changed to the following, and again WITHOUT having the AUTO INCREMENT set on the Id column.
#Table(name="EMP_INFO")
#Entity
public class EmployeeInfo {
#Id
#GeneratedValue(generator="foreign")
#GenericGenerator(name="foreign", strategy = "foreign", parameters={
#Parameter(name="property", value="verifInfo")})
private Long id;
#OneToOne(optional=false)
#JoinColumn (name="id")
private Employee emp;
#Column(name="EMPLOYEE_EMAIL")
private String email;
This helped me achieve what I wanted but on the downside, GenericGenerator is not a JPA annotation, it is a hibernate annotation, and sadly I have to make do with that as of now because JPA does not currently support this(or any similar) annotation.
Anyway, it helps to get through such cases :-)

I have a scenario in which I would like to save the parent (Employee) object without the associated EmpInfo object.
The optional attribute of a OneToOne is true by default, which is what you want.
However, you are somehow misusing the #PrimaryKeyJoinColumn here (well, it actually depends on what you really want to achieve but your current combination of annotations is not correct).
IF you want to map a OneToOne with a shared primary-key, use the #PrimaryKeyJoinColumn. But in that case, don't use a GeneratedValue on EmployeeInfo and set the id manually or, if you don't want to set it manually, use the Hibernate specific foreign generator that I already mentioned in your previous question. Check also the related question mentioned below.
And IF you do not want to use a shared primary key (like in your current code since you're trying to get the id generated by the database), then do not use the PrimaryKeyJoinColumn.
You have to make a choice.
References
JPA 1.0 specification:
9.1.32 PrimaryKeyJoinColumn Annotation
Related question
JPA Hibernate One-to-One relationship.