I'm a beginning Java programmer and I had a project on my USB and I was trying to double click the source code just from the folder and not going into any software or IDEs.
However, it just opens the code in a Notepad and gives me an "Open with Visual Studio" option when I right click on the folder. There is no "Open with IntelliJ IDEA" option. Would be great if you guys could help me out.
I was also wondering how I could save projects in another folder or drive without having to go to the files program and copying and pasting into the drive I want it to be in.
Create a text file and add the following code in it:
#echo off
SET PhpStormPath=C:\Program Files\JetBrains\PhpStorm 2019.3.1\bin\phpstorm64.exe
echo Adding file entries
#reg add "HKEY_CLASSES_ROOT\*\shell\PhpStorm" /t REG_SZ /v "" /d "Open in PhpStorm" /f
#reg add "HKEY_CLASSES_ROOT\*\shell\PhpStorm" /t REG_EXPAND_SZ /v "Icon" /d "%PhpStormPath%,0" /f
#reg add "HKEY_CLASSES_ROOT\*\shell\PhpStorm\command" /t REG_SZ /v "" /d "%PhpStormPath% \"%%1\"" /f
echo Adding within a folder entries
#reg add "HKEY_CLASSES_ROOT\Directory\Background\shell\PhpStorm" /t REG_SZ /v "" /d "Open with PhpStorm" /f
#reg add "HKEY_CLASSES_ROOT\Directory\Background\shell\PhpStorm" /t REG_EXPAND_SZ /v "Icon" /d "%PhpStormPath%,0" /f
#reg add "HKEY_CLASSES_ROOT\Directory\Background\shell\PhpStorm\command" /t REG_SZ /v "" /d "%PhpStormPath% \"%%V\"" /f
echo Adding folder entries
#reg add "HKEY_CLASSES_ROOT\Directory\shell\PhpStorm" /t REG_SZ /v "" /d "Open with PhpStorm" /f
#reg add "HKEY_CLASSES_ROOT\Directory\shell\PhpStorm" /t REG_EXPAND_SZ /v "Icon" /d "%PhpStormPath%,0" /f
#reg add "HKEY_CLASSES_ROOT\Directory\shell\PhpStorm\command" /t REG_SZ /v "" /d "%PhpStormPath% \"%%1\"" /f
pause
Rename the file with the extension to script.cmd or script.bat
Run this file as administrator.
However, it just opens the code on a notepad and gives me an open with visual studio option when I right click on the folder. There is no "open with Intellij idea" option
Sounds like you're on Windows and missed the option during Intellij installation to associate file types to the IDE.
In windows control center, there is file associations you can edit away from notepad or you can right click, go to properties, then change the "open with" options
Regarding opening whole folders, I don't typically go through right click menus, but if you want to edit code, you'd typically open the IDE anyway, so just open it, then open the folder as a project
For copying files, I don't quite understand the problem, but it's not going to be solved by Java or Intellij, and I don't know any easier way to copy files between directories or drives
When you 1st installed IntelliJ, you must have not checked the appropriate boxes to allow you to do those actions that you wanted. Installation Options when installing IntelliJ IDEA Community Edition
Under "Update context menu" you should check the box to Add "Open Folder as Project". This will allow you to choose your directory with all your Java files.
Under "Create Associations" you should check the box for .java. This will allow to double-click on your .java file to open IntelliJ.
Press W+R then type regedit and navigate to the displayed location. If those directories are not there then you can add them and add the value of the icon according to your software location.and then add these to command
I would like to kill a process using java on windows by it's parameters.
If I have an exe and I run it using "exe param1 param2 etc.." and let's say param1 is unique but exe is not, I woulk like to kill the process by param1.
How can I do that ?
You could use following command to find the java process id then use taskkill to kill the process or use cygwin in windows and use linux command to kill the process hth
jps -lv | findstr "STRING"
You could use following command to find the tasklist with commandline column
wmic path win32_process get | findstr java.exe
I am not sure what do you mean.
If you want to kill the process in Windows by command in Java you need to type this:
Runtime.getRuntime().exec("taskkill /F <processname>.exe")
It executes the Windows command passed as the string of the method of Runtime class.
taskkill - command ends one or more tasks or processes.
/F - parameter specifies process to be terminated
target process started via command line : notepad killme.txt"
for /f "tokens=1,2" %i in ('wmic path win32_process get Commandline') do (IF "%j" == "killme.txt" (taskkill /FI "IMAGENAME eq %i*"))
This is irritating. I am trying to incorporate a trigger in a script to run if the major version of Java is 1.6,1.7, etc.
In the line I am trying to set the variable in, I pull the Java version and pipe it to for with tokens and delims identified, resulting in the "do" as a set command for variable %jver%. However, echoing %jver% results in "echo is on". Why wont it set the variable? Everything looks legit until %jver% is used.
Yes, I double the percentages for the script. The code here is for use at the command prompt.
Here is the line:
%systemroot%\system32\java.exe -version 2>&1 | for /f "tokens=1-4 delims=. " %a in ('findstr /i "version"') do (set jver=%~c.%d)
#rao thank you for helping me discover an alternate solution to meet my intent.
My workaround solution to this is the following line:
for /f "tokens=1-4 delims=. " %a in ('java -version 2^>^&1 ^| findstr /i "version"') do (SET JVER=%~c.%d)
Looks this is answered in this post by Patrick Cuff
Here is the solution adding from mentioned original post
#echo off
setlocal
set VERSION6="1.6.0_21"
for /f "tokens=3" %%g in ('java -version 2^>^&1 ^| findstr /i "version"') do (
#echo Output: %%g
set JAVAVER=%%g
)
set JAVAVER=%JAVAVER:"=%
#echo Output: %JAVAVER%
Alright i made a executable jar that holds a test game ran through a application. It runs fine for me but for my friend it does not. It says its unable to find the main class. So does he have to install java jdk or something? Is there a way around this?
Well, for one, he could be using the wrong command line arguments to the JVM to run the Java jar. Secondly, you could have not defined the main class correctly when you built the jar file (see: Unable to load main-class for jar file).
The way that you work around this? In the link I provided above, you'll see that there are a few command line parameters that can be supplied to the JVM that makes a big difference in how the JVM runs. Take those command line parameters and build a batch (or shell) file that end users can run to initialize the program correctly.
As your computer is setup differently, so may be the shell extension that handles files of type ".jar"
Try installing the newest version of java (JRE) on their machine (make sure it is of equal or higher version than the one your application was compiled against) and ensure that if you are using different architectures (x86 / x64) that you have the right versions of any libraries. I had this error only yesterday because I deployed a JDK 7u7 application to a machine with JRE 6u7.
Yes, there is a way around it. Run this script:
#ECHO off
SETLOCAL ENABLEDELAYEDEXPANSION
:: this .bat script creates a file association for executable .jar files
ECHO Creating .jar file association...
ECHO JAVA_HOME is %JAVA_HOME%
IF NOT DEFINED JAVA_HOME GOTO :FAIL
REG ADD "HKCR\jarfile" /ve /t REG_SZ /d "Executable Jar File" /f
REG ADD "HKCR\jarfile\shell" /ve /f
REG ADD "HKCR\jarfile\shell\open" /ve /f
ECHO REG ADD "HKCR\jarfile\shell\open\command" /ve /t REG_SZ /d "\"%JAVA_HOME%\bin\javaw.exe\" -jar \"%%1\" %%*" /f
REG ADD "HKCR\jarfile\shell\open\command" /ve /t REG_SZ /d "\"%JAVA_HOME%\bin\javaw.exe\" -jar \"%%1\" %%**" /f
REG ADD "HKLM\jarfile" /ve /t REG_SZ /d "Executable Jar File" /f
REG ADD "HKLM\SOFTWARE\Classes\jarfile\shell" /ve /f
REG ADD "HKLM\SOFTWARE\Classes\jarfile\shell\open" /ve /f
REG ADD "HKLM\SOFTWARE\Classes\jarfile\shell\open\command" /ve /t REG_SZ /d "\"%JAVA_HOME%\bin\javaw.exe\" -jar \"%%1\" %%*" /f
ECHO Finished creating .jar file association for executable .jar files.
PAUSE
GOTO EOF
:FAIL
ECHO Script failed. JAVA_HOME not defined.
PAUSE
install the new JRE .
while running the jar make sure you giv the class path in he command.
Eg. java -cp asd -jar file.jar
I need to know where JDK is located on my machine.
On running Java -version in cmd, it shows the version as '1.6.xx'.
To find the location of this SDK on my machine I tried using echo %JAVA_HOME% but it is only showing 'JAVA_HOME' (as there is no 'JAVA_PATH' var set in my environment variables).
If you are using Linux/Unix/Mac OS X:
Try this:
$ which java
Should output the exact location.
After that, you can set JAVA_HOME environment variable yourself.
In my computer (Mac OS X - Snow Leopard):
$ which java
/usr/bin/java
$ ls -l /usr/bin/java
lrwxr-xr-x 1 root wheel 74 Nov 7 07:59 /usr/bin/java -> /System/Library/Frameworks/JavaVM.framework/Versions/Current/Commands/java
If you are using Windows:
c:\> for %i in (java.exe) do #echo. %~$PATH:i
Windows > Start > cmd >
C:> for %i in (javac.exe) do #echo. %~$PATH:i
If you have a JDK installed, the Path is displayed,
for example: C:\Program Files\Java\jdk1.6.0_30\bin\javac.exe
In Windows at the command prompt
where javac
Command line:
Run where java on Command Prompt.
GUI:
On Windows 10 you can find out the path by going to Control Panel > Programs > Java. In the panel that shows up, you can find the path as demonstrated in the screenshot below. In the Java Control Panel, go to the 'Java' tab and then click the 'View' button under the description 'View and manage Java Runtime versions and settings for Java applications and applets.'
This should work on Windows 7 and possibly other recent versions of Windows.
In windows the default is: C:\Program Files\Java\jdk1.6.0_14 (where the numbers may differ, as they're the version).
Java installer puts several files into %WinDir%\System32 folder (java.exe, javaws.exe and some others). When you type java.exe in command line or create process without full path, Windows runs these as last resort if they are missing in %PATH% folders.
You can lookup all versions of Java installed in registry. Take a look at HKLM\SOFTWARE\JavaSoft\Java Runtime Environment and HKLM\SOFTWARE\Wow6432Node\JavaSoft\Java Runtime Environment for 32-bit java on 64 bit Windows.
This is how java itself finds out different versions installed. And this is why both 32-bit and 64-bit version can co-exist and works fine without interfering.
Plain and simple on Windows platforms:
where java
Under Windows, you can use
C:>dir /b /s java.exe
to print the full path of each and every "java.exe" on your C: drive, regardless of whether they are on your PATH environment variable.
The batch script below will print out the existing default JRE. It can be easily modified to find the JDK version installed by replacing the Java Runtime Environment with Java Development Kit.
#echo off
setlocal
::- Get the Java Version
set KEY="HKLM\SOFTWARE\JavaSoft\Java Runtime Environment"
set VALUE=CurrentVersion
reg query %KEY% /v %VALUE% 2>nul || (
echo JRE not installed
exit /b 1
)
set JRE_VERSION=
for /f "tokens=2,*" %%a in ('reg query %KEY% /v %VALUE% ^| findstr %VALUE%') do (
set JRE_VERSION=%%b
)
echo JRE VERSION: %JRE_VERSION%
::- Get the JavaHome
set KEY="HKLM\SOFTWARE\JavaSoft\Java Runtime Environment\%JRE_VERSION%"
set VALUE=JavaHome
reg query %KEY% /v %VALUE% 2>nul || (
echo JavaHome not installed
exit /b 1
)
set JAVAHOME=
for /f "tokens=2,*" %%a in ('reg query %KEY% /v %VALUE% ^| findstr %VALUE%') do (
set JAVAHOME=%%b
)
echo JavaHome: %JAVAHOME%
endlocal
In a Windows command prompt, just type:
set java_home
Or, if you don't like the command environment, you can check it from:
Start menu > Computer > System Properties > Advanced System Properties. Then open Advanced tab > Environment Variables and in system variable try to find JAVA_HOME.
Powershell one liner:
$p='HKLM:\SOFTWARE\JavaSoft\Java Development Kit'; $v=(gp $p).CurrentVersion; (gp $p/$v).JavaHome
In Windows PowerShell you can use the Get-Command function to see where Java is installed:
Get-Command -All java
Or
gcm -All java
The -All part makes sure to show all places it appears in the Path lookup. Below is example output.
PS C:> gcm -All java
CommandType Name Version Source
----------- ---- ------- ------
Application java.exe 8.0.202.8 C:\Program Files (x86)\Common Files\Oracle\Java\jav...
Application java.exe 8.0.131... C:\ProgramData\Oracle\Java\javapath\java.exe
Run this program from commandline:
// File: Main.java
public class Main {
public static void main(String[] args) {
System.out.println(System.getProperty("java.home"));
}
}
$ javac Main.java
$ java Main
More on Windows... variable java.home is not always the same location as the binary that is run.
As Denis The Menace says, the installer puts Java files into Program Files, but also java.exe into System32. With nothing Java related on the path java -version can still work. However when PeterMmm's program is run it reports the value of Program Files as java.home, this is not wrong (Java is installed there) but the actual binary being run is located in System32.
One way to hunt down the location of the java.exe binary, add the following line to PeterMmm's code to keep the program running a while longer:
try{Thread.sleep(60000);}catch(Exception e) {}
Compile and run it, then hunt down the location of the java.exe image. E.g. in Windows 7 open the task manager, find the java.exe entry, right click and select 'open file location', this opens the exact location of the Java binary. In this case it would be System32.
Have you tried looking at your %PATH% variable. That's what Windows uses to find any executable.
Just execute the set command in your command line. Then you see all the environments variables you have set.
Or if on Unix you can simplify it:
$ set | grep "JAVA_HOME"
This is OS specific. On Unix:
which java
will display the path to the executable. I don't know of a Windows equivalent, but there you typically have the bin folder of the JDK installation in the system PATH:
echo %PATH%
On macOS, run:
cd /tmp && echo 'public class Main {public static void main(String[] args) {System.out.println(System.getProperty("java.home"));}}' > Main.java && javac Main.java && java Main
On my machine, this prints:
/Library/Java/JavaVirtualMachines/jdk-9.0.4.jdk/Contents/Home
Note that running which java does not show the JDK location, because the java command is instead part of JavaVM.framework, which wraps the real JDK:
$ which java
/usr/bin/java
/private/tmp
$ ls -l /usr/bin/java
lrwxr-xr-x 1 root wheel 74 14 Nov 17:37 /usr/bin/java -> /System/Library/Frameworks/JavaVM.framework/Versions/Current/Commands/java
None of these answers are correct for Linux if you are looking for the home that includes the subdirs such as: bin, docs, include, jre, lib, etc.
On Ubuntu for openjdk1.8.0, this is in:
/usr/lib/jvm/java-1.8.0-openjdk-amd64
and you may prefer to use that for JAVA_HOME since you will be able to find headers if you build JNI source files. While it's true which java will provide the binary path, it is not the true JDK home.
I have improved munsingh's answer above by testing for the registry key in 64-bit and 32-bit registries, if needed:
::- Test for the registry location
SET VALUE=CurrentVersion
SET KEY_1="HKLM\SOFTWARE\JavaSoft\Java Development Kit"
SET KEY_2=HKLM\SOFTWARE\JavaSoft\JDK
SET REG_1=reg.exe
SET REG_2="C:\Windows\sysnative\reg.exe"
SET REG_3="C:\Windows\syswow64\reg.exe"
SET KEY=%KEY_1%
SET REG=%REG_1%
%REG% QUERY %KEY% /v %VALUE% 2>nul
IF %ERRORLEVEL% EQU 0 GOTO _set_value
SET KEY=%KEY_2%
SET REG=%REG_1%
%REG% QUERY %KEY% /v %VALUE% 2>nul
IF %ERRORLEVEL% EQU 0 GOTO _set_value
::- %REG_2% is for 64-bit installations, using "C:\Windows\sysnative"
SET KEY=%KEY_1%
SET REG=%REG_2%
%REG% QUERY %KEY% /v %VALUE% 2>nul
IF %ERRORLEVEL% EQU 0 GOTO _set_value
SET KEY=%KEY_2%
SET REG=%REG_2%
%REG% QUERY %KEY% /v %VALUE% 2>nul
IF %ERRORLEVEL% EQU 0 GOTO _set_value
::- %REG_3% is for 32-bit installations on a 64-bit system, using "C:\Windows\syswow64"
SET KEY=%KEY_1%
SET REG=%REG_3%
%REG% QUERY %KEY% /v %VALUE% 2>nul
IF %ERRORLEVEL% EQU 0 GOTO _set_value
SET KEY=%KEY_2%
SET REG=%REG_3%
%REG% QUERY %KEY% /v %VALUE% 2>nul
IF %ERRORLEVEL% EQU 0 GOTO _set_value
:_set_value
FOR /F "tokens=2,*" %%a IN ('%REG% QUERY %KEY% /v %VALUE%') DO (
SET JDK_VERSION=%%b
)
SET KEY=%KEY%\%JDK_VERSION%
SET VALUE=JavaHome
FOR /F "tokens=2,*" %%a IN ('%REG% QUERY %KEY% /v %VALUE%') DO (
SET JAVAHOME=%%b
)
ECHO "%JAVAHOME%"
::- SETX JAVA_HOME "%JAVAHOME%"
reference for access to the 64-bit registry
Maybe the above methods work... I tried some and didn't for me. What did was this :
Run this in terminal :
/usr/libexec/java_home
Simple method (Windows):
Open an application using java.
press ctrl + shift + esc
Right click on OpenJDK platform binary. Click open file location.
Then it will show java/javaw.exe then go to the top where it shows the folder and click on the jdk then right copy the path, boom. (Wont work for apps using bundled jre paths/runtimes, because it will show path to the bundled runtime)
in Windows cmd:
set "JAVA_HOME"
#!/bin/bash
if [[ $(which ${JAVA_HOME}/bin/java) ]]; then
exe="${JAVA_HOME}/bin/java"
elif [[ $(which java) ]]; then
exe="java"
else
echo "Java environment is not detected."
exit 1
fi
${exe} -version
For windows:
#echo off
if "%JAVA_HOME%" == "" goto nojavahome
echo Using JAVA_HOME : %JAVA_HOME%
"%JAVA_HOME%/bin/java.exe" -version
goto exit
:nojavahome
echo The JAVA_HOME environment variable is not defined correctly
echo This environment variable is needed to run this program.
goto exit
:exit
This link might help to explain how to find java executable from bash: http://srcode.org/2014/05/07/detect-java-executable/
Script for 32/64 bit Windows.
#echo off
setlocal enabledelayedexpansion
::- Get the Java Version
set KEY="HKLM\SOFTWARE\JavaSoft\Java Runtime Environment"
set KEY64="HKLM\SOFTWARE\WOW6432Node\JavaSoft\Java Runtime Environment"
set VALUE=CurrentVersion
reg query %KEY% /v %VALUE% 2>nul || (
set KEY=!KEY64!
reg query !KEY! /v %VALUE% 2>nul || (
echo JRE not installed
exit /b 1
)
)
set JRE_VERSION=
for /f "tokens=2,*" %%a in ('reg query %KEY% /v %VALUE% ^| findstr %VALUE%') do (
set JRE_VERSION=%%b
)
echo JRE VERSION: %JRE_VERSION%
::- Get the JavaHome
set KEY="HKLM\SOFTWARE\JavaSoft\Java Runtime Environment\%JRE_VERSION%"
set KEY64="HKLM\SOFTWARE\WOW6432Node\JavaSoft\Java Runtime Environment\%JRE_VERSION%"
set VALUE=JavaHome
reg query %KEY% /v %VALUE% 2>nul || (
set KEY=!KEY64!
reg query !KEY! /v %VALUE% 2>nul || (
echo JavaHome not installed
exit /b 1
)
)
set JAVAHOME=
for /f "tokens=2,*" %%a in ('reg query %KEY% /v %VALUE% ^| findstr %VALUE%') do (
set JAVAHOME=%%b
)
echo JavaHome: %JAVAHOME%
endlocal