We Keep Coding

Need to get value after Domain name in url using java

We are getting url from JSON Response and which we open in in Chrome.The page loads , there is submit button which we click then it redirect to url as :-
https://www.google.com/AB1234
We need the need to retrieve only "AB1234" value from url.
tried following code to get value ="AB1234"
String url = driver.getCurrentUrl();
int index=url.lastIndexOf("/");
String result = url.substring(0,index);
but here getting initial part of url:https://www.google.com/

You need to call substring function with index +1 .
Try below code :
String url = driver.getCurrentUrl();
int index = url.lastIndexOf("/");
String result = url.substring(index + 1);

To parse a URI, it's likely a good idea to use a URI parser.
Given http://example.com/bar
String path = URI.create(driver.getCurrentUrl()).getPath();
will get you '/bar'.
Given http://example.com/bar/mumble the same code gets '/bar/mumble'. It's unclear from your question whether this is what you want. Nevertheless, you should at least start the parse as above.

Android java split string via special character fails

I would like to attach a platform parameter to a url with ? if the url has no query string and using & if url has a query string
SO i have added the following
String api_url;
//costructor next to assign apiurl value
//method to extract url and process request
processData(){
String apiUrl = "";
String[] urlParams = this.api_url.split("\\?");
if (urlParams.length > 0){
apiUrl = this.api_url+"&platform="+tokenService.getToken(AppDetailsHelpers.AppSettingsKeys.PLATFORM);
}else {
apiUrl = this.api_url+"?platform="+tokenService.getToken(AppDetailsHelpers.AppSettingsKeys.PLATFORM);
}
}
The above always evaluates the urlParams to a an array even when a url doesnt contain the ?
Example for a url
http://test.com
is resolved with the above code as
http://test.com&platform=12
But i expected it to be as http://test.com?platform=12
I have tried adding
String[] urlParams = this.api_url.split("?");
But it throws an error of Dangling metacharacter. What am i missing out on this. Why does this fail.

This is expected behaviour for String#split. Running "http://test.com".split("\\?") returns an array with one element, "http://test.com". So, just update your condition to if(uriParams.length > 1).
You could also consider parsing your String to a Uri, as you may not need this check and could possibly instead use:
Uri.parse(api_url)
.buildUpon()
.appendQuery("platform", tokenService.getToken(AppSettingsKeys.PLATFORM))
.build().toString();

Get relevant part of domain name in Java

If we have an url e.g www.google.de how can I get ONLY the "google"
In Java new URL (url).getHost(); does work but it gives me google.de
and this is not what I want to have.
Thank you
EDIT: If we have something like www.google.co.uk then I also want to have only "google" as result.
I dont want "google.de" or "www.google" I ONLY want "google"

Splitting on a period and selecting the first or second element (whichever is not "www") would work:
URL url = new URL("http://www.host.ext.ext");
String host = url.getHost(); // host = "www.host.ext.ext"
String splitHost = host.split("\\.") // splitHost = { "www", "host", "ext", "ext" }
host = splitHost[0].equals("www") ? splitHost[1] : splitHost[0]; // host = "host"
If there is anything more than http://www. before it, and the extension is potentially more than two "extensions" (.co.uk for instance), then there is no easy way to get just the part you want. As far as I know, you would have to try iterating over a list of extensions and return the part immediately before the longest matching extension.

The most basic solution would be using
System.out.println(url.split("\\.")[1]);
Or you could try this https://stackoverflow.com/a/23079402/2555419
public String getHostName(String url) {
URI uri = new URI(url);
String hostname = uri.getHost();
// to provide faultproof result, check if not null then return only hostname, without www.
if (hostname != null) {
return hostname.startsWith("www.") ? hostname.substring(4) : hostname;
}
return hostname;
}

Get last part of url using a regex

How do I get the last part of the a URL using a regex, here is my URL, I want the segmeent between the last forward slash and the #
http://mycompany.com/test/id/1234#this
So I only want to get 1234.
I have the following but is not removing the '#this'
".*/(.*)(#|$)",
I need this while indexing data so don't want to use the URL class.

Just use URI:
final URI uri = URI.create(yourInput);
final String path = uri.getPath();
path.substring(path.lastIndexOf('/') + 1); // will return what you want
Will also take care of URIs with query strings etc. In any event, when having to extract any part from a URL (which is a URI), using a regex is not what you want: URI can handle it all for you, at a much lower cost -- since it has a dedicated parser.
Demo code using, in addition, Guava's Optional to detect the case where the URI has no path component:
public static void main(final String... args) {
final String url = "http://mycompany.com/test/id/1234#this";
final URI uri = URI.create(url);
final String path = Optional.fromNullable(uri.getPath()).or("/");
System.out.println(path.substring(path.lastIndexOf('/') + 1));
}

how about:
".*/([^/#]*)(#.*|$)"

Addition to what #jtahlborn answer to include query string:
".*/([^/#|?]*)(#.*|$)"

Extract part of a URL with URL/URI objects

I have a String holding a URL in this format: http://hello.world.com/service/sps/f4c0e810456t
And I would like to extract the last part of the URL, i.e. f4c0e810456t.
I can do it with substrings:
System.out.println(s.substring(s.lastIndexOf("/") + 1, s.length()));
Or regexp however looking for something more elegant using URL/URI objects but couldn't find something.
Any ideas...?

If you can change the URL to "http://hello.world.com/service/sps/?f4c0e810456t" then you could use the getQuery() method (both on URL and URI).

Example with URL and split (it wrap regular expression for you):
String address = "http://hello.world.com/service/sps/f4c0e810456t";
URL url = new URL(address);
String [] str = url.getPath().split("/");
String result = str[str.length-1];