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String to Date Conversion mm/dd/yy to YYYY-MM-DD in java [duplicate]

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Java Date Error
(8 answers)
Closed 4 years ago.
I want to convert String values in the format of mm/dd/yy to YYYY-MM-DD Date. how to do this conversion?
The input parameter is: 03/01/18
Code to convert String to Date is given below
public static Date stringToDateLinen(String dateVlaue) {
Date date = null;
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd");
try {
date = formatter.parse(dateVlaue);
} catch (ParseException e) {
e.printStackTrace();
}
return date;
}
When tried to convert using this method it shows the following error
java.text.ParseException: Unparseable date: "03/01/18"

As you say the input is in a different format, first convert the String to a valid Date object. Once you have the Date object you can format it into different types , as you want, check.
To Convert as Date,
SimpleDateFormat formatter = new SimpleDateFormat("MM/dd/yy");
date = formatter.parse(dateVlaue);
To Print it out in the other format,
SimpleDateFormat formatter1 = new SimpleDateFormat("yyyy-MM-dd");
dateString = formatter1.format(date)

You are writing it the wrong way. In fact, for the date you want to convert, you need to write
SimpleDateFormat formatter = new SimpleDateFormat("MM/dd/yy");

The format you are passing to SimpleDateFormat is ("yyyy-MM-dd") which expects date to be in form 2013-03-01 and hence the error.
You need to supply the correct format that you are passing your input as something like below
public static Date stringToDateLinen(String dateVlaue) {
Date date = null;
SimpleDateFormat formatter = new SimpleDateFormat("dd/MM/yy");
try {
date = formatter.parse(dateVlaue);
} catch (ParseException e) {
e.printStackTrace();
}
return date;
}

The solution for the above problem
Convert the String date value in the Format of "dd/mm/yy" to Date.
By using the converted Date can able to frame the required date format.
The method has given below
public static String stringToDateLinen(String dateVlaue) {
Date date = null;
SimpleDateFormat formatter = new SimpleDateFormat("dd/mm/yy");
String dateString = null;
try {
// convert to Date Format From "dd/mm/yy" to Date
date = formatter.parse(dateVlaue);
// from the Converted date to the required format eg : "yyyy-MM-dd"
SimpleDateFormat formatter1 = new SimpleDateFormat("yyyy-MM-dd");
dateString = formatter1.format(date);
} catch (ParseException e) {
e.printStackTrace();
}
return dateString;
}

EDIT: Your question said “String values in the format of mm/dd/yy”, but I understand from your comments that you meant “my input format is dd/mm/yy as string”, so I have changed the format pattern string in the below code accordingly. Otherwise the code is the same in both cases.
public static Optional<LocalDate> stringToDateLinen(String dateValue) {
DateTimeFormatter dateFormatter = DateTimeFormatter.ofPattern("dd/MM/yy");
try {
return Optional.of(LocalDate.parse(dateValue, dateFormatter));
} catch (DateTimeParseException dtpe) {
return Optional.empty();
}
}
Try it:
stringToDateLinen("03/01/18")
.ifPresentOrElse(System.out::println,
() -> System.out.println("Could not parse"));
Output:
2018-01-03
I recommend you stay away from SimpleDateFormat. It is long outdated and notoriously troublesome too. And Date is just as outdated. Instead use LocalDate and DateTimeFormatter from java.time, the modern Java date and time API. It is so much nicer to work with. A LocalDate is a date without time of day, so this suites your requirements much more nicely than a Date, which despite its name is a point in time. LocalDate.toString() produces exactly the format you said you desired (though the LocalDate doesn’t have a format in it).
My method interprets your 2-digit year as 2000-based, that is, from 2000 through 2099. Please think twice before deciding that this is what you want.
What would you want to happen if the string cannot be parsed into a valid date? I’m afraid that returning null is a NullPointerException waiting to happen and a subsequent debugging session to track down the root cause. You may consider letting the DateTimeParseException be thrown out of your method (just declare that in Javadoc) so the root cause is in the stack trace. Or even throw an AssertionError if the situation is not supposed to happen. In my code I am returning an Optional, which clearly signals to the caller that there may not be a result, which (I hope) prevents any NullPointerException. In the code calling the method I am using the ifPresentOrElse method introduced in Java 9. If not using Java 9 yet, use ifPresent and/or read more about using Optional elsewhere.
What went wrong in your code?
The other answers are correct: Your format pattern string used for parsing needs to match the input (not your output). The ParseException was thrown because the format pattern contained hyphens and the input slashes. It was good that you got the exception because another problem is that the order of year, month and day doesn’t match, neither does the number of digits in the year.
Link
Oracle tutorial: Date Time explaining how to use java.time.

joda time parse method return format

I have very simple question - I read couple of threads here but I still do not understand how to get simple thing. I want to send string to method and get back joda date. I had no problem to build it up, but return format is 2015-03-11T17:13:09:000+01:00. How can I get desired (e.g. mmm-dd hh:mm) format back from below mentioned method (it mustto be a dateTime for sorting purposes on FX form)? I tried to gamble with another dateTimeFormatter but had no luck. Thank you very much in advance
public static DateTime stringToDateTime(String textDate) throws ParseException
{
DateTimeFormatter dateTimeFormatter = DateTimeFormat.forPattern("yyyy-MM-dd HH:mm:ss.SSS");
DateTime jodaTime = dateTimeFormatter.parseDateTime(textDate);
return jodaTime;
}

What do you mean by "return format"? "Format" term here could only be related to a string representation of a DateTime object. That means you should specify format of your input string (what you've already done in your code) - and a corresponding DateTime object will be created. After that you probably use toString() to check the results, but DateTime.toString() uses ISO8601 format (yyyy-MM-ddTHH:mm:ss.SSSZZ) according to JavaDoc - that gives you your 2015-03-11T17:13:09:000+01:00 result.
So to get it as desired you could try using toString(String pattern) method with format you need. But once again - it's just an output format to convert DateTime to String, it doesn't affect the datetime stored in your DateTime object.

I just use Calendar object so this is a possible way to do it:
static String stringToDateTime(String textDate) {
Calendar c = new GregorianCalendar();
// How you want the input to be formatted
DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
try {
Date date = df.parse(textDate);
c.setTime(date);
} catch (ParseException e) {
e.printStackTrace();
}
// How do you want to print your date
df= new SimpleDateFormat("dd-MM-yy");
return df.format(c.getTime());
}
// input
String myDate = "2015-04-15 14:25:25";
System.out.println(stringToDateTime(myDate));

How to converted timestamp string to a date in java

I have a string "1427241600000" and I want it converted to "yyyy-MM-dd" format.
I have tried, but I am not able to parse it, please review the below code
try {
String str = "1427241600000";
SimpleDateFormat sf = new SimpleDateFormat("yyyy-MM-dd");
Date date =sf.parse(str);
System.out.println(date);
} catch (ParseException e) {
e.printStackTrace();
}
I would like to know where I went wrong.

You should try it the other way around. First get the Date out of the milliTime and then format it.
String str = "1427241600000";
SimpleDateFormat sf = new SimpleDateFormat("yyyy-MM-dd");
Date date = new Date(Long.parseLong(str));
System.out.println(sf.format(date));

the conversion is highly dependent on what format the timestamp is in. But i assume the whole thing should actually be a long and is simply the systemtime from when the timestamp was created. So this should work:
String str = ...;
Date date = new Date(Long.parseLong(str));

Use Date date =new Date(Long.parseLong(str)); to convert your String to Date object.
if you are using SimpleDateFormat() the format specified as a parameter to this function should match the format of the date in the String (str in your case). In your case yyyy-MM-dd does not match the format of the time stamp (1427241600000).

You can do it like this:
use a SimpleDateFormat with an appropriate format string (be careful to use the correct format letters, uppercase and lowercase have different meanings!).
DateFormat format = new SimpleDateFormat("MMddyyHHmmss");
Date date = format.parse("022310141505");

Java : Impossible to parse "23/10/1973" with "dd/MM/yyyy HH:mm" format

I'm trying to parse many string dates to Date(s), some with time part, others without, with the "dd/MM/yyyy HH:mm" format.
public static Date StringToDate (String format, String theDate) {
SimpleDateFormat df = new SimpleDateFormat(format);
Date retDate = null;
try {
df.setLenient(true);
retDate = df.parse(theDate);
}
catch (ParseException e) {
e.printStackTrace();
}
return (retDate);
}
(here, format is always "dd/MM/yyyy HH:mm").
But this causes an exception, even with setLenient forced at true. Do you know how I may convert to Date a lot of strings formatted like "dd/MM/yyyy HH:mm:ss", but with someones without time, some others without secondes, and still other one with everything ?

If you know that some strings have a time and some don't, and there are no other cases, I'd just check the length of the string. However, if you have many different formats available, I'd try each one in some order that makes sense, until you get a valid date.

I always have two parse strings, and I parse twice; once with date/time and once with date only.

How to convert time data in java?

The following time formats are in outlook calendar file
DTSTART;TZID="Eastern":20100728T140000
DTEND;TZID="Eastern":20100728T150000
how to convert this time to java time format.

This looks like iCalendar. Take a look at ical4j - a Java API for it.

Without tested, look at SimpleDateFormat
String ds = "DTSTART;TZID=\"Eastern\":20100728T140000";
Date d = new SimpleDateFormat("yyyyMMdd'T'HHMMSS").parse(ds.split(":")[1]);

Handling the timezone will be tricky as "Eastern" is not an actual timezone. However if you handle that, I would suggest the following SimpleDateFormat will handle the unadjusted parse for you.
Date unadjusted =
new SimpleDateFormat("yyyyMMdd'T'HHmmss").parse(line.split(":")[1]);

Another way using always SimpleDateFormat:
String[] strings = new String[]{"DTSTART;TZID=\"Eastern\":20100728T140000", "DTEND;TZID=\"Eastern\":20100728T150000"};
for (String string : strings) {
String dateString = string.replaceAll("(DTSTART|DTEND);TZID=\"Eastern\":", "");
dateString = dateString.replaceAll("T", "");
SimpleDateFormat sdf = new SimpleDateFormat("yyyyMMddHHmmss");
try {
Date date = sdf.parse(dateString);
System.out.println(date);
} catch (ParseException e) {
e.printStackTrace();
}
}