Related
We have to make a program on printing initials, which seems pretty easy ok, but I don't know how to cut the string when the input is all on one line using the scanner class in.nextline();. I cant seem to find a way to cut the string using only string methods. Also, another problem arose when I have to also be able to adjust if there isn't a middle name either. if anyone can help me or lead me in the right direction that would be nice.
If you can use split function as you can see below:
String inputString=s.nextLine();
String [] str = inputString.split(" ");
If you want to have extract only first letter then -
import java.util.Scanner;
public class TestStringInput {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println("Please Enter the Name");
String input = scan.nextLine();
int value = input.indexOf(" ",input.indexOf(" "));
String result = input.substring(0,value);
System.out.println(result);
}
}
But if you want to Extract Starting 2 Initials then change this line-
int value = input.indexOf(" ",input.indexOf(" ")+1);
As Stephen mentioned, your question is about Java, consider re-tagging.
You can use a for loop to iterate through the string. Remember a string is an object. It would help a lot if you posted your code.
import java.util.Scanner;
public class HW03 {
public static void main (String args[])
{
Scanner in = new Scanner(System.in);
String str = "";
System.out.println("What are your first, middle and last names?");
str = in.nextLine();
}
}
I am trying to find a way to take a char input from the keyboard.
I tried using:
Scanner reader = new Scanner(System.in);
char c = reader.nextChar();
This method doesn't exist.
I tried taking c as a String. Yet, it would not always work in every case, since the other method I am calling from my method requires a char as an input. Therefore I have to find a way to explicitly take a char as an input.
Any help?
You could take the first character from Scanner.next:
char c = reader.next().charAt(0);
To consume exactly one character you could use:
char c = reader.findInLine(".").charAt(0);
To consume strictly one character you could use:
char c = reader.next(".").charAt(0);
Setup scanner:
reader.useDelimiter("");
After this reader.next() will return a single-character string.
There is no API method to get a character from the Scanner. You should get the String using scanner.next() and invoke String.charAt(0) method on the returned String.
Scanner reader = new Scanner(System.in);
char c = reader.next().charAt(0);
Just to be safe with whitespaces you could also first call trim() on the string to remove any whitespaces.
Scanner reader = new Scanner(System.in);
char c = reader.next().trim().charAt(0);
There are three ways to approach this problem:
Call next() on the Scanner, and extract the first character of the String (e.g. charAt(0)) If you want to read the rest of the line as characters, iterate over the remaining characters in the String. Other answers have this code.
Use setDelimiter("") to set the delimiter to an empty string. This will cause next() to tokenize into strings that are exactly one character long. So then you can repeatedly call next().charAt(0) to iterate the characters. You can then set the delimiter to its original value and resume scanning in the normal way!
Use the Reader API instead of the Scanner API. The Reader.read() method delivers a single character read from the input stream. For example:
Reader reader = new InputStreamReader(System.in);
int ch = reader.read();
if (ch != -1) { // check for EOF
// we have a character ...
}
When you read from the console via System.in, the input is typically buffered by the operating system, and only "released" to the application when the user types ENTER. So if you intend your application to respond to individual keyboard strokes, this is not going to work. You would need to do some OS-specific native code stuff to turn off or work around line-buffering for console at the OS level.
Reference:
How to read a single char from the console in Java (as the user types it)?
You can solve this problem, of "grabbing keyboard input one char at a time" very simply. Without having to use a Scanner all and also not clearing the input buffer as a side effect, by using this.
char c = (char)System.in.read();
If all you need is the same functionality as the C language "getChar()" function then this will work great. The Big advantage of the "System.in.read()" is the buffer is not cleared out after each char your grab. So if you still need all the users input you can still get the rest of it from the input buffer. The "char c = scanner.next().charAt(0);" way does grab the char but will clear the buffer.
// Java program to read character without using Scanner
public class Main
{
public static void main(String[] args)
{
try {
String input = "";
// Grab the First char, also wait for user input if the buffer is empty.
// Think of it as working just like getChar() does in C.
char c = (char)System.in.read();
while(c != '\n') {
//<do your magic you need to do with the char here>
input += c; // <my simple magic>
//then grab the next char
c = (char)System.in.read();
}
//print back out all the users input
System.out.println(input);
} catch (Exception e){
System.out.println(e);
}
}
}
Hope this helpful, and good luck! P.S. Sorry i know this is an older post, but i hope that my answer bring new insight and could might help other people who also have this problem.
This actually doesn't work:
char c = reader.next().charAt(0);
There are some good explanations and references in this question:
Why doesn't the Scanner class have a nextChar method?
"A Scanner breaks its input into tokens using a delimiter pattern", which is pretty open ended. For example when using this
c = lineScanner.next().charAt(0);
for this line of input
"(1 + 9) / (3 - 1) + 6 - 2"
the call to next returns "(1", c will be set to '(', and you'll end up losing the '1' on the next call to next()
Typically when you want to get a character you would like to ignore whitespace. This worked for me:
c = lineScanner.findInLine("[^\\s]").charAt(0);
Reference:
regex to match a single character that is anything but a space
The best way to take input of a character in Scanner class is:
Scanner sca=new Scanner(System.in);
System.out.println("enter a character");
char ch=sca.next().charAt(0);
You should use your custom input reader for faster results instead of extracting first character from reading String.
Link for Custom ScanReader and explanation: https://gist.github.com/nik1010/5a90fa43399c539bb817069a14c3c5a8
Code for scanning Char :
BufferedInputStream br=new BufferedInputStream(System.in);
char a= (char)br.read();
There are two approaches, you can either take exactly one character or strictly one character.
When you use exactly, the reader will take only the first character, irrespective of how many characters you input.
For example:
import java.util.Scanner;
public class ReaderExample {
public static void main(String[] args) {
try {
Scanner reader = new Scanner(System.in);
char c = reader.findInLine(".").charAt(0);
reader.close();
System.out.print(c);
} catch (Exception ex) {
System.out.println(ex.getMessage());
}
}
}
When you give a set of characters as input, say "abcd", the reader will consider only the first character i.e., the letter 'a'
But when you use strictly, the input should be just one character. If the input is more than one character, then the reader will not take the input
import java.util.Scanner;
public class ReaderExample {
public static void main(String[] args) {
try {
Scanner reader = new Scanner(System.in);
char c = reader.next(".").charAt(0);
reader.close();
System.out.print(c);
} catch (Exception ex) {
System.out.println(ex.getMessage());
}
}
}
Suppose you give input "abcd", no input is taken, and the variable c will have Null value.
import java.util.Scanner;
public class Test {
public static void main(String[] args) {
Scanner reader = new Scanner(System.in);
char c = reader.next(".").charAt(0);
}
}
To get only one character char c = reader.next(".").charAt(0);
import java.util.Scanner;
public class userInput{
public static void main(String[] args){
// Creating your scanner with name kb as for keyBoard
Scanner kb = new Scanner(System.in);
String name;
int age;
char bloodGroup;
float height;
// Accepting Inputs from user
System.out.println("Enter Your Name");
name = kb.nextLine(); // for entire line of String including spaces
System.out.println("Enter Your Age");
age = kb.nextInt(); // for taking Int
System.out.println("Enter Your BloodGroup : A/B/O only");
bloodGroup = kb.next().charAt(0); // For character at position 0
System.out.println("Enter Your Height in Meters");
height = kb.nextFloat(); // for taking Float value
// closing your scanner object
kb.close();
// Outputting All
System.out.println("Name : " +name);
System.out.println("Age : " +age);
System.out.println("BloodGroup : " +bloodGroup);
System.out.println("Height : " +height+" m");
}
}
Try this:
char c=S.nextLine().charAt(0);
// Use a BufferedReader to read characters from the console.
import java.io.*;
class BRRead {
public static void main(String args[]) throws IOException
{
char c;
BufferedReader br = new
BufferedReader(new InputStreamReader(System.in));
System.out.println("Enter characters, 'q' to quit.");
// read characters
do {
c = (char) br.read();
System.out.println(c);
} while(c != 'q');
}
}
You should get the String using scanner.next() and invoke String.charAt(0) method on the returned String.
Exmple :
import java.util.Scanner;
public class InputC{
public static void main(String[] args) {
// TODO Auto-generated method stub
// Declare the object and initialize with
// predefined standard input object
Scanner scanner = new Scanner(System.in);
System.out.println("Enter a character: ");
// Character input
char c = scanner.next().charAt(0);
// Print the read value
System.out.println("You have entered: "+c);
}
}
output
Enter a character:
a
You have entered: a
you just need to write this for getting value in char type.
char c = reader.next().charAt(0);
try followings.
Scanner reader = new Scanner(System.in);
char c = reader.next().charAt(0);
this will get a character from the keyboard.
import java.io.*;
class abc // enter class name (here abc is class name)
{
public static void main(String arg[])
throws IOException // can also use Exception
{
BufferedReader z =
new BufferedReader(new InputStreamReader(System.in));
char ch = (char) z.read();
} // PSVM
} // class
Try this
Scanner scanner=new Scanner(System.in);
String s=scanner.next();
char c=s.charAt(0);
Scanner key = new Scanner(System.in);
//shortcut way
char firstChar=key.next().charAt(0);
//how it works;
/*key.next() takes a String as input then,
charAt method is applied on that input (String)
with a parameter of type int (position) that you give to get
that char at that position.
You can simply read it out as:
the char at position/index 0 from the input String
(through the Scanner object key) is stored in var. firstChar (type char) */
//you can also do it in a bit elabortive manner to understand how it exactly works
String input=key.next(); // you can also write key.nextLine to take a String with spaces also
char firstChar=input.charAt(0);
char charAtAnyPos= input.charAt(pos); // in pos you enter that index from where you want to get the char from
By the way, you can't take a char directly as an input. As you can see above, a String is first taken then the charAt(0); is found and stored
Simple solution to read a charachter from user input.
Read a String. Then use charAt(0) over String
Scanner reader = new Scanner(System.in);
String str = reader.next();
char c = str.charAt(0);
That's it.
You could use typecasting:
Scanner sc= new Scanner(System.in);
char a=(char) sc.next();
This way you will take input in String due to the function 'next()' but then it will be converted into character due to the 'char' mentioned in the brackets.
This method of conversion of data type by mentioning the destination data type in brackets is called typecating. It works for me, I hope it works for u :)
Just use...
Scanner keyboard = new Scanner(System.in);
char c = keyboard.next().charAt(0);
This gets the first character of the next input.
To find the index of a character in a given sting, you can use this code:
package stringmethodindexof;
import java.util.Scanner;
import javax.swing.JOptionPane;
/**
*
* #author ASUS//VERY VERY IMPORTANT
*/
public class StringMethodIndexOf {
/**
* #param args the command line arguments
*/
public static void main(String[] args) {
// TODO code application logic here
String email;
String any;
//char any;
//any=JOptionPane.showInputDialog(null,"Enter any character or string to find out its INDEX NUMBER").charAt(0);
//THE AVOBE LINE IS FOR CHARACTER INPUT LOL
//System.out.println("Enter any character or string to find out its INDEX NUMBER");
//Scanner r=new Scanner(System.in);
// any=r.nextChar();
email = JOptionPane.showInputDialog(null,"Enter any string or anything you want:");
any=JOptionPane.showInputDialog(null,"Enter any character or string to find out its INDEX NUMBER");
int result;
result=email.indexOf(any);
JOptionPane.showMessageDialog(null, result);
}
}
The easiest way is, first change the variable to a String and accept the input as a string. Then you can control based on the input variable with an if-else or switch statement as follows.
Scanner reader = new Scanner(System.in);
String c = reader.nextLine();
switch (c) {
case "a":
<your code here>
break;
case "b":
<your code here>
break;
default:
<your code here>
}
I wanted to take a String using Scanner.next() and see if it contains a number or not. I used regex to check if a string contains anything but a number. The regex works correctly if the string is hard coded, but not when taken from keyboard. I expected input of 5 to be detected as a number, but it is not. Please tell me why. My code:
import java.util.Scanner;
public class Error {
public static void main(String[] args) {
Scanner inp = new Scanner(System.in);
int num = 0;
String input = "";
boolean isStringNumber = true;
System.out.println("\nPlease enter a number only...");
input = inp.nextLine();
isStringNumber = input.contains("[^0-9]+");
if (isStringNumber == false) {
System.out.println("\nYou entered a non number " + input);
}
}
}
contains uses a String literal as its argument. Use matches instead
isStringNumber = input.matches("[0-9]+");
or simply
isStringNumber = input.matches("\\d+");
BTW: Scanner has a nextInt method for accepting integer values
instead isStringNumber = input.contains("[^0-9]+");
try isStringNumber = input.matches("[0-9]+");
I'm trying to print a string in reverse. i.e.
hello world
should come out as:
dlrow olleh
But the outcome only shows the reverse of the first word. i.e.
olleh
Any thoughts?
import java.util.Scanner;
public class test {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner input = new Scanner(System.in);
System.out.println("Input a string:");
String s;
s = input.next();
String original, reverse = "";
original = s;
int length = original.length();
for ( int i = length - 1 ; i >= 0 ; i-- )
reverse = reverse + original.charAt(i);
System.out.println("Reverse of entered string is: "+reverse);
input.close();
}
}
Using input.next() only stores the next word in the variable (only "hello"). Try this:
System.out.println("Input a string:");
String s;
s = input.nextLine();
System.out.println("entered: " + s);
The line
s=input.next()
will only take one word.
So to get the whole line 'hello world', you've to use the nextLine() function.
s = input.nextLine();
Your scanner object returns only the next complete token through the input.next() method. A token is considered complete when there is a whitespace character. Use the nextLine() method of the scanner to get the complete input if you are using multiple words.
new StringBuilder("hello world").reverse().toString();
Maybe much more simpler.
use s.nextline() instead of s.next() as s.next() read only first token string
Scanner sc= new Scanner(System.in);
String s = sc.nextLine();
System.out.println(new StringBuilder(s).reverse().toString());
From Scanner javadoc:
public String next()
Finds and returns the next complete token from this scanner. A
complete token is preceded and followed by input that matches the
delimiter pattern. This method may block while waiting for input to
scan, even if a previous invocation of hasNext() returned true.
What happens is that the token delimiter may not be what you're expecting (newline, for instance).
If you wish your program to read the entire line input by the user, you might want to use Scanner.nextLine(), which will read the entire line input by the user, or maybe Scanner.next(String delimiter), which will allow you to enter the desired token delimiter.
Change s = input.next() to s = input.nextLine()
I can't really write some source code but maybe try using two different inputs. After that add each string to it's own variable. After that, reverse them both and add them together as an output.
I am trying to find a way to take a char input from the keyboard.
I tried using:
Scanner reader = new Scanner(System.in);
char c = reader.nextChar();
This method doesn't exist.
I tried taking c as a String. Yet, it would not always work in every case, since the other method I am calling from my method requires a char as an input. Therefore I have to find a way to explicitly take a char as an input.
Any help?
You could take the first character from Scanner.next:
char c = reader.next().charAt(0);
To consume exactly one character you could use:
char c = reader.findInLine(".").charAt(0);
To consume strictly one character you could use:
char c = reader.next(".").charAt(0);
Setup scanner:
reader.useDelimiter("");
After this reader.next() will return a single-character string.
There is no API method to get a character from the Scanner. You should get the String using scanner.next() and invoke String.charAt(0) method on the returned String.
Scanner reader = new Scanner(System.in);
char c = reader.next().charAt(0);
Just to be safe with whitespaces you could also first call trim() on the string to remove any whitespaces.
Scanner reader = new Scanner(System.in);
char c = reader.next().trim().charAt(0);
There are three ways to approach this problem:
Call next() on the Scanner, and extract the first character of the String (e.g. charAt(0)) If you want to read the rest of the line as characters, iterate over the remaining characters in the String. Other answers have this code.
Use setDelimiter("") to set the delimiter to an empty string. This will cause next() to tokenize into strings that are exactly one character long. So then you can repeatedly call next().charAt(0) to iterate the characters. You can then set the delimiter to its original value and resume scanning in the normal way!
Use the Reader API instead of the Scanner API. The Reader.read() method delivers a single character read from the input stream. For example:
Reader reader = new InputStreamReader(System.in);
int ch = reader.read();
if (ch != -1) { // check for EOF
// we have a character ...
}
When you read from the console via System.in, the input is typically buffered by the operating system, and only "released" to the application when the user types ENTER. So if you intend your application to respond to individual keyboard strokes, this is not going to work. You would need to do some OS-specific native code stuff to turn off or work around line-buffering for console at the OS level.
Reference:
How to read a single char from the console in Java (as the user types it)?
You can solve this problem, of "grabbing keyboard input one char at a time" very simply. Without having to use a Scanner all and also not clearing the input buffer as a side effect, by using this.
char c = (char)System.in.read();
If all you need is the same functionality as the C language "getChar()" function then this will work great. The Big advantage of the "System.in.read()" is the buffer is not cleared out after each char your grab. So if you still need all the users input you can still get the rest of it from the input buffer. The "char c = scanner.next().charAt(0);" way does grab the char but will clear the buffer.
// Java program to read character without using Scanner
public class Main
{
public static void main(String[] args)
{
try {
String input = "";
// Grab the First char, also wait for user input if the buffer is empty.
// Think of it as working just like getChar() does in C.
char c = (char)System.in.read();
while(c != '\n') {
//<do your magic you need to do with the char here>
input += c; // <my simple magic>
//then grab the next char
c = (char)System.in.read();
}
//print back out all the users input
System.out.println(input);
} catch (Exception e){
System.out.println(e);
}
}
}
Hope this helpful, and good luck! P.S. Sorry i know this is an older post, but i hope that my answer bring new insight and could might help other people who also have this problem.
This actually doesn't work:
char c = reader.next().charAt(0);
There are some good explanations and references in this question:
Why doesn't the Scanner class have a nextChar method?
"A Scanner breaks its input into tokens using a delimiter pattern", which is pretty open ended. For example when using this
c = lineScanner.next().charAt(0);
for this line of input
"(1 + 9) / (3 - 1) + 6 - 2"
the call to next returns "(1", c will be set to '(', and you'll end up losing the '1' on the next call to next()
Typically when you want to get a character you would like to ignore whitespace. This worked for me:
c = lineScanner.findInLine("[^\\s]").charAt(0);
Reference:
regex to match a single character that is anything but a space
The best way to take input of a character in Scanner class is:
Scanner sca=new Scanner(System.in);
System.out.println("enter a character");
char ch=sca.next().charAt(0);
You should use your custom input reader for faster results instead of extracting first character from reading String.
Link for Custom ScanReader and explanation: https://gist.github.com/nik1010/5a90fa43399c539bb817069a14c3c5a8
Code for scanning Char :
BufferedInputStream br=new BufferedInputStream(System.in);
char a= (char)br.read();
There are two approaches, you can either take exactly one character or strictly one character.
When you use exactly, the reader will take only the first character, irrespective of how many characters you input.
For example:
import java.util.Scanner;
public class ReaderExample {
public static void main(String[] args) {
try {
Scanner reader = new Scanner(System.in);
char c = reader.findInLine(".").charAt(0);
reader.close();
System.out.print(c);
} catch (Exception ex) {
System.out.println(ex.getMessage());
}
}
}
When you give a set of characters as input, say "abcd", the reader will consider only the first character i.e., the letter 'a'
But when you use strictly, the input should be just one character. If the input is more than one character, then the reader will not take the input
import java.util.Scanner;
public class ReaderExample {
public static void main(String[] args) {
try {
Scanner reader = new Scanner(System.in);
char c = reader.next(".").charAt(0);
reader.close();
System.out.print(c);
} catch (Exception ex) {
System.out.println(ex.getMessage());
}
}
}
Suppose you give input "abcd", no input is taken, and the variable c will have Null value.
import java.util.Scanner;
public class Test {
public static void main(String[] args) {
Scanner reader = new Scanner(System.in);
char c = reader.next(".").charAt(0);
}
}
To get only one character char c = reader.next(".").charAt(0);
import java.util.Scanner;
public class userInput{
public static void main(String[] args){
// Creating your scanner with name kb as for keyBoard
Scanner kb = new Scanner(System.in);
String name;
int age;
char bloodGroup;
float height;
// Accepting Inputs from user
System.out.println("Enter Your Name");
name = kb.nextLine(); // for entire line of String including spaces
System.out.println("Enter Your Age");
age = kb.nextInt(); // for taking Int
System.out.println("Enter Your BloodGroup : A/B/O only");
bloodGroup = kb.next().charAt(0); // For character at position 0
System.out.println("Enter Your Height in Meters");
height = kb.nextFloat(); // for taking Float value
// closing your scanner object
kb.close();
// Outputting All
System.out.println("Name : " +name);
System.out.println("Age : " +age);
System.out.println("BloodGroup : " +bloodGroup);
System.out.println("Height : " +height+" m");
}
}
Try this:
char c=S.nextLine().charAt(0);
// Use a BufferedReader to read characters from the console.
import java.io.*;
class BRRead {
public static void main(String args[]) throws IOException
{
char c;
BufferedReader br = new
BufferedReader(new InputStreamReader(System.in));
System.out.println("Enter characters, 'q' to quit.");
// read characters
do {
c = (char) br.read();
System.out.println(c);
} while(c != 'q');
}
}
You should get the String using scanner.next() and invoke String.charAt(0) method on the returned String.
Exmple :
import java.util.Scanner;
public class InputC{
public static void main(String[] args) {
// TODO Auto-generated method stub
// Declare the object and initialize with
// predefined standard input object
Scanner scanner = new Scanner(System.in);
System.out.println("Enter a character: ");
// Character input
char c = scanner.next().charAt(0);
// Print the read value
System.out.println("You have entered: "+c);
}
}
output
Enter a character:
a
You have entered: a
you just need to write this for getting value in char type.
char c = reader.next().charAt(0);
try followings.
Scanner reader = new Scanner(System.in);
char c = reader.next().charAt(0);
this will get a character from the keyboard.
import java.io.*;
class abc // enter class name (here abc is class name)
{
public static void main(String arg[])
throws IOException // can also use Exception
{
BufferedReader z =
new BufferedReader(new InputStreamReader(System.in));
char ch = (char) z.read();
} // PSVM
} // class
Try this
Scanner scanner=new Scanner(System.in);
String s=scanner.next();
char c=s.charAt(0);
Scanner key = new Scanner(System.in);
//shortcut way
char firstChar=key.next().charAt(0);
//how it works;
/*key.next() takes a String as input then,
charAt method is applied on that input (String)
with a parameter of type int (position) that you give to get
that char at that position.
You can simply read it out as:
the char at position/index 0 from the input String
(through the Scanner object key) is stored in var. firstChar (type char) */
//you can also do it in a bit elabortive manner to understand how it exactly works
String input=key.next(); // you can also write key.nextLine to take a String with spaces also
char firstChar=input.charAt(0);
char charAtAnyPos= input.charAt(pos); // in pos you enter that index from where you want to get the char from
By the way, you can't take a char directly as an input. As you can see above, a String is first taken then the charAt(0); is found and stored
Simple solution to read a charachter from user input.
Read a String. Then use charAt(0) over String
Scanner reader = new Scanner(System.in);
String str = reader.next();
char c = str.charAt(0);
That's it.
You could use typecasting:
Scanner sc= new Scanner(System.in);
char a=(char) sc.next();
This way you will take input in String due to the function 'next()' but then it will be converted into character due to the 'char' mentioned in the brackets.
This method of conversion of data type by mentioning the destination data type in brackets is called typecating. It works for me, I hope it works for u :)
Just use...
Scanner keyboard = new Scanner(System.in);
char c = keyboard.next().charAt(0);
This gets the first character of the next input.
To find the index of a character in a given sting, you can use this code:
package stringmethodindexof;
import java.util.Scanner;
import javax.swing.JOptionPane;
/**
*
* #author ASUS//VERY VERY IMPORTANT
*/
public class StringMethodIndexOf {
/**
* #param args the command line arguments
*/
public static void main(String[] args) {
// TODO code application logic here
String email;
String any;
//char any;
//any=JOptionPane.showInputDialog(null,"Enter any character or string to find out its INDEX NUMBER").charAt(0);
//THE AVOBE LINE IS FOR CHARACTER INPUT LOL
//System.out.println("Enter any character or string to find out its INDEX NUMBER");
//Scanner r=new Scanner(System.in);
// any=r.nextChar();
email = JOptionPane.showInputDialog(null,"Enter any string or anything you want:");
any=JOptionPane.showInputDialog(null,"Enter any character or string to find out its INDEX NUMBER");
int result;
result=email.indexOf(any);
JOptionPane.showMessageDialog(null, result);
}
}
The easiest way is, first change the variable to a String and accept the input as a string. Then you can control based on the input variable with an if-else or switch statement as follows.
Scanner reader = new Scanner(System.in);
String c = reader.nextLine();
switch (c) {
case "a":
<your code here>
break;
case "b":
<your code here>
break;
default:
<your code here>
}