Given I have the following structure already existing:
private void acceptInner(final Path path) throws IOException {
String newId = FileUtils.readAndModifyFileEntry(StageRename.ID_FILE, "id",
idString -> String.valueOf(Integer.parseInt(idString) + 1));
BaseUtils.moveKeepExtension(path, StageRename.OUTPUT_DIRECTORY, newId);
}
Where FileUtils.readAndModifyFileEntry is declared as:
public static String readAndModifyFileEntry(final Path path, final String entryKey
, final UnaryOperator<String> operator) throws IOException { ... }
Now I want to move the operator that increases a string value as an integer by one, to a new helper class, I have made two proposals:
final public class MapperUtils {
private MapperUtils() {
throw new UnsupportedOperationException();
}
public static String incrementAsInt(final String input) {
return String.valueOf(Integer.parseInt(input) + 1);
}
public static UnaryOperator<String> incrementAsIntOperator() {
return input -> String.valueOf(Integer.parseInt(input) + 1);
}
}
Which one would be better, usages are below:
String newId = FileUtils.readAndModifyFileEntry(StageRename.ID_FILE, "id",
MapperUtils::incrementAsInt);
versus
String newId = FileUtils.readAndModifyFileEntry(StageRename.ID_FILE, "id",
MapperUtils.incrementAsIntOperator());
Or should I keep both?
One of the advantages of the latter is that I can chain the operator with andThen() or compose(), but are there any disadvantages to it?
For more reference, I can use the following:
((UnaryOperator<String>)MapperUtils::incrementAsInt).andThen(/*something*/)
To manually cast it to an operator, but it really looks ugly. However if I provide both, does it then create an unwanted method explosion on the codebase?
If you keep both, then the incrementAsIntOperator() one can be written as
public static UnaryOperator<String> incrementAsIntOperator() {
return input -> incrementAsInt(input);
}
Which tells me that your second one is just a more specialized version of the first one.
I would keep the first method, as that one is more re-usable, and get rid of the second.
Whether or not providing both gives you an "unwanted method explosion" or not is really up to you. Besides that, I can't see any disadvantages of it. Of course you could use this also:
String newId = FileUtils.readAndModifyFileEntry(StageRename.ID_FILE, "id",
input -> MapperUtils.incrementAsInt(input));
Related
The target class is:
class Example{
public void m(){
System.out.println("Hello" + 1);
}
}
I want to get the full string of MethodInvocation "System.out.println("Hello" + 1)" for some regex check. How to write?
public class Rule extends BaseTreeVisitor implements JavaFileScanner {
#Override
public void visitMethodInvocation(MethodInvocationTree tree) {
//get the string of MethodInvocation
//some regex check
super.visitMethodInvocation(tree);
}
}
I wrote some code inspection rules using eclipse jdt and idea psi whose expression tree node has these attributes. I wonder why sonar's just has first and last token instead.
Thanks!
An old question, but I have a solution.
This works for any sort of tree.
#Override
public void visitMethodInvocation(MethodInvocationTree tree) {
int firstLine = tree.firstToken().line();
int lastLine = tree.lastToken().line();
String rawText = getRelevantLines(firstLine, lastLine);
// do your thing here with rawText
}
private String getRelevantLines(int startLine, int endLine) {
StringBuilder builder = new StringBuilder();
context.getFileLines().subList(startLine, endLine).forEach(builder::append);
return builder.toString();
}
If you want to refine further, you can also use firstToken().column or perhaps use the method name in your regex.
If you want more lines/bigger scope, just use the parent of that tree tree.parent()
This will also handle cases where the expression/params/etc span multiple lines.
There might be a better way... but I don't know of any other way. May update if I figure out something better.
Modifying a local variable in forEach gives a compile error:
Normal
int ordinal = 0;
for (Example s : list) {
s.setOrdinal(ordinal);
ordinal++;
}
With Lambda
int ordinal = 0;
list.forEach(s -> {
s.setOrdinal(ordinal);
ordinal++;
});
Any idea how to resolve this?
Use a wrapper
Any kind of wrapper is good.
With Java 10+, use this construct as it's very easy to setup:
var wrapper = new Object(){ int ordinal = 0; };
list.forEach(s -> {
s.setOrdinal(wrapper.ordinal++);
});
With Java 8+, use either an AtomicInteger:
AtomicInteger ordinal = new AtomicInteger(0);
list.forEach(s -> {
s.setOrdinal(ordinal.getAndIncrement());
});
... or an array:
int[] ordinal = { 0 };
list.forEach(s -> {
s.setOrdinal(ordinal[0]++);
});
Note: be very careful if you use a parallel stream. You might not end up with the expected result. Other solutions like Stuart's might be more adapted for those cases.
For types other than int
Of course, this is still valid for types other than int.
For instance, with Java 10+:
var wrapper = new Object(){ String value = ""; };
list.forEach(s->{
wrapper.value += "blah";
});
Or if you're stuck with Java 8 or 9, use the same kind of construct as we did above, but with an AtomicReference...
AtomicReference<String> value = new AtomicReference<>("");
list.forEach(s -> {
value.set(value.get() + s);
});
... or an array:
String[] value = { "" };
list.forEach(s-> {
value[0] += s;
});
This is fairly close to an XY problem. That is, the question being asked is essentially how to mutate a captured local variable from a lambda. But the actual task at hand is how to number the elements of a list.
In my experience, upward of 80% of the time there is a question of how to mutate a captured local from within a lambda, there's a better way to proceed. Usually this involves reduction, but in this case the technique of running a stream over the list indexes applies well:
IntStream.range(0, list.size())
.forEach(i -> list.get(i).setOrdinal(i));
If you only need to pass the value from the outside into the lambda, and not get it out, you can do it with a regular anonymous class instead of a lambda:
list.forEach(new Consumer<Example>() {
int ordinal = 0;
public void accept(Example s) {
s.setOrdinal(ordinal);
ordinal++;
}
});
As the used variables from outside the lamda have to be (implicitly) final, you have to use something like AtomicInteger or write your own data structure.
See
https://docs.oracle.com/javase/tutorial/java/javaOO/lambdaexpressions.html#accessing-local-variables.
An alternative to AtomicInteger is to use an array (or any other object able to store a value):
final int ordinal[] = new int[] { 0 };
list.forEach ( s -> s.setOrdinal ( ordinal[ 0 ]++ ) );
But see the Stuart's answer: there might be a better way to deal with your case.
Yes, you can modify local variables from inside lambdas (in the way shown by the other answers), but you should not do it. Lambdas have been made for functional style of programming and this means: No side effects. What you want to do is considered bad style. It is also dangerous in case of parallel streams.
You should either find a solution without side effects or use a traditional for loop.
If you are on Java 10, you can use var for that:
var ordinal = new Object() { int value; };
list.forEach(s -> {
s.setOrdinal(ordinal.value);
ordinal.value++;
});
You can wrap it up to workaround the compiler but please remember that side effects in lambdas are discouraged.
To quote the javadoc
Side-effects in behavioral parameters to stream operations are, in general, discouraged, as they can often lead to unwitting violations of the statelessness requirement
A small number of stream operations, such as forEach() and peek(), can operate only via side-effects; these should be used with care
I had a slightly different problem. Instead of incrementing a local variable in the forEach, I needed to assign an object to the local variable.
I solved this by defining a private inner domain class that wraps both the list I want to iterate over (countryList) and the output I hope to get from that list (foundCountry). Then using Java 8 "forEach", I iterate over the list field, and when the object I want is found, I assign that object to the output field. So this assigns a value to a field of the local variable, not changing the local variable itself. I believe that since the local variable itself is not changed, the compiler doesn't complain. I can then use the value that I captured in the output field, outside of the list.
Domain Object:
public class Country {
private int id;
private String countryName;
public Country(int id, String countryName){
this.id = id;
this.countryName = countryName;
}
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public String getCountryName() {
return countryName;
}
public void setCountryName(String countryName) {
this.countryName = countryName;
}
}
Wrapper object:
private class CountryFound{
private final List<Country> countryList;
private Country foundCountry;
public CountryFound(List<Country> countryList, Country foundCountry){
this.countryList = countryList;
this.foundCountry = foundCountry;
}
public List<Country> getCountryList() {
return countryList;
}
public void setCountryList(List<Country> countryList) {
this.countryList = countryList;
}
public Country getFoundCountry() {
return foundCountry;
}
public void setFoundCountry(Country foundCountry) {
this.foundCountry = foundCountry;
}
}
Iterate operation:
int id = 5;
CountryFound countryFound = new CountryFound(countryList, null);
countryFound.getCountryList().forEach(c -> {
if(c.getId() == id){
countryFound.setFoundCountry(c);
}
});
System.out.println("Country found: " + countryFound.getFoundCountry().getCountryName());
You could remove the wrapper class method "setCountryList()" and make the field "countryList" final, but I did not get compilation errors leaving these details as-is.
To have a more general solution, you can write a generic Wrapper class:
public static class Wrapper<T> {
public T obj;
public Wrapper(T obj) { this.obj = obj; }
}
...
Wrapper<Integer> w = new Wrapper<>(0);
this.forEach(s -> {
s.setOrdinal(w.obj);
w.obj++;
});
(this is a variant of the solution given by Almir Campos).
In the specific case this is not a good solution, as Integer is worse than int for your purpose, anyway this solution is more general I think.
I have a java class in which I store an Enum.(shown at the bottom of this question) In this enum, I have a method named toCommaSeperatedString() who returns a comma separated String of the enums values. I am using a StringBuilder after reading some information on performance in this question here.
Is the way I am converting this enum's values into a commaSeperatedString the most efficient way of doing so, and if so, what would be the most efficient way to remove the extra comma at the last char of the String?
For example, my method returns 123, 456, however I would prefer 123, 456. If I wanted to return PROPERTY1, PROPERTY2 I could easily use Apache Commons library StringUtils.join(), however, I need to get one level lower by calling the getValue method when I am iterating through the String array.
public class TypeEnum {
public enum validTypes {
PROPERTY1("123"),
PROPERTY2("456");
private String value;
validTypes(String value) {
this.value = value;
}
public String getValue() {
return value;
}
public static boolean contains(String type) {
for (validTypes msgType : validTypes.values()) {
if (msgType.value.equals(type)) {
return true;
}
}
return false;
}
public static String toCommaSeperatedString() {
StringBuilder commaSeperatedValidMsgTypes = new StringBuilder();
for(validTypes msgType : validTypes.values()) {
commaSeperatedValidMsgTypes.append(msgType.getValue() + ", ");
}
return commaSeperatedValidMsgTypes.toString();
}
}
}
I wouldn't worry much about efficiency. It's simple enough to do this that it will be fast, provided you don't do it in a crazy way. If this is the most significant performance bottleneck in your code, I would be amazed.
I'd do it something like this:
return Arrays.stream(TypeEnum.values())
.map(t -> t.value)
.collect(Collectors.joining(','));
Cache it if you want; but that's probably not going to make a huge difference.
A common pattern for the trailing comma problem I see is something like
String[] values = {"A", "B", "C"};
boolean is_first = true;
StringBuilder commaSeperatedValidMsgTypes = new StringBuilder();
for(String value : values){
if(is_first){
is_first = false;
}
else{
commaSeperatedValidMsgTypes.append(',');
}
commaSeperatedValidMsgTypes.append(value);
}
System.out.println(commaSeperatedValidMsgTypes.toString());
which results in
A,B,C
Combining this with the answers about using a static block to initialize a static final field will probably give the best performance.
The most efficient code is code that doesn't run. This answer can't ever change, so run that code as you have it once when creating the enums. Take the hit once, return the calculated answer every other time somebody asks for it. The savings in doing that would be far greater in the long term over worrying about how specifically to construct the string, so use whatever is clearest to you (write code for humans to read).
For example:
public enum ValidTypes {
PROPERTY1("123"),
PROPERTY2("345");
private final static String asString = calculateString();
private final String value;
private static String calculateString() {
return // Do your work here.
}
ValidTypes(final String value) {
this.value = value;
}
public static String toCommaSeparatedString() {
return asString;
}
}
If you have to call this static method thousand and thousand of times on a short period, you may worry about performance and you should first check that this has a performance cost.
The JVM performs at runtime many optimizations.
So finally you could write more complex code without added value.
Anyway, the actual thing that you should do is storing the String returned by toCommaSeperatedString and returned the same instance.
Enum are constant values. So caching them is not a problem.
You could use a static initializer that values a static String field.
About the , character, just remove it after the loop.
public enum validTypes {
PROPERTY1("123"), PROPERTY2("456");
private static String valueSeparatedByComma;
static {
StringBuilder commaSeperatedValidMsgTypes = new StringBuilder();
for (validTypes msgType : validTypes.values()) {
commaSeperatedValidMsgTypes.append(msgType.getValue());
commaSeperatedValidMsgTypes.append(",");
}
commaSeperatedValidMsgTypes.deleteCharAt
(commaSeperatedValidMsgTypes.length()-1);
valueSeparatedByComma = commaSeperatedValidMsgTypes.toString();
}
public static String getvalueSeparatedByComma() {
return valueSeparatedByComma;
}
I usually add a static method on the enum class itself:
public enum Animal {
CAT, DOG, LION;
public static String possibleValues() {
return Arrays.stream(Animal.values())
.map(Enum::toString)
.collect(Collectors.joining(","));
}
}
So I can use it like String possibleValues = Animal.possibleValues();
Most people understand the innate benefits that enum brings into a program verses the use of int or String. See here and here if you don't know. Anyway, I came across a problem that I wanted to solve that kind of is on the same playing field as using int or String to represent a constant instead of using an enum. This deals specifically with String.format(...).
With String.format, there seems to be a large opening for programmatic error that isn't found at compile-time. This can make fixing errors more complex and / or take longer.
This was the issue for me that I set out to fix (or hack a solution). I came close, but I am not close enough. For this problem, this is more certainly over-engineered. I understand that, but I just want to find a good compile-time solution to this, that provides the least amount of boiler-plate code.
I was writing some non-production code just to write code with the following rules.
Abstraction was key.
Readability was very important
Yet the simplest way to the above was preferred.
I am running on...
Java 7 / JDK 1.7
Android Studio 0.8.2
These are unsatisfactory
Is there a typesafe alternative to String.format(...)
How to get string.format to complain at compile time
My Solution
My solution uses the same idea that enums do. You should use enum types any time you need to represent a fixed set of constants...data sets where you know all possible values at compile time(docs.oracle.com). The first argument in String.format seems to fit that bill. You know the whole string beforehand, and you can split it up into several parts (or just one), so it can be represented as a fixed set of "constants".
By the way, my project is a simple calculator that you probably seen online already - 2 input numbers, 1 result, and 4 buttons (+, -, ×, and ÷). I also have a second duplicate calculator that has only 1 input number, but everything else is the same
Enum - Expression.java & DogeExpression.java
public enum Expression implements IExpression {
Number1 ("%s"),
Operator (" %s "),
Number2 ("%s"),
Result (" = %s");
protected String defaultFormat;
protected String updatedString = "";
private Expression(String format) { this.defaultFormat = format; }
// I think implementing this in ever enum is a necessary evil. Could use a switch statement instead. But it would be nice to have a default update method that you could overload if needed. Just wish the variables could be hidden.
public <T> boolean update(T value) {
String replaceValue
= this.equals(Expression.Operator)
? value.toString()
: Number.parse(value.toString()).toString();
this.updatedString = this.defaultFormat.replace("%s", replaceValue);
return true;
}
}
...and...
public enum DogeExpression implements IExpression {
Total ("Wow. Such Calculation. %s");
// Same general code as public enum Expression
}
Current Issue
IExpression.java - This is a HUGE issue. Without this fixed, my solution cannot work!!
public interface IExpression {
public <T> boolean update(T Value);
class Update { // I cannot have static methods in interfaces in Java 7. Workaround
public static String print() {
String replacedString = "";
// for (Expression expression : Expression.values()) { // ISSUE!! Switch to this for Expression
for (DogeExpression expression : DogeExpression.values()) {
replacedString += expression.updatedString;
}
return replacedString;
}
}
}
So Why Is This An Issues
With IExpression.java, this had to hacked to work with Java 7. I feel that Java 8 would have played a lot nicer with me. However, the issue I am having is paramount to getting my current implementation working The issue is that IExpression does not know which enum to iterate through. So I have to comment / uncomment code to get it to work now.
How can I fix the above issue??
How about something like this:
public enum Operator {
addition("+"),
subtraction("-"),
multiplication("x"),
division("÷");
private final String expressed;
private Operator(String expressed) { this.expressed = expressed; }
public String expressedAs() { return this.expressed; }
}
public class ExpressionBuilder {
private Number n1;
private Number n2;
private Operator o1;
private Number r;
public void setN1(Number n1) { this.n1 = n1; }
public void setN2(Number n2) { this.n2 = n2; }
public void setO1(Operator o1) { this.o1 = o1; }
public void setR(Number r) { this.r = r; }
public String build() {
final StringBuilder sb = new StringBuilder();
sb.append(format(n1));
sb.append(o1.expressedAs());
sb.append(format(n2));
sb.append(" = ");
sb.append(format(r));
return sb.toString();
}
private String format(Number n) {
return n.toString(); // Could use java.text.NumberFormat
}
}
I'm writing a small library.
public class MyClass {
public static String doSomethingWithString(final String s) {
new MyClass().doSomething(s);
}
public String doSomething(final String s) {
return null;
}
}
Or I can do like this.
public class MyClass {
public static String doSomethingWithString(final String s) {
return null;
}
public String doSomething(final String s) {
return doSomethingWithString(s);
}
}
Which style is preferable? Are they same?
UPDATE
Thank you for comments and answers.
Here are two classes.
public class IdEncoder {
private static String block(final long decoded) {
final StringBuilder builder = new StringBuilder(Long.toString(decoded));
builder.append(Integer.toString(
ThreadLocalRandom.current().nextInt(9) + 1)); // 1-9
builder.append(Integer.toString(
ThreadLocalRandom.current().nextInt(9) + 1)); // 1-9
builder.reverse();
return Long.toString(
Long.parseLong(builder.toString()), Character.MAX_RADIX);
}
public static String encodeLong(final long decoded) {
return block(decoded >>> 0x20) + "-" + block(decoded & 0xFFFFFFFFL);
}
public String encode(final long decoded) {
return encodeLong(decoded);
}
}
And another style.
public class IdDecoder {
public static long decodeLong(final String encoded) {
return new IdDecoder().decode(encoded);
}
public long decode(final String encoded) {
final int index = encoded.indexOf('-');
if (index == -1) {
throw new IllegalArgumentException("wrong encoded: " + encoded);
}
return (block(encoded.substring(0, index)) << 32)
| (block(encoded.substring(index + 1)));
}
private long block(final String encoded) {
final StringBuilder builder = new StringBuilder(
Long.toString(Long.parseLong(encoded, Character.MAX_RADIX)));
builder.reverse();
builder.deleteCharAt(builder.length() - 1);
builder.deleteCharAt(builder.length() - 1);
return Long.parseLong(builder.toString());
}
}
If you are just picking between these 2 options, take the second one.
The reason is the first requires you to allocate a new dummy object on the heap just to call a method. If there is truly no other difference, don't waste the time and space and just call the static method from the class.
The second is more akin to a static Utility function, which are a fine coding practice.
When writing a library, ease of use dramatically trumps general best practices. Your method should be static if it doesn't make sense for a user to instantiate something in order to access it. However often it is actually much cleaner and more powerful for a method to be part of an object, because it allows the user (as well as the library writer) to override it in child classes.
In a sense, you aren't actually asking a programming question, but a UX question. Ask yourself how your users would best benefit from accessing your code, and implement it that way. As a good benchmark, look at the Guava API; it consists of many static utility classes, but just as many classes and interfaces designed to be easily extended. Do what you think is best.