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"or" condition in embedded document java

What is the correct syntax for creating $or condition in embedded document in MongoDB Java driver?
Is it actually possible to get a cursor to embedded documents?
Suppose I have the following document:
{
statuses: [{
{
streamName: A
}{
statusA: 0
}{
statusB: 1
}
},
{
{
streamName: B
}{
statusA: 0
}{
statusB: 1
}
}]
}
I would also like to get cursor to sub documents (in array of statuses) that has at least one status bigger than 0.
This is how I did it but it didn't work:
List<BasicDBObject> obj = new ArrayList<BasicDBObject>();
DBObject query = new BasicDBObject();
obj.add(new BasicDBObject ("statuses",
new BasicDBObject ("statusA",
new BasicDBObject ("$gt",0 ) )));
obj.add(new BasicDBObject ("statuses",
new BasicDBObject ("statusB" ,
new BasicDBObject ("$gt",0 ) )));
query.put("$or",obj)
db.find(collectionName,query)
I didn't find any documentation on that.

What you have translates to
{ "$or" : [ { "statuses" : { "statusA" : { "$gt" : 0}}} , { "statuses" : { "statusB" : { "$gt" : 0}}}]}
which is used for whole document comparison.
For comparing fields inside an embedded arrays/doc you've to use dot notation.
{ "$or" : [ { "statuses.statusA" : { "$gt" : 0}} , { "statuses.statusB" : { "$gt" : 0}}]}
The equliavent java code is below
List<BasicDBObject> obj = new ArrayList<BasicDBObject>();
DBObject query = new BasicDBObject();
obj.add(new BasicDBObject ("statuses.statusA", new BasicDBObject ("$gt",0 ) ));
obj.add(new BasicDBObject ("statuses.statusB" , new BasicDBObject ("$gt",0 ) ));
query.put("$or",obj);
Alternatively you can use $elemMatch to run matches on embedded arrays. Similar to what you've but $elemMatch applies condition to each fields.
Something like
{ "statuses" : { "$elemMatch" : { "$or" : [ { "statusA" : { "$gt" : 0}} , { "statusB" : { "$gt" : 0}}]}}}
Java Code
BasicDBList obj = new BasicDBList();
obj.add(new BasicDBObject ("statusA",new BasicDBObject ("$gt",0 ) ));
obj.add(new BasicDBObject ("statusB",new BasicDBObject ("$gt",0 ) ));
DBObject query = new BasicDBObject("statuses", new BasicDBObject("$elemMatch", new BasicDBObject("$or",obj)));
Count the no of matching occurrences.
Bson count = new Document("statuses", Document.parse("{$size:{\n" +
" $filter: {\n" +
" input: \"$statuses\",\n" +
" as: \"status\",\n" +
" cond: { \"$or\" : [ {$gt:[\"$$status.statusA\", 0]} , {$gt:[\"$$status.statusB\", 0]}]}\n" +
" }\n" +
" }}"));
Bson project = new Document("$project", count);
col.aggregate(Arrays.asList(project));

Get Average from Mongo Collection using Aggrerate

I am trying to learn how to use the Mongo in Java and have been able to make some simple queries but I have been having trouble with the aggregate operator.
The document structure is a simple one, as the following:
{
"_id" : ObjectId("57dbe94f0507a4d8710ac5b2"),
"name" : "Name1",
"age" : 23
}
{
"_id" : ObjectId("57dbe9750507a4d8710ac5b3"),
"name" : "Name2",
"age" : "String for examble"
}
{
"_id" : ObjectId("57dbee630507a4d8710ac5b5"),
"name" : "Name3",
"age" : 24
}
All I want to do is get the average of the ages in the collection ( name example ).
Simply using mongo I can get the desirable result with the following consult:
db.example.aggregate([
{
$group: {
_id: null,
averageAge: { $avg: "$age" }
}
}
]);
I have tried the following:
BasicDBObject groupFields = new BasicDBObject("_id", "null");
BasicDBObject media = new BasicDBObject("$avg", "$age");
groupFields.put("mediaIdade", media);
BasicDBObject group = new BasicDBObject("$group", groupFields );
AggregateIterable<org.bson.Document> agregate = db.getCollection("exemplo").aggregate(Arrays.asList (group));
Which is almost a direct translation but got a "java.lang.NoSuchMethodError: org.bson.codecs.BsonTypeClassMap.keys()Ljava/util/Set;" , unsurprisingly.
But I cannot translate that to Java. I have checked and found this question but could not understand it due to the use of opperators such as $unwind. So I'm trying to make query as simple as possible to better understand how the Java framework for aggregation works.
Can someone help?

Try something like this.
MongoCollection<Document> dbCollection = db.getCollection("example", Document.class);
AggregateIterable<org.bson.Document> aggregate = dbCollection.aggregate(Arrays.asList(Aggregates.group("_id", new BsonField("averageAge", new BsonDocument("$avg", new BsonString("$age"))))));
Document result = aggregate.first();
double age = result.getDouble("averageAge");
Input:
{ "_id" : ObjectId("58136d6ed96cc299c224d529"), "name" : "Name1", "age" : 23 }
{ "_id" : ObjectId("58136d6ed96cc299c224d52a"), "name" : "Name2", "age" : 26 }
{ "_id" : ObjectId("58136d6ed96cc299c224d52b"), "name" : "Name3", "age" : 24 }
Output:
24.333333333333332

I noticed a small typo in your code:
db.getCollection("exemplo").aggregate(Arrays.asList (group));
Should be example instead of examplo
Also the easiest way to translate working mongo expression is using Document.parse method.
In your case it could be:
db.getCollection("exemplo").aggregate(Arrays.asList(
Document.parse("{ $group: { _id: null, averageAge: { $avg: '$age' } } }")
));
Your impl also almost correct, two minor issues:
replace "null" string with just null value
Use "averageAge" instead of "mediaIdade"
BasicDBObject groupFields = new BasicDBObject("_id", null);
BasicDBObject media = new BasicDBObject("$avg", "$age");
groupFields.put("averageAge", media);
BasicDBObject group = new BasicDBObject("$group", groupFields );
AggregateIterable<org.bson.Document> agregate = db.getCollection("exemple").aggregate(Arrays.asList (group));
To get result:
agregate.first().getDouble("averageAge");

Try this:
DBObject groupFields = new BasicDBObject( "_id", 0);
groupFields.put("average", new BasicDBObject( "$avg", "$age"));
DBObject group = new BasicDBObject("$group", groupFields);
AggregationOutput output = db.getCollection("exemplo").aggregate(group);
Iterable<DBObject> list = output.results();
If required add a filter to the query you can add a match parameter:
DBObject match = new BasicDBObject();
match.put("age", new BasicDBObject("$gte", 25));
DBObject groupFields = new BasicDBObject( "_id", 0);
groupFields.put("average", new BasicDBObject( "$avg", "$age"));
DBObject group = new BasicDBObject("$group", groupFields);
AggregationOutput output = db.getCollection("exemplo").aggregate(match, group);
Iterable<DBObject> list = output.results();

How do I group the results of mongodb query and implement in Java?

I have a collection in a Mongo database that looks like this:
{
"_id" : ObjectId("561b42d4e4b0d4227d011d2c"),
"product_related_data" : {
"depth" : 6,
"height" : 23,
"product_barcode" : "54491472",
"product_name" : "xyz product",
"product_uuid" : "009b9846-b3ad-49f7-a7a0-d35a04f83480",
"width" : 6
},
"sensostrip_data" : {
"barcode" : "130150208299",
"battery_level" : 2.894
},
"stock_related_data" : {
"calculated_max_product_percentage" : 15.625,
"calculated_min_product_percentage" : 12.5,
"current_stock" : 2,
"max_stock" : 6,
"stock_difference_percentage" : 0,
"stock_difference_value" : 0,
"stock_percentage" : 37.5
},
"store_data" : {
"city_uuid" : "cbb4dfe8-172b-11e4-a1f0-00163ed23ec2",
"ip" : "10.0.1.1",
"retailer_uuid" : "8c33c32c-5903-11e4-a1f0-00163ed23ec2",
"store_name" : "xyz store",
"store_uuid" : "15a6cc90-081f-11e5-b213-001e6745ff8d"
},
"time" : {
"check_date" : "2015-10-11 11:53:55",
"previous_check_date" : "2015-10-11 11:48:57"
},
"id" : "6be54bef-0aa3-456c-b912-1731f8154e7d"
}
The mongo query I'm currently executing returns all the documents for a list of store_uuid's and for a product_uuid, and looks like this:
db.readings
.find({ $and:[ {"store_data.store_uuid": {$in:["15a6cc90-081f-11e5-b213-001e6745ff8d","217b983b-5904-11e4-a1f0-00163ed23ec2","5337d78d-5904-11e4-a1f0-00163ed23ec2"]}}
,{"product_related_data.product_uuid": "f44aa29d-09ce-4902-bf12-d45d44b3dfd0"}]})
My current Java implementation (where I make use of projection) looks like this:
DBCollection table = databaseConncetion().getCollection("readings");
BasicDBObject sensorReturn = new BasicDBObject("sensostrip_data.barcode",1);
BasicDBObject clause1 = new BasicDBObject("store_data.store_uuid", new BasicDBObject("$in", StoreIds));
BasicDBObject clause2 = new BasicDBObject("product_related_data.product_uuid", productId);
BasicDBList and = new BasicDBList();
and.add(clause1);
and.add(clause2);
DBObject query = new BasicDBObject("$and", and);
DBCursor cursor = table.find(query, sensorReturn
.append("stock_related_data.stock_percentage",1)
.append("store_data.store_uuid",1)
.append("time.check_date", 1))
.sort(new BasicDBObject("time.check_date", -1))
.limit(100);
However I need this query to group the results for the latest check_date by barcode

The aggregation framework is at your disposal. Running the following aggregation pipeline will give you the desired result:
Mongo shell:
pipeline = [
{
"$match": {
"store_data.store_uuid": {
"$in": [
"15a6cc90-081f-11e5-b213-001e6745ff8d",
"217b983b-5904-11e4-a1f0-00163ed23ec2",
"5337d78d-5904-11e4-a1f0-00163ed23ec2"
]
},
"product_related_data.product_uuid": "f44aa29d-09ce-4902-bf12-d45d44b3dfd0"
}
},
{ "$sort": { "time.check_date": -1 } },
{
"$group": {
"_id": "$sensostrip_data.barcode",
"stock_percentage": { "$first": "$stock_related_data.stock_percentage" },
"store_uuid": { "$first": "$store_data.store_uuid" },
"check_date": { "$first": "$time.check_date" }
}
},
{ "$limit": 100 }
];
db.readings.aggregate(pipeline);
Java test implementation
public class JavaAggregation {
public static void main(String args[]) throws UnknownHostException {
MongoClient mongo = new MongoClient();
DB db = mongo.getDB("test");
DBCollection coll = db.getCollection("readings");
// create the pipeline operations, first with the $match
DBObject match = new BasicDBObject("$match",
new BasicDBObject("store_data.store_uuid", new BasicDBObject("$in", StoreIds))
.append("product_related_data.product_uuid", productId)
);
// sort pipeline
DBObject sort = new BasicDBObject("$sort",
new BasicDBObject("time.check_date", -1)
);
// build the $group operations
DBObject groupFields = new BasicDBObject( "_id", "$sensostrip_data.barcode"); // group by barcode
groupFields.put("stock_percentage", new BasicDBObject( "$first", "$stock_related_data.stock_percentage")); // get the first when ordered documents are grouped
groupFields.put("store_uuid", new BasicDBObject( "$first", "$store_data.store_uuid"));
groupFields.put("check_date", new BasicDBObject( "$first", "$time.check_date"));
// append any other necessary fields
DBObject group = new BasicDBObject("$group", groupFields);
// limit step
DBObject limit = new BasicDBObject("$limit", 100);
// put all together
List<DBObject> pipeline = Arrays.asList(match, sort, group, limit);
AggregationOutput output = coll.aggregate(pipeline);
for (DBObject result : output.results()) {
System.out.println(result);
}
}
}

MongoDb $setIntersection with Java Driver

i want to build the following mongodb-json-query with the java driver from mongodb:
db.item.aggregate([
{'$project': { attr: {
$setIntersection:["$structureAttributeValueIdList", [ObjectId("54bfba08ef6643acaa5be2c9")]]
}, _id : 0, document: "$$ROOT"
}},
{ "$unwind": "$attr" },
{ "$match": { "document.stateDeleted" : 0 } }]);
What I have so far ist this:
DBObject intersection =
new BasicDBObject( "$setIntersection", ???? );
DBObject fields = new BasicDBObject( "attributes", intersection );
fields.put( " document", "$$ROOT" );
fields.put( "_id", 0 );
DBObject project = new BasicDBObject( "$project", fields );
DBObject unwind = new BasicDBObject( "$unwind", "attributes" );
DBObject match =
new BasicDBObject( "$match", new BasicDBObject( "document.stateDeleted", 0 ) );
List< DBObject > pipeline = Arrays.asList( project, unwind, match );
AggregationOutput output = operations.getCollection( "item" ).aggregate( pipeline );
But i dont know how to build the setIntersection-Part!
Any help?
Thanks...

Found it by myself ... very easy when you know how
BasicDBList intersectionList = new BasicDBList();
intersectionList.add( "$structureAttributeValueIdList" );
intersectionList.add( objectIdDBList );
DBObject intersection = new BasicDBObject( "$setIntersection", intersectionList );

How to calculate unique elements in collections?

I have collection like
id : 1, url : youtube.com
also one url can be many times,
I need get whole collections and count unique elements
like
youtube 10
google 8
lycos 5
here is the code
public List<URLEntity> findAll() {
List<URLEntity> list = new ArrayList<URLEntity>();
String sort = "searchDate";
String order = "desc";
DBObject sortCriteria = new BasicDBObject(sort, "desc".equals(order) ? -1 : 1);
BasicDBObject query = new BasicDBObject();
DBCursor cursor = mongoCoreService.getDomainCollection().find(query).sort(sortCriteria);
try {
while (cursor.hasNext()) {
DBObject document = cursor.next();
URLEntity entity = new URLEntity();
entity = Converter.toObject(URLEntity.class, document);
list.add(entity);
}
} finally {
cursor.close();
}
return list;
}
thanks

You can achieve this by using the aggregate framework from MongoDB.
db.yourcollection.aggregate({ $group: { _id: '$url', total: {$sum: 1} }})
You'll obtain something like this, that you can manipulate in JAVA:
{
"result" : [
{
"_id" : "youtube.com",
"total" : 10
},
{
"_id" : "google.com",
"total" : 8
},
{
"_id" : "lycos",
"total" : 5
}
],
"ok" : 1
}

Today I found and test answer in java, here is a code
DBCollection mycoll= db.getCollection("domain");
DBObject fields = new BasicDBObject("domain", 1);
DBObject project = new BasicDBObject("$project", fields );
// Now the $group operation
DBObject groupFields = new BasicDBObject( "_id", "$domain");
groupFields.put("total", new BasicDBObject( "$sum", 1));
DBObject group = new BasicDBObject("$group", groupFields);
// run aggregation
AggregationOutput output = mycoll.aggregate(project, group);
System.out.println(output.getCommand().toString());
for (DBObject dbObject : output.results()) {
System.out.println(dbObject);
}