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Not Sure where to put my hibernate.cfg.xml in Spring Project?

I am Facing the problem as my code is not able to locate hibernate.cfg.xml file
my employee-servlet.xml code is
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:jee="http://www.springframework.org/schema/jee"
xmlns:lang="http://www.springframework.org/schema/lang"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:util="http://www.springframework.org/schema/util"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee.xsd
http://www.springframework.org/schema/lang http://www.springframework.org/schema/lang/spring-lang.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd
http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util.xsd">
<context:annotation-config />
<context:component-scan base-package="com.spring.controller.EmpController" />
<bean id="jspViewResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="viewClass"
value="org.springframework.web.servlet.view.JstlView" />
<property name="prefix" value="/WEB-INF/view/" />
<property name="suffix" value=".jsp" />
</bean>
<bean id="messageSource"
class="org.springframework.context.support.ReloadableResourceBundleMessageSource">
<property name="basename" value="classpath:messages" />
<property name="defaultEncoding" value="UTF-8" />
</bean>
<bean id="propertyConfigurer"
class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer"
p:location="/WEB-INF/jdbc.properties" />
<bean id="dataSource"
class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close"
p:driverClassName="${jdbc.driverClassName}"
p:url="${jdbc.databaseurl}" p:username="${jdbc.username}"
p:password="${jdbc.password}" />
<bean id="sessionFactory"
class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="configLocation">
<value>classpath:hibernate.cfg.xml</value>
</property>
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">${jdbc.dialect}</prop>
<prop key="hibernate.show_sql">true</prop>
</props>
</property>
</bean>
<bean id="empDao" class="com.spring.dao.EmpDaoImpl"></bean>
<bean id="empService" class="com.spring.service.EmpServiceImpl"></bean>
<tx:annotation-driven transaction-manager="transactionManager"/>
<bean id="transactionManager"
class="org.springframework.orm.hibernate4.HibernateTransactionManager">
<property name="sessionFactory" ref="sessionFactory" />
</bean>
</beans>
and my hibernate.cfg.xml file is in the source file as shown below
i confused waht to write here in this code
<bean id="sessionFactory"
class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="configLocation">
<value>classpath:hibernate.cfg.xml</value>
</property>
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">${jdbc.dialect}</prop>
<prop key="hibernate.show_sql">true</prop>
</props>
</property>
</bean>
to get the exact path of hibrenate.cfg.xml file?
due to this error is coming as :
Caused by: java.io.FileNotFoundException: class path resource [hibernate.cfg.xml] cannot be resolved to URL because it does not exist
at org.springframework.core.io.ClassPathResource.getURL(ClassPathResource.java:177)
at org.springframework.orm.hibernate4.LocalSessionFactoryBean.afterPropertiesSet(LocalSessionFactoryBean.java:283)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1571)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1509)
... 21 more
Kindly help me anyone.
Thanks and Regards

I have put hibernate.cfg.xml and employee-servlet.xm in same place "/src" directory and using the same code
<bean id="sessionFactory"
class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
<property name="dataSource">
<ref bean="dataSource" />
</property>
<property name="configLocation">
<value>classpath:hibernate.cfg.xml</value>
</property>
and in web.xml
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:employee-servlet.xml</param-value>
</context-param>

Spring MVC with JPA: Not able to instantiate JpaRepository from a jar

I am trying to import a standard spring project P1 into a web project P2 and I am implementing the web aspect of P1 in P2.
I have imported all resources of P1 in P2 as P1.jar
Have explicitly imported the application context file as well using <import-resource> which happens successfully.
But the JpaRepositories does not get autowired in P2. It doesn't seem to be in the context of P2.
Can anyone suggest what I might be missing here.
UPDATE: 25Nov2016
P1-ApplicationContext.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:jpa="http://www.springframework.org/schema/data/jpa"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:repository="http://www.springframework.org/schema/data/repository"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-4.3.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-4.3.xsd
http://www.springframework.org/schema/data/jpa http://www.springframework.org/schema/data/jpa/spring-jpa-1.8.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-4.3.xsd
http://www.springframework.org/schema/data/repository http://www.springframework.org/schema/data/repository/spring-repository-1.11.xsd">
<tx:annotation-driven proxy-target-class="true"/>
<context:component-scan base-package="com.home.p1.blog" />
<jpa:repositories base-package="com.home.p1.blog.repo" />
<bean id="dataSource"
class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="org.apache.derby.jdbc.ClientDriver" />
<property name="url"
value="jdbc:derby://localhost:1527/MyDerby" />
<property name="username" value="root" />
<property name="password" value="root" />
</bean>
<bean id="entityManagerFactory"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="persistenceUnitName" value="WorkUp" />
<property name="dataSource" ref="dataSource"></property>
<property name="packagesToScan" value="com.home.p1.blog"/>
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="databasePlatform" value="org.hibernate.dialect.DerbyDialect" />
</bean>
</property>
<property name="jpaProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.DerbyDialect</prop>
<prop key="hibernate.hbm2ddl.auto">create</prop>
<prop key="hibernate.show_sql">true</prop>
<prop key="hibernate.use_sql_comments">false</prop>
</props>
</property>
</bean>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory" />
</bean>
<bean id="authorDAO" class="com.home.p1.blog.repo.AuthorDAO">
</bean>
<bean id="authorService" class="com.home.p1.blog.service.AuthorServiceImpl"></bean>
<bean id="blogService" class="com.home.p1.blog.service.BlogServiceImpl"></bean>
</beans>
P2-ApplicationContext.xml (its actually named: rest-servlet.xml to hold the RestController scan package)
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:jpa="http://www.springframework.org/schema/data/jpa"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:repository="http://www.springframework.org/schema/data/repository"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-4.3.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-4.3.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-4.3.xsd
http://www.springframework.org/schema/data/jpa http://www.springframework.org/schema/data/jpa/spring-jpa-1.8.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-4.3.xsd
http://www.springframework.org/schema/data/repository http://www.springframework.org/schema/data/repository/spring-repository-1.11.xsd">
<import resource="classpath:com.home.p1.blog.src/src/main/resources/P1-ApplicationContext.xml"/> <!-- this loads find -->
<context:component-scan base-package="com.home.p2.blog.controller" /> <!-- this will load the RestController -->
<!-- <context:component-scan base-package="com.home.**" /> -->
<!-- THIS GIVES SOME WIERD ERROR <jpa:repositories base-package="com.home.*" /> -->
<mvc:annotation-driven/>
<!-- <bean id="blogService" class="com.oracle.blog.service.BlogServiceImpl"></bean> -->
</beans>
UPDATE: 28Nov2016
Upon including <jpa:repositories base-package> configuration in P2's application context, I no longer get the wierd error which I was getting earlier.
Also, enabling a successful import of xml config in Spring bean support, everything else is falling appropriately into place. Only the JpaRepositories referred in P1 are not reflecting in P2's context.

I dont think what you are trying to do is possible. You need to enable repository scan in your p2 and mention the packages in that scan.
If your p1.jar is in the classpath of p2 then you only have enable repository scan in your p2,
<jpa:repositories base-package="com.home.p1.blog.repo" />

RESOLVED: Please note that to import the JpaRepositories from P1.jar in P2, we don't have to mention <jpa:repositories> tag in P2's config xml.
Just ensure that we are appropriately importing the P1's config.xml.
Also Eclipse users need to add Xml / Java config in Spring Beans Support tab as well as enable support for import element.

Hibernate not creating tables with HSQL and Spring

anybody has idea why hibernate is not creating tables in my example ?
Here's my web.xml - http://pastebin.com/ZaseSaBS
mvc-dispatcher-servlet.xml - http://pastebin.com/LbdxMSAb
applicationContext.xml - http://pastebin.com/bAHMaVNX
console logs - http://pastebin.com/tTZZbxkX
I have similiar project with almost the same configuration and everything seems to run just fine on the other project. Any ideas why it's not creating tables here?
I've one test enity in com.calculator.enity with #Entity #GeneratedValue annotations, i have it listed in persistence.xml file. There's also JpaRepository for this entity in com.calculator.repository

It looks like your persistence configuration is not properly done. Use this sample persistence configuration as per your requirement. This is working fine for me.
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context"
xmlns:tx="http://www.springframework.org/schema/tx" xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.2.xsd
http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.2.xsd">
<context:component-scan base-package="com.xxx.xxx"/>
<tx:annotation-driven />
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactoryBean" />
</bean>
<bean id="entityManagerFactoryBean"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="packagesToScan" value="com.xxx.xxx" />
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter" />
</property>
<property name="jpaProperties">
<props>
<prop key="hibernate.hbm2ddl.auto">update</prop>
<prop key="hibernate.dialect">org.hibernate.dialect.PostgreSQLDialect</prop>
<prop key="hibernate.show_sql">true</prop>
<prop key="hibernate.format_sql">true</prop>
</props>
</property>
</bean>
<bean id="dataSource"
class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="org.postgresql.Driver" />
<property name="url" value="jdbc:postgresql://localhost:5432/test" />
<property name="username" value="postgres" />
<property name="password" value="prateek" />
</bean>
</beans>

How to use Tomcat with Spring without context Loader

I searched for how to configure spring with tomcat I found that I have to put the following loader into context
<Loader loaderClass="org.springframework.instrument.classloading.tomcat.TomcatInstrumentableClassLoader"/>
And I have to put spring-instrument-tomcat-x.x.jar into the tomcat lib folder
applicationContext.xml
<?xml version='1.0' encoding='UTF-8' ?>
<!-- was: <?xml version="1.0" encoding="UTF-8"?> -->
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-4.0.xsd
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-4.0.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-4.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-4.0.xsd">
<import resource="database-mysql.xml" />
<context:load-time-weaver aspectj-weaving="off" />
<!-- enables interpretation of the #Resource annotation to apply dependency injection through annotations -->
<context:component-scan base-package="com.shs.dao"></context:component-scan>
<context:component-scan base-package="com.shs.service"></context:component-scan>
<context:component-scan base-package="com.shs.web"></context:component-scan>
<bean class="org.springframework.context.annotation.CommonAnnotationBeanPostProcessor"/>
<!-- enables interpretation of the #PersistenceUnit/#PersistenceContext annotations providing convenient
access to EntityManagerFactory/EntityManager -->
<bean class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor"/>
<bean id="contextApplicationContextProvider" class="com.shs.utils.spring.AppContext"></bean>
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="persistenceUnitName" value="Default_Persistence_Unit"/>
<property name="dataSource" ref="dataSource"/>
<property name="jpaDialect">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaDialect"/>
</property>
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="showSql" value="false"/>
<property name="database" value="MYSQL"/>
</bean>
</property>
<property name="loadTimeWeaver">
<bean class="org.springframework.instrument.classloading.ReflectiveLoadTimeWeaver"/>
</property>
</bean>
<bean id="jpaTransactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory"/>
<property name="dataSource" ref="dataSource"/>
</bean>
<tx:annotation-driven transaction-manager="jpaTransactionManager" proxy-target-class="true"/>
</beans>
But I know there is another methodology to configure spring without using context loader or putting the jar into tomcat lib folder
Any ideas how to do that
Thanks in advance

Spring Security JDBC and Hibernate JPA

I'm writing a spring webapp that uses spring security with jdbc and jpa/hibernate (I'm 100% newbie with spring). I have made it work by configuring the database either in a "dataSource" bean for spring security and repeating it in persistence.xml. I tried to use the datasource inside the persistence, but I had no luck. How can I reuse my datasource configuration inside persistence.xml? My working configuration is:
datasource.xml:
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.1.xsd">
<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="com.mysql.jdbc.Driver"/>
<property name="url" value="jdbc:mysql://host:3306/db"/>
<property name="username" value="user"/>
<property name="password" value="pass"/>
</bean>
persistence.xml:
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.1" xmlns="http://xmlns.jcp.org/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://xmlns.jcp.org/xml/ns/persistence
http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">
<persistence-unit name="GCGastosPersistence">
<provider>org.hibernate.jpa.HibernatePersistenceProvider</provider>
<class>com.mypackage.MyFirstClass</class>
<class>com.mypackage.MyAnotherClass</class>
<properties>
<property name="javax.persistence.jdbc.user" value="user"/>
<property name="javax.persistence.jdbc.password" value="pass"/>
<property name="javax.persistence.jdbc.url" value="jdbc:mysql://host:3306/db"/>
<property name="javax.persistence.jdbc.driver" value="com.mysql.jdbc.Driver"/>
<property name="javax.persistence.schema-generation.database.action" value="none"/>
<property name="hibernate.connection.charset" value="utf8"/>
<property name="hibernate.connection.charsetEncoding" value="utf8"/>
<property name="hibernate.connection.useUnicode" value="true"/>
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQL5Dialect" />
</properties>
</persistence-unit>
Any hint is appreciated.

You can actually ask spring to handle that for you using LocalContainerEntityManagerFactoryBean:
<bean class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean" id="entityManagerFactory">
<property name="persistenceUnitName" value="persistenceUnit"/>
<property name="dataSource" ref="dataSource"/>
</bean>
Hence you don't need to rewrite your datasource config on persistence.xml. However this is normally used if you container do not already come with its own EntityManagerFactory (eg: tomcat, jetty). Some profiles of JBoss, Glassfish, Websphere have their own EntityManagerFactory.
I have a blog post on setting up spring and jpa if you like to see more, however this is just one of many other method on how you can setup hibernate / JPA.

You can drop your whole persistence.xml and only use the spring context to create your entityManager. It would be something like this...
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context"
xmlns:tx="http://www.springframework.org/schema/tx" xmlns:jpa="http://www.springframework.org/schema/data/jpa"
xsi:schemaLocation="
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd
http://www.springframework.org/schema/data/jpa http://www.springframework.org/schema/data/jpa/spring-jpa-1.1.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">
<bean id="jdbcTemplate" class="org.springframework.jdbc.core.JdbcTemplate">
<property name="dataSource" ref="dataSource"/>
</bean>
<bean id="entityManagerFactory"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="packagesToScan" value="com.app.domain" />
<property name="persistenceProviderClass" value="org.hibernate.ejb.HibernatePersistence"/>
<property name="persistenceUnitName" value="persUnit" />
<property name="mappingResources" value="META-INF/orm.xml"/>
<property name="jpaProperties">
<props><prop key="hibernate.dialect">org.hibernate.dialect.PostgreSQLDialect</prop>
<prop key="hibernate.max_fetch_depth">3</prop>
<prop key="hibernate.jdbc.fetch_size">50</prop>
<prop key="hibernate.jdbc.batch_size">10</prop>
<prop key="hibernate.show_sql">true</prop>
</props>
</property>
</beans>
--EDIT-- I'm referencing the datasource here but for me it's in another context file. You would need to add yours here as well.
<bean id="dataSource"
class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="org.postgresql.Driver" />
<property name="url"
value="jdbc:postgresql://localhost:5432/mydb" />
<property name="username" value="myuser" />
<property name="password" value="mypasswd/>
</bean>
--EDIT2--
Just leave your persistence.xml empty then. Like...
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.1" xmlns="http://xmlns.jcp.org/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">
</persistence>
then define your JPA properties inside spring.