I am new to XML. I want to read the following XML on the basis of request name. Please help me on how to read the below XML in Java -
<?xml version="1.0"?>
<config>
<Request name="ValidateEmailRequest">
<requestqueue>emailrequest</requestqueue>
<responsequeue>emailresponse</responsequeue>
</Request>
<Request name="CleanEmail">
<requestqueue>Cleanrequest</requestqueue>
<responsequeue>Cleanresponse</responsequeue>
</Request>
</config>
If your XML is a String, Then you can do the following:
String xml = ""; //Populated XML String....
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document document = builder.parse(new InputSource(new StringReader(xml)));
Element rootElement = document.getDocumentElement();
If your XML is in a file, then Document document will be instantiated like this:
Document document = builder.parse(new File("file.xml"));
The document.getDocumentElement() returns you the node that is the document element of the document (in your case <config>).
Once you have a rootElement, you can access the element's attribute (by calling rootElement.getAttribute() method), etc. For more methods on java's org.w3c.dom.Element
More info on java DocumentBuilder & DocumentBuilderFactory. Bear in mind, the example provided creates a XML DOM tree so if you have a huge XML data, the tree can be huge.
Related question.
Update Here's an example to get "value" of element <requestqueue>
protected String getString(String tagName, Element element) {
NodeList list = element.getElementsByTagName(tagName);
if (list != null && list.getLength() > 0) {
NodeList subList = list.item(0).getChildNodes();
if (subList != null && subList.getLength() > 0) {
return subList.item(0).getNodeValue();
}
}
return null;
}
You can effectively call it as,
String requestQueueName = getString("requestqueue", element);
In case you just need one (first) value to retrieve from xml:
public static String getTagValue(String xml, String tagName){
return xml.split("<"+tagName+">")[1].split("</"+tagName+">")[0];
}
In case you want to parse whole xml document use JSoup:
Document doc = Jsoup.parse(xml, "", Parser.xmlParser());
for (Element e : doc.select("Request")) {
System.out.println(e);
}
If you are just looking to get a single value from the XML you may want to use Java's XPath library. For an example see my answer to a previous question:
How to use XPath on xml docs having default namespace
It would look something like:
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathFactory;
import org.w3c.dom.Document;
import org.w3c.dom.NodeList;
public class Demo {
public static void main(String[] args) {
DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance();
try {
DocumentBuilder builder = domFactory.newDocumentBuilder();
Document dDoc = builder.parse("E:/test.xml");
XPath xPath = XPathFactory.newInstance().newXPath();
Node node = (Node) xPath.evaluate("/Request/#name", dDoc, XPathConstants.NODE);
System.out.println(node.getNodeValue());
} catch (Exception e) {
e.printStackTrace();
}
}
}
There are a number of different ways to do this. You might want to check out XStream or JAXB. There are tutorials and the examples.
If the XML is well formed then you can convert it to Document. By using the XPath you can get the XML Elements.
String xml = "<stackusers><name>Yash</name><age>30</age></stackusers>";
Form XML-String Create Document and find the elements using its XML-Path.
Document doc = getDocument(xml, true);
public static Document getDocument(String xmlData, boolean isXMLData) throws Exception {
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
dbFactory.setNamespaceAware(true);
dbFactory.setIgnoringComments(true);
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc;
if (isXMLData) {
InputSource ips = new org.xml.sax.InputSource(new StringReader(xmlData));
doc = dBuilder.parse(ips);
} else {
doc = dBuilder.parse( new File(xmlData) );
}
return doc;
}
Use org.apache.xpath.XPathAPI to get Node or NodeList.
System.out.println("XPathAPI:"+getNodeValue(doc, "/stackusers/age/text()"));
NodeList nodeList = getNodeList(doc, "/stackusers");
System.out.println("XPathAPI NodeList:"+ getXmlContentAsString(nodeList));
System.out.println("XPathAPI NodeList:"+ getXmlContentAsString(nodeList.item(0)));
public static String getNodeValue(Document doc, String xpathExpression) throws Exception {
Node node = org.apache.xpath.XPathAPI.selectSingleNode(doc, xpathExpression);
String nodeValue = node.getNodeValue();
return nodeValue;
}
public static NodeList getNodeList(Document doc, String xpathExpression) throws Exception {
NodeList result = org.apache.xpath.XPathAPI.selectNodeList(doc, xpathExpression);
return result;
}
Using javax.xml.xpath.XPathFactory
System.out.println("javax.xml.xpath.XPathFactory:"+getXPathFactoryValue(doc, "/stackusers/age"));
static XPath xpath = javax.xml.xpath.XPathFactory.newInstance().newXPath();
public static String getXPathFactoryValue(Document doc, String xpathExpression) throws XPathExpressionException, TransformerException, IOException {
Node node = (Node) xpath.evaluate(xpathExpression, doc, XPathConstants.NODE);
String nodeStr = getXmlContentAsString(node);
return nodeStr;
}
Using Document Element.
System.out.println("DocumentElementText:"+getDocumentElementText(doc, "age"));
public static String getDocumentElementText(Document doc, String elementName) {
return doc.getElementsByTagName(elementName).item(0).getTextContent();
}
Get value in between two strings.
String nodeVlaue = org.apache.commons.lang.StringUtils.substringBetween(xml, "<age>", "</age>");
System.out.println("StringUtils.substringBetween():"+nodeVlaue);
Full Example:
public static void main(String[] args) throws Exception {
String xml = "<stackusers><name>Yash</name><age>30</age></stackusers>";
Document doc = getDocument(xml, true);
String nodeVlaue = org.apache.commons.lang.StringUtils.substringBetween(xml, "<age>", "</age>");
System.out.println("StringUtils.substringBetween():"+nodeVlaue);
System.out.println("DocumentElementText:"+getDocumentElementText(doc, "age"));
System.out.println("javax.xml.xpath.XPathFactory:"+getXPathFactoryValue(doc, "/stackusers/age"));
System.out.println("XPathAPI:"+getNodeValue(doc, "/stackusers/age/text()"));
NodeList nodeList = getNodeList(doc, "/stackusers");
System.out.println("XPathAPI NodeList:"+ getXmlContentAsString(nodeList));
System.out.println("XPathAPI NodeList:"+ getXmlContentAsString(nodeList.item(0)));
}
public static String getXmlContentAsString(Node node) throws TransformerException, IOException {
StringBuilder stringBuilder = new StringBuilder();
NodeList childNodes = node.getChildNodes();
int length = childNodes.getLength();
for (int i = 0; i < length; i++) {
stringBuilder.append( toString(childNodes.item(i), true) );
}
return stringBuilder.toString();
}
OutPut:
StringUtils.substringBetween():30
DocumentElementText:30
javax.xml.xpath.XPathFactory:30
XPathAPI:30
XPathAPI NodeList:<stackusers>
<name>Yash</name>
<age>30</age>
</stackusers>
XPathAPI NodeList:<name>Yash</name><age>30</age>
following links might help
http://labe.felk.cvut.cz/~xfaigl/mep/xml/java-xml.htm
http://developerlife.com/tutorials/?p=25
http://www.java-samples.com/showtutorial.php?tutorialid=152
There are two general ways of doing that. You will either create a Domain Object Model of that XML file, take a look at this
and the second choice is using event driven parsing, which is an alternative to DOM xml representation. Imho you can find the best overall comparison of these two basic techniques here. Of course there are much more to know about processing xml, for instance if you are given XML schema definition (XSD), you could use JAXB.
There are various APIs available to read/write XML files through Java.
I would refer using StaX
Also This can be useful - Java XML APIs
You can make a class which extends org.xml.sax.helpers.DefaultHandler and call
start_<tag_name>(Attributes attrs);
and
end_<tag_name>();
For it is:
start_request_queue(attrs);
etc.
And then extends that class and implement xml configuration file parsers you want. Example:
...
public void startElement(String uri, String name, String qname,
org.xml.sax.Attributes attrs)
throws org.xml.sax.SAXException {
Class[] args = new Class[2];
args[0] = uri.getClass();
args[1] = org.xml.sax.Attributes.class;
try {
String mname = name.replace("-", "");
java.lang.reflect.Method m =
getClass().getDeclaredMethod("start" + mname, args);
m.invoke(this, new Object[] { uri, (org.xml.sax.Attributes)attrs });
}
catch (IllegalAccessException e) {
throw new RuntimeException(e);
}
catch (NoSuchMethodException e) {
throw new RuntimeException(e); }
catch (java.lang.reflect.InvocationTargetException e) {
org.xml.sax.SAXException se =
new org.xml.sax.SAXException(e.getTargetException());
se.setStackTrace(e.getTargetException().getStackTrace());
}
and in a particular configuration parser:
public void start_Request(String uri, org.xml.sax.Attributes attrs) {
// make sure to read attributes correctly
System.err.println("Request, name="+ attrs.getValue(0);
}
Since you are using this for configuration, your best bet is apache commons-configuration. For simple files it's way easier to use than "raw" XML parsers.
See the XML how-to
I want to get all the namespaces in the xml file for example
[http://www.utilities-online.info/xpath/?save=a4ac7360-1994-44c2-9c26-c9f741dc2e44-xpath#.VeRWSvmqpBc][1]
basically problem is to to search using xpath based on namespaces and for that purpose i have to use setNamespaceContext and don't know namespaces value because it will be on runtime while parsing file.
xpath.setNamespaceContext(namespaces);
public class SimpleNamespaceContext implements NamespaceContext {
private final Map<String, String> PREF_MAP = new HashMap<String, String>();
public SimpleNamespaceContext(final Map<String, String> prefMap) {
PREF_MAP.putAll(prefMap);
}
public String getNamespaceURI(String prefix) {
return PREF_MAP.get(prefix);
}
public String getPrefix(String uri) {
throw new UnsupportedOperationException();
}
public Iterator getPrefixes(String uri) {
throw new UnsupportedOperationException();
}
}
XPathFactory factory = XPathFactory.newInstance();
XPath xpath = factory.newXPath();
HashMap<String, String> prefMap = new HashMap<String, String>() {{
put("main", "http://schemas.openxmlformats.org/spreadsheetml/2006/main");
put("r", "http://schemas.openxmlformats.org/officeDocument/2006/relationships");
}};
SimpleNamespaceContext namespaces = new SimpleNamespaceContext(prefMap);
xpath.setNamespaceContext(namespaces);
XPathExpression expr = xpath
.compile("/main:workbook/main:sheets/main:sheet[1]");
Object result = expr.evaluate(doc, XPathConstants.NODESET);
reference link [How to query XML using namespaces in Java with XPath?
To implement above mention reference i need to get all namespaces
query i am using to get all namespaces using xpath is
try {
XPathFactory xPathfactory = XPathFactory.newInstance();
XPath xpath = xPathfactory.newXPath();
XPathExpression expr = xpath.compile("//namespace::*");
NodeList a = (NodeList) expr.evaluate(doc, XPathConstants.NODESET);
System.out.println(a.getLength());
} catch (Exception e) {
Utility.consoleInfo(e);
}
but this always return nodelist of size 0 .
Am i going in wrong direction to achieve this? or what else would be the solution to this problem ?
Summary
How should i get all namespaces so that it can be used in xpath ?
please help me in this regard
I do not succeed in parsing a SOAP Response in Java (using Bonita Open Solution BPM).
I have the following SOAP response (searching for a document in the IBM Content Manager; the SOAP Response returns 1 matching document)
<soapenv:Envelope xmlns:soapenv="http://www.w3.org/2003/05/soap-envelope" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<soapenv:Body>
<ns1:RunQueryReply xmlns="http://www.ibm.com/xmlns/db2/cm/beans/1.0/schema" xmlns:ns1="http://www.ibm.com/xmlns/db2/cm/beans/1.0/schema">
<ns1:RequestStatus success="true"></ns1:RequestStatus>
<ns1:ResultSet count="1">
<ns1:Item URI="http://xxxx/CMBSpecificWebService/CMBGetPIDUrl?pid=96 3 ICM8 ICMNLSDB16 ICCSPArchivSuche59 26 A1001001A12D18B30015E9357518 A12D18B30015E935751 14 1087&server=ICMNLSDB&dsType=ICM">
<ns1:ItemXML>
<ICCSPArchivSuche ICCCreatedBy="EBUSINESS\iccadmin" ICCCreatedDate="2012-04-18T10:51:26.000000" ICCFileName="Golem_Artikel.txt" ICCFolderPath="" ICCLastModifiedDate="2012-04-18T10:51:28.000000" ICCLibrary="Dokumente" ICCModifiedBy="EBUSINESS\iccadmin" ICCSharePointGUID="c43f9c93-a228-43f9-8232-06bdea4695d1" ICCSharePointVersion="1.0 " ICCSite="Archiv Suche" cm:PID="96 3 ICM8 ICMNLSDB16 ICCSPArchivSuche59 26 A1001001A12D18B30015E9357518 A12D18B30015E935751 14 1087" xmlns:cm="http://www.ibm.com/xmlns/db2/cm/api/1.0/schema">
<cm:properties type="document">
<cm:lastChangeUserid value="ICCCMADMIN"/>
<cm:lastChangeTime value="2012-04-18T11:00:15.914"/>
<cm:createUserid value="ICCCMADMIN"/>
<cm:createTime value="2012-04-18T11:00:15.914"/>
<cm:semanticType value="1"/>
<cm:ACL name="DocRouteACL"/>
<cm:lastOperation name="RETRIEVE" value="SUCCESS"/>
</cm:properties>
<cm:resourceObject CCSID="0" MIMEType="text/plain" RMName="rmdb" SMSCollName="CBR.CLLCT001" externalObjectName=" " originalFileName="" resourceFlag="2" resourceName=" " size="702" textSearchable="true" xsi:type="cm:TextObjectType">
<cm:URL value="http://cmwin01.ebusiness.local:9080/icmrm/ICMResourceManager/A1001001A12D18B30015E93575.txt?order=retrieve&item-id=A1001001A12D18B30015E93575&version=1&collection=CBR.CLLCT001&libname=icmnlsdb&update-date=2012-04-18+11%3A00%3A15.001593&token=A4E6.IcQyRE6_QbBPESDGxK2;&content-length=0"/>
</cm:resourceObject>
</ICCSPArchivSuche>
</ns1:ItemXML>
</ns1:Item>
</ns1:ResultSet>
</ns1:RunQueryReply>
</soapenv:Body>
</soapenv:Envelope>
I would like to get the filename (ICCFileName="Golem_Artikel.txt") and the url to this file ( <cm:URL value="http://cmwin01.ebusiness.local:9080/icmrm/ICMResourceManager/A10...) in string Variables using Java. I read several articles on how to do this (Can't process SOAP response , How to do the Parsing of SOAP Response) but without success. Here is what I tried:
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.InputSource;
// Clean response xml document
responseDocumentBody.normalizeDocument();
// Get result node
NodeList resultList = responseDocumentBody.getElementsByTagName("ICCSPArchivSuche");
Element resultElement = (Element) resultList.item(0);
String XMLData = resultElement.getTextContent();
// Check for empty result
if ("Data Not Found".equalsIgnoreCase(XMLData))
return null;
DocumentBuilder documentBuilder = DocumentBuilderFactory.newInstance().newDocumentBuilder();
InputSource inputSource = new InputSource();
inputSource.setCharacterStream(new StringReader(XMLData));
Document doc = documentBuilder.parse(inputSource);
Node node = doc.getDocumentElement();
String result = doc.getNodeType();
return result;
From Bonita, I only get responseDocumentBody or responseDocumentEnvelope (org.w3c.dom.Document) as webservice response. Therefore, I need to navigate from the SOAP Body to my variables. I would be pleased if someone could help.
Best regards
If you do a lot of work with this, I would definitively recommend using JAXB as MGoron suggests. If this is a one shot excersize, XPATH could also work well.
/*
* Must use a namespace aware factory
*/
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
dbf.setNamespaceAware(true);
Document doc = dbf.newDocumentBuilder().parse(...);
/*
* Create an XPath object
*/
XPath p = XPathFactory.newInstance().newXPath();
/*
* Must use a namespace context
*/
p.setNamespaceContext(new NamespaceContext() {
public Iterator getPrefixes(String namespaceURI) {
return null;
}
public String getPrefix(String namespaceURI) {
return null;
}
public String getNamespaceURI(String prefix) {
if (prefix.equals("ns1"))
return "http://www.ibm.com/xmlns/db2/cm/beans/1.0/schema";
if (prefix.equals("cm"))
return "http://www.ibm.com/xmlns/db2/cm/api/1.0/schema";
return null;
}
});
/*
* Find the ICCSFileName attribute
*/
Node iccsFileName = (Node) p.evaluate("//ns1:ICCSPArchivSuche/#ICCFileName", doc, XPathConstants.NODE);
System.out.println(iccsFileName.getNodeValue());
/*
* Find the URL
*/
Node url = (Node) p.evaluate("//ns1:ICCSPArchivSuche/cm:resourceObject/cm:URL/#value", doc, XPathConstants.NODE);
System.out.println(url.getNodeValue());
get RunQueryReply schema
map xsd to java classes using jax-b
unmarshall response string to jax-b class object
Below is the code to do this in VTD-XML, it basically consists of 2 XPath queries, each returning one result... however the code is robust as it doesn't assume those queries will return non-empty result...
import com.ximpleware.*;
public class parseSOAP {
public static void main(String[] s) throws VTDException, Exception{
VTDGen vg = new VTDGen();
vg.selectLcDepth(5);// soap has deep nesting so set to 5 to speed up navigation
if (!vg.parseFile("d:\\xml\\soap2.xml", true))
return;
VTDNav vn = vg.getNav();
AutoPilot ap =new AutoPilot(vn);
//declare name space for xpath
ap.declareXPathNameSpace("ns", "http://www.ibm.com/xmlns/db2/cm/beans/1.0/schema");
ap.declareXPathNameSpace("ns1", "http://www.ibm.com/xmlns/db2/cm/beans/1.0/schema");
ap.declareXPathNameSpace("cm", "http://www.ibm.com/xmlns/db2/cm/api/1.0/schema");
ap.declareXPathNameSpace("soapenv", "http://www.w3.org/2003/05/soap-envelope");
ap.selectXPath("/soapenv:Envelope/soapenv:Body/ns1:RunQueryReply/ns1:ResultSet/ns1:Item/ns1:ItemXML//ICCSPArchivSuche/#ICCFileName");
int i=0;
if ((i=ap.evalXPath())!=-1){
System.out.println("file name ==>"+vn.toString(i+1));
}
ap.selectXPath("/soapenv:Envelope/soapenv:Body/ns1:RunQueryReply/ns1:ResultSet/ns1:Item/ns1:ItemXML//ICCSPArchivSuche/cm:resourceObject/cm:URL/#value");
if ((i=ap.evalXPath())!=-1){
System.out.println("file name ==>"+vn.toString(i+1));
}
}
}
I have an XML file and i want to get values of the nodes attributes in it, it works efficiently when the node is usual but is the case of nodes named like something:something it didn't give me back any result, just null.
The XML file :
<?xml version="1.0" encoding="UTF-8" standalone="yes" ?>
<rss version="2.0" xmlns:yweather="http://xml.weather.yahoo.com/ns/rss/1.0" xmlns:geo="http://www.w3.org/2003/01/geo/wgs84_pos#">
<channel>
<title>Yahoo! Weather - Sunnyvale, CA</title>
<link>http://us.rd.yahoo.com/dailynews/rss/weather/Sunnyvale__CA/*http://weather.yahoo.com/forecast/USCA1116_f.html</link>
<description>Yahoo! Weather for Sunnyvale, CA</description>
<language>en-us</language>
<lastBuildDate>Fri, 18 Dec 2009 9:38 am PST</lastBuildDate>
<ttl>60</ttl>
<yweather:location city="Sunnyvale" region="CA" country="United States"/>
<yweather:units temperature="F" distance="mi" pressure="in" speed="mph"/>
</channel>
</rss>
The Java Code :
XPathFactory factory = XPathFactory.newInstance();
XPath xpath = factory.newXPath();
XPathExpression expr = xpath.compile("//rss/#version");
Object result = expr.evaluate(doc, XPathConstants.STRING);
System.out.println(result);
the previous java code works efficiently but when replacing //rss/#version with
//rss/channel/yweather:location/#city it returns me null.
First of all, the part before the : is called a namespace. It is quite an important concept in XML.
To retrieve a value with a namespace you have to make the context aware of the namespace. You can do this using
xpath.setNamespaceContext(context);
context must be an implementation of NamespaceContext. In this case, the namspaces are defined within the XML so it might be good to have a namespace resolver which can get the namespaces from the document directly. This class is exactly doing this:
public class UniversalNamespaceResolver implements NamespaceContext {
private Document sourceDocument;
public UniversalNamespaceResolver(Document document) {
sourceDocument = document;
}
public String getNamespaceURI(String prefix) {
if (prefix.equals(XMLConstants.DEFAULT_NS_PREFIX)) {
return sourceDocument.lookupNamespaceURI(null);
} else {
return sourceDocument.lookupNamespaceURI(prefix);
}
}
public String getPrefix(String namespaceURI) {
return sourceDocument.lookupPrefix(namespaceURI);
}
public Iterator getPrefixes(String namespaceURI) {
return null;
}
}
Read more about it at http://www.ibm.com/developerworks/library/x-nmspccontext/
I have a xml file which is a response from Webservice.It has got various namespaces involved with it. When I try to validate it with appropriate XSD its throwing "org.xml.sax.SAXParseException: cvc-elt.1: Cannot find the declaration of element 'SOAP-ENV:Envelope'." The namespace declaration for all the namespaces are declared in the response.
Following is my code
try {
DocumentBuilderFactory xmlFact = DocumentBuilderFactory.newInstance();
SchemaFactory schemaFactory = SchemaFactory
.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
SAXSource mainInputStream = new SAXSource(new InputSource(new FileInputStream(new File("FIXEDINCOME_v3_0.xsd"))));
SAXSource importInputStream1 =new SAXSource(new InputSource(new FileInputStream(new File("Rating.xsd"))));
SAXSource importInputStream2 = new SAXSource(new InputSource(new FileInputStream(new File("Datatypes.xsd"))));
Source[] sourceSchema = new SAXSource[]{mainInputStream , importInputStream1, importInputStream2};
Schema schema = schemaFactory.newSchema(sourceSchema);
xmlFact.setNamespaceAware(true);
xmlFact.setSchema(schema);
DocumentBuilder builder = xmlFact.newDocumentBuilder();
xmlDOC = builder.parse(new InputSource(new StringReader(inputXML)));
NamespaceContext ctx = new NamespaceContext() {
public String getNamespaceURI(String prefix) {
String uri;
if (prefix.equals("ns0"))
uri = "http://namespace.worldnet.ml.com/EDS/Standards/Common/Service_v1_0/";
else if (prefix.equals("ns1"))
uri = "http://namespace.worldnet.ml.com/EDS/Product/Services/Get_Product_Data_Svc_v3_0/";
else if (prefix.equals("ns2"))
uri = "http://namespace.worldnet.ml.com/DataSOA/Product/Objects/FixedIncome/FixedIncome_v3_0/";
else if (prefix.equals("ns3")) {
uri = "http://namespace.worldnet.ml.com/DataSOA/Product/Objects/Rating/Rating_v2_0/";
} else if (prefix.equals("SOAP-ENV")) {
uri = "http://schemas.xmlsoap.org/soap-envelope/";
} else
uri = null;
return uri;
}
// Dummy implementation - not used!
public Iterator getPrefixes(String val) {
return null;
}
// Dummy implemenation - not used!
public String getPrefix(String uri) {
return null;
}
};
XPathFactory xpathFact = XPathFactory.newInstance();
xPath = xpathFact.newXPath();
xPath.setNamespaceContext(ctx);
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
I don't think the problem is with detecting the namespace definition for the SOAP-ENV prefix. The validator needs the XSD file that defines elements used in that namespace in order to validate the SOAP-ENV:Envelope element, so you need to tell the validator where that schema is located.
I think the solution is either to add the following to your XML reponse:
<SOAP-ENV:Envelope
xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/"
xmlns:xsi="http://schemas.xmlsoap.org/soap/envelope/"
xsi:schemaLocation="http://schemas.xmlsoap.org/soap/envelope/
http://schemas.xmlsoap.org/soap/envelope/">
Or, go download that schema off the web, save it to your local filesystem as an XSD file, and add it to your sourceSchema array. The first method should be preferred as it leads to more portable code (and XML).
Have you tried using the following URI for the SOAP-ENV?
http://schemas.xmlsoap.org/soap/envelope/
The set of schemas you are providing for validation does not include the soap schema. you can either include the soap schema in the schema collection, or, if you don't care about validating the soap wrapper, just grab the actual body content element and run your validation from there.