I have one table in mysql which has three field with data inserted. there are three fields in it which are as below.
i want to display this data on a web browser with using ajax in java.
i search on a net and find this below code are most useful
Connection con=DriverManager.getConnection("jdbc:mysql://localhost:3306/ajax_demo","root","");
PreparedStatement ps=con.prepareStatement("select * from ajax");
what are other things i have to implement for displaying output.
You need to do a AJAX request, the main code body for an ajax request is the following
request.onreadystatechange=handleResponse;
request.open(typeReq, url, true);
request.setRequestHeader("Content-Type", "application/x-www-form-urlencoded; charset=UTF-8");
request.send(queryString);
typeReq is the type of the request: POST or GET.
url: the destination url address.
queryString: the set of data which you want to send.
handleResponse is a function to hanled the response. For example:
function handleResponse () {
if (request.readyState = 4) {
if (request.status = 200) {
var response = request.responseText;
//code to handle response
} else {
//code to handle errors
}
}
Now, you can use an API like prototype or jquery, it's easier.
I hope this information helps you.
Good Luck
Related
I have just created an AJAX request in velocity template and able to get request at .java file as below: (java file is extended for "JiraWebActionSupport" as webwork module).
var url = "PlanIssuesAction!IssuesPlanning.jspa";
jQuery.post(url,myJSONObject,function(result) {
alert('success');
})
.done(function() { alert("in done"); })
.fail(function() { alert("error"); })
.always(function() { alert("finished"); });
On the server side, in doIssuesPlanning method, able to get call and insert the posted data.
public String doIssuesPlanning() {
System.out.println("Success executed result appear"); //i want this value to be //retrieval at client side but it's not working. unable to receive at ajax response.
return getRedirect("PlanIssuesAction!default.jspa");
//return "result is success" //also tried instead of getRedirect ,used direct response //return but not worked, it capture at error in ajax response at client side.
}
Now I need to return the result data to the client side back at jquery "Result" parameter.
How can I achieve this? Currently, in "Result" object shows all HTML text and nothing else.
(i have set object above through - "System.out.println and expect to be retrieved at client side but not working).
Can you please let me know , what is wrong here.
Thank you.
Webwork jspa URLs return HTML since that is their purpose. Most AJAX calls would be to a REST resource that returns JSON. I'd define a new REST resource for this. More information at https://developer.atlassian.com/display/DOCS/Developing+a+REST+Service+Plugin
I am studying on the Spring MVC showcase example dowlodable from the STS dashboard.
In this time I am studying on the Converters section of this example and I have some question for you.
To start, in my view I have the following two links:
<li>
<a id="writeJsonAccept" class="writeJsonLink" href="<c:url value="/messageconverters/json" />">Write JSON via Accept=application/json</a>
</li>
<li>
<a id="writeJsonExt" class="writeJsonLink" href="<c:url value="messageconverters/json" />">Write JSON via ".json"</a>
</li>
The first link generate an HTTP Request towards the URL: messageconverters/json
The second link generate an HTTP Request towards the URL: /messageconverters/json.json (differently from the first URL this one end with .json extension
Ok, both these links have class="writeJsonLink" and related to the click event of these links the following JQuery callback function is called:
$("a.writeJsonLink").click(function() {
var link = $(this);
$.ajax({
url: this.href,
beforeSend: function(req) {
if (!this.url.match(/\.json$/)) {
req.setRequestHeader("Accept", "application/json");
}
},
success: function(json) {
MvcUtil.showSuccessResponse(JSON.stringify(json), link);
},
error: function(xhr) {
MvcUtil.showErrorResponse(xhr.responseText, link);
}});
return false;
});
This function only execute an AJAX call and wait for an HTTP Response passing its content to an handler that will show the output in the view...ok...
Before sending the request, the function check if the URL don't end with .json extension
If this request don't end with .json extension the following header is added to my HTTP Request:
Accept = application/json
From what I know the Accept Header say which specific mediatype is considerable acceptable for the HTTP Response, in this case say that the only acceptable media type is a JavaScript object having JSON format, ok...
This Request is handled from the following method of my controller class that return a valorized object that will be converted in JSON forma using Jaxb2RootElementHttpMessageConverter
#RequestMapping(value="/json", method=RequestMethod.GET)
public ResponseEntity<JavaBean> writeJson() {
// Oggetto che rappresenta gli HTTP Header dell'HTTP Response
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.TEXT_PLAIN);
return new ResponseEntity<JavaBean>(new JavaBean("bar", "apple"), headers , HttpStatus.OK);
// return new JavaBean("bar", "apple");
}
Now, my question is about the differences from the two links.
The first one don't end with .json extension, so the Accept header is added and it is setted on application/json sayng that the browsers expects to receive a JSON object
The second one end with .json extension, so the Jquery method don't set the Accept Header
But, this thing what mean? that when an URL end with .json the Accept header is automatically setted? Or more generally, when I have an URL that end with some kind extension (for example like .xml) the relative Accept header is automatically setted?
Or simply in this second case, don't set the Accept Header mean don't handle the media type that I can recive in the body of the HTTP Response?
Ok, your english is not-so-hot, so let me try to help you the best I can.
In my understanding, which may very well be wrong, is that you want to know if the browser will set the Accept: header to be json when the URL ends in json? I do not believe this is the case. I may be greatly mistaken on this, but you can test this by using something like Firebug or Chrome's Developer Tools, or if you like IE get Fiddler, and see exactly what headers get sent from the browser.
Now, if you are asking if Spring will magically put the headers there, then again I think the answer is "no". The HTTP headers on the request come from the browser, and although you could put in a Servlet Filter or something to set the request filters, I think this would be dangerous to assume all browsers handle these request headers the same way.
No, if the question is "how are my requests all getting to my Controller's writeJson() method?", then the answer has nothing to do with the "Accept" header at all. Your method is matching on any URI pattern that ends in /json, and in both cases your URL ends in /json. If you want to filter on things that have an "Accept" header of JSON, then I think you want to do something like this:
#RequestMapping(value="/someUriPattern", headers = {"Accept=application/json"})
Please understand I typed the above from memory, so you may need to tweak it a tad.
I have a situation where a intermediate servlet needs to be introduced which will handle requests from existing project and redirect the manipulated response to either existing project or the new one. This servlet will act as an interface to login into the new project from some other application.
So currently I use the following code to get back response in jsp as an xml.
var jqxhr =$.post("http://abhishek:15070/abc/login.action",
{ emailaddress: "ars#gmail.com",
projectid: "123" },
function(xml)
{
if($(xml).find('isSuccess').text()=="true")
{
sessiontoken=$(xml).find('sessiontoken').text();
setCookie("abcsessionid", sessiontoken , 1);
setCookie("abcusername",e_add,1);
}
}
)
.error(function() {
if(jqxhr.responseText == 'INVALID_SESSION') {
alert("Your Session has been timed out");
window.location.replace("http://abhishek:15070/abc/index.html");
}else {
alert( jqxhr.responseText);
}
});
xml content
<Response>
<sessiontoken>334465683124</sessiontoken>
<isSuccess>true</isSuccess>
</Response>
but now I want the same thing to be done using servlet, is it possible?
String emailid=(String) request.getParameter("emailaddress");
String projectid=(String) request.getParameter("projectid");
Update
I just came up with something.
Is it possible to return back a html page with form (from servlet), whose on body load it will submit a form and on submission of this form it will receive the response xml which will get processed.
Use java.net.URLConnection or Apache HttpComponents Client. Then, parse the returned HTTP response with a XML tool like as JAXB or something.
Kickoff example:
String emailaddress = request.getParameter("emailaddress");
String projectid = request.getParameter("projectid");
String charset = "UTF-8";
String query = String.format("emailaddress=%s&projectid=%s",
URLEncoder.encode(emailaddress, charset),
URLEncoder.encode(projectid, charset));
URLConnection connection = new URL("http://abhishek:15070/abc/login.action").openConnection();
connection.setDoOutput(true);
connection.setRequestProperty("Accept-Charset", charset);
connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded;charset=" + charset);
try {
connection.getOutputStream().write(query.getBytes(charset));
}
finally {
connection.getOutputStream().close();
}
InputStream response = connection.getInputStream();
// ...
See also:
Using java.net.URLConnection to fire and handle HTTP requests
HttpClient tutorial and examples
Actually, what you probably want is not an intermediate servlet at all. What you probably want is called a servlet filter and writing one is not particularly hard. I've written one in the past and I just started on a new one yesterday.
An article like this one or this one lays out pretty simply how you can use a servlet filter to intercept calls to specific URLs and then redirect or reject from there. If the incoming URL matches the pattern for the filter, it will get a shot at the request and response and it can then make a choice whether or not to pass it on to the next filter in line.
I don't know if all third party security solutions do it like this, but at least CAS seemed to be implemented that way.
hi I am querying database to load all items based on some criteria and setting this result in session as
data = service.getData();
session.setAttribute("data", data);
now I am trying to access this data via an Ajax call and my Ajax call is served by a different servlet rather then which fetched the data from DB.
Ajax call using jquery
$.ajax({
type: "POST",
url: "/com/tp/AjaxXML.jsp",
data: ({cmd: "report"}),
dataType: "xml",
success: function(xml) {
$(xml).find('site').each(function(){
var url = $(this).attr('url');
});
}
});
in my AjaxXML.jsp
I am doing
if("report".equals(cmd)){
List<Object> data = (List<Object>)request.getSession().getAttribute("data");
if(data == null){
System.out.println("data is null ");
}
}
every time I am getting the data as null via the Ajax call how ever I try to access the session data normally from my first servlet it works.
could someone let me know if I am doing something wrong?
I noticed one more thing when we do session.getId(); and pageContext.getSession().getId();
both of them are returning different Id's? Is this expected to me they should be same anyone differ on that?
I noticed one more thing when we do session.getId(); and pageContext.getSession().getId(); both of them are returning different Id's? Is this expected to me they should be same anyone differ on that?
No, they should definitely not differ. I however assume that you have examined them within the same request. If you examined them in different requests, then the difference can be explained by the absence of the proper JSESSIONID cookie. Cookies are domain and context specific. You're apparently sending the ajax request to a different domain/context. The leading slash / in the ajax URL also confirms this less or more. Make sure that you're sending it to the same domain/context. Use a context-relative URL, something like as url: "AjaxXML.jsp" and move the code to the same domain/context, or turn on session sharing between different contexts at server level.
Unrelated to the concrete problem, doing the Ajax response handling in a JSP is a bad idea. Rather do it in a servlet.
Replace
url: "/com/tp/AjaxXML.jsp",
by
url: "/com/tp/AjaxXML",
and put the code in doPost() method of the servlet which is mapped on that URL pattern.
See also:
How to use Servlets and Ajax?
I need to send large amount of string in a ajax post request to server. If i add it the end of the url, i can get using request.getParameter() method in the server.
But i can't append large string in the url.So i want to send using the method send() of XMLHttpRequest instead of appending it to url.
But i couldn't retrieve the same using request.getParameter() in server.
How to retrieve data send from ajax request in j2ee server?
Please guide me.
If you have an ajax intensive webapp, I would suggest using a javascript library (such as jquery) to handle ajax. In jQuery, you could do this as :
$.post("your_url.php", { param1: "value1", param2: "value2" } );
Regardless of whether you are or arent using AJAX, there are limits to the actual length of the Url which changes browser to browser.
It will be better POST all your data. Below is the code to do the same using AJAX:
var http = new XMLHttpRequest(); // Get the correct http object depending on browser
var url = "YOUR_URL.php";
var params = "param1=value1¶m2=value2";
http.open("POST", url, true);
//Send the proper header information along with the request
http.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
http.setRequestHeader("Content-length", params.length);
http.setRequestHeader("Connection", "close");
http.onreadystatechange = function() { // Call a function when the state changes.
if(http.readyState == 4 && http.status == 200) {
alert(http.responseText);
}
}
http.send(params);
Hope this helps.