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How to solve the java.nio.file.NoSuchFileException?

I have a file called "result.csv", from that file i want to read certain data and display them. I have that file in my eclipse project folder itself. Still i'm unable to read the file.
public static void main(String [] args) {
int i=0;
String filename="result.csv";
Path pathToFile = Paths.get(filename);
try (BufferedReader br = Files.newBufferedReader(pathToFile, StandardCharsets.US_ASCII)) {
// read the first line from the text file
String line = br.readLine();
// loop until all lines are read
while (i<10) {
// use string.split to load a string array with the values from
// each line of
// the file, using a comma as the delimiter
String[] attributes = line.split(",");
double x=Double.parseDouble(attributes[8]);
double y=Double.parseDouble(attributes[9]);
System.out.println(GeoHash.withCharacterPrecision(x, y, 10));
// read next line before looping
// if end of file reached, line would be null
line = br.readLine();
i++;
}
} catch (IOException ioe) {
ioe.printStackTrace();
}
}
OUTPUT:
java.nio.file.NoSuchFileException: result.csv
at sun.nio.fs.WindowsException.translateToIOException(Unknown Source)
at sun.nio.fs.WindowsException.rethrowAsIOException(Unknown Source)
at sun.nio.fs.WindowsException.rethrowAsIOException(Unknown Source)
at sun.nio.fs.WindowsFileSystemProvider.newByteChannel(Unknown Source)
at java.nio.file.Files.newByteChannel(Unknown Source)
at java.nio.file.Files.newByteChannel(Unknown Source)
at java.nio.file.spi.FileSystemProvider.newInputStream(Unknown Source)
at java.nio.file.Files.newInputStream(Unknown Source)
at java.nio.file.Files.newBufferedReader(Unknown Source)
at com.uvce.cse.searchiot.geohash.TestGeoHash.main(TestGeoHash.java:19)
Can anyone point where exactly i missed? and how can i overcome this or any alternate methods for this method?

The problem is that your default directory at application startup is not what you think it is. Try adding the following line to your code, just after you create the path:
public static void main(String [] args) {
int i=0;
String filename="result.csv";
Path pathToFile = Paths.get(filename);
System.out.println(pathToFile.toAbsolutePath());
That way, you'll see exactly where it is looking for the file.
How to fix it is your decision. You can use a full path spec instead of just a filename, or put the filename in a special "Resources" directory and reference it using a relative path, or move the file to wherever your default directory is.

If your file("result.csv") in the src directory, you should use the "src/result.csv" instead of "result.csv".

The problem there is that java isn't able to find the "result.csv" file in the project folder. Thus, try to use the fully qualified path to the file, e.g. C:\your_folder\project\result.csv in the Path variable. Also I think It would be better to use bufferedreader like this: BufferedReader br = new BufferedReader(new FileReader(insert here the String in which is defined the path to the file)); Check the uses of BufferedReader here

If you're a MacOSX user please type the file path manually instead of copying it from "Get Info".
You'll get something like this if you copied it from "Get Info":
/Users/username<200e><2068><2068>/Desktop<2069>/source.txt

I had the same error caused by escaped characters on windows file path. For example, my application was looking for "C:\Users\david\my%20folder%20name\source.txt" meanwhile the real path was "C:\Users\david\my folder name\source.txt".

Not discarding all possible solutions here, this error also occurs when your running Android Studio on Windows environment and using a project directory on an external hard drive formatted with other than NFTS. ]
If this is the case, simply move your project into the main HDD (NTFS) and reload the project again , this time from the main HDD folder path.

Error trying to read from a text file [duplicate]

I have a file named "word.txt".
It is in the same directory as my java file.
But when I try to access it in the following code this file not found error occurs:
Exception in thread "main" java.io.FileNotFoundException: word.txt
(The system cannot find the file specified)
at java.io.FileInputStream.open(Native Method)
at java.io.FileInputStream.<init>(Unknown Source)
at java.util.Scanner.<init>(Unknown Source)
at Hangman1.main(Hangman1.java:6)
Here's my code:
import java.io.File;
import java.util.*;
public class Hangman1 {
public static void main(String[] args) throws Exception {
Scanner input = new Scanner(new File("word.txt"));
String in = "";
in = input.nextLine();
}
}

Put the word.txt directly as a child of the project root folder and a peer of src
Project_Root
src
word.txt
Disclaimer: I'd like to explain why this works for this particular case and why it may not work for others.
Why it works:
When you use File or any of the other FileXxx variants, you are looking for a file on the file system relative to the "working directory". The working directory, can be described as this:
When you run from the command line
C:\EclipseWorkspace\ProjectRoot\bin > java com.mypackage.Hangman1
the working directory is C:\EclipseWorkspace\ProjectRoot\bin. With your IDE (at least all the ones I've worked with), the working directory is the ProjectRoot. So when the file is in the ProjectRoot, then using just the file name as the relative path is valid, because it is at the root of the working directory.
Similarly, if this was your project structure ProjectRoot\src\word.txt, then the path "src/word.txt" would be valid.
Why it May not Work
For one, the working directory could always change. For instance, running the code from the command line like in the example above, the working directory is the bin. So in this case it will fail, as there is not bin\word.txt
Secondly, if you were to export this project into a jar, and the file was configured to be included in the jar, it would also fail, as the path will no longer be valid either.
That being said, you need to determine if the file is to be an embedded-resource (or just "resource" - terms which sometimes I'll use interchangeably). If so, then you will want to build the file into the classpath, and access it via an URL. First thing you would need to do (in this particular) case is make sure that the file get built into the classpath. With the file in the project root, you must configure the build to include the file. But if you put the file in the src or in some directory below, then the default build should put it into the class path.
You can access classpath resource in a number of ways. You can make use of the Class class, which has getResourceXxx method, from which you use to obtain classpath resources.
For example, if you changed your project structure to ProjectRoot\src\resources\word.txt, you could use this:
InputStream is = Hangman1.class.getResourceAsStream("/resources/word.txt");
BufferedReader reader = new BufferedReader(new InputStreamReader(is));
getResourceAsStream returns an InputStream, but obtains an URL under the hood. Alternatively, you could get an URL if that's what you need. getResource() will return an URL
For Maven users, where the directory structure is like src/main/resources, the contents of the resources folder is put at the root of the classpath. So if you have a file in there, then you would only use getResourceAsStream("/thefile.txt")

Relative paths can be used, but they can be tricky. The best solution is to know where your files are being saved, that is, print the folder:
import java.io.File;
import java.util.*;
public class Hangman1 {
public static void main(String[] args) throws Exception {
File myFile = new File("word.txt");
System.out.println("Attempting to read from file in: "+myFile.getCanonicalPath());
Scanner input = new Scanner(myFile);
String in = "";
in = input.nextLine();
}
}
This code should print the folder where it is looking for. Place the file there and you'll be good to go.

Your file should directly be under the project folder, and not inside any other sub-folder.
If the folder of your project is named for e.g. AProject, it should be in the same place as your src folder.
Aproject
src
word.txt

Try to create a file using the code, so you will get to know the path of the file where the system create
File test=new File("check.txt");
if (test.createNewFile()) {
System.out.println("File created: " + test.getName());
}

I was reading path from a properties file and didn't mention there was a space in the end.
Make sure you don't have one.

Make sure when you create a txt file you don't type in the name "name.txt", just type in "name". If you type "name.txt" Eclipse will see it as "name.txt.txt". This solved it for me. Also save the file in the src folder, not the folder were the .java resides, one folder up.

I have the same problem, but you know why? because I didn't put .txt in the end of my File and so it was File not a textFile, you shoud do just two things:
Put your Text File in the Root Directory (e.x if you have a project called HelloWorld, just right-click on the HelloWorld file in the package Directory and create File
Save as that File with any name that you want but with a .txt in the end of that
I guess your problem is solved, but I write it to other peoples know that.
Thanks.

i think it always boils to the classpath. having said that if you run from the same folder where your .class is then change Scanner input = new Scanner(new File("word.txt")); to Scanner input = new Scanner(new File("./word.txt")); that should work

Reading a text file from expected path in java

I want to read a file from directory.File is in root directory. If i use path as E:\Java\Netbeans_practice\project_141\Description.txt then it works fine.But when i wanted to use path as the file name or within a defined folder as Info\Description.txt , it gives error (java.io.FileNotFoundException: Description.txt (The system cannot find the file specified)). Actually i don't want to use the path name before project directory (ex: E:\Java\Netbeans_practice\project_141).I have searched a lot but unable to solve.Please help me. Here is my portion of code :
Scanner in = new Scanner(new FileReader("Description.txt");
while(in.hasNextLine()){
out.print("* "+in.nextLine()+"<br>");
}

When you deploy your web app, only the contents inside the "WebContent" will be deployed. You can verify this by going to (assuming you are using tomcat in your eclipse):
projectworkspace\.metadata\.plugins\org.eclipse.wst.server.core\tmp0\wtpwebapps\<contextName>
So you may wanan copy your "Description.txt" file into "/WEB-INF" (for security sake) directory. Then you should be able to access it:
File file = new File(getServletContext().getRealPath("/WEB-INF/Description.txt"));
Update:
String path="/WEB-INF/Description.txt";
InputStream inputStream = this.getServletConfig().getServletContext().getResourceAsStream(path);
BufferedReader reader = new BufferedReader(new InputStreamReader(inputStream));

The system cannot find the file specified in java

I am making a program that opens and reads a file.
This is my code:
import java.io.*;
public class FileRead{
public static void main(String[] args){
try{
File file = new File("hello.txt");
System.out.println(file.getCanonicalPath());
FileInputStream ft = new FileInputStream(file);
DataInputStream in = new DataInputStream(ft);
BufferedReader br = new BufferedReader(new InputStreamReader(in));
String strline;
while((strline = br.readLine()) != null){
System.out.println(strline);
}
in.close();
}catch(Exception e){
System.err.println("Error: " + e.getMessage());
}
}
}
but when I run, I get this error:
C:\Users\User\Documents\Workspace\FileRead\hello.txt
Error: hello.txt (The system cannot find the file specified)
my FileRead.java and hello.txt where in the same directory that can be found in:
C:\Users\User\Documents\Workspace\FileRead
I'm wondering what I am doing wrong?

Try to list all files' names in the directory by calling:
File file = new File(".");
for(String fileNames : file.list()) System.out.println(fileNames);
and see if you will find your files in the list.

I have copied your code and it runs fine.
I suspect you are simply having some problem in the actual file name of hello.txt, or you are running in a wrong directory. Consider verifying by the method suggested by #Eng.Fouad

You need to give the absolute pathname to where the file exists.
File file = new File("C:\\Users\\User\\Documents\\Workspace\\FileRead\\hello.txt");

In your IDE right click on the file you want to read and choose "copy path"
then paste it into your code.
Note that windows hides the file extension so if you create a text file "myfile.txt" it might be actually saved as "myfile.txt.txt"

Generally, just stating the name of file inside the File constructor means that the file is located in the same directory as the java file. However, when using IDEs like NetBeans and Eclipse i.e. not the case you have to save the file in the project folder directory. So I think checking that will solve your problem.

How are you running the program?
It's not the java file that is being ran but rather the .class file that is created by compiling the java code. You will either need to specify the absolute path like user1420750 says or a relative path to your System.getProperty("user.dir") directory. This should be the working directory or the directory you ran the java command from.

First Create folder same as path which you Specified. after then create File
File dir = new File("C:\\USER\\Semple_file\\");
File file = new File("C:\\USER\\Semple_file\\abc.txt");
if(!file.exists())
{
dir.mkdir();
file.createNewFile();
System.out.println("File,Folder Created.);
}

When you run a jar, your Main class itself becomes args[0] and your filename comes immediately after.
I had the same issue: I could locate my file when provided the absolute path from eclipse (because I was referring to the file as args[0]). Yet when I run the same from jar, it was trying to locate my main class - which is when I got the idea that I should be reading my file from args[1].

Getting error saying file won't open in Java...any idea why this is happening?

I think I am really close, but I am unable to open a file I have called LocalNews.txt. Error says can't find file specified.
String y = "LocalNews.txt";
FileInputStream fstream = new FileInputStream(y);
DataInputStream in = new DataInputStream(fstream);
BufferedReader br = new BufferedReader(new InputStreamReader(in));
Name of file is LocalNews.txt in library called News....anyone know why the file will not open?
The file is in the same Java Project that I am working on.
Error: LocalNews.txt (The system cannot find the file specified)
Project is named Bst, package is src in subPackage newsFinder, and library that the text files are stored in is called News.
Found out it was looking in
C:\EclipseIndigoWorkspace1\Bst\bin\LocalNews.txt
But I want it to look in (I believe)
C:\EclipseIndigoWorkspace1\Bst\News\LocalNews.txt
But if I make the above url a string, I get an error.

String y = "LocalNews.txt";
instead use
String y = "path from root/LocalNews.txt"; //I mean the complete path of the file

Your program can probably not find the file because it is looking in another folder.
Try using a absolute path like
String y = "c:\\temp\\LocalNews.txt";

By 'library called News' I assume you mean a jar file like News.jar which is on the classpath and contains the LocalNews.txt file you need. If this is the case, then you can get an InputStream for it by calling:
InputStream is = Thread.currentThread().getContextClassLoader()
.getResourceAsStream("LocalNews.txt");

Use
System.out.println(System.getProperty("user.dir") );
to find out what your current directory is. Then you'll know for sure whether your file is in the current directory or not. If it is not, then you have to specify the path so that it looks in the right directory.
Also, try this -
File file = new File (y);
System.out.println(file.getCanonicalPath());
This will tell you the exact path of your file on the system, provided your file is in the current directory. If it does not, then you know your file is not in the current directory.