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How to validate if XML matches the XSD using the xmlet / XsdParser in Java

I am trying to validate if the XML adheres to XSD. To achieve this I am using xmlet/XsdParser But I am unable to find any good example apart from the GitHub page.
In the readme doc, they have provided only how to convert the XSD to the respective Java objects but it does not show how to validate if the XML matches the XSD.
Following is the code that I have which reads the XSD and creates the Java Object:
public class XSDParser {
public static void main(String[] args) throws URISyntaxException {
String xsdPath = Paths.get(XSDParser.class.getClassLoader().getResource("test.xsd").toURI()).toFile().getAbsolutePath();
String filePath = Path.of(xsdPath).toString();
XsdParser parserInstance = new XsdParser(filePath);
System.out.println(filePath);
Stream<XsdElement> elementsStream = parserInstance.getResultXsdElements();
Stream<XsdSchema> schemasStream = parserInstance.getResultXsdSchemas();
}
}
This code reads the XSD file and creates the Stream of the element. Now I have also added the following lines of the code which will read the XML file and create the stream:
String absolutePath = Paths.get(ApplicationMain.class.getClassLoader().getResource("inputXML.xml").toURI()).toFile()
.getAbsolutePath();
String path = Path.of(absolutePath).toString();
File xml = new File(path);
InputStream stream = new FileInputStream(xml);
Now, I want to know if my XML adheres to the XSD that I have read and stored. How to achieve this?
I would like to use the XMLET/XSDPARSER to parse my XSD file.
I am using the SAX PARSER to parse my XML file.
I am unable to find any good example on the net which has been implemented using the XMLET/XSDPARSER.
Any help would be really appreciated. Thanks.

The library you're using is apparently a library for analysing XSD schemas, not for using the schema for validation, so you're using the wrong tool for the job. You can perform XSD 1.0 validation in Java using the JAXP interfaces (see https://docs.oracle.com/javase/tutorial/jaxp/dom/validating.html), and if you want to use XSD 1.1, download Apache Xerces or Saxon.

Java - How to extract information from many XML files in a directory and export it to an excel file

I am trying to get information from many xml files in a directory.
How can I get specific information from each one and send it to an excel file, in java?
file 1.xml
file 2.xml
file 3.xml
*********
**file.csv** or .**xls** with the information of the 'n' files XML

there are several libraries on Java that can help you to do so.
For instance, for getting information from XML you can use dom4j and extract the specific information make use of the query language XPATH, supported by the library (examples). And to read all the XML files form a directory, Java 8 has an easy way of achieving that.
Files.list(Paths.get("/path/to/xml/files"))
.map(YourXMLParser::parse)
.forEach(XLSExporter::export);
where parse method would have the signature:
public MyDataBean parse(Path path) {
InputStream inputStream = Files.newInputStream(Path);
SAXBuilder saxBuilder = new SAXBuilder(inputStream);
... <-- Making use of SAX for instance and return the read data in a custom Bean (MyDataBean)
}
As Files.list() method return Stream you can take advantage of that to use map and forEach.
Once you have the information from each XML files to you can export to XLS using the most used library in Java for it: Apache POI
I hope it can help.

Storing html values in xml

Trying to figure out a way to strip out specific information(name,description,id,etc) from an html file leaving behind the un-wanted information and storing it in an xml file.
I thought of trying using xslt since it can do xml to html... but it doesn't seem to work the other way around.
I honestly don't know what other language i should try to accomplish this. i know basic java and javascript but not to sure if it can do it.. im kind of lost on getting this started.
i'm open to any advice/help. willing to learn a new language too as i'm just doing this for fun.

There are a number of Java libraries for handling HTML input that isn't well-formed (according to XML). These libraries also have built-in methods for querying or manipulating the document, but it's important to realize that once you've parsed the document it's usually pretty easy to treat it as though it were XML in the first place (using the standard Java XML interfaces). In other words, you only need these libraries to parse the malformed input; the other utilities they provide are mostly superfluous.
Here's an example that shows parsing HTML using HTMLCleaner and then converting that object into a standard org.w3c.dom.Document:
TagNode tagNode = new HtmlCleaner().clean("<html><div><p>test");
DomSerializer ser = new DomSerializer(new CleanerProperties());
org.w3c.dom.Document doc = ser.createDOM(tagNode);
In Jsoup, simply parse the input and serialize it into a string:
String text = Jsoup.parse("<html><div><p>test").outerHtml();
And convert that string into a W3C Document using one of the methods described here:
How to parse a String containing XML in Java and retrieve the value of the root node?
You can now use the standard JAXP interfaces to transform this document:
TransformerFactory tFact = TransformerFactory.newInstance();
Transformer transformer = tFact.newTransformer();
Source source = new DOMSource(doc);
Result result = new StreamResult(System.out);
transformer.transform(source, result);
Note: Provide some XSLT source to tFact.newTransformer() to do something more useful than the identity transform.

I would use HTMLAgilityPack or Chris Lovett's SGMLReader.
Or, simply HTML Tidy.

Ideally, you can treat your HTML as XML. If you're lucky, it will already be XHTML, and you can process it as HTML. If not, use something like http://nekohtml.sourceforge.net/ (a HTML tag balancer, etc.) to process the HTML into something that is XML compliant so that you can use XSLT.
I have a specific example and some notes around doing this on my personal blog at http://blogger.ziesemer.com/2008/03/scraping-suns-bug-database.html.

TagSoup
JSoup
Beautiful Soup

Dynamic XML creation in Java

I am trying to dynamically y create an XML file in Java to display a timetable. I have created a DTD for my XML file and I have an XSL file I would like to use to transform the XML. I don't know exactly how to continue.
What I've tried so far is onClick of some button a Servlet is called which generates the string of the content of the XML file (inserting the dynamic parts of the XML into the String. I now have a String containing the content of the XML file. I would now like to transform the XML file using an XSL file i have on my server and display the result in the page which has called the Servlet (doing this via AJAX).
I'm not sure if I'm in the direction, perhaps I shouldn't even create the XML code in String form from the beginning. So my question is, how do I continue from here? how do I transform the XML string, using the XSL file, and send it as a response to the AJAX call so I can plant the generated code into the page? Or if this is not the way to do it, how do I create a dynamic XML file in a different way producing the same result?

You can use JAXP for this. It's part of standard Java SE API.
StringReader xmlInput = new StringReader(xmlStringWhichYouHaveCreated);
InputStream xslInput = getServletContext().getResourceAsStream("file.xsl"); // Or wherever it is. As long as you've it as an InputStream, it's fine.
Source xmlSource = new StreamSource(xmlInput);
Source xslSource = new StreamSource(xslInput);
Result xmlResult = new StreamResult(response.getOutputStream()); // XML result will be written to HTTP response.
Transformer transformer = TransformerFactory.newInstance().newTransformer(xslSource);
transformer.transform(xmlSource, xmlResult);

Depending on how complicated and large your XML is going to be I would suggest two options. For small, simple structures Java's DOM implementation (Document) will suffice.
If your XML is more elaborate I would look into JAXB. The benefit there is that there are tools that automatically create Java classes from an XML schema (XSD). So you'd have to transform your DTD into an XSD first, but that shouldn't be a problem. You end up with plain data transfer objects (plain objects with getters/setters for the values of the corresponding XML elements) and parsing/encoding plus setting namespaces correctly is done for you. It's quite convenient but can also be a bit of an overkill for simple XML structures.
In both cases, you will end up with a Document instance that you can finally transform using JAXP.

Apache XMLBeans are a nice solution to serializing to and from XML. Here's what you need to do:
Download XMLBeans from http://www.apache.org/dyn/closer.cgi/xmlbeans/binaries
Use the XMLBeans inst2xsd executable (in the bin dir0 to convert your DTD to an XSD
Use the XMLBeans ANT task to convert the XSD into classes which you can use in your app
Here's an example ANT script to use XMLBeans to create the classes:
<project name="my_project" basedir="..">
<property name="my_project.project.path" value="${basedir}"/>
<property name="xbean.dir" value="C:/lib/xmlbeans-2.2.0/lib" />
<path id="classpath">
<fileset dir="${xbean.dir}" includes="**/*.jar" />
</path>
<taskdef name="xmlbean" classname="org.apache.xmlbeans.impl.tool.XMLBean" classpathref="classpath" />
<xmlbean schema="${testing_project.project.path}/my.xsd" srcgendir="${my_project.project.path}/src-tms-template-filter-fields" classgendir="${my_project.project.path}/bin">
<classpath><path refid="classpath" /></classpath>
</xmlbean>
You'll now have nice Java classes which you can use for clean code to create the XML from the data stored in your DB. Use BalusC's answer for the XSLT.

How to create XML file?

I have some data which my program discovers after observing a few things about files.
For instance, i know file name, time file was last changed, whether file is binary or ascii text, file content (assuming it is properties) and some other stuff.
i would like to store this data in XML format.
How would you go about doing it?
Please provide example.

If you want something quick and relatively painless, use XStream, which lets you serialise Java Objects to and from XML. The tutorial contains some quick examples.

Use StAX; it's so much easier than SAX or DOM to write an XML file (DOM is probably the easiest to read an XML file but requires you to have the whole thing in memory), and is built into Java SE 6.
A good demo is found here on p.2:
OutputStream out = new FileOutputStream("data.xml");
XMLOutputFactory factory = XMLOutputFactory.newInstance();
XMLStreamWriter writer = factory.createXMLStreamWriter(out);
writer.writeStartDocument("ISO-8859-1", "1.0");
writer.writeStartElement("greeting");
writer.writeAttribute("id", "g1");
writer.writeCharacters("Hello StAX");
writer.writeEndDocument();
writer.flush();
writer.close();
out.close();

Standard are the W3C libraries.
final Document docToSave = DocumentBuilderFactory.newInstance().newDocumentBuilder().newDocument();
final Element fileInfo = docToSave.createElement("fileInfo");
docToSave.appendChild(fileInfo);
final Element fileName = docToSave.createElement("fileName");
fileName.setNodeValue("filename.bin");
fileInfo.appendChild(fileName);
return docToSave;
XML is almost never the easiest thing to do.

You can use to do that SAX or DOM, review this link: https://web.archive.org/web/1/http://articles.techrepublic%2ecom%2ecom/5100-10878_11-1044810.html
I think is that you want