Dont want the 1st position in array [duplicate] - java

This question already has answers here:
How to create a sub array from another array in Java?
(8 answers)
Closed 8 years ago.
I have one array, say
String[] a={a,b,c,d,e,f,g}
I want this array in second array but without the first element in the array, for example
String[] b{b,c,d,e,f,g}
How do I achieve this?

You can use System.arrayCopy() (jdk 1.5) or Arrays.copyOfRange() (jdk 1.6+) methods.

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How do I assign List<Project> to Project[ ] in Java? [duplicate]

This question already has answers here:
Converting 'ArrayList<String> to 'String[]' in Java
(17 answers)
Closed 3 years ago.
I am trying to initialize an array object with a get method which returns an arraylist object. I have tried using .toArray() to convert but it didn't work.
Would Project[] projects = list.toArray(new Project[[0]]) work? The reason it doesn't work normally is because by default toArray returns an Object[], and the JVM is unable to cast that to a Project[]. Passing in the project array allows it to determine the type of the desired array.

pick first N elements from a static list java [duplicate]

This question already has answers here:
Get only part of an Array in Java? [duplicate]
(8 answers)
Fastest way to get the first n elements of a List into an Array
(6 answers)
Closed 4 years ago.
I want to pick first N elements from a list in java
String[] ligature = new String{there,is not,a,single,person,who,knows,the,answer};
Now I want to pick first 5 elements from this.something like
Stiring[] selectedLigature = ligature[0:4];
I want to do it without using for loop.
Do not stream this simple case, there is subList for this:
// for a List
yourList.subList(0, 5)...
// for an array
Arrays.copyOfRange
Arrays class has a method for this:
Arrays.copyOfRange(ligature, 0, 5);

Arrays.asList(int_array).indexOf(int_element) returns -1 even if element is present java [duplicate]

This question already has answers here:
Converting array to list in Java
(24 answers)
Closed 5 years ago.
I have taken an int[] as input. For searching the index of an integer in the array I used Arrays.asList(arr).indexOf(element) method. However, I am getting index as -1 even if the element is present in the array.
int[] is one object, so Arrays.asList(arr) puts one object in the list, you need to put values from int[] one by one

how to use toString in arrays [duplicate]

This question already has answers here:
What's the simplest way to print a Java array?
(37 answers)
Closed 5 years ago.
how to use toString() method in arrays bigger than one dimensional for example
int[][][] array = new array[x][y][z];
print one dimensional
Ststem.out.print(array[a][b].toString());
print all dimensional
System.out.print(array.toString());
my console only show :
[I#15db9742
You have a multidimentional array so you need to do:
Arrays.deepToString(array);
or nest for loops and print the element at index i,j,k
It looks like more like Java :).
In any case, I'd create a function that iterates through the different levels and print each element of the array.

How to declare an array in java [duplicate]

This question already has answers here:
How do I declare and initialize an array in Java?
(31 answers)
Closed 6 years ago.
What does the below line of code mean?
is it a legal way to declare or define an array.
I googled it but couldn't find any information regarding this.
int[] []x[]
This is a valid line of code. It references a 3 dimensional integer array. Following codes are equivalent:
int[][][]x
int[][]x[]
int[]x[][]
int x[][][]
All of them are reference to a 3 dimensional integer array. You can declare a 10x10x10 size array like the following:
x = new int[10][10][10];

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