I'm new to java and i need some help. I got few things to do and i'm stuck
with this problem. I really have no idea how to do it...
So in CMD line if i enter banana banana apple apple -name Carlos banana Mike -c 8
it will print "Hello Carlos!" eight times.
public class cheese {
public static void main(String args[]) {
for(String s: args){
if(s.equals("-name")){
String p = (GIVE VALUE OF FIRST ARGUMENT AFTER "-name");
if (s.equals("-c")){
int i = Integer.parseInt(THE FIRST ARGUMENTS AFTER "-c");
for(int j=0; j >= i ; j++)
System.out.println("Hello "+p+"!");
}
}
}
}
}
Parsing command-line arguments properly is surprisingly hard, and there are lots of libraries that can help. Your example code can be rearranged as follows to make it work (but it has no real error handling, so there are lots of ways to make it go wrong, such as passing "-name" twice, or not supplying enough arguments).
public class CmdLine {
public static void main(String args[]) {
String p = "";
int i = 0;
for (int k = 0; k < args.length; k++) {
if (args[k].equals("-name")) {
p = args[k + 1];
} else if (args[k].equals("-c")) {
i = Integer.parseInt(args[k + 1]);
}
}
for (int j = 0; j < i; j++) {
System.out.println("Hello " + p + "!");
}
}
}
Related
What is the error in following code while trying command line arguments ? I am getting an error at line System.out.println(args[i]);
public class CommandLA{
public static void main(String []args)
{
int s = 0;
for(int i=0;i<args.length;i++)
System.out.println(args[i]);
s = s + Integer.parseInt(args[i]);
System.out.println("Sum is : "+s);
}
}
maybe
public static void main(String []args)
{
int s = 0;
for (String str : args) {
s = s + Integer.parseInt(str);
}
System.out.println("Sum is : "+s);
}
or using an indexed for
public static void main(String []args)
{
int s = 0;
for (int i = 0; i < args.length; i++) {
s = s + Integer.parseInt(args[i]);
}
System.out.println("Sum is : "+s);
}
Simple:
for(int i=0;i<args.length;i++)
System.out.println(args[i]);
followed by
s = s + Integer.parseInt(args[i]);
But - you are missing the { after the loop! Therefore the scope in which i exists (is visible) is only the line directly after the "for-loop" line!
In other words you need for (..) { all stuff that uses i }!
To elaborate on the answer of GhostCat:
for(int i=0;i<args.length;i++)
System.out.println(args[i]);
s = s + Integer.parseInt(args[i]);
is the same as
for(int i=0;i<args.length;i++){
System.out.println(args[i]);
}
s = s + Integer.parseInt(args[i]);
Which means that in the last line, i is not known, resulting in an error.
I wonder why the error was detected at the line before, because until that, the code is technically correct.
That said, I recommend to use brackets in any case. Some people omit them to get shorter code, but that means that if one adds a line later on, he could easily make a mistake. This is personal preference, of course.
I am writing a Java program that will take a sentence (or phrase) and translate it into a group of objects that the computer can easily read. I wanted to make a simple word separating program, and then extend it later on.
My code is like this:
package Literary;
import java.util.ArrayList;
public class WordParser {
public static String[] getWords(String tempone){
ArrayList<String> temptwo = new ArrayList();
ArrayList<Character> tempthree = new ArrayList();
for (int tempfour = 0; tempfour == tempone.length() - 1; tempfour++){
if (tempone.charAt(tempfour) != ' '){
tempthree.add(tempone.charAt(tempfour));
} else {
temptwo.add(getStringRepresentation(tempthree));
tempthree.clear();
}
}
String[] tempfive = new String[temptwo.size()];
for (int tempfour = 0; tempfour == tempfive.length - 1; tempfour++){
tempfive[tempfour] = temptwo.get(tempfour);
}
return tempfive;
}
/** Courtesy of Vineet Reynolds on StackExchange.
*
* "You can iterate through the list and create the string."
*
* #param list
* #return
*/
public static String getStringRepresentation(ArrayList<Character> list){
StringBuilder builder = new StringBuilder(list.size());
for(int i = 0; i == list.size() + 1; i++)
{
builder.append(list.get(i).charValue());
}
return builder.toString();
}
}
It's supposed to receive a string as an input, and return a list of strings that have been separated by spaces.
But when I run my main class:
import Literary.WordParser;
public class Start {
public static void main(String[] args) {
String x = "There was once a sword in the stone";
String[] tempstring = WordParser.getWords(x);
for (int i = 1; i == tempstring.length; i++){
System.out.println("Word " + i + " : " + tempstring[i]);
}
}
}
The console tells me nothing except run: and BUILD SUCCESSFUL (total time: 1 second).
I'm using Netbeans 8 and Java 1.7 if that helps.
Looks like the problem's here:
for (int i = 1; i == tempstring.length; i++) {
This for loop will run at most once: if tempstring is exactly one String long, it should print out the word.
However, since your test sentence has 8 words, nothing will ever print out (provided WordParser works correctly).
You probably want to change this line to: (note the < between i and tempstring.length.)
for (int i = 1; i < tempstring.length; i++) {
so that it will loop through all the items in tempstring.
You had multiple issues in your code:
1) for loops were not properly made, they would never execute. Use either !=, > or < instead of ==.
2) you don't need a method getWords() nor getStringRepresentation(). Method like that are already implemented in Java.
So the final code should be this:
public class WordParser {
public static String[] getWords(String tempone) {
return tempone.split(" ");
}
public static void main(String[] args) {
String x = "There was once a sword in the stone";
String[] tempstring = WordParser.getWords(x);
for (int i = 0; i < tempstring.length; i++) {
System.out.println("Word " + (i+1) + " : " + tempstring[i]);
}
}
}
Output:
Word 1 : There
Word 2 : was
Word 3 : once
Word 4 : a
Word 5 : sword
Word 6 : in
Word 7 : the
Word 8 : stone
I've also fixed your code that runs the same as above, if you are interested:
import java.util.ArrayList;
public class WordParser {
public static String[] getWords(String tempone) {
ArrayList<String> sarr = new ArrayList<String>();
ArrayList<Character> tempthree = new ArrayList<Character>();
String[] ansarr;
if(tempone.charAt(tempone.length()-1) != ' ')
tempone += " "; //Add white space to the end to catch the last word
for (int i = 0; i < tempone.length(); i++) {
if (tempone.charAt(i) != ' ') {
tempthree.add(tempone.charAt(i));
} else {
sarr.add(tempthree.toString());
tempthree.clear();
}
}
ansarr = new String[sarr.size()];
for (int i = 0; i < ansarr.length; i++) {
ansarr[i] = sarr.get(i);
}
return ansarr;
}
public static void main(String[] args) {
String x = "There was once a sword in the stone";
String[] tempstring = WordParser.getWords(x);
for (int i = 0; i < tempstring.length; i++) {
System.out.println("Word " + (i+1) + " : " + tempstring[i]);
}
}
}
Enjoy! :)
I think you should use String.split(" ") which seems to do the same thing
Change your main method as follows,
and it will work
public static void main(String[] args) {
String x = "There was once a sword in the stone";
String[] tempstring = WordParser.getWords(x);
for (int i = 1; i <= tempstring.length; i++){
System.out.println("Word " + i + " : " + tempstring[i - 1]);
}
}
For the WordParser you could use,
public class WordParser
{
public static String[] getWords(String tempone)
{
return tempone.split(" ");
}
}
First of, I would recommend using the split method to break up a sentence
it is defined as:
public String[] split(String regex, int limit)
and you can simply call
String s1=new String("Random words in a sentence");
String[] words=s1.split(" ");
in order to break the string up into words and you will now have a String
array of five elements where each element consists of a word
In Respect to your question, you are not using the conditional statement correctly
You want to iterate over the elements of the String array WHILE the position
is less than stringname.length, not only if it the position equals the stringname.length
Therefore, you must make the following changes in these parts of your code
For Example:
for (int i = 1; i == tempstring.length; i++)
should have its line changed to
for (int i = 1; i < tempstring.length; i++)
and this problem also occurs in various places in your WordParser.java file
It is useful to remember also that you may often want to start at index 0 instead
of index 1, as java has its' first indice as 0.
I have a java program where the following is what I wanted to achieve:
first input: ABC
second input: xyz
output: AxByCz
and my Java program is as follows:
import java.io.*;
class DisplayStringAlternately
{
public static void main(String[] arguments)
{
String firstC[], secondC[];
firstC = new String[] {"A","B","C"};
secondC = new String[] {"x","y","z"};
displayStringAlternately(firstC, secondC);
}
public static void displayStringAlternately (String[] firstString, String[] secondString)
{
int combinedLengthOfStrings = firstString.length + secondString.length;
for(int counter = 1, i = 0; i < combinedLengthOfStrings; counter++, i++)
{
if(counter % 2 == 0)
{
System.out.print(secondString[i]);
}
else
{
System.out.print(firstString[i]);
}
}
}
}
however I encounter the following runtime error:
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 3
AyC at DisplayStringAlternately.displayStringAlternately(DisplayStringAlternately.java:23)
at DisplayStringAlternately.main(DisplayStringAlternately.java:12)
Java Result: 1
What mistake is in my Java program?
If both arrays have same length for loop should continue while i < anyArray.length.
Also you don't need any counter to determine from which array you should print first. Just hardcode that first element will be printed from firstString and next one from secondString.
So your displayStringAlternately method can look like
public static void displayStringAlternately(String[] firstString,
String[] secondString) {
for (int i = 0; i < firstString.length; i++) {
System.out.print(firstString[i]);
System.out.print(secondString[i]);
}
}
Anyway your code throws ArrayIndexOutOfBoundsException because each time you decide from which array print element you are incrementing i, so effectively you are jumping through arrays this way
i=0 i=2
{"A","B","C"};
{"x","y","z"};
i=1 i=3
^^^-here is the problem
so as you see your code tries to access element from second array which is not inside of it (it is out of its bounds).
As you commented, If both arrays length is same, you can simply do
firstC = new String[] {"A","B","C"};
secondC = new String[] {"x","y","z"};
Then
for(int i = 0; i < firstC.length; i++) {
System.out.print(firstC[i]);
System.out.print(secondC[i]);
}
Using the combined length of the Strings is wrong, since, for example, secondString[i] would cause an exception when i >= secondString.length.
Try the below working code with high performance
public static void main(String[] arguments)
{
String firstC[], secondC[];
firstC = new String[] {"A","B","C"};
secondC = new String[] {"x","y","z"};
StringBuilder builder = new StringBuilder();
for (int i = 0; i < firstC.length; i++) {
builder.append(firstC[i]);
builder.append(secondC[i]);
}
System.out.println(builder.toString());
}
public class concad {
public void main(String[] args) {
String s1 = "RAMESH";
String s2 = "SURESH";
int i;
int j;
for (i = 0; i < s1.length(); i++) {
System.out.print(s1.charAt(i));
for (j = i; j <= i; j++) {
if (j == i) {
System.out.print(s2.charAt(j));
}
}
}
}
}
I have taken two strings as mentioned.Then pass one counter variable in inner for-loop with second string,Then for every even position pass with code "counter%2".Check this out if any concern then comment below.
public class AlternatePosition {
public static void main(String[] arguments) {
String abc = "abcd";
String def = "efgh";
displayStringAlternately(abc, def);
}
public static void displayStringAlternately(String firstString, String secondString) {
for (int i = 0; i < firstString.length(); i++) {
for (int counter = 1, j = 0; j < secondString.length(); counter++, j++) {
if (counter % 2 == 0) {
System.out.print(secondString.charAt(i));
break;
} else {
System.out.print(firstString.charAt(i));
}
}
}
}
}
I need help sorting this array in alphabetical order using the bubble sort algorithm.
My code is:
public class Strings
{
public static void main(String[] args)
{
Scanner reader = new Scanner(System.in);
String tempStr;
System.out.print("Enter the strings > ");
String s1 = new String(reader.nextLine());
String[] t1 = s1.split(", ");
for (int t=0; t<t1.length-1; t++)
{
for (int i = 0; i<t1.length -1; i++)
{
if(t1[i+1].compareTo(t1[1+1])>0)
{
tempStr = t1[i];
t1[i] = t1[i+1];
t1[i+1] = tempStr;
}
}
}
for(int i=0;i<t1.length;i++)
{
System.out.println(t1[i]);
}
}
}
The code compiles, but it does not sort alphabetical. Please help me.
You have three errors in your code.
The first error is in the inner for loop, in the place where you do the check statement, it should be i < t1.length - t -1 not i < t1.length -1. You subtract t because you do not want to loop through the whole array again, only the first part of it.
The second and third errors are in the if statement. You need to turn the greater than symbol into a lesser than symbol, because the way you have the compareTo method set up, it will return a negative number.
The other error in this line is that in the compareTo parameter you put 1 + 1 it actually should be just i, because you want one less than the object it is comparing to.
The fixed working code is below (Comments are what you originally had):
public static void main(String[] args) {
Scanner reader = new Scanner(System.in);
String tempStr;
System.out.print("Enter the strings > ");
String s1 = new String(reader.nextLine());
String[] t1 = s1.split(", ");
for (int t = 0; t < t1.length - 1; t++) {
for (int i= 0; i < t1.length - t -1; i++) {
if(t1[i+1].compareTo(t1[i])<0) {
tempStr = t1[i];
t1[i] = t1[i + 1];
t1[i + 1] = tempStr;
}
}
}
for (int i = 0; i < t1.length; i++) {
System.out.println(t1[i]);
}
}
please change
String[] t1 = s1.split(", ");
to
String[] t1 = s1.split("");
This will solve the issue.
I have an encoded String like this:
17298457,abcdef/17298529,ghijklm/17298562,opq%2Frstu
and want to split it on the "/".
In the last part, there is a encoded "/" as "%2F".
The result is
[17298457,abcdef , 17298529,ghijklm , 17298562,opq , rstu]
The problem is, that Java decodes the string on the fly as soon as i pass it to another method (split method e.c.)
Do someone have a good idea how to work around that?
thanks a lot!
monk
Not for me....
import java.util.Arrays;
public class Test {
public static void main(String[] args) throws Exception {
String s = "17298457,abcdef/17298529,ghijklm/17298562,opq%2Frstu";
System.out.println(Arrays.toString(s.split("/")));
}
}
gives
[17298457,abcdef, 17298529,ghijklm, 17298562,opq%2Frstu]
public static void main(String[] args) {
String test = "17298457,abcdef/17298529,ghijklm/17298562,opq%2Frstu";
String[] args2 = test.split("/");
for (int i = 0; i < args2.length; i++) {
String[] args3 = args2[i].split("%2F");
for (int j = 0; j < args3.length; j++) {
if(!args3[j].trim().startsWith(",") && j != 0)
System.out.print(" ,");
System.out.print(args3[j]);
}
}
OUT PUT - AS U WRITTEN -
17298457,abcdef17298529,ghijklm17298562,opq ,rstu