There are two java classes both having main function. Now i have to call object of first class to the second and object of second class to first. Whenever i m doing this it is giving stack overflow exception. Is there any way to call these simulatneously?
First class :
public class ChangePasswordLogin extends javax.swing.JFrame {
Connection con = null;
Statement stmt = null;
ResultSet rs = null;
String message = null;
RandomStringGenerator rsg = new RandomStringGenerator();
MD5Generator pass = new MD5Generator();
PopUp popobj = new PopUp();
ForgotPassword fpemail = new ForgotPassword();
Second class:
public class ForgotPassword extends javax.swing.JFrame {
Connection con = null;
Statement stmt = null;
ResultSet rs = null;
String message = null;
String useremail;
PopUp popobj = new PopUp();
RandomStringGenerator rsg = new RandomStringGenerator();
MD5Generator pass = new MD5Generator();
ChangePasswordLogin cpl = new ChangePasswordLogin();
You've got recursion going on where class A creates an instance of class B in its constructor and class B creates an instance of A in its constructor or initiation code. This will continue on and on until you run out of memory. The solution is not to do this. Use setter methods to set the instances outside of the constructor and initiation code.
This can be demonstrated simply with:
// this will cause a StackOverfowException
public class RecursionEg {
public static void main(String[] args) {
A a = new A();
}
}
class A {
private B b = new B();
}
class B {
private A a = new A();
}
Solved with setter methods:
// this won't cause a StackOverfowException
public class RecursionEg {
public static void main(String[] args) {
A a = new A();
B b = new B();
a.setB(b);
b.setA(a);
}
}
class A {
private B b;
public void setB(B b) {
this.b = b;
}
}
class B {
private A a;
public void setA(A a) {
this.a = a;
}
}
Substitute ForgotPassword and ChangePasswordLoging for A and B.
Or you could get by like the code below, where you take care to create one instance of each type:
public class RecursionEg {
public static void main(String[] args) {
A a = new A();
}
}
class A {
private B b = new B(this);
}
class B {
private A a;
public B(A a) {
this.a = a;
}
public void setA(A a) {
this.a = a;
}
}
for educational purposes I am trying to understand how to access a list's maximum element(originally in class B) (in this case from a Double list) through another class e.g class A. The list is used in a different class in which elements are added to it (e.g class C). However, when I add something like this to my class A to access my Max element, it does not seem to work: // help is appreciated :) and the error I usually get is noSuchElementException
just a method of class A
void printMax () {
B b = new B();
Double result;
result = Collections.max(b.array);
System.out.println("MAX:" +result);
}
here is my class B:
public class B {
public ArrayList<Double> array;
B() {
array = new ArrayList<Double>();
}
public void doSomething() {
int i;
for(i = 0; i < array.size(); i++) {
System.out.println("Doubles:" +array.get(i));
}
}
public static void main(String[] args) {
// TODO Auto-generated method stub
new B().doSomething();
}
}
Here is my class C that adds to my ArrayList.
Class C {
public String line;
C () {
}
public void linePicker() {
B b = new B();
Scanner dScanner = new Scanner(line);
while (dScanner.hasNext()) {
if (dScanner.hasNextDouble()) {
b.array.add(dScanner.nextDouble());
break;
} else {
dScanner.next();
}
}
dScanner.close();
b.doSomething();
}
public static void main(String[] args) {
// TODO Auto-generated method stub
new C().linePicker();
}
}
According to the javadocs (http://docs.oracle.com/javase/7/docs/api/java/util/Collections.html#max(java.util.Collection,%20java.util.Comparator)), it throws that exception when the Collection is empty. You initialize b.array, but haven't added to it yet before calling max().
I am a newbie to Java (I come from the C/C++ background) and I was having a hard time figuring out how to allocated memory of a data member in one class from another. For eg,
Class A
{
B bInA;
C cInA;
public void foo(someValue)
{
cInA = new C();
cInA.foo(bInA, someValue)
}
public static void main(String args[])
{
A myA = new A();
myA.foo(xyz)
// myA.bInA.value should be equal to xyz
}
}
Class B { ... }
Class C
{
public void foo(bInA, someValue)
{
bInA = new B();
bInA.value = someValue;
}
}
Can I do something like this in java?
Any help will be much appreciated.
----EDIT-----
Class A
{
B bInA;
C cInA;
public void foo(someValue)
{
cInA = new C();
bInA = new B();
cInA.foo(bInA, someValue)
}
public static void main(String args[])
{
A myA = new A();
myA.foo(xyz)
// myA.bInA.value should be equal to xyz
}
}
Class B { ... }
Class C
{
public void foo(bInA, someValue)
{
bInA.value = someValue;
}
}
Unless I'm misunderstanding your intention (change value of bInA from C), your recent edit seems to work fine. Here's my java version of your pseudocode.
class A
{
B bInA;
C cInA;
public void foo(int someValue)
{
cInA = new C();
bInA = new B();
cInA.foo(bInA, someValue);
System.out.println(bInA.value);
}
public static void main(String args[])
{
A myA = new A();
myA.foo(123);
// myA.bInA.value should be equal to xyz
}
}
class B { int value; }
class C
{
public void foo(B bInA, int someValue)
{
bInA.value = someValue;
}
}
Output
123
Java does not have pass-by-reference; rather, all you ever have are references to objects, and those references must be passed by value. So your code is roughly equivalent to something like this in C++:
class A {
private:
B *bInA = NULL;
C *cInA = NULL;
public:
void foo(someValue) {
cInA->foo(bInA, someValue);
}
static void main() {
A *myA = new A();
myA->foo(xyz)
// myA->bInA->value should be equal to xyz
}
}
int main() {
A::main();
return 0;
}
class B { ... }
class C {
public:
void foo(bInA, someValue) {
bInA = new B(); // defeats the point of having passed in a bInA
bInA->value = someValue;
}
}
(Except that the C++ code has memory leaks, since you allocate some things without freeing them, whereas in Java that's not an issue.)
This is related to the following question:
How to improve the builder pattern?
I'm curious whether it's possible to implement a builder with the following properties:
Some or all parameters are required
No method receives many parameters (i.e., no list of defaults supplied to the initial builder factory method)
All builder fields can be reassigned an arbitrary number of times
The compiler should check that all parameters have been set
It is ok to require that parameters are initially set in some order, but once any parameter is set, all following builders can have this parameter set again (i.e., you can reassign the value of any field of the builder you wish)
No duplicate code should exist for setters (e.g., no overriding setter methods in builder subtypes)
One failed attempt is below (empty private constructors omitted). Consider the following toy builder implementation, and note that line with "Foo f2" has a compiler error because the inherited setter for a returns a BuilderB, not a BuilderFinal. Is there a way to use the java type system to parameterize the return types of the setters to achieve the above goals, or achieve them some other way.
public final class Foo {
public final int a;
public final int b;
public final int c;
private Foo(
int a,
int b,
int c) {
this.a = a;
this.b = b;
this.c = c;
}
public static BuilderA newBuilder() {
return new BuilderC();
}
public static class BuilderA {
private volatile int a;
public BuilderB a(int v) {
a = v;
return (BuilderB) this;
}
public int a() {
return a;
}
}
public static class BuilderB extends BuilderA {
private volatile int b;
public BuilderC b(int v) {
b = v;
return (BuilderC) this;
}
public int b() {
return b;
}
}
public static class BuilderC extends BuilderB {
private volatile int c;
public BuilderFinal c(int v) {
c = v;
return (BuilderFinal) this;
}
public int c() {
return c;
}
}
public static class BuilderFinal extends BuilderC {
public Foo build() {
return new Foo(
a(),
b(),
c());
}
}
public static void main(String[] args) {
Foo f1 = newBuilder().a(1).b(2).c(3).build();
Foo f2 = newBuilder().a(1).b(2).c(3).a(4).build();
}
}
Your requirements are really hard, but see if this generic solution fits the bill:
public final class Foo {
public final int a;
public final int b;
public final int c;
private Foo(
int a,
int b,
int c) {
this.a = a;
this.b = b;
this.c = c;
}
public static BuilderA<? extends BuilderB<?>> newBuilder() {
return new BuilderFinal();
}
public static class BuilderA<T extends BuilderB<?>> {
private volatile int a;
#SuppressWarnings("unchecked")
public T a(int v) {
a = v;
return (T) this;
}
public int a() {
return a;
}
}
public static class BuilderB<T extends BuilderC<?>> extends BuilderA<T> {
private volatile int b;
#SuppressWarnings("unchecked")
public T b(int v) {
b = v;
return (T) this;
}
public int b() {
return b;
}
}
public static class BuilderC<T extends BuilderFinal> extends BuilderB<T> {
private volatile int c;
#SuppressWarnings("unchecked")
public T c(int v) {
c = v;
return (T) this;
}
public int c() {
return c;
}
}
public static class BuilderFinal extends BuilderC<BuilderFinal> {
public Foo build() {
return new Foo(
a(),
b(),
c());
}
}
public static void main(String[] args) {
Foo f1 = newBuilder().a(1).b(2).c(3).build();
Foo f2 = newBuilder().a(1).b(2).c(3).a(4).build();
}
}
To my knowledge the builder pattern should be used in case multiple parameters are used that make the invocation rather complicated as parameters might swap positions or not make it obviously clear what which parameter is for.
A rule of thumb would be to require compulsory parameters within the constructor of the builder and optional parameters within the methods. However, often more than 4 parameters may be required which makes the invocation again rather unclear and the pattern redundant. So a split up into default constructor and parameter setting for each parameter can also be used.
The checks should happen in a own method which is invoked within the build-method so you could invoke it using super. Compile-time security is only guaranteed on the correct data types (only exception - null is possible to, this has to be fetched within the checkParameters()-method). You can however force that all required parameters are set on requiring them within the Builder constructor - but as mentioned before, this may lead to a redundant pattern.
import java.util.ArrayList;
import java.util.List;
public class C
{
public static class Builder<T extends C, B extends C.Builder<? extends C,? extends B>> extends AbstractBuilder<C>
{
protected String comp1;
protected String comp2;
protected int comp3;
protected int comp4;
protected int comp5;
protected List<Object> comp6 = new ArrayList<>();
protected String optional1;
protected List<Object> optional2 = new ArrayList<>();
public Builder()
{
}
public B withComp1(String comp1)
{
this.comp1 = comp1;
return (B)this;
}
public B withComp2(String comp2)
{
this.comp2 = comp2;
return (B)this;
}
public B withComp3(int comp3)
{
this.comp3 = comp3;
return (B)this;
}
public B withComp4(int comp4)
{
this.comp4 = comp4;
return (B)this;
}
public B withComp5(int comp5)
{
this.comp5 = comp5;
return (B)this;
}
public B withComp6(Object comp6)
{
this.comp6.add(comp6);
return (B)this;
}
public B withOptional1(String optional1)
{
this.optional1 = optional1;
return (B)this;
}
public B withOptional2(Object optional2)
{
this.optional2.add(optional2);
return (B)this;
}
#Override
protected void checkParameters() throws BuildException
{
if (this.comp1 == null)
throw new BuildException("Comp1 violates the rules");
if (this.comp2 == null)
throw new BuildException("Comp2 violates the rules");
if (this.comp3 == 0)
throw new BuildException("Comp3 violates the rules");
if (this.comp4 == 0)
throw new BuildException("Comp4 violates the rules");
if (this.comp5 == 0)
throw new BuildException("Comp5 violates the rules");
if (this.comp6 == null)
throw new BuildException("Comp6 violates the rules");
}
#Override
public T build() throws BuildException
{
this.checkParameters();
C c = new C(this.comp1, this.comp2,this.comp3, this.comp4, this.comp5, this.comp6);
c.setOptional1(this.optional1);
c.setOptional2(this.optional2);
return (T)c;
}
}
private final String comp1;
private final String comp2;
private final int comp3;
private final int comp4;
private final int comp5;
private final List<?> comp6;
private String optional1;
private List<?> optional2;
protected C(String comp1, String comp2, int comp3, int comp4, int comp5, List<?> comp6)
{
this.comp1 = comp1;
this.comp2 = comp2;
this.comp3 = comp3;
this.comp4 = comp4;
this.comp5 = comp5;
this.comp6 = comp6;
}
public void setOptional1(String optional1)
{
this.optional1 = optional1;
}
public void setOptional2(List<?> optional2)
{
this.optional2 = optional2;
}
// further methods omitted
#Override
public String toString()
{
StringBuilder sb = new StringBuilder();
sb.append(this.comp1);
sb.append(", ");
sb.append(this.comp2);
sb.append(", ");
sb.append(this.comp3);
sb.append(", ");
sb.append(this.comp4);
sb.append(", ");
sb.append(this.comp5);
sb.append(", ");
sb.append(this.comp6);
return sb.toString();
}
}
On extending D from C and also the builder, you need to override the checkParameters() and build() method. Due to the use of Generics the correct type will be return on invoking build()
import java.util.List;
public class D extends C
{
public static class Builder<T extends D, B extends D.Builder<? extends D, ? extends B>> extends C.Builder<D, Builder<D, B>>
{
protected String comp7;
public Builder()
{
}
public B withComp7(String comp7)
{
this.comp7 = comp7;
return (B)this;
}
#Override
public void checkParameters() throws BuildException
{
super.checkParameters();
if (comp7 == null)
throw new BuildException("Comp7 violates the rules");
}
#Override
public T build() throws BuildException
{
this.checkParameters();
D d = new D(this.comp1, this.comp2, this.comp3, this.comp4, this.comp5, this.comp6, this.comp7);
if (this.optional1 != null)
d.setOptional1(optional1);
if (this.optional2 != null)
d.setOptional2(optional2);
return (T)d;
}
}
protected String comp7;
protected D(String comp1, String comp2, int comp3, int comp4, int comp5, List<?> comp6, String comp7)
{
super(comp1, comp2, comp3, comp4, comp5, comp6);
this.comp7 = comp7;
}
#Override
public String toString()
{
StringBuilder sb = new StringBuilder();
sb.append(super.toString());
sb.append(", ");
sb.append(this.comp7);
return sb.toString();
}
}
The abstract builder class is quite simple:
public abstract class AbstractBuilder<T>
{
protected abstract void checkParameters() throws BuildException;
public abstract <T> T build() throws BuildException;
}
The exception is simple too:
public class BuildException extends Exception
{
public BuildException(String msg)
{
super(msg);
}
}
And last but not least the main method:
public static void main(String ... args)
{
try
{
C c = new C.Builder<>().withComp1("a1").withComp2("a2").withComp3(1)
.withComp4(4).withComp5(5).withComp6("lala").build();
System.out.println("c: " + c);
D d = new D.Builder<>().withComp1("d1").withComp2("d2").withComp3(3)
.withComp4(4).withComp5(5).withComp6("lala").withComp7("d7").build();
System.out.println("d: " + d);
C c2 = new C.Builder<>().withComp1("a1").withComp3(1)
.withComp4(4).withComp5(5).withComp6("lala").build();
System.out.println(c2);
}
catch (Exception e)
{
e.printStackTrace();
}
}
Output:
c: a1, a2, 1, 4, 5, [lala]
d: d1, d2, 3, 4, 5, [lala], d7
Builders.BuildException: Comp2 violates the rules
... // StackTrace omitted
Though, before messing to much with Generics I'd suggest to stick to the KISS policy and forget inheritance for builders and code them simple and stupid (with part of them including dumb copy&paste)
#edit: OK, after all the work done and re-reading the OP as well as the linked post I had a totally wrong assumption of the requirements - like a German wording says: "Operation successful, patient is dead" - though I leave this post here in case someone wants a copy&paste like solution for a builder-inheritance which actually returns the correct type instead of the the base type
I had a crazy idea once, and it kind of goes against some of your requirements, but I think you can have the builder constructor take the required parameters, but in a way that makes it still clear which parameters are being set. Take a look:
package myapp;
public final class Foo {
public final int a;
public final int b;
public final int c;
private Foo(int a, int b, int c) {
this.a = a;
this.b = b;
this.c = c;
}
public static class Builder {
private int a;
private int b;
private int c;
public Builder(A a, B b, C c) {
this.a = a.v;
this.b = b.v;
this.c = c.v;
}
public Builder a(int v) { a = v; return this; }
public Builder b(int v) { b = v; return this; }
public Builder c(int v) { c = v; return this; }
public Foo build() {
return new Foo(a, b, c);
}
}
private static class V {
int v;
V(int v) { this.v = v; }
}
public static class A extends V { A(int v) { super(v); } }
public static class B extends V { B(int v) { super(v); } }
public static class C extends V { C(int v) { super(v); } }
public static A a(int v) { return new A(v); }
public static B b(int v) { return new B(v); }
public static C c(int v) { return new C(v); }
public static void main(String[] args) {
Foo f1 = new Builder(a(1), b(2), c(3)).build();
Foo f2 = new Builder(a(1), b(2), c(3)).a(4).build();
}
}
For other clients, static imports are your friends:
package myotherapp;
import myapp.Foo;
import static myapp.Foo.*;
public class Program {
public static void main(String[] args) {
Foo f1 = new Builder(a(1), b(2), c(3)).build();
Foo f2 = new Builder(a(1), b(2), c(3)).a(4).build();
}
}
Building on Jordão's idea, I came up with the following, which may arguably satisfy all requirements 1-6 even though there is some duplicate code in the type parameters. Essentially, the idea is to "pass around" the return types of each method by using type parameters to override the return value of the inherited methods. Even though the code is verbose and impractical, and actually requires Omega(n^3) characters if you extend it out to an arbitrary number of fields n, I'm posting it because I think it's an interesting use of the java type system. If anyone can find a way to reduce the number of type parameters (especially asymptotically), please post in the comments or write another answer.
public final class Foo {
public final int a;
public final int b;
public final int c;
private Foo(
int a,
int b,
int c) {
this.a = a;
this.b = b;
this.c = c;
}
public static BuilderA<? extends BuilderB<?, ?>, ? extends BuilderC<?, ?>> newBuilder() {
return new BuilderFinal();
}
public static class BuilderA<B extends BuilderB<?, ?>, C extends BuilderC<?, ?>> {
private volatile int a;
#SuppressWarnings("unchecked")
public B a(int v) {
a = v;
return (B) this;
}
public int a() {
return a;
}
}
public static class BuilderB<B extends BuilderB<?, ?>, C extends BuilderC<?, ?>> extends BuilderA<B, C> {
private volatile int b;
#SuppressWarnings("unchecked")
public C b(int v) {
b = v;
return (C) this;
}
public int b() {
return b;
}
}
public static class BuilderC<B extends BuilderC<?, ?>, C extends BuilderC<?, ?>> extends BuilderB<B, C> {
private volatile int c;
#SuppressWarnings("unchecked")
public BuilderFinal c(int v) {
c = v;
return (BuilderFinal) this;
}
public int c() {
return c;
}
}
public static class BuilderFinal extends BuilderC<BuilderFinal, BuilderFinal> {
public Foo build() {
return new Foo(
a(),
b(),
c());
}
}
public static void main(String[] args) {
Foo f1 = newBuilder().a(1).b(2).c(3).a(2).build();
Foo f2 = newBuilder().a(1).a(2).c(3).build(); // compile error
Foo f3 = newBuilder().a(1).b(2).a(3).b(4).b(5).build(); // compile error
}
}
Why don't you want to override the setters in BuilderFinal? They would just need to downcast the super method:
public static class BuilderFinal extends BuilderC {
#Override
public BuilderFinal a(int v) {
return (BuilderFinal) super.a(v);
}
#Override
public BuilderFinal b(int v) {
return (BuilderFinal) super.b(v);
}
public Foo build() {
return new Foo(
a(),
b(),
c());
}
}
class A {
static int i;
{
System.out.println("A init block"+ ++i);
}
}
class B extends A {
static int j;
{
System.out.println("B init block"+ ++j);
}
}
class C extends B {
static int k;
{
System.out.println("C init block"+ ++k);
}
public static void main(String abc[])
{
C c =new C();
}
}
In the code above, we can easily count the number of objects created for each class.
But if i want to check the number of object created explicitly , i mean if I create C's object using new C(), or B's object using new B(), then it should give the count accordingly
Take for example,
C c2=new C();
B b2=new B();
So it should give the output of B's count as 1 and not 2.
public class Foo {
private static int fooCount = 0;
public Foo() {
if (this.getClass() == Foo.class) {
fooCount++;
}
}
public static int getFooCount() {
return fooCount;
}
}
public class Test {
static int count;
Test() {
count++;
}
public static void main(String[] args) {
Test t = new Test();
Test t1 = new Test();
NewTest nt = new NewTest();
System.out.println("Test Count : " + Test.count);
System.out.println("NewTest Count : " + NewTest.count);
}
}
class NewTest extends Test
{ static int count;
NewTest()
{
Test.count--;
NewTest.count++;
}
}
OP :
Test Count : 2
NewTest Count : 1