TimeUtil package in java [duplicate]

TimeUtil package in java [duplicate] - java

I want to record the time using System.currentTimeMillis() when a user begins something in my program. When he finishes, I will subtract the current System.currentTimeMillis() from the start variable, and I want to show them the time elapsed using a human readable format such as "XX hours, XX mins, XX seconds" or even "XX mins, XX seconds" because its not likely to take someone an hour.
What's the best way to do this?

Use the java.util.concurrent.TimeUnit class:
String.format("%d min, %d sec",
TimeUnit.MILLISECONDS.toMinutes(millis),
TimeUnit.MILLISECONDS.toSeconds(millis) -
TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(millis))
);
Note: TimeUnit is part of the Java 1.5 specification, but toMinutes was added as of Java 1.6.
To add a leading zero for values 0-9, just do:
String.format("%02d min, %02d sec",
TimeUnit.MILLISECONDS.toMinutes(millis),
TimeUnit.MILLISECONDS.toSeconds(millis) -
TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(millis))
);
If TimeUnit or toMinutes are unsupported (such as on Android before API version 9), use the following equations:
int seconds = (int) (milliseconds / 1000) % 60 ;
int minutes = (int) ((milliseconds / (1000*60)) % 60);
int hours = (int) ((milliseconds / (1000*60*60)) % 24);
//etc...

Based on #siddhadev's answer, I wrote a function which converts milliseconds to a formatted string:
/**
* Convert a millisecond duration to a string format
*
* #param millis A duration to convert to a string form
* #return A string of the form "X Days Y Hours Z Minutes A Seconds".
*/
public static String getDurationBreakdown(long millis) {
if(millis < 0) {
throw new IllegalArgumentException("Duration must be greater than zero!");
}
long days = TimeUnit.MILLISECONDS.toDays(millis);
millis -= TimeUnit.DAYS.toMillis(days);
long hours = TimeUnit.MILLISECONDS.toHours(millis);
millis -= TimeUnit.HOURS.toMillis(hours);
long minutes = TimeUnit.MILLISECONDS.toMinutes(millis);
millis -= TimeUnit.MINUTES.toMillis(minutes);
long seconds = TimeUnit.MILLISECONDS.toSeconds(millis);
StringBuilder sb = new StringBuilder(64);
sb.append(days);
sb.append(" Days ");
sb.append(hours);
sb.append(" Hours ");
sb.append(minutes);
sb.append(" Minutes ");
sb.append(seconds);
sb.append(" Seconds");
return(sb.toString());
}

long time = 1536259;
return (new SimpleDateFormat("mm:ss:SSS")).format(new Date(time));
Prints:
25:36:259

Using the java.time package in Java 8:
Instant start = Instant.now();
Thread.sleep(63553);
Instant end = Instant.now();
System.out.println(Duration.between(start, end));
Output is in ISO 8601 Duration format: PT1M3.553S (1 minute and 3.553 seconds).

Uhm... how many milliseconds are in a second? And in a minute? Division is not that hard.
int seconds = (int) ((milliseconds / 1000) % 60);
int minutes = (int) ((milliseconds / 1000) / 60);
Continue like that for hours, days, weeks, months, year, decades, whatever.

I would not pull in the extra dependency just for that (division is not that hard, after all), but if you are using Commons Lang anyway, there are the DurationFormatUtils.
Example Usage (adapted from here):
import org.apache.commons.lang3.time.DurationFormatUtils
public String getAge(long value) {
long currentTime = System.currentTimeMillis();
long age = currentTime - value;
String ageString = DurationFormatUtils.formatDuration(age, "d") + "d";
if ("0d".equals(ageString)) {
ageString = DurationFormatUtils.formatDuration(age, "H") + "h";
if ("0h".equals(ageString)) {
ageString = DurationFormatUtils.formatDuration(age, "m") + "m";
if ("0m".equals(ageString)) {
ageString = DurationFormatUtils.formatDuration(age, "s") + "s";
if ("0s".equals(ageString)) {
ageString = age + "ms";
}
}
}
}
return ageString;
}
Example:
long lastTime = System.currentTimeMillis() - 2000;
System.out.println("Elapsed time: " + getAge(lastTime));
//Output: 2s
Note: To get millis from two LocalDateTime objects you can use:
long age = ChronoUnit.MILLIS.between(initTime, LocalDateTime.now())

Either hand divisions, or use the SimpleDateFormat API.
long start = System.currentTimeMillis();
// do your work...
long elapsed = System.currentTimeMillis() - start;
DateFormat df = new SimpleDateFormat("HH 'hours', mm 'mins,' ss 'seconds'");
df.setTimeZone(TimeZone.getTimeZone("GMT+0"));
System.out.println(df.format(new Date(elapsed)));
Edit by Bombe: It has been shown in the comments that this approach only works for smaller durations (i.e. less than a day).

Just to add more info
if you want to format like: HH:mm:ss
0 <= HH <= infinite
0 <= mm < 60
0 <= ss < 60
use this:
int h = (int) ((startTimeInMillis / 1000) / 3600);
int m = (int) (((startTimeInMillis / 1000) / 60) % 60);
int s = (int) ((startTimeInMillis / 1000) % 60);
I just had this issue now and figured this out

Shortest solution:
Here's probably the shortest which also deals with time zones.
System.out.printf("%tT", millis-TimeZone.getDefault().getRawOffset());
Which outputs for example:
00:18:32
Explanation:
%tT is the time formatted for the 24-hour clock as %tH:%tM:%tS.
%tT also accepts longs as input, so no need to create a Date. printf() will simply print the time specified in milliseconds, but in the current time zone therefore we have to subtract the raw offset of the current time zone so that 0 milliseconds will be 0 hours and not the time offset value of the current time zone.
Note #1: If you need the result as a String, you can get it like this:
String t = String.format("%tT", millis-TimeZone.getDefault().getRawOffset());
Note #2: This only gives correct result if millis is less than a day because the day part is not included in the output.

I think the best way is:
String.format("%d min, %d sec",
TimeUnit.MILLISECONDS.toSeconds(length)/60,
TimeUnit.MILLISECONDS.toSeconds(length) % 60 );

Revisiting #brent-nash contribution, we could use modulus function instead of subtractions and use String.format method for the result string:
/**
* Convert a millisecond duration to a string format
*
* #param millis A duration to convert to a string form
* #return A string of the form "X Days Y Hours Z Minutes A Seconds B Milliseconds".
*/
public static String getDurationBreakdown(long millis) {
if (millis < 0) {
throw new IllegalArgumentException("Duration must be greater than zero!");
}
long days = TimeUnit.MILLISECONDS.toDays(millis);
long hours = TimeUnit.MILLISECONDS.toHours(millis) % 24;
long minutes = TimeUnit.MILLISECONDS.toMinutes(millis) % 60;
long seconds = TimeUnit.MILLISECONDS.toSeconds(millis) % 60;
long milliseconds = millis % 1000;
return String.format("%d Days %d Hours %d Minutes %d Seconds %d Milliseconds",
days, hours, minutes, seconds, milliseconds);
}

Joda-Time
Using Joda-Time:
DateTime startTime = new DateTime();
// do something
DateTime endTime = new DateTime();
Duration duration = new Duration(startTime, endTime);
Period period = duration.toPeriod().normalizedStandard(PeriodType.time());
System.out.println(PeriodFormat.getDefault().print(period));

For those who looking for Kotlin code:
fun converter(millis: Long): String =
String.format(
"%02d : %02d : %02d",
TimeUnit.MILLISECONDS.toHours(millis),
TimeUnit.MILLISECONDS.toMinutes(millis) - TimeUnit.HOURS.toMinutes(
TimeUnit.MILLISECONDS.toHours(millis)
),
TimeUnit.MILLISECONDS.toSeconds(millis) - TimeUnit.MINUTES.toSeconds(
TimeUnit.MILLISECONDS.toMinutes(millis)
)
)
Sample output: 09 : 10 : 26

My simple calculation:
String millisecToTime(int millisec) {
int sec = millisec/1000;
int second = sec % 60;
int minute = sec / 60;
if (minute >= 60) {
int hour = minute / 60;
minute %= 60;
return hour + ":" + (minute < 10 ? "0" + minute : minute) + ":" + (second < 10 ? "0" + second : second);
}
return minute + ":" + (second < 10 ? "0" + second : second);
}
Happy coding :)

Firstly, System.currentTimeMillis() and Instant.now() are not ideal for timing. They both report the wall-clock time, which the computer doesn't know precisely, and which can move erratically, including going backwards if for example the NTP daemon corrects the system time. If your timing happens on a single machine then you should instead use System.nanoTime().
Secondly, from Java 8 onwards java.time.Duration is the best way to represent a duration:
long start = System.nanoTime();
// do things...
long end = System.nanoTime();
Duration duration = Duration.ofNanos(end - start);
System.out.println(duration); // Prints "PT18M19.511627776S"
System.out.printf("%d Hours %d Minutes %d Seconds%n",
duration.toHours(), duration.toMinutes() % 60, duration.getSeconds() % 60);
// prints "0 Hours 18 Minutes 19 Seconds"

for Android below API 9
(String.format("%d hr %d min, %d sec", millis/(1000*60*60), (millis%(1000*60*60))/(1000*60), ((millis%(1000*60*60))%(1000*60))/1000))

For small times, less than an hour, I prefer:
long millis = ...
System.out.printf("%1$TM:%1$TS", millis);
// or
String str = String.format("%1$TM:%1$TS", millis);
for longer intervalls:
private static final long HOUR = TimeUnit.HOURS.toMillis(1);
...
if (millis < HOUR) {
System.out.printf("%1$TM:%1$TS%n", millis);
} else {
System.out.printf("%d:%2$TM:%2$TS%n", millis / HOUR, millis % HOUR);
}

Here is an answer based on Brent Nash answer, Hope that helps !
public static String getDurationBreakdown(long millis)
{
String[] units = {" Days ", " Hours ", " Minutes ", " Seconds "};
Long[] values = new Long[units.length];
if(millis < 0)
{
throw new IllegalArgumentException("Duration must be greater than zero!");
}
values[0] = TimeUnit.MILLISECONDS.toDays(millis);
millis -= TimeUnit.DAYS.toMillis(values[0]);
values[1] = TimeUnit.MILLISECONDS.toHours(millis);
millis -= TimeUnit.HOURS.toMillis(values[1]);
values[2] = TimeUnit.MILLISECONDS.toMinutes(millis);
millis -= TimeUnit.MINUTES.toMillis(values[2]);
values[3] = TimeUnit.MILLISECONDS.toSeconds(millis);
StringBuilder sb = new StringBuilder(64);
boolean startPrinting = false;
for(int i = 0; i < units.length; i++){
if( !startPrinting && values[i] != 0)
startPrinting = true;
if(startPrinting){
sb.append(values[i]);
sb.append(units[i]);
}
}
return(sb.toString());
}

long startTime = System.currentTimeMillis();
// do your work...
long endTime=System.currentTimeMillis();
long diff=endTime-startTime;
long hours=TimeUnit.MILLISECONDS.toHours(diff);
diff=diff-(hours*60*60*1000);
long min=TimeUnit.MILLISECONDS.toMinutes(diff);
diff=diff-(min*60*1000);
long seconds=TimeUnit.MILLISECONDS.toSeconds(diff);
//hour, min and seconds variables contains the time elapsed on your work

This is easier in Java 9:
Duration elapsedTime = Duration.ofMillis(millisDiff );
String humanReadableElapsedTime = String.format(
"%d hours, %d mins, %d seconds",
elapsedTime.toHours(),
elapsedTime.toMinutesPart(),
elapsedTime.toSecondsPart());
This produces a string like 0 hours, 39 mins, 9 seconds.
If you want to round to whole seconds before formatting:
elapsedTime = elapsedTime.plusMillis(500).truncatedTo(ChronoUnit.SECONDS);
To leave out the hours if they are 0:
long hours = elapsedTime.toHours();
String humanReadableElapsedTime;
if (hours == 0) {
humanReadableElapsedTime = String.format(
"%d mins, %d seconds",
elapsedTime.toMinutesPart(),
elapsedTime.toSecondsPart());
} else {
humanReadableElapsedTime = String.format(
"%d hours, %d mins, %d seconds",
hours,
elapsedTime.toMinutesPart(),
elapsedTime.toSecondsPart());
}
Now we can have for example 39 mins, 9 seconds.
To print minutes and seconds with leading zero to make them always two digits, just insert 02 into the relevant format specifiers, thus:
String humanReadableElapsedTime = String.format(
"%d hours, %02d mins, %02d seconds",
elapsedTime.toHours(),
elapsedTime.toMinutesPart(),
elapsedTime.toSecondsPart());
Now we can have for example 0 hours, 39 mins, 09 seconds.

for correct strings ("1hour, 3sec", "3 min" but not "0 hour, 0 min, 3 sec") i write this code:
int seconds = (int)(millis / 1000) % 60 ;
int minutes = (int)((millis / (1000*60)) % 60);
int hours = (int)((millis / (1000*60*60)) % 24);
int days = (int)((millis / (1000*60*60*24)) % 365);
int years = (int)(millis / 1000*60*60*24*365);
ArrayList<String> timeArray = new ArrayList<String>();
if(years > 0)
timeArray.add(String.valueOf(years) + "y");
if(days > 0)
timeArray.add(String.valueOf(days) + "d");
if(hours>0)
timeArray.add(String.valueOf(hours) + "h");
if(minutes>0)
timeArray.add(String.valueOf(minutes) + "min");
if(seconds>0)
timeArray.add(String.valueOf(seconds) + "sec");
String time = "";
for (int i = 0; i < timeArray.size(); i++)
{
time = time + timeArray.get(i);
if (i != timeArray.size() - 1)
time = time + ", ";
}
if (time == "")
time = "0 sec";

If you know the time difference would be less than an hour, then you can use following code:
Calendar c1 = Calendar.getInstance();
Calendar c2 = Calendar.getInstance();
c2.add(Calendar.MINUTE, 51);
long diff = c2.getTimeInMillis() - c1.getTimeInMillis();
c2.set(Calendar.MINUTE, 0);
c2.set(Calendar.HOUR, 0);
c2.set(Calendar.SECOND, 0);
DateFormat df = new SimpleDateFormat("mm:ss");
long diff1 = c2.getTimeInMillis() + diff;
System.out.println(df.format(new Date(diff1)));
It will result to: 51:00

This answer is similar to some answers above. However, I feel that it would be beneficial because, unlike other answers, this will remove any extra commas or whitespace and handles abbreviation.
/**
* Converts milliseconds to "x days, x hours, x mins, x secs"
*
* #param millis
* The milliseconds
* #param longFormat
* {#code true} to use "seconds" and "minutes" instead of "secs" and "mins"
* #return A string representing how long in days/hours/minutes/seconds millis is.
*/
public static String millisToString(long millis, boolean longFormat) {
if (millis < 1000) {
return String.format("0 %s", longFormat ? "seconds" : "secs");
}
String[] units = {
"day", "hour", longFormat ? "minute" : "min", longFormat ? "second" : "sec"
};
long[] times = new long[4];
times[0] = TimeUnit.DAYS.convert(millis, TimeUnit.MILLISECONDS);
millis -= TimeUnit.MILLISECONDS.convert(times[0], TimeUnit.DAYS);
times[1] = TimeUnit.HOURS.convert(millis, TimeUnit.MILLISECONDS);
millis -= TimeUnit.MILLISECONDS.convert(times[1], TimeUnit.HOURS);
times[2] = TimeUnit.MINUTES.convert(millis, TimeUnit.MILLISECONDS);
millis -= TimeUnit.MILLISECONDS.convert(times[2], TimeUnit.MINUTES);
times[3] = TimeUnit.SECONDS.convert(millis, TimeUnit.MILLISECONDS);
StringBuilder s = new StringBuilder();
for (int i = 0; i < 4; i++) {
if (times[i] > 0) {
s.append(String.format("%d %s%s, ", times[i], units[i], times[i] == 1 ? "" : "s"));
}
}
return s.toString().substring(0, s.length() - 2);
}
/**
* Converts milliseconds to "x days, x hours, x mins, x secs"
*
* #param millis
* The milliseconds
* #return A string representing how long in days/hours/mins/secs millis is.
*/
public static String millisToString(long millis) {
return millisToString(millis, false);
}

There is a problem. When milliseconds is 59999, actually it is 1 minute but it will be computed as 59 seconds and 999 milliseconds is lost.
Here is a modified version based on previous answers, which can solve this loss:
public static String formatTime(long millis) {
long seconds = Math.round((double) millis / 1000);
long hours = TimeUnit.SECONDS.toHours(seconds);
if (hours > 0)
seconds -= TimeUnit.HOURS.toSeconds(hours);
long minutes = seconds > 0 ? TimeUnit.SECONDS.toMinutes(seconds) : 0;
if (minutes > 0)
seconds -= TimeUnit.MINUTES.toSeconds(minutes);
return hours > 0 ? String.format("%02d:%02d:%02d", hours, minutes, seconds) : String.format("%02d:%02d", minutes, seconds);
}

I have covered this in another answer but you can do:
public static Map<TimeUnit,Long> computeDiff(Date date1, Date date2) {
long diffInMillies = date2.getTime() - date1.getTime();
List<TimeUnit> units = new ArrayList<TimeUnit>(EnumSet.allOf(TimeUnit.class));
Collections.reverse(units);
Map<TimeUnit,Long> result = new LinkedHashMap<TimeUnit,Long>();
long milliesRest = diffInMillies;
for ( TimeUnit unit : units ) {
long diff = unit.convert(milliesRest,TimeUnit.MILLISECONDS);
long diffInMilliesForUnit = unit.toMillis(diff);
milliesRest = milliesRest - diffInMilliesForUnit;
result.put(unit,diff);
}
return result;
}
The output is something like Map:{DAYS=1, HOURS=3, MINUTES=46, SECONDS=40, MILLISECONDS=0, MICROSECONDS=0, NANOSECONDS=0}, with the units ordered.
It's up to you to figure out how to internationalize this data according to the target locale.

DurationFormatUtils.formatDurationHMS(long)

I modified #MyKuLLSKI 's answer and added plurlization support. I took out seconds because I didn't need them, though feel free to re-add it if you need it.
public static String intervalToHumanReadableTime(int intervalMins) {
if(intervalMins <= 0) {
return "0";
} else {
long intervalMs = intervalMins * 60 * 1000;
long days = TimeUnit.MILLISECONDS.toDays(intervalMs);
intervalMs -= TimeUnit.DAYS.toMillis(days);
long hours = TimeUnit.MILLISECONDS.toHours(intervalMs);
intervalMs -= TimeUnit.HOURS.toMillis(hours);
long minutes = TimeUnit.MILLISECONDS.toMinutes(intervalMs);
StringBuilder sb = new StringBuilder(12);
if (days >= 1) {
sb.append(days).append(" day").append(pluralize(days)).append(", ");
}
if (hours >= 1) {
sb.append(hours).append(" hour").append(pluralize(hours)).append(", ");
}
if (minutes >= 1) {
sb.append(minutes).append(" minute").append(pluralize(minutes));
} else {
sb.delete(sb.length()-2, sb.length()-1);
}
return(sb.toString());
}
}
public static String pluralize(long val) {
return (Math.round(val) > 1 ? "s" : "");
}

Use java.util.concurrent.TimeUnit, and use this simple method:
private static long timeDiff(Date date, Date date2, TimeUnit unit) {
long milliDiff=date2.getTime()-date.getTime();
long unitDiff = unit.convert(milliDiff, TimeUnit.MILLISECONDS);
return unitDiff;
}
For example:
SimpleDateFormat sdf = new SimpleDateFormat("yy/MM/dd HH:mm:ss");
Date firstDate = sdf.parse("06/24/2017 04:30:00");
Date secondDate = sdf.parse("07/24/2017 05:00:15");
Date thirdDate = sdf.parse("06/24/2017 06:00:15");
System.out.println("days difference: "+timeDiff(firstDate,secondDate,TimeUnit.DAYS));
System.out.println("hours difference: "+timeDiff(firstDate,thirdDate,TimeUnit.HOURS));
System.out.println("minutes difference: "+timeDiff(firstDate,thirdDate,TimeUnit.MINUTES));
System.out.println("seconds difference: "+timeDiff(firstDate,thirdDate,TimeUnit.SECONDS));

This topic has been well covered, I just wanted to share my functions perhaps you can make use of these rather than importing an entire library.
public long getSeconds(ms) {
return (ms/1000%60);
}
public long getMinutes(ms) {
return (ms/(1000*60)%60);
}
public long getHours(ms) {
return ((ms/(1000*60*60))%24);
}

Related

Calculate the difference between two dates in hours:minutes:seconds?

How can I calculate the difference between two dates and show it in the format hours:minutes:seconds?
Example:
StartTime : 2016-12-20T04:30
EndTime : 2016-12-22T05:00
The output should be "48hours 30minutes 0 seconds".
This is what I've tried:
Long diff = (endDate.get time() -startDate.gettime())/1000;
Log.d("App","difference in hour is"+diff/1000/60/60);
Mins = diff/1000/60;
Seconds = diff/1000;
Using this code I'm getting hours as a correct value. But the minute and seconds values are not getting their proper values.

Try this function:-
//1 minute = 60 seconds
//1 hour = 60 x 60 = 3600
//1 day = 3600 x 24 = 86400
public void printDifference(Date startDate, Date endDate){
//milliseconds
long different = endDate.getTime() - startDate.getTime();
System.out.println("startDate : " + startDate);
System.out.println("endDate : "+ endDate);
System.out.println("different : " + different);
long secondsInMilli = 1000;
long minutesInMilli = secondsInMilli * 60;
long hoursInMilli = minutesInMilli * 60;
long daysInMilli = hoursInMilli * 24;
//long elapsedDays = different / daysInMilli;
//different = different % daysInMilli;
long elapsedHours = different / hoursInMilli;
different = different % hoursInMilli;
long elapsedMinutes = different / minutesInMilli;
different = different % minutesInMilli;
long elapsedSeconds = different / secondsInMilli;
System.out.printf(
"%d hours, %d minutes, %d seconds%n",
elapsedHours, elapsedMinutes, elapsedSeconds);
}

Try
1. Add following methods first, then use parseDate.
Date startDate = parseDate("2016-12-20T04:30");
Date endDate = parseDate("2016-12-22T05:00");
2. Calculate difference b/w these two
long differenceInMillis = endDate.getTime() - startDate.getTime();
3. Use formatElapsedTime method to formatted difference
String formattedText = formatElapsedTime(differenceInMillis/1000); //divide by 1000 to get seconds from milliseconds
//Result will be 48hours 30minutes 0 seconds
public static Date parseDate (String strDate) {
DateFormat dateFormat = new SimpleDateFormat ("yyyy-MM-dd'T'HH:mm");
Date date1 = null;
try {
date1 = dateFormat.parse (strDate);
}
catch (ParseException e) {
e.printStackTrace ();
}
return date1;
}
public static String formatElapsedTime (long seconds) {
long hours = TimeUnit.SECONDS.toHours(seconds);
seconds -= TimeUnit.HOURS.toSeconds (hours);
long minutes = TimeUnit.SECONDS.toMinutes (seconds);
seconds -= TimeUnit.MINUTES.toSeconds (minutes);
return String.format ("%dhr:%dmin:%dsec", hours, minutes, seconds);
}

import java.util.Calendar;
public class DateDifferenceExample {
public static void main(String[] args) {
// Creates two calendars instances
Calendar cal1 = Calendar.getInstance();
Calendar cal2 = Calendar.getInstance();
// Set the date for both of the calendar instance
cal1.set(2006, Calendar.DECEMBER, 30);
cal2.set(2007, Calendar.MAY, 3);
// Get the represented date in milliseconds
long millis1 = cal1.getTimeInMillis();
long millis2 = cal2.getTimeInMillis();
// Calculate difference in milliseconds
long diff = millis2 - millis1;
// Calculate difference in seconds
long diffSeconds = diff / 1000;
// Calculate difference in minutes
long diffMinutes = diff / (60 * 1000);
// Calculate difference in hours
long diffHours = diff / (60 * 60 * 1000);
// Calculate difference in days
long diffDays = diff / (24 * 60 * 60 * 1000);
System.out.println("In milliseconds: " + diff + " milliseconds.");
System.out.println("In seconds: " + diffSeconds + " seconds.");
System.out.println("In minutes: " + diffMinutes + " minutes.");
System.out.println("In hours: " + diffHours + " hours.");
System.out.println("In days: " + diffDays + " days.");
}
}

New answer to an old question using a newer API: java.time
You can write a method that actually accepts the datetimes as Strings along with a time zone and then calculates the difference by means of a class designed for such purpose: java.time.Duration
Here's a code example:
public static String getDifference(String firstDt, String secondDt, String zone) {
// create the zone for the calculation just to respect daylight saving time
ZoneId zoneId = ZoneId.of(zone);
// then parse the datetimes passed and add the time zone
ZonedDateTime firstZdt = ZonedDateTime.of(
LocalDateTime.parse(firstDt), zoneId
);
ZonedDateTime secondZdt = ZonedDateTime.of(
LocalDateTime.parse(secondDt), zoneId
);
// calculate the duration between the two datetimes
Duration duration;
/*
* the JavaDocs of Duration tell us the following:
*
* "The result of this method can be a negative period
* if the end is before the start.".
*
* So we need to make sure the older datetime will be
* the "start" in the method "between(start, end)"
*/
if (firstZdt.isAfter(secondZdt)) {
duration = Duration.between(secondZdt, firstZdt);
} else {
duration = Duration.between(firstZdt, secondZdt);
}
// store the amount of full hours the duration has
long hoursBetween;
hoursBetween = duration.toHours();
// calculate the minutes left from the full duration in minutes
long minutesBetween;
minutesBetween = duration.toMinutes() - (hoursBetween * 60);
// calculate the seconds left from the full duration in seconds
long secondsBetween;
secondsBetween = duration.getSeconds() - (duration.toMinutes() * 60);
// build the result String, take care of possibly missing leading zeros
StringBuilder resultBuilder = new StringBuilder();
resultBuilder.append(hoursBetween).append(" hours ");
if (minutesBetween < 10 && minutesBetween > 0)
resultBuilder.append("0");
resultBuilder.append(minutesBetween).append(" minutes ");
if (secondsBetween < 10 && secondsBetween > 0)
resultBuilder.append("0");
resultBuilder.append(secondsBetween).append(" seconds");
return resultBuilder.toString();
}
If you use it in a main...
public static void main(String[] args) {
String timeDiff = getDifference("2016-12-20T04:30", "2016-12-22T05:00", "UTC");
System.out.println(timeDiff);
}
... you will get the following output:
48 hours 30 minutes 0 seconds
The code above is the one to be used in Java 8, later on, Duration got the methods toHoursPart(), toMinutesPart() and toSecondsPart() which actually do the necessary calculation internally.
The code that would change (tried with Java 11):
// store the amount of full hours the duration has
long hoursBetween;
hoursBetween = duration.toHoursPart();
// calculate the minutes left from the full duration in minutes
long minutesBetween;
minutesBetween = duration.toMinutesPart();
// calculate the seconds left from the full duration in seconds
long secondsBetween;
secondsBetween = duration.toSecondsPart();

Java String Time Formatting

Is there a way to do this without the if ( hours > 0 ) ? I feel like there must be a way to indicate a conditional display for the digit, but I couldn't find it in the javadocs or with google.
public String getLengthDisplay () {
int hours = getLength() / 3600;
int minutes = ( getLength() % 3600 ) / 60;
int seconds = getLength() % 60;
if ( hours > 0 ) {
return String.format ( "%d:%02d:%02d", hours, minutes, seconds );
} else {
return String.format ( "%d:%02d", minutes, seconds );
}
}
Thanks!

I don't think the code will be flexible without the hour > 0 condition.
Trimming is also a good option.
/**
* This method is used to get the Execution Time
* by calculating the difference between StartTime and EndTime
*
* #param StartTime Execution Start Time
* #param EndTime Execution End Time
* #return Total Execution Time
*/
private static String ExecutionTime(String StartTime, String EndTime){
LocalTime fromDateTime = LocalTime.parse(StartTime);
LocalTime toDateTime = LocalTime.parse(EndTime);
LocalTime tempDateTime = LocalTime.from( fromDateTime );
long hours = tempDateTime.until( toDateTime, ChronoUnit.HOURS);
tempDateTime = tempDateTime.plusHours( hours );
long minutes = tempDateTime.until( toDateTime, ChronoUnit.MINUTES);
tempDateTime = tempDateTime.plusMinutes( minutes );
long seconds = tempDateTime.until( toDateTime, ChronoUnit.SECONDS);
if(hours > 0){
return hours + "h " +minutes + "min " + seconds + "s";
}else{
return minutes + "min " + seconds + "s";
}
}
Check the above code, which return Hour Minute Second format, you can add minute condition also if needed.

There's no way with format(), but just trim leading zeros:
return String.format("%d:%02d:%02d", hours, minutes, seconds)
.replaceAll("^0:(00:)?", "");
This code also trims the minutes if both hour and minute are zero. If you always want the minutes, delete (00:)? from this code.

Convert long to remaining time

I'm currently trying to convert a long to a remaining time. I have got a
long remaining = XXXX
The long are the milliseconds to a certain date. For example: 3,600,000 should result in int weeks = 0, days = 0, hours = 1, minutes = 0, seconds = 0
how can I convert this long so that I end up with 5 ints:
int weeks;
int days;
int hours;
int minutes;
int seconds;
Thank you in advance!
DirtyDev

First, I suggest defining the number of ms in a second, minute, hour, etc as constants
static final int SECOND = 1000; // no. of ms in a second
static final int MINUTE = SECOND * 60; // no. of ms in a minute
static final int HOUR = MINUTE * 60; // no. of ms in an hour
static final int DAY = HOUR * 24; // no. of ms in a day
static final int WEEK = DAY * 7; // no. of ms in a week
Then, you can use basic division (/) and modulus (%) operations to find what you need.
long remaining = XXXX;
int weeks = (int)( remaining / WEEK);
int days = (int)((remaining % WEEK) / DAY);
int hours = (int)((remaining % DAY) / HOUR);
int minutes = (int)((remaining % HOUR) / MINUTE);
int seconds = (int)((remaining % MINUTE) / SECOND);

Excuse me, I don’t want to criticize too much, still I gather from the other answers that it’s easy to either write code that is hard to read or code with typos that gives an incorrect result. DirtyDev, I am aware that you may not be allowed to use Duration, but for anyone else:
long remaining = 3_600_000;
Duration remainingTime = Duration.ofMillis(remaining);
long days = remainingTime.toDays();
remainingTime = remainingTime.minusDays(days);
long weeks = days / 7;
days %= 7; // or if you prefer, days = days % 7;
long hours = remainingTime.toHours();
remainingTime = remainingTime.minusHours(hours);
long minutes = remainingTime.toMinutes();
remainingTime = remainingTime.minusMinutes(minutes);
long seconds = remainingTime.getSeconds();
System.out.println("" + weeks + " weeks " + days + " days "
+ hours + " hours " + minutes + " minutes " + seconds + " seconds");
This prints:
0 weeks 0 days 1 hours 0 minutes 0 seconds
It’s not perfect, but I believe it’s both readable, correct and robust. Duration was meant for times from hours down to nanoseconds, so we still have to do the weeks “by hand”.
Happy New Year.

This should do what you want.
long inputTimeInMilliseconds = 93800000;
long milliseconds = inputTimeInMilliseconds % 1000;
long seconds = (inputTimeInMilliseconds / 1000) % 60 ;
long minutes = ((inputTimeInMilliseconds / (1000*60)) % 60);
long hours = ((inputTimeInMilliseconds / (1000*60*60)) % 24);
long days = ((inputTimeInMilliseconds / (1000*60*60*24)) % 7);
long weeks = (inputTimeInMilliseconds / (1000*60*60*24*7));
String remainingTime = "time:"+weeks+":"+days+":"+ hours+":"+minutes+":"+seconds+":"+milliseconds;
System.out.println(remainingTime);

JAVA convert minutes into default time [hh:mm:ss]

what is the easiest and fastest way to convert minutes (double) to default time hh:mm:ss
for example I used this code in python and it's working
time = timedelta(minutes=250.0)
print time
result:
4:10:00
is there a java library or a simple code can do it?

EDIT: To show the seconds as SS you can make an easy custom formatter variable to pass to the String.format() method
EDIT: Added logic to add one minute and recalculate seconds if the initial double value has the number value after the decimal separator greater than 59.
EDIT: Noticed loss of precision when doing math on the double (joy of working with doubles!) seconds, so every now and again it would not be the correct value. Changed code to properly calculate and round it. Also added logic to treat cases when minutes and hour overflow because of cascading from seconds.
Try this (no external libraries needed)
public static void main(String[] args) {
final double t = 1304.00d;
if (t > 1440.00d) //possible loss of precision again
return;
int hours = (int)t / 60;
int minutes = (int)t % 60;
BigDecimal secondsPrecision = new BigDecimal((t - Math.floor(t)) * 100).setScale(2, RoundingMode.HALF_UP);
int seconds = secondsPrecision.intValue();
boolean nextDay = false;
if (seconds > 59) {
minutes++; //increment minutes by one
seconds = seconds - 60; //recalculate seconds
}
if (minutes > 59) {
hours++;
minutes = minutes - 60;
}
//next day
if (hours > 23) {
hours = hours - 24;
nextDay = true;
}
//if seconds >=10 use the same format as before else pad one zero before the seconds
final String myFormat = seconds >= 10 ? "%d:%02d:%d" : "%d:%02d:0%d";
final String time = String.format(myFormat, hours, minutes, seconds);
System.out.print(time);
System.out.println(" " + (nextDay ? "The next day" : "Current day"));
}
Of course this can go on and on, expanding on this algorithm to generalize it. So far it will work until the next day but no further, so we could limit the initial double to that value.
if (t > 1440.00d)
return;

Using Joda you can do something like:
import org.joda.time.Period;
import org.joda.time.format.PeriodFormatter;
import org.joda.time.format.PeriodFormatterBuilder;
final Period a = Period.seconds(25635);
final PeriodFormatter hoursMinutes = new PeriodFormatterBuilder().appendHours().appendSuffix(" hour", " hours")
.appendSeparator(" and ").appendMinutes().appendSuffix(" minute", " minutes").appendSeparator(" and ")
.appendSeconds().appendSuffix(" second", " seconds").toFormatter();
System.out.println(hoursMinutes.print(a.normalizedStandard()));

//Accept minutes from user and return time in HH:MM:SS format
private String convertTime(long time)
{
String finalTime = "";
long hour = (time%(24*60)) / 60;
long minutes = (time%(24*60)) % 60;
long seconds = time / (24*3600);
finalTime = String.format("%02d:%02d:%02d",
TimeUnit.HOURS.toHours(hour) ,
TimeUnit.MINUTES.toMinutes(minutes),
TimeUnit.SECONDS.toSeconds(seconds));
return finalTime;
}

How to convert milliseconds to "hh:mm:ss" format?

I'm confused. After stumbling upon this thread, I tried to figure out how to format a countdown timer that had the format hh:mm:ss.
Here's my attempt -
//hh:mm:ss
String.format("%02d:%02d:%02d",
TimeUnit.MILLISECONDS.toHours(millis),
TimeUnit.MILLISECONDS.toMinutes(millis) -
TimeUnit.MINUTES.toMinutes(TimeUnit.MILLISECONDS.toHours(millis)),
TimeUnit.MILLISECONDS.toSeconds(millis) -
TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(millis)));
So, when I try a value like 3600000ms, I get 01:59:00, which is wrong since it should be 01:00:00. Obviously there's something wrong with my logic, but at the moment, I cannot see what it is!
Can anyone help?
Edit -
Fixed it. Here's the right way to format milliseconds to hh:mm:ss format -
//hh:mm:ss
String.format("%02d:%02d:%02d",
TimeUnit.MILLISECONDS.toHours(millis),
TimeUnit.MILLISECONDS.toMinutes(millis) -
TimeUnit.HOURS.toMinutes(TimeUnit.MILLISECONDS.toHours(millis)),
TimeUnit.MILLISECONDS.toSeconds(millis) -
TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(millis))));
The problem was this TimeUnit.MINUTES.toMinutes(TimeUnit.MILLISECONDS.toHours(millis)). It should have been this TimeUnit.HOURS.toMinutes(TimeUnit.MILLISECONDS.toHours(millis)) instead.

You were really close:
String.format("%02d:%02d:%02d",
TimeUnit.MILLISECONDS.toHours(millis),
TimeUnit.MILLISECONDS.toMinutes(millis) -
TimeUnit.HOURS.toMinutes(TimeUnit.MILLISECONDS.toHours(millis)), // The change is in this line
TimeUnit.MILLISECONDS.toSeconds(millis) -
TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(millis)));
You were converting hours to millisseconds using minutes instead of hours.
BTW, I like your use of the TimeUnit API :)
Here's some test code:
public static void main(String[] args) throws ParseException {
long millis = 3600000;
String hms = String.format("%02d:%02d:%02d", TimeUnit.MILLISECONDS.toHours(millis),
TimeUnit.MILLISECONDS.toMinutes(millis) - TimeUnit.HOURS.toMinutes(TimeUnit.MILLISECONDS.toHours(millis)),
TimeUnit.MILLISECONDS.toSeconds(millis) - TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(millis)));
System.out.println(hms);
}
Output:
01:00:00
I realised that my code above can be greatly simplified by using a modulus division instead of subtraction:
String hms = String.format("%02d:%02d:%02d", TimeUnit.MILLISECONDS.toHours(millis),
TimeUnit.MILLISECONDS.toMinutes(millis) % TimeUnit.HOURS.toMinutes(1),
TimeUnit.MILLISECONDS.toSeconds(millis) % TimeUnit.MINUTES.toSeconds(1));
Still using the TimeUnit API for all magic values, and gives exactly the same output.

The generic method for this is fairly simple:
public static String convertSecondsToHMmSs(long seconds) {
long s = seconds % 60;
long m = (seconds / 60) % 60;
long h = (seconds / (60 * 60)) % 24;
return String.format("%d:%02d:%02d", h,m,s);
}

If you are using apache commons:
DurationFormatUtils.formatDuration(timeInMS, "HH:mm:ss,SSS");

I used this:
String.format("%1$tH:%1$tM:%1$tS.%1$tL", millis);
See description of class Formatter.
See runnable example using input of 2400 ms.

// New date object from millis
Date date = new Date(millis);
// formattter
SimpleDateFormat formatter= new SimpleDateFormat("HH:mm:ss.SSS");
formatter.setTimeZone(TimeZone.getTimeZone("UTC"));
// Pass date object
String formatted = formatter.format(date );
You can also use new DateTime API
var formatted = DateTimeFormatter.ofPattern("HH:mm:ss.SSS")
.withZone(ZoneId.of("UTC"))
.format(Instant.ofEpochMilli(millis));

DateFormat df = new SimpleDateFormat("HH:mm:ss");
String formatted = df.format(aDateObject);

this worked for me, with kotlin
fun formatToDigitalClock(miliSeconds: Long): String {
val hours = TimeUnit.MILLISECONDS.toHours(miliSeconds).toInt() % 24
val minutes = TimeUnit.MILLISECONDS.toMinutes(miliSeconds).toInt() % 60
val seconds = TimeUnit.MILLISECONDS.toSeconds(miliSeconds).toInt() % 60
return when {
hours > 0 -> String.format("%d:%02d:%02d", hours, minutes, seconds)
minutes > 0 -> String.format("%02d:%02d", minutes, seconds)
seconds > 0 -> String.format("00:%02d", seconds)
else -> {
"00:00"
}
}
}

Test results for the 4 implementations
Having to do a lot of formatting for huge data, needed the best performance, so here are the (surprising) results:
for (int i = 0; i < 1000000; i++) {
FUNCTION_CALL
}
Durations:
combinationFormatter: 196 millis
formatDuration: 272 millis
apacheFormat: 754 millis
formatTimeUnit: 2216 millis
public static String apacheFormat(long millis) throws ParseException {
return DurationFormatUtils.formatDuration(millis, "HH:mm:ss");
}
public static String formatTimeUnit(long millis) throws ParseException {
String formatted = String.format(
"%02d:%02d:%02d",
TimeUnit.MILLISECONDS.toHours(millis),
TimeUnit.MILLISECONDS.toMinutes(millis)
- TimeUnit.HOURS.toMinutes(TimeUnit.MILLISECONDS.toHours(millis)),
TimeUnit.MILLISECONDS.toSeconds(millis)
- TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(millis)));
return formatted;
}
public static String formatDuration(final long millis) {
long seconds = (millis / 1000) % 60;
long minutes = (millis / (1000 * 60)) % 60;
long hours = millis / (1000 * 60 * 60);
StringBuilder b = new StringBuilder();
b.append(hours == 0 ? "00" : hours < 10 ? String.valueOf("0" + hours) :
String.valueOf(hours));
b.append(":");
b.append(minutes == 0 ? "00" : minutes < 10 ? String.valueOf("0" + minutes) :
String.valueOf(minutes));
b.append(":");
b.append(seconds == 0 ? "00" : seconds < 10 ? String.valueOf("0" + seconds) :
String.valueOf(seconds));
return b.toString();
}
public static String combinationFormatter(final long millis) {
long seconds = TimeUnit.MILLISECONDS.toSeconds(millis)
- TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(millis));
long minutes = TimeUnit.MILLISECONDS.toMinutes(millis)
- TimeUnit.HOURS.toMinutes(TimeUnit.MILLISECONDS.toHours(millis));
long hours = TimeUnit.MILLISECONDS.toHours(millis);
StringBuilder b = new StringBuilder();
b.append(hours == 0 ? "00" : hours < 10 ? String.valueOf("0" + hours) :
String.valueOf(hours));
b.append(":");
b.append(minutes == 0 ? "00" : minutes < 10 ? String.valueOf("0" + minutes) :
String.valueOf(minutes));
b.append(":");
b.append(seconds == 0 ? "00" : seconds < 10 ? String.valueOf("0" + seconds) :
String.valueOf(seconds));
return b.toString();
}

Java 9
Duration timeLeft = Duration.ofMillis(3600000);
String hhmmss = String.format("%02d:%02d:%02d",
timeLeft.toHours(), timeLeft.toMinutesPart(), timeLeft.toSecondsPart());
System.out.println(hhmmss);
This prints:
01:00:00
You are doing right in letting library methods do the conversions involved for you. java.time, the modern Java date and time API, or more precisely, its Duration class does it more elegantly and in a less error-prone way than TimeUnit.
The toMinutesPart and toSecondsPart methods I used were introduced in Java 9.
Java 6, 7 and 8
long hours = timeLeft.toHours();
timeLeft = timeLeft.minusHours(hours);
long minutes = timeLeft.toMinutes();
timeLeft = timeLeft.minusMinutes(minutes);
long seconds = timeLeft.toSeconds();
String hhmmss = String.format("%02d:%02d:%02d", hours, minutes, seconds);
System.out.println(hhmmss);
The output is the same as above.
Question: How can that work in Java 6 and 7?
In Java 8 and later and on newer Android devices (from API level 26, I’m told) java.time comes built-in.
In Java 6 and 7 get the ThreeTen Backport, the backport of the modern classes (ThreeTen for JSR 310; see the links at the bottom).
On (older) Android use the Android edition of ThreeTen Backport. It’s called ThreeTenABP. And make sure you import the date and time classes from org.threeten.bp with subpackages.
Links
Oracle tutorial: Date Time explaining how to use java.time.
Java Specification Request (JSR) 310, where java.time was first described.
ThreeTen Backport project, the backport of java.timeto Java 6 and 7 (ThreeTen for JSR-310).
ThreeTenABP, Android edition of ThreeTen Backport
Question: How to use ThreeTenABP in Android Project, with a very thorough explanation.

The answer marked as correct has a little mistake,
String myTime = String.format("%02d:%02d:%02d",
TimeUnit.MILLISECONDS.toHours(millis),
TimeUnit.MILLISECONDS.toMinutes(millis) -
TimeUnit.HOURS.toMinutes(TimeUnit.MILLISECONDS.toHours(millis)), // The change is in this line
TimeUnit.MILLISECONDS.toSeconds(millis) -
TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(millis)));
for example this is an example of the value that i get:
417474:44:19
This is the solution to get the right format is:
String myTime = String.format("%02d:%02d:%02d",
//Hours
TimeUnit.MILLISECONDS.toHours(millis) -
TimeUnit.DAYS.toHours(TimeUnit.MILLISECONDS.toDays(millis)),
//Minutes
TimeUnit.MILLISECONDS.toMinutes(millis) -
TimeUnit.HOURS.toMinutes(TimeUnit.MILLISECONDS.toHours(millis)),
//Seconds
TimeUnit.MILLISECONDS.toSeconds(millis) -
TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(millis)));
getting as a result a correct format:
18:44:19
other option to get the format hh:mm:ss is just :
Date myDate = new Date(timeinMillis);
SimpleDateFormat formatter = new SimpleDateFormat("HH:mm:ss");
String myTime = formatter.format(myDate);

public String millsToDateFormat(long mills) {
Date date = new Date(mills);
DateFormat formatter = new SimpleDateFormat("HH:mm:ss");
String dateFormatted = formatter.format(date);
return dateFormatted; //note that it will give you the time in GMT+0
}

Going by Bohemian's answer we need need not use TimeUnit to find a known value.
Much more optimal code would be
String hms = String.format("%02d:%02d:%02d", millisLeft/(3600*1000),
millisLeft/(60*1000) % 60,
millisLeft/1000 % 60);
Hope it helps

String string = String.format("%02d:%02d:%02d.%03d",
TimeUnit.MILLISECONDS.toHours(millisecend), TimeUnit.MILLISECONDS.toMinutes(millisecend) - TimeUnit.HOURS.toMinutes(TimeUnit.MILLISECONDS.toHours(millisecend)),
TimeUnit.MILLISECONDS.toSeconds(millisecend) - TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(millisecend)), millisecend - TimeUnit.SECONDS.toMillis(TimeUnit.MILLISECONDS.toSeconds(millisecend)));
Format: 00:00:00.000
Example: 615605 Millisecend
00:10:15.605

The code below does the conversion in both way
23:59:58:999 to 86398999
and than
86398999 to 23:59:58:999
import java.util.concurrent.TimeUnit;
public class TimeUtility {
public static void main(String[] args) {
long currentDateTime = System.currentTimeMillis();
String strTest = "23:59:58:999";
System.out.println(strTest);
long l = strToMilli(strTest);
System.out.println(l);
l += 1;
String str = milliToString(l);
System.out.println(str);
}
/**
* convert a time string into the equivalent long milliseconds
*
* #param strTime string fomratted as HH:MM:SS:MSMS i.e. "23:59:59:999"
* #return long integer like 86399999
*/
public static long strToMilli(String strTime) {
long retVal = 0;
String hour = strTime.substring(0, 2);
String min = strTime.substring(3, 5);
String sec = strTime.substring(6, 8);
String milli = strTime.substring(9, 12);
int h = Integer.parseInt(hour);
int m = Integer.parseInt(min);
int s = Integer.parseInt(sec);
int ms = Integer.parseInt(milli);
String strDebug = String.format("%02d:%02d:%02d:%03d", h, m, s, ms);
//System.out.println(strDebug);
long lH = h * 60 * 60 * 1000;
long lM = m * 60 * 1000;
long lS = s * 1000;
retVal = lH + lM + lS + ms;
return retVal;
}
/**
* convert time in milliseconds to the corresponding string, in case of day
* rollover start from scratch 23:59:59:999 + 1 = 00:00:00:000
*
* #param millis the number of milliseconds corresponding to tim i.e.
* 34137999 that can be obtained as follows;
* <p>
* long lH = h * 60 * 60 * 1000; //hour to milli
* <p>
* long lM = m * 60 * 1000; // minute to milli
* <p>
* long lS = s * 1000; //seconds to milli
* <p>
* millis = lH + lM + lS + ms;
* #return a string formatted as HH:MM:SS:MSMS i.e. "23:59:59:999"
*/
private static String milliToString(long millis) {
long hrs = TimeUnit.MILLISECONDS.toHours(millis) % 24;
long min = TimeUnit.MILLISECONDS.toMinutes(millis) % 60;
long sec = TimeUnit.MILLISECONDS.toSeconds(millis) % 60;
//millis = millis - (hrs * 60 * 60 * 1000); //alternative way
//millis = millis - (min * 60 * 1000);
//millis = millis - (sec * 1000);
//long mls = millis ;
long mls = millis % 1000;
String toRet = String.format("%02d:%02d:%02d:%03d", hrs, min, sec, mls);
//System.out.println(toRet);
return toRet;
}
}

I tried as shown in the first answer. It works, but minus brought me into confusion. My answer by Groovy:
import static java.util.concurrent.TimeUnit.*
...
private static String formatElapsedTime(long millis) {
int hrs = MILLISECONDS.toHours(millis) % 24
int min = MILLISECONDS.toMinutes(millis) % 60
int sec = MILLISECONDS.toSeconds(millis) % 60
int mls = millis % 1000
sprintf( '%02d:%02d:%02d (%03d)', [hrs, min, sec, mls])
}

For Kotlin
val hours = String.format("%02d", TimeUnit.MILLISECONDS.toHours(milSecs))
val minutes = String.format("%02d",
TimeUnit.MILLISECONDS.toMinutes(milSecs) - TimeUnit.HOURS.toMinutes(TimeUnit.MILLISECONDS.toHours(milSecs)))
val seconds = String.format("%02d",
TimeUnit.MILLISECONDS.toSeconds(milSecs) - TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(milSecs)))
where, milSecs is milliseconds

Well, you could try something like this, :
public String getElapsedTimeHoursMinutesSecondsString() {
long elapsedTime = getElapsedTime();
String format = String.format("%%0%dd", 2);
elapsedTime = elapsedTime / 1000;
String seconds = String.format(format, elapsedTime % 60);
String minutes = String.format(format, (elapsedTime % 3600) / 60);
String hours = String.format(format, elapsedTime / 3600);
String time = hours + ":" + minutes + ":" + seconds;
return time;
}
to convert milliseconds to a time value

In kotlin
private fun stringForTime(timeMs: Int): String {
val totalSeconds = timeMs / 1000
val seconds = totalSeconds % 60
val minutes = totalSeconds / 60 % 60
val hours = totalSeconds / 3600
return if (hours > 0) {
"%d:%02d:%02d".format(hours, minutes, seconds)
} else {
"%02d:%02d".format(minutes, seconds)
}
}
In Java
private String stringForTime(int timeMs) {
int totalSeconds = timeMs / 1000;
int seconds = totalSeconds % 60;
int minutes = totalSeconds / 60 % 60;
int hours = totalSeconds / 3600;
return hours > 0 ? String.format(Locale.getDefault(),
"%d:%02d:%02d",
hours,
minutes,
seconds) :
String.format(Locale.getDefault(),
"%02d:%02d",
minutes,
seconds);
}

In Kotlin:
fun FUNCTION_NAME(milliSeconds: Long): String {
val s: Long = milliSeconds / 1000 % 60
val m: Long = milliSeconds / (1000*60) % 60
val h: Long = milliSeconds / (1000*60*60) % 24
return String.format("%02d:%02d:%02d", h, m, s)
}

We Keep Coding

Java is a programming language and computing platform first released by Sun Microsystems in 1995.

TimeUtil package in java [duplicate] - java

long time = 1536259; return (new SimpleDateFormat("mm:ss:SSS")).format(new Date(time)); Prints: 25:36:259

Using the java.time package in Java 8: Instant start = Instant.now(); Thread.sleep(63553); Instant end = Instant.now(); System.out.println(Duration.between(start, end)); Output is in ISO 8601 Duration format: PT1M3.553S (1 minute and 3.553 seconds).

Uhm... how many milliseconds are in a second? And in a minute? Division is not that hard. int seconds = (int) ((milliseconds / 1000) % 60); int minutes = (int) ((milliseconds / 1000) / 60); Continue like that for hours, days, weeks, months, year, decades, whatever.

I think the best way is: String.format("%d min, %d sec", TimeUnit.MILLISECONDS.toSeconds(length)/60, TimeUnit.MILLISECONDS.toSeconds(length) % 60 );

for Android below API 9 (String.format("%d hr %d min, %d sec", millis/(10006060), (millis%(10006060))/(100060), ((millis%(10006060))%(100060))/1000))

DurationFormatUtils.formatDurationHMS(long)

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Java is a programming language and computing platform first released by Sun Microsystems in 1995.

TimeUtil package in java [duplicate] - java

long time = 1536259; return (new SimpleDateFormat("mm:ss:SSS")).format(new Date(time)); Prints: 25:36:259

Using the java.time package in Java 8: Instant start = Instant.now(); Thread.sleep(63553); Instant end = Instant.now(); System.out.println(Duration.between(start, end)); Output is in ISO 8601 Duration format: PT1M3.553S (1 minute and 3.553 seconds).

Uhm... how many milliseconds are in a second? And in a minute? Division is not that hard. int seconds = (int) ((milliseconds / 1000) % 60); int minutes = (int) ((milliseconds / 1000) / 60); Continue like that for hours, days, weeks, months, year, decades, whatever.

I think the best way is: String.format("%d min, %d sec", TimeUnit.MILLISECONDS.toSeconds(length)/60, TimeUnit.MILLISECONDS.toSeconds(length) % 60 );

for Android below API 9 (String.format("%d hr %d min, %d sec", millis/(1000*60*60), (millis%(1000*60*60))/(1000*60), ((millis%(1000*60*60))%(1000*60))/1000))

DurationFormatUtils.formatDurationHMS(long)

Related

Calculate the difference between two dates in hours:minutes:seconds?

Java String Time Formatting

Convert long to remaining time

JAVA convert minutes into default time [hh:mm:ss]

How to convert milliseconds to "hh:mm:ss" format?

Categories

Resources

for Android below API 9 (String.format("%d hr %d min, %d sec", millis/(10006060), (millis%(10006060))/(100060), ((millis%(10006060))%(100060))/1000))