Sorry im totally New to the Http, i Hardly Could Write a Http Server With Examples i have seen, and Im Trying to Download Images from this Http Server with Picasso Lib, but it seems Doesnt Work, here is my Server :
my content is : D:\Users\Default and im trying to load Default.jpg into iv:
public class SimpleHttpServer {
public static void main(String[] args) throws Exception {
HttpServer server = HttpServer.create(new InetSocketAddress(8000), 0);
server.createContext("/info", new InfoHandler());
server.createContext("/get", new GetHandler());
server.setExecutor(null); // creates a default executor
server.start();
}
static class InfoHandler implements HttpHandler {
public void handle(HttpExchange t) throws IOException {
String response = "Use /get to download an Image";
t.sendResponseHeaders(200, response.length());
OutputStream os = t.getResponseBody();
os.write(response.getBytes());
os.close();
}
}
static class GetHandler implements HttpHandler {
public void handle(HttpExchange t) throws IOException {
// add the required response header for an Image file
Headers h = t.getResponseHeaders();
h.add("Content-Type", "image/jpg");
// a PDF (you provide your own!)
File file = new File ("D:/Users/Default/Default.jpg");
byte [] bytearray = new byte [(int)file.length()];
FileInputStream fis = new FileInputStream(file);
BufferedInputStream bis = new BufferedInputStream(fis);
bis.read(bytearray, 0, bytearray.length);
// ok, we are ready to send the response.
t.sendResponseHeaders(200, file.length());
OutputStream os = t.getResponseBody();
os.write(bytearray,0,bytearray.length);
os.close();
}
}
}
and loading it from picasso like this:
Picasso.with(getActivity()).load(Uri.parse("http://192.168.1.103:8000/D:/Users
/Default/Default.jpg")).into(iv);
Which are my Mistakes and how funny they are? :P
Well first off, you hard-coded the file that the server will return, so you don't need the file location in your Uri.... you would use /get at the end... it even says so in your code... String response = "Use /get to download an Image";. Also, you need to add:
<uses-permission android:name="android.permission.INTERNET"></uses-permission>
to your manifest file if you have not already... It would be helpful FYI to post a log, not just ask whats wrong and not give any hints.
Related
I have a setup a simple http server in java that only deals with one type of post request.
The server code:
int port = 5555;
HttpServer server = HttpServer.create(new InetSocketAddress(port), 0);
System.out.println("server started at " + port);
server.createContext("/echoPost", new echoPost());
server.setExecutor(null);
server.start();
The echoPost() class:
public class echoPost implements HttpHandler {
#Override
public void handle(HttpExchange http) throws IOException {
InputStreamReader inputStreamReader = new InputStreamReader(http.getRequestBody(), "utf-8");
BufferedReader bufferReader = new BufferedReader(inputStreamReader);
String incoming = br.readLine();
System.out.println(incoming);
String response = "response";
http.sendResponseHeaders(200, response.length());
OutputStream outputStream = http.getResponseBody();
os.write(response.toString().getBytes());
os.close();
}
}
I want the server to stop after a post request is received. Is there a way to do this so straight after one post request is handled the server stops?
What's wrong with calling server.stop(delay), where the delay is small enough (0 or 1)? You'll need to pass server as argument to the echoPost constructor.
Use
System.exit(0);
It doesn't matter where this line of code is executed, it will terminate the JVM and quit.
I am trying to download an image from the below URL but it always returns HTML.
Do you know how to download it by java? The below code can download successfully other URL like (http://example.com/img/abc.jpg)
URL
https://www.ttbonline.gov/colasonline/publicViewAttachment.do?filename=Sankaty%20Body.JPG&filetype=l
Code
private static void getImages(String src) throws IOException {
URL url = new URL(src);
InputStream in = url.openStream();
FileUtils.copyURLToFile(
url,
new File("C:\\Users\\admin\\Desktop\\output\\img.jpeg"),
10000,
10000);
in.close();
}
Thanks in advance.
I try to send a SOAP message in an XML file to a webservice and than grab the binary output and decode it. Endpoint uses HTTPS protocol, so I used TrustManager in my code to avoid PKIX problems. You can see my code here:
import javax.net.ssl.*;
import java.io.*;
import java.net.HttpURLConnection;
import java.net.URL;
import java.net.URLConnection;
import java.security.cert.X509Certificate;
public class Main{
public static void sendSoapRequest() throws Exception {
String SOAPUrl = "URL HERE";
String xmlFile2Send = ".\\src\\request.xml";
String responseFileName = ".\\src\\response.xml";
String inputLine;
TrustManager[] trustAllCerts = new TrustManager[] { new X509TrustManager() {
public java.security.cert.X509Certificate[] getAcceptedIssuers() { return null; }
public void checkClientTrusted(X509Certificate[] certs, String authType) { }
public void checkServerTrusted(X509Certificate[] certs, String authType) { }
} };
SSLContext sc = SSLContext.getInstance("SSL");
sc.init(null, trustAllCerts, new java.security.SecureRandom());
HttpsURLConnection.setDefaultSSLSocketFactory(sc.getSocketFactory());
// Create all-trusting host name verifier
HostnameVerifier allHostsValid = new HostnameVerifier() {
public boolean verify(String hostname, SSLSession session) { return true; }
};
// Install the all-trusting host verifier
HttpsURLConnection.setDefaultHostnameVerifier(allHostsValid);
// Create the connection with http
URL url = new URL(SOAPUrl);
URLConnection connection = url.openConnection();
HttpURLConnection httpConn = (HttpURLConnection) connection;
FileInputStream fin = new FileInputStream(xmlFile2Send);
ByteArrayOutputStream bout = new ByteArrayOutputStream();
copy(fin, bout);
fin.close();
byte[] b = bout.toByteArray();
StringBuffer buf=new StringBuffer();
String s=new String(b);
b=s.getBytes();
// Set the appropriate HTTP parameters.
httpConn.setRequestProperty("Content-Length", String.valueOf(b.length));
httpConn.setRequestProperty("Content-Type", "text/xml; charset=utf-8");
httpConn.setRequestProperty("SOAPAction", "");
httpConn.setRequestMethod("POST");
httpConn.setDoOutput(true);
OutputStream out = httpConn.getOutputStream();
out.write(b);
out.close();
// Read the response.
httpConn.connect();
System.out.println("http connection status :"+ httpConn.getResponseMessage());
InputStreamReader isr = new InputStreamReader(httpConn.getInputStream());
BufferedReader in = new BufferedReader(isr);
while ((inputLine = in.readLine()) != null)
System.out.println(inputLine);
FileOutputStream fos=new FileOutputStream(responseFileName);
copy(httpConn.getInputStream(),fos);
in.close();
}
public static void copy(InputStream in, OutputStream out) throws IOException {
synchronized (in) {
synchronized (out) {
byte[] buffer = new byte[256];
while (true) {
int bytesRead = in.read(buffer);
if (bytesRead == -1)
break;
out.write(buffer, 0, bytesRead);
}
}
}
}
public static void main(String args[]) throws Exception {
sendSoapRequest();
}
}
I get following error code, when I execute this.
Exception in thread "main" java.io.IOException: Server returned HTTP
response code: 403 for URL
Your implementation is alright, the problem is related to your Content-Type header, in fact.
The value text/xml; charset=utf-8 is the default Content-Type of SOAP 1.1, which is probably not the version of yours. SOAP 1.2 expects a header of type application/soap+xml; charset=utf-8, so changing your line of code to this one below is gonna make it working:
httpConn.setRequestProperty("Content-Type", "application/soap+xml; charset=utf-8");
In SoapUI, it's possible to check the headers calling the request and going to the Headers tab on the bottom of the window:
Then, you can compare the differences between your application configs and the SoapUI ones.
403 error might be related to your soap request headers being sent to the server.
All Hosts valid will allow your Java App to trust the SSL Cert for the URL.
Check if your server is expecting soap header with username/password. If you have access to this server, you can check through the web server logs on where your request is failing. Error code points to to missing Soap Header particularly Soap Headers with username and password
Wonder if your SOAP request contains any kind of authentication information in headers like SAML. One option is, in your above code where you read the file and send the data to server, instead of sending it to server you dump it to another file. Dump that byteoutputstream. Then copy text from that file and put it in SOAP UI and try running that. Does that work?
In a similar situation we have been some time before, and as long as trying TrustManager didn't work as expected, we managed to overcome this problem by installing the certificate from server to JVM's keystore (JVM used to run the application). More information about how to do it you can find in several posts, like
How to import a .cer certificate into a java keystore?
I am aware that it is a try to force JVM to accept SSL certificates, and this functionality would be better to live in application context, but as long as we were building a web application which ran in specific application servers, the implemented solution was an accepted one.
I am trying to POST a file using HttpClient. However, I don't have access to the actual File but I have access to its InputStream. Is there a way I can still POST the file?
This is what I have done so far:
public void sendFile (InputStream instream) {
HttpClient client = new HttpClient();
PostMethod method = new PostMethod("http://localhost:8080/myservice/testupload");
Part[] parts = new Part[] {
//new FilePart("myFile", file.getName(), file)
};
method.setRequestEntity(
new MultipartRequestEntity(parts, method.getParams()));
client.executeMethod(method);
}
as you can see, the FilePart needs file but I have InputStream. How can I POST the input stream as a file?
Looking at the javadoc for FilePart, there is a constructor which accepts PartSource instead of File, and there is a subclass of PartSource called ByteArrayPartSource, which you can construct from byte[]; you can obtain this from the InputStream as described here.
How do I get an OutputStream using org.apache.http.impl.client.DefaultHttpClient?
I'm looking to write a long string to an output stream.
Using HttpURLConnection you would implement it like so:
HttpURLConnection connection = (HttpURLConnection)url.openConnection();
OutputStream out = connection.getOutputStream();
Writer wout = new OutputStreamWriter(out);
writeXml(wout);
Is there a method using DefaultHttpClient similar to what I have above? How would I write to an OutputStream using DefaultHttpClient instead of HttpURLConnection?
e.g
DefaultHttpClient client = new DefaultHttpClient();
OutputStream outstream = (get OutputStream somehow)
Writer wout = new OutputStreamWriter(out);
I know that another answer has already been accepted, just for the record this is how one can write content out with HttpClient without intermediate buffering in memory.
AbstractHttpEntity entity = new AbstractHttpEntity() {
public boolean isRepeatable() {
return false;
}
public long getContentLength() {
return -1;
}
public boolean isStreaming() {
return false;
}
public InputStream getContent() throws IOException {
// Should be implemented as well but is irrelevant for this case
throw new UnsupportedOperationException();
}
public void writeTo(final OutputStream outstream) throws IOException {
Writer writer = new OutputStreamWriter(outstream, "UTF-8");
writeXml(writer);
writer.flush();
}
};
HttpPost request = new HttpPost(uri);
request.setEntity(entity);
You can't get an OutputStream from BasicHttpClient directly. You have to create an HttpUriRequest object and give it an HttpEntity that encapsulates the content you want to sent. For instance, if your output is small enough to fit in memory, you might do the following:
// Produce the output
ByteArrayOutputStream out = new ByteArrayOutputStream();
Writer writer = new OutputStreamWriter(out, "UTF-8");
writeXml(writer);
// Create the request
HttpPost request = new HttpPost(uri);
request.setEntity(new ByteArrayEntity(out.toByteArray()));
// Send the request
DefaultHttpClient client = new DefaultHttpClient();
HttpResponse response = client.execute(request);
If the data is large enough that you need to stream it, it becomes more difficult because there's no HttpEntity implementation that accepts an OutputStream. You'd need to write to a temp file and use FileEntity or possibly set up a pipe and use InputStreamEntity
EDIT See oleg's answer for sample code that demonstrates how to stream the content - you don't need a temp file or pipe after all.
This worked well on android. It should also work for large files, as no buffering is needed.
PipedOutputStream out = new PipedOutputStream();
PipedInputStream in = new PipedInputStream();
out.connect(in);
new Thread() {
#Override
public void run() {
//create your http request
InputStreamEntity entity = new InputStreamEntity(in, -1);
request.setEntity(entity);
client.execute(request,...);
//When this line is reached your data is actually written
}
}.start();
//do whatever you like with your outputstream.
out.write("Hallo".getBytes());
out.flush();
//close your streams
I wrote an inversion of Apache's HTTP Client API [PipedApacheClientOutputStream] which provides an OutputStream interface for HTTP POST using Apache Commons HTTP Client 4.3.4.
Calling-code looks like this:
// Calling-code manages thread-pool
ExecutorService es = Executors.newCachedThreadPool(
new ThreadFactoryBuilder()
.setNameFormat("apache-client-executor-thread-%d")
.build());
// Build configuration
PipedApacheClientOutputStreamConfig config = new
PipedApacheClientOutputStreamConfig();
config.setUrl("http://localhost:3000");
config.setPipeBufferSizeBytes(1024);
config.setThreadPool(es);
config.setHttpClient(HttpClientBuilder.create().build());
// Instantiate OutputStream
PipedApacheClientOutputStream os = new
PipedApacheClientOutputStream(config);
// Write to OutputStream
os.write(...);
try {
os.close();
} catch (IOException e) {
logger.error(e.getLocalizedMessage(), e);
}
// Do stuff with HTTP response
...
// Close the HTTP response
os.getResponse().close();
// Finally, shut down thread pool
// This must occur after retrieving response (after is) if interested
// in POST result
es.shutdown();
Note - In practice the same client, executor service, and config will likely be reused throughout the life of the application, so the outer prep and close code in the above example will likely live in bootstrap/init and finalization code rather than directly inline with the OutputStream instantiation.