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Java visible interface that can not be implemented

I'm working on making a programming language that compiles to JVM bytecode, and it highly relies on interfaces as types. I need some way to make an interface private, but have other code still be able to access it, but not make something that implements it.
I was thinking about using abstract classes with a private constructor, so only the classes in the same file would be able to access it. The only problem is that it is impossible to extend multiple abstract classes at once. For example, the structure of a simple compiled program would be this:
// -> Main.java
public class Main {
public static MyInteger getMyInteger() {
return new MyIntegerImpl(10);
}
public static void main(String[] args) {}
private interface MyInteger {
public int getValue();
}
private static class MyIntegerImpl implements MyInteger {
private final int value;
public int getValue() {
return value;
}
public MyIntegerImpl(int value) {
this.value = value;
}
}
}
And another file, in which there is a problem:
// -> OtherFile.java
public class OtherFile {
public static void main(String[] args) {
Main.MyInteger myInteger = Main.getMyInteger(); //Error: The type Main.MyInteger is not visible.
System.out.println(myInteger.getValue());
}
//I do not want this to be allowed
public static class sneakyInteger implements Main.MyInteger { //Error(Which is good)
public int getValue() {
System.out.println("Person accessed value");
return 10;
}
}
}
The reason why I want to do this is so one person can not mess up any other person's code by providing their own implementations of things that should be only implemented by that other person.
Any help would be much appreciated.

I'm pretty sure that you should think again about what you are trying to do and change approach, but the answer for your question is to add to the interface some empty void method that is getting the parameter of the inner private class specific for the wrapper class
public class Test {
private class InnerPrivateClass {
private InnerPrivateClass() {}
}
public interface MyInteger {
int getValue();
void accept(InnerPrivateClass c);
}
private class MyIntegerImpl implements MyInteger {
#Override
public int getValue() {
return 0;
}
#Override
public void accept(InnerPrivateClass c) {}
}
}
However, as I said, I don't like this and for me it means that your idea is broken

How does a static method use a comparator?

I have a static method which needs to invoke the SportsMenComparator. But this, as we all know is not allowed. How does a static function use a comparator subclass ? Although I have workarounds, I am looking for best practices for this particular problem.
final class SportsMan {
private final String name;
private final int rank;
private final String sport;
public SportsMan (String name, int rank, String sport) {
this.name = name;
this.rank = rank;
this.sport = sport;
}
public String getName() {
return name;
}
public int getRank() {
return rank;
}
public String getSport() {
return sport;
}
}
final class Sport {
private final String sport;
private final int numberOfPlayers;
public Sport(String sport, int numberOfPlayers) {
this.sport = sport;
this.numberOfPlayers = numberOfPlayers;
}
public String getSport() {
return sport;
}
public int getNumberOfPlayers() {
return numberOfPlayers;
}
}
public final class Joins {
private Joins () {}
public class SportsMenComparator implements Comparator<SportsMan> {
#Override
public int compare(SportsMan s1, SportsMan s2) {
return s1.getSport().compareTo(s2.getSport());
}
}
public static void innerJoinSort(List<SportsMan> sportsMans, List<Sport> sportList) {
Collections.sort(sportsMans, new SportsMenComparator());
}
}
Eclipse results in the following message: No enclosing instance of type Joins is accessible where Joins is name of the enclosing class.

But this, as we all know is not allowed. How does a static function use a comparator subclass ?
You cannot use a non static reference,still you are allowed to create a new object and use it. So since you are creating a new SportsMenComparator object and passing, no issues.
For example:
public static void main(String[] args) {
List<String> s =new ArrayList<String>();
s.add(""); // allowed
}
But
List<String> s =new ArrayList<String>();
public static void main(String[] args) {
System.out.println();
s.add(""); // Error: Cannot make a static reference to the non-static field s
}
Edit:
Since you defined the comparator class inside the Joins , you need the Joins object to access the comparation inside it
Collections.sort(sportsMans, new Joins().new SportsMenComparator());

For using a Comparator, there is no difference between using it from a static- or non-static method. In either case an instance of the Comparator has to be used.
The Garbage Collector of modern JVMs is very efficient at handling short-lived objects. Therefore the penalty to be paid for using a fresh instance (via new) every time is usually no issue. However, if you don't want to use a fresh instance every time, I think the best option would be to add a static field to your SportsMenComparator, containing a singleton instance of the comparator:
public class SportsMenComparator implements Comparator<SportsMan> {
public static final SportsMenComparator instance=new SportsMenComparator();
#Override
public int compare(SportsMan s1, SportsMan s2) {
return s1.getSport().compareTo(s2.getSport());
}
}
public static void innerJoinSort(List<SportsMan> sportsMans, List<Sport> sportList) {
Collections.sort(sportsMans, SportsMenComparator.instance);
}

The problem is that you try to access an instance element (in this case it is a class, indeed the same as with a filed or method) within a static method, which is not associated with an instance. SURESH ATTA's answer is right, but you can also make your SportsMenComparator class static and it will work. I do not sse any reason to associate your comparator with an instance of the Joins class.

One can use something like this---
public static boolean someMethod(MyObject obj1, MyObject obj2){
return obj1.compare(obj2);
}

Why you cant include parameter to the function.
public static void innerJoinSort(List<SportsMan> sportsMans, List<Sport> sportList, Comparator comparator) {
Collections.sort(sportsMans, comparator);
}

Utilizing Public Final Classes Java

I would just like a clear example of how to instantiate a public final class in Java. I have to use a method from a class like this for a project, and have no idea how to instantiate it in the first place. Very difficult to find a clear example and explanation of the proper syntax. Thanks for the help.

public class Test {
public static void main(String[] args) {
Project pro = new Project();
pro.getName();
}
}
final class Project{
public String getName(){return "";}
}
===============================
A final class can be created like a normal class, Only thing is it can not be extended

This is an example
public class del {
public static void main(String args[])
{
x x1=new x();
System.out.println(x1.u());
}
}
final class x
{
public String u()
{
return "hi";
}
}
As you can see,x is a final class and have a method u which returns a string.
I am instatiating x in class del and calling its method u.
The output is hi
For more info click on final

final class Test{
public void callMe(){
System.out.println("In callMe method.");
}
}
public class TestingFinalClass{
public static void main(String[] args){
Test t1 = new Test();
t1.callMe();
}
}
Output : In callMe method.
final in java is applied to variable,method,class
final variable : the variable can not be signed with another value.
final method : the method cannot not be overridden.
final class : the class cannot extended.
The best example is String class in java. public final class String you can access the methods of String class as normal.
Some links
final keyword
String class

public class Test {
public static void main(String[] args) {
StdRandom stdRandom = StdRandom.getInstance(); /* this will retun an instance of the class, if needed you can use it */
int result =StdRandom.uniform(1);
System.out.println(result);
}
}
final class StdRandom{
private static StdRandom stdRandom = new StdRandom();
private StdRandom(){
}
public static StdRandom getInstance(){
return stdRandom;
}
public static int uniform(int N){
// Implement your logic here
return N;
}
}

Java Enum with multiple datatype fields?

I have following fields
a(String)
b(String)
c(String)
d(boolean)
e(boolean)
Is it possible to have them all in an Enum like following?
public enum Fields {
a("A")
b("B")
c("C")
d(true)
e(false)
}

You can have them but you should define constructors which takes String or boolean as parameters.
public enum Constants {
CONSTANT_STRING1("CONSTANT_VALUE1"),
CONSTANT_STRING2("CONSTANT_VALUE2"),
CONSTANT_STRING3("CONSTANT_VALUE3");
CONSTANT_FLAG1(false);
CONSTANT_FLAG2(true);
private String constants;
private boolean flag;
private Constants(String cons) {
this.constants = cons;
}
private Constants(boolean lFlag) {
this.flag= lFlag;
}
}

It sounds like you are using an enum to store constants, which is bad practice.

It is possible, but I would advice against it. In most cases, what you really want is a common interface, which is implemented by two (or more) different classes.
Please also note that is fully legitimate for an enum to implement an interface, but it is seldom you see two enums implement the same interface like in the example below:
public interface Fields {
}
public enum StringFields implements Fields {
A("A"),
B("B"),
C("C")
private StringFields(String str) {
this.str = str;
}
private final String str;
}
public enum BooleanFields implements Fields {
D(true),
E(false);
private BooleanFields(boolean val) {
this.val = val;
}
private final boolean val;
}

You can have two different constructors in the enum, but that means you need to have two fields (with one of them not being set). I do not think this would make much sense.
public enum Fields {
a("A"), b("B"), c("C"), d(true), e(false);
Fields(String str) {
strval = str;
value = false;
}
Fields(boolean val) {
strval = null;
value = val;
}
private final String strval;
private final boolean value;
}
EDITED*** Compiles now. You have to initialize both at the same time.

How to declare field inside Enum in Java?

I want to declare static(or not static) variable inside Enum. I need this because I want to associate enum values with some strings. But i Don't want to hardcode this strings. I want to use my application-wide class with String constants.
I.e. I want to write like this inside enum declaraton, but there compile time error:
public enum MyEnum {
private static final AppConstants CONSTANTS = AppConstants.getInstance();
ONE(CONSTANTS.one()),
TWO(CONSTANTS.two());
}
How I can put in enum a field?

It's one of the limitations, the enum values must be specified first but you can always refer to the same singelton in every instantiation...
enum MyEnum {
ONE(Test.getInstance().one()),
TWO(Test.getInstance().two());
public final String val;
MyEnum(String val) { this.val = val; }
}
Example that outputs "hello":
public class Test {
public static void main(String[] args) {
System.out.println(MyEnum.ONE.val);
}
public String one() {
return "hello";
}
public String two() {
return "world" ;
}
static Test instance;
public synchronized static Test getInstance() {
if (instance == null)
instance = new Test();
return instance;
}
}

It's a bit hacky. But you'll have to change your AppConstants class a bit.
public enum MyEnum {
ONE(getConstant("one")),
TWO(getConstant("one"));
private static final AppConstants CONSTANTS = AppConstants.getInstance();
private static String getConstant(String key) {
// You can use a map inside the AppConstants or you can
// invoke the right method using reflection. Up to you.
return CONSTANTS.get(key);
}
private MyEnum(String value) {
}
}

The enum constants need to be the first elements in the Enumeration
public enum MyEnum {
ONE,TWO;
private static final AppConstants CONSTANTS = AppConstants.getInstance();
#Override
public String toString() {
if(this==ONE){
return CONSTANTS.one();
} else if(this==TWO){
return CONSTANTS.two();
}
return null;
}
}