I am connecting to a MySQL table using JPA Hibernate. But I am getting error in my Java code:
org.hibernate.HibernateException: Missing table
My table is present in MySQL database schema. I am not getting why missing table exception is thrown here. This is a newly created table. All other existing tables in the same schema are accessible from Hibernate. I saw similar posts with same error. But the answers there didn't help my cause. Can you please let me know what can be the issue here.
If table is present, then most likely it is user permission issue. This happens if you have created the table using a different MySQL user. Make sure the MySQL username/password that you are using in Hibernate is having access to the table. To test, login to MySQL console directly using Hibernate credential & run a select query on the table. If you see similar error as below, then you need to grant access to the table for the Hibernate user.
ERROR 1142 (42000): SELECT command denied to user
Source: http://www.w3spot.com/2020/10/how-to-solve-caused-by-hibernateexception-missing-table.html
Make sure the user has access to the table
Make sure names are equals in terms of case sensitivity
Make sure the schema name and table name are not misspelled
If you share more information about the issue, it would be easier to pinpoint the problem.
Chances are there is an inheritance scenario with a physical table that you assumed to be abstract.
To dig deeper you can put a breakpoint in org.hibernate.tool.schema.extract.internal.DatabaseInformationImpl#getTablesInformation which calls extractor.getTable to see why your table is not returned as part of schema tables.
Rerun the app with the specified breakpoint and step through lines to get to the line which queries table names from the database metadat.
#Override
public TableInformation getTableInformation(QualifiedTableName tableName) {
if ( tableName.getObjectName() == null ) {
throw new IllegalArgumentException( "Passed table name cannot be null" );
}
return extractor.getTable(
tableName.getCatalogName(),
tableName.getSchemaName(),
tableName.getTableName()
);
}
I'm using hsql 2.3.3. According to documentation I can fix this either by adding additional statement to the sql
SET DATABASE SQL SYNTAX ORA TRUE
or by adding property to the url
url: jdbc:h2:mem:test;sql.syntax_ora=true
First one fixes the issue for me (so this is root cause of it), but I would like to use second one as it looks more generalized for me. But url property does't do the trick. What I'm missing?
The URL property works only if you create a new database with the connection property. The new database will then include the SQL statement and run it automatically at each startup.
I'm trying to make custom spring Data query using field from reference as query
parameter. When i performed this query via REST i had no results at all:
I enabled hibernate logs and copy it to H2 console and I got many results:
My Flight and Airport entities are very simple
So what am I doing wrong? I have other simpler methods and they work fine using browser. I tried the same using Query annotation(second method on second screen), but I got same results. (Copied generated sql query to H2 console and received many results but it didn't work via REST).
EDIT
I found the solution. I just removed quotation marks from URL and
it works well :D
Sorry for my inattention.
Regards,
Michal
I found the solution. It was very simple. Basically I just removed quotation marks from URL and it works well :D
Actual method in Repository looks like:
List findFlightsByFromCityAndToCity(#Param("from") String from, #Param("to") String to);
Regards,
Michal
I am getting below exception, when trying to insert a batch of rows to an existing table
ORA-00942: table or view does not exist
I can confirm that the table exists in db and I can insert data to that table using oracle
sql developer. But when I try to insert rows using preparedstatement in java, its throwing table does not exist error.
Please find the stack trace of error below
java.sql.SQLException: ORA-00942: table or view does not exist
at oracle.jdbc.dbaccess.DBError.throwSqlException(DBError.java:134)
at oracle.jdbc.ttc7.TTIoer.processError(TTIoer.java:289)
at oracle.jdbc.ttc7.Oall7.receive(Oall7.java:573)
at oracle.jdbc.ttc7.TTC7Protocol.doOall7(TTC7Protocol.java:1889)
at oracle.jdbc.ttc7.TTC7Protocol.parseExecuteFetch(TTC7Protocol.java:1093)
at oracle.jdbc.driver.OracleStatement.executeNonQuery(OracleStatement.java:2047)
at oracle.jdbc.driver.OracleStatement.doExecuteOther(OracleStatement.java:1940)
at oracle.jdbc.driver.OracleStatement.doExecuteWithTimeout>>(OracleStatement.java:2709)
at oracle.jdbc.driver.OraclePreparedStatement.executeUpdate(OraclePreparedStatement.java:589)
at quotecopy.DbConnection.insertIntoDestinationDb(DbConnection.java:591)
at quotecopy.QuoteCopier.main(QuoteCopier.java:72)
Can anyone suggest the reasons for this error ?
Update : Issue solved
There was no problem with my database connection properties or with my table or view name. The solution to the problem was very strange. One of the columns that I was trying insert was of Clob type. As I had a lot of trouble handling clob data in oracle db before, gave a try by replacing the clob setter with a temporary string setter and the same code executed with out any problems and all the rows were correctly inserted!!!.
ie. peparedstatement.setClob(columnIndex, clob)
was replaced with
peparedstatement.setString(columnIndex, "String")
Why an error table or view does exist error was throws for error in inserting clob data. Could anyone of you please explain ?
Thanks a lot for your answers and comments.
Oracle will also report this error if the table exists, but you don't have any privileges on it. So if you are sure that the table is there, check the grants.
There seems to be some issue with setCLOB() that causes an ORA-00942 under some circumstances when the target table does exist and is correctly privileged. I'm having this exact issue now, I can make the ORA-00942 go away by simply not binding the CLOB into the same table.
I've tried setClob() with a java.sql.Clob and setCLOB() with an oracle.jdbc.CLOB but with the same result.
As you say, if you bind as a string the problem goes away - but this then limits your data size to 4k.
From testing it seems to be triggered when a transaction is open on the session prior to binding the CLOB. I'll feed back when I've solved this...checking Oracle support.
There was no problem with my database connection properties or with my table or view name. The solution to the problem was very strange. One of the columns that I was trying insert was of Clob type. As I had a lot of trouble handling clob data in oracle db before, gave a try by replacing the clob setter with a temporary string setter and the same code executed with out any problems and all the rows were correctly inserted!!!.
ie. peparedstatement.setClob(columnIndex, clob)
was replaced with
peparedstatement.setString(columnIndex, "String")
#unbeli is right. Not having appropriate grants on a table will result in this error. For what it's worth, I recently experienced this. I was experiencing the exact problem that you described, I could execute insert statements through sql developer but would fail when using hibernate. I finally realized that my code was doing more than the obvious insert. Inserting into other tables that did not have appropriate grants. Adjusting grant privileges solved this for me.
Note: Don't have reputation to comment, otherwise this may have been a comment.
We experienced this issue on a BLOB column. Just in case anyone else lands on this question when encountering this error, here is how we resolved the issue:
We started out with this:
preparedStatement.setBlob(parameterIndex, resultSet.getBlob(columnName)); break;
We resolved the issue by changing that line to this:
java.sql.Blob blob = resultSet.getBlob(columnName);
if (blob != null) {
java.io.InputStream blobData = blob.getBinaryStream();
preparedStatement.setBinaryStream(parameterIndex, blobData);
} else {
preparedStatement.setBinaryStream(parameterIndex, null);
}
I found how to solve this problem without using JDBC's setString() method which limits the data to 4K.
What you need to do is to use preparedStatement.setClob(int parameterIndex, Reader reader). At least this is what that worked for me. Thought Oracle drivers converts data to character stream to insert, seems like not. Or something specific causing an error.
Using a characterStream seems to work for me. I am reading tables from one db and writing to another one using jdbc. And i was getting table not found error just like it is mentioned above. So this is how i solved the problem:
case Types.CLOB: //Using a switch statement for all columns, this is for CLOB columns
Clob clobData = resultSet.getClob(columnIndex); // The source db
if (clobData != null) {
preparedStatement.setClob(columnIndex, clobData.getCharacterStream());
} else {
preparedStatement.setClob(columnIndex, clobData);
}
clobData = null;
return;
All good now.
Is your script providing the schema name, or do you rely on the user logged into the database to select the default schema?
It might be that you do not name the schema and that you perform your batch with a system user instead of the schema user resulting in the wrong execution context for a script that would work fine if executed by the user that has the target schema set as default schema. Your best action would be to include the schema name in the insert statements:
INSERT INTO myschema.mytable (mycolums) VALUES ('myvalue')
update: Do you try to bind the table name as bound value in your prepared statement? That won't work.
It works for me:
Clob clob1;
while (rs.next()) {
rs.setString(1, rs.getString("FIELD_1"));
clob1 = rs.getClob("CLOB1");
if (clob1 != null) {
sta.setClob(2, clob1.getCharacterStream());
} else {
sta.setClob(2, clob1);
}
clob1 = null;
sta.setString(3, rs.getString("FIELD_3"));
}
Is it possible that you are doing INSERT for VARCHAR but doing an INSERT then an UPDATE for CLOB?
If so, you'll need to grant UPDATE permissions to the table in addition to INSERT.
See https://stackoverflow.com/a/64352414/1089967
Here I got the solution for the question. The problem is on glass fish if you are using it. When you create JNDI name make sure pool name is correct and pool name is the name of connection pool name that you are created.
I am using an APACHE DERBY database, and basing my database interactions on EntityManager, and I don't want to use JDBC class to build a query to change my tables' names (i just need to put a prefix to each new user to the application, but have the same structure of tables), such as:
//em stands for EntityManager object
Query tableNamesQuery= em.createNamedQuery("RENAME TABLE SCHEMA.EMP_ACT TO EMPLOYEE_ACT");
em.executeUpdate();
// ... rest of the function's work
// The command works from the database command prompt but i don't know how to use it in a program
//Or as i know you can't change system tables data, but here's the code
Query tableNamesQuery= em.createNamedQuery("UPDATE SYS.SYSTABLES SET TABLENAME='NEW_TABLE_NAME' WHERE TABLETYPE='T'");
em.executeUpdate();
// ... rest of the function's work
My questions are :
This syntax is correct?
Will it work?
Is there any other alternative?
Should I just use the SYS.SYSTABLES and find all the tables that has 'T' as tabletype and alter their name their, will it change the access name ?
I think you're looking for the RENAME TABLE statement: http://db.apache.org/derby/docs/10.10/ref/rrefsqljrenametablestatement.html
Don't just issue update statements against the system catalogs, you will corrupt your database.