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Input not converted to string?

I'm just getting started with Java (via an edX class), and one of the assignments is to create a vacation planner program that gathers information from the user. When I run the code in terminal, it works, but the strings "name" and "place" are not displayed correctly. Instead, the lines after the string declarations are displayed as "Nice to meet you + name + where are you traveling to?". Am I missing something that would have the input assigned to "name" displayed in the sentence?
The code below is for 1 of 4 methods that will be in the program. Image of my output:
import java.util.Scanner;
public class projectplanner{
public static void main(String[] args) {
partOne();
partTwo();
partThree();
partFour();
}
public static void partOne() {
[enter image description here][1] Scanner input = new Scanner(System.in);
System.out.print("Welcome to Vacation Planner!");
System.out.print("What is your name?" + "");
String name = input.nextLine();
System.out.println("Nice to meet you " + name + "where are you travelling to?");
String place = input.nextLine();
System.out.println("Great! " + place + " sounds like a great trip.");
}

How do I return the number of items found after I do a search?

Please help me to figure out how I can get a count of the result when I do a search against a specific folder?
Also how can I ask the user if they want to perform another search?
// Importing utilities
import java.io.File;
import java.util.*;
public class FileListing
{
public static void main (String[] args)
{
// Creating a Scanner
Scanner keyboard = new Scanner(System.in);
// Specifying search location
File file = new File("D:/Music");
String[] content = file.list();
// Searching for a match
System.out.println("Enter the first few characters of the folder/file to do a lookup");
String userInput = keyboard.nextLine();
// Adding text to say what the user searched for
System.out.println("Below you will find the list of folders/files with a partial match to (" + userInput + ").");
System.out.println();
// Posting the contents
for(String folders : content)
{
if(folders.toUpperCase().startsWith(userInput.toUpperCase()))
{
System.out.println("Name: " + folders);
}
}
}
}

If you want to count your matches you can do the following
int i=0;
// Posting the contents
for(String folders : content)
{
if(folders.toUpperCase().startsWith(userInput.toUpperCase()))
{
System.out.println("Name: " + folders);
i++;
}
}
System.out.println("Total number of results: " + i);`
As for asking the user, consider using a do-while loop in the following format
do{
// your code
// ask user and read his answer on a string called userChoice
}while (userChoice.equals('y'))
Experiment with our suggestions and you will find the answer easily enough!

I would add a variable
int count = 0;
right before the for loop, and just increment it if it's a match.

This should get you started. I am incrementing the variable count each time a match is found. I am also looping forever so it keeps asking the user for more input.
// Importing utilities
import java.io.File;
import java.util.*;
public class FileListing
{
public static void main (String[] args)
{
// Creating a Scanner
Scanner keyboard = new Scanner(System.in);
// Specifying search location
File file = new File("D:/Music");
String[] content = file.list();
while(true){
// Searching for a match
System.out.println("Enter the first few characters of the folder/file to do a lookup");
String userInput = keyboard.nextLine();
// Adding text to say what the user searched for
System.out.println("Below you will find the list of folders/files with a partial match to (" + userInput + ").");
System.out.println();
// Posting the contents
int count=0;
for(String folders : content)
{
if(folders.toUpperCase().startsWith(userInput.toUpperCase()))
{
System.out.println("Name: " + folders);
count++;
}
}
}
}
}

Use a while loop and prompt the user to enter a phrase (such as 'exit') if they want to stop. After reading the user input, check the phrase and call a break if it matches the exit phrase.
Use a variable as Robert suggested to count the total number of files found.

How do I run this program in an applet?

package Homework;
import java.util.Scanner;
class FantasyGame{
public static void main ( String args[])
{
Scanner scan = new Scanner(System.in);
System.out.println("Welcome to Supercalifragilisticexpialidocious Quest!");
System.out.println("Enter the name of your character: ");
String name;
name = scan.nextLine();
System.out.println("Welcome to Supercalifragilisticexpialidocious Quest, " + (name) + "! " + "You will now assign attributes to your character, the total value assigned must not exceed 15 or be under 0, or the points will be assigned by default! (Type any NUMBER to continue)");
int ans = scan.nextInt();
System.out.println("Enter Strength (0-15): ");
int str = scan.nextInt();
System.out.println("Enter Health (0-15): ");
int hp = scan.nextInt();
System.out.println("Enter Luck (0-15): ");
int lck = scan.nextInt();
if (str + hp + lck <= 15)
{
System.out.println("Congratulations! You have successfully created your character!");
System.out.println("Name: " + (name));
System.out.println("Strength: " + (str));
System.out.println("Health: " + (hp));
System.out.println("Luck: " + (lck));
}
if (str + hp + lck > 15)
{
System.out.println("You have give your character too many attribute points! Default values have been assigned.");
System.out.println("Name: " + (name));
System.out.println("Strength: " + (5));
System.out.println("Health: " + (5));
System.out.println("Luck: " + (5));
}
}
}
I want to make a text-based game for my history class and I know basic Java enough to make a small one with just variables and stuff but I don't know how I can make it so that it runs directly as an applet with a black background and white text that shows up and responds to what you type, like the code above does in the console.
I've tried the command prompt method but all I get is "Access is Denied."
Also, when I try to export in eclipse, the launch configuration always goes to a class I don't want. Sorry but I am really confused and need a lot of help on this.

to write a simple applet, http://docs.oracle.com/javase/tutorial/deployment/applet/ this tutorial from oracle will walk you through it fairly well, it shouldn't be too hard to rearrange your code then

I figured it out. I just exported my program as a .jar and used Jar2Exe and it worked perfectly. Thanks!

You have not made you class public and that is why you are getting error "Access is denied" because it is not visible any more. Compiler is not able to find that class. Just write
....
//change is here
public class FantasyGame
{
....
}
....
Thanks !

Java How to search a word from text file [closed]

Closed. This question needs debugging details. It is not currently accepting answers.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Closed 6 years ago.
Improve this question
edit: Write a program to read in 100 words from a file. Then, have the user search for a word until they enter 'quit'.
The program will read in up to 100 words from a file. The file may or may not contain 100 words but the array should hold up to 100 (if the list does not contain enough words, fill the rest of the array with empty strings).
After the file is read in, the program will prompt the user for a search string. The program will then search for the string and tell the user if the word was found or not. The program will continue to get search strings from the user until the user enters 'quit'
Hello I need help write a program to find a word from text file
the result should look like:
Enter a word to search for: taco
Word 'taco' was found.
Enter a word to search for: asd
Word 'asd' was NOT found.
and when user enter the word "quit" the program will quit
below is what I have so far and need help to complete
import java.io.*;
import java.util.Scanner;
public class project2 {
public static void main( String[] args ) throws IOException {
String[] list;
String search;
list = load_list( "words.txt" );
search = prompt_user( "\nEnter a word to search for: " );
while ( ! search.equals( "quit" ) ) {
System.out.println( "Word '" + search + "' was" +
( ( find_word( search, list ) ) ? "" : " NOT" ) +
" found." );
search = prompt_user( "\nEnter a word to search for: " );
}
System.out.println();
}

for(String s: list){
if(s.equals(search)){
//do whatever
}
}

Use this:
Scanner txtscan = new Scanner(new File("filename.txt"));
while(txtscan.hasNextLine()){
String str = txtscan.nextLine();
if(str.indexOf("word") != -1){
System.out.println("EXISTS");
}
}

The below code answers this question perfectly:
String word = ""; int val = 0;
while(!word.matches("quit"))
{
System.out.println("Enter the word to be searched for");
Scanner input = new Scanner(System.in);
word = input.next();
Scanner file = new Scanner(new File("newFile.txt"));
while(file.hasNextLine())
{
String line = file.nextLine();
if(line.indexOf(word) != -1)
{
System.out.println("Word EXISTS in the file");
val = 1;
break;
}
else
{
val = 0;
continue;
}
}
if(val == 0)
{
System.out.println("Word does not exist");
}
System.out.println("-------continue or quit--- enter continue or quit");
word = input.next();
}

Why does the compiler complain "while expected" when I try to add more code?

Write a program with a word containing # character as an input. If the word doesn't contain #, it should prompt the user for a word with #. Once a word with # is read, it should output the word then terminate.
This is what I have done so far:
public class find {
public static void main(String[] args) {
System.out.println(" Please enter a word with # ");
Scanner scan = new Scanner(System.in);
String bad = "#";
String word = scan.next();
do
if (!word.contains(bad))
System.out.println(" Please try again ");
else
System.out.println(" " + word);
while (!word.contains(bad));
}
}
I can get it to terminate after a word containing "#" is given as input, but if I try to add a Scanner to the line after "please try again", it says while expected.

I think issue is you are missing surrounding braces for do/while:
do
if (!word.contains( bad ))
System.out.println( " Please try again " );
else
System.out.println( " " + word);
while ( !word.contains( bad ));
should be:
do
{
if (!word.contains( bad ))
System.out.println( " Please try again " );
else
System.out.println( " " + word);
}while ( !word.contains( bad ));
Some people may not like this, but my suggestion is always use open/close braces. In this case, for the code if/else also. It avoids lot of confusion.

This is where your problem lies:
do
if (!word.contains(bad))
System.out.println(" Please try again ");
else
System.out.println(" " + word);
while (!word.contains(bad));
You need to put braces from where the loop starts until it ends. |So this thing should like:
do {
if (!word.contains(bad))
System.out.println(" Please try again ");
else
System.out.println(" " + word);
} while(!word.contains(bad));
For Better Practice You should Check do...while loops here.

The problem with your code is it is not re-reading the word in your loop.
Modify your loop like this (minimum change to your code).
do {
word = scan.next();
if (!word.contains(bad))
System.out.println(" Please try again ");
else
System.out.println(" " + word);
}
while (!word.contains(bad));
And yes as others have pointed out try to use braces especially with nested constructs.

There are two issues.
Your code is not using the braces properly
you are not attempting to read the new word if right word is not entered.
Also I prefer while loop better in the case as opposed to do-while loop as below.
Scanner scan = new Scanner ( System.in );
String required= "#";
System.out.println( " Please enter a word with # " );
String word = scan.next() ;
//check if the right word(containing #) is entered,
//if not then loop until it is enteres
while((!word.contains(required)){
System.out.println( " Please try again " );
//read the new word as input from the user
word = scan.next() ;
}
//right word is entered, display it
System.out.println(word);
Also please note that when you use scan.next(), it reads each word separately if entered in the same line.