We Keep Coding

Convert PDF to JPG2000 file(s)

I recently started working on this project where I need to convert a PDF File into a JPEG2000 file(s) - 1 jp2 file per page -.
The goal was to replace a previous pdf to jpeg converter method we had, in order to reduce the size of the output file(s).
Based on a code I found on the internet, I made the pdftojpeg2000 converter method below, and I've been changing the setEncodingRate parameter value and comparing the results.
I managed to get smaller jpeg2000 output files, but the quality is very poor, compared to the Jpeg ones, specially for colored text or images.
Here is what my orginal pdf file looks like:
When I set setEncodingRate to 0.8 it looks like this:
My output file size is 850Ko, which is even bigger than the Jpeg (around 600Ko) ones, and lower quality.
At 0.1 setEncodingRate, the file size is considerably small, 111 Ko, but basically unreadable.
So basically what I'm trying to get here is smaller output files ( <600K ) with a better quality, And I'm wondering if it is feasible with the Jpeg2000 format.
public class ImageConverter {
public void compressor(String inputFile, String outputFile) throws IOException {
J2KImageWriteParam iwp = new J2KImageWriteParam();
PDDocument document = PDDocument.load(new File (inputFile), MemoryUsageSetting.setupMixed(10485760L));
PDFRenderer pdfRenderer = new PDFRenderer(document);
int nbPages = document.getNumberOfPages();
int pageCounter = 0;
BufferedImage image;
for (PDPage page : document.getPages()) {
if (page.hasContents()) {
image = pdfRenderer.renderImageWithDPI(pageCounter, 300, ImageType.RGB);
if (image == null)
{
System.out.println("If no registered ImageReader claims to be able to read the resulting stream");
}
Iterator writers = ImageIO.getImageWritersByFormatName("JPEG2000");
String name = null;
ImageWriter writer = null;
while (name != "com.sun.media.imageioimpl.plugins.jpeg2000.J2KImageWriter") {
writer = (ImageWriter) writers.next();
name = writer.getClass().getName();
System.out.println(name);
}
File f = new File(outputFile+"_"+pageCounter+".jp2");
long s = System.currentTimeMillis();
ImageOutputStream ios = ImageIO.createImageOutputStream(f);
writer.setOutput(ios);
J2KImageWriteParam param = (J2KImageWriteParam) writer.getDefaultWriteParam();
IIOImage ioimage = new IIOImage(image, null, null);
param.setSOP(true);
param.setWriteCodeStreamOnly(true);
param.setProgressionType("layer");
param.setLossless(true);
param.setCompressionMode(J2KImageWriteParam.MODE_EXPLICIT);
param.setCompressionType("JPEG2000");
param.setCompressionQuality(0.01f);
param.setEncodingRate(1.01);
param.setFilter(J2KImageWriteParam.FILTER_53 );
writer.write(null, ioimage, param);
System.out.println(System.currentTimeMillis() - s);
writer.dispose();
ios.flush();
ios.close();
image.flush();
pageCounter++;
}
}
}
public static void main(String[] args) {
String input = "E:/IMGTEST/mail-DOC0002.pdf";
String output = "E:/IMGTEST/mail-DOC0002/docamail-DOC0002-";
ImageConverter imgcv = new ImageConverter();
try {
imgcv.compressor(input, output);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}

Sharing multiple files with Gluon ShareService (image and txt)

We want to know how we can share multiple files (image and txt file) with the Gluon ShareService. Especially how to share an image which was previously taken and stored (in gallery) with the PictureService.
But we need to create a file first with the path and image name. Unfortunately, the PictureService saves the image with the image title consisting of date and time at the moment the picture was taken.
We tried to get the image name with the loadImageFromGallery method but this returns void and opens the recent-screen.
Here what we've tried to share an image:
public void sharePicture() {
Services.get(PicturesService.class).ifPresent(picturesService -> {
Image image = picturesService.loadImageFromGallery().get();
File file= new File("Pictures", image.toString());
Services.get(ShareService.class).ifPresent(service -> {
service.share("image/jpg", file);
});
});
}
How can we store the image where we want with a title we want?
How can we share a file and an image together?

You are on the right track, combining different services from Charm Down, in order to select an image from the gallery and share it.
There is a major problem in this approach, though: You can't convert easily a JavaFX Image into a File.
So far the PicturesService returns only a JavaFX Image, and not a File, so we need a way to save that image into a file that we can read and share.
And the process is not easy since on mobile we don't have SwingUtilities.
The initial approach of using a PixelReader to read the image and get a byte array doesn't really work, as it will give you a big raw file that can't be read or share.
I've used this solution that makes use of a PNG encoder to get the byte array of a png from a JavaFX image:
PngEncoderFX encoder = new PngEncoderFX(image, true);
byte[] bytes = encoder.pngEncode();
Then I'll save that byte array into a file in the public storage folder (so it can be shared), that I can retrieve using the `StorageService:
private File getImageFile(Image image) {
if (image == null) {
return null;
}
// 1. Encode image to png
PngEncoderFX encoder = new PngEncoderFX(image, true);
byte[] bytes = encoder.pngEncode();
// 2.Write byte array to a file in public storage
File root = Services.get(StorageService.class)
.flatMap(storage -> storage.getPublicStorage("Pictures"))
.orElse(null);
if (root != null) {
File file = new File(root, "Image-" + LocalDateTime.now().format(DateTimeFormatter.ofPattern("uuuuMMdd-HHmmss")) + ".png");
try (FileOutputStream fos = new FileOutputStream(file)) {
fos.write(bytes);
return file;
} catch (IOException ex) {
System.out.println("Error: " + ex);
}
}
return null;
}
Now, you can call the PicturesService, retrieve the image, save it to the file and finally share it:
Services.get(PicturesService.class).ifPresent(pictures -> {
// 1. Retrieve picture from gallery
pictures.loadImageFromGallery().ifPresent(image -> {
// 2. Convert image to file
File imageFile = getImageFile(image);
// 3. Share file
if (imageFile != null) {
Services.get(ShareService.class).ifPresent(share -> {
share.share("image/png", imageFile);
});
}
});
});
Note that you may run into memory issues if you try to encode big images.
Anyway, all the process could be simplified if the PicturesService will return a file in the first place. If you want to file an issue, you can do it here.
EDIT
A possible solution to avoid memory issues, and to reduce the size of the shared file, and based on this solution, is scaling down the original image, if it exceeds certain size, like it is already done in the iOS implementation of the PicturesService:
private Image scaleImage(Image source) {
// Possible limit based on memory limitations
double maxResolution = 1280;
double width = source.getWidth();
double height = source.getHeight();
double targetWidth = width;
double targetHeight = height;
if (width > maxResolution || height > maxResolution) {
double ratio = width/height;
if (ratio > 1) {
targetWidth = maxResolution;
targetHeight = targetWidth/ ratio;
}
else {
targetHeight = maxResolution;
targetWidth = targetHeight * ratio;
}
}
ImageView imageView = new ImageView(source);
imageView.setPreserveRatio(true);
imageView.setFitWidth(targetWidth);
imageView.setFitHeight(targetHeight);
return imageView.snapshot(null, null);
}
This method can be used now in getImageFile():
// 1 Scale image to avoid memory issues
Image scaledImage = scaleImage(image);
// 2. Encode image to png
PngEncoderFX encoder = new PngEncoderFX(scaledImage, true);
byte[] bytes = encoder.pngEncode();
// 3. Write byte array to a file in public storage
...

How to reduce size of a multipart file in java

I have Java Spring MVC application in which there is an option to upload an image and save to the server. i have the following method:
#RequestMapping(value = "/uploaddocimagecontentsubmit", method = RequestMethod.POST)
public String createUpdateFileImageContentSubmit(#RequestParam("file") MultipartFile file, ModelMap model)
{
//methods to handle file upload
}
I am now trying to reduce the size of the image refering the following:
increasing-resolution-and-reducing-size-of-an-image-in-java and decrease-image-resolution-in-java
The problem I am facing is that in the above examples, we are dealing with java.io.File Objects which are saved to a specified location. I dont want to save the image. Is there any way that I can use something similar to compress my Multipart Image file and continue with the upload.

Why don't you resize it on the client before upload? That will save some bandwidth
BlueImp JQuery Upload can do this

It was my first time taking a deep dive into the ImageIO package. I came across the MemoryCacheImageOutputStream, which allows you to write an image output stream to an output stream, i.e. ByteArrayOutputStream. From there, The data can be retrieved using toByteArray() and toString(), after compression. I used toByteArray, as I am storing images to postgresql and it stores the images as a byte array. I know this is late, but I hope it helps someone.
private byte[] compressImage(MultipartFile mpFile) {
float quality = 0.3f;
String imageName = mpFile.getOriginalFilename();
String imageExtension = imageName.substring(imageName.lastIndexOf(".") + 1);
// Returns an Iterator containing all currently registered ImageWriters that claim to be able to encode the named format.
// You don't have to register one yourself; some are provided.
ImageWriter imageWriter = ImageIO.getImageWritersByFormatName(imageExtension).next();
ImageWriteParam imageWriteParam = imageWriter.getDefaultWriteParam();
imageWriteParam.setCompressionMode(ImageWriteParam.MODE_EXPLICIT); // Check the api value that suites your needs.
// A compression quality setting of 0.0 is most generically interpreted as "high compression is important,"
// while a setting of 1.0 is most generically interpreted as "high image quality is important."
imageWriteParam.setCompressionQuality(quality);
ByteArrayOutputStream baos = new ByteArrayOutputStream();
// MemoryCacheImageOutputStream: An implementation of ImageOutputStream that writes its output to a regular
// OutputStream, i.e. the ByteArrayOutputStream.
ImageOutputStream imageOutputStream = new MemoryCacheImageOutputStream(baos);
// Sets the destination to the given ImageOutputStream or other Object.
imageWriter.setOutput(imageOutputStream);
BufferedImage originalImage = null;
try (InputStream inputStream = mpFile.getInputStream()) {
originalImage = ImageIO.read(inputStream);
} catch (IOException e) {
String info = String.format("compressImage - bufferedImage (file %s)- IOException - message: %s ", imageName, e.getMessage());
logger.error(info);
return baos.toByteArray();
}
IIOImage image = new IIOImage(originalImage, null, null);
try {
imageWriter.write(null, image, imageWriteParam);
} catch (IOException e) {
String info = String.format("compressImage - imageWriter (file %s)- IOException - message: %s ", imageName, e.getMessage());
logger.error(info);
} finally {
imageWriter.dispose();
}
return baos.toByteArray();
}

Can I tell what the file type of a BufferedImage originally was?

In my code, I have a BufferedImage that was loaded with the ImageIO class like so:
BufferedImage image = ImageIO.read(new File (filePath);
Later on, I want to save it to a byte array, but the ImageIO.write method requires me to pick either a GIF, PNG, or JPG format to write my image as (as described in the tutorial here).
I want to pick the same file type as the original image. If the image was originally a GIF, I don't want the extra overhead of saving it as a PNG. But if the image was originally a PNG, I don't want to lose translucency and such by saving it as a JPG or GIF. Is there a way that I can determine from the BufferedImage what the original file format was?
I'm aware that I could simply parse the file path when I load the image to find the extension and just save it for later, but I'd ideally like a way to do it straight from the BufferedImage.

As #JarrodRoberson says, the BufferedImage has no "format" (i.e. no file format, it does have one of several pixel formats, or pixel "layouts"). I don't know Apache Tika, but I guess his solution would also work.
However, if you prefer using only ImageIO and not adding new dependencies to your project, you could write something like:
ImageInputStream input = ImageIO.createImageInputStream(new File(filePath));
try {
Iterator<ImageReader> readers = ImageIO.getImageReaders(input);
if (readers.hasNext()) {
ImageReader reader = readers.next();
try {
reader.setInput(input);
BufferedImage image = reader.read(0); // Read the same image as ImageIO.read
// Do stuff with image...
// When done, either (1):
String format = reader.getFormatName(); // Get the format name for use later
if (!ImageIO.write(image, format, outputFileOrStream)) {
// ...handle not written
}
// (case 1 done)
// ...or (2):
ImageWriter writer = ImageIO.getImageWriter(reader); // Get best suitable writer
try {
ImageOutputStream output = ImageIO.createImageOutputStream(outputFileOrStream);
try {
writer.setOutput(output);
writer.write(image);
}
finally {
output.close();
}
}
finally {
writer.dispose();
}
// (case 2 done)
}
finally {
reader.dispose();
}
}
}
finally {
input.close();
}

BufferedImage does not have a "format"
Once the bytes have been translated into a BufferedImage the format of the source file is completely lost, the contents represent a raw byte array of the pixel information nothing more.
Solution
You should use the Tika library to determine the format from the original byte stream before the BufferedImage is created and not rely on file extensions which can be inaccurate.

One could encapsulate the BufferedImage and related data in class instance(s) like so:
final public class TGImage
{
public String naam;
public String filename;
public String extension;
public int layerIndex;
public Double scaleX;
public Double scaleY;
public Double rotation;
public String status;
public boolean excluded;
public BufferedImage image;
public ArrayList<String> history = new ArrayList<>(5);
public TGImage()
{
naam = "noname";
filename = "";
extension ="";
image = null;
scaleX = 0.0;
scaleY = 0.0;
rotation = 0.0;
status = "OK";
excluded = false;
layerIndex = 0;
addHistory("Created");
}
final public void addHistory(String str)
{
history.add(TGUtil.getCurrentTimeStampAsString() + " " + str);
}
}
and then use it like this:
public TGImage loadImage()
{
TGImage imgdat = new TGImage();
final JFileChooser fc = new JFileChooser();
FileNameExtensionFilter filter = new FileNameExtensionFilter("Image Files", "jpg", "png", "gif", "tif");
fc.setFileFilter(filter);
fc.setCurrentDirectory(new File(System.getProperty("user.home")));
int result = fc.showOpenDialog(this); // show file chooser
if (result == JFileChooser.APPROVE_OPTION)
{
File file = fc.getSelectedFile();
System.out.println("Selected file extension is " + TGUtil.getFileExtension(file));
if (TGUtil.isAnImageFile(file))
{
//System.out.println("This is an Image File.");
try
{
imgdat.image = ImageIO.read(file);
imgdat.filename = file.getName();
imgdat.extension = TGUtil.getFileExtension(file);
info("image has been loaded from file:" + imgdat.filename);
} catch (IOException ex)
{
Logger.getLogger(TGImgPanel.class.getName()).log(Level.SEVERE, null, ex);
imgdat.image = null;
info("File not loaded IOexception: img is null");
}
} else
{
imgdat = null;
info("File not loaded: The requested file is not an image File.");
}
}
return imgdat;
}
Then you have everything relevant together in TGImage instance(s).
and perhaps use it in an imagelist like so:
ArrayList<TGImage> images = new ArrayList<>(5);

Get Image from the document using Apache POI

I am using Apache Poi to read images from docx.
Here is my code:
enter code here
public Image ReadImg(int imageid) throws IOException {
XWPFDocument doc = new XWPFDocument(new FileInputStream("import.docx"));
BufferedImage jpg = null;
List<XWPFPictureData> pic = doc.getAllPictures();
XWPFPictureData pict = pic.get(imageid);
String extract = pict.suggestFileExtension();
byte[] data = pict.getData();
//try to read image data using javax.imageio.* (JDK 1.4+)
jpg = ImageIO.read(new ByteArrayInputStream(data));
return jpg;
}
It reads images properly but not in order wise.
For example, if document contains
image1.jpeg
image2.jpeg
image3.jpeg
image4.jpeg
image5.jpeg
It reads
image4
image3
image1
image5
image2
Could you please help me to resolve it?
I want to read the images order wise.
Thanks,
Sithik

public static void extractImages(XWPFDocument docx) {
try {
List<XWPFPictureData> piclist = docx.getAllPictures();
// traverse through the list and write each image to a file
Iterator<XWPFPictureData> iterator = piclist.iterator();
int i = 0;
while (iterator.hasNext()) {
XWPFPictureData pic = iterator.next();
byte[] bytepic = pic.getData();
BufferedImage imag = ImageIO.read(new ByteArrayInputStream(bytepic));
ImageIO.write(imag, "jpg", new File("D:/imagefromword/" + pic.getFileName()));
i++;
}
} catch (Exception e) {
System.exit(-1);
}
}