Check if String token contains string char and String number value - java

1)I need to check if String contains a String characters what will be the corect way how to do it ?
2) Are some ways how to corectly transform String to number and then compare theese two number s? Like String = "House":1234 is equal to "House":1234 but no to "house":123
Priview:
String token ="123"; False
String token = "ā123"; or other characters True utc.
if(isChars(token)){
Long value = toLong(token);
}
THANKS!
//EDIT
public BigDecimal eval() {
Stack<BigDecimal> stack = new Stack<BigDecimal>();
for (String token : getRPN()) {
if (operators.containsKey(token)) {
BigDecimal v1 = stack.pop();
BigDecimal v2 = stack.pop();
stack.push(operators.get(token).eval(v2, v1));
} else if (variables.containsKey(token)) {
stack.push(variables.get(token).round(mc));
} else if (functions.containsKey(token.toUpperCase())) {
Function f = functions.get(token.toUpperCase());
ArrayList<BigDecimal> p = new ArrayList<BigDecimal>(f.getNumParams());
for (int i = 0; i < f.numParams; i++) {
p.add(0, stack.pop());
}
BigDecimal fResult = f.eval(p);
stack.push(fResult);
} else if (isDate(token)) {
Long date = null;
try {
date = SU.sdf.parse(token).getTime();
} catch (ParseException e) {/* IGNORE! */
}
// mylog.pl("LONG DATE : "+new BigDecimal(date, mc));
stack.push(new BigDecimal(date, mc));
}//TODO HERE
else if (isChar(token)){
Long cha = toLong(token);
stack.push(new BigDecimal(cha, mc));
//TODO ENDS HERE
}
else {
// mylog.pl("Token : "+ token);
stack.push(new BigDecimal(token, mc));
}
}
return stack.pop().stripTrailingZeros();
}

Another way for determing whether string contains any chars is nice class StringUtils from apache-commons-lang library.
It contains several methods for analyzing string's contents. It seems that in your case you can use StringUtils.isAlphanumeric(CharSequence cs) or negation of StringUtils.isNumeric(CharSequence cs)'s result.
What about second part of your question, so I do not see here necessety of extracting numbers from string. You can compare strings "House":1234 and "house":123 using standard String.equals() method.

Long l;
try{
l = Long.parseLong(token);
} catch(NumberFormatException e){
//contains non-numeric character(s)
}
As for "transforming varchar into Long" - that sounds rather impossible, we do not have universally accepted way of doing that, and you did not provide one. However if I guess correctly that what you want is the number within the string disregarding the characters - you want regular expressions. The code you want could look like:
if (!StringUtils.isNumeric(token)){
String stripped = token.replaceAll("\\D","");
Long l = Long.parseLong(stripped);
}

Related

Extracting Operation(...); and sub Operation from String using REGEX

I have an issue with a Regex in java for Android.
i would like to retreive the first operation (and each sub operations) like in the following samples:
"OPERATION(ASYNC_OPERATION,_RFID_ITEM_SERIAL);"
"OPERATION(CONCAT,~1261,01,OPERATION(ASYNC_OPERATION,_RFID_ITEM_ID);,21,OPERATION(ASYNC_OPERATION,_RFID_ITEM_SERIAL););"
As you can see each Operation can have sub Operations... And that's where i'm getting problems.
Actually i am using this Regex: ^\s*(OPERATION\s*\(\s*)(.*)(\);)
but the index of ");" returned is always the last index, and in case of two sub operations, inside of a "Main" operation, this is wrong...
private static Pattern operationPattern=Pattern.compile("^\\s*(OPERATION\\s*\\(\\s*)(.*)(\\);)",Pattern.CASE_INSENSITIVE);
public Operation(String text){
parseOperationText(text);
}
private void parseOperationText(String text){
String strText = text.replace("#,", "§");
Matcher matcher=operationPattern.matcher(strText);
if(matcher.find()) {
//This is an OPERATION
subOperations=new ArrayList<>();
String strChain = matcher.group(2);//Should only contain the text between "OPERATION(" and ");"
int commaIdx = strChain.indexOf(",");
if (commaIdx == -1) {
//Operation without parameter
operationType = strChain;
} else {
//Operation with parameters
operationType = strChain.substring(0, commaIdx);
strChain = strChain.substring(commaIdx + 1);
while (strChain.length()>0) {
matcher = operationPattern.matcher(strChain);
if (matcher.find()) {
String subOpText=matcher.group(0);
strChain=StringUtils.stripStart(strChain.substring(matcher.end())," ");
if(strChain.startsWith(",")){
strChain=strChain.substring(1);
}
subOperations.add(new Operation(subOpText));
}
else{
commaIdx = strChain.indexOf(",");
if(commaIdx==-1)
{
subOperations.add(new Operation(strChain));
strChain="";
}
else{
subOperations.add(new Operation(strChain.substring(0,commaIdx)));
strChain=strChain.substring(commaIdx+1);
}
}
}
}
}
else {
//Not an operation
//...
}
}
It works for sample 1 but for Sample 2, after finding the "Main" operation (CONCAT in the sample), the second match returns this:
OPERATION(ASYNC_OPERATION,_RFID_ITEM_ID);,21,OPERATION(ASYNC_OPERATION,_RFID_ITEM_SERIAL);
What i would like to retrieve is this:
"CONCAT,~1261,01,OPERATION(ASYNC_OPERATION,_RFID_ITEM_ID);,21,OPERATION(ASYNC_OPERATION,_RFID_ITEM_SERIAL);"
"ASYNC_OPERATION,_RFID_ITEM_ID"
"ASYNC_OPERATION,_RFID_ITEM_SERIAL"
Could use this
"(?s)(?=OPERATION\\s*\\()(?:(?=.*?OPERATION\\s*\\((?!.*?\\1)(.*\\)(?!.*\\2).*))(?=.*?\\)(?!.*?\\2)(.*)).)+?.*?(?=\\1)(?:(?!OPERATION\\s*\\().)*(?=\\2$)"
to find the balanced OPERATION( ) string in group 0.
https://regex101.com/r/EsaDtC/1
Then use this
(?s)^OPERATION\((.*?)\)$
on that last matched string to get the inner contents of the
operation, which is in group 1.
Finally i'm using two different REGEX :
//First Regex catches main operation content (Group 2):
\s*(OPERATION\s*\(\s*)(.*)(\);)
//Second Regex catches next full sub "OPERATION(...);" (Group 0):
^(?:\s*(OPERATION\s*\(\s*))(.*)(?:\)\s*\;\s*)(?=\,)|^(?:\s*(OPERATION\s*\(\s*))(.*)(?:\)\s*\;\s*)$
Then i can use Fisst Regex to detect if this is an operation (match.find()), catch it's content in Group(2) and then for each param (separated by comma) i can check if it's a sub operation with second regex. If it's a sub Operation i call recursively the same function that uses First Regex again... and so on.
private static Pattern operationPattern=Pattern.compile("^\\s*(OPERATION\\s*\\(\\s*)(.*)(\\);)",Pattern.CASE_INSENSITIVE);
private static Pattern subOperationPattern=Pattern.compile("^(?:\\s*(OPERATION\\s*\\(\\s*))(.*)(?:\\)\\s*\\;\\s*)(?=\\,)|^(?:\\s*(OPERATION\\s*\\(\\s*))(.*)(?:\\)\\s*\\;\\s*)$",Pattern.CASE_INSENSITIVE);
private void parseOperationText(String strText ){
Matcher matcher=operationPattern.matcher(strText);
if(matcher.find()) {
//This is an OPERATION
subOperations=new ArrayList<>();
String strChain = matcher.group(2);
int commaIdx = strChain.indexOf(",");
if (commaIdx == -1) {
//Operation without parameter
operationType = strChain;
} else {
//Operation with parameters
operationType = strChain.substring(0, commaIdx);
strChain = strChain.substring(commaIdx + 1);
while (strChain.length()>0) {
matcher = subOperationPattern.matcher(strChain);
if (matcher.find()) {
String subOpText=matcher.group(0);
strChain=StringUtils.stripStart(strChain.substring(matcher.end())," ");
if(strChain.startsWith(",")){
strChain=strChain.substring(1);
}
subOperations.add(new Operation(subOpText));
}
else{
commaIdx = strChain.indexOf(",");
if(commaIdx==-1)
{
subOperations.add(new Operation(strChain));
strChain="";
}
else{
subOperations.add(new Operation(strChain.substring(0,commaIdx)));
strChain=strChain.substring(commaIdx+1);
}
}
}
}
}
else {
//Fixed value: we store the value as is
fieldValue = strText;
operationType = OperationType.NONE;
}
}
public Operation(String text){
parseOperationText(text);
}

How do I split a string by specific pairing groups?

I am writing my own JSON parser in Java and I am looking for a way to split a string by a comma or a colon, that are outside [], {} or "" pairs.
I found a tutorial via Google, and it works. The issue is, that it also captures the commas inside those brackets, and I need it to ommit them. I don't know how to edit the regular expression to exclude captured commass from one of these bracket pairs. I tried something like ",(?=([^\"\\{\\[]*\"[^\"\\}\\]]*\")*[^\"]*$)", but it doesn't work. It messes it up even more. The same also applies to the colon separation, which is used in separation of key and value of a JSON object.
Is there a way to combine the "", {} and [] pairs together in the regex in such way that it works? Sorry if I look like a lame, but I really can't figure out how the regex should look like.
BTW, this is a code snippet I want to use it in:
public class JavaJSON {
private HashMap<String, Object> content;
// Constructors
/**
* Create new empty JSON object
*/
public JavaJSON() {
this.content = new HashMap<>();
}
// ...
/**
* Parse a JSON string to a JSON object
*
* #param JSON JSON string to be converted to JSON object
* #return JSON object from given string
*/
public static JavaJSON parse(#NotNull String JSON) {
if (!JSON.startsWith("{") || !JSON.endsWith("}")) return null;
// If this is not a valid JSON string, return nothing.
JavaJSON output = new JavaJSON();
String content = JSON.substring(1, JSON.length() - 1);
if (content.length() == 0) return output; // if empty, return an empty JSON object
// Regex literals
String commaSeparated = ",(?=([^\"]*\"[^\"]*\")*[^\"]*$)"; // TODO: Change commaSeparated to capture any {} [] "" pair group
String colonSeparated = ":(?=([^\"]*\"[^\"]*\")*[^\"]*$)"; // TODO: Change colonSeparated to capture any {} [] "" pair group
String[] tokens = content.split(commaSeparated);
if (tokens.length == 0) return null;
// Don't know exactly if this is going to happen, but better be sure
for (String token : tokens) {
String rawToken = token.trim();
if (rawToken.length() == 0) return null;
// Omitted comma, extra comma, etc. = JSON error
String[] mapToken = rawToken.split(colonSeparated);
if (mapToken.length < 2 || mapToken.length > 2) return null;
// Expected format = {"foo": "bar"}; format isn't valid
String mapKey = mapToken[0].trim();
String mapValue = mapToken[1].trim();
if (!mapKey.startsWith("\"") || !mapKey.endsWith("\"")) return null;
// Key must be a string
String rawMapKey = mapKey.substring(1, mapKey.length() - 1); // get quote-less variant
if (rawMapKey.length() == 0) return null;
// Key must not be empty
// check errors
if (mapValue.startsWith("{") && !mapValue.endsWith("}")) return null;
// Not a valid JSON object
if (mapValue.startsWith("[") && !mapValue.endsWith("]")) return null;
// Not a valid JSON array
if (mapValue.startsWith("\"") && !mapValue.endsWith("\"")) return null;
// Not a valid string
// get value object
Object rawMapValue;
// parse value object
if (mapValue.startsWith("\"") && mapValue.endsWith("\"")) {
rawMapValue = mapValue.substring(1, mapValue.length() - 1);
} else if (mapValue.startsWith("{") && mapValue.endsWith("}")) {
rawMapValue = parse(mapValue);
} else if (mapValue.startsWith("[") && mapValue.endsWith("]")) {
rawMapValue = parseArray(mapValue);
} else {
try {
rawMapValue = Long.parseLong(mapValue);
} catch (Exception e) {
try {
rawMapValue = Double.parseDouble(mapValue);
} catch (Exception f) {
return null;
// Not a valid number
}
}
}
output.update(rawMapKey, rawMapValue);
}
return output;
}
// ...
}

TextView Numbers shown in English in Persian font

I am loading a string which contains some number (all in Persian) into an android TextView. Everything was fine until I changed my custom font, numbers of text shown as English number.
Expected : ۱۲۳۴
Received : 1234
I know that my new font support Persian number. When I change the number locale using code below the number shown correctly.
NumberFormat numberFormat = NumberFormat.getInstance(new Locale("fa", "IR"));
String newNumber = numberFormat.format(number);
The problem is I have a string and it's hard to find the numeric part and change it. also my previous font works fine and I can't understand what's the problem with this font.
Any Idea how to globally solve this problem for all textview, or at least for a string?
Try to use this method:
private String setPersianNumbers(String str) {
return str
.replace("0", "۰")
.replace("1", "۱")
.replace("2", "۲")
.replace("3", "۳")
.replace("4", "۴")
.replace("5", "۵")
.replace("6", "۶")
.replace("7", "۷")
.replace("8", "۸")
.replace("9", "۹");
}
You can use this
String NumberString = String.format("%d", NumberInteger);
123 will become ١٢٣
Use this code for show Hegira date in Persian number:
String farsiDate = "1398/11/3";
farsiDate = farsiDate
.replace('0', '٠')
.replace('1', '١')
.replace('2', '٢')
.replace('3', '٣')
.replace('4', '٤')
.replace('5', '٥')
.replace('6', '٦')
.replace('7', '٧')
.replace('8', '٨')
.replace('9', '٩');
dateText.setText(farsiDate);
You'll have to translate it yourself. TextFormat does not automatically translate from arabic digits to any other language's, because that's actually not what people usually want. Each of those digits have their own character codes, a simple walk of the string and replacing them with the appropriate persian code would be sufficient.
private static String[] persianNumbers = new String[]{ "۰", "۱", "۲", "۳", "۴", "۵", "۶", "۷", "۸", "۹" };
public static String PerisanNumber(String text) {
if (text.length() == 0) {
return "";
}
String out = "";
int length = text.length();
for (int i = 0; i < length; i++) {
char c = text.charAt(i);
if ('0' <= c && c <= '9') {
int number = Integer.parseInt(String.valueOf(c));
out += persianNumbers[number];
} else if (c == '٫') {
out += '،';
} else {
out += c;
}
}
return out;
}}
and after that u can use it like below vlock
TextView textView = findViewById(R.id.text_view);
textView.setText(PersianDigitConverter.PerisanNumber("این یک نمونه است ۱۲ "));
In JS, you can use the function below:
function toPersianDigits(inputValue: any) {
let value = `${inputValue}`;
const charCodeZero = '۰'.charCodeAt(0);
return String(value).replace(/[0-9]/g, w =>
String.fromCharCode(w.charCodeAt(0) + charCodeZero - 48),
);
}
export {toPersianDigits};

Avoiding a particular check for YYYY-MM--dd format in date

I have below method in which different date patterns have been handled
below is the method in which different date formats have been handled now
now for the particulat format YYYY-MM-dd i don't want it to go for the check where we are prefixing 20 before in code please advise how can i skip that part lets say if the date pattern is YYYY-MM-dd then avoid the logic of prefixing 20 in front of year
below is my code
public java.util.Date extractDate(String dateStr, String dateType) {
String[] datePatternsOfUk = { "d-M-yy", "d-M-yyyy", "d/M/yy", "d/M/yyyy", "yyyy-MM-dd","dd-MM-yy", "dd-MMM-yy","dd-MMM-yyyy","dd-MM-yyyy",
"dd/MM/yy","dd/MMM/yy","dd/MMM/yyyy"};
String[] datePatternsOfUs = { "M-d-yy","MM-dd-yy","M/d/yy","MM/dd/yy", "MM/dd/yy", "MMM-dd-yy",
"MMM/dd/yy", "MMM-dd-yyyy", "MM-dd-yyyy", "MMM/dd/yyyy",
"MM/dd/yyyy" };
java.util.Date date = null;
String[] datePatterns = datePatternsOfUk;
if (dateType.equals("US")) {
datePatterns = datePatternsOfUs;
} else if (dateType.equals("UK")) {
datePatterns = datePatternsOfUk;
}
///******code should not go in this check where date pattern is YYYY-MM-dd
int p = dateStr.lastIndexOf("/");
if (p == -1) {
p = dateStr.lastIndexOf("-");
}
String firstSubstring = dateStr.substring(0, p + 1);
String secondSubstring = dateStr.substring(p + 1);
if (p != -1 && secondSubstring.length() <= 2) {
secondSubstring = Integer.toString(2000 + Integer.parseInt(secondSubstring));
dateStr = firstSubstring + secondSubstring;
}
///****************************************//
try {
date = DateUtils.parseDate(dateStr, datePatterns);
} catch (ParseException ex) {
logger.error("##$$$$$### Error in invoice inside extractDate method : ##$$$$$$#### "
+ ErrorUtility.getStackTraceForException(ex));
}
return date;
}
You could avoid trying any inappropriate pattern by checking if the string "looks like" the pattern before parsing with the pattern.
The general way to do this is:
String datePattern = "yyyy-MM-dd"; // for example
String input;
if (input.matches(datePattern.replaceAll("\\w", "\\d"))) {
// the input looks like the pattern
// in this example "dddd-dd-dd" where "d" is any digit
// so go ahead and try the parse
}
You can enhance this logic to add:
if (input.matches("\\d\\d\\D.*")) {
// then it only has a two digit year, so add "20" to the front
}
if (!dateStr.equals("YYYY-MM-dd")) {
// code
}

how to read two consecutive commas from .csv file format as unique value in java

Suppose csv file contains
1,112,,ASIF
Following code eliminates the null value in between two consecutive commas.
Code provided is more than it is required
String p1=null, p2=null;
while ((lineData = Buffreadr.readLine()) != null)
{
row = new Vector(); int i=0;
StringTokenizer st = new StringTokenizer(lineData, ",");
while(st.hasMoreTokens())
{
row.addElement(st.nextElement());
if (row.get(i).toString().startsWith("\"")==true)
{
while(row.get(i).toString().endsWith("\"")==false)
{
p1= row.get(i).toString();
p2= st.nextElement().toString();
row.set(i,p1+", "+p2);
}
String CellValue= row.get(i).toString();
CellValue= CellValue.substring(1, CellValue.length() - 1);
row.set(i,CellValue);
//System.out.println(" Final Cell Value : "+row.get(i).toString());
}
eror=row.get(i).toString();
try
{
eror=eror.replace('\'',' ');
eror=eror.replace('[' , ' ');
eror=eror.replace(']' , ' ');
//System.out.println("Error "+ eror);
row.remove(i);
row.insertElementAt(eror, i);
}
catch (Exception e)
{
System.out.println("Error exception "+ eror);
}
//}
i++;
}
how to read two consecutive commas from .csv file format as unique value in java.
Here is an example of doing this by splitting to String array. Changed lines are marked as comments.
// Start of your code.
row = new Vector(); int i=0;
String[] st = lineData.split(","); // Changed
for (String s : st) { // Changed
row.addElement(s); // Changed
if (row.get(i).toString().startsWith("\"") == true) {
while (row.get(i).toString().endsWith("\"") == false) {
p1 = row.get(i).toString();
p2 = s.toString(); // Changed
row.set(i, p1 + ", " + p2);
}
...// Rest of Code here
}
The StringTokenizer skpis empty tokens. This is their behavious. From the JLS
StringTokenizer is a legacy class that is retained for compatibility reasons although its use is discouraged in new code. It is recommended that anyone seeking this functionality use the split method of String or the java.util.regex package instead.
Just use String.split(",") and you are done.
Just read the whole line into a string then do string.split(",").
The resulting array should have exactly what you are looking for...
If you need to check for "escaped" commas then you will need some regex for the query instead of a simple ",".
while ((lineData = Buffreadr.readLine()) != null) {
String[] row = line.split(",");
// Now process the array however you like, each cell in the csv is one entry in the array

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