hi i'm trying to change my default home page for another one but i couldn't do it, so i try to redirect the page from the default home page to the one i want, but i get this error
No mapping found for HTTP request with URI:
[/myapp/WEB-INF/views/index.html] in DispatcherServlet with name
'appServlet'
this is my setup i left everything by default when i create the project with spring tools suite
this is my servlet-contex.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">
<!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure -->
<!-- Enables the Spring MVC #Controller programming model -->
<annotation-driven />
<!-- Handles HTTP GET requests for /resources/** by efficiently serving up static resources in the ${webappRoot}/resources directory -->
<resources mapping="/resources/**" location="/resources/" />
<!-- Resolves views selected for rendering by #Controllers to .jsp resources in the /WEB-INF/views directory -->
<beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<beans:property name="prefix" value="/WEB-INF/views/" />
<beans:property name="suffix" value="" />
</beans:bean>
<context:component-scan base-package="com.proj.myapp" />
this is my web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<!-- The definition of the Root Spring Container shared by all Servlets and Filters -->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/root-context.xml</param-value>
</context-param>
<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<!-- Processes application requests -->
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
this is my deafult home file
home.jsp
enter code here
<%# taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c" %>
<%# page session="false" %>
<html>
<head>
<title>Home</title>
</head>
<body>
<h1>
Hello world!
<c:redirect url="/indice.html"/>
</h1>
</body>
</html>
and this is the page i want to be redirected
enter code here
<html>
<body>
<h1>
INDICE
</h1>
</body>
</html>
and my contoller
#Controller
public class HomeController {
#RequestMapping(value = "/")
public String home() {
return "home.jsp";
}
#RequestMapping(value = "/indice.html")
public String indice() {
return "indice.html";
}
}
and i get this error
No mapping found for HTTP request with URI:
[/myapp/WEB-INF/views/indice.html] in DispatcherServlet with name
'appServlet'
As from your code suffix property value is blank so you need to pass the type of suffix to this property in in servlet-context.xml.
You have to change it
<beans:property name="suffix" value=".jsp" />
and your indices.html to indices.jsp then it will work.
But if you want to work it with html file but .html files are static and do not require processing by a servlet then it is more efficient, and simpler, to use an mapping. This requires Spring 3.0.4+.
For example:
<mvc:resources mapping="/static/**" location="/static/" />
which would pass through all requests starting with /static/ to the webapp/static/ directory.
So by putting indices.html in webapp/static/ and using return "indices.html"; from your method, Spring should find the view.
Related
the below is my configuration
project directory
the below image is my project structure. Spring Maven project
Servlet-context.xml
i have done resource mapping
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-4.0.xsd">
<!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure -->
<!-- Enables the Spring MVC #Controller programming model -->
<annotation-driven />
<!-- Handles HTTP GET requests for /resources/** by efficiently serving up static resources in the ${webappRoot}/resources directory -->
<resources mapping="/resources/**" location="/resources/" />
<!-- Resolves views selected for rendering by #Controllers to .jsp resources in the /WEB-INF/views directory -->
<beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<beans:property name="prefix" value="/views/" />
<beans:property name="suffix" value=".jsp" />
</beans:bean>
<context:component-scan base-package="com.manjunath.controller" />
</beans:beans>
home.jsp
<%# page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Insert title here</title>
<link href="/resources/css/test.css" rel="stylesheet" type="text/css"/>
</head>
<body>
<h1>Home page:${pageContext.request.contextPath}</h1>
<h2 id="kaka">Hi this is manjunath</h2>
</body>
</html>
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<!-- The definition of the Root Spring Container shared by all Servlets and Filters -->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/root-context.xml</param-value>
</context-param>
<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<!-- Processes application requests -->
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
and there is no error in project and successfully executed
but resource files are not mapping
I guess there is only 1 mistake in your code
In the page you need to give css link like below
<link href="resources/css/test.css" rel="stylesheet" type="text/css"/>
Just remove the / from href.
I know this has been asked, but that didn't solve my problem and have tried many things unsuccessfully:
My spring webapp project directory is pretty standard and looks like:
/webapp/js/* eg. /webapp/js/query.jeditable.js
/webapp/WEB-INF/jsp/*
/webapp/WEB-INF/web.xml+
/webapp/WEB-INF/spring-servlet.xml - dispatcher servlet config
/webapp/WEB-INF/spring-security.xml - spring security config
I am trying to source a javascript file in js from jsp url, which is also filtered through spring security url matcher.
Here is my web.xml:
web.xml
<?xml version="1.0" encoding="ISO-8859-1"?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" version="2.4">
<display-name>Welcome to projectBananaStand</display-name>
<description>
Welcome to 'projectBananaStand' Add Event Test
</description>
<context-param>
<param-name>jmxLogEnabled</param-name>
<param-value>false</param-value>
</context-param>
<servlet>
<servlet-name>spring</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring</servlet-name>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>default</servlet-name>
<url-pattern>/js/*</url-pattern>
</servlet-mapping>
<listener>
<listener-class>com.jpmorgan.tyger.listeners.JMXLog4JContextListener</listener-class>
</listener>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<context-param>
<param-name>registerName</param-name>
<param-value>projectBananaStand</param-value>
</context-param>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/applicationContext.xml
/WEB-INF/spring-security.xml
</param-value>
</context-param>
<!-- Spring Security -->
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy
</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<error-page>
<error-code>500</error-code>
<location>/custError.jsp</location>
</error-page>
<distributable />
</web-app>
This is my jsp code trying to source js file:
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js" type="text/javascript"></script>
<link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css"/>
<script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js"></script>
<!-- DataTables CSS -->
<link rel="stylesheet" type="text/css" href="//cdn.datatables.net/1.10.4/css/jquery.dataTables.css">
<!-- DataTables -->
<script type="text/javascript" charset="utf8" src="//cdn.datatables.net/1.10.4/js/jquery.dataTables.js"></script>
<!-- editable datatables -->
<script src="/js/jquery.jeditable.js" type="text/javascript"></script>
<script src="/js/jquery.dataTables.editable.js" type="text/javascript"></script>
<script src="/js/addEvent.js" type="text/javascript"></script>
<script src="http://cdn.jsdelivr.net/jquery.validation/1.13.1/jquery.validate.js" type="text/javascript"></script>
Here is spring-servlet.xml
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:util="http://www.springframework.org/schema/util"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util-3.2.xsd
http://www.springframework.org/schema/aop
http://www.springframework.org/schema/aop/spring-aop-3.0.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-3.0.xsd">
<context:annotation-config />
<!-- declaring base package -->
<context:component-scan base-package="com.banana.controller" />
<mvc:annotation-driven/>
<!-- adding view resolver to show jsp's on browser -->
<bean id="viewResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/jsp/</value></property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
<bean class="org.springframework.context.support.ResourceBundleMessageSource"
id="messageSource">
<property name="basename" value="messages" />
</bean>
</beans>
All app level beans and spring security related configuration has been defined in applicationContext.xml and added via contextListener
I cannot use
<mvc:resources mapping="/js/**" location="/js/" />
as I am using Spring 3.0.3 and don't want to upgrade whole framework.
I tried using just the xmlns definition for spring mvc 3.1 and that still caused the error - mvc:resource declaration not found.
I tried mapping a default servlet with url patterns
*.js, /js/**, and /somethingelse/*
and they broke the spring security default login page loading. Resource not found error for the spring security login page.
Tried different tags inside the jsp file including
source="<c:url value="something" />"
Please help, how can I include the javascript files in jsp without mvc:resource mappingor use mvc:resource mapping without changing all spring framework version and just using different
xmlns schemaLocationand not bring spring security with default servlet
Is there a way to include the files without treating them as urls? What am I doing wrong?
Help would be greatly appreciated as I have spent much time battling this.
Thanks
Keep your js folder into /WEB-INF/jsp/ folder it may be work i did not tried.
I've created a basic Spring MVC web app with Maven. However, I've been struggling with getting constant 404 errors when I'm accessing the /login URL.
The /login URL should be mapped to the AuthController servlet and the createLoginForm() method, but unfortunately it fails and I'm ending up with a 404 error.
I'm trying to figure out what is issue that is causing 404 errors and why the /login URL cannot be mapped to the servlet.
Is the problem located in bad configuration of the web.xml or spring-dispatcher-servlet.xml files that prevent the URL to be mapped?
When I'm accessing the / URL, then the index.jsp file is mapped and it's is working fine
The login.jsp file is put outside the WEB-INF directory, in the webapp one as well as the index.jsp file.
Thanks in advance.AuthController.java
package com.github.wjoz.springmvcreview.auth;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;
#Controller
public class AuthController {
#RequestMapping(value="/login", method=RequestMethod.GET)
public ModelAndView createLoginForm() {
ModelAndView model = new ModelAndView("login");
return model;
}
}
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web- app_3_0.xsd" id="WebApp_ID" version="3.0">
<display-name>springmvcreview</display-name>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>spring-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet
</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>spring-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
spring-dispatcher-servlet.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc.xsd">
<mvc:default-servlet-handler/>
<context:component-scan base-package="main.java.com.github.wjoz.springmvcreview.auth" />
<mvc:annotation-driven />
<!-- Tells the location of the view in the project -->
<bean id="viewResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver" >
<property name="prefix">
<value>/WEB-INF/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
</beans>
login.jsp
<%# page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<!DOCTYPE>
<html>
<head>
<title>Welcome to our application. Sign in.</title>
</head>
<body>
<form action="/springmvcreview/login" method="post">
<div>
<label for="username">Username</label>
<input type="text" name="username" id="username">
<label for="password">Password</label>
<input type="password" name="password" id="password">
<button type="submit">Sign in</button>
</div>
</form>
</body>
</html>
This is in addition to Shazin's answer
First, put your JSP files inside WEB-INF. There is no reason to have them outside of it, since you're deliberately breaking your view rendering functionality.
Second,
<servlet-mapping>
<servlet-name>spring-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
means that the URL www.somedomain.com/ will load the index page, and all other URLs will start with that. However, your form
<form action="/springmvcreview/login" method="post">
is hitting the URL www.somedomain.com/springmvcreview/login. This does not match up with the controller URL mapping
#RequestMapping(value="/login", method=RequestMethod.GET)
public ModelAndView createLoginForm() {
does not contain a mapping for the form action. So either remove /springmvcreview from the form action, or modify #RequstMapping value to /springmvcreview/login
You don't have the contextConfigLocation for your DispatcherServlet. You need that to tell context:component-scan to scan the com.github.wjoz.springmvcreview.auth package and load the AuthController.
<servlet>
<servlet-name>spring-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value><PATH_TO>/spring-dispatcher-servlet.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
I saw one more issue. You don't need the main.java part in the following;
<context:component-scan base-package="com.github.wjoz.springmvcreview.auth" />
The css and javascript is not work on my page.
My home.jsp
<%#page pageEncoding="UTF-8"%>
<!DOCTYPE html>
<html lang="ru">
<jsp:include page="/WEB-INF/views/fragments/headTag.jsp"/>
<body>
<h2>Welcome!</h2>
</body></html>
The headTag.jsp
<%# taglib prefix="s" uri="http://www.springframework.org/tags" %>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8"/>
<s:url value="/resources/css/test.css" var="testCss"/>
<link href="${testCss}" rel="stylesheet"/>
</head>
The web.xml
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<!-- The definition of the Root Spring Container shared by all Servlets and Filters -->
<!-- <context-param>
<param-name>spring.profiles.active</param-name>
<param-value>jdbc</param-value>
</context-param> -->
<context-param>
<param-name>spring.profiles.active</param-name>
<param-value>hibernate</param-value>
</context-param>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:spring/business-config.xml</param-value>
</context-param>
<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<!-- Processes application requests -->
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:spring/appServlet/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
and my app servlet-comntext.xml
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">
<!-- <Enable #Controller> -->
<mvc:annotation-driven />
<context:component-scan base-package="com.a72.coursapp.controller" />
<!-- resources mapping -->
<mvc:resources location="/resources/**" mapping="/resources/"/>
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/views/"/>
<property name="suffix" value=".jsp"/>
</bean>
</beans>
The test.css
h2 {
color:red;
}
css location: src/main/webapp/resources/css/test.css
folder structure
-src
--main
---webapp
----resources
-----css
------test.css
-----js
-----fonts
----WEB-INF
-----views
------fragments
-------headTag.jsp
------home.jsp
What's wrong? Thanks in advance!
If look to source code page in firefox, page has test.ccs style, but it has this log:
Pivotal tc Runtime 3.0.0.RELEASE/8.0.9.B.RELEASE - Error report
HTTP Status 400 - description
The request sent by the client was syntactically incorrect.
Pivotal tc Runtime 3.0.0.RELEASE/8.0.9.B.RELEASE
I would have thought that your problem is the line:
<jsp:include page="/WEB-INF/views/fragments/headTag.jsp"/>
Don't think you can include anything behind WEB-INF with jsp:include.
It would anyway be rather unorthodox to call a view directly, they should be called by controllers.
Presumably if you are using spring you have a controller which calls that view? If so, then call the uri provided by the controller.
Otherwise I guess you need to move the jsp to a position that is not hiding behind WEB-INF.
Try this move your CSS and JS folder under WEB-INF
eg. if you are keeping your files like..
WEB-INF/resources/css/test.css
then change path in servlet-comntext.xml
<!-- resources mapping -->
<mvc:resources location="/WEB-INF/resources/" mapping="/resources/"/>
change in headTag.jsp page
<link rel="stylesheet" href="${pageContext.request.contextPath}/resources/css/test.css" />
<script type="text/javascript" src="${pageContext.request.contextPath}/resources/js/test.js"></script>
Probably, you problem is base path. Try out:
<%# taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core" %>
<link rel="stylesheet" href="<c:url value="/resources/css/test.css" />" />
I am working on a spring MVC project in which I am trying to use css style sheets by referencing it to design my JSP page. But somehow my css files are not being picked up once I hit my method in the controller..
Below is my JSP file -
<html>
<head>
<link rel="stylesheet" type="text/css" href="test.css" />
</head>
<body>
<h1>All header 1 elements will be red</h1>
<h2>All header 2 elements will be blue</h2>
<p>All text in paragraphs will be green.</p>
</body>
</html>
And below is my test.css file -
h1 {color:red;}
h2 {color:blue;}
p {color:green;}
And below is my method in controller class -
#RequestMapping(value = "testing", method = RequestMethod.GET)
public Map<String, String> testing() {
final Map<String, String> model = new LinkedHashMap<String, String>();
return model;
}
Directory structure is like this -
webapp/
|-- resources/
| +-- css/
| test.css
+- WEB-INF/
+-- views/
testing.jsp
But somehow it's not working for me.. Is there anything wrong I am doing here?
UPDATE:-
Here is my web.xml file-
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
<display-name>testweb</display-name>
<listener>
<listener-class>com.host.webres.resource.env.EbayResourceRuntimeListener</listener-class>
</listener>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
<welcome-file>index</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/testweb/*</url-pattern>
</servlet-mapping>
</web-app>
And below is my context.xml file -
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:task="http://www.springframework.org/schema/task"
xsi:schemaLocation="
http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.1.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.1.xsd
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.1.xsd
http://www.springframework.org/schema/task http://www.springframework.org/schema/task/spring-task-3.1.xsd">
<!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure -->
<!-- Allow proxys -->
<aop:aspectj-autoproxy />
<!-- Enables the Spring MVC #Controller programming model -->
<mvc:annotation-driven>
<mvc:message-converters>
<!-- Support AJAX processing with progressive rendering. Overrides HttpOutputMessage with RaptorResponseWriter -->
<beans:bean class="com.host.terr.kernel.filter.RaptorJacksonHttpMessageConverter"/>
</mvc:message-converters>
</mvc:annotation-driven>
<context:component-scan base-package="com.host.terr.config" />
<context:component-scan base-package="com.host.personalization.bullseye.zookeeper.p13nzook.controller" />
<!-- Handles HTTP GET requests by efficiently serving up static resources
in the corresponding directory -->
<resources mapping="/js/**" location="/js/" />
<resources mapping="/css/**" location="/css/" />
<!-- Resolves views selected for rendering by #Controllers to .jsp resources in the /WEB-INF/views directory -->
<beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<beans:property name="prefix" value="/WEB-INF/views/" />
<beans:property name="suffix" value=".jsp" />
</beans:bean>
</beans:beans>
This is exception I am getting on my console but browser shows the data without any css -
404 /testweb/test.css Not Found /testweb/test.css Not Found }, Correlations : {} }
In your servlet-context.xml file,you have setting about your directory of resources.In your case,with changing
<resources mapping="/resources/**" location="/resources/"/>
and in your jsp page like below,
<link rel="stylesheet" type="text/css" href="
<c:url value="/resources/css/test.css"/> "/>
I hope it will work
You need to provide the context path.
<link rel="stylesheet" href="${pageContext.request.contextPath}/resources/css/test.css" />
What does this expression language ${pageContext.request.contextPath} exactly do in JSP EL?
You need to set <base/> as following...
<c:set var="req" value="${pageContext.request}" />
<c:set var="url"> ${req.requestURL} </c:set>
<c:set var="uri" value="${req.requestURI}" />
<head>
<title></title>
<base href="${fn:substring(url, 0, fn:length(url) - fn:length(uri))}${req.contextPath}/" />
Then You can Import any JS or CSS like below..
<script src="assets/js/angular/angular.js"></script>
Maybe by adding your .css file in a specific folder inside the WEB-Content then, you could use the attribute href = "yourFolder/yourFile.css
Indeed all "web" ressources like the view should be there (i.e. jsp, css.).
You can also precise that your link (in the .jsp file) is a stylesheet one by adding: rel="stylesheet"
you will have a link looking like this :
this css resource issue
please try below
<link rel="stylesheet" type="text/css" href="css/test.css" />
and you can see this resource if be load by bowaser.