I have an Android app that parses a RSS feed. The "date" item returns the date in this format: "Mon, 16 Jun 2014 14:31:00 +0000". How can I convert this to the default device format?
Use simpleDateFormat
Something like:
SimpleDateFormat sdf = new SimpleDateFormat("E, dd MMM yyyy hh:mm:ss Z")
First parse this to a Date object
String str = "Mon, 16 Jun 2014 14:31:00 +0000";
Date date = new SimpleDateFormat("E, d, M yyyy H:m:s Z", Locale.ENGLISH).parse(str);
Related
I've been struggling a strange question.
I'm trying to parse a date format looks like this
"Thu, 18 Aug 2016 16:25:25 GMT"
to only Month and date like this
"08/18"
well I use two SimpleDateFormat, to parse and format the input and output
DateFormat inputFormat = new SimpleDateFormat("EEE, dd MMM yyyy HH:mm:ss z");
DateFormat outputFormat = new SimpleDateFormat("MM/dd");
however, everything seems to be correct when using genymotion emulator
but when it comes to the real phone, say sony Xperia Care
the following questions kept on comming
java.text.ParseException: Unparseable date: "Wed, 10 Aug 2016 15:40:57 GMT" (at offset 0)
so whats the reason that this happens?
Try to use
new SimpleDateFormat("EE MMM dd HH:mm:ss z yyyy",Locale.ENGLISH);
Your String-DAte has information that is related to an specific language, therefor you need to prepare the SimpleDAteFormat for such an information.
ERGO: you need to give a Locale
Example:
public static void main(String[] args) throws ParseException {
String dateStr = "Thu, 18 Aug 2016 16:25:25 GMT";
DateFormat inputFormat = new SimpleDateFormat("EEE, dd MMM yyyy HH:mm:ss z", Locale.ENGLISH);
Date d = null;
d = inputFormat.parse(dateStr);
DateFormat outputFormat = new SimpleDateFormat("MM/dd");
System.out.println("After format: " + outputFormat.format(d));
}
This is due to different jdk versions on android.
String string = "Tue Oct 16 00:00:55 IST 2012";
Date date = new SimpleDateFormat("EEE MMM dd HH:mm:ss z yyyy").parse(string);
and also tried
String string = "Tue Oct 16 00:00:55 IST 2012";
Date date = new SimpleDateFormat("EEE MMM dd HH:mm:ss 'UTC' yyyy").parse(string);
adding Locale in SimpleDateFormat constructor has no effect.
I have searched and got this but can't find any workaround.
Is there any workaround for this?
In my project ,I get json data from Server,there's a field named 'creat_at' in the json which style is like 'Wed Jun 20 11:01:05 +0800 2012'
How to change it to more easy-to-read style like '2012/06/20'?
(I have tried 'DateFormat.parse' but it dose not work:
new SimpleDateFormat("EEE MMM dd HH:mm:ss Z yyyy").parse(dateString)
cause
java.text.ParseException: Unparseable date: "Wed Jun 20 11:00:53 +0800 2012")
See SimpleDateFormat API
Date date = new SimpleDateFormat("EEE MMM dd HH:mm:ss Z yyyy").parse(dateString);
String formattedDate = new SimpleDateFormat("yyyy/MM/dd").format(date);
You need to try SimpleDateFormat
SimpleDateFormat sdf = new SimpleDateFormat("EEE MMM dd HH:mm:ss Z yyyy");
SimpleDateFormat sdf2 = new SimpleDateFormat("yyyy/MM/dd");
System.out.println(sdf2.format(sdf.parse("Wed Jun 20 11:01:05 +0800 2012")));
prints
2012/06/20
You may also need to set an approriate timezone.
am having a string like this.
Thu Oct 07 11:31:50 IST 2010
I want to convert this into its exact date time format to store it in SQL.
Am familiar with so many string to date conversions like the following.
String dateString = "2001/03/09";
SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy/mm/dd");
Date convertedDate = dateFormat.parse(dateString);
But i need to convert a string like Thu Oct 07 11:31:50 IST 2010
into its Date format with timestamp.
Can anyone explain the proper way of converting this into its java.util.Date format.?
Try this:
SimpleDateFormat dateFormat = new SimpleDateFormat("EEE MMM dd HH:mm:ss z yyyy");
For future reference read up on the SimpleDateFormat class:
http://docs.oracle.com/javase/7/docs/api/java/text/SimpleDateFormat.html
Use this format -'EEE MMM dd HH:mm:ss z yyyy'
Date date = new SimpleDateFormat("EEE MMM dd HH:mm:ss z yyyy")
.parse("Thu Oct 07 11:31:50 IST 2010");
System.out.println(date);
Can't you do like below
String str = "Thu Oct 07 11:31:50 IST 2010";
SimpleDateFormat sdf = new SimpleDateFormat("E MMM dd hh:mm:ss 'IST' yyyy");
SimpleDateFormat sdf2 = new SimpleDateFormat("yyyy/MM/dd");
System.out.println(sdf2.format(sdf.parse(str)));
How can I parse a pubDate from a RSS feed to a Date object in java.
The format in the RSS feed:
Sat, 24 Apr 2010 14:01:00 GMT
What I have at the moment:
DateFormat dateFormat = DateFormat.getInstance();
Date pubDate = dateFormat.parse(item.getPubDate().getText());
But this code throws an ParseException with the message Unparseable date
You can define the date format you are trying to parse, using the class SimpleDateFormat:
DateFormat formatter = new SimpleDateFormat("EEE, dd MMM yyyy HH:mm:ss zzz");
Date date = formatter.parse("Sat, 24 Apr 2010 14:01:00 GMT");
Additionally, for non-English Locale's, be sure to use the following when parsing dates in English:
new SimpleDateFormat("EEE, dd MMM yyyy HH:mm:ss zzz", Locale.ENGLISH);
If you need to have an RFC822 compliant date, try this :
DateFormat dateFormatterRssPubDate = new SimpleDateFormat("EEE, dd MMM yyyy HH:mm:ss Z", Locale.ENGLISH);
For the lucky one that can use the Java 8 LocalDateTime:
LocalDateTime localDateTime = LocalDateTime.from(DateTimeFormatter.RFC_1123_DATE_TIME.parse("Sat, 24 Apr 2010 14:01:00 GMT"));