I'm creating a server to receive both text and binary data from clients. It works with text data as well as the first time receiving binary file, but after this it didn't continue to reading data and throw an exception.
Here is my server code:
public class ConnectedProcessThread implements Runnable{
private final Socket socket;
public ConnectedProcessThread(Socket clientSocket){
socket = clientSocket;
}
public void run(){
DataInputStream dis = null;
try{
while(true) {
dis = new DataInputStream(socket.getInputStream());
String meta = dis.readUTF();
Log.i("Data received", meta);
if(meta.equalsIgnoreCase("Text")){
String message = dis.readUTF();
Log.i("Data received", message);
}else if(meta.equalsIgnoreCase("Binary")){
InputStream is = socket.getInputStream();
ByteArrayOutputStream stream = new ByteArrayOutputStream();
byte[] buf = new byte[4096];
int len;
while((len=is.read(buf))>-1){
stream.write(buf,0,len);
}
stream.flush();
//read object input
try {
ObjectInputStream ois = new ObjectInputStream(new ByteArrayInputStream(stream.toByteArray()));
byte[] buffer = (byte[])ois.readObject();
FileOutputStream fos = new FileOutputStream("/storage/emulated/0/DCIM/IMG-Saved.jpeg");
fos.write(buffer);
}catch (ClassNotFoundException e){
e.printStackTrace();
}
finally {
Log.i("Binary_Transfer","File created");
}
}
}
} catch (IOException e){
e.printStackTrace();
}finally {
Log.i("Client_Socket","Stream will close");
if(dis!=null){
try {
dis.close();
}catch (IOException e){
e.printStackTrace();
}
}
}
}
}
For both text and binary data, before sending the data, client will sent text meta-data to inform the server the data is text or binary. But after receiving a file(image), it throws an EOFException at line: String meta = dis.readUTF(); I guessed it happened because after reading and writing binary file, the thread continues to loop so DataInputStream will read again, and now there's nothing to receive so readUTF() throws EOFException. I tried to send a meta-data from client after sending the binary file to let DataInputStream can read something and not throw an exception, but it didn't work, the client did send the meta-data but the server still throws EOFException. Anyone knows what the problem is? Thanks so much.
Here is my send binary method from client:
public void sendBinaryData(byte[] binaryData){
if(dos!=null && socket!=null){
try {
ObjectOutputStream oos = new ObjectOutputStream(socket.getOutputStream());
oos.writeObject(binaryData);
Log.d("Binary_Transfer", "C: Sent.");
oos.close();
dos.writeUTF("Binary_End");
dos.flush();
}catch (Exception e){
Log.e("File_Exception",e.toString());
}
}
}
Because when you start reading the binary data, you enter a loop that only terminates at end of stream, i.e. when the peer disconnects:
while((len=is.read(buf))>-1){
stream.write(buf,0,len);
}
At that point you are at the end of the stream. There was no more data, there is no more data, and there never will be any more data.
You need to completely remove this part:
InputStream is = socket.getInputStream();
ByteArrayOutputStream stream = new ByteArrayOutputStream();
byte[] buf = new byte[4096];
int len;
while((len=is.read(buf))>-1){
stream.write(buf,0,len);
}
stream.flush();
There is rarely any point in reading things into ByteArrayOutputStreams anyway, and this is no exception. Just remove that completely, and change the next part:
ObjectInputStream ois = new ObjectInputStream(new ByteArrayInputStream(stream.toByteArray()));
to
ObjectInputStream ois = new ObjectInputStream(socket.getInputStream());
and continue as you are already. However you have another problem:
oos.close();
This closes the socket. So the next part:
dos.writeUTF("Binary_End");
dos.flush();
cannot possibly work. Just flush the ObjectOutputStream instead of closing it.
But I would strongly suggest you discard the DataInput/OutputStreams and use a single ObjectInput/OutputStream for the life of the socket, at both ends.
Related
I'm writing a program to download/upload a file between a client and server using socket programming. The code i've written till now works in the sense that i can sucesfully transfer files. However , if a connection fails due to problem in the network/client/server while a download / upload is occuring.. i need to RESUME the download/upload from the original point(Do not want the originally sent data to be resent). I'm not sure how to go about this. I'm reading the file into a byte array and sending it across the network. My initial idea is that everytime i'm downloading.. i should check if the file already exists and read the data into a byte array --> send the data to the server for comparison and then return the remaining data from the server file by comparing the two byte arrays. But this seems inefficient and takes away the point of resuming a download(since i'm sending the data again).
Note: The file name is an unique identifier.
I would really appreciate it if anybody could give me suggestions as to how i should implement the file resume functionality?
Server side code:
package servers;
import java.io.*;
import java.net.*;
import java.util.Arrays;
public class tcpserver1 extends Thread
{
public static void main(String args[]) throws Exception
{
ServerSocket welcomeSocket = null;
try
{
welcomeSocket = new ServerSocket(5555);
while(true)
{
Socket socketConnection = welcomeSocket.accept();
System.out.println("Server passing off to thread");
tcprunnable tcprunthread = new tcprunnable(socketConnection);
Thread thrd = new Thread(tcprunthread);
thrd.start();
System.out.println(thrd.getName());
}
}
catch(IOException e){
welcomeSocket.close();
System.out.println("Could not connect...");
}
}
}
class tcprunnable implements Runnable
{
Socket socke;
public tcprunnable(Socket sc){
socke = sc;
}
public void download_server(String file_name)
{
System.out.println("Inside server download method");
try
{
System.out.println("Socket port:" + socke.getPort());
//System.out.println("Inside download method of thread:clientsentence is:"+clientSentence);
// Create & attach output stream to new socket
OutputStream outToClient = socke.getOutputStream();
// The file name needs to come from the client which will be put in here below
File myfile = new File("D:\\ "+file_name);
byte[] mybytearray = new byte[(int) myfile.length()];
BufferedInputStream bis = new BufferedInputStream(new FileInputStream(myfile));
bis.read(mybytearray, 0, mybytearray.length);
outToClient.write(mybytearray, 0, mybytearray.length);
System.out.println("Arrays on server:"+Arrays.toString(mybytearray));
outToClient.flush();
bis.close();
}
catch(FileNotFoundException f){f.printStackTrace();}
catch(IOException ie){
ie.printStackTrace();
}
}
public void upload_server(String file_name){
try{
byte[] mybytearray = new byte[1024];
InputStream is = socke.getInputStream();
ByteArrayOutputStream baos = new ByteArrayOutputStream();
FileOutputStream fos = new FileOutputStream("D:\\ "+file_name);
BufferedOutputStream bos = new BufferedOutputStream(fos);
int bytesRead = is.read(mybytearray, 0, mybytearray.length);
bos.write(mybytearray, 0, bytesRead);
do {
baos.write(mybytearray);
bytesRead = is.read(mybytearray);
}
while (bytesRead != -1);
bos.write(baos.toByteArray());
System.out.println("Array on server while downloading:"+Arrays.toString(baos.toByteArray()));
bos.close();
}
catch(FileNotFoundException fe){fe.printStackTrace();}
catch(IOException ie){ie.printStackTrace();}
}
#Override
public void run()
{
try
{
System.out.println("Server1 up and running" + socke.getPort());
// Create & attach input stream to new socket
BufferedReader inFromClient = new BufferedReader
(new InputStreamReader(socke.getInputStream()));
// Read from socket
String clientSentence = inFromClient.readLine();
String file_name = inFromClient.readLine();
System.out.println("Sever side filename:" + file_name);
try{
if(clientSentence.equals("download"))
{
download_server(file_name);
}
else if(clientSentence.equals("upload"))
{
upload_server(file_name);
System.out.println("Sever side filename:" + file_name);
}
else
{
System.out.println("Invalid input");
}
}
catch(NullPointerException npe){
System.out.println("Invalid input!");
}
socke.close();
}
catch(IOException e)
{
e.printStackTrace();
System.out.println("Exception caught");
}
}
}
Client side code:
package clients;
import java.io.*;
import java.net.*;
import java.util.Arrays;
public class tcpclient1
{
public static void main (String args[]) throws Exception
{
// Create input stream to send sentence to server
BufferedReader inFromUser = new BufferedReader(new InputStreamReader(System.in));
Socket clientSocket = null;
while(true){
System.out.println("Please enter the server you want to use");
System.out.println("Enter 1 for Server 1 and 2 for Server2");
String server_choice = inFromUser.readLine();
if(server_choice.equals("1")){
// Create client socket to connect to server
// The server to use will be specified by the user
clientSocket = new Socket("localhost",5555);
break;
}
else if(server_choice.equals("2"))
{
clientSocket = new Socket("localhost",5556);
break;
}
else
{
System.out.println("Invalid entry");
}
}
System.out.println("Please enter download for dowloading");
System.out.println("Please enter upload for uploading");
// sentence is what'll be received from input jsp
String sentence = inFromUser.readLine();
if(sentence.equals("download"))
{
download_client(clientSocket,sentence);
}
else if(sentence.equals("upload"))
{
upload_client(clientSocket,sentence);
}
else
{
System.out.println("Invalid input");
}
clientSocket.close();
}
public static void download_client(Socket clientSocket , String sentence)
{
try{
// Create output stream attached to socket
DataOutputStream outToServer = new DataOutputStream(clientSocket.getOutputStream());
// Send line to server
outToServer.writeBytes(sentence+'\n');
BufferedReader inFromUser = new BufferedReader(new InputStreamReader(System.in));
System.out.println("Enter the name of file to download:");
String file_to_download = inFromUser.readLine();
if(searching(file_to_download))
{
// Read local file and send that to the server for comparison
// DONT THINK THIS IS THE RIGHT WAY TO GO ABOUT THINGS SINCE IT BEATS THE PURPOSE OF RESUMING A DOWNLOAD/UPLOAD
}
// Send filetodownload to server
outToServer.writeBytes(file_to_download+'\n');
byte[] mybytearray = new byte[1024];
InputStream is = clientSocket.getInputStream();
ByteArrayOutputStream baos = new ByteArrayOutputStream();
FileOutputStream fos = new FileOutputStream("E:\\ "+file_to_download);
BufferedOutputStream bos = new BufferedOutputStream(fos);
int bytesRead = is.read(mybytearray, 0, mybytearray.length);
bos.write(mybytearray, 0, bytesRead);
do {
baos.write(mybytearray);
bytesRead = is.read(mybytearray);
}
while (bytesRead != -1);
bos.write(baos.toByteArray());
System.out.println("Array on client while downloading:"+Arrays.toString(baos.toByteArray()));
bos.close();
}
catch(FileNotFoundException fe){fe.printStackTrace();}
catch(IOException ie){ie.printStackTrace();}
}
public static void upload_client(Socket clientSocket, String sentence)
{
try{
// Create output stream attached to socket
DataOutputStream outToServer1 = new DataOutputStream(clientSocket.getOutputStream());
// Send line to server
outToServer1.writeBytes(sentence+'\n');
System.out.println("In the client upload method");
BufferedReader inFromUser = new BufferedReader(new InputStreamReader(System.in));
System.out.println("Enter the name of file to upload:");
String file_to_upload = inFromUser.readLine();
//System.out.println("Cline side file name:"+file_to_upload);
outToServer1.writeBytes(file_to_upload+'\n');
System.out.println(file_to_upload);
OutputStream outtoserver = clientSocket.getOutputStream();
File myfile = new File("E:\\ "+file_to_upload);
byte[] mybytearray = new byte[(int) myfile.length()];
BufferedInputStream bis = new BufferedInputStream(new FileInputStream(myfile));
bis.read(mybytearray, 0, mybytearray.length);
outtoserver.write(mybytearray, 0, mybytearray.length);
System.out.println("filename:"+file_to_upload+"Arrays on client while uploading:"+Arrays.toString(mybytearray));
outtoserver.flush();
bis.close();
}
catch(FileNotFoundException fe){fe.printStackTrace();}
catch(IOException ie){ie.printStackTrace();}
}
public static boolean searching(String file_name)
{
String file_path = "E:\\ "+file_name;
File f = new File(file_path);
if(f.exists() && !f.isDirectory()) { return true; }
else
return false;
}
}
The above code runs fine for transferring files between the client and server.
Again , would really appreciate any help!
There are many ways which you can do this, I suggest you to create a separate type of request to the server that accepts the file's name and file position which is the position where in the file where the connection failed.
That's how you will get the file from the server in the client's side:
int filePosition = 0;
InputStream is = clientSocket.getInputStream();
ByteArrayOutputStream baos = new ByteArrayOutputStream();
do {
baos.write(mybytearray);
bytesRead = is.read(mybytearray);
if(bytesRead != -1)
filePosition += bytesRead;
}
while (bytesRead != -1);
Now if the connection got interrupted for some reason you can send a request again to the server with the same file name and the filePosition, and the server will send the file back like this:
OutputStream outToClient = socke.getOutputStream();
// The file name needs to come from the client which will be put in here below
File myfile = new File("D:\\ "+file_name);
byte[] mybytearray = new byte[(int) myfile.length()];
BufferedInputStream bis = new BufferedInputStream(new FileInputStream(myfile));
bis.skip(filePosition) //Advance the stream to the desired location in the file
bis.read(mybytearray, 0, mybytearray.length);
outToClient.write(mybytearray, 0, mybytearray.length);
System.out.println("Arrays on server:"+Arrays.toString(mybytearray));
outToClient.flush();
bis.close();
And in the client you can open the file stream and specify append = true in the constructor like this:
FileOutputStream fos = new FileOutputStream("D:\\ "+file_name, true);
This could be one way to do this, there are a lot more options. And I also suggest verify the files after the transfer using some hash function like MD5 for example, it creates unique stamp for a given input and it always outputs same result for the same input, which means, you can create the stamp from the same file both in the server and in the client and if the file is truly the same, it will generate the same stamp. Since the stamp's size is very small relative to the file it self and it is also fixed, it can be send between the client/server without much overhead.
You can generate an MD5 hash with this code:
MessageDigest md = MessageDigest.getInstance("MD5");
try (InputStream is = Files.newInputStream(Paths.get("file.txt"))) {
DigestInputStream dis = new DigestInputStream(is, md);
/* Read stream to EOF as normal... */
}
byte[] digest = md.digest();
(taken from: Getting a File's MD5 Checksum in Java)
Basically, when requesting a download You should attach information about how many bytes need to be skipped (0 on new download). You should get this information from part of the file that you have downloaded (read it's size). Server should skip given count of bytes and send back the remainder of file. Client should append this to the existing file. For sanity check, You could add some file hash checking in the end, to ensure You got the file correctly.
I have implemented a client/server to send files . When there is no more messages exchanged after sending the file , the code works perfectly , but if the client sends some string to the server directly after the code of receiving the file both client and server stop doing anything and the file is not sent it's something like if they both get stuck in deadlock but I'm not really sure :
Here is the code to send the file without sending anything after it , which works:
Client
String filename;
BufferedReader UIn = new BufferedReader(new InputStreamReader(System.in));
Socket peer = new Socket("localhost",9999);
System.out.print("Enter the file name to download :");
filename= UIn.readLine();
///////////////////////////////
DataOutputStream OutToServer;
OutToServer = new DataOutputStream(peer.getOutputStream());
OutToServer.writeBytes(filename+"\n");
FileOutputStream fos = new FileOutputStream(new File("D:/new.txt"));
BufferedOutputStream out = new BufferedOutputStream(fos);
InputStream in = peer.getInputStream();
buffer = new byte[1024];
while((count=in.read(buffer))>0)
{
fos.write(buffer, 0, count);
System.out.println(buffer);
}
fos.close();
System.out.println("done");
Server:
ServerSocket server =null;
try {
server = new ServerSocket(9999);
while(true)
{
client= server.accept();
//System.out.println("Connection accepted");
BufferedReader inFromClient = new BufferedReader(new InputStreamReader(client.getInputStream()));
DataOutputStream outToclient =new DataOutputStream(client.getOutputStream());
String request=inFromClient.readLine();
file = new File(request);
if (file.exists())
{
OutputStream out = client.getOutputStream();
BufferedInputStream in = new BufferedInputStream(new FileInputStream(file));
while((count =in.read(buffer)) >0)
{
out.write(buffer,0,count);
out.flush();
}
}
// System.out.println(request);
// outToclient.writeBytes("alaa\n");
}
} catch (IOException ex) {
Logger.getLogger(ServerWork.class.getName()).log(Level.SEVERE, null, ex);
}
But if I try to send anything after the loop between client and server it stops working . Is it because I'm using readLine() and writeBytes()?
You are using both DataOutputStream and OutputStream. I think that they
should work together but what I guess you should do is to flush the buffer (or close it).
After you're done writing everything you want to send, some data may still be in the buffer. Now you will have to flush the buffer, to force it to send all the data.(as it is said here).
outToclient.writeBytes("alaa\n");
outToclient.flush();
Iam sending a image from my android to pc ,its part of my app, Iam using sockets for this The sending part code includes
public void sendfile()
{
try {
System.out.println("looppppppp");
File file = new File(Environment.getExternalStorageDirectory()+ File.separator + "test.jpg");
byte [] mybytearray = new byte [(int)file.length()];
FileInputStream fis = new FileInputStream(file);
BufferedInputStream bis = new BufferedInputStream(fis);
bis.read(mybytearray,0,mybytearray.length);
System.out.println("Send:"+mybytearray.length);
bis.close();
OutputStream ous = socket.getOutputStream();
System.out.println("Sending...");
ous.write(mybytearray,0,mybytearray.length);
ous.flush();
//ous.close();
// socket.close();
System.out.println("send overrrrrrrrrrr");
}catch (UnknownHostException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
The Socket is connected in a thread when the program starts.
The receiver is a java code in pc as follows
#Override
public void run()
{
try
{
ServerSocket servsocket = new ServerSocket(13267);
System.out.println("Thread Waiting...");
Socket socket = servsocket.accept();
System.out.println("Accepted connection : " + socket);
System.out.println("Connected..");
while(true)
{
// filesize temporary hardcoded
long start = System.currentTimeMillis();
int bytesRead;
int current = 0;
mybytearray = new byte [filesize];
File f=new File("d:\\ab.jpg");
f.createNewFile();
InputStream is = socket.getInputStream();
FileOutputStream fos = new FileOutputStream(f);
BufferedOutputStream bos = new BufferedOutputStream(fos);
System.out.println("b4");
bytesRead = is.read(mybytearray,0,mybytearray.length);
System.out.println("after");
current = bytesRead;
do {
bytesRead =
is.read(mybytearray, current, (mybytearray.length-current));
if(bytesRead >= 0) current += bytesRead;
} while(bytesRead > -1);
bos.write(mybytearray, 0 , current);
bos.flush();
long end = System.currentTimeMillis();
System.out.println(end-start);
bos.close();
fos.close();
}
}catch(IOException e)
{
System.out.println("errorr");
}
}
}
The problem is File Does'nt appear on my pc Unless i close my output stream or socket If i close output stream the socket is getting closed why this?
Keep Socket alive while send file
Sending the file keeps the socket alive. I don't see the relevance of your title to your question.
The problem is File Does'nt appear on my pc Unless i close my output stream or socket
So close it. Closing the socket at the sender causes the receiver to exit your receive loop, which has no other way of exiting. Your stream copy loops are far more elaborate than necessary. It is neither necessary nor advisable to buffer entire files in memory before or after sending.
If i close output stream the socket is getting closed why this?
Because that's what it's specified to do. Closing the input or output stream of a socket closes the other stream and the socket.
If I understand correct you want to keep the socket open with the client, and also send files ...
My suggestion is :
- keep one main thread open to notify the server about new files
- open new threads to send each new file
- add code to control the maximum number of files that you can send at the same time (optional)
So the flow would be :
1. client open main socket
2. server open the main socket and assign a client id
3. client request the send of a new file
4. server keep in memory the file name and client id
5. server send response authorizing the client to send the file
6. client open a new thread to send the file
Hello there im trying to send files using client-server classes in java. For some reason when the method that sends the file is called the socket closes. here is the code :
FileInputStream fIn = new FileInputStream(file);
out = new BufferedOutputStream(clientSocket.getOutputStream());
byte fileContent[] = new byte[(int) file.length()];
fIn.read(fileContent);
for (byte b : fileContent) {
out.write(b);
}
and the code from the client :
FileOutputStream fIn = new FileOutputStream("testing");
BufferedInputStream inAout = new BufferedInputStream(clientSocket.getInputStream());
byte fileContent[] = new byte[1000000];
inAout.read(fileContent);
fIn.write(fileContent);
and the error message i get : SEVERE: null
java.net.SocketException: Socket closed
Im not really experienced with this so if any can help it would be great.
The InputStream.read(byte[]) method returns an int for the number of bytes it actually read. It's not guaranteed to read as many bytes as you requested from the byte array. It'll often return the size of the underlying buffer and you'll have to call it many times.
You can use this to be more efficient by streaming the bytes from the socket to the file instead of buffering the whole byte array in memory. Likewise on the server side you can do the same thing to save memory and be faster than writing a byte at a time.
Here's a working example of a server and client in one that connects to itself to transfer a file:
public class SocketFileExample {
static void server() throws IOException {
ServerSocket ss = new ServerSocket(3434);
Socket socket = ss.accept();
InputStream in = new FileInputStream("send.jpg");
OutputStream out = socket.getOutputStream();
copy(in, out);
out.close();
in.close();
}
static void client() throws IOException {
Socket socket = new Socket("localhost", 3434);
InputStream in = socket.getInputStream();
OutputStream out = new FileOutputStream("recv.jpg");
copy(in, out);
out.close();
in.close();
}
static void copy(InputStream in, OutputStream out) throws IOException {
byte[] buf = new byte[8192];
int len = 0;
while ((len = in.read(buf)) != -1) {
out.write(buf, 0, len);
}
}
public static void main(String[] args) throws IOException {
new Thread() {
public void run() {
try {
server();
} catch (IOException e) {
e.printStackTrace();
}
}
}.start();
client();
}
}
The reason is pretty simple: The call inAout.read(fileContent) will return after about 4KB of data has been transmitted. That's the input buffer size. So instead of a single huge read, you need a loop and many reads and write as many bytes to fIn as you got from the socket.
Also don't forget to flush the output on the server side (closing will flush it) or some data will be lost.
SEVERE: null java.net.SocketException: Socket closed
That means you've closed the socket yourself and then called another operation that needs it open. For example, closing the socket or its input stream or output stream closes the other stream and the socket. Somewhere or other you are doing that.
I am trying to send a file (an image sent as a byte array) with the client and then the server should receive said byte array to make further use of it. However when I click on the "send" to send the image the file transfer starts (as I get a sentImage.jpg in my Desktop) but it gets stuck for some reason I can't figure out and the image never gets correctly sent.
Here's the part that receives from the server (it already accepted the connection):
public void run(){
try {
byte[] receivedData = new byte[1024];
BufferedInputStream bis = new BufferedInputStream(client.getInputStream());
// while(bis.read() != -1){
s.acquireUninterruptibly();
BufferedOutputStream bos = new BufferedOutputStream(new FileOutputStream("C:\\Users\\Admin\\Desktop\\sentImage.jpg"));
while ((incoming = bis.read(receivedData)) != -1) {
bos.write(receivedData, 0, incoming);
}
s.release();
n.release();
bis.close();
bos.flush();
// }
} catch (IOException e) {
e.printStackTrace();
}
}
and the client is sending here:
public void sendImageResult() {
new Thread(new Runnable() {
public void run() {
try {
int inside = 0;
Socket socket = new Socket("localhost", 4444);
File myImageFile = new File("C:\\Users\\Admin\\Desktop\\test.jpg");
BufferedInputStream bis = new BufferedInputStream(new FileInputStream(myImageFile));
BufferedOutputStream bos = new BufferedOutputStream(socket.getOutputStream( ));
byte[] byteArray = new byte[1024];
while ((inside = bis.read(byteArray)) != -1){
bos.write(byteArray,0,inside);
}
bis.close();
bos.flush();
} catch (UnknownHostException ex) {
System.out.println("No se pudo establecer la conexión.");
ex.printStackTrace();
} catch (FileNotFoundException fnf){
fnf.printStackTrace();
} catch(IOException ioe){
ioe.printStackTrace();
}
}
}).start();
}
It does not appear that the OutputStream (bos) that is used to write to disk is being closed. This could lead to unexpected results.
As jt said, the OutputStream writing to disk is not being closed, but neither is the OutputStream being used to send the data, nor is the Socket being closed from the sending side. The sending side may be buffering the data at the tcp level, waiting for more bytes before sending the last packet. You are calling flush, but that can be ignored, it's not guaranteed to work like you expect. Another thing to try is calling shutdownOutput on the Socket and seeing if that forces it to flush. You can also try setTcpNoDelay(true) when you open the Socket. If none of that works, get a tcp trace program (I like tcpdump) and use it to see if the packets are actually being sent, it will at least narrow it down to either the send or receive end of things.