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Java: ClassNotFound Classpath issues

Im trying to read some information from a file into some objects. Main method just reads the Information into some string variables then uses those strings to initialize objects. Pretty simple. The objects are stored using a BST.
However, The error Im getting is ClassNotFoundException. Except when I run the java 'file' command, 'file' is spelled and capitalized correctly.
I've been reading that you can change the path that JVM uses when searching for class files.
so I tried:
set CLASSPATH=$CLASSPATH=~/../../BackEnd
but that didn't do anything..
Here is my main file..
import java.util.Scanner;
import java.io.File;
class BackEnd
{
public static void main(String args[]) throws java.io.FileNotFoundException
{
Tree.ServiceTree providers = new Tree.ServiceTree();
String path = "./providers.txt";
Scanner read = new Scanner (new File(path));
read.useDelimiter(",");
String information[] = new String[5];//array of strings used to store info from file, then used to initialize objects
try
{
while(read.hasNext())
{
for(int i = 0; i < 5; ++i)
{
information[i] = read.nextLine();//read in all the info into the array
}
Services.Service newService;//used as dynamic reference to be passed to tree
Services.Service serviceInfo = new Services.Service(information[0], information[1]);//initalizes base class to be passed to derived constructor
switch(information[0])//check type to initalize appropriate object
{
case "Dogwalk":
newService = new Services.Dogwalk(serviceInfo, information[2], information[3]);
case "Groceries":
newService = new Services.Groceries(serviceInfo, information[2], information[3]);
case "Housework":
newService = new Services.Housework(serviceInfo, information[2], information[3]);
}
providers.insert(information[4], newService);
}
read.close();
throw new java.io.FileNotFoundException("File not found...");
}
catch(java.io.FileNotFoundException exception)
{
System.out.println("File not found");
}
//providers.display();
}
}

Figured it out. Error had nothing to do with compilation or class path and was due
to uninitialized variable newService

Converting part of .dox document to html using Apache POI

I use XHTMLConverter to convert .docx to html, to make preview of the document. Is there any way to convert only few pages from original document? I'll be grateful for any help.

You have to parse the complete .docx file. It is not possible to read just parts of it. Otherwise if you want to know how to select a specific page number, im afraid to tell you(at least I believe) that word does not store page numbers therefore there is no function in the libary to accsess a specified page..
(I've read this at another forum, it actually might be false information).
PS: the Excel POI contains a .getSheetAt()method (this might helps you for your research)
But there are also other ways to accsess your pages. For instance you could read the lines of your docx document and search for the pagenumbers(might crash if your text contains those numbers though). Another way would be to search for the header of the site which would be more accurate:
HeaderStories headerStore = new HeaderStories( doc);
String header = headerStore.getHeader(pageNumber);
this should give you the header of the specified page. Same with footer:
HeaderStories headerStore = new HeaderStories( doc);
String footer = headerStore.getFooter(pageNumber);
If this dosen't work. I am not really into that API....
here a little Example for a very sloppy solution:
import java.io.*;
import org.apache.poi.hwpf.HWPFDocument;
import org.apache.poi.hwpf.extractor.WordExtractor;
public class ReadDocFile
{
public static void main(String[] args)
{
File file = null;
WordExtractor extractor = null;
try
{
file = new File("c:\\New.doc");
FileInputStream fis = new FileInputStream(file.getAbsolutePath());
HWPFDocument document = new HWPFDocument(fis);
extractor = new WordExtractor(document);
String[] fileData = extractor.getParagraphText();
for (int i = 0; i < fileData.length; i++)
{
if (fileData[i].equals("headerPageOne")){
int firstLineOfPageOne = i;
}
if (fileData[i]).equals("headerPageTwo"){
int lastLineOfPageOne = i
}
}
}
catch (Exception exep)
{
exep.printStackTrace();
}
}
}
If you go with this i would recommend you to create a String[] with your headers and refractor the for-loop to a seperate getPages() Method. Therefore your loop would look like:
List<String> = new ArrayList<String>(Arrays.asList("header1","header2","header3","header4"));
for (int i = 0; i < fileData.length; i++)
{
//well there should be a loop for "x" too
if (fileData[i].equals(headerArray[x])){
int firstLineOfPageOne = i;
}
if (fileData[i]).equals(headerArray[x+1]){
int lastLineOfPageOne = i
}
}
You could create an Object(int pageStart, int PageStop), wich would be the product of your method.
I hope it helped you :)

Loading and saving files in a text based game (java)

So, i'm trying to save my player data onto a txt file, then load the data from the text from when the game is opened again, but its not working, I get it to save while in the game, but when I close the game, and open it back up its no longer saved, and it has all the default data in the game, and in the file...
Here is the some of the code from the game (Sorry it's in pastebin, I thought i might be too long to just paste it into here.)
Game.java
Save.java
I am in need of some assistance, trying to get it to load from the text document, and when the game opens, not resetting the text document into its default settings.

The issue is in Save.savePlayer()
At the beginning you declare saveInfo to hold the values that the game holds at that point in time. When initially loading they will hold the default values.
int[] saveInfo = { Game.hp, Game.level, Game.mana, Game.expTotal,
Game.goldTotal, Game.arrow, Game.shuriken, Game.bomb,
Game.hpPotion, Game.mpPotion, Game.potion, Game.items };
The variables here:Game.hp=100, Save.saveInfo[0]=100
Then you set all of the game variables to saveInfo at the beginning of Save.savePlayer()
Game.hp = saveInfo[0];
Game.level = saveInfo[1];
Game.mana = saveInfo[2];
Game.expTotal = saveInfo[3];
Game.goldTotal = saveInfo[4];
Game.arrow = saveInfo[5];
Game.shuriken = saveInfo[6];
Game.bomb = saveInfo[7];
Game.hpPotion = saveInfo[8];
Game.mpPotion = saveInfo[9];
Game.potion = saveInfo[10];
Game.items = saveInfo[11];
The variables here:Game.hp=100, Save.saveInfo[0]=100
They don't change because you just set them back to their default values.
Then you load the saved state but you don't do anything with the data. You should be setting the variables after loading here so they're set to the new saveInfo values instead of the old.
for (int i = 0; i < saveInfo.length; i++) {
saveInfo[i] = Integer.parseInt(inputReader.readLine());
}

I think this part is the problem...
private void readPlayer(String filePath) {
File inputFile;
BufferedReader inputReader;
try {
inputFile = new File(filePath);
inputReader = new BufferedReader(new FileReader(inputFile));
Game.hp = saveInfo[0];
Game.level = saveInfo[1];
Game.mana = saveInfo[2];
Game.expTotal = saveInfo[3];
Game.goldTotal = saveInfo[4];
Game.arrow = saveInfo[5];
Game.shuriken = saveInfo[6];
Game.bomb = saveInfo[7];
Game.hpPotion = saveInfo[8];
Game.mpPotion = saveInfo[9];
Game.potion = saveInfo[10];
Game.items = saveInfo[11];
for (int i = 0; i < saveInfo.length; i++) {
saveInfo[i] = Integer.parseInt(inputReader.readLine());
}
inputReader.close();
} catch (Exception e) {
e.printStackTrace();
}
}
put these lines
for (int i = 0; i < saveInfo.length; i++) {
saveInfo[i] = Integer.parseInt(inputReader.readLine());
}
before
Game.hp = saveInfo[0];
Game.level = saveInfo[1];
Game.mana = saveInfo[2];
Game.expTotal = saveInfo[3];
Game.goldTotal = saveInfo[4];
Game.arrow = saveInfo[5];
Game.shuriken = saveInfo[6];
Game.bomb = saveInfo[7];
Game.hpPotion = saveInfo[8];
Game.mpPotion = saveInfo[9];
Game.potion = saveInfo[10];
Game.items = saveInfo[11];
in order to read the file before setting the game values...

If you do not mind it, then using xstream and apache fileutils is an excellent solution and less coding. I am just sharing my thoughts.
import org.apache.commons.io.FileUtils;
import com.thoughtworks.xstream.XStream;
//saving your data
XStream xstream=new XStream(new DOMDriver());
String xml = xstream.toXML(yourGambeObj);
FileUtils.writeStringToFile(new File("yourfilename", xml);
//reading your data
Game gameData=xstream.fromXML(new File("yourfilename"),Game.class);
//now you can use access your methods n attribute. no conversion as you did in serialization.
Please download and add these jars.XStream &
Apache Commons IO

So, I was fiddling around with some things, and I did it! So, the problem was, that i would load it from the save data, then write over it, then load it again, for some reason, it would do the whole Save.java 2 times and just save over it, but I put them all as public static voids and instead of calling the whole Constructor, I call them by individual methods by where and what they need to do, which seem to work great! Thank you all for all your help, it helped a lot!

How to write and retrieve objects arraylist to file?

I have an object arraylist, can someone please help me by telling me the most efficient way to write AND retrieve an object from file?
Thanks.
My attempt
public static void LOLadd(String ab, String cd, int ef) throws IOException {
MyShelf newS = new MyShelf();
newS.Fbooks = ab;
newS.Bbooks = cd;
newS.Cbooks = ef;
InfoList.add(newS);
FileWriter fw;
fw = new FileWriter("UserInfo.out.txt");
PrintWriter outt = new PrintWriter(eh);
for (int i = 0; i <InfoList.size(); i++)
{
String ax = InfoList.get(i).Fbooks;
String ay = InfoList.get(i).Bbooks;
int az = InfoList.get(i).Cbooks;
output.print(ax + " " + ay + " " + az); //Output all the words to file // on the same line
output.println(""); //Make space
}
fw.close();
output.close();
}
My attempt to retrieve file. Also, after retrieving file, how can I read each column of Objects?? For example, if I have ::::: Fictions, Dramas, Plays --- How can I read, get, replace, delete, and add values to Dramas column?
public Object findUsername(String a) throws FileNotFoundException, IOException, ClassNotFoundException
{
ObjectInputStream sc = new ObjectInputStream(new FileInputStream("myShelf.out.txt"));
//ArrayList<Object> List = new ArrayList<Object>();
InfoList = null;
Object obj = (Object) sc.readObject();
InfoList.add((UserInfo) obj);
sc.close();
for (int i=0; i <InfoList.size(); i++) {
if (InfoList.get(i).user.equals(a)){
return "something" + InfoList.get(i);
}
}
return "doesn't exist";
}
public static String lbooksMatching(String b) {
//Retrieve data from file
//...
for (int i=0; i<myShelf.size(); i++) {
if (myShelf.get(i).user.equals (b))
{
return b;
}
else
{
return "dfbgregd";
}
}
return "dfgdfge";
}
public static String matching(String qp) {
for (int i=0; i<myShelf.size(); i++) {
if (myShelf.get(i).pass.equals (qp))
{
return c;
}
else
{
return "Begegne";
}
}
return "Bdfge";
}
Thanks!!!

It seems like you want to serialize an object and persist that serialized form to some kind of storage (in this case a file).
2 important remarks here :
Serialization
Internal java serialization
Java provides automatic serialization which requires that the object be marked by implementing the java.io.Serializable interface. Implementing the interface marks the class as "okay to serialize," and Java then handles serialization internally.
See this post for a code sample on how to serialize /
deserialize an object to/from bytes.
This might nog always be the ideal way to persist an object, as you have no control over the format (handled by java), it's not human readable, and you can versioning issues if your objects change.
Marshalling to JSON or XML
A better way to seralize an object to disk is to use another data format like XML or JSON.
A sample on how to convert an object to/from a JSON structure can be found here.
Important : I would not do the kind of serialization in code like you're doing unless there is a very good reason (that I don't see here). It quickly becomes messy and is subject to change when your objects change. I would opt for a more automated way of serializing. Also, when using a format like JSON / XML, you know that there are tons of APIs available to read/write to that format, so all of that serialization / deserialization logic doesn't need to be implemented by you anymore.
Persistence
Writing your serialized object to a file isn't always a good idea for various reasons (no versioning / concurrency issues / .....).
A better approach is to use a database. If it's a hierarchical database, take a look at Hibernate or JPA to persist your objects with very little code.
If it's a document database like MongoDB, you can persist your JSON serialized representation.
There are tons of resources available on persisting objects to databases in Java. I would suggest checking out JPA, the the standard API for persistence and object/relational mapping .

Here is another basic example, which will give you insight into Arraylist,constructor and writing output to file:
After running this, if you are using IDE go to project folder, there you will file *.txt file.
import java.io.*;
import java.util.List;
import java.util.ArrayList;
import java.util.logging.Level;
import java.util.logging.Logger;
public class ListOfNumbers {
private List<Integer> list;
private static final int SIZE = 10;//whatever size you wish
public ListOfNumbers () {
list = new ArrayList<Integer>(SIZE);
for (int i = 0; i < SIZE; i++) {
list.add(new Integer(i));
}
}
public void writeList() {
PrintWriter out = null;
try {
out = new PrintWriter(new FileWriter("ManOutFile.txt"));
for (int i = 0; i < SIZE; i++) {
out.println("Value at: " + i + " = " + list.get(i));
}
out.close();
} catch (IOException ex) {
Logger.getLogger(ListOfNumbers.class.getName()).log(Level.SEVERE, null, ex);
} finally {
out.close();
}
}
public static void main(String[] args)
{
ListOfNumbers lnum=new ListOfNumbers();
lnum.writeList();
}
}

saving random numbers in java

I'm doing an animation in Processing. I'm using random points and I need to execute the code twice for stereo vision.
I have lots of random variables in my code, so I should save it somewhere for the second run or re-generate the SAME string of "random" numbers any time I run the program. (as said here: http://www.coderanch.com/t/372076/java/java/save-random-numbers)
Is this approach possible? How? If I save the numbers in a txt file and then read it, will my program run slower? What's the best way to do this?
Thanks.

If you just need to be able to generate the same sequence for a limited time, seeding the random number generator with the same value to generate the same sequence is most likely the easiest and fastest way to go. Just make sure that any parallel threads always request their pseudo random numbers in the same sequence, or you'll be in trouble.
Note though that there afaik is nothing guaranteeing the same sequence if you update your Java VM or even run a patch, so if you want long time storage for your sequence, or want to be able to use it outside of your Java program, you need to save it to a file.

Here is a sample example:
public static void writeRandomDoublesToFile(String filePath, int numbersCount) throws IOException
{
FileOutputStream fos = new FileOutputStream(new File(filePath));
BufferedOutputStream bos = new BufferedOutputStream(fos);
DataOutputStream dos = new DataOutputStream(bos);
dos.writeInt(numbersCount);
for(int i = 0; i < numbersCount; i++) dos.writeDouble(Math.random());
}
public static double[] readRandomDoublesFromFile(String filePath) throws IOException
{
FileInputStream fis = new FileInputStream(new File(filePath));
BufferedInputStream bis = new BufferedInputStream(fis);
DataInputStream dis = new DataInputStream(bis);
int numbersCount = dis.readInt();
double[] result = new double[numbersCount];
for(int i = 0; i < numbersCount; i++) result[i] = dis.readDouble();
return result;
}

Well, there's a couple of ways that you can approach this problem. One of them would be to save the random variables as input into a file and pass that file name as a parameter to your program.
And you could do that in one of two ways, the first of which would be to use the args[] parameter:
import java.io.*;
import java.util.*;
public class bla {
public static void main(String[] args) {
// You'd need to put some verification code here to make
// sure that input was actually sent to the program.
Scanner in = new Scanner(new File(args[1]));
while(in.hasNextLine()) {
System.out.println(in.nextLine());
}
} }
Another way would be to use Scanner and read from the console input. It's all the same code as above, but instead of Scanner in = new Scanner(new File(args[1])); and all the verification code above that. You'd substitute Scanner in = new Scanner(System.in), but that's just to load the file.
The process of generating those points could be done in the following manner:
import java.util.*;
import java.io.*;
public class generator {
public static void main(String[] args) {
// You'd get some user input (or not) here
// that would ask for the file to save to,
// and that can be done by either using the
// scanner class like the input example above,
// or by using args, but in this case we'll
// just say:
String fileName = "somefile.txt";
FileWriter fstream = new FileWriter(fileName);
BufferedWriter out = new BufferedWriter(fstream);
out.write("Stuff");
out.close();
}
}
Both of those solutions are simple ways to read and write to and from a file in Java. However, if you deploy either of those solutions, you're still left with some kind of parsing of the data.
If it were me, I'd go for object serialization, and store a binary copy of the data structure I've already generated to disk rather than having to parse and reparse that information in an inefficient way. (Using text files, usually, takes up more disk space.)
And here's how you would do that (Here, I'm going to reuse code that has already been written, and comment on it along the way) Source
You declare some wrapper class that holds data (you don't always have to do this, by the way.)
public class Employee implements java.io.Serializable
{
public String name;
public String address;
public int transient SSN;
public int number;
public void mailCheck()
{
System.out.println("Mailing a check to " + name
+ " " + address);
}
}
And then, to serialize:
import java.io.*;
public class SerializeDemo
{
public static void main(String [] args)
{
Employee e = new Employee();
e.name = "Reyan Ali";
e.address = "Phokka Kuan, Ambehta Peer";
e.SSN = 11122333;
e.number = 101;
try
{
FileOutputStream fileOut =
new FileOutputStream("employee.ser");
ObjectOutputStream out =
new ObjectOutputStream(fileOut);
out.writeObject(e);
out.close();
fileOut.close();
}catch(IOException i)
{
i.printStackTrace();
}
}
}
And then, to deserialize:
import java.io.*;
public class DeserializeDemo
{
public static void main(String [] args)
{
Employee e = null;
try
{
FileInputStream fileIn =
new FileInputStream("employee.ser");
ObjectInputStream in = new ObjectInputStream(fileIn);
e = (Employee) in.readObject();
in.close();
fileIn.close();
}catch(IOException i)
{
i.printStackTrace();
return;
}catch(ClassNotFoundException c)
{
System.out.println(.Employee class not found.);
c.printStackTrace();
return;
}
System.out.println("Deserialized Employee...");
System.out.println("Name: " + e.name);
System.out.println("Address: " + e.address);
System.out.println("SSN: " + e.SSN);
System.out.println("Number: " + e.number);
}
}
Another alternative solution to your problem, that does not involve storing data, is to create a lazy generator for whatever function that provides you your random values, and provide the same seed each and every time. That way, you don't have to store any data at all.
However, that still is quite a bit slower (I think) than serializing the object to disk and loading it back up again. (Of course, that's a really subjective statement, but I'm not going to enumerate cases where that is not true). The advantage of doing that is so that it doesn't require any kind of storage at all.
Another way, that you may have not possibly thought of, is to create a wrapper around your generator function that memoizes the output -- meaning that data that has already been generated before will be retrieved from memory and will not have to be generated again if the same inputs are true. You can see some resources on that here: Memoization source
The idea behind memoizing your function calls is that you save time without persisting to disk. This is ideal if the same values are generated over and over and over again. Of course, for a set of random points, this isn't going to work very well if every point is unique, but keep that in the back of your mind.
The really interesting part comes when considering the ways that all the previous strategies I've described in this post can be combined together.
It'd be interesting to setup a Memoizer class, like described in the second page of 2 and then implement java.io.Serialization in that class. After that, you can add methods save(String fileName) and load(String fileName) in the memoizer class that make serialization and deserialization easier, so you can persist the cache used to memoize the function. Very useful.
Anyway, enough is enough. In short, just use the same seed value, and generate the same point pairs on the fly.