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Dividing Floats in Java [closed]

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First day learning Java and I came across this problem: I need to divide 2 floats(given from command line input). I am getting an error every time I input my 2 floats. I included my code down below
import java.util.Scanner;
public class doubledivision
{
public static void main(String [] args)
{
float num1, num2;
Scanner in = new Scanner(System.in);
System.out.print("Please enter two floating point numbers: ");
num1 = in.nextInt();
num2 = in.nextInt();
float result = num1 / num2;
System.out.println(result);
}
}

If you want to read a number of type float from the user, you need to use :
in.nextFloat()
because this in.nextInt() will return a value of type int.
Also you need to consider some things :
You need to clear the scanner since you want 2 floating numbers , why ? because if the user enters :
>>> 1.0 2.0
The space will make your scanner assigne num1 with 1.0 and num2 with 2.0.
So if you want to ask the user 2 times use :
num1 = in.nextFloat();
in.nextLine(); // to refresh
num2 = in.nextFloat();
If the user enters zero (any number) divided by 0 will blow up​ your app , so add a check :
if(num2==0){
System.out.println("NaN");
}
else {
float result = num1 / num2;
System.out.println(result);
}

impossible to pass user's input to the array [closed]

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I am trying to pass user's input to the array through a scanner. The goal is to make the average value of the inputs, this is the code:
public static void main(String args[]) {
Scanner scanner = new Scanner(System.in);
double[] str1 = new int [20] ;
str1 = scanner.next.Double();
System.out.println("Average is: " + Arrays.stream(str1).summaryStatistics().getAverage());
}
}

Below 2 statements are having syntax error and because of this code will not compile:
double[] str1 = new int [20] ;
str1 = scanner.next.Double();
you need to declare double array as double[] str1 = new double[20];
you need to take the double value as input like this scanner.nextDouble(); and as str1 is array we can't store the input directly as str1 = scanner.nextDouble(); in that case your program will give compile time error
Type mismatch: cannot convert from double to double[]
To resolve this error we need to store the value of every input at specific index like str1[0] = scanner.nextDouble();
Below is the working code as per your requirement(as I understand from your question):
Scanner scanner = new Scanner(System.in);
double[] str1 = new double[20] ;
for(int i = 0; i < 20;i++) {
str1[i] = scanner.nextDouble();
}
System.out.println("Average is: " + Arrays.stream(str1).summaryStatistics().getAverage());
I hope it will help you resolve the error you're facing.

How to find the closest element in an array [closed]

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I've tried looking for the answer to this question, but I haven't had a lot of luck. Basically I am asked to create the Fibonacci Code, and then allow a user input to look for there input in the sequence. If its in the sequence then it shows what index. If its not then it shows the two closest numbers to it.
So if a user inputs 4, the nearest elements would be 3 and 5 and the indexes would be 4 and 5.
I'm basically struggling with finding the nearest elements. I'm not exactly sure how to do it.
****update****
So I did figure it out thank you

1.Store the previous Fibonacci number in a buffer (you can initialize with -1)
2.update the buffer after every new number is calculated.
3.if the current number is not equal to the new number
3.A check if the number is greater than buffer and less than the new number
3.A.1)If yes, those two are your nearest numbers.
import java.util.Scanner;
public class Fibonacci {
public static void main(String[] args) {
int userInput;
Fibonacci.fibonacciAlgor(5);
}
public static void fibonacciAlgor(int userInput)
{
int i=0;
int buffer=-1;
int x=0,y=1;
System.out.println("Input: " + userInput);
while(i<1000000){
if(x==userInput){
System.out.println("Belongs to sequence: Yes "");
break;
}
else{
if(userInput>buffer&&userInput<x){
System.out.println("Belongs to sequence: No ");
System.out.println("Nearest Elements: " + buffer+","+x);
break;
}
}
buffer=x;
int temp=y;
y=x+y;
x=temp;
i++;
}
}
}

Else without if error that hinders code from correct output [closed]

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Closed 8 years ago.
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import java.util.Scanner;
public class FantahunKeburAlmostIsoscelesRightTriangle{
public static void main (String []args){
Scanner s = new Scanner(System.in);
System.out.println("Enter the longest side: ");
double longest = s.nextDouble();
System.out.println("Enter 2nd side: ");
double second = s.nextDouble();
System.out.println("Enter 3rd side: ");
double third = s.nextDouble();
double longsq = Math.pow(longest, 2);
double secondsq = Math.pow(second, 2);
double thirdsq = Math.pow(third, 2);
double secthirdsq = secondsq + thirdsq;
double SecLongLength = second + 1 ;
if (secthirdsq==longsq) {
System.out.println("This triangle is an almost-Isosceles right triangle. ");
}
else if (secthirdsq!=longsq) {
System.out.println("This triangle is not a right triangle. ");
else (SecLongLength!=longest) {
System.out.println("This triangle is a right triangle, but not almost-Isosceles.");
}
}
}
}
I get these errors after I try to run the code. Basically, if I input numbers like 5, 4, and 3 for longest, second, and third respectively I should get "this triangle is an almost-Isosceles right triangle" as an "Almost Isosceles Right Triangle" is a right triangle where the numbers are one integer from each other, and this function works. When I input numbers like 10, 8, and 6 I should get this output: "This triangle is a right triangle, but not almost-Isosceles." But alas, I get the errors below. I tried to make it an else if and it then gave me a ";" error which corrected and more errors came up. What can I do to get the output I want?
FantahunKeburAlmostIsoscelesRightTriangle.java:33: error: 'else' without 'if'
else (SecLongLength!=longest) {
^
FantahunKeburAlmostIsoscelesRightTriangle.java:33: error: not a statement
else (SecLongLength!=longest) {
^
FantahunKeburAlmostIsoscelesRightTriangle.java:33: error: ';' expected
else (SecLongLength!=longest) {

Take a look at your code, This is wrong
else if (secthirdsq!=longsq) {
System.out.println("This .......");
else(SecLongLength!=longest) { // this else inside if without a if
System.out.println("This .....");
}
}
There must be a if to have else. It is obvious what is the point of having else without a if?
You can follow following order
if(condition1){
else if(condition2){
}else{
}

Two things are wrong...
1. the closing bracket
2. the else branch.. either else without or else-if with condition
else if (secthirdsq!=longsq) {
...
else (SecLongLength!=longest) {
...
}

Syntax error on token ";" in Java [closed]

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Closed 8 years ago.
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"Syntax error on token ";", Primitive Type expected after this token" is the message i get rite after the semi colon on this statement "String data = input.next(); " and i don't know why.
import java.util.*;
public class PorterHouse {
public static void main(String[] args){
System.out.println("enter interest rate, loan mount, and number of years: ex. "+
" 7.9-400000-5");
Scanner input = new Scanner(System.in);
String data = input.next();
[] b = data.split("[-]");
double interstRate = Double.parseDouble(b[0]);
double loanPrincipal = Double.parseDouble(b[1]);
double loanLength = Double.parseDouble(b[2]);
double monthlyPayment = (b[1]*b[2] / 1);
double totalPayment = ( monthlyPayment * loanLength * 12);
System.out.println("Monthly Pament: " + monthlyPayment);
System.out.println("totalPayment: " + totalPayment);
}
}

Try to change this:
[] b = data.split("[-]");
with this:
string[] b = data.split("[-]");
Presently [] b has no data type. So do provide a data type to it.

I guess instead of :
[] b = data.split("[-]");
you need something like :
String[] b = data.split("[-]");
also
you might wanna replace :
double monthlyPayment = (b[1]*b[2] / 1);
by :
double monthlyPayment = (loanPrincipal * loanLength / 1); //idk why divide by 1??
cuz, b[1] and b[2] are two Strings.