I am new to Eclipse and Java and I have researched this a fair amount, but most answers and examples (SO included) assume you have a basic understanding of where you are heading, so please explain simply (I am sure it must be simple).
I have a function such as this, which runs successfully in eclipse. However I need to be able to call this function twice and for them to run simultaneously, opposed to one after the other.
public static void reporting(String category, String message) {
// Code for this function
}
public static void main(String[] args) {
// Call the function once
reporting("one","Starting");
// Call the function a second time
reporting("two","Starting");
}
So currently instance 1 is running, then the second instance executes after the first completes. I need the first to start executing and then for the second to start straight away after. My only vague idea to this so far is this:
public static void main(String[] args) {
// Call the function once
async reporting("one","Starting");
// Call the function a second time
async reporting("two","Starting");
}
However this just throws errors about async not being a variable so clearly it isn't right.
As far as I can gather this is possible using async somehow - but as I say everywhere I look (SO
answers included) assume you have an idea of where this should fit.
(Ps, I am fully away that I maybe to totally wrong about async or there maybe a more efficient way altogether, but anything to help me learn in the right direction is beneficial)
You should extend Thread or implement Runnable for that.
You then execute the code in run methods, and start the Runnables by invoking their start methods.
Self-contained, quick and dirty example (within a Main class):
public static void main(String[] args) throws Exception {
// these are spawned as new threads,
// therefore there is no guarantee the first one runs before the second one
// (although in this specific case it's likely the first one terminates first)
new Reporter("one","Starting").start();
new Reporter("two","Starting").start();
}
static class Reporter extends Thread {
String category, message;
Reporter(String category, String message) {
this.category = category;
this.message = message;
}
#Override
public void run() {
reporting(category, message);
}
void reporting(String category, String message) {
System.out.printf("Category: %s, Message: %s%n", category, message);
}
}
You should read some Thread tutorials.
One of the many possibilities:
public static void main(String[] args)
{
try{
Thread t1 = new Thread()
{
public void run() {
reporting("one","Starting");
};
};
Thread t2 = new Thread()
{
public void run() {
reporting("two","Starting");
};
};
t1.start();//start the threads
t2.start();
t1.join();//wait for the threads to terminate
t2.join();
}catch(Exception e)
{
e.printStackTrace();
}
}
You can do create two Thread objects inside your main() like this:
Thread thread1 = new Thread () {
public void run () {
reporting("one","Starting");
}
};
Thread thread2 = new Thread () {
public void run () {
reporting("two","Starting");
}
};
Then start the 2 threads like:
thread1.start();
thread2.start();
Read more about the Thread Class and also check out some useful examples.
Related
In my applications there are an n number of actions that must happen, one after the other in sequence, for the whole life of the program. Instead of creating methods which implement those actions and calling them in order in a while(true) loop, I decided to create one thread for each action, and make them execute their run method once, then wait until all the other threads have done the same, wait for its turn, and re-execute again, and so on...
To implement this mechanism I created a class called StatusHolder, which has a single field called threadTurn (which signifies which thread should execute), a method to read this value, and one for updating it. (Note, this class uses the Singleton design pattern)
package Test;
public class StatusHolder
{
private static volatile StatusHolder statusHolderInstance = null;
public static volatile int threadTurn = 0;
public synchronized static int getTurn()
{
return threadTurn;
}
public synchronized static void nextTurn()
{
System.out.print("Thread turn: " + threadTurn + " --> ");
if (threadTurn == 1)
{
threadTurn = 0;
}
else
{
threadTurn++;
}
System.out.println(threadTurn);
//Wake up all Threads waiting on this obj for the right turn to come
synchronized (getStatusHolder())
{
getStatusHolder().notifyAll();
}
}
public static synchronized StatusHolder getStatusHolder()
{//Returns reference to this object
if (statusHolderInstance == null)
{
statusHolderInstance = new StatusHolder();
}
return statusHolderInstance;
}
}
Then I have, let's say, two threads which must be execute in the way explained above, t1 and t2.
T1 class looks like this:
package Test;
public class ThreadOne implements Runnable
{
#Override
public void run()
{
while (true)
{
ThreadUtils.waitForTurn(0);
//Execute job, code's not here for simplicity
System.out.println("T1 executed");
StatusHolder.nextTurn();
}
}
}
And T2 its the same, just change 0 to 1 in waitForTurn(0) and T1 to T2 in the print statement.
And my main is the following:
package Test;
public class Main
{
public static void main(String[] args) throws InterruptedException
{
Thread t1 = new Thread(new ThreadOne());
Thread t2 = new Thread(new ThreadTwo());
t1.start();
t2.start();
}
}
So the run method goes like this:
At the start of the loop the thread looks if it can act by checking the turn value with the waitForTurn() call:
package Test;
public class ThreadUtils
{
public static void waitForTurn(int codeNumber)
{ //Wait until turn value is equal to the given number
synchronized (StatusHolder.getStatusHolder())
{
while (StatusHolder.getTurn() != codeNumber)
{
try
{
StatusHolder.getStatusHolder().wait();
}
catch (InterruptedException e)
{
e.printStackTrace();
}
}
}
}
}
If the two values are equal, the thread executes, otherwise it waits on the StatusHolder object to be awaken from the nextTurn() call, because when the turn value changes all the threads are awaken so that they can check if the new turn value is the one they are waiting for so they can run.
Note thatnextTurn() cycles between 0 and 1: that is because in this scenario I just have two threads, the first executes when the turn flag is 0, and the second when its 1, and then 0 again and so on. I can easily change the number of turns by changing this value.
The problem: If I run it, all goes well and seems to work, but suddenly the output console stops flowing, even if the program doesn't crash at all. I tried to put a t1.join() and then a print in the main but that print never executes, this means that the threads never stop/dies, but instead they remain locked sometimes.
This looks to be even more evident if I put three threads: it stops even sooner than with two threads.
I'm relatively new to threads, so I might be missing something really stupid here...
EDIT: I'd prefer not to delete a thread and create a new one every time: creating and deleting thousands of objs every second seems a big work load for the garbage collector.
The reason why I'm using threads and not functions is because in my real application (this code is just simplified) at a certain turn there actually are multiple threads that must run (in parallel), for example: turn 1 one thread, turn 2 one thread, turn 3 30 threads, repeat. So I thought why not creating threads also for the single functions and make the whole think sequential.
This is a bad approach. Multiple threads allow you to execute tasks concurrently. Executing actions "one after the other in sequence" is a job for a single thread.
Just do something like this:
List<Runnable> tasks = new ArrayList<>();
tasks.add(new ThreadOne()); /* Pick better names for tasks */
tasks.add(new ThreadTwo());
...
ExecutorService worker = Executors.newSingleThreadExecutor();
worker.submit(() -> {
while (!Thread.interrupted())
tasks.forEach(Runnable::run);
});
worker.shutdown();
Call worker.shutdownNow() when your application is cleanly exiting to stop these tasks at the end of their cycle.
you can use Semaphore class it's more simple
class t1 :
public class t1 implements Runnable{
private Semaphore s2;
private Semaphore s1;
public t1(Semaphore s1,Semaphore s2){
this.s1=s1;
this.s2=s2;
}
public void run()
{
while (true)
{
try {
s1.acquire();
} catch (InterruptedException ex) {
Logger.getLogger(t1.class.getName()).log(Level.SEVERE, null, ex);
}
//Execute job, code's not here for simplicity
System.out.println("T1 executed");
s2.release();
}
}
}
class t2:
public class t2 implements Runnable{
private Semaphore s2;
private Semaphore s1;
public t2(Semaphore s1,Semaphore s2){
this.s1=s1;
this.s2=s2;
}
public void run()
{
while (true)
{
try {
s2.acquire();
} catch (InterruptedException ex) {
Logger.getLogger(t2.class.getName()).log(Level.SEVERE, null, ex);
}
//Execute job, code's not here for simplicity
System.out.println("T2 executed");
s1.release();
}
}
}
class main:
public class Testing {
/**
* #param args the command line arguments
*/
public static void main(String[] args) {
Semaphore s2=new Semaphore(0);
Semaphore s1=new Semaphore(1);
Thread th1 = new Thread(new t1(s1,s2));
Thread th2 = new Thread(new t2(s1,s2));
th1.start();
th2.start();
}}
I have a static function like:
public static void foo()
{
//code follows
System.out.println(Thread.currentThread().getName());
//code follows
}
and multiple threads are calling this function concurrently. I have set the names of threads using
Thread.setName(String)
When i execute the code, the print statement will print the name of only one thread. How can i identify the names of all the threads currently executing the foo() function?
EDIT:
public class FooThread extends Thread
{
public FooThread(String name)
{
this.setName(name);
}
#Override public void run()
{
//do something
//do something
Main.foo();
}
}
//Main Class
public class Main
{
public static void main(String[] args)
{
for(int i=0;i<6;++i)
{
new FooThread("Thread"+i).start();
}
}
public static void foo()
{
//do something
while(true)
{
//do something
System.out.println(Thread.currentThread().getName());
}
}
}
You're already showing the name of the Thread that is calling your code. Code that proves this:
public class Foo2 {
public static synchronized void foo() {
System.out.println(Thread.currentThread().getName());
}
public static void main(String[] args) {
int maxCount = 10;
for (int i = 0; i < maxCount; i++) {
Thread thread = new Thread(new Runnable() {
public void run() {
foo();
}
});
thread.setName("Thread " + i);
thread.start();
long sleepTime = 1000;;
try {
Thread.sleep(sleepTime);
} catch (InterruptedException e) {}
}
}
}
Return:
Thread 0
Thread 1
Thread 2
Thread 3
Thread 4
Thread 5
Thread 6
Thread 7
Thread 8
Thread 9
Your problem lies in code not shown.
Either your method is being called by one and only one thread, or
Or you're giving all your threads the same name.
Again, for a complete solution as to what is actually wrong with your current set up, create and post an sscce similar to what I've posted above. For all we know you could be calling run() on your Threads, and until we can see and reproduce your problem, I don't think that we'll be able to fully understand it.
EDIT
Regarding your SSCCE: Compare the results of the two methods below, foo1() and foo2()
class FooThread extends Thread {
public FooThread(String name) {
this.setName(name);
}
#Override
public void run() {
// do something
// do something
Main.foo1(); // !! Swap comments
// Main.foo2(); // !! Swap comments
}
}
// Main Class
public class Main {
private static final long SLEEP_TIME = 4;
public static void main(String[] args) {
for (int i = 0; i < 6; ++i) {
new FooThread("Thread" + i).start();
}
}
public static void foo1() {
// do something
while (true) {
// do something
synchronized (Main.class) {
System.out.println(Thread.currentThread().getName());
}
try {
Thread.sleep(SLEEP_TIME);
} catch (InterruptedException e) {}
}
}
public static void foo2() {
while (true) {
System.out.println(Thread.currentThread().getName());
}
}
}
If your while loop isn't so tight, but yields the CPU with say a short Thread.sleep, you'll see more of the different threads sharing foo in closer proximity.
But again, your code also proves that your Thread names *are8 being displayed, but that you're only seeing one name likely because that thread is hogging the CPU.
Another option is to get all the Thread stacks and look for all the threads in the foo() This has the benefit of no overhead or extra code, except to capture the information you want.
BTW: Can you make it clearer why do you need this information as I suspect there is a better way to do what you really want?
If you only want to get the count of threads, use a thread-safe counter to store number of threads. Increase the counter when foo() begins, and decrease the counter when foo() exits.
If you need to get the names, use a hash set (or list if there are duplicates of thread names) to store the names: Add the name when foo() begins, and remove the name when foo() exits. Make sure the access to hash set is thread safe. You also need another method to print out the content of the hash set, so you can call it any time to see what are the name of threads executing foo().
You can put the name into a list when the method starts (in a synchronized block) and remove it at the end again.
List allTheNames = Collections.synchronizedList(new ArrayList<String>());
public void foo() {
allTheNames.add(Thread.currentThread().getName());
// now allTheNames contains all the names of all threads currently in this method.
System.out.println(allTheNames.toString());
allTheNames.remove(Thread.currentThread().getName());
}
Of course, if you change the name of the thread in the meantime that wont work, but why would you do so?
You could also store the Thread itself if you need other informations that the name.
I have a task x that is executed continuously in a thread which will only stop when the boolean changes it's state to true. I have done some reading and there are 3 ways that I approach when killing threads that are in the code below. Which of the 3 methods is effective ? And if none of them aren't effective or correct kindly suggest a proper approach with some code for reference.
Below is the code :
public class MyTest {
private static class transaction {
private String param1,param2,param3, param4, param5;
public transaction (String param1,String param2,String param3,String param4,String param5){
this.param1=param1;
this.param2=param2;
this.param3=param3;
this.param4=param4;
this.param5=param5;
}
public String getParam1(){
return this.param1;
}
public String getParam2(){
return this.param2;
}
public String getParam3(){
return this.param3;
}
public String getParam4(){
return this.param4;
}
public String getParam5(){
return this.param5;
}
}
public static void processBatch(String workerName){
try{
java.util.List <transaction> transactions= new java.util.LinkedList<transaction>();
java.sql.ResultSet dbtrx=Database.db.execQuery((Object)"dbname.procname");
while(dbtrx.next()){// Takes a snapshot of the pending payments in the table and stores it into the list.
Object obj=new transaction (dbtrx.getString("col1"), dbtrx.getString("col2"), dbtrx.getString("col3"), dbtrx.getString("col4"), dbtrx.getString("col5"));
transactions.add((transaction)obj);
obj=null;
}
java.util.Iterator<transaction> iterate= transactions.iterator();
/* Processes the pending batch payments*/
while(iterate.hasNext()){
transaction trx=iterate.next();
/*Calls posting function here*/
System.out.println(workerName+":- Param1 : "+trx.getParam1()+" - Param2 : " +trx.getParam2()+
" - Param3 : "+ trx.getParam3()+" - Param4 : "+ trx.getParam4()+" - Param5 : "+ trx.getParam5());
iterate.remove();
}
/*cleaning object references*/
dbtrx=null;
transactions=null;
iterate=null;
}catch(Exception e){
e.printStackTrace();
}
}
public static void main(String [] args) throws InterruptedException{
volatile boolean stop=false;
Object hold= new Object();
new Thread("Batch Worker A"){
#Override
public void run(){
while(true){
if(stop!=true){
processBatch(Thread.currentThread().getName());
}else{
try{
Thread.sleep(0);
Thread.currentThread().interrupt();
}catch(java.lang.InterruptedException e){
Thread.currentThread().interrupt();
break;
}
}
}
}}.start();
new Thread("Batch Worker B"){
#Override
public void run(){
try{
while(stop!=true){
processBatch(Thread.currentThread().getName());
}
Thread.sleep(0);
Thread.currentThread().interrupt();
}catch(java.lang.InterruptedException e){
Thread.currentThread().interrupt();
}
}}.start();
new Thread("Batch Worker C"){
#Override
public void run(){
while(!Thread.currentThread().isInterrupted()){
if(stop!=true){
processBatch(Thread.currentThread().getName());
}else{
Thread.currentThread().interrupt();
}
}
}}.start();
}
}
}
The recommended approach is to use the thread's interrupted flag to signal the thread loop to terminate. There's no reason to use two flags (stopped and the interrupted flag) where one will do, and you don't seem to be using the interrupted flag for anything else.
See the Java tutorial subject Interrupts for a more extensive discussion and examples.
Why not simply this way:
new Thread("Batch Worker A"){
#Override
public void run() {
while(!stop){
processBatch(Thread.currentThread().getName());
}
}
}}.start();
Alternatively, use Thread.interrupt() like so:
new Thread("Batch Worker A"){
#Override
public void run() {
while(!interrupted()){
processBatch(Thread.currentThread().getName());
}
}
}}.start();
but then you need to keep reference to all the threads, and interrupt them all, so the boolean flag might be simpler (be sure to make it volatile).
In all of your examples, you aren't really killing the thread, you are stopping the batch from processing more items.
To understand the difference, note that none of your methods would actually stop the thread while the thread is within the processBatch function.
There are some things to take note of:
There is no point in calling Interrupt() on your current thread. The idea behind Interrupt is for external threads to call it. In your case, you can just as well throw an exception, or return from the run() function (which would shut down the thread automatically).
Even interrupt() can't in many situations stop a thread if that thread is locked outside java ,such as thread waiting for IO (if not using NIO), including a socket, which is what the database connection is, you'll need to design a different way to stop a thread inside IO (usually by doing a timeout, but there are other ways).
if you goal is simply to stop the next batch from happing use the code from Joonas :
new Thread("Batch Worker A"){
#Override
public void run() {
while(!stop){
processBatch(Thread.currentThread().getName());
}
}
}}.start();
if your goal is to interrupt the process while running the batch, you can just as well do:
public static void main(String[] args) {
var t =new Thread("Batch Worker A"){
#Override
public void run() {
processBatch(Thread.currentThread().getName());
}
}.start();
t.interrupt();
}
in general interrupt is the preferred method, and using a local scoped variable and anonymous classes is a really bad idea (use a static variable, or better an injected interface with a function to check if the thread should continue).
Here's what I want to do. Given a function
public void foo() {
}
I would like to have it end after certain time has elapsed. That is, imagine this is some kind of random generator which has to produce random objects that satisfy some difficult constraints and hence it may or may not succeed under a given time allotment. That is, the function may actually be something like this
public void foo() {
//task1
while(fails) {
//...
}
//task2
while(fails2) {
//...
}
//more tasks may follow, which use the data from the previous tasks to further try to satisfy difficult conditions
}
That is simply just an example. But the point is that the function consists of many while loops, many test cases, and lots of heavy computation.
The goal: I want to be able to say "run foo() and if 4 seconds has elapsed and foo() is still not done, then stop foo() immediately."
What I have tried: I have tried to include conditions on just about every line of foo() to see how much time has elapsed and to return out of the function if the 4 seconds has passed. But given how complicated foo() is, this is clearly very difficult to do code wise because this requires testing the time on every single line of the function.
My thought logic: I think this should be possible because there are functions that do this sort of thing, that terminate code regardless of the state, such as System.exit(1). That is the idea. I'd like to be able to call, from the outside, to have this function foo() terminate.
// foo method and global variables used
private static ArrayList<Integer> foo() {
// info class
class Info {
public boolean run, completed;
public ArrayList<Integer> list;
}
// declare info object, list
final Info info = new Info();
final Object wait = new Object();
// run a new thread
Thread t = new Thread(
new Runnable() {
// run method
#Override
public void run() {
// setup run
info.run = true;
info.completed = false;
info.list = new ArrayList<>();
// loop to modify list. Don't put a big piece of code that will
// take a long time to execute in here.
while(info.run) {
// example of what you should be doing in here:
info.list.add(1);
// and if you are done modifying the list, use:
break;
}
// done modifying list
info.completed = true;
synchronized(wait) {
wait.notify();
}
}
}
);
t.start();
// wait for four seconds, then return list
try {
synchronized(wait) {
wait.wait(4000);
}
} catch (InterruptedException e) { e.printStackTrace(); }
info.run = false;
return info.completed ? info.list : null;
}
// main method
public static void main(String[] args) {
// get list
ArrayList<Integer> list = foo();
System.out.println("Done!");
}
What the foo() method does?
Begins to modify the list it will eventually return
If the time took modifying this list exceeds four seconds, it will stop modifying the list and return the list.
It will return null if the list was stopped early.
It now only uses local variables!
Nice bonus, it will immediately return the list the second modifying it is done.
Submit it as a runnable to an executor service and call get on the returned future with the desired timeout. Then in the catch block for the timeout exception you can cancel the future.
EDIT: Code sample
import com.google.common.base.Throwables;
import java.util.concurrent.*;
public class ExecutorExample {
private static final ExecutorService executor = Executors.newSingleThreadExecutor();
public void example() {
Future<String> future = executor.submit(new Callable<String>() {
#Override
public String call() throws Exception {
return "Do your complicated stuff";
}
});
try {
future.get(4, TimeUnit.SECONDS);
} catch (InterruptedException e) {
Throwables.propagate(e);
} catch (ExecutionException e) {
//handle
} catch (TimeoutException e) {
future.cancel(true);
}
}
}
Something like this will do the trick, but beware:
public static void main(String[] args){
Runnable fooRunner = new Runnable(){ public void run(){
foo();
}
Thread fooThread = new Thread(fooRunner);
fooThread.start();
Thread.sleep(4000);
fooThread.stop(); //warning -- this is deprecated!
}
The problem is that Thread.stop is deprecated.
Multi-threading in Java is fundamentally a cooperative endeavor. Because foo() may be manipulating shared state, probably protected by a lock that it currently owns, stopping it at an arbitrary point is potentially very dangerous and could lead to unpredictable failures, bugs, etc. later on in the program. (Indeed, since foo's return type is void, it must manipulate some shared state at some point in order to store its result.)
The language does provide a way to tell a thread that it should stop at the next convenient point: Thread.interrupt(), Thread.interrupted(), and InterruptedException. Your foo() method does need to check whether it's been interrupted periodically; that's the way it's done, and any higher-level library constructs (like Future.cancel()) rely on this.
You must enter into the hellish arena of writing threaded code.
http://docs.oracle.com/javase/tutorial/essential/concurrency/
Pseudo code (mutableboolean available in apache commons http://commons.apache.org/lang/download_lang.cgi)
...
final MutableBoolean finished = new MutableBoolean(false);
new Thread(new Runnable(){
public void run() {
doComplicatedStuff(finished);
}
}).start();
Thread.sleep(4000);
finished.setValue(true);
I have two classes. In class A, I have the run() method looped forever, while in the class B, i have the threadpool.
My question is, From Class B, how can I control and stop the thread executing run() method in class A , I have tried forceshutdown, threadExecutor.shutdownNow(), But it isnt working.
The loop seems to go on forever.
Here is example piece of code:
public class A implements Runnable {
public void run() {
while (true) {
System.out.println("Hi");
}
}
}
public class B {
public static void main(String[] args) {
int noOfThreads = 1;
A ThreadTaskOne = new A();
System.out.println("Threads are being started from Class B");
ExecutorService threadExecutor = Executors.newFixedThreadPool(noOfThreads);
threadExecutor.execute(ThreadTaskOne);
threadExecutor.shutdownNow();
System.out.println("B Ends, no of threads that are alive : " + Thread.activeCount());
}
}
As #MadProgammer said, your "infinite" loop needs to pay attention to Thread.isInterrupted. e.g. (very schematic)
public void run() {
while (!Thread.isInterrupted()) {
doSomethinginTheLoop1();
blah...blah...blah
// if the loop is very long you might want to check isInterrupted
// multiple times for quicker termination response
doSomethingInTheLoop2();
}
// now, here's a decision of what you do
// do you throw an InterruptedException or trust others to check interrupted flag.
// read Java COncurrency in Practice or similar...
}
The documentation on ExecutorService#shutdownNow() says -
There are no guarantees beyond best-effort attempts to stop processing actively executing tasks. For example, typical implementations will cancel via Thread.interrupt(), so any task that fails to respond to interrupts may never terminate.
And your thread doesn't seem to care if it has been interrupted.
So check if it has been interrupted
while (Thread.currentThread().isInterrupted())
instead of just doing
while (true)
May be below is useful for you.
public static class A implements Runnable {
public void run() {
while (!Thread.currentThread().isInterrupted()) {
System.out.println("Hi");
}
}
}