Wait for system time to continue application - java

I've written a class to continue a started JAVA application if the current second is a multiple of 5 (i.e. Calender.SECOND % 5 == 0)
The class code is presented below, what I'm curious about is, am I doing this the right way? It doesn't seem like an elegant solution, blocking the execution like this and getting the instance over and over.
public class Synchronizer{
private static Calendar c;
public static void timeInSync(){
do{
c = Calendar.getInstance();
}
while(c.get(Calendar.SECOND) % 5 != 0);
}
}
Synchronizer.timeInSync() is called in another class's constructor and an instance of that class is created at the start of the main method. Then the application runs forever with a TimerTask that's called every 5 seconds.
Is there a cleaner solution for synchronizing the time?
Update:
I think I did not clearly stated but what I'm looking for here is to synchronization with the system time without doing busy waiting.
So I need to be able to get
12:19:00
12:19:05
12:19:10
...

What you have now is called busy waiting (also sometimes referred as polling), and yes its inefficient in terms of processor usage and also in terms of energy usage. You code executes whenever the OS allows it, and in doing so it prevents the use of a CPU for other work, or when there is no other work it prevents the CPU from taking a nap, wasting energy (heating the CPU, draining the battery...).
What you should do is put your thread to sleep until the time where you want to do something arrives. This allows the CPU to perform other tasks or go to sleep.
There is a method on java.lang.Thread to do just that: Thread.sleep(long milliseconds) (it also has a cousin taking an additional nanos parameter, but the nanos may be ignored by the VM, and that kind of precision is rarely needed).
So first you determine when you need to do some work. Then you sleep until then. A naive implementation could look like that:
public static void waitUntil(long timestamp) {
long millis = timestamp - System.currentTimeMillis();
// return immediately if time is already in the past
if (millis <= 0)
return;
try {
Thread.sleep(millis);
} catch (InterruptedException e) {
throw new RuntimeException(e.getMessage(), e);
}
}
This works fine if you don't have too strict requirements on precisely hitting the time, you can expect it to return reasonably close to the specified time (a few ten ms away probably) if the time isn't too far in the future (a few secs tops). You have however no guarantees that occasionally when the OS is really busy that it possily returns much later.
A slightly more accurate method is to determine the reuired sleep time, sleep for half the time, evaluate required sleep again, sleep again half the time and so on until the required sleep time becomes very small, then busy wait the remaining few milliseconds.
However System.currentTimeMillis() does not guarantee the actual resolution of time; it may change once every millisecond, but it might as well only change every ten ms by 10 (this depends on the platform). Same goes for System.nanoTime().
Waiting for an exact point in time is not possible in high level programming languages in a multi-tasking environment (practically everywhere nowadays). If you have strict requirements, you need to turn to the operating system specifics to create an interrupt at the specified time and handle the event in the interrupt (that means assembler or at least C for the interrupt handler). You won't need that in most normal applications, a few ms +/- usually don't matter in a game/application.

As #ChrisK suggests, you could simplify by just making a direct call to System.currentTimeMillis().
For example:
long time = 0;
do
{
time = System.currentTimeMillis();
} while (time % 5000 != 0);
Note that you need to change the comparison value to 5000 because the representation of the time is in milliseconds.
Also, there are possible pitfalls to doing any comparison so directly like this, as the looping call depends on processor availability and whatnot, so there is a chance that an implementation such as this could make one call that returns:
`1411482384999`
And then the next call in the loop return
`1411482385001`
Meaning that your condition has been skipped by virtue of hardware availability.
If you want to use a built in scheduler, I suggest looking at the answer to a similar question here java: run a function after a specific number of seconds

You should use
System.nanoTime()
instead of
System.currentTimeMillis()
because it returns the measured elapsed time instead of the system time, so nanoTime is not influenced by system time changes.
public class Synchronizer
{
public static void timeInSync()
{
long lastNanoTime = System.nanoTime();
long nowTime = System.nanoTime();
while(nowTime/1000000 - lastNanoTime /1000000 < 5000 )
{
nowTime = System.nanoTime();
}
}
}

The first main point is that you must never use busy-waiting. In java you can avoid busy-waiting by using either Object.wait(timeout) or Thread.sleep(timeout). The later is more suitable for your case, because your case doesn't require losing monitor lock.
Next, you can use two approaches to wait until your time condition is satisfied. You can either precalculate your whole wait time or wait for small time intervals in loop, checking the condition.
I will illustrate both approaches here:
private static long nextWakeTime(long time) {
if (time / 1000 % 5 == 0) { // current time is multiple of five seconds
return time;
}
return (time / 1000 / 5 + 1) * 5000;
}
private static void waitUsingCalculatedTime() {
long currentTime = System.currentTimeMillis();
long wakeTime = nextWakeTime(currentTime);
while (currentTime < wakeTime) {
try {
System.out.printf("Current time: %d%n", currentTime);
System.out.printf("Wake time: %d%n", wakeTime);
System.out.printf("Waiting: %d ms%n", wakeTime - currentTime);
Thread.sleep(wakeTime - currentTime);
} catch (InterruptedException e) {
// ignore
}
currentTime = System.currentTimeMillis();
}
}
private static void waitUsingSmallTime() {
while (System.currentTimeMillis() / 1000 % 5 != 0) {
try {
System.out.printf("Current time: %d%n", System.currentTimeMillis());
Thread.sleep(100);
} catch (InterruptedException e) {
// ignore
}
}
}
As you can see, waiting for the precalculated time is more complex, but it is more precise and more efficient (since in general case it will be done in single iteration). Waiting iteratively for small time interval is simpler, but less efficient and precise (precision is dependent on the selected size of the time interval).
Also please note how I calculate if the time condition is satisfied:
(time / 1000 % 5 == 0)
In first step you need to calculate seconds and only then check if the are multiple of five. Checking by time % 5000 == 0 as suggested in other answer is wrong, as it is true only for the first millisecond of each fifth second.

Related

java: I am supposed to call a method 50x per second in the run method of a thread, ONLY WITH THE METHOD SLEEP (All other threads here with timer)

I have to call a method in the run method of a thread 50 times in one second, the problem is, i am only allowed to use sleep as a method!
Now the problem is how can i do that, other threads here for instance:
java- Calling a function at every interval
do that with a timer.
With a timer its easy. But i am only allowed to use sleep as a method...
while (true) {
long t0 = System.currentTimeMillis();
doSomething();
long t1 = System.currentTimeMillis();
Thread.sleep(20 - (t1-t0));
}
t1 minus t0 is the time you spent in 'doSomething', so you need to sleep for that much less than 20 mS.
You probably ought to add some checks for t1-t0 > 20.
You cannot avoid jitter in timing based on System.currentTimeMillis() (or, based on any other system clock).
This solution will not accumulate error due to jitter (unlike another answer here that measures how long the task actually took on each iteration of the loop.) Use this version if it's important for the task to be performed exactly the right number of times over a long span of time.
long dueDate = System.currentTimeMillis();
while (true) {
performThePeriodicTask();
dueDate = dueDate + TASK_PERIOD;
long sleepInterval = dueDate - System.currentTimeMillis();
if (sleepInteval > 0) {
Thread.sleep(sleepInterval);
}
}

How can I set while repeat count per second?

I use a while loop to repeat my codes in my program. I want to repeat a code 1000 times per second. How can I do this?
For the fixed-delay execution of some code, it might be a better approach to use a timer object, such as java.util.Timer or javax.swing.Timer, or even AnimationTimer, depending on what you're trying to accomplish. This being said, it's not possible to guarantee a frequency and a frequency of 1000/s (or period of 1ms) is quite fast, and java.util.Timer and javax.swing.Timer won't be able to keep up.
See also:
How to use swing timers
How to use Java.Util.Timer
High Resolution Timer in Java 5
I will show you an example of this using System.nanoTime() to determine how much time has passed, and will explain why your premise typically does not make much sense and you probably should not do this.
First off here is code that will execute a block of code 1000 times and will take 1 second to finish every time, as long as that code can be executed that quickly.
long startTime = System.nanoTime();
long currentTime = startTime;
int counter = 0;
while (((currentTime - startTime) < 1_000_000_000) || counter < 1000) { //Executes until 1 second has passed AND it has iterated 1000 times
counter++;
currentTime = System.nanoTime();
if (counter < 1000) {
//The code you want to execute 1000 times
System.out.println(counter);
}
}
System.out.println((currentTime - startTime)/1_000_000 + " milliseconds have passed.");
Now the problem with this code is you will obviously hit the 1000 executions before you hit 1 second, so it will sit in the loop doing nothing after the 1000 executions are completed to ensure the total time of the loop takes 1 second.
However what happens if that block of code takes so long that you cannot complete that code 1000 times within a second? It is impossible to go the other direction and add extra time to complete the 1000 executions, the 1000 executions will no longer take 1 second and it is impossible to fix this. The only way this can be done, is if you know that 1000 executions will be completed under 1 second and wait for the remaining time.
However, this does not seem like a good way to do things in general and you should not program in a way that depends on time AND loop iteration count, it just does not really make sense and there are likely better ways to do what your actual goal is.
Note: This code will only execute the block of code 1000 times, a single time. Surround all of this code by another loop if you want to do this multiple times.
EDIT:
Just to make it more clear I made an example that will take longer to execute than 1 second.
public static void main(String[] args){
long startTime = System.nanoTime();
long currentTime = startTime;
int counter = 0;
while (((currentTime - startTime) < 1_000_000_000) || counter < 1000) {
counter++;
currentTime = System.nanoTime();
if (counter < 1000) {
//The code you want to execute 1000 times
int count2 = 0;
while (count2 < 1000) { //1000 blank lines per loop to take a long time
count2++;
System.out.println();
}
System.out.println(counter);
}
}
System.out.println((currentTime - startTime)/1_000_000 + " milliseconds have passed.");
}
This will print blank lines just to ensure it takes a long time. For my system this outputted:
2831 milliseconds have passed.
The code took 2.8 seconds because time was no longer the restrictive condition, but 1000 iterations was, and there is no way to make this exact code run 1000 times per second, it is impossible.
TLDR: You can force something to take a minimum amount of a time, but you cannot force it to take a maximum amount of time.
Try to use a thread and use Thread.sleep() or System.currentTimeMillis() / 1000, this will give you the time in seconds.

How to achieve a guaranteed sleep time on a thread

I have a requirement for a class method to be called every 50 milliseconds. I don't use Thread.sleep because it's very important that it happens as precisely as possible to the milli, whereas sleep only guarantees a minimum time. The basic set up is this:
public class ClassA{
public void setup(){
ScheduledExecutorService se = Executors.newScheduledThreadPool(20);
se.scheduleAtFixedRate(this::onCall, 2000, 50, TimeUnit.MILLISECONDS);
}
protected void onCall(Event event) {
// do something
}
}
Now this by and large works fine. I have put System.out.println(System.nanoTime) in onCall to check its being called as precisely as I hope it is. I have found that there is a drift of 1-5 milliseconds over the course of 100s of calls, which corrects itself now and again.
A 5 ms drift unfortunately is pretty hefty for me. 1 milli drift is ok but at 5ms it messes up the calculation I'm doing in onCall because of states of other objects. It would be almost OK if I could get the scheduler to auto-correct such that if it's 5ms late on one call, the next one would happen in 45ms instead of 50.
My question is: Is there a more precise way to achieve this in Java? The only solution I can think of at the moment is to call a check method every 1ms and check the time to see if its at the 50ms mark. But then I'd need to maintain some logic if, on the off-chance, the precise 50ms interval is missed (49,51).
Thanks
Can I achieve a guaranteed sleep time on a thread?
Sorry, but No.
There is no way to get reliable, precise delay timing in a Java SE JVM. You need to use a Real time Java implementation running on a real time operating system.
Here are a couple of reasons why Java SE on a normal OS cannot do this.
At certain points, the GC in a Java SE JVM needs to "stop the world". While this is happening, no user thread can run. If your timer goes off in a "stop the world" pause, it can't be scheduled until the pause is over.
Scheduling of threads in a JVM is actually done by the host operating system. If the system is busy, the host OS may decide not to schedule the JVM's threads when your application needs this to happen.
The java.util.Timer.scheduleAtFixedRate approach is probably as good as you will get on Java SE. It should address long-term drift, but you can't get rid of the "jitter". And that jitter could easily be hundreds of milliseconds ... or even seconds.
Spinlocks won't help if the system is busy and the OS is preempting or not scheduling your threads. (And spinlocking in user code is wasteful ...)
According to the comment, the primary goal is not to concurrently execute multiple tasks at this precise interval. Instead, the goal is to execute a single task at this interval as precisely as possible.
Unfortunately, neither the ScheduledExecutorService nor any manual constructs involving Thread#sleep or LockSupport#parkNanos are very precise in that sense. And as pointed out in the other answers: There may always be influencing factors that are beyond your control - namely, details of the JVM implementation, garbage collection, JIT runs etc.
Nevertheless, a comparatively simple approach to achieve a high precision here is busy waiting. (This was already mentioned in an answer that is now deleted). But of course, this has several caveats. Most importantly, it will burn processing resources of one CPU. (And on a single-CPU-system, this may be particularly bad).
But in order to show that it may be far more precise than other waiting approaches, here is a simple comparison of the ScheduledExecutorService approach and the busy waiting:
import java.util.concurrent.Executors;
import java.util.concurrent.ScheduledExecutorService;
import java.util.concurrent.TimeUnit;
public class PreciseSchedulingTest
{
public static void main(String[] args)
{
long periodMs = 50;
PreciseSchedulingA a = new PreciseSchedulingA();
a.setup(periodMs);
PreciseSchedulingB b = new PreciseSchedulingB();
b.setup(periodMs);
}
}
class CallTracker implements Runnable
{
String name;
long expectedPeriodMs;
long baseTimeNs;
long callTimesNs[];
int numCalls;
int currentCall;
CallTracker(String name, long expectedPeriodMs)
{
this.name = name;
this.expectedPeriodMs = expectedPeriodMs;
this.baseTimeNs = System.nanoTime();
this.numCalls = 50;
this.callTimesNs = new long[numCalls];
}
#Override
public void run()
{
callTimesNs[currentCall] = System.nanoTime();
currentCall++;
if (currentCall == numCalls)
{
currentCall = 0;
double maxErrorMs = 0;
for (int i = 1; i < numCalls; i++)
{
long ns = callTimesNs[i] - callTimesNs[i - 1];
double ms = ns * 1e-6;
double errorMs = ms - expectedPeriodMs;
if (Math.abs(errorMs) > Math.abs(maxErrorMs))
{
maxErrorMs = errorMs;
}
//System.out.println(errorMs);
}
System.out.println(name + ", maxErrorMs : " + maxErrorMs);
}
}
}
class PreciseSchedulingA
{
public void setup(long periodMs)
{
CallTracker callTracker = new CallTracker("A", periodMs);
ScheduledExecutorService se = Executors.newScheduledThreadPool(20);
se.scheduleAtFixedRate(callTracker, periodMs,
periodMs, TimeUnit.MILLISECONDS);
}
}
class PreciseSchedulingB
{
public void setup(long periodMs)
{
CallTracker callTracker = new CallTracker("B", periodMs);
Thread thread = new Thread(new Runnable()
{
#Override
public void run()
{
while (true)
{
long periodNs = periodMs * 1000 * 1000;
long endNs = System.nanoTime() + periodNs;
while (System.nanoTime() < endNs)
{
// Busy waiting...
}
callTracker.run();
}
}
});
thread.setDaemon(true);
thread.start();
}
}
Again, this should be taken with a grain of salt, but the results on My MachineĀ® are as follows:
A, maxErrorMs : 1.7585339999999974
B, maxErrorMs : 0.06753599999999693
A, maxErrorMs : 1.7669149999999973
B, maxErrorMs : 0.007193999999998368
A, maxErrorMs : 1.7775299999999987
B, maxErrorMs : 0.012780999999996823
showing that the error for the waiting times is in the range of few microseconds.
In order to apply such an approach in practice, a more sophisticated infrastructure would be necessary. E.g. the bookkeeping that is necessary to compensate for waiting times that have been too high. (I think they can't be too low). Also, all this still does not guarantee a precisely timed execution. But it may be an option to consider, at least.
If you really have hard time constraints, you want to use a real-time operating system. General computing does not have hard time constraints; if your OS goes to virtual memory in one of your intervals, then you can miss your sleep interval. The real-time OS will make the tradeoff that you may get less done, but that work will can be better scheduled.
If you need to do this on a normal OS, you can spinlock instead of sleeping. This is really inefficient, but if you really have hard time constraints, it's the best way to approximate that.
That will be hard - think about GC... What I would do is to grab time with nanoTime, and use it in calculations. Or in other words I would get exact time and use it in calculations.
Yes (assuming you only want to prevent long term drifts and don't worry about each delay individually). java.util.Timer.scheduleAtFixedRate:
...In fixed-rate execution, each execution is scheduled relative to the scheduled execution time of the initial execution. If an execution is delayed for any reason (such as garbage collection or other background activity), two or more executions will occur in rapid succession to "catch up." In the long run, the frequency of execution will be exactly the reciprocal of the specified period (assuming the system clock underlying Object.wait(long) is accurate). ...
Basically, do something like this:
new Timer().scheduleAtFixedRate(new TimerTask() {
#Override
public void run() {
this.onCall();
}
}, 2000, 50);

Java: First iteration of for loop takes longer

I am writing some code to test using the MIDI libraries in Java, and have run across a problem. The pause between notes is much longer (almost twice as long, in fact) after the very first note than after all the others. I can't see any reason why, as the sequence of notes has already been generated (hence it is not also having to perform those calculations within the first iteration of the loop, it is only playing notes).
I think I may have also had this problem in the past with a simulation which, without any explanation I could find, took almost 100% of its tick length to perform calculations on the first tick only, and then used only about 2% on all successive iterations.
Main code (extract):
public void play() {
MidiPlayer player = new MidiPlayer();
for (int i = 0; i < NUMNOTES; i++) {
long tic = System.currentTimeMillis();
player.playNote(10, notes[i]);
try {
Thread.sleep(200);
} catch (InterruptedException e) {
e.printStackTrace();
}
long toc = System.currentTimeMillis();
System.out.println(toc - tic);
}
try {
Thread.sleep(500);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
Code for playNote():
public void playNote(int channel, int note) {
channels[channel].allNotesOff();
channels[channel].noteOn(note + 60, volume);
}
There are no 'if' statements that specify the first loop, so surely the delay should be uniform for all notes, as the number of calculations being performed should be the same for all iterations. Please note that the timing variables are just for testing purposes, and the effect was audibly noticeable before I included those.
EDIT: I should also mention that the output produced shows each iteration of the loop taking the expected 200 (occasionally 201) milliseconds. It seems to suggest that there is no gap - yet I clearly hear a gap every time I run the code.
Since you have sleeps, you should calculate how long you should sleep instead of trying to sleep the same amount of time each time - calculate how much more time you actually need to the next note to be played and sleep that much amount. i.e.
long tic = System.currentTimeMillis();
player.playNote(10, notes[i]);
long time_spent = System.currentTimeMillis() - tic;
Thread.sleep(200 - time_spent);

Java calculations that takes X amount of time

This is just a hypothetical question, but could be a way to get around an issue I have been having.
Imagine you want to be able to time a calculation function based not on the answer, but on the time it takes to calculating. So instead of finding out what a + b is, you wish to continue perform some calculation while time < x seconds.
Look at this pseudo code:
public static void performCalculationsForTime(int seconds)
{
// Get start time
int millisStart = System.currentTimeMillis();
// Perform calculation to find the 1000th digit of PI
// Check if the given amount of seconds have passed since millisStart
// If number of seconds have not passed, redo the 1000th PI digit calculation
// At this point the time has passed, return the function.
}
Now I know that I am horrible, despicable person for using precious CPU cycles to simple get time to pass, but what I am wondering is:
A) Is this possible and would JVM start complaining about non-responsiveness?
B) If it is possible, what calculations would be best to try to perform?
Update - Answer:
Based on the answers and comments, the answer seems to be that "Yes, this is possible. But only if it is not done in Android main UI thread, because the user's GUI will be become unresponsive and will throw an ANR after 5 seconds."
A) Is this possible and would JVM start complaining about non-responsiveness?
It is possible, and if you run it in the background, neither JVM nor Dalvik will complain.
B) If it is possible, what calculations would be best to try to perform?
If the objective is to just run any calculation for x seconds, just keep adding 1 to a sum until the required time has reached. Off the top of my head, something like:
public static void performCalculationsForTime(int seconds)
{
// Get start time
int secondsStart = System.currentTimeMillis()/1000;
int requiredEndTime = millisStart + seconds;
float sum = 0;
while(secondsStart != requiredEndTime) {
sum = sum + 0.1;
secondsStart = System.currentTimeMillis()/1000;
}
}
You can and JVM won't complain if your code is not part of some complex system that actually tracks thread execution time.
long startTime = System.currentTimeMillis();
while(System.currentTimeMillis() - startTime < 100000) {
// do something
}
Or even a for loop that checks time only every 1000 cycles.
for (int i = 0; ;i++) {
if (i % 1000 == 0 && System.currentTimeMillis() - startTime < 100000)
break;
// do something
}
As for your second question, the answer is probably calculating some value that can always be improved upon, like your PI digits example.

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